4. UNBALANCED 3 FAULTS

Size: px
Start display at page:

Download "4. UNBALANCED 3 FAULTS"

Transcription

1 4. UNBALANCED AULTS So fr: we hve tudied lned fult ut unlned fult re more ommon. Need: to nlye unlned ytem. Could: nlye three-wire ytem V n V n V n Mot ommon fult type = ingle-phe to ground i.e. write node eqution in term of Vn, Vn, Vn,,, Alterntive: ue Symmetril omponent expre: eh unlned equene,, where i voltge or urrent : um of lned equene (lled ymmetril omponent) then: poitive phe equene (--) negtive phe equene (--) zero phe equene (ll phor in phe) nlye eprte lned network Reltion n e implified y uing the opertor. 4. Ue of the opertor Define: Thu: Alo: j e.5 j j j.866 * j j.866 j or lned ytem with phe equene --: V V n n Vn n V V V V V V V n n n ELEC46: Anlyi of power ytem fult p. ELEC46: Anlyi of power ytem fult p.4

2 4. ntrodution to ymmetril omponent Exmple: Now onider n unlned equene,, + + nd the ymmetril omponent equene: Poitive equene,, -- Negtive equene,, -- Zero equene,, = ELEC46: Anlyi of power ytem fult p.5 ELEC46: Anlyi of power ytem fult p.6

3 Unlned equene: 6 degree of freedom,,,,, Symmetril omponent equene: 6 degree of freedom,,,,, Will now how tht, given ny unlned - equene,,, n find +ve, -ve nd zero equene,,,,,, nd,, whih um to it: i.e. tht i in mtrix form: Proof: n exerie, how tht thu ymmetril omponent given y will um to,, qed tht i the ymmetril omponent for,, re given y: ELEC46: Anlyi of power ytem fult p.7 ELEC46: Anlyi of power ytem fult p.8

4 Exmple:.,, lned with -equene -- i.e. nd o tht 4.,, V V V line-line voltge. Then zero eq. volt. V V V V (y KVL) ELEC46: Anlyi of power ytem fult p.9 i.e. no zero-equene omponent in line-line voltge (ut n exit in line-neutrl voltge).,, line urrent into Y-onneted lod. Then zero-equene urrent i: onlude: n N () neutrl urrent = x zero-equene urrent () iolted neutrl zero-equene urrent = 4. open iruit in one line: ELEC46: Anlyi of power ytem fult p. Suppoe: 7.. A o tht: A nd:. A. A Symmetril omponent vlue for urrent in eh phe re thu: Phe Phe Phe ( eq.)... (+ve eq.) 5 9 (-ve eq.) 5 9 Note: ut i.e. n hve non-zero ymmetril omponent of phe vrile whih i zero.

5 Power in ymmetril omponent V n V n V n Complex - power i: * * * n n n S P jq V V V unlned - ytem: Vn, Vn, Vn nd,, * * T * T * Vn Vn Vn Vp. p AV A * where: Vp phe voltge vetor; p phe urrent vetor; V equene voltge vetor; equene urrent vetor. V n A ; V V n ; V n thu: * * i.e. T T S V A A * * Vn Vn Vn * * * * n n n S V V V * * * n n n V V V S 4. Applition of ymmetril omponent t i neery to determine ymmetril omponent of urrent in ll prt of network nd then omine to get true urrent. Thi require determintion of the tul network in whih equene urrent flow: poitive equene: network i norml lned equivlent. for negtive equene: for poitive equene exept for genertor. No voltge oure. for zero equene: equivlent network depend on the tul onfigurtion. Sequene network: for lned-y impedne lod g Z y Z y Z y Z n V Z Z Z Z Z Z Z Z g y n n y n y n n n V Z Z Z Z g n y n n V Z Z Z Z g n n y n Z=R+j ELEC46: Anlyi of power ytem fult p. ELEC46: Anlyi of power ytem fult p.

6 or: V Z Z Z Z g y n n n Vg Zn Zy Zn Z n V g Zn Zn Zy Z n or: Vp Zp. p ut: Vp AV. nd p A. V where: A ; V V V Hene: AV. Z. A. where: V Z p Z. nd A Zp A Sequene impedne mtrix: Thu: y n V Z Z Z V Zy Z V Z Z y Z i zero equene impedne Z i poitive equene impedne Z i negtive equene impedne ; A Zy Zn Z Zy Z y Thu for the Y iruit, the equene network re: Zero: Poitive: Negtive: V V V Z y Z n Z y Z y Z Z Z Z Z y Z y Z y when there i no neutrl onnetion; Zn nd thu there i no zero equene urrent. when olidly erthed; Zn or onnetion: onvert into equivlent Y iruit (uing the -Y trnformtion) wherey ZY Z /. Thu the equene network re: Zero: Poitive: Negtive: = Z Z Z Z Z Z n ELEC46: Anlyi of power ytem fult p. ELEC46: Anlyi of power ytem fult p.4

7 Repreenttion of plnt item in equene network. Synhronou mhine: // Poitive equene impedne d Negtive equene i not = +ve equene // Typilly:.5 to.5.5 to.5.4 to.4 Only voltge ville re poitive equene one.. Line nd le: Poitive nd negtive equene impedne vlue re equl. Zero equene impedne depend on nture of return pth through the erth if no fourth wire ville.. Trnformer: Poitive nd negtive equene vlue re equl nd re norml lned vlue. Zero equene omponent vry widely, depending on trnformer onnetion. Zero equene impedne for vriou t/f onnetion. or eh of equene network, we need to redue them to Thévenin equivlent een from the fult, i.e. Z Z Z V V V V _ zero eq. +ve eq. -ve eq. ELEC46: Anlyi of power ytem fult p.5 ELEC46: Anlyi of power ytem fult p.6

8 Exmple 9. [ee textook] Note tht for the line: Z V Z.5 pu 9.4 B Bline SB 6 Thévenin equivlent: Ue MVA,.8kV e (genertor zone). Prefult voltge i V.5 o. Drw equene digrm nd redue to Thévenin equivlent for fult t u (motor terminl). zero eq. +ve eq. Z j.5 Z j.89 V.5 + _ V + V _ j. j.5 j.455// j. -ve eq. Z j V _ j.475// j. Ce : lned fult t u Ue only poitive equene iruit V.5 j7.558 pu Z j.89 Here: ; V ; V j7.558 ; V Uing: p A ELEC46: Anlyi of power ytem fult p.7 ELEC46: Anlyi of power ytem fult p.8

9 // // where: p nd j7.558 // // // thu j // pu Ce : A ingle-phe ground fult ult ondition (expreed in phe domin) re: ; V Z if ring fult (r impedne Z ) or V if olted fult ( Z ) But: A p () V V Vp AV V V V V V V V V () Generl -phe u () nteronneted equene network ig. 9.7 (Glover et l) Thu: V VV V Z Z () Condition () nd () n e tified y interonneting the equene network hown in () ove. rom thi: V Z ZZ Z or uing: p A. V Z ZZ Z () (4) (5) Uing previou exmple: Single-phe ground fult on u with Z ELEC46: Anlyi of power ytem fult p.9 ELEC46: Anlyi of power ytem fult p.4

10 Ce : A line-line fult () Generl -phe u ig. 9.9 (Glover et l).5 j j.964 j5.89 pu pu () nteronneted equene network Conider line-line fult from phe to. ult ondition, expreed in phe domin, re: (6) (7) V V Z (8) Trnform thee into the equene domin: But: V V V V V V V V So eq.8 eome: V V V V V V Z (9) But from eq.9, nd o: V V Z Hene: V V Z Thu, fult ondition in the equene domin: V V Z Thee ondition n e tified y onneting the poitive- nd negtive-equene network in prllel t the fult terminl through the fult impedne Z. rom thi: V Z Z Z Trnform into the phe domin: ELEC46: Anlyi of power ytem fult p.4 ELEC46: Anlyi of power ytem fult p.4

11 j j V () ZZ Z Alo: () () Ce 4: A doule line-to-ground fult () Generl -phe u ig. 9. (Glover et l) ELEC46: Anlyi of power ytem fult p.4 () nteronneted equene network Conider fult from phe to through fult impedne Z to ground. ult ondition, expreed in phe domin, re: () V V (4) V Z (5) Trnform thee into the equene domin. Note tht: nd thu from eq.: But: V V V V (6) V V V V So eq.4 eome: V V V V V V or: V V Sutitute into eq.6: V V V V V (7) But: = Hene, from eq.5 nd eq.: V V Z Z Thu, fult ondition in the equene domin: V V V V Z Thee ondition n e tified y onneting the zero-, poitive- nd negtive-equene network in prllel t the fult terminl. n ddition, Z i inluded in erie with the zero-equene network. rom thi: ELEC46: Anlyi of power ytem fult p.44

12 V ZZ // Z Z Uing urrent diviion: Z Z Z Z Z Z Z Z Z Thee n e trnformed into the phe domin vi: Ce 5: Effet of trnformer phe hift Note tht we ignored effet of -Y trnformer phe hift in the previou exmple. ult urrent nd ontriution to fult urrent on the fult ide of -Y trnformer re not ffeted y -Y phe hift; ontriution to the fult from the other ide re ffeted. ELEC46: Anlyi of power ytem fult p.45

Power System Representation and Equations. A one-line diagram of a simple power system

Power System Representation and Equations. A one-line diagram of a simple power system Power ystem epresenttion nd Equtions Lod B Lod A Bus Bus A oneline digrm of simple power system Oil or liquid iruit reker otting mhine Twowinding power trnsformer Wye onnetion, neutrl ground PerPhse, Per

More information

8 THREE PHASE A.C. CIRCUITS

8 THREE PHASE A.C. CIRCUITS 8 THREE PHSE.. IRUITS The signls in hpter 7 were sinusoidl lternting voltges nd urrents of the so-lled single se type. n emf of suh type n e esily generted y rotting single loop of ondutor (or single winding),

More information

IEEE PES Boston Chapter. Protection Engineering Course Series. Instructor: Dean V. Sorensen (National Grid)

IEEE PES Boston Chapter. Protection Engineering Course Series. Instructor: Dean V. Sorensen (National Grid) ymmetril Components EEE PE Boston Chpter Protetion Engineering Course eries Fll nstrutor: Den. orensen (Ntionl Grid) ymmetril Components Disussion Topis History nd Desription The Generl ethod of ymmetril

More information

Dorf, R.C., Wan, Z. T- Equivalent Networks The Electrical Engineering Handbook Ed. Richard C. Dorf Boca Raton: CRC Press LLC, 2000

Dorf, R.C., Wan, Z. T- Equivalent Networks The Electrical Engineering Handbook Ed. Richard C. Dorf Boca Raton: CRC Press LLC, 2000 orf, R.C., Wn,. T- Equivlent Networks The Eletril Engineering Hndook Ed. Rihrd C. orf Bo Rton: CRC Press LLC, 000 9 T P Equivlent Networks hen Wn University of Cliforni, vis Rihrd C. orf University of

More information

ELE B7 Power System Engineering. Unbalanced Fault Analysis

ELE B7 Power System Engineering. Unbalanced Fault Analysis Power System Engineering Unblnced Fult Anlysis Anlysis of Unblnced Systems Except for the blnced three-phse fult, fults result in n unblnced system. The most common types of fults re single lineground

More information

Symmetrical Components 1

Symmetrical Components 1 Symmetril Components. Introdution These notes should e red together with Setion. of your text. When performing stedy-stte nlysis of high voltge trnsmission systems, we mke use of the per-phse equivlent

More information

Polyphase Systems. Objectives 23.1 INTRODUCTION

Polyphase Systems. Objectives 23.1 INTRODUCTION Polyphse Systems 23 Ojetives eome fmilir with the opertion of threephse genertor nd the mgnitude nd phse reltionship etween the three phse voltges. e le to lulte the voltges nd urrents for three-phse Y-onneted

More information

Polyphase Systems 22.1 INTRODUCTION

Polyphase Systems 22.1 INTRODUCTION 22 Polyphse Systems 22.1 INTRODUTION n genertor designed to develop single sinusoidl voltge for eh rottion of the shft (rotor) is referred to s single-phse genertor. If the numer of oils on the rotor is

More information

SOLUTIONS TO ASSIGNMENT NO The given nonrecursive signal processing structure is shown as

SOLUTIONS TO ASSIGNMENT NO The given nonrecursive signal processing structure is shown as SOLUTIONS TO ASSIGNMENT NO.1 3. The given nonreursive signl proessing struture is shown s X 1 1 2 3 4 5 Y 1 2 3 4 5 X 2 There re two ritil pths, one from X 1 to Y nd the other from X 2 to Y. The itertion

More information

is the cut off frequency in rads.

is the cut off frequency in rads. 0 ELETRIAL IRUITS 9. HIGH RDER ATIVE FILTERS (With Tle) Introdution Thi development explin how to deign Butterworth (Mximlly Flt) or heyhev (Equl Ripple) Low P, High P or Bnd P tive filter. Thi tretment

More information

Chapter 10: Symmetrical Components and Unbalanced Faults, Part II

Chapter 10: Symmetrical Components and Unbalanced Faults, Part II Chpter : Symmetricl Components nd Unblnced Fults, Prt.4 Sequence Networks o Loded Genertor n the igure to the right is genertor supplying threephse lod with neutrl connected through impednce n to ground.

More information

Magnetically Coupled Coil

Magnetically Coupled Coil Mgnetilly Coupled Ciruits Overview Mutul Indutne Energy in Coupled Coils Liner Trnsformers Idel Trnsformers Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 Mgnetilly Coupled Coil i v L

More information

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the

More information

EE 330/330L Energy Systems (Spring 2012) Laboratory 1 Three-Phase Loads

EE 330/330L Energy Systems (Spring 2012) Laboratory 1 Three-Phase Loads ee330_spring2012_l_01_3phse_lods.do 1/5 EE 330/330L Energy Systems (Spring 2012) Lortory 1 ThreePhse Lods Introdution/Bkground In this lortory, you will mesure nd study the voltges, urrents, impednes,

More information

Distributed Generation Placement in Unbalanced Distribution System with Seasonal Load Variation

Distributed Generation Placement in Unbalanced Distribution System with Seasonal Load Variation Distriuted Genertion Plement in Unlned Distriution System with Sesonl Lod Vrition Rvi Tej Bhimrsetti Dept. of Eletril Engg., NT Kurukshetr Kurukshetr, ndi svrtej@gmil.om Ashwni Kumr, Memer, EEE Dept. of

More information

EE Control Systems LECTURE 8

EE Control Systems LECTURE 8 Coyright F.L. Lewi 999 All right reerved Udted: Sundy, Ferury, 999 EE 44 - Control Sytem LECTURE 8 REALIZATION AND CANONICAL FORMS A liner time-invrint (LTI) ytem cn e rereented in mny wy, including: differentil

More information

Problem-Solving Companion

Problem-Solving Companion ProblemSolving Compnion To ccompny Bic Engineering Circuit Anlyi Eight Edition J. Dvid Irwin Auburn Univerity JOHN WILEY & SONS, INC. Executive Editor Bill Zobrit Aitnt Editor Kelly Boyle Mrketing Mnger

More information

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3 2 The Prllel Circuit Electric Circuits: Figure 2- elow show ttery nd multiple resistors rrnged in prllel. Ech resistor receives portion of the current from the ttery sed on its resistnce. The split is

More information

Designing Information Devices and Systems I Discussion 8B

Designing Information Devices and Systems I Discussion 8B Lst Updted: 2018-10-17 19:40 1 EECS 16A Fll 2018 Designing Informtion Devices nd Systems I Discussion 8B 1. Why Bother With Thévenin Anywy? () Find Thévenin eqiuvlent for the circuit shown elow. 2kΩ 5V

More information

CSCI565 - Compiler Design

CSCI565 - Compiler Design CSCI565 - Compiler Deign Spring 6 Due Dte: Fe. 5, 6 t : PM in Cl Prolem [ point]: Regulr Expreion nd Finite Automt Develop regulr expreion (RE) tht detet the longet tring over the lphet {-} with the following

More information

Chapter 8 Three-Phase Power System and Three-Phase Transformers

Chapter 8 Three-Phase Power System and Three-Phase Transformers Chpter 8 Three-Phse Power System nd Three-Phse Trnsformers Single-phse systems re dequte for residentil pplitions up to n pprent power S of 5 kva (per residene), nd 25 kva single-phse pole trnsformers

More information

Project 6: Minigoals Towards Simplifying and Rewriting Expressions

Project 6: Minigoals Towards Simplifying and Rewriting Expressions MAT 51 Wldis Projet 6: Minigols Towrds Simplifying nd Rewriting Expressions The distriutive property nd like terms You hve proly lerned in previous lsses out dding like terms ut one prolem with the wy

More information

332:221 Principles of Electrical Engineering I Fall Hourly Exam 2 November 6, 2006

332:221 Principles of Electrical Engineering I Fall Hourly Exam 2 November 6, 2006 2:221 Principles of Electricl Engineering I Fll 2006 Nme of the student nd ID numer: Hourly Exm 2 Novemer 6, 2006 This is closed-ook closed-notes exm. Do ll your work on these sheets. If more spce is required,

More information

I 3 2 = I I 4 = 2A

I 3 2 = I I 4 = 2A ECE 210 Eletril Ciruit Anlysis University of llinois t Chigo 2.13 We re ske to use KCL to fin urrents 1 4. The key point in pplying KCL in this prolem is to strt with noe where only one of the urrents

More information

APPENDIX 2 LAPLACE TRANSFORMS

APPENDIX 2 LAPLACE TRANSFORMS APPENDIX LAPLACE TRANSFORMS Thi ppendix preent hort introduction to Lplce trnform, the bic tool ued in nlyzing continuou ytem in the frequency domin. The Lplce trnform convert liner ordinry differentil

More information

POLYPHASE CIRCUITS. Introduction:

POLYPHASE CIRCUITS. Introduction: POLYPHASE CIRCUITS Introduction: Three-phse systems re commonly used in genertion, trnsmission nd distribution of electric power. Power in three-phse system is constnt rther thn pulsting nd three-phse

More information

A SVC Based Control Algorithm for Load Balancing

A SVC Based Control Algorithm for Load Balancing Proeedings of the 7th WSEAS nterntionl onferene on Power Systems, eijing, hin, September 5-7, 7 A S sed ontrol Algorithm for od lning AHAD KAZEM kzemi@iust..ir A. MORAD KOOH Arshmordi@ee.iust..ir Ele.

More information

Section 4.2 Analysis of synchronous machines Part II

Section 4.2 Analysis of synchronous machines Part II Section 4. Anlyi of ynchronou mchine Prt 4.. Sttor flux linkge in non-lient pole ynchronou motor due to rotor The ir-gp field produced by the rotor produce flux linkge with individul phe winding. Thee

More information

Network Analysis and Synthesis. Chapter 5 Two port networks

Network Analysis and Synthesis. Chapter 5 Two port networks Network Anlsis nd Snthesis hpter 5 Two port networks . ntroduction A one port network is completel specified when the voltge current reltionship t the terminls of the port is given. A generl two port on

More information

MATH4455 Module 10 Evens, Odds and Ends

MATH4455 Module 10 Evens, Odds and Ends MATH4455 Module 10 Even, Odd nd End Min Mth Conept: Prity, Ple Vlue Nottion, Enumertion, Story Prolem Auxiliry Ide: Tournment, Undireted grph I. The Mind-Reding Clultor Prolem. How doe the mind-reding

More information

Vector Integration. Line integral: Let F ( x y,

Vector Integration. Line integral: Let F ( x y, Vetor Integrtion Thi hpter tret integrtion in vetor field. It i the mthemti tht engineer nd phiit ue to deribe fluid flow, deign underwter trnmiion ble, eplin the flow of het in tr, nd put tellite in orbit.

More information

CHAPTER 7 SYMMETRICAL COMPONENTS AND REPRESENTATION OF FAULTED NETWORKS

CHAPTER 7 SYMMETRICAL COMPONENTS AND REPRESENTATION OF FAULTED NETWORKS HAPTER 7 SMMETRAL OMPOETS AD REPRESETATO OF FAULTED ETWORKS A uled three-phe yte e reolved ito three led yte i the iuoidl tedy tte. Thi ethod of reolvig uled yte ito three led phor yte h ee propoed y.

More information

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Vector Integration

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Vector Integration www.boopr.om VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Vetor Integrtion Thi hpter tret integrtion in vetor field. It i the mthemti tht engineer nd phiit ue to deribe fluid flow, deign underwter trnmiion

More information

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then. pril 8, 2017 Mth 9 Geometry Solving vetor prolems Prolem Prove tht if vetors nd stisfy, then Solution 1 onsider the vetor ddition prllelogrm shown in the Figure Sine its digonls hve equl length,, the prllelogrm

More information

Solutions for HW9. Bipartite: put the red vertices in V 1 and the black in V 2. Not bipartite!

Solutions for HW9. Bipartite: put the red vertices in V 1 and the black in V 2. Not bipartite! Solutions for HW9 Exerise 28. () Drw C 6, W 6 K 6, n K 5,3. C 6 : W 6 : K 6 : K 5,3 : () Whih of the following re iprtite? Justify your nswer. Biprtite: put the re verties in V 1 n the lk in V 2. Biprtite:

More information

DIRECT CURRENT CIRCUITS

DIRECT CURRENT CIRCUITS DRECT CURRENT CUTS ELECTRC POWER Consider the circuit shown in the Figure where bttery is connected to resistor R. A positive chrge dq will gin potentil energy s it moves from point to point b through

More information

QUADRATIC EQUATION EXERCISE - 01 CHECK YOUR GRASP

QUADRATIC EQUATION EXERCISE - 01 CHECK YOUR GRASP QUADRATIC EQUATION EXERCISE - 0 CHECK YOUR GRASP. Sine sum of oeffiients 0. Hint : It's one root is nd other root is 8 nd 5 5. tn other root 9. q 4p 0 q p q p, q 4 p,,, 4 Hene 7 vlues of (p, q) 7 equtions

More information

NEW CIRCUITS OF HIGH-VOLTAGE PULSE GENERATORS WITH INDUCTIVE-CAPACITIVE ENERGY STORAGE

NEW CIRCUITS OF HIGH-VOLTAGE PULSE GENERATORS WITH INDUCTIVE-CAPACITIVE ENERGY STORAGE NEW CIRCUITS OF HIGH-VOLTAGE PULSE GENERATORS WITH INDUCTIVE-CAPACITIVE ENERGY STORAGE V.S. Gordeev, G.A. Myskov Russin Federl Nuler Center All-Russi Sientifi Reserh Institute of Experimentl Physis (RFNC-VNIIEF)

More information

Math 2142 Homework 2 Solutions. Problem 1. Prove the following formulas for Laplace transforms for s > 0. a s 2 + a 2 L{cos at} = e st.

Math 2142 Homework 2 Solutions. Problem 1. Prove the following formulas for Laplace transforms for s > 0. a s 2 + a 2 L{cos at} = e st. Mth 2142 Homework 2 Solution Problem 1. Prove the following formul for Lplce trnform for >. L{1} = 1 L{t} = 1 2 L{in t} = 2 + 2 L{co t} = 2 + 2 Solution. For the firt Lplce trnform, we need to clculte:

More information

Educational Modeling for Fault Analysis of Power Systems with STATCOM Controllers using Simulink

Educational Modeling for Fault Analysis of Power Systems with STATCOM Controllers using Simulink University of New Orlens SholrWorks@UNO University of New Orlens Theses nd Disserttions Disserttions nd Theses Fll 12-18-2014 Edutionl Modeling for Fult nlysis of Power Systems with STTOM ontrollers using

More information

MAT 403 NOTES 4. f + f =

MAT 403 NOTES 4. f + f = MAT 403 NOTES 4 1. Fundmentl Theorem o Clulus We will proo more generl version o the FTC thn the textook. But just like the textook, we strt with the ollowing proposition. Let R[, ] e the set o Riemnn

More information

Instructions. An 8.5 x 11 Cheat Sheet may also be used as an aid for this test. MUST be original handwriting.

Instructions. An 8.5 x 11 Cheat Sheet may also be used as an aid for this test. MUST be original handwriting. ID: B CSE 2021 Computer Orgniztion Midterm Test (Fll 2009) Instrutions This is losed ook, 80 minutes exm. The MIPS referene sheet my e used s n id for this test. An 8.5 x 11 Chet Sheet my lso e used s

More information

3 Angle Geometry. 3.1 Measuring Angles. 1. Using a protractor, measure the marked angles.

3 Angle Geometry. 3.1 Measuring Angles. 1. Using a protractor, measure the marked angles. 3 ngle Geometry MEP Prtie ook S3 3.1 Mesuring ngles 1. Using protrtor, mesure the mrked ngles. () () (d) (e) (f) 2. Drw ngles with the following sizes. () 22 () 75 120 (d) 90 (e) 153 (f) 45 (g) 180 (h)

More information

Designing Information Devices and Systems I Spring 2018 Homework 7

Designing Information Devices and Systems I Spring 2018 Homework 7 EECS 16A Designing Informtion Devices nd Systems I Spring 2018 omework 7 This homework is due Mrch 12, 2018, t 23:59. Self-grdes re due Mrch 15, 2018, t 23:59. Sumission Formt Your homework sumission should

More information

Exam 2 Solutions ECE 221 Electric Circuits

Exam 2 Solutions ECE 221 Electric Circuits Nme: PSU Student ID Numer: Exm 2 Solutions ECE 221 Electric Circuits Novemer 12, 2008 Dr. Jmes McNmes Keep your exm flt during the entire exm If you hve to leve the exm temporrily, close the exm nd leve

More information

50 AMC Lectures Problem Book 2 (36) Substitution Method

50 AMC Lectures Problem Book 2 (36) Substitution Method 0 AMC Letures Prolem Book Sustitution Metho PROBLEMS Prolem : Solve for rel : 9 + 99 + 9 = Prolem : Solve for rel : 0 9 8 8 Prolem : Show tht if 8 Prolem : Show tht + + if rel numers,, n stisf + + = Prolem

More information

Section 1.3 Triangles

Section 1.3 Triangles Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior

More information

Fundamentals of Electrical Circuits - Chapter 3

Fundamentals of Electrical Circuits - Chapter 3 Fundmentls of Electricl Circuits Chpter 3 1S. For the circuits shown elow, ) identify the resistors connected in prllel ) Simplify the circuit y replcing prllel connect resistors with equivlent resistor.

More information

20.2. The Transform and its Inverse. Introduction. Prerequisites. Learning Outcomes

20.2. The Transform and its Inverse. Introduction. Prerequisites. Learning Outcomes The Trnform nd it Invere 2.2 Introduction In thi Section we formlly introduce the Lplce trnform. The trnform i only pplied to cul function which were introduced in Section 2.1. We find the Lplce trnform

More information

Engr354: Digital Logic Circuits

Engr354: Digital Logic Circuits Engr354: Digitl Logi Ciruits Chpter 4: Logi Optimiztion Curtis Nelson Logi Optimiztion In hpter 4 you will lern out: Synthesis of logi funtions; Anlysis of logi iruits; Tehniques for deriving minimum-ost

More information

ROUTH-HURWITZ CRITERION

ROUTH-HURWITZ CRITERION Automti Cotrol Sytem, Deprtmet of Mehtroi Egieerig, Germ Jordi Uiverity Routh-Hurwitz Criterio ite.google.om/ite/ziydmoud 7 ROUTH-HURWITZ CRITERION The Routh-Hurwitz riterio i lytil proedure for determiig

More information

Electrical Circuits II (ECE233b)

Electrical Circuits II (ECE233b) Eletril Ciruits (ECE2) Polyhse Ciruits Anestis Dounis The Uniersity of Western Ontrio Fulty of Engineering Siene ThreePhse Ciruits Blned three hse iruit: ontins three oltge soures tht re equl in mgnitude

More information

LECTURE 23 SYNCHRONOUS MACHINES (3)

LECTURE 23 SYNCHRONOUS MACHINES (3) ECE 330 POWER CIRCUITS AND ELECTROMECHANICS LECTURE 3 SYNCHRONOUS MACHINES (3) Acknowledgent-Thee hndout nd lecture note given in cl re bed on teril fro Prof. Peter Suer ECE 330 lecture note. Soe lide

More information

VECTOR ALGEBRA. Syllabus :

VECTOR ALGEBRA. Syllabus : MV VECTOR ALGEBRA Syllus : Vetors nd Slrs, ddition of vetors, omponent of vetor, omponents of vetor in two dimensions nd three dimensionl spe, slr nd vetor produts, slr nd vetor triple produt. Einstein

More information

Discrete Structures, Test 2 Monday, March 28, 2016 SOLUTIONS, VERSION α

Discrete Structures, Test 2 Monday, March 28, 2016 SOLUTIONS, VERSION α Disrete Strutures, Test 2 Mondy, Mrh 28, 2016 SOLUTIONS, VERSION α α 1. (18 pts) Short nswer. Put your nswer in the ox. No prtil redit. () Consider the reltion R on {,,, d with mtrix digrph of R.. Drw

More information

2. The Laplace Transform

2. The Laplace Transform . The Lplce Trnform. Review of Lplce Trnform Theory Pierre Simon Mrqui de Lplce (749-87 French tronomer, mthemticin nd politicin, Miniter of Interior for 6 wee under Npoleon, Preident of Acdemie Frncie

More information

SECTION A STUDENT MATERIAL. Part 1. What and Why.?

SECTION A STUDENT MATERIAL. Part 1. What and Why.? SECTION A STUDENT MATERIAL Prt Wht nd Wh.? Student Mteril Prt Prolem n > 0 n > 0 Is the onverse true? Prolem If n is even then n is even. If n is even then n is even. Wht nd Wh? Eploring Pure Mths Are

More information

CHENG Chun Chor Litwin The Hong Kong Institute of Education

CHENG Chun Chor Litwin The Hong Kong Institute of Education PE-hing Mi terntionl onferene IV: novtion of Mthemtis Tehing nd Lerning through Lesson Study- onnetion etween ssessment nd Sujet Mtter HENG hun hor Litwin The Hong Kong stitute of Edution Report on using

More information

Estimation of Sequence Components using Magnitude Information

Estimation of Sequence Components using Magnitude Information 6th NATIONAL POWER SYSTEMS CONFERENCE, 5th-7th DECEMBER, 2 47 Estimtion of Sequene Components using Mgnitude Informtion P.S. Ngendr ro nd Ssikirn Veknuru Deprtment of Eletril Engineering Indin Institute

More information

Designing Information Devices and Systems I Fall 2016 Babak Ayazifar, Vladimir Stojanovic Homework 6. This homework is due October 11, 2016, at Noon.

Designing Information Devices and Systems I Fall 2016 Babak Ayazifar, Vladimir Stojanovic Homework 6. This homework is due October 11, 2016, at Noon. EECS 16A Designing Informtion Devices nd Systems I Fll 2016 Bk Ayzifr, Vldimir Stojnovic Homework 6 This homework is due Octoer 11, 2016, t Noon. 1. Homework process nd study group Who else did you work

More information

THREE DIMENSIONAL GEOMETRY

THREE DIMENSIONAL GEOMETRY MD THREE DIMENSIONAL GEOMETRY CA CB C Coordintes of point in spe There re infinite numer of points in spe We wnt to identif eh nd ever point of spe with the help of three mutull perpendiulr oordintes es

More information

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e Green s Theorem. Let be the boundry of the unit squre, y, oriented ounterlokwise, nd let F be the vetor field F, y e y +, 2 y. Find F d r. Solution. Let s write P, y e y + nd Q, y 2 y, so tht F P, Q. Let

More information

Section 4.4. Green s Theorem

Section 4.4. Green s Theorem The Clulus of Funtions of Severl Vriles Setion 4.4 Green s Theorem Green s theorem is n exmple from fmily of theorems whih onnet line integrls (nd their higher-dimensionl nlogues) with the definite integrls

More information

ELE B7 Power Systems Engineering. Power System Components Modeling

ELE B7 Power Systems Engineering. Power System Components Modeling Power Systems Engineering Power System Components Modeling Section III : Trnsformer Model Power Trnsformers- CONSTRUCTION Primry windings, connected to the lternting voltge source; Secondry windings, connected

More information

Transfer Functions. Chapter 5. Transfer Functions. Derivation of a Transfer Function. Transfer Functions

Transfer Functions. Chapter 5. Transfer Functions. Derivation of a Transfer Function. Transfer Functions 5/4/6 PM : Trnfer Function Chpter 5 Trnfer Function Defined G() = Y()/U() preent normlized model of proce, i.e., cn be ued with n input. Y() nd U() re both written in devition vrible form. The form of

More information

Examination Electrical Machines and Drives Et4-117 Thursday, October 30, 2003 from 9.00 to 12.00

Examination Electrical Machines and Drives Et4-117 Thursday, October 30, 2003 from 9.00 to 12.00 Exmintion Electricl Mchine nd Drive Et4-117 Thurdy, Octoer 30, 003 from 900 to 100 Thi exmintion conit of 6 prolem The numer efore prolem indicte how mny point cn e erned with thi prolem 15 Prolem 1 c

More information

Professor Ramzy R. Obaid HW: Ch.8 # 6, 10, 11, and 12

Professor Ramzy R. Obaid HW: Ch.8 # 6, 10, 11, and 12 Three-Phse Systems Prt 2 Prfessr Rmzy R. Oid HW: Ch.8 # 6, 10, 11, nd 12 With mny thnks nd ppreitin t Prfessr Mhmed A. El-Shrkwi 3 Y-Cnnetin Sure nd Ld Sure Trnsmissin Line Line urrent Ld n Phse urrent

More information

Part 4. Integration (with Proofs)

Part 4. Integration (with Proofs) Prt 4. Integrtion (with Proofs) 4.1 Definition Definition A prtition P of [, b] is finite set of points {x 0, x 1,..., x n } with = x 0 < x 1

More information

SPACE VECTOR PULSE- WIDTH-MODULATED (SV-PWM) INVERTERS

SPACE VECTOR PULSE- WIDTH-MODULATED (SV-PWM) INVERTERS CHAPTER 7 SPACE VECTOR PULSE- WIDTH-MODULATED (SV-PWM) INVERTERS 7-1 INTRODUCTION In Chpter 5, we briefly icue current-regulte PWM inverter uing current-hyterei control, in which the witching frequency

More information

Coalgebra, Lecture 15: Equations for Deterministic Automata

Coalgebra, Lecture 15: Equations for Deterministic Automata Colger, Lecture 15: Equtions for Deterministic Automt Julin Slmnc (nd Jurrin Rot) Decemer 19, 2016 In this lecture, we will study the concept of equtions for deterministic utomt. The notes re self contined

More information

Hadamard-Type Inequalities for s-convex Functions

Hadamard-Type Inequalities for s-convex Functions Interntionl Mthemtil Forum, 3, 008, no. 40, 965-975 Hdmrd-Type Inequlitie or -Convex Funtion Mohmmd Alomri nd Mlin Dru Shool o Mthemtil Siene Fulty o Siene nd Tehnology Univeriti Kebngn Mlyi Bngi 43600

More information

Approximation of continuous-time systems with discrete-time systems

Approximation of continuous-time systems with discrete-time systems Approximtion of continuou-time ytem with icrete-time ytem he continuou-time ytem re replce by icrete-time ytem even for the proceing of continuou-time ignl.. Impule invrince metho 2. Step invrince metho

More information

STABILITY and Routh-Hurwitz Stability Criterion

STABILITY and Routh-Hurwitz Stability Criterion Krdeniz Technicl Univerity Deprtment of Electricl nd Electronic Engineering 6080 Trbzon, Turkey Chpter 8- nd Routh-Hurwitz Stbility Criterion Bu der notlrı dece bu deri ln öğrencilerin kullnımın çık olup,

More information

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES Mthemtics SKE: STRN J STRN J: TRNSFORMTIONS, VETORS nd MTRIES J3 Vectors Text ontents Section J3.1 Vectors nd Sclrs * J3. Vectors nd Geometry Mthemtics SKE: STRN J J3 Vectors J3.1 Vectors nd Sclrs Vectors

More information

Exercise 3 Logic Control

Exercise 3 Logic Control Exerise 3 Logi Control OBJECTIVE The ojetive of this exerise is giving n introdution to pplition of Logi Control System (LCS). Tody, LCS is implemented through Progrmmle Logi Controller (PLC) whih is lled

More information

Bi-quad filters realization on AIC Codecs

Bi-quad filters realization on AIC Codecs pplition Report pril Bi-qud filter reliztion on IC Code HP Softwre BSTRCT Thi pplition report provide informtion regrding filter eqution nd o-effiient formt repreenttion tht n e ued to relize digitl filter

More information

Solutions Problem Set 2. Problem (a) Let M denote the DFA constructed by swapping the accept and non-accepting state in M.

Solutions Problem Set 2. Problem (a) Let M denote the DFA constructed by swapping the accept and non-accepting state in M. Solution Prolem Set 2 Prolem.4 () Let M denote the DFA contructed y wpping the ccept nd non-ccepting tte in M. For ny tring w B, w will e ccepted y M, tht i, fter conuming the tring w, M will e in n ccepting

More information

Polynomials. Polynomials. Curriculum Ready ACMNA:

Polynomials. Polynomials. Curriculum Ready ACMNA: Polynomils Polynomils Curriulum Redy ACMNA: 66 www.mthletis.om Polynomils POLYNOMIALS A polynomil is mthemtil expression with one vrile whose powers re neither negtive nor frtions. The power in eh expression

More information

Industrial Electrical Engineering and Automation

Industrial Electrical Engineering and Automation CODEN:LUTEDX/(TEIE-719)/1-7/(7) Industril Electricl Engineering nd Automtion Estimtion of the Zero Sequence oltge on the D- side of Dy Trnsformer y Using One oltge Trnsformer on the D-side Frncesco Sull

More information

4-4 E-field Calculations using Coulomb s Law

4-4 E-field Calculations using Coulomb s Law 1/11/5 ection_4_4_e-field_clcultion_uing_coulomb_lw_empty.doc 1/1 4-4 E-field Clcultion uing Coulomb Lw Reding Aignment: pp. 9-98 Specificlly: 1. HO: The Uniform, Infinite Line Chrge. HO: The Uniform Dik

More information

Bogoliubov Transformation in Classical Mechanics

Bogoliubov Transformation in Classical Mechanics Bogoliubov Tranformation in Claical Mechanic Canonical Tranformation Suppoe we have a et of complex canonical variable, {a j }, and would like to conider another et of variable, {b }, b b ({a j }). How

More information

Functions. mjarrar Watch this lecture and download the slides

Functions. mjarrar Watch this lecture and download the slides 9/6/7 Mustf Jrrr: Leture Notes in Disrete Mthemtis. Birzeit University Plestine 05 Funtions 7.. Introdution to Funtions 7. One-to-One Onto Inverse funtions mjrrr 05 Wth this leture nd downlod the slides

More information

GM1 Consolidation Worksheet

GM1 Consolidation Worksheet Cmridge Essentils Mthemtis Core 8 GM1 Consolidtion Worksheet GM1 Consolidtion Worksheet 1 Clulte the size of eh ngle mrked y letter. Give resons for your nswers. or exmple, ngles on stright line dd up

More information

Proving the Pythagorean Theorem

Proving the Pythagorean Theorem Proving the Pythgoren Theorem W. Bline Dowler June 30, 2010 Astrt Most people re fmilir with the formul 2 + 2 = 2. However, in most ses, this ws presented in lssroom s n solute with no ttempt t proof or

More information

A Study on the Properties of Rational Triangles

A Study on the Properties of Rational Triangles Interntionl Journl of Mthemtis Reserh. ISSN 0976-5840 Volume 6, Numer (04), pp. 8-9 Interntionl Reserh Pulition House http://www.irphouse.om Study on the Properties of Rtionl Tringles M. Q. lm, M.R. Hssn

More information

CIT 596 Theory of Computation 1. Graphs and Digraphs

CIT 596 Theory of Computation 1. Graphs and Digraphs CIT 596 Theory of Computtion 1 A grph G = (V (G), E(G)) onsists of two finite sets: V (G), the vertex set of the grph, often enote y just V, whih is nonempty set of elements lle verties, n E(G), the ege

More information

Eigenvectors and Eigenvalues

Eigenvectors and Eigenvalues MTB 050 1 ORIGIN 1 Eigenvets n Eigenvlues This wksheet esries the lger use to lulte "prinipl" "hrteristi" iretions lle Eigenvets n the "prinipl" "hrteristi" vlues lle Eigenvlues ssoite with these iretions.

More information

Figure 1. The left-handed and right-handed trefoils

Figure 1. The left-handed and right-handed trefoils The Knot Group A knot is n emedding of the irle into R 3 (or S 3 ), k : S 1 R 3. We shll ssume our knots re tme, mening the emedding n e extended to solid torus, K : S 1 D 2 R 3. The imge is lled tuulr

More information

LESSON 11: TRIANGLE FORMULAE

LESSON 11: TRIANGLE FORMULAE . THE SEMIPERIMETER OF TRINGLE LESSON : TRINGLE FORMULE In wht follows, will hve sides, nd, nd these will e opposite ngles, nd respetively. y the tringle inequlity, nd..() So ll of, & re positive rel numers.

More information

Logic Synthesis and Verification

Logic Synthesis and Verification Logi Synthesis nd Verifition SOPs nd Inompletely Speified Funtions Jie-Hong Rolnd Jing 江介宏 Deprtment of Eletril Engineering Ntionl Tiwn University Fll 2010 Reding: Logi Synthesis in Nutshell Setion 2 most

More information

CS 2204 DIGITAL LOGIC & STATE MACHINE DESIGN SPRING 2014

CS 2204 DIGITAL LOGIC & STATE MACHINE DESIGN SPRING 2014 S 224 DIGITAL LOGI & STATE MAHINE DESIGN SPRING 214 DUE : Mrh 27, 214 HOMEWORK III READ : Relte portions of hpters VII n VIII ASSIGNMENT : There re three questions. Solve ll homework n exm prolems s shown

More information

Vectors , (0,0). 5. A vector is commonly denoted by putting an arrow above its symbol, as in the picture above. Here are some 3-dimensional vectors:

Vectors , (0,0). 5. A vector is commonly denoted by putting an arrow above its symbol, as in the picture above. Here are some 3-dimensional vectors: Vectors 1-23-2018 I ll look t vectors from n lgeric point of view nd geometric point of view. Algericlly, vector is n ordered list of (usully) rel numers. Here re some 2-dimensionl vectors: (2, 3), ( )

More information

1/16/2013. Overview. 05-Three Phase Analysis Text: Three Phase. Three-Phase Voltages. Benefits of Three-Phase Systems.

1/16/2013. Overview. 05-Three Phase Analysis Text: Three Phase. Three-Phase Voltages. Benefits of Three-Phase Systems. oltge () 1/16/21 Overview 5Three Phse Alysis Text: 2.4 2.7 ECEGR 451 Power Systems ThreePhse Soures Delt d Y Coetios ThreePhse Lods ThreePhse Power ThreePhse Alysis PerPhse Alysis Dr. Louie 2 ThreePhse

More information

1.3 SCALARS AND VECTORS

1.3 SCALARS AND VECTORS Bridge Course Phy I PUC 24 1.3 SCLRS ND VECTORS Introdution: Physis is the study of nturl phenomen. The study of ny nturl phenomenon involves mesurements. For exmple, the distne etween the plnet erth nd

More information

y = c 2 MULTIPLE CHOICE QUESTIONS (MCQ's) (Each question carries one mark) is...

y = c 2 MULTIPLE CHOICE QUESTIONS (MCQ's) (Each question carries one mark) is... . Liner Equtions in Two Vriles C h p t e r t G l n e. Generl form of liner eqution in two vriles is x + y + 0, where 0. When we onsier system of two liner equtions in two vriles, then suh equtions re lle

More information

18.06 Problem Set 4 Due Wednesday, Oct. 11, 2006 at 4:00 p.m. in 2-106

18.06 Problem Set 4 Due Wednesday, Oct. 11, 2006 at 4:00 p.m. in 2-106 8. Problem Set Due Wenesy, Ot., t : p.m. in - Problem Mony / Consier the eight vetors 5, 5, 5,..., () List ll of the one-element, linerly epenent sets forme from these. (b) Wht re the two-element, linerly

More information

Introduction to Laplace Transform Techniques in Circuit Analysis

Introduction to Laplace Transform Techniques in Circuit Analysis Unit 6 Introduction to Laplace Tranform Technique in Circuit Analyi In thi unit we conider the application of Laplace Tranform to circuit analyi. A relevant dicuion of the one-ided Laplace tranform i found

More information

Compiler Design. Fall Lexical Analysis. Sample Exercises and Solutions. Prof. Pedro C. Diniz

Compiler Design. Fall Lexical Analysis. Sample Exercises and Solutions. Prof. Pedro C. Diniz Univerity of Southern Cliforni Computer Siene Deprtment Compiler Deign Fll 6 Lexil Anlyi Smple Exerie nd Solution Prof. Pedro C. Dini USC / Informtion Siene Intitute 4676 Admirlty Wy, Suite Mrin del Rey,

More information

Chapter Gauss Quadrature Rule of Integration

Chapter Gauss Quadrature Rule of Integration Chpter 7. Guss Qudrture Rule o Integrtion Ater reding this hpter, you should e le to:. derive the Guss qudrture method or integrtion nd e le to use it to solve prolems, nd. use Guss qudrture method to

More information

CONTROL SYSTEMS LABORATORY ECE311 LAB 3: Control Design Using the Root Locus

CONTROL SYSTEMS LABORATORY ECE311 LAB 3: Control Design Using the Root Locus CONTROL SYSTEMS LABORATORY ECE311 LAB 3: Control Deign Uing the Root Locu 1 Purpoe The purpoe of thi lbortory i to deign cruie control ytem for cr uing the root locu. 2 Introduction Diturbnce D( ) = d

More information