Concept Category 4 (textbook ch. 8) Parametric Equations
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1 Concept Category 4 (textbook ch. 8) Parametric Equations
2 Parametric Equations Write parametric equations. Graph parametric equations. Determine an equivalent rectangular equation for parametric equations. Determine parametric equations for a rectangular equation. Determine the location of a moving object at a specific time. 2
3 It is the bottom of the ninth inning, with two outs and two men on base. The home team is losing by two runs. The batter swings and hits the baseball at 140 feet per second and at an angle of approximately 45 degrees to the horizontal. How far will the ball travel? Will it clear the fence for a game-winning home run? The outcome may depend partly on other factors (for example, the wind), but mathematicians can model the path of a projectile and predict approximately how far it will travel using parametric equations. 3
4 Algebra is really about relationships. How are things connected? Do they move together, or apart, or maybe they re completely independent? Normal equations assume an input to output connection. That is, we take an input (x=3), plug it into the relationship (y=x 2 ), and observe the result (y=9). But is that the only way to see a scenario? The setup y=x 2 implies that y only moves because of x. But it could be that y just coincidentally equals x 2, and some hidden factor is changing them both (the factor changes x to 3 while also changing y to 9). 4
5 As a real world example: For every degree above 70, our convenience store sells x bottles of sunscreen and x 2 pints of ice cream. We could write the algebra relationship like this: 2 ice cream sunscreen And it s correct but misleading! The equation implies sunscreen directly changes the demand for ice cream, when it s the hidden variable (temperature) that changed them both! 5
6 It s much better to write two separate equations sunscreen temperature 70 ice cream (t emperature 70) that directly point out the causality. The ideas temperature impacts ice cream and temperature impacts sunscreen clarify the situation, and we lose information by trying to factor away the common temperature portion. Parametric equations get us closer to the realworld relationship
7 Definition 7
8 8
9 Let s start with an easy one. Then create a rectangular equation 9
10 10
11 Solution: 11
12 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 12
13 Ex2) Graph the curve represented by the equations x 1 2 t, y t 2 3; 3 t 3. The rectangular equation is? 13
14 Ex2) Graph the curve represented by the equations x 1 2 t, y t 2 3; 3 t 3. The rectangular equation is y 4x 2 3, 3 2 x
15 Today s Agenda CC3 Mastery Check Error Analysis: 2 Model cards for CC3 Retake during lunch on Tuesday Copyright by Houghton Mifflin Company, Inc. All rights reserved. 15
16 Example: Sketch the curve given by x = t + 2 and y = t 2, 3 t 3. t x y y orientation of the curve x Copyright by Houghton Mifflin Company, Inc. All rights reserved. 16
17 Graphing Utility: Sketch the curve given by x = t + 2 and y = t 2, 3 t 3. Mode Menu: Set to parametric mode. Window Graph Table Copyright by Houghton Mifflin Company, Inc. All rights reserved. 17
18 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 18
19 Eliminating the parameter is a process for finding the rectangular equation (in x and y) of a curve represented by parametric equations. x = t + 2 y = t 2 t = x 2 Parametric equations Solve for t in one equation. y = (x 2) 2 Substitute into the second equation. y = (x 2) 2 Equation of a parabola with the vertex at (2, 0) Copyright by Houghton Mifflin Company, Inc. All rights reserved. 19
20 For your For information: your information pg. 2
21 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 21
22 Link: graphing conics for TIs AU/software/details/en/6D27F3EB7E354D8D BDA5543AF744D0E3/83conicgraphing 22
23 PARAMETRIC CURVES for Trigonometry What curve is represented by the following parametric equations? x = cos t y = sin t 0 t 2π
24 t (angles) x = cos t y = sin t 0 also
25 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 25
26 If we plot points, it appears the curve is a circle. We can confirm this by eliminating t.
27 Notice that, in this example, the parameter t can be interpreted as the angle as shown.
28 From CC2, Trig Identity: cos 2 t + sin 2 t = 1 thus x 2 + y 2 = 1 This is the rectangular equation Thus, the point (x, y) moves on the unit circle x 2 + y 2 = 1
29 Trigonometric Parametric xt ( ) 4 cos t y(t) 8sin t 0 t 2 a) Sketch b) Find the rectangular equation 29
30 Let s just use the simple input values t x(t) y(t)
31 31
32 (cos t) 2 (sin t) 2 1 x 4 cos t y 8sin t x y cos t 4 8 sin t Copyright by Houghton Mifflin Company, Inc. All rights reserved. 32
33 Trigonometric Parametric xt ( ) cos t 4 y(t) sin t 8 0 t 2 a) Sketch b) Find the rectangular equation 33
34 34
35 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 35
36 Trigonometric Parametric xt ( ) 4 cos t 4 y(t) 8sin t 8 0 t 2 a) Sketch b) Find the rectangular equation 36
37 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 37
38 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 38
39 Due 02/20th CC3 Model Cards Pick 2 problems Traveling at a speed of 10 knots, a ship proceeds south from its port for 2.5 hours and then changes course to true bearing of 130 degrees for 2 hours. At this time, how far from the port is the ship? *FYI: 1 knot = 1 nautical miles per hr = 1.15 miles per hr A plane is flying at a speed of miles per hour on a true bearing of 204 degrees. If the plane s groundspeed is miles per hour and its true bearing is 228 degrees, what are the speed and direction of the wind? The course for a boat race starts at point A and proceeds in the direction with true bearing of degrees to point B, then in the direction with true bearing of 44.8 degrees to point C, and finally back to point A. Point C lies kilometers directly east of point A. Find the total distance of the race course. 39
40 CC3 Model Cards Traveling at a speed of 10 knots, a ship proceeds south from its port for 2.5 hours and then changes course to true bearing of 130 degrees for 2 hours. At this time, how far from the port is the ship? distance: approx knots; direction: approx degrees Q2 = degrees A plane is flying at a speed of miles per hour on a true bearing of 204 degrees. If the plane s groundspeed is miles per hour and its true bearing is 228 degrees, what are the speed and direction of the wind? Distance: approx m/h; direction: approx degrees Q2 = degrees The course for a boat race starts at point A and proceeds in the direction with true bearing of degrees to point B, then in the direction with true bearing of 44.8 degrees to point C, and finally back to point A. Point C lies kilometers directly east of point A. Find the total distance of the race course. a is km; c is 95.71km; total = km 40
41 2/14 th Practice for CC4 Graph the curve represented by the equations, then find the rectangular equation for each: a] x 5cos t y 2 sin t 0 t 2 b x t t y t t 2 ] c t t 2 ] x(t) sin t y(t) 2 cos 0 2 d x t y t t t in ] 1 2 [0,1] e] x cos t 2 y sin t 3 0 t 2 f ] x 3cos t y 2 sin t t in [0, 2 ] 41
42 2 2 x y a] B] Copyright by Houghton Mifflin Company, Inc. All rights reserved. 42
43 B] solution for converting it to rectangular equation It is not possible to solve for x in this case, so we have to rewrite y y y 2t 1 1 2t y 1 2 t x 2 y 1 y y y 1 y y y Copyright by Houghton Mifflin Company, Inc. All rights reserved. 43
44 44
45 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 45
46 Happy Friday Monday Tuesday Ex) x(t) = 2sec t, y(t) = 4tan t *Sketch (it is not a circle or ellipse) 0 t 2 *Create a rectangular equation using the second trig identity: (sec t) 2 (tan t)
47 0 45 t x(t) = 2sec t y(t) = 4tan t no solution so don t bother 270 no solution so don t bother 315 Hope no one forgets this : sec t 1 cos t 47
48 2 2 (sec t) (tan t) 1 x y sec t tan t (x/ 2) (y/ 4) 1 48
49 49
50 Ex) x(t) = 2cot t, y(t) = 4csc t *Sketch (it is not a circle or ellipse) *Create a rectangular equation using the third trig identity: (csc t) 2 (cot t)
51 t x(t) = 2cot t y(t) = 4csc t cot t 1 tan t Just in case: 1 csc t sin t 51
52 2 2 (csc t) (cot t) 1 x y cot t csc t (y/ 4) (x/ 2) 1 which is : 2 2 (x/ 2) (y/ 4) 1 52
53 53
54 If an object is dropped, thrown, launched etc. at a certain angle and has gravity acting upon it, the equations for its position at time t can be written as: v cos t y gt v sin t h o x o horizontal position initial velocity angle measured from horizontal time vertical position gravitational constant which is 9.8 m/s 2 or 32 ft/s 2 initial height
55 Projectile: think parabola Copyright by Houghton Mifflin Company, Inc. All rights reserved. 55
56 56
57 Finding the parametric equations to describe the motion of a baseball A baseball is hit with an initial velocity of 140 ft/sec at an angle of 45 degrees to the horizontal, making contact 3 ft above the ground: 57
58 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 58
59 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 59
60 4. Cannot confirm that the hit was home run without knowing the size of the outfield. For simplicity s sake, we will use 400 ft as the distance between the outfield wall and home plate, and 10 feet for the height of the wall: set x = 400 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 60
61 Example 2 61
62 62
63 Example3) 63
64 By solving x, you will realize the ball will reach the fence in less than 3 seconds. So it will not clear the wall. 64
65 example 4) The center-field fence in a ballpark is 10 feet high and 400 feet from home plate. A baseball is hit at a point 3 feet above the ground and leaves the bat at a speed of 150 feet per second at an angle of 15. The parametric equations for its path are? Graph the path of the baseball. Is the hit a home run? y x Copyright by Houghton Mifflin Company, Inc. All rights reserved. 65
66 Application: The center-field fence in a ballpark is 10 feet high and 400 feet from home plate. A baseball is hit at a point 3 feet above the ground and leaves the bat at a speed of 150 feet per second at an angle of 15. The parametric equations for its path are x = 145t and y = t 16t 2. Graph the path of the baseball. Is the hit a home run? y (0, 3) The ball only traveled 364 feet and was not a home run. (364, 0) x Home Run Copyright by Houghton Mifflin Company, Inc. All rights reserved. 66
67 Practice Now 2/22 Routine: For each equation, create a rectangular equation, and sketch t,x,y chart optional 2 1] x t 1, y t 4 t 4 2 2]x t, y t 1 4 t 4 3] x 4 2 cos t, y 2 3sin t 0 t 2 4] x 5sec t, y 6 tan t 0 t 2 5] x 4 csc t, y 3cot t 0 t 2 67
68 Application Practice 68
69 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 69
70 3] Rectangular equation method 2 : x 2 t x y t 1 x 1 t 70
71 71
72 72
73 More Practice 2/23 a] x 5cos t 3 y 2 sin t 4 0 t 2 b x t y t t 2 ] c] x 2sec t 3 y 4 tan t 5 0 t 2 d] x 2 cot t 3 y 4 csc t 5 0 t 2 e x t y t t 2 ] F] Lisa hits a golf ball off the ground with a velocity of 50 ft./sec at an angle of 35 from the horizon. (a) Write a set of parametric equations to model this situation. (b) Find when and where the ball will hit the ground (c) Find the max. height of the ball. When does this occur? 73
74 B] D] E] 74
75 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 75
76 76
77 Quiz yourself (no notes) Sketch the parametric equations: Convert the parametric equations to rectangular equations: 77
78 78
79 CC4: Conics Circles Parabolas Ellipse Hyperbolas 79
80 Circles The set of all points that are the same distance from the center. Standard Equation: ( x h) ( y k) r CENTER: (h, k) RADIUS: r (square root) (h, k) r
81 Ellipses Salami is often cut obliquely to obtain elliptical slices, which are larger.
82 V a Center: (h,k) Ellipses Basically, an ellipse is a squished circle Standard Equation: (h, k) b CV (x - h) a c 2 = a 2 - b 2 (y - k) b (cos t) (sin t) 1 2 =1 Formula for the Foci 2 2 x h y k a b a: major radius: the longer radius; the vertices are located at the ends of the major radii b: minor radius: the shorter radius; the co-vertices are located their ends 1
83 Quick Check Error Analysis #1, 2, 3: Graph = 1 point Mastery Check next Thursday Rectangular eq. = 1 point If #1 to 3 are all correct: #4a correct = 3- a + b = 3+ all correct = 4+ 83
84 History Early Greek astronomers thought that the planets moved in circular orbits about an unmoving earth, since the circle is the simplest mathematical curve. In the 17th century, Johannes Kepler eventually discovered that each planet travels around the sun in an elliptical orbit with the sun at one of its foci.
85 Science On a far smaller scale, the electrons of an atom move in an approximately elliptical orbit with the nucleus at one focus.
86 Hyperbolas 2 2 (sec t) (tan t) (csc t) (cot t) 1 Looks like: two parabolas, back to back. Center: (h, k) Standard Equations: ( x h) a ( y k) 2 b 1 ( y k) a ( x h) 2 b 1 Opens LEFT and RIGHT (h, k) Opens UP and DOWN (h, k)
87 Hyperbolas Transverse Axis
88 There is a pattern 88
89 89
90 Sketch the Conics (Rectangular Eq.) c] x 2sec t 3 y 4 tan t 5 0 t 2 d] x 2cot t 3 y 4csc t 5 0 t 2 90
91 91
92 a x t y t Happy Friday Create a rectangular equation for each, then sketch: (label key features for each graph) 2 ] 3 1 b] x 3sec t 2 y 2 tan t 3 0 t 2 c] x 4 cos t 5 y 6sin t 2 0 t 2 d] x 7 cot t 1 y 3csc t 2 0 t 2 92
93 Create a rectangular equation for each graph, then create parametric equations 93
94 94
95 Copyright by Houghton Mifflin Company, Inc. All rights reserved. 95
96 2 2 (sec t) (tan t) 1 x 2 y 2 sec t tan t 3 4 3sec t x 2 4 tan t y (cos t) (sin t) 1 x 1 y cos t sin t cos t x 1 7 cos t 1 x 3sin t 3sec t 2 x 4 tan t 2 y 2 2 (csc t) (cot t) 1 You might have a different solution for this problem y 2 x 1 csc t cot t csc t y 2 4 cot t x 1 2 csc t 2 y 4 cot t 1 x y 96
97 2 2 x h y k a b 2 2 x h y k a b 2 2 y k x h b a Copyright by Houghton Mifflin Company, Inc. All rights reserved. 97
98 Sketch the equations: CC Final Study Guide x 1 1] y 2(3) 4 CC1] y 2 Log ( x 1) 4 o CC 2] y 2 sin( x 90 ) 4 o CC 2] y 2 cos( x 90 ) 4 CC y x 2 4] 2( 1) 4 CC x y 2 4] 2( 1) x 1 y 4 CC4] x 1 y 4 CC4] Know all these graphs and their key features for the finals 98
99 Horizontal asymptote Vertical Asymptote 99
100 Asymptotes 100
101 Mastery Check Thursday Mar. 8th Projectile Motion Kevin hits a baseball at 3 ft above the ground with an initial speed of 150ft/sec at an angle of 18 degrees with the horizontal: a) Write the parametric equations that represent the motion of the baseball b) What is the maximum height of the baseball? What is the time when it reaches its maximum height? How far is this from Kevin in the horizontal direction? c) When will it hit the ground? How far is this from Kevin in the horizontal direction? d) Will it clear a 20 ft wall that is 400 ft away? Create a sketch for this scenario. e) Create a rectangular equation 101
102 [CC1] Create an exponential or log equation for each graph [CC4] Create a rectangular, then parametric equations: 102
103 Mastery Check Thursday Mar. 8th Projectile Motion Answer Key Kevin hits a baseball at 3 ft above the ground with an initial speed of 150ft/sec at an angle of 18 degrees with the horizontal: a x t y t t o 2 o ] (150 cos18 ) 16 (150 sin18 ) 3 b] max height 36.53ft; t 1.45sec; about 206 ft away c]t 2.9sec; about 220 ft away o d ] No,if you solve t 400 (150cos18 ) t, then find y, y 7.35 ft only 2 x o x e] 16 (150 sin18 ) o cos cos18 o 103
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