Nuevo examen - 02 de Febrero de 2017 [280 marks]
|
|
- Branden Ramsey
- 5 years ago
- Views:
Transcription
1 Nuevo examen - 0 de Febrero de 0 [0 marks] Jar A contains three red marbles and five green marbles. Two marbles are drawn from the jar, one after the other, without replacement. a. Find the probability that (i) none of the marbles are green; (ii) exactly one marble is green. [ marks] (i) attempt to find P(red) P(red),, P(none green) = (= ) (ii) attempt to find P(red) P(green),, recognizing two ways to get one red, one green P(R) P(G), +, P(exactly one green) = 0 (= ) [ marks] Find the expected number of green marbles drawn from the jar. b. [ marks]
2 P(both green) = 0 (seen anywhere) correct substitution into formula for E(X) expected number of green marbles is 0 (= ), () [ marks] Jar B contains six red marbles and two green marbles. A fair six-sided die is tossed. If the score is or, a marble is drawn from jar A. Otherwise, a marble is drawn from jar B. c. (i) Write down the probability that the marble is drawn from jar B. (ii) Given that the marble was drawn from jar B, write down the probability that it is red. (i) P(jar B) = (= ) N (ii) P(red jar B) = (= ) N Given that the marble is red, find the probability that it was drawn from jar A. d. [ marks]
3 recognizing conditional probability P(A R), P(jar A and red) P(red), tree diagram attempt to multiply along either branch (may be seen on diagram) P(jar A and red) = (= ) attempt to multiply along other branch P(jar B and red) = (= ) adding the probabilities of two mutually exclusive paths P(red) = + correct substitution P(jar A red) = P(jar A red) = +, N () [ marks] A running club organizes a race to select girls to represent the club in a competition. The times taken by the group of girls to complete the race are shown in the table below. a. Find the value of p and of q.
4 attempt to find p 0 0, x = 0 p = 0 attempt to find q 0 0, q = 0 A girl is chosen at random. b. (i) Find the probability that the time she takes is less than minutes. (ii) Find the probability that the time she takes is at least minutes. [ marks] (i) (= ) N (ii) valid approach 0 + 0, (= ) [ marks] A girl is selected for the competition if she takes less than c. x minutes to complete the race. Given that 0% of the girls are not selected, (i) find the number of girls who are not selected; (ii) find x.
5 (i) attempt to find number of girls 0., are not selected (ii) 0 are selected () x = 0 Girls who are not selected, but took less than d. minutes to complete the race, are allowed another chance to be selected. The new times taken by these girls are shown in the cumulative frequency diagram below. (i) (ii) Write down the number of girls who were allowed another chance. Find the percentage of the whole group who were selected.
6 (i) 0 given second chance N (ii) 0 took less than 0 minutes () attempt to find their selected total (may be seen in % calculation) (= 0), 0+ their answer from (i) 0 ( %) N Bill and Andrea play two games of tennis. The probability that Bill wins the first game is. If Bill wins the first game, the probability that he wins the second game is. If Bill loses the first game, the probability that he wins the second game is. a. Copy and complete the following tree diagram. (Do not write on this page.) [ marks]
7 N Note: Award for each correct bold probability. [ marks] Find the probability that Bill wins the first game and Andrea wins the second game. b. multiplying along the branches (may be seen on diagram) 0 ( ) c. Find the probability that Bill wins at least one game.
8 c. METHOD multiplying along the branches (may be seen on diagram) adding their probabilities of three mutually exclusive paths correct simplification METHOD N () recognizing Bill wins at least one is complement of Andrea wins finding P (Andrea wins ) P (Andrea wins both) = () evidence of complement,, N + +, + + +, (= ) p, (R) Given that Bill wins at least one game, find the probability that he wins both games. d. [ marks] P (B wins both) evidence of recognizing conditional probability correct substitution (= ) [ marks] N (A) (R) P(A B), P (Bill wins both Bill wins at least one), tree diagram 0 (= ) Let A and B be independent events, where P(A) = 0. and P(B) = 0.. a. Find P(A B).
9 correct substitution P(A B) = 0. () b. Find P(A B). correct substitution () P(A B) = P(A B) = 0. c. On the following Venn diagram, shade the rion that represents A B. [ mark] N d. Find P(A B ). appropriate approach 0. 0., P(A) P( B ) P(A B ) = 0. (may be seen in Venn diagram)
10 Two events A and B are such that P(A) = 0. and P(A B) = 0.. a. Given that A and B are mutually exclusive, find P(B). correct approach () 0. = 0. + P(B), P(A B) = 0 P(B) = 0. b. Given that A and B are independent, find P(B). Correct expression for P(A B) (seen anywhere) P(A B) = 0.P(B), 0.x attempt to substitute into correct formula for P(A B) correct working P(A B) = 0. + P(B) P(A B), P(A B) = 0. + x 0.x () 0. = 0. + P(B) 0.P(B), 0.x = 0. P(B) = (= 0., exact) N Samantha goes to school five days a week. When it rains, the probability that she goes to school by bus is 0.. When it does not rain, the probability that she goes to school by bus is 0.. The probability that it rains on any given day is 0.. a. On a randomly selected school day, find the probability that Samantha goes to school by bus.
11 appropriate approach P(R B) + P( R B), tree diagram, one correct multiplication () 0. 0., 0. correct working () , P(bus) = 0.(exact) N b. Given that Samantha went to school by bus on Monday, find the probability that it was raining. [ marks] recognizing conditional probability P(A B) = P(A B) P(B) correct working [ marks] P(R B) =, 0.9 (R) c. In a randomly chosen school week, find the probability that Samantha goes to school by bus on exactly three days. recognizing binomial probability X B(n, p), ( ) (R) (0.), (0.) ( 0.) P(X = ) = 0. d. After n school days, the probability that Samantha goes to school by bus at least once is greater than 0.9. Find the smallest value of n. [ marks]
12 METHOD evidence of using complement (seen anywhere) P (none), 0.9 valid approach correct inequality (accept equation) METHOD N () valid approach using guess and check/trial and error finding P(X ) for various values of n seeing the cross over values for the probabilities recognising [ marks] N (R) P (none) > 0.9, P (none) < 0.0, P (none) = 0.9 (0.) n > 0.9, (0.) n = 0.0 n >.09 (accept n =.09) n = n =, P(X ) = 0.9, n =, P(X ) = > 0.9 n = Adam travels to school by car ( ) or by bicycle ( ). On any particular day he is equally likely to travel by car or by bicycle. The probability of being late ( L) for school is if he travels by car. The probability of being late for school is C if he travels by bicycle. This information is represented by the following tree diagram. B p Find the value of. a. correct working () p =
13 Find the probability that Adam will travel by car and be late for school. b. multiplying along correct branches P(C L) = () Find the probability that Adam will be late for school. c. multiplying along the other branch adding probabilities of their mutually exclusive paths correct working + + P(L) = (= ) () N Given that Adam is late for school, find the probability that he travelled by car. d. [ marks] recognizing conditional probability (seen anywhere) P(C L) correct substitution of their values into formula () P(C L) = [ marks] Adam will go to school three times next week. e. Find the probability that Adam will be late exactly once.
14 valid approach correct substitution correct working Total [ marks] X B (, ), ( ) ( ), ( ) () (), three ways it could happen ( ) ( ), + + ( ) ( ) ( ), Let and C D P(C) = k P(D) = k 0 < k < 0. be independent events, with and, where. Write down an expression for a.. k P(C D) in terms of P(C D) = k k P(C D) = k () b. Find P( C D). [ marks] METHOD finding their P( C D) (seen anywhere) () 0. 0., 0. 0., 0.0 correct substitution into conditional probability formula () METHOD recognizing finding their P( C ) = P(C) (only if first line seen) () P( D) =, [ marks] C P( D) 0. P( C D) = 0. Total [ marks] C P( C D) = P( C ) k, 0. P( C D) = 0. ( k)( k ) k
15 At a large school, students are required to learn at least one language, Spanish or French. It is known that 9a. % of the students learn Spanish, and 0% learn French. Find the percentage of students who learn both Spanish and French. valid approach Venn diagram with intersection, union formula, P(S F) = (accept % ) At a large school, students are required to learn at least one language, Spanish or French. It is known that 9b. % of the students learn Spanish, and 0% learn French. Find the percentage of students who learn Spanish, but not French. valid approach involving subtraction Venn diagram, 0 (accept 0% ) 9c. At a large school, students are required to learn at least one language, Spanish or French. It is known that [ marks] % of the students learn Spanish, and 0% learn French. At this school, % of the students are girls, and % of the girls learn Spanish. A student is chosen at random. Let G be the event that the student is a girl, and let S be the event that the student learns Spanish. (i) Find P(G S). (ii) Show that G and S are not independent.
16 (i) valid approach tree diagram, multiplying probabilities, P(S G) P(G) correct calculation () P(G S) = 0. (exact) N (ii) valid reasoning, with words, symbols or numbers (seen anywhere) P(G) P(S) P(G S), P(S G) P(S), not equal, one correct value P(G) P(S) = 0.9, P(S G) = 0., G and S are not independent AG N0 [ marks] R At a large school, students are required to learn at least one language, Spanish or French. It is known that 9d. % of the students learn Spanish, and 0% learn French. At this school, % of the students are girls, and % of the girls learn Spanish. A boy is chosen at random. Find the probability that he learns Spanish. [ marks]
17 METHOD % are boys (seen anywhere) P(B) = 0. appropriate approach P(girl and Spanish) + P(boy and Spanish) = P(Spanish) correct approach to find P(boy and Spanish) P(B S)= P(S) P(G S), P(B S)= P(S B) P(B), 0.0 correct substitution x = 0., 0.x = 0.0 correct manipulation P(S B) = () () P(Spanish boy) = P(Spanish boy) = 0. [0., 0.] N [ marks] METHOD % are boys (seen anywhere) 0. used in tree diagram appropriate approach tree diagram, correctly labelled branches on tree diagram () () first branches are boy/girl, second branches are Spanish/not Spanish correct substitution x = 0. correct manipulation 0.x = 0.0, P(S B) = [ marks] () () P(Spanish boy) = P(Spanish boy) = 0. [0., 0.],
18 Bag A contains three white balls and four red balls. Two balls are chosen at random without replacement. 0a. (i) Copy and complete the following tree diagram. [ marks] (ii) Find the probability that two white balls are chosen. (i), and (, and ) (ii) multiplying along the correct branches (may be seen on diagram) (= ) [ marks] N () Bag A contains three white balls and four red balls. Two balls are chosen at random without replacement. 0b. Bag B contains four white balls and three red balls. When two balls are chosen at random without replacement from bag B, the probability that they are both white is. [ marks] A standard die is rolled. If or is obtained, two balls are chosen without replacement from bag A, otherwise they are chosen from bag B. Find the probability that the two balls are white.
19 P(bagA) = (= ), P(bagB) = (= ) (seen anywhere) appropriate approach P(WW A) + P(WW B) ()() correct calculation + + [ marks] 0 P(W) = (= ), N Bag A contains three white balls and four red balls. Two balls are chosen at random without replacement. 0c. Bag B contains four white balls and three red balls. When two balls are chosen at random without replacement from bag B, the probability that they are both white is. A standard die is rolled. If or is obtained, two balls are chosen without replacement from bag A, otherwise they are chosen from bag B. Given that both balls are white, find the probability that they were chosen from bag A. recognizing conditional probability P(A B), P(B) P(A WW) = P(WW A) P(WW) correct numerator () P(A WW) =, correct denominator, probability (= ) 0 N ()
20 Events A and B are such that P(A) = 0., P(B) = 0. and P(A B) = 0.. The values q, r, s and t represent probabilities. Write down the value of t. a. [ mark] t = 0. N [ mark] (i) Show that b. r = 0.. (ii) Write down the value of q and of s. [ marks] (i) correct values , r = 0. (ii) q = 0., s = 0. [ marks] AG N0 (i) Write down c. P( B ). (ii) Find P(A B ). [ marks] (i) 0. N (ii) P(A ) = A B [ marks]
21 A box contains six red marbles and two blue marbles. Anna selects a marble from the box. She replaces the marble and then selects a second marble. a. Write down the probability that the first marble Anna selects is red. [ mark] Note: In this question, method marks may be awarded for selecting without replacement, as noted in the examples. P(R) = (= ) [ mark] N Find the probability that Anna selects two red marbles. b. attempt to find P(Red) P(Red) P(R) P(R),, P(R) = (= ) 9 Find the probability that one marble is red and one marble is blue. c. [ marks]
22 METHOD attempt to find P(Red) P(Blue) P(R) P(B),, recognizing two ways to get one red, one blue P(RB) + P(BR), ( ), + [ marks] METHOD recognizing that P(R, B) is P(B) P(R) attempt to find P(R) and P(B) P(R) = ; P(B) = [ marks] P(R,B) = (= ),, P(R,B) = (= ) Let f(x) = + kx +, where x k Z. Find the values of k such that a. f(x) = 0 has two equal roots.
23 METHOD evidence of discriminant b ac, discriminant = 0 correct substitution into discriminant k, k = 0 k = ± METHOD N recognizing that equal roots means perfect square attempt to complete the square, ( + kx + ) x correct working (x + k) = k k = ±, N (R) Each value of k is equally likely for b. k. Find the probability that f(x) = 0 has no roots. evidence of appropriate approach b ac < 0 correct working for k < k <, k <, list all correct values of k p = A N
24 The diagram below shows the probabilities for events A and B, with P( A ) = p. Write down the value of p. a. [ mark] p = N [ mark] Find b. P(B). [ marks] multiplying along the branches 0, adding products of probabilities of two mutually exclusive paths [ marks] P(B) = 0 (= ) 0, Find c. P( A B). [ marks]
25 appropriate approach which must include A (may be seen on diagram) P( A B) P(B) P(A B) P(B) ) (do not accept A 0 P( B) = P( B) = (= ) A () [ marks] Consider the events A and B, where P(A) = 0., P(B) = 0. and P(A B) = 0.. The Venn diagram below shows the events A and B, and the probabilities p, q and r. Write down the value of a. (i) p ; (ii) q ; (iii) r. [ marks] (i) p = 0. N (ii) q = 0. N (iii) r = 0. N [ marks] Find the value of b. P(A B ).
26 P(A B ) = A Note: Award for an unfinished answer such as c. Hence, or otherwise, show that the events A and B are not independent. [ mark] valid reason 0., R thus, A and B are not independent AG N0 [ mark] José travels to school on a bus. On any day, the probability that José will miss the bus is. If he misses his bus, the probability that he will be late for school is. If he does not miss his bus, the probability that he will be late is. Let E be the event he misses his bus and F the event he is late for school. The information above is shown on the following tree diagram. Find a. (i) P(E F) ; (ii) P(F).
27 (i) N (ii) evidence of multiplying along the branches, adding probabilities of two mutually exclusive paths ( ) + ( ), ( ) + ( ) P(F) = Find the probability that b. (i) José misses his bus and is not late for school; (ii) José missed his bus, given that he is late for school. [ marks] (i) () (ii) recognizing this is P(E F) (= ) [ marks] A N c. The cost for each day that José catches the bus is euros. José goes to school on Monday and Tuesday. Copy and complete the probability distribution table. [ marks] A N [ marks]
28 The cost for each day that José catches the bus is euros. José goes to school on Monday and Tuesday. d. Find the expected cost for José for both days. correct substitution into E(X) formula E(X) = (euros) 9, In a class of 00 boys, boys play football and boys play rugby. Each boy must play at least one sport from football and rugby. (i) a. (ii) Find the number of boys who play both sports. Write down the number of boys who play only rugby. [ marks] (i) evidence of substituting into n(a B) = n(a) + n(b) n(a B) + 00, Venn diagram 0 (ii) N [ marks] b. One boy is selected at random. (i) Find the probability that he plays only one sport. (ii) Given that the boy selected plays only one sport, find the probability that he plays rugby.
29 (i) METHOD evidence of using complement, Venn diagram p, (= ) METHOD attempt to find P(only one sport), Venn diagram (ii) 0 0 (= ) 0 9 (= ) 00 A Let A be the event that a boy plays football and B be the event that a boy plays rugby. c. Explain why A and B are not mutually exclusive. valid reason in words or symbols (R) P(A B) = 0 if mutually exclusive, P(A B) 0 if not mutually exclusive correct statement in words or symbols P(A B) = 0., P(A B) P(A) + P(B), P(A) + P(B) >, some students play both sports, sets intersect d. Show that A and B are not independent. [ marks] valid reason for independence P(A B) = P(A) P(B), P(B A) = P(B) correct substitution N [ marks] 00, (R)
30 Jan plays a game where she tosses two fair six-sided dice. She wins a prize if the sum of her scores is. a. Jan tosses the two dice once. Find the probability that she wins a prize. [ marks] outcomes (seen anywhere, even in denominator) () valid approach of listing ways to get sum of, showing at least two pairs (, )(, ), (, )(, ), (, )(, ), (, )(, ), lattice diagram P(prize) = (= ) 9 N [ marks] b. Jan tosses the two dice times. Find the probability that she wins prizes. recognizing binomial probability B(, ), binomial pdf, 9 ( ) ( ) 9 ( 9 ) P( prizes) = 0.0 In a group of students, take art and take music. One student takes neither art nor music. The Venn diagram below shows the events art and music. The values p, q, r and s represent numbers of students. (i) 9a. Write down the value of s. (ii) Find the value of q. (iii) Write down the value of p and of r. [ marks]
31 (i) s = N (ii) evidence of appropriate approach, + q = q = (iii) p =, r = [ marks] 9b. (i) (ii) A student is selected at random. Given that the student takes music, write down the probability the student takes art. Hence, show that taking music and taking art are not independent events. (i) P(art music) = (ii) METHOD P(art) = (= ) A evidence of correct reasoning R the events are not independent AG N0 METHOD P(art) P(music) = 9 (= ) evidence of correct reasoning R the events are not independent AG N0 9c. Two students are selected at random, one after the other. Find the probability that the first student takes only music and the second student takes only art.
32 P(first takes only music) = P(second takes only art) = evidence of valid approach P(music and art) = 0 (= ) 0 (seen anywhere) (seen anywhere) A company uses two machines, A and B, to make boxes. Machine A makes 0% of the boxes. 0% of the boxes made by machine A pass inspection. 90% of the boxes made by machine B pass inspection. A box is selected at random. 0a. Find the probability that it passes inspection. [ marks] evidence of valid approach involving A and B P(A pass) + P(B pass), tree diagram correct expression () P(pass) = P(pass) = 0. [ marks] 0b. The company would like the probability that a box passes inspection to be 0.. Find the percentage of boxes that should be made by machine B to achieve this.
33 evidence of recognizing complement (seen anywhere) P(B) = x, P(A) = x, P(B), 00 x, x + y = evidence of valid approach 0.( x) + 0.9x, 0.x + 0.9y correct expression 0. = 0.( x) + 0.9x, = 0., 0.x + 0.9y = 0. 0% from B The Venn diagram below shows events A and B where P(A) = 0., P(A B) = 0. and P(A B) = 0.. The values m, n, p and q are probabilities. (i) Write down the value of n. a. (ii) Find the value of m, of p, and of q. (i) n = 0. N (ii) m = 0., p = 0., q = 0. N Find b. P( B ).
34 appropriate approach P( B ) = P(B), m + q, (n + p) P( B ) = 0. Two fair -sided dice, one red and one green, are thrown. For each die, the faces are labelled,,,. The score for each die is the number which lands face down. a. List the pairs of scores that give a sum of. [ marks] three correct pairs N (, ), (, ), (, ), RG, RG, RG [ marks] The probability distribution for the sum of the scores on the two dice is shown below. b. [ marks] Find the value of p, of q, and of r. p =, q =, r = [ marks] N Fred plays a game. He throws two fair -sided dice four times. He wins a prize if the sum is on three or more throws. c. Find the probability that Fred wins a prize. [ marks]
35 let X be the number of times the sum of the dice is evidence of valid approach X B(n, p), tree diagram, sets of outcomes produce a win one correct parameter n =, p = 0., q = 0. Fred wins prize is P(X ) () () appropriate approach to find probability M complement, summing probabilities, using a CDF function correct substitution () 0.99,, , + probability of winning = 0.00 ( ) N [ marks] Let A and B be independent events, where P(A) = 0. and P(B) = x. Write down an expression for a. P(A B). [ mark] P(A B) = P(A) P(B)(= 0.x) [ mark] N b. Given that P(A B) = 0., (i) find x ; (ii) find P(A B).
36 (i) evidence of using P(A B) = P(A) + P(B) P(A)P(B) correct substitution 0. = 0. + x 0.x, 0. = 0.x x = 0. (ii) P(A B) = 0. N c. Hence, explain why A and B are not mutually exclusive. [ mark] valid reason, with reference to P(A B) R N P(A B) 0 [ mark] There are 0 students in a classroom. Each student plays only one sport. The table below gives their sport and gender. a. One student is selected at random. (i) Calculate the probability that the student is a male or is a tennis player. (ii) Given that the student selected is female, calculate the probability that the student does not play football. (i) correct calculation (ii) correct calculation, 0 P(male or tennis) = , () () P(not football female) = Two students are selected at random. Calculate the probability that neither student plays football. b. [ marks]
37 b. P(first not football) =, 0 P(second not football) = 0 9 P(neither football) = 0 P(neither football) = 0 0 [ marks] 0 9 N Consider the independent events A and B. Given that. P(B) = P(A), and P(A B) = 0., find P(B). [ marks]
38 METHOD for independence P(A B) = P(A) P(B) expression for P(A B), indicating P(B) = P(A) () P(A) P(A), x x (R) substituting into P(A B) = P(A) + P(B) P(A B) correct substitution 0. = x + x x, 0. = P(A) + P(A) P(A)P(A) correct solutions to the equation 0.,. (accept the single answer 0.) P(B) = 0. [ marks] METHOD N for independence P(A B) = P(A) P(B) expression for P(A B), indicating P(A) = P(B) () P(B) P(B), x x (R) (A) substituting into P(A B) = P(A) + P(B) P(A B) correct substitution 0. = 0.x + x 0.x, 0. = 0.P(B) + P(B) 0.P(B)P(B) correct solutions to the equation (A) 0.,. (accept the single answer 0.) P(B) = 0. (accept x = 0. if x set up as P(B) ) N [ marks]
39 The letters of the word PROBABILITY are written on cards as shown below. Two cards are drawn at random without replacement. Let A be the event the first card drawn is the letter A. Let B be the event the second card drawn is the letter B. Find a. P(A). [ mark] P(A) = [ mark] N Find b. P(B A). P(B A) = 0 A Find c. P(A B). [ marks] recognising that P(A B) = P(A) P(B A) correct values P(A B) = [ marks] P(A B) = 0 () 0 N
40 Two standard six-sided dice are tossed. A diagram representing the sample space is shown below. Let X be the sum of the scores on the two dice. a. (i) Find P(X = ). (ii) Find P(X > ). (iii) Find P(X = X > ). [ marks] (i) number of ways of getting X = is P(X = ) = (ii) number of ways of getting X > is P(X > ) = (= ) (iii) P(X = X > ) = (= ) [ marks] A b. Elena plays a game where she tosses two dice. If the sum is, she wins points. If the sum is greater than, she wins point. If the sum is less than, she loses k points. Find the value of k for which the game is fair. [ marks]
41 attempt to find P(X < ) M fair game if E(W) = 0 (may be seen anywhere) attempt to substitute into E(X) formula M 0 ( ) + ( ) k( ) correct substitution into E(W) = 0 0 ( ) + ( ) k( ) = 0 work towards solving + 0k = 0 [ marks] P(X < ) = 0 = 0k k = (=.) 0 M N R A four-sided die has three blue faces and one red face. The die is rolled. Let B be the event a blue face lands down, and R be the event a red face lands down. a. Write down (i) P(B); (ii) P(R). (i) P(B) = N (ii) P(R) = N
42 If the blue face lands down, the die is not rolled again. If the red face lands down, the die is rolled once again. This is b. represented by the following tree diagram, where p, s, t are probabilities. Find the value of p, of s and of t. p = N s =, t = N c. Guiseppi plays a game where he rolls the die. If a blue face lands down, he scores and is finished. If the red face lands down, he scores and rolls one more time. Let X be the total score obtained. (i) Show that P(X = ) =. (ii) Find P(X = ). [ marks] (i) P(X = ) = P (getting and ) = = AG N0 (ii) P(X = ) = + (or ) = [ marks] () (i) Construct a probability distribution table for X. d. (ii) Calculate the expected value of X. [ marks]
43 (i) A (ii) evidence of using E(X) = xp(x = x) E(X) = ( ) + ( ) () = (= ) [ marks] If the total score is, Guiseppi wins e. $0. If the total score is, Guiseppi gets nothing. Guiseppi plays the game twice. Find the probability that he wins exactly $0. win $0 scores one time, other time P() P() = (seen anywhere) evidence of recognising there are different ways of winning $0 P() P() + P() P(), ( ), P(win $0) = (= ) N International Baccalaureate Organization 0 International Baccalaureate - Baccalauréat International - Bachillerato Internacional Printed for Colio Aleman de Barranquilla
Math SL Day 66 Probability Practice [196 marks]
Math SL Day 66 Probability Practice [96 marks] Events A and B are independent with P(A B) = 0.2 and P(A B) = 0.6. a. Find P(B). valid interpretation (may be seen on a Venn diagram) P(A B) + P(A B), 0.2
More informationTopic 5: Probability. 5.4 Combined Events and Conditional Probability Paper 1
Topic 5: Probability Standard Level 5.4 Combined Events and Conditional Probability Paper 1 1. In a group of 16 students, 12 take art and 8 take music. One student takes neither art nor music. The Venn
More informationTopic 5 Part 3 [257 marks]
Topic 5 Part 3 [257 marks] Let 0 3 A = ( ) and 2 4 4 0 B = ( ). 5 1 1a. AB. 1b. Given that X 2A = B, find X. The following table shows the probability distribution of a discrete random variable X. 2a.
More information, x {1, 2, k}, where k > 0. Find E(X). (2) (Total 7 marks)
1.) The probability distribution of a discrete random variable X is given by 2 x P(X = x) = 14, x {1, 2, k}, where k > 0. Write down P(X = 2). Show that k = 3. (1) Find E(X). (Total 7 marks) 2.) In a group
More information1. Consider the independent events A and B. Given that P(B) = 2P(A), and P(A B) = 0.52, find P(B). (Total 7 marks)
1. Consider the independent events A and B. Given that P(B) = 2P(A), and P(A B) = 0.52, find P(B). (Total 7 marks) 2. In a school of 88 boys, 32 study economics (E), 28 study history (H) and 39 do not
More information$ and det A = 14, find the possible values of p. 1. If A =! # Use your graph to answer parts (i) (iii) below, Working:
& 2 p 3 1. If A =! # $ and det A = 14, find the possible values of p. % 4 p p" Use your graph to answer parts (i) (iii) below, (i) Find an estimate for the median score. (ii) Candidates who scored less
More informationMath SL Distribution Practice [75 marks]
Math SL Distribution Practice [75 marks] The weights, W, of newborn babies in Australia are normally distributed with a mean 3.41 kg and standard deviation 0.57 kg. A newborn baby has a low birth weight
More informationSolutionbank S1 Edexcel AS and A Level Modular Mathematics
file://c:\users\buba\kaz\ouba\s1_5_a_1.html Exercise A, Question 1 For each of the following experiments, identify the sample space and find the probability of the event specified. Throwing a six sided
More informationPaper1Practice [289 marks]
PaperPractice [89 marks] INSTRUCTIONS TO CANDIDATE Write your session number in the boxes above. Do not open this examination paper until instructed to do so. You are not permitted access to any calculator
More informationIB Math High Level Year 1 Probability Practice 1
IB Math High Level Year Probability Practice Probability Practice. A bag contains red balls, blue balls and green balls. A ball is chosen at random from the bag and is not replaced. A second ball is chosen.
More informationOCR Statistics 1 Probability. Section 1: Introducing probability
OCR Statistics Probability Section : Introducing probability Notes and Examples These notes contain subsections on Notation Sample space diagrams The complement of an event Mutually exclusive events Probability
More informationUNIT 5 ~ Probability: What Are the Chances? 1
UNIT 5 ~ Probability: What Are the Chances? 1 6.1: Simulation Simulation: The of chance behavior, based on a that accurately reflects the phenomenon under consideration. (ex 1) Suppose we are interested
More informationIndependence 1 2 P(H) = 1 4. On the other hand = P(F ) =
Independence Previously we considered the following experiment: A card is drawn at random from a standard deck of cards. Let H be the event that a heart is drawn, let R be the event that a red card is
More information3.2 Probability Rules
3.2 Probability Rules The idea of probability rests on the fact that chance behavior is predictable in the long run. In the last section, we used simulation to imitate chance behavior. Do we always need
More informationIntroduction to Probability 2017/18 Supplementary Problems
Introduction to Probability 2017/18 Supplementary Problems Problem 1: Let A and B denote two events with P(A B) 0. Show that P(A) 0 and P(B) 0. A A B implies P(A) P(A B) 0, hence P(A) 0. Similarly B A
More informationEvent A: at least one tail observed A:
Chapter 3 Probability 3.1 Events, sample space, and probability Basic definitions: An is an act of observation that leads to a single outcome that cannot be predicted with certainty. A (or simple event)
More informationF71SM STATISTICAL METHODS
F71SM STATISTICAL METHODS RJG SUMMARY NOTES 2 PROBABILITY 2.1 Introduction A random experiment is an experiment which is repeatable under identical conditions, and for which, at each repetition, the outcome
More informationLECTURE NOTES by DR. J.S.V.R. KRISHNA PRASAD
.0 Introduction: The theory of probability has its origin in the games of chance related to gambling such as tossing of a coin, throwing of a die, drawing cards from a pack of cards etc. Jerame Cardon,
More information( ) 2 + ( 2 x ) 12 = 0, and explain why there is only one
IB Math SL Practice Problems - Algebra Alei - Desert Academy 0- SL Practice Problems Algebra Name: Date: Block: Paper No Calculator. Consider the arithmetic sequence, 5, 8,,. (a) Find u0. (b) Find the
More informationMath Exam 1 Review. NOTE: For reviews of the other sections on Exam 1, refer to the first page of WIR #1 and #2.
Math 166 Fall 2008 c Heather Ramsey Page 1 Math 166 - Exam 1 Review NOTE: For reviews of the other sections on Exam 1, refer to the first page of WIR #1 and #2. Section 1.5 - Rules for Probability Elementary
More information2011 Pearson Education, Inc
Statistics for Business and Economics Chapter 3 Probability Contents 1. Events, Sample Spaces, and Probability 2. Unions and Intersections 3. Complementary Events 4. The Additive Rule and Mutually Exclusive
More informationProbability. VCE Maths Methods - Unit 2 - Probability
Probability Probability Tree diagrams La ice diagrams Venn diagrams Karnough maps Probability tables Union & intersection rules Conditional probability Markov chains 1 Probability Probability is the mathematics
More informationPresentation on Theo e ry r y o f P r P o r bab a il i i l t i y
Presentation on Theory of Probability Meaning of Probability: Chance of occurrence of any event In practical life we come across situation where the result are uncertain Theory of probability was originated
More informationThe enumeration of all possible outcomes of an experiment is called the sample space, denoted S. E.g.: S={head, tail}
Random Experiment In random experiments, the result is unpredictable, unknown prior to its conduct, and can be one of several choices. Examples: The Experiment of tossing a coin (head, tail) The Experiment
More informationCHAPTER 3 PROBABILITY TOPICS
CHAPTER 3 PROBABILITY TOPICS 1. Terminology In this chapter, we are interested in the probability of a particular event occurring when we conduct an experiment. The sample space of an experiment is the
More informationConditional Probability
Conditional Probability Terminology: The probability of an event occurring, given that another event has already occurred. P A B = ( ) () P A B : The probability of A given B. Consider the following table:
More information4/17/2012. NE ( ) # of ways an event can happen NS ( ) # of events in the sample space
I. Vocabulary: A. Outcomes: the things that can happen in a probability experiment B. Sample Space (S): all possible outcomes C. Event (E): one outcome D. Probability of an Event (P(E)): the likelihood
More informationEdexcel past paper questions
Edexcel past paper questions Statistics 1 Discrete Random Variables Past examination questions Discrete Random variables Page 1 Discrete random variables Discrete Random variables Page 2 Discrete Random
More informationTopic -2. Probability. Larson & Farber, Elementary Statistics: Picturing the World, 3e 1
Topic -2 Probability Larson & Farber, Elementary Statistics: Picturing the World, 3e 1 Probability Experiments Experiment : An experiment is an act that can be repeated under given condition. Rolling a
More information(a) Fill in the missing probabilities in the table. (b) Calculate P(F G). (c) Calculate P(E c ). (d) Is this a uniform sample space?
Math 166 Exam 1 Review Sections L.1-L.2, 1.1-1.7 Note: This review is more heavily weighted on the new material this week: Sections 1.5-1.7. For more practice problems on previous material, take a look
More informationSTA 2023 EXAM-2 Practice Problems From Chapters 4, 5, & Partly 6. With SOLUTIONS
STA 2023 EXAM-2 Practice Problems From Chapters 4, 5, & Partly 6 With SOLUTIONS Mudunuru Venkateswara Rao, Ph.D. STA 2023 Fall 2016 Venkat Mu ALL THE CONTENT IN THESE SOLUTIONS PRESENTED IN BLUE AND BLACK
More informationTOPIC 12 PROBABILITY SCHEMATIC DIAGRAM
TOPIC 12 PROBABILITY SCHEMATIC DIAGRAM Topic Concepts Degree of Importance References NCERT Book Vol. II Probability (i) Conditional Probability *** Article 1.2 and 1.2.1 Solved Examples 1 to 6 Q. Nos
More informationFind the value of n in order for the player to get an expected return of 9 counters per roll.
. A biased die with four faces is used in a game. A player pays 0 counters to roll the die. The table below shows the possible scores on the die, the probability of each score and the number of counters
More informationCh 14 Randomness and Probability
Ch 14 Randomness and Probability We ll begin a new part: randomness and probability. This part contain 4 chapters: 14-17. Why we need to learn this part? Probability is not a portion of statistics. Instead
More informationThe possible experimental outcomes: 1, 2, 3, 4, 5, 6 (Experimental outcomes are also known as sample points)
Chapter 4 Introduction to Probability 1 4.1 Experiments, Counting Rules and Assigning Probabilities Example Rolling a dice you can get the values: S = {1, 2, 3, 4, 5, 6} S is called the sample space. Experiment:
More informationChapter. Probability
Chapter 3 Probability Section 3.1 Basic Concepts of Probability Section 3.1 Objectives Identify the sample space of a probability experiment Identify simple events Use the Fundamental Counting Principle
More informationProbability- describes the pattern of chance outcomes
Chapter 6 Probability the study of randomness Probability- describes the pattern of chance outcomes Chance behavior is unpredictable in the short run, but has a regular and predictable pattern in the long
More informationProbability and Statistics Notes
Probability and Statistics Notes Chapter One Jesse Crawford Department of Mathematics Tarleton State University (Tarleton State University) Chapter One Notes 1 / 71 Outline 1 A Sketch of Probability and
More information3 PROBABILITY TOPICS
Chapter 3 Probability Topics 135 3 PROBABILITY TOPICS Figure 3.1 Meteor showers are rare, but the probability of them occurring can be calculated. (credit: Navicore/flickr) Introduction It is often necessary
More informationIf S = {O 1, O 2,, O n }, where O i is the i th elementary outcome, and p i is the probability of the i th elementary outcome, then
1.1 Probabilities Def n: A random experiment is a process that, when performed, results in one and only one of many observations (or outcomes). The sample space S is the set of all elementary outcomes
More informationProbabilistic models
Probabilistic models Kolmogorov (Andrei Nikolaevich, 1903 1987) put forward an axiomatic system for probability theory. Foundations of the Calculus of Probabilities, published in 1933, immediately became
More informationDescriptive Statistics and Probability Test Review Test on May 4/5
Descriptive Statistics and Probability Test Review Test on May 4/5 1. The following frequency distribution of marks has mean 4.5. Mark 1 2 3 4 5 6 7 Frequency 2 4 6 9 x 9 4 Find the value of x. Write down
More informationSection 13.3 Probability
288 Section 13.3 Probability Probability is a measure of how likely an event will occur. When the weather forecaster says that there will be a 50% chance of rain this afternoon, the probability that it
More informationDISCRETE VARIABLE PROBLEMS ONLY
DISCRETE VARIABLE PROBLEMS ONLY. A biased die with four faces is used in a game. A player pays 0 counters to roll the die. The table below shows the possible scores on the die, the probability of each
More informationIf all the outcomes are equally likely, then the probability an event A happening is given by this formula:
Understanding Probability Probability Scale and Formula PROBIBILITY Probability is a measure of how likely an event is to happen. A scale is used from zero to one, as shown below. Examples The probability
More informationBusiness Statistics MBA Pokhara University
Business Statistics MBA Pokhara University Chapter 3 Basic Probability Concept and Application Bijay Lal Pradhan, Ph.D. Review I. What s in last lecture? Descriptive Statistics Numerical Measures. Chapter
More informationstudents all of the same gender. (Total 6 marks)
January Exam Review: Math 11 IB HL 1. A team of five students is to be chosen at random to take part in a debate. The team is to be chosen from a group of eight medical students and three law students.
More informationChapter 5 : Probability. Exercise Sheet. SHilal. 1 P a g e
1 P a g e experiment ( observing / measuring ) outcomes = results sample space = set of all outcomes events = subset of outcomes If we collect all outcomes we are forming a sample space If we collect some
More informationTopic 3 Part 4 [163 marks]
Topic 3 Part 4 [163 marks] Consider the statement p: If a quadrilateral is a square then the four sides of the quadrilateral are equal. Write down the inverse of statement p in words. 1a. Write down the
More informationSTA 2023 EXAM-2 Practice Problems. Ven Mudunuru. From Chapters 4, 5, & Partly 6. With SOLUTIONS
STA 2023 EXAM-2 Practice Problems From Chapters 4, 5, & Partly 6 With SOLUTIONS Mudunuru, Venkateswara Rao STA 2023 Spring 2016 1 1. A committee of 5 persons is to be formed from 6 men and 4 women. What
More informationName: Exam 2 Solutions. March 13, 2017
Department of Mathematics University of Notre Dame Math 00 Finite Math Spring 07 Name: Instructors: Conant/Galvin Exam Solutions March, 07 This exam is in two parts on pages and contains problems worth
More informationSouth Pacific Form Seven Certificate
141/1 South Pacific Form Seven Certificate INSTRUCTIONS MATHEMATICS WITH STATISTICS 2015 QUESTION and ANSWER BOOKLET Time allowed: Two and a half hours Write your Student Personal Identification Number
More informationProbability 5-4 The Multiplication Rules and Conditional Probability
Outline Lecture 8 5-1 Introduction 5-2 Sample Spaces and 5-3 The Addition Rules for 5-4 The Multiplication Rules and Conditional 5-11 Introduction 5-11 Introduction as a general concept can be defined
More informationIntermediate Math Circles November 8, 2017 Probability II
Intersection of Events and Independence Consider two groups of pairs of events Intermediate Math Circles November 8, 017 Probability II Group 1 (Dependent Events) A = {a sales associate has training} B
More informationH2 Mathematics Probability ( )
H2 Mathematics Probability (208 209) Practice Questions. For events A and B it is given that P(A) 0.7, P(B) 0. and P(A B 0 )0.8. Find (i) P(A \ B 0 ), [2] (ii) P(A [ B), [2] (iii) P(B 0 A). [2] For a third
More informationIntro to Probability Day 4 (Compound events & their probabilities)
Intro to Probability Day 4 (Compound events & their probabilities) Compound Events Let A, and B be two event. Then we can define 3 new events as follows: 1) A or B (also A B ) is the list of all outcomes
More informationExam III Review Math-132 (Sections 7.1, 7.2, 7.3, 7.4, 7.5, 7.6, 8.1, 8.2, 8.3)
1 Exam III Review Math-132 (Sections 7.1, 7.2, 7.3, 7.4, 7.5, 7.6, 8.1, 8.2, 8.3) On this exam, questions may come from any of the following topic areas: - Union and intersection of sets - Complement of
More informationWhat is Probability? Probability. Sample Spaces and Events. Simple Event
What is Probability? Probability Peter Lo Probability is the numerical measure of likelihood that the event will occur. Simple Event Joint Event Compound Event Lies between 0 & 1 Sum of events is 1 1.5
More informationMTH 201 Applied Mathematics Sample Final Exam Questions. 1. The augmented matrix of a system of equations (in two variables) is:
MTH 201 Applied Mathematics Sample Final Exam Questions 1. The augmented matrix of a system of equations (in two variables) is: 2 1 6 4 2 12 Which of the following is true about the system of equations?
More informationChapter 6: Probability The Study of Randomness
Chapter 6: Probability The Study of Randomness 6.1 The Idea of Probability 6.2 Probability Models 6.3 General Probability Rules 1 Simple Question: If tossing a coin, what is the probability of the coin
More informationLecture Lecture 5
Lecture 4 --- Lecture 5 A. Basic Concepts (4.1-4.2) 1. Experiment: A process of observing a phenomenon that has variation in its outcome. Examples: (E1). Rolling a die, (E2). Drawing a card form a shuffled
More informationProbability the chance that an uncertain event will occur (always between 0 and 1)
Quantitative Methods 2013 1 Probability as a Numerical Measure of the Likelihood of Occurrence Probability the chance that an uncertain event will occur (always between 0 and 1) Increasing Likelihood of
More informationPaper2Practice [303 marks]
PaperPractice [0 marks] Consider the expansion of (x + ) 10. 1a. Write down the number of terms in this expansion. [1 mark] 11 terms N1 [1 mark] 1b. Find the term containing x. evidence of binomial expansion
More informationTerm Definition Example Random Phenomena
UNIT VI STUDY GUIDE Probabilities Course Learning Outcomes for Unit VI Upon completion of this unit, students should be able to: 1. Apply mathematical principles used in real-world situations. 1.1 Demonstrate
More information2 TWO OR MORE RANDOM VARIABLES
2 TWO OR MORE RANDOM VARIABLES Many problems in probability theory relate to two or more random variables. You might have equipment which is controlled by two computers and you are interested in knowing
More informationProbabilistic models
Kolmogorov (Andrei Nikolaevich, 1903 1987) put forward an axiomatic system for probability theory. Foundations of the Calculus of Probabilities, published in 1933, immediately became the definitive formulation
More informationYear 10 Mathematics Probability Practice Test 1
Year 10 Mathematics Probability Practice Test 1 1 A letter is chosen randomly from the word TELEVISION. a How many letters are there in the word TELEVISION? b Find the probability that the letter is: i
More informationMutually Exclusive Events
172 CHAPTER 3 PROBABILITY TOPICS c. QS, 7D, 6D, KS Mutually Exclusive Events A and B are mutually exclusive events if they cannot occur at the same time. This means that A and B do not share any outcomes
More informationProbability deals with modeling of random phenomena (phenomena or experiments whose outcomes may vary)
Chapter 14 From Randomness to Probability How to measure a likelihood of an event? How likely is it to answer correctly one out of two true-false questions on a quiz? Is it more, less, or equally likely
More informationDescriptive Statistics Class Practice [133 marks]
Descriptive Statistics Class Practice [133 marks] The weekly wages (in dollars) of 80 employees are displayed in the cumulative frequency curve below. 1a. (i) (ii) Write down the median weekly wage. Find
More informationpaper 2 most likely questions May 2018 [327 marks]
paper 2 most likely questions May 2018 [327 marks] Let f(x) = 6x2 4, for 0 x 7. e x 1a. Find the x-intercept of the graph of f. 1b. The graph of f has a maximum at the point A. Write down the coordinates
More informationSample Space: Specify all possible outcomes from an experiment. Event: Specify a particular outcome or combination of outcomes.
Chapter 2 Introduction to Probability 2.1 Probability Model Probability concerns about the chance of observing certain outcome resulting from an experiment. However, since chance is an abstraction of something
More informationConditional probability
CHAPTER 4 Conditional probability 4.1. Introduction Suppose there are 200 men, of which 100 are smokers, and 100 women, of which 20 are smokers. What is the probability that a person chosen at random will
More informationP(A) = Definitions. Overview. P - denotes a probability. A, B, and C - denote specific events. P (A) - Chapter 3 Probability
Chapter 3 Probability Slide 1 Slide 2 3-1 Overview 3-2 Fundamentals 3-3 Addition Rule 3-4 Multiplication Rule: Basics 3-5 Multiplication Rule: Complements and Conditional Probability 3-6 Probabilities
More informationOutline Conditional Probability The Law of Total Probability and Bayes Theorem Independent Events. Week 4 Classical Probability, Part II
Week 4 Classical Probability, Part II Week 4 Objectives This week we continue covering topics from classical probability. The notion of conditional probability is presented first. Important results/tools
More informationStatistics for Engineers
Statistics for Engineers Antony Lewis http://cosmologist.info/teaching/stat/ Starter question Have you previously done any statistics? 1. Yes 2. No 54% 46% 1 2 BOOKS Chatfield C, 1989. Statistics for
More informationAxioms of Probability
Sample Space (denoted by S) The set of all possible outcomes of a random experiment is called the Sample Space of the experiment, and is denoted by S. Example 1.10 If the experiment consists of tossing
More information1. A machine produces packets of sugar. The weights in grams of thirty packets chosen at random are shown below.
No Gdc 1. A machine produces packets of sugar. The weights in grams of thirty packets chosen at random are shown below. Weight (g) 9.6 9.7 9.8 9.9 30.0 30.1 30. 30.3 Frequency 3 4 5 7 5 3 1 Find unbiased
More informationThe probability of an event is viewed as a numerical measure of the chance that the event will occur.
Chapter 5 This chapter introduces probability to quantify randomness. Section 5.1: How Can Probability Quantify Randomness? The probability of an event is viewed as a numerical measure of the chance that
More informationConditional Probability. CS231 Dianna Xu
Conditional Probability CS231 Dianna Xu 1 Boy or Girl? A couple has two children, one of them is a girl. What is the probability that the other one is also a girl? Assuming 50/50 chances of conceiving
More informationChapter 13, Probability from Applied Finite Mathematics by Rupinder Sekhon was developed by OpenStax College, licensed by Rice University, and is
Chapter 13, Probability from Applied Finite Mathematics by Rupinder Sekhon was developed by OpenStax College, licensed by Rice University, and is available on the Connexions website. It is used under a
More informationLecture 6 Probability
Lecture 6 Probability Example: When you toss a coin, there are only two possible outcomes, heads and tails. What if we toss a coin 4 times? Figure below shows the results of tossing a coin 5000 times twice.
More information6.041/6.431 Spring 2009 Quiz 1 Wednesday, March 11, 7:30-9:30 PM. SOLUTIONS
6.0/6.3 Spring 009 Quiz Wednesday, March, 7:30-9:30 PM. SOLUTIONS Name: Recitation Instructor: Question Part Score Out of 0 all 0 a 5 b c 5 d 5 e 5 f 5 3 a b c d 5 e 5 f 5 g 5 h 5 Total 00 Write your solutions
More informationOutline. Probability. Math 143. Department of Mathematics and Statistics Calvin College. Spring 2010
Outline Math 143 Department of Mathematics and Statistics Calvin College Spring 2010 Outline Outline 1 Review Basics Random Variables Mean, Variance and Standard Deviation of Random Variables 2 More Review
More informationBasic Concepts of Probability
Probability Probability theory is the branch of math that deals with random events Probability is used to describe how likely a particular outcome is in a random event the probability of obtaining heads
More informationTheoretical Probability (pp. 1 of 6)
Theoretical Probability (pp. 1 of 6) WHAT ARE THE CHANCES? Objectives: Investigate characteristics and laws of probability. Materials: Coin, six-sided die, four-color spinner divided into equal sections
More informationExample. What is the sample space for flipping a fair coin? Rolling a 6-sided die? Find the event E where E = {x x has exactly one head}
Chapter 7 Notes 1 (c) Epstein, 2013 CHAPTER 7: PROBABILITY 7.1: Experiments, Sample Spaces and Events Chapter 7 Notes 2 (c) Epstein, 2013 What is the sample space for flipping a fair coin three times?
More informationSolutionbank S1 Edexcel AS and A Level Modular Mathematics
Heinemann Solutionbank: Statistics S Page of Solutionbank S Exercise A, Question Write down whether or not each of the following is a discrete random variable. Give a reason for your answer. a The average
More informationProbability Review Answers (a) (0.45, 45 %) (A1)(A1) (C2) 200 Note: Award (A1) for numerator, (A1) for denominator.
Probability Review Answers 90. (a) (0.45, 45 %) (A)(A) (C) 00 Note: Award (A) for numerator, (A) for denominator. 60 (b) ( 0.6, 0.667, 66.6%, 66.6...%, 66.7 %) (A)(A)(ft) (C) 90 Notes: Award (A) for numerator,
More informationBasic Concepts of Probability
Probability Probability theory is the branch of math that deals with unpredictable or random events Probability is used to describe how likely a particular outcome is in a random event the probability
More informationDept. of Linguistics, Indiana University Fall 2015
L645 Dept. of Linguistics, Indiana University Fall 2015 1 / 34 To start out the course, we need to know something about statistics and This is only an introduction; for a fuller understanding, you would
More informationStatistical Theory 1
Statistical Theory 1 Set Theory and Probability Paolo Bautista September 12, 2017 Set Theory We start by defining terms in Set Theory which will be used in the following sections. Definition 1 A set is
More informationACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 2 MATH00040 SEMESTER / Probability
ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 2 MATH00040 SEMESTER 2 2017/2018 DR. ANTHONY BROWN 5.1. Introduction to Probability. 5. Probability You are probably familiar with the elementary
More informationMATH STUDENT BOOK. 12th Grade Unit 9
MATH STUDENT BOOK 12th Grade Unit 9 Unit 9 COUNTING PRINCIPLES MATH 1209 COUNTING PRINCIPLES INTRODUCTION 1. PROBABILITY DEFINITIONS, SAMPLE SPACES, AND PROBABILITY ADDITION OF PROBABILITIES 11 MULTIPLICATION
More information2.4. Conditional Probability
2.4. Conditional Probability Objectives. Definition of conditional probability and multiplication rule Total probability Bayes Theorem Example 2.4.1. (#46 p.80 textbook) Suppose an individual is randomly
More informationELEG 3143 Probability & Stochastic Process Ch. 1 Probability
Department of Electrical Engineering University of Arkansas ELEG 3143 Probability & Stochastic Process Ch. 1 Probability Dr. Jingxian Wu wuj@uark.edu OUTLINE 2 Applications Elementary Set Theory Random
More informationMATH2206 Prob Stat/20.Jan Weekly Review 1-2
MATH2206 Prob Stat/20.Jan.2017 Weekly Review 1-2 This week I explained the idea behind the formula of the well-known statistic standard deviation so that it is clear now why it is a measure of dispersion
More informationCourse: ESO-209 Home Work: 1 Instructor: Debasis Kundu
Home Work: 1 1. Describe the sample space when a coin is tossed (a) once, (b) three times, (c) n times, (d) an infinite number of times. 2. A coin is tossed until for the first time the same result appear
More informationMidterm Review Honors ICM Name: Per: Remember to show work to receive credit! Circle your answers! Sets and Probability
Midterm Review Honors ICM Name: Per: Remember to show work to receive credit! Circle your answers! Unit 1 Sets and Probability 1. Let U denote the set of all the students at Green Hope High. Let D { x
More informationWeek 2. Section Texas A& M University. Department of Mathematics Texas A& M University, College Station 22 January-24 January 2019
Week 2 Section 1.2-1.4 Texas A& M University Department of Mathematics Texas A& M University, College Station 22 January-24 January 2019 Oğuz Gezmiş (TAMU) Topics in Contemporary Mathematics II Week2 1
More information