Chapter Start Thinking. 10π 31.4 cm. 1. 5π 15.7 cm 2. 5 π 7.9 cm π 13.1 cm Warm Up , 8π 2. 90,15π 3.

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1 x = 8andx = 7 8. x = andx = 7. x = 0. x = 10 x = 11. x = 18. x =. x = 8 x = 1. x = x = 1 8. x = a. x + 11 b. c. 11 d. 17. (, ) , 5, 11, 1 7, 5 1, 5 1 1, 11, Sample answer: ABC, ABD,and CBD. Sample answer: GFJ, GFH,and JFH a. 18. in. b.. in. a. in. b. 1 in. Chapter Start Thinking 10 cm 5 17 cm. 5 cm. 5 1 cm 11 Warm Up 10, 8. 0,15. 15,1 11 Cumulative Review Warm Up = 1 11 Practice A 1 m. about 1. ft. about 1 in.. cm Divide the circumference of the tree by to find the diameter of the tree. Because the diameter is 50 1 inches, which is less than 18 inches, the tree is not suitable for tapping.. about.8 cm about 1 in. 8. about ft. about.57 mm 10. about 8.85 in ft 11 Practice B m ft. about.0 cm about 1.5 m about. m about.1 m 10. about 11 1 about 58.0 ft about 0.5 cm a. in. b. about 71 teeth A108

2 11 Enrichment and Extension a cm b cm. 8. about 0.1 cm. about.85 cm about 8.57 in 1 about cm 1. coverage area is times greater; new coverage area ft old coverage area 1811 ft 11 Puzzle Time SO THAT THE AUDIENCE WOULD BE GLUED TO THEIR SEATS 1 Start Thinking 1 in in in in Warm Up 81 5 in mi. 11 cm ft 1 Cumulative Review Warm Up m x =, y =. x = 7, y = 7. x =, y = 11 1 Practice A 17 ft.. 18 m. 0 in. about 10,10 people/mi. about 88,57 people 8.5 cm about 8 ft, about 5 ft 8. about. about 18.5 in., about.58 in. m, about m 10. about 1 cm, about 17 cm yd about 57 m 1 Practice B about 1.1 in.. about 0.07 mi. about.5 km. about. yd about 5 mi. about 10.5 mi about 0.18 m, about 8. about. about.8 cm, about 0. in., about 0. m.5 cm 0.8 in. 10. about 87 yd, about.8 yd 1 about.5 cm about 0. ft about 10.5 m 1. about 1 about. in. 1. about 1 Enrichment and Extension. 7 m a a. b. 8 c. 1. cm b. Measure of arc, x Area of sector, y y = x 0 1 Puzzle Time A SCREWDRIVER. 0.1 ft.18 in.. 8 square units about 81 ft 1. about 85 mm A10

3 1 Start Thinking Sample answer: To find the area of the triangle, draw an altitude and create two congruent triangles. Using the special right triangle, the altitude would have a measure of units. Using the formula for the area of a triangle, you have A = 1 bh = 1 ( )( ) = square units.. Sample answer: To find the area of the regular hexagon, connect two pairs of non-consecutive vertices and create four congruent triangles and a rectangle as shown. Using the special right triangle, you can find the measures needed to calculate the area. The area of the hexagon would be the sum of the areas of the four congruent triangles and the rectangle in the center, or 1 A = ( )( ) ( ) + = square units. 10. square units 1. 5 square units square units cm m 18. a. about ft b. containers; The area of the floor is about 1.5 square feet. Because and you cannot buy part of a container, you will need containers of wood sealer. 1 Practice B 85 square units square units. 5 square units. 8 square units square units square units 1. square units 1 ft, 8 ft mm, mm 1. a. Sample answer: 0 8 ft 15 ft 1 Warm Up sin cos 1 Cumulative Review Warm Up sometimes. always. always. never always. sometimes 1 Practice A 0.5 square units. 5 square units. 1 square units. 10 square units b. 181 ft 1 yes; One side length of the 11-gon is 1.5 = 5 meters. The length of the apothem a is a =. tan 1. So, A = ( 1.5) 1 square meters. tan 1. 1 Enrichment and Extension. 5 ft. A ; 0 = s. A1 = s + s 1 + s A110

4 . A = s + s + s 1 7 A = s + s + s + s S = 5 sphere with radius. An = s square units 5 1 Puzzle Time A WATCH DOG 1 Start Thinking triangular prism: F = 5, V =, E =, rectangular prism: F =, V = 8, E = 1, pentagonal prism: F = 7, V = 10, E = 15, hexagonal prism: F = 8, V = 1, E = 18; F + V E = for each of the prisms; As you increase the number of faces by 1, the numbers of vertices increases by, and the number of edges increases by. 1 Warm Up yes. no; The sides are not segments.. no; It is not a plane figure. 1 Cumulative Review Warm Up Practice A 1 yes; rectangular prism. yes; triangular pyramid. cone with height and base radius 10. yes; It is bounded by polygons only. 1 yes; Sample answer: parallel to a horizontal face and parallel to a vertical face a. + 5 in. b in. 1 Practice B triangle. trapezoid. semicircle.. no. circle triangle. rectangle 5 cylinder with height and base radius cylinder with height and base radius 5 Sample answer: part of a cone with height and two different circular bases with radii and A111

5 .. z (0, 0, ) (, 0, 0) y hemisphere with radius none of the parts are polyhedrons; Sample answer: Two parts contain some faces that are polygons, but all three parts also contain faces that are not polygons circle x. no; Sample answer: An oblique cylinder does not have rotational symmetry, so you cannot draw a shape and an axis of revolution that could form the cylinder.. Sample answer: two adjacent cylinders that share the same axis of symmetry. a. trapezoid, triangle b. trapezoid: perimeter = in., area = 18 in. triangle: perimeter = in., area = in. c. no; Sample answer: It is flatter than a circle, more like an oval. 1 Enrichment and Extension z (0, 0, 5) 1 Puzzle Time BECAUSE THEY HAD JUST FINISHED A MARCH OF THIRTY-ONE DAYS 15 Start Thinking cubic units; cubic units; no; no; The volume of a right solid and an oblique solid will be the same if the height and cross-sectional area are the same. 15 Warm Up 18 cm. 80 in.. 0. cm x y (0,, 0) 15 Cumulative Review Warm Up Practice A 8 in... about 8 cm 1.1 ft. about yd A11

6 about 7 g. m about 100 in ft ; Sample answer: length: ft, width: ft cm ; Sample answer: length: cm, width cm m 1 cm about 8.87 gallons 15 Practice B 88 ft. 18 m. about 10,. in.. about 1.55 cm 700 g. ft about.00 m yd ; Sample answer: length: yd, width: yd. in. ; Sample answer: length: 8 in., width: in in. 1 about 17 ft 1 in. 15 Enrichment and Extension V = x + x x. V = x + x + x Sample answer: The volume is equal to the surface area, so rh= r + rh. Solve for r to h obtain r =. If 0 < h <, then r < 0, h so h must be greater than. Similarly, if you solve r for h, you get h =. If 0 < r <, then r h < 0, so r must be greater than cm in. 7 cm 8. 5 in.. 5 ft 15 Puzzle Time POST OFFICE 1 Start Thinking Sample answer: The volume of the cube is clearly greater than the volume of the pyramid. You can see that the pyramid would fit inside the cube. The volume of the cube is 15 cubic inches and the volume of the pyramid will be one third of that value. 1 Warm Up. 10 in.. 5 tan 5 cm 15 m 1 Cumulative Review Warm Up ( x ) ( y ) + 5 =. ( x ) ( y ) + + =. ( x ) ( y ) =. ( x ) ( y ) = 1 1 Practice A 0 m. 85 in.. 8 ft. 8 cm 5 ft. 1 m in mm. 70 yd m 1 0 cm 8, or m 1 Practice B about 0 cm. about. ft. about.7 yd.. m 5 in.. 18 cm.175 yd 8. 0 cm. 80 in m Enrichment and Extension cm.. 0 cubic units cm. Sample answer: V = B( h + h ) V. units 1 ; A11

7 10.1 V = ( ) = 0. cm 1 Puzzle Time A CAR POOL 17 Start Thinking 50 in.; 1 8 in.; 50 8 in. 17 Warm Up about 8. cm. about 1 in.. about 58. m 17 Cumulative Review Warm Up y = x 8. y = x y = x Practice A about 77 ft. 5 m. about 0. cm. about 1.7 in. 51 mm. 7 in. about 877 in. 8. about cm. h ; r ; Sample answer: The original volume is 1 V = r h and the new volume is V = r h. 10. cylindrical container; The cost of the cylindrical container is $.75 per cubic inches (or about $0.0 per cubic inch), whereas the cost per cubic inch for the cone-shaped container is $.5 per cubic inches (or about $0.0 per cubic inch). 17 Practice B about 8 yd. about mm. about 175 in.. about 1 cm 75 ft. 7 5 m about in. 8. about 1.0 cm. 1 ; h r ; Sample answer: The original volume is 1 1 V = r h and the new volume is V = r h. 10. about sec 17 Enrichment and Extension a m 5 b. 17 m.. c. about ft 8. m. ft ft about 15 m. Sample answer: You are increasing the area of the base by a factor of =, so the height of the cone must be 1 the original size ft 8. about. m 17 Puzzle Time BECAUSE THEY TAKE TOO LONG TO CHANGE 18 Start Thinking ( ) S cube =.55 5 in., Scyl = (.55) +.8 in. ; no; cylinder 18 Warm Up 15 in.. 5 in.. in. 18 Cumulative Review Warm Up radius. tangent. diameter. chord secant. radius 18 Practice A about 50.7 in.. about 1.1 mm. about 00 ft. m yd. about 110 ft about 1,117 cm 8. about 58 m A11

8 . about.1 in. 10. about 0.8 km 1 about 0 cm about 78 ft about m, about 1.0 m 1. about 57 yd ; The edge length of the cube, yards, is the diameter of the sphere. 1 surface area of new ball is = = 11 times the surface area of the old ball (an 11% increase), volume of new ball is = = 17 times the volume of the old ball, (a 17% increase); Use the properties of similar solids; surface area of new ball = =, surface area of old ball 1 1 volume of new ball, = = volume of old ball 7, Practice B about 110 m. about 7 yd. about 7 in.. 5 cm.5 in.. about 0 ft about 5717 cm 8. about m ft 10. about 0.5 mi 1 about yd about 8.78 in. surface area shrinks to one-fourth original size, volume shrinks to one-eight original size 1. a. no; You also need to know the radius of one of the cannonballs. b. lb 18 Enrichment and Extension greater than; The volume of the box is cubic inches. The volume of the four balls is less than 17 cubic inches. So, there is more than 15 cubic inches left over inside the box, and the volume of a fifth ball is less than cubic inches, so the volume left over inside the box is greater than a fifth ball.. 1,87,578 L. 0 in.. a. r b. V c. r = S S S = The shape of the graph is similar to half a parabola. r S = r + r + r + 1. S = r + r + r 18 Puzzle Time EGG SHELLS 8 V r V = S S 8 Cumulative Review ft. 1 cm. 5 in.. 18 km 11 m. 18 mm M ( 1, ) 8. M ( 1, 1). M (, ) 10. M ( 8, ) 1 H (, 0) G( 5, ) G( 10, 5) 1. (, 8) H XYZ, ZYX, Y. JKL, LKJ, K. Sample answer: consecutive even integers beginning with ; 1, 1. Sample answer: consecutive odd integers beginning with 1, alternatively negative and positive; 11, 1 S r A115

9 Sample answer: skip two letters in the alphabet, beginning with A; P, S. Sample answer: skip one letter in the alphabet, beginning with B; L, N x = 1 8. x = 1. x = 0. x = 1 x =. x =. x = 7. x = 1 y = x 7. y = 5x + y = x y = 10x +. y = 5x y = x x =, y =. x = 15, y = 18. x = 15, y = 10. x = 1, y = y = x 50. y = 8x 1 5 y = x + y = x y = x y = x 11 y = x 7 y = 8x + 5 A (, ) 58. B (, ) C (, 7) 0. D (, 1) E( 11, ). P ( 10,11 ), Q (, 1 ), R (, ). P ( 5,, ) Q (,, ) R ( 1, ). P ( 1, 1 ), Q (,1 ), R ( 5, ) P ( 1,, ) Q (,, ) R ( 7, 8). P (, 1 ), Q ( 5, 1 ), R ( 1, ) A ( 7, 1 ), B ( 1, 0 ), C ( 0, 1) 8. X (, 0 ), Y ( 0, ), Z (, ). M (, 0 ), N (, ), P (, ) 70. Q ( 5, ), R ( 0, ), S (, 5 ), T (, ) 7 D (, 8 ), E (, 0 ), F ( 8, 1 ), G (, ) a. 50. in. b. 5 in. c. 5 in. a. 50. cm b. cm c. 8 cm d. the circle Chapter 1 1 Start Thinking Sample answer: Sample answer: It is not too likely that you will grab the number that matches your jersey. You have a 1 in 15 chance of choosing a matching pair of shorts.. Sample answer: Possible Outcomes: Jersey and shorts 11 and 1, 11 and, 11 and, 11 and, 11 and 5, 11 and, 11 and 7, 11 and 8, 11 and, 11 and 10, 11 and 11, 11 and 1, 11 and 1, 11 and 1, 11 and 15 1 Warm Up H for heads, T for tails, HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. B for blue, Y for yellow, G for green, R for red, BB, BY, BG, BR, YY, YB, YG, YR, GG, GB, GY, GR, RR, RB, RY, RG. BH, BT, YH, YT, GH, GT, RH, RT 1 Cumulative Review Warm Up sin θ =, cos θ =, tan θ =, 7 7 csc θ = 7 7, sec θ =, cot θ = A11

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