Exam 3 Solutions. Multiple Choice Questions

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1 MA 4 Exam 3 Solutions Fall 26 Exam 3 Solutions Multiple Choice Questions. The average value of the function f (x) = x + sin(x) on the interval [, 2π] is: A. 2π 2 2π B. π 2π 2 + 2π 4π 2 2π 4π 2 + 2π 2. Let f (x) and g(x) be two functions such that f (x) g(x) in the interval [a, b]. If we want to find the volume of the solid of revolution obtained by rotating around the y- axis the region R between f (x) and g(x) and a x b, the right integral to compute is: b A. 2πx + ( f (x) g(x)) dx B. a b a b a b a b a π( f (x)) 2 π(g(x)) 2 dx 2πx( f (x) g(x))dx + ( f (x) g(x)) dx f (x) g(x)dx

2 MA 4 Exam 3 Solutions Fall Given that f (x) = 3x 2 find all of the values of x that satisfy the Mean Value Theorem for Integrals on the interval [ 2, 4]. 67 A. ± 3 B. ±2 ± There is no such value of x. 4. The base of the solid S is the region enclosed by the parabola y = x 2 and the x-axis. The cross-sections perpendicular to the x-axis are squares. The volume of this solid is A B π Page 2 of

3 MA 4 Exam 3 Solutions Fall Consider the region in the first quadrant bounded by the graph of f (x) = ln(x) and the line x = 8. Which of the following integrals represents the volume obtained by rotating the region about the line x =? A. 2π B. 2π 2π 2π π ( x) ln(x) dx. ( x) ln(x) dx. x ln(x) dx. ( + x) ln(x) dx. ln(x) 2 dx. 6. Which of the following integrals represents the arc length of the graph of f (x) = ln(x) over the interval [, 8]? A. + x 2 dx. B. x ln(x) dx. x 2 + x 2 dx. + ln(x) 2 dx. + x 2 dx. Page 3 of

4 MA 4 Exam 3 Solutions Fall Which of the following represents the integral for the surface area obtained by rotating the graph of f (x) = 4 cos(x 3 ) over [, 2] about the x-axis? 2 A. 2π 4 cos(x 3 ) + 2x 2 sin(x 3 ) dx. B. 2π 2π 2π 2π cos(x 3 ) + 44x 4 sin 2 (x 3 ) dx. 4 cos(x 3 ) + 44x 4 cos 2 (x 3 ) dx. 4 cos(x 3 ) + 44x 4 sin(x 6 ) dx. + 44x 4 sin 2 (x 3 ) dx. 8. Which of the following integrals represents the y-moment M y of a thin plate of constant density ρ = 3 covering the region enclosed by the graphs of f (x) = x 2 4x + 6 and g(x) = x + 2? A. M y = B. M y = 3 2 M y = M y = M y = 3x(x 2 5x + 4) dx. ( (2 + x) 2 (x 2 4x + 6) 2) dx. 3x( x 2 + 5x 4) dx. 3( x 2 + 5x 4) dx. ( x 2 + 5x 4) dx. Page 4 of

5 MA 4 Exam 3 Solutions Fall If x = e 2t and y = sin(2t), then dy dx = A. 4e 2t cos(2t) B. e 2t cos(2t) sin(2t) 2e 2t cos(2t) 2e 2t cos(2t) e 2t. For what values of t does the curve given by the parametric equations x = t 3 t 2 and y = t 4 + 2t 2 8t have a vertical tangent line? A. only B. only and 2 3 only, 2 3, and No value Page 5 of

6 MA 4 Exam 3 Solutions Fall 26. A curve C is defined by the parametric equations x = t 2 4t + and y = t 3. Which of the following is an equation of the line tangent to the graph of C at the point ( 3, 8)? A. x = 3 B. x = 2 y = 8 y = 27 (x + 3) + 8 y = 2(x + 3) The length of the path described by the parametric equations x = 3 t3 and y = 2 t2, where t, is given by A. t2 + dt B. t2 + tdt t4 + t 2 dt t 2 dt 6 t2 4t 2 + 9dt Page 6 of

7 MA 4 Exam 3 Solutions Fall 26 Free Response Questions 3. Setup (and do not compute) the integral that needs to be calculated if we want to find the volume of the solid of revolution obtained by rotating the region R enclosed by y = e x + sin(x) +, y and x 2 using the most suitable method, when R is rotated: (a) (5 points) around the x-axis 2 π (e x + sin x + ) 2 dx. (b) (5 points) around the y-axis 2π 2 x (e x + sin x + ) dx. 4. ( points) Compute the arc length of the graph of f (x) = 2x over the interval [, 7]. Give the exact answer. f (x) = 3x /2 so the arc length is given by L = = [ f (x)] 2 dx + 9xdx = 2 27 ( + 9x)3/2 7 = Page 7 of

8 MA 4 Exam 3 Solutions Fall Consider the functions f (x) = 6 x and g(x) = 3x. (a) (4 points) Compute the intersection points of f (x) and g(x). 6 x = 3x 4x = x 2 x =, 4 (b) (2 points) Give a sketch of the region enclosed by the graphs of f (x) and g(x). (c) (2 points) Compute the centroid of the region. M = M y = M x = (6 x 3x)dx = 8 x(6 x 3x)dx = 64 5 = 2.8 ( (6 x) 2 (3x) 2) dx = 48 2 x = M y M = 8 5 =.6 y = M x M = 6 Page 8 of

9 MA 4 Exam 3 Solutions Fall The surface S is generated by revolving the parametric curve given by x = + cos t and y = 2 sin t for t 2π around the x-axis. (a) (6 points) Write down the integral that is required to compute the surface area of this surface, S. 2π 2π(2 sin t) ( sin t) 2 + ( cos t) 2 dt. (b) (4 points) Find the exact value of this integral. 2π 2π 2π(2 sin t) sin 2 t + cos 2 t = = 2π 2π( + sin t)dt 2π = 2π(4π + ) = 8π 2 2 sin t dt Page 9 of

10 MA 4 Exam 3 Solutions Fall Consider the parametric equations x = 4 cos(t) and y = 6 cos(2t). (a) (6 points) Find dy dx dy dt = y = 2 sin(2t) = 24 sin t cos t dx dt = x = 4 sin t dy dx = y x = 24 sin t cos t 4 sin t = 6 cos t = 3 sin(2t) sin t (b) (2 points) Find the slope of the tangent line when t = π/3. dy dx = 6 cos π t=π/3 3 = 3. (c) (3 points) Find the equation of the tangent line when t = π/3. x(π/3) = 2 and y(π/3) = 3, thus y + 3 = 3(x 2) or y = 3x 9. (d) (5 points) Find d2 y dx 2. d 2 y dx 2 = d dt ( ) dy dx dx dt = 6 sin t cos(2t) 3 sin(2t) cos t sin 2 t 4 sin t = 6 sin t 4 sin t = 3 2. Page of

SCORE. Exam 3. MA 114 Exam 3 Fall 2016

SCORE. Exam 3. MA 114 Exam 3 Fall 2016 Exam 3 Name: Section and/or TA: Do not remove this answer page you will return the whole exam. You will be allowed two hours to complete this test. No books or notes may be used. You may use a graphing