PHYS PRACTICE EXAM 2

Size: px
Start display at page:

Download "PHYS PRACTICE EXAM 2"

Transcription

1 PHYS 1800 PRACTICE EXAM Pa I Muliple Choice Quesions [ ps each] Diecions: Cicle he one alenaive ha bes complees he saemen o answes he quesion. Unless ohewise saed, assume ideal condiions (no ai esisance, unifom gaviy, ec.) 1) Which of he following is NOT a uni fo angle? (A) deg (B) ad (C) ev (D) pm ) A wheel spins 30 imes in 6 seconds. Is peiod of evoluion equals (A) 0. sec (B) 5 sec (C) 6 sec (D) 30 sec 3) A ca moves a consan speed couneclockwise along a cicula ack. Wha is he diecion of he cenipeal foce acing on he ca when i eaches poin P? P (A) (B) (C) (D) 4) A change o ansfe of momenum is known as (A) enegy. (B) foce. (C) impulse. (D) wok. 5) A ball is dopped fom a vey all building. Ignoe ficion. As he ball falls, which of he following quaniies is conseved? (A) Momenum only. (B) Mechanical enegy only. (C) Boh momenum and mechanical enegy. (D) Neihe momenum no mechanical enegy.

2 6) A guy hows a bowling ball along a bowling alley. As i avels owad he pins, he ball has which of he following kineic enegies? (A) Tanslaional kineic enegy only. (B) Roaional kineic enegy only. (C) Boh anslaional and oaional kineic enegy. (D) Neihe anslaional no oaional kineic enegy 7) A bulle is sho fom a ifle. A he insan ha he bulle begins moving, wha is he elaionship beween he momenum of he bulle (magniude p B ) and he momenum of he ifle (magniude p R )? (A) p B p R (B) p B > p R (C) p B < p R (D) No enough info. 8) A solid ball and a hollow ball of equal mass and equal oue adius sa a he op of a amp. When hey ae eleased, he balls oll o he boom. Which of wo will each he boom fis? (A) The solid ball. (B) The hollow ball. (C) They each he boom simulaneously. (D) No enough info. 9) An ice skae is spinning upigh wih he ams ouseched. As she pulls he ams inwad, which of he following quaniies emains consan? (A) angula speed (B) angula displacemen (C) angula momenum (D) angula velociy 10) The Fis Condiion of Saic Equilibium pevens which of he following moions? (A) Roaion only. (B) Tanslaion only. (C) Tanslaion and oaion only. (D) Tanslaion and vibaion only.

3 Pa II Wod Poblems [0 ps each] Diecions: Show you wok o eceive full cedi. Box you final answe and ecod is appopiae uni. Poblem 1 A wheel iniially uning a 000 pm unifomly inceases is speed o 6600 pm in 9.00 sec. Calculae (A) he angula acceleaion of he wheel in ad/s. (B) he numbe of evoluions uned by he wheel duing he 9.00-sec ineval.

4 Poblem A 1.00 m C B 0.75 m A bead (mass kg) is able o slide along a cuved wie as shown in he diagam. (A) The bead has a downwad speed of m/s a poin A (a a heigh of 1.00 m above poin B). Calculae he bead s speed a poin C (a a heigh of 0.75 m above poin B) if hee is no ficion pesen. (B) Suppose ha ficion is pesen. The bead sas a poin A wih a speed of m/s and slides o poin C whee i sops momenaily (befoe i slides back down). Calculae he enegy los by he bead in sliding fom poin A o poin C.

5 Poblem 3 A kg bulle moving hoizonally a 00 m/s sikes and passes hough a kg in can siing on a able. Immediaely afe impac, he can has a hoizonal speed of m/s. (A) Daw a momenum consevaion ( befoe and afe ) diagam. (B) Calculae he velociy of he bulle immediaely afe he collision. (C) Calculae he impulse expeienced by he can as a esul of he collision.

6 Poblem 4 35 cable 0.80 m 700 N A.00-mee long unifom beam weighs 500 N and suppos a 700-N load a one end. The beam is hinged o a wall and is held a es by a cable. (A) Calculae he ension in he cable. (B) Calculae he hoizonal foce acing on he beam fom he hinge. (C) Calculae he veical foce acing on he beam fom he hinge.

7 Fomulas and Consans Gm1m F ne ma w mg f µn F gav d x v s av v av a av G N m /kg x i + 1 v a v f vi + a x 1 ( v + v g 9.8 m/s i f ) v fy v iy g y iy 1 v g v fy viy g y x v ix d θ v ω ω π v a ω T c F c mac 1 ev π ad 360 v GM π v a T α T ω f ω i + α 1 1 θ ( ω f + ωi ) ω f ω i + α θ θ ωi + α W F x cosθ W µ n x f k P E K 1 mv U mgy gav U 1 elasic kx E K + U E 1 + W f E p mv p m v p F ne τ F sinθ τ ne Iα K o L Iω 1 Iω

WORK POWER AND ENERGY Consevaive foce a) A foce is said o be consevaive if he wok done by i is independen of pah followed by he body b) Wok done by a consevaive foce fo a closed pah is zeo c) Wok done

More information

Circular Motion. Radians. One revolution is equivalent to which is also equivalent to 2π radians. Therefore we can.

Circular Motion. Radians. One revolution is equivalent to which is also equivalent to 2π radians. Therefore we can. 1 Cicula Moion Radians One evoluion is equivalen o 360 0 which is also equivalen o 2π adians. Theefoe we can say ha 360 = 2π adians, 180 = π adians, 90 = π 2 adians. Hence 1 adian = 360 2π Convesions Rule

More information

KINEMATICS OF RIGID BODIES

KINEMATICS OF RIGID BODIES KINEMTICS OF RIGID ODIES In igid body kinemaics, we use he elaionships govening he displacemen, velociy and acceleaion, bu mus also accoun fo he oaional moion of he body. Descipion of he moion of igid

More information

Today - Lecture 13. Today s lecture continue with rotations, torque, Note that chapters 11, 12, 13 all involve rotations

Today - Lecture 13. Today s lecture continue with rotations, torque, Note that chapters 11, 12, 13 all involve rotations Today - Lecue 13 Today s lecue coninue wih oaions, oque, Noe ha chapes 11, 1, 13 all inole oaions slide 1 eiew Roaions Chapes 11 & 1 Viewed fom aboe (+z) Roaional, o angula elociy, gies angenial elociy

More information

2. v = 3 4 c. 3. v = 4c. 5. v = 2 3 c. 6. v = 9. v = 4 3 c

2. v = 3 4 c. 3. v = 4c. 5. v = 2 3 c. 6. v = 9. v = 4 3 c Vesion 074 Exam Final Daf swinney (55185) 1 This pin-ou should have 30 quesions. Muliple-choice quesions may coninue on he nex column o page find all choices befoe answeing. 001 10.0 poins AballofmassM

More information

Relative and Circular Motion

Relative and Circular Motion Relaie and Cicula Moion a) Relaie moion b) Cenipeal acceleaion Mechanics Lecue 3 Slide 1 Mechanics Lecue 3 Slide 2 Time on Video Pelecue Looks like mosly eeyone hee has iewed enie pelecue GOOD! Thank you

More information

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics 1114: Unit 5 Hand-out Homework (Answers) Physics 1114: Unit 5 Hand-out Homewok (Answes) Poblem set 1 1. The flywheel on an expeimental bus is otating at 420 RPM (evolutions pe minute). To find (a) the angula velocity in ad/s (adians/second),

More information

P h y s i c s F a c t s h e e t

P h y s i c s F a c t s h e e t P h y s i c s F a c s h e e Sepembe 2001 Numbe 20 Simple Hamonic Moion Basic Conceps This Facshee will:! eplain wha is mean by simple hamonic moion! eplain how o use he equaions fo simple hamonic moion!

More information

Potential Energy and Conservation of Energy

Potential Energy and Conservation of Energy Potential Enegy and Consevation of Enegy Consevative Foces Definition: Consevative Foce If the wok done by a foce in moving an object fom an initial point to a final point is independent of the path (A

More information

b) (5) What average force magnitude was applied by the students working together?

b) (5) What average force magnitude was applied by the students working together? Geneal Physics I Exam 3 - Chs. 7,8,9 - Momentum, Rotation, Equilibium Nov. 3, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults

More information

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet Linea and angula analogs Linea Rotation x position x displacement v velocity a T tangential acceleation Vectos in otational motion Use the ight hand ule to detemine diection of the vecto! Don t foget centipetal

More information

Exam 3: Equation Summary

Exam 3: Equation Summary MAACHUETT INTITUTE OF TECHNOLOGY Depatment of Physics Physics 8. TEAL Fall Tem 4 Momentum: p = mv, F t = p, Fext ave t= t f t = Exam 3: Equation ummay = Impulse: I F( t ) = p Toque: τ =,P dp F P τ =,P

More information

Physics 30: Chapter 2 Exam Momentum & Impulse

Physics 30: Chapter 2 Exam Momentum & Impulse Physics 30: Chaper 2 Exam Momenum & Impulse Name: Dae: Mark: /29 Numeric Response. Place your answers o he numeric response quesions, wih unis, in he blanks a he side of he page. (1 mark each) 1. A golfer

More information

PHYS 1410, 11 Nov 2015, 12:30pm.

PHYS 1410, 11 Nov 2015, 12:30pm. PHYS 40, Nov 205, 2:30pm. A B = AB cos φ x = x 0 + v x0 t + a 2 xt 2 a ad = v2 2 m(v2 2 v) 2 θ = θ 0 + ω 0 t + 2 αt2 L = p fs µ s n 0 + αt K = 2 Iω2 cm = m +m 2 2 +... m +m 2 +... p = m v and L = I ω ω

More information

Physics 207 Lecture 13

Physics 207 Lecture 13 Physics 07 Lecue 3 Physics 07, Lecue 3, Oc. 8 Agenda: Chape 9, finish, Chape 0 Sa Chape 9: Moenu and Collision Ipulse Cene of ass Chape 0: oaional Kineaics oaional Enegy Moens of Ineia Paallel axis heoe

More information

Suggested Practice Problems (set #2) for the Physics Placement Test

Suggested Practice Problems (set #2) for the Physics Placement Test Deparmen of Physics College of Ars and Sciences American Universiy of Sharjah (AUS) Fall 014 Suggesed Pracice Problems (se #) for he Physics Placemen Tes This documen conains 5 suggesed problems ha are

More information

ÖRNEK 1: THE LINEAR IMPULSE-MOMENTUM RELATION Calculate the linear momentum of a particle of mass m=10 kg which has a. kg m s

ÖRNEK 1: THE LINEAR IMPULSE-MOMENTUM RELATION Calculate the linear momentum of a particle of mass m=10 kg which has a. kg m s MÜHENDİSLİK MEKANİĞİ. HAFTA İMPULS- MMENTUM-ÇARPIŞMA Linea oenu of a paicle: The sybol L denoes he linea oenu and is defined as he ass ies he elociy of a paicle. L ÖRNEK : THE LINEAR IMPULSE-MMENTUM RELATIN

More information

Exam 3: Equation Summary

Exam 3: Equation Summary MAACHUETT INTITUTE OF TECHNOLOGY Depatment of Physics Physics 8. TEAL Fall Tem 4 Momentum: p = mv, F t = p, Fext ave t= t f t = Exam 3: Equation ummay = Impulse: I F( t ) = p Toque: τ =,P dp F P τ =,P

More information

1. VELOCITY AND ACCELERATION

1. VELOCITY AND ACCELERATION 1. VELOCITY AND ACCELERATION 1.1 Kinemaics Equaions s = u + 1 a and s = v 1 a s = 1 (u + v) v = u + as 1. Displacemen-Time Graph Gradien = speed 1.3 Velociy-Time Graph Gradien = acceleraion Area under

More information

Physics 1A (b) Fall 2010: FINAL Version A 1. Comments:

Physics 1A (b) Fall 2010: FINAL Version A 1. Comments: Physics A (b) Fall 00: FINAL Vesion A Name o Initials: Couse 3-digit Code Comments: Closed book. No wok needs to be shown fo multiple-choice questions.. An 80 kg man is one fouth of the way up a 0 m ladde

More information

Dynamics of Rotational Motion

Dynamics of Rotational Motion Dynamics of Rotational Motion Toque: the otational analogue of foce Toque = foce x moment am τ = l moment am = pependicula distance though which the foce acts a.k.a. leve am l l l l τ = l = sin φ = tan

More information

Rotational Motion: Statics and Dynamics

Rotational Motion: Statics and Dynamics Physics 07 Lectue 17 Goals: Lectue 17 Chapte 1 Define cente of mass Analyze olling motion Intoduce and analyze toque Undestand the equilibium dynamics of an extended object in esponse to foces Employ consevation

More information

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 13, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Physics 2001/2051 Moments of Inertia Experiment 1

Physics 2001/2051 Moments of Inertia Experiment 1 Physics 001/051 Momens o Ineia Expeimen 1 Pelab 1 Read he ollowing backgound/seup and ensue you ae amilia wih he heoy equied o he expeimen. Please also ill in he missing equaions 5, 7 and 9. Backgound/Seup

More information

Experiment 09: Angular momentum

Experiment 09: Angular momentum Expeiment 09: Angula momentum Goals Investigate consevation of angula momentum and kinetic enegy in otational collisions. Measue and calculate moments of inetia. Measue and calculate non-consevative wok

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

PHYS 1114, Lecture 21, March 6 Contents:

PHYS 1114, Lecture 21, March 6 Contents: PHYS 1114, Lectue 21, Mach 6 Contents: 1 This class is o cially cancelled, being eplaced by the common exam Tuesday, Mach 7, 5:30 PM. A eview and Q&A session is scheduled instead duing class time. 2 Exam

More information

Page 1 o 13 1. The brighes sar in he nigh sky is α Canis Majoris, also known as Sirius. I lies 8.8 ligh-years away. Express his disance in meers. ( ligh-year is he disance coered by ligh in one year. Ligh

More information

Physics 101 Lecture 6 Circular Motion

Physics 101 Lecture 6 Circular Motion Physics 101 Lectue 6 Cicula Motion Assist. Pof. D. Ali ÖVGÜN EMU Physics Depatment www.aovgun.com Equilibium, Example 1 q What is the smallest value of the foce F such that the.0-kg block will not slide

More information

Physics 201 Homework 4

Physics 201 Homework 4 Physics 201 Homewok 4 Jan 30, 2013 1. Thee is a cleve kitchen gadget fo dying lettuce leaves afte you wash them. 19 m/s 2 It consists of a cylindical containe mounted so that it can be otated about its

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving.

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving. Chapte 5 Fiction When an object is in motion it is usually in contact with a viscous mateial (wate o ai) o some othe suface. So fa, we have assumed that moving objects don t inteact with thei suoundings

More information

Multiple choice questions [100 points] As shown in the figure, a mass M is hanging by three massless strings from the ceiling of a room.

Multiple choice questions [100 points] As shown in the figure, a mass M is hanging by three massless strings from the ceiling of a room. Multiple choice questions [00 points] Answe all of the following questions. Read each question caefully. Fill the coect ule on you scanton sheet. Each coect answe is woth 4 points. Each question has exactly

More information

Hoizontal Cicula Motion 1. A paticle of mass m is tied to a light sting and otated with a speed v along a cicula path of adius. If T is tension in the sting and mg is gavitational foce on the paticle then,

More information

Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) , PART A PHYSICS

Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) ,  PART A PHYSICS Pena Towe, oad No, Conacos Aea, isupu, Jamshedpu 83, Tel (657)89, www.penaclasses.com AIEEE PAT A PHYSICS Physics. Two elecic bulbs maked 5 W V and W V ae conneced in seies o a 44 V supply. () W () 5 W

More information

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 10, 2012 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Physics 2001 Problem Set 5 Solutions

Physics 2001 Problem Set 5 Solutions Physics 2001 Poblem Set 5 Solutions Jeff Kissel Octobe 16, 2006 1. A puck attached to a sting undegoes cicula motion on an ai table. If the sting beaks at the point indicated in the figue, which path (A,

More information

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer. Kiangsu-Chekiang College (Shatin) F:EasteHolidaysAssignmentAns.doc Easte Holidays Assignment Answe Fom 6B Subject: Physics. (a) State the conditions fo a body to undego simple hamonic motion. ( mak) (a)

More information

Physics 101 Fall 2006: Exam #1- PROBLEM #1

Physics 101 Fall 2006: Exam #1- PROBLEM #1 Physics 101 Fall 2006: Exam #1- PROBLEM #1 1. Problem 1. (+20 ps) (a) (+10 ps) i. +5 ps graph for x of he rain vs. ime. The graph needs o be parabolic and concave upward. ii. +3 ps graph for x of he person

More information

Lecture 16 (Momentum and Impulse, Collisions and Conservation of Momentum) Physics Spring 2017 Douglas Fields

Lecture 16 (Momentum and Impulse, Collisions and Conservation of Momentum) Physics Spring 2017 Douglas Fields Lecure 16 (Momenum and Impulse, Collisions and Conservaion o Momenum) Physics 160-02 Spring 2017 Douglas Fields Newon s Laws & Energy The work-energy heorem is relaed o Newon s 2 nd Law W KE 1 2 1 2 F

More information

Physics 201 Lecture 18

Physics 201 Lecture 18 Phsics 0 ectue 8 ectue 8 Goals: Define and anale toque ntoduce the coss poduct Relate otational dnamics to toque Discuss wok and wok eneg theoem with espect to otational motion Specif olling motion (cente

More information

Movie Review Part One due Tuesday (in class) please print

Movie Review Part One due Tuesday (in class) please print Movie Review Pat One due Tuesday (in class) please pint Test in class on Fiday. You may stat at 8:30 if you want. (The topic of powe is not on test.) Chaptes 4-6 Main Ideas in Class Today Afte class, you

More information

2002 November 14 Exam III Physics 191

2002 November 14 Exam III Physics 191 November 4 Exam III Physics 9 Physical onsans: Earh s free-fall acceleraion = g = 9.8 m/s ircle he leer of he single bes answer. quesion is worh poin Each 3. Four differen objecs wih masses: m = kg, m

More information

Physics 1A (a) Fall 2010: FINAL Version A 1. Comments:

Physics 1A (a) Fall 2010: FINAL Version A 1. Comments: Physics A (a) Fall 00: FINAL Vesion A Name o Initials: Couse 3-digit Code Comments: Closed book. No wok needs to be shown fo multiple-choice questions.. A helicopte is taveling at 60 m/s at a constant

More information

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Physics 4A Chapter 8: Dynamics II Motion in a Plane Physics 4A Chapte 8: Dynamics II Motion in a Plane Conceptual Questions and Example Poblems fom Chapte 8 Conceptual Question 8.5 The figue below shows two balls of equal mass moving in vetical cicles.

More information

SUMMARY GENERAL STRATEGY IMPORTANT CONCEPTS APPLICATIONS. Problem Solving. Motion Diagrams. Pictorial Representation

SUMMARY GENERAL STRATEGY IMPORTANT CONCEPTS APPLICATIONS. Problem Solving. Motion Diagrams. Pictorial Representation The goal of Chape 1 has been o inoduce he fundamenal conceps of moion. GENERL STRTEGY Moion Diagams Help visualize moion. Povide a ool fo finding acceleaion vecos. Dos show posiions a equal ime inevals.

More information

Circular Motion. Mr. Velazquez AP/Honors Physics

Circular Motion. Mr. Velazquez AP/Honors Physics Cicula Motion M. Velazquez AP/Honos Physics Objects in Cicula Motion Accoding to Newton s Laws, if no foce acts on an object, it will move with constant speed in a constant diection. Theefoe, if an object

More information

2001 November 15 Exam III Physics 191

2001 November 15 Exam III Physics 191 1 November 15 Eam III Physics 191 Physical Consans: Earh s free-fall acceleraion = g = 9.8 m/s 2 Circle he leer of he single bes answer. quesion is worh 1 poin Each 3. Four differen objecs wih masses:

More information

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once. Honos Physics Fall, 2016 Cicula Motion & Toque Test Review Name: M. Leonad Instuctions: Complete the following woksheet. SHOW ALL OF YOUR WORK ON A SEPARATE SHEET OF PAPER. 1. Detemine whethe each statement

More information

PHYS 2135 Exam I February 13, 2018

PHYS 2135 Exam I February 13, 2018 Exam Total /200 PHYS 2135 Exam I Febuay 13, 2018 Name: Recitation Section: Five multiple choice questions, 8 points each Choose the best o most nealy coect answe Fo questions 6-9, solutions must begin

More information

1121 T Question 1

1121 T Question 1 1121 T1 2008 Question 1 ( aks) You ae cycling, on a long staight path, at a constant speed of 6.0.s 1. Anothe cyclist passes you, tavelling on the sae path in the sae diection as you, at a constant speed

More information

156 There are 9 books stacked on a shelf. The thickness of each book is either 1 inch or 2

156 There are 9 books stacked on a shelf. The thickness of each book is either 1 inch or 2 156 Thee ae 9 books sacked on a shelf. The hickness of each book is eihe 1 inch o 2 F inches. The heigh of he sack of 9 books is 14 inches. Which sysem of equaions can be used o deemine x, he numbe of

More information

Momentum is conserved if no external force

Momentum is conserved if no external force Goals: Lectue 13 Chapte 9 v Employ consevation of momentum in 1 D & 2D v Examine foces ove time (aka Impulse) Chapte 10 v Undestand the elationship between motion and enegy Assignments: l HW5, due tomoow

More information

When a mass moves because of a force, we can define several types of problem.

When a mass moves because of a force, we can define several types of problem. Mechanics Lectue 4 3D Foces, gadient opeato, momentum 3D Foces When a mass moves because of a foce, we can define seveal types of poblem. ) When we know the foce F as a function of time t, F=F(t). ) When

More information

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points PHYSICS 1210 Exam 2 Univesity of Wyoming 14 Mach ( Day!) 2013 150 points This test is open-note and closed-book. Calculatos ae pemitted but computes ae not. No collaboation, consultation, o communication

More information

Principles of Physics I

Principles of Physics I Pinciples of Physics I J. M. Veal, Ph. D. vesion 8.05.24 Contents Linea Motion 3. Two scala equations........................ 3.2 Anothe scala equation...................... 3.3 Constant acceleation.......................

More information

Lecture 4 Kinetics of a particle Part 3: Impulse and Momentum

Lecture 4 Kinetics of a particle Part 3: Impulse and Momentum MEE Engineering Mechanics II Lecure 4 Lecure 4 Kineics of a paricle Par 3: Impulse and Momenum Linear impulse and momenum Saring from he equaion of moion for a paricle of mass m which is subjeced o an

More information

Rotational Motion and the Law of Gravity

Rotational Motion and the Law of Gravity Chape 7 7 Roaional Moion and he Law of Gaiy PROBLEM SOLUTIONS 7.1 (a) Eah oaes adians (360 ) on is axis in 1 day. Thus, ad 1 day 5 7.7 10 ad s 4 1 day 8.64 10 s Because of is oaion abou is axis, Eah bulges

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

Midterm Exam #2, Part A

Midterm Exam #2, Part A Physics 151 Mach 17, 2006 Midtem Exam #2, Pat A Roste No.: Scoe: Exam time limit: 50 minutes. You may use calculatos and both sides of ONE sheet of notes, handwitten only. Closed book; no collaboation.

More information

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b,

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b, SAMPLE QUIZ 3 - PHYSICS 1301.1 his is a closed book, closed notes quiz. Calculatos ae pemitted. he ONLY fomulas that may be used ae those given below. Define all symbols and justify all mathematical expessions

More information

Chapter 7-8 Rotational Motion

Chapter 7-8 Rotational Motion Chapte 7-8 Rotational Motion What is a Rigid Body? Rotational Kinematics Angula Velocity ω and Acceleation α Unifom Rotational Motion: Kinematics Unifom Cicula Motion: Kinematics and Dynamics The Toque,

More information

From Newton to Einstein. Mid-Term Test, 12a.m. Thur. 13 th Nov Duration: 50 minutes. There are 20 marks in Section A and 30 in Section B.

From Newton to Einstein. Mid-Term Test, 12a.m. Thur. 13 th Nov Duration: 50 minutes. There are 20 marks in Section A and 30 in Section B. Fom Newton to Einstein Mid-Tem Test, a.m. Thu. 3 th Nov. 008 Duation: 50 minutes. Thee ae 0 maks in Section A and 30 in Section B. Use g = 0 ms in numeical calculations. You ma use the following epessions

More information

AST1100 Lecture Notes

AST1100 Lecture Notes AST00 Lecue Noes 5 6: Geneal Relaiviy Basic pinciples Schwazschild geomey The geneal heoy of elaiviy may be summaized in one equaion, he Einsein equaion G µν 8πT µν, whee G µν is he Einsein enso and T

More information

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK. AP Physics C Sping, 2017 Cicula-Rotational Motion Mock Exam Name: Answe Key M. Leonad Instuctions: (92 points) Answe the following questions. SHOW ALL OF YOUR WORK. ( ) 1. A stuntman dives a motocycle

More information

IB Physics Kinematics Worksheet

IB Physics Kinematics Worksheet IB Physics Kinemaics Workshee Wrie full soluions and noes for muliple choice answers. Do no use a calculaor for muliple choice answers. 1. Which of he following is a correc definiion of average acceleraion?

More information

KINEMATICS IN ONE DIMENSION

KINEMATICS IN ONE DIMENSION KINEMATICS IN ONE DIMENSION PREVIEW Kinemaics is he sudy of how hings move how far (disance and displacemen), how fas (speed and velociy), and how fas ha how fas changes (acceleraion). We say ha an objec

More information

Physics 180A Fall 2008 Test points. Provide the best answer to the following questions and problems. Watch your sig figs.

Physics 180A Fall 2008 Test points. Provide the best answer to the following questions and problems. Watch your sig figs. Physics 180A Fall 2008 Tes 1-120 poins Name Provide he bes answer o he following quesions and problems. Wach your sig figs. 1) The number of meaningful digis in a number is called he number of. When numbers

More information

PS113 Chapter 5 Dynamics of Uniform Circular Motion

PS113 Chapter 5 Dynamics of Uniform Circular Motion PS113 Chapte 5 Dynamics of Unifom Cicula Motion 1 Unifom cicula motion Unifom cicula motion is the motion of an object taveling at a constant (unifom) speed on a cicula path. The peiod T is the time equied

More information

Physics 1C Fall 2011: Quiz 1 Version A 1

Physics 1C Fall 2011: Quiz 1 Version A 1 Physics 1C Fall 2011: Quiz 1 Vesion A 1 Depatment of Physics Physics 1C Fall Quate - 2011 D. Mak Paddock INSTRUCTIONS: 1. Pint you full name below LAST NAME FIRST NAME MIDDLE INITIAL 2. You code numbe

More information

Summary:Linear Motion

Summary:Linear Motion Summary:Linear Moion D Saionary objec V Consan velociy D Disance increase uniformly wih ime D = v. a Consan acceleraion V D V = a. D = ½ a 2 Velociy increases uniformly wih ime Disance increases rapidly

More information

Momentum and Collisions

Momentum and Collisions SOLUTIONS TO PROBLES Section 8. P8. m 3.00 kg, (a) omentum and Collisions Linea omentum and Its Consevation v ( 3.00î 4.00ĵ ) m s p mv ( 9.00î.0ĵ ) kg m s Thus, p x 9.00 kg m s and p y.0 kg m s. p p x

More information

1. The graph below shows the variation with time t of the acceleration a of an object from t = 0 to t = T. a

1. The graph below shows the variation with time t of the acceleration a of an object from t = 0 to t = T. a Kinemaics Paper 1 1. The graph below shows he ariaion wih ime of he acceleraion a of an objec from = o = T. a T The shaded area under he graph represens change in A. displacemen. B. elociy. C. momenum.

More information

Physics 111. Exam #1. January 24, 2011

Physics 111. Exam #1. January 24, 2011 Physics 111 Exam #1 January 4, 011 Name Muliple hoice /16 Problem #1 /8 Problem # /8 Problem #3 /8 Toal /100 ParI:Muliple hoice:irclehebesansweroeachquesion.nyohermarks willnobegivencredi.eachmuliple choicequesionisworh4poinsoraoalo

More information

Name. Date. Period. Engage Examine the pictures on the left. 1. What is going on in these pictures?

Name. Date. Period. Engage Examine the pictures on the left. 1. What is going on in these pictures? AP Physics 1 Lesson 9.a Unifom Cicula Motion Outcomes 1. Define unifom cicula motion. 2. Detemine the tangential velocity of an object moving with unifom cicula motion. 3. Detemine the centipetal acceleation

More information

Spring 2001 Physics 2048 Test 3 solutions

Spring 2001 Physics 2048 Test 3 solutions Sping 001 Physics 048 Test 3 solutions Poblem 1. (Shot Answe: 15 points) a. 1 b. 3 c. 4* d. 9 e. 8 f. 9 *emembe that since KE = ½ mv, KE must be positive Poblem (Estimation Poblem: 15 points) Use momentum-impulse

More information

2.1: What is physics? Ch02: Motion along a straight line. 2.2: Motion. 2.3: Position, Displacement, Distance

2.1: What is physics? Ch02: Motion along a straight line. 2.2: Motion. 2.3: Position, Displacement, Distance Ch: Moion along a sraigh line Moion Posiion and Displacemen Average Velociy and Average Speed Insananeous Velociy and Speed Acceleraion Consan Acceleraion: A Special Case Anoher Look a Consan Acceleraion

More information

MOMENTUM CONSERVATION LAW

MOMENTUM CONSERVATION LAW 1 AAST/AEDT AP PHYSICS B: Impulse and Momenum Le us run an experimen: The ball is moving wih a velociy of V o and a force of F is applied on i for he ime inerval of. As he resul he ball s velociy changes

More information

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun Chapte 12 Gavitation PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified by P. Lam 5_31_2012 Goals fo Chapte 12 To study Newton s Law

More information

11. HAFAT İş-Enerji Power of a force: Power in the ability of a force to do work

11. HAFAT İş-Enerji Power of a force: Power in the ability of a force to do work MÜHENDİSLİK MEKNİĞİ. HFT İş-Eneji Pwe f a fce: Pwe in he abiliy f a fce d wk F: The fce applied n paicle Q P = F v = Fv cs( θ ) F Q v θ Pah f Q v: The velciy f Q ÖRNEK: İŞ-ENERJİ ω µ k v Calculae he pwe

More information

Chapter 7. Rotational Motion Angles, Angular Velocity and Angular Acceleration Universal Law of Gravitation Kepler s Laws

Chapter 7. Rotational Motion Angles, Angular Velocity and Angular Acceleration Universal Law of Gravitation Kepler s Laws Chapte 7 Rotational Motion Angles, Angula Velocity and Angula Acceleation Univesal Law of Gavitation Keple s Laws Angula Displacement Cicula motion about AXIS Thee diffeent measues of angles: 1. Degees.

More information

Artemis Project. Analysis of recovery buoy for Artemis. Analysis. Executive Summary. Model. Before and during deployment.

Artemis Project. Analysis of recovery buoy for Artemis. Analysis. Executive Summary. Model. Before and during deployment. Aemis Pojec Analysis of ecovey buoy fo Aemis Auho: Ahu Sale Vesion and dae hisoy: v1.01, 1 May 003 Documen ID: Sucue-1-1.01 Execuive Summay I is planned o fi a ecovey buoy o Aemis, ahe han aanging fo Aemis

More information

Describing Circular motion

Describing Circular motion Unifom Cicula Motion Descibing Cicula motion In ode to undestand cicula motion, we fist need to discuss how to subtact vectos. The easiest way to explain subtacting vectos is to descibe it as adding a

More information

CLASS XI SET A PHYSICS. 1. If and Let. The correct order of % error in. (a) (b) x = y > z (c) x < z < y (d) x > z < y

CLASS XI SET A PHYSICS. 1. If and Let. The correct order of % error in. (a) (b) x = y > z (c) x < z < y (d) x > z < y PHYSICS 1. If and Le. The correc order of % error in (a) (b) x = y > z x < z < y x > z < y. A hollow verical cylinder of radius r and heigh h has a smooh inernal surface. A small paricle is placed in conac

More information

The Contradiction within Equations of Motion with Constant Acceleration

The Contradiction within Equations of Motion with Constant Acceleration The Conradicion wihin Equaions of Moion wih Consan Acceleraion Louai Hassan Elzein Basheir (Daed: July 7, 0 This paper is prepared o demonsrae he violaion of rules of mahemaics in he algebraic derivaion

More information

Chap 5. Circular Motion: Gravitation

Chap 5. Circular Motion: Gravitation Chap 5. Cicula Motion: Gavitation Sec. 5.1 - Unifom Cicula Motion A body moves in unifom cicula motion, if the magnitude of the velocity vecto is constant and the diection changes at evey point and is

More information

~v = x. ^x + ^y + ^x + ~a = vx. v = v 0 + at. ~v P=A = ~v P=B + ~v B=A. f k = k. W tot =KE. P av =W=t. W grav = mgy 1, mgy 2 = mgh =,U grav

~v = x. ^x + ^y + ^x + ~a = vx. v = v 0 + at. ~v P=A = ~v P=B + ~v B=A. f k = k. W tot =KE. P av =W=t. W grav = mgy 1, mgy 2 = mgh =,U grav PHYSICS 5A FALL 2001 FINAL EXAM v = x a = v x = 1 2 a2 + v 0 + x 0 v 2 = v 2 0 +2a(x, x 0) a = v2 r ~v = x ~a = vx v = v 0 + a y z ^x + ^y + ^z ^x + vy x, x 0 = 1 2 (v 0 + v) ~v P=A = ~v P=B + ~v B=A ^y

More information

Orthotropic Materials

Orthotropic Materials Kapiel 2 Ohoopic Maeials 2. Elasic Sain maix Elasic sains ae elaed o sesses by Hooke's law, as saed below. The sesssain elaionship is in each maeial poin fomulaed in he local caesian coodinae sysem. ε

More information

( ) ( ) Review of Force. Review of Force. r = =... Example 1. What is the dot product for F r. Solution: Example 2 ( )

( ) ( ) Review of Force. Review of Force. r = =... Example 1. What is the dot product for F r. Solution: Example 2 ( ) : PHYS 55 (Pat, Topic ) Eample Solutions p. Review of Foce Eample ( ) ( ) What is the dot poduct fo F =,,3 and G = 4,5,6? F G = F G + F G + F G = 4 +... = 3 z z Phs55 -: Foce Fields Review of Foce Eample

More information

Course II. Lesson 7 Applications to Physics. 7A Velocity and Acceleration of a Particle

Course II. Lesson 7 Applications to Physics. 7A Velocity and Acceleration of a Particle Course II Lesson 7 Applicaions o Physics 7A Velociy and Acceleraion of a Paricle Moion in a Sraigh Line : Velociy O Aerage elociy Moion in he -ais + Δ + Δ 0 0 Δ Δ Insananeous elociy d d Δ Δ Δ 0 lim [ m/s

More information

Department of Physics, Korea University Page 1 of 5

Department of Physics, Korea University Page 1 of 5 Name: Depatment: Student ID #: Notice ˆ + ( 1) points pe coect (incoect) answe. ˆ No penalty fo an unansweed question. ˆ Fill the blank ( ) with ( ) if the statement is coect (incoect). ˆ : coections to

More information

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

C3 Interactions transfer momentum. C4 - Particles and Systems. General Physics 1

C3 Interactions transfer momentum. C4 - Particles and Systems. General Physics 1 C3 Inteactions tansfe momentum C4 - Paticles and Systems Geneal Physics 1 Solutions to HW Download PobViewe 1.4 www.physics.pomona.edu/sixideas/sicp.html Passwod fo daily HW poblems kllxjks8 Geneal Physics

More information

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j.

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j. 7. We denote the two foces F A + F B = ma,sof B = ma F A. (a) In unit vecto notation F A = ( 20.0 N)ˆ i and Theefoe, Phys 201A Homewok 6 Solutions F A and F B. Accoding to Newton s second law, a = [ (

More information

2013 Checkpoints Chapter 6 CIRCULAR MOTION

2013 Checkpoints Chapter 6 CIRCULAR MOTION 013 Checkpoints Chapte 6 CIRCULAR MOTIO Question 09 In unifom cicula motion, thee is a net foce acting adially inwads. This net foce causes the elocity to change (in diection). Since the speed is constant,

More information

PROJECTILE MOTION. At any given point in the motion, the velocity vector is always a tangent to the path.

PROJECTILE MOTION. At any given point in the motion, the velocity vector is always a tangent to the path. PROJECTILE MOTION A pojectile is any object that has been thown though the ai. A foce must necessaily set the object in motion initially but, while it is moing though the ai, no foce othe than gaity acts

More information

Lecture 19 Angular momentum. Chapter

Lecture 19 Angular momentum. Chapter PHYS 172H: Moden Mechanics Fall 2010 Lectue 19 ngula momentum Chapte 11.4 11.7 The angula momentum pinciple dp = F dl =? net d ( p ) d dp = p+ = v γ mv = = 0 The angula momentum pinciple fo a point paticle

More information

Physics 231 Lecture 21

Physics 231 Lecture 21 Physics 3 Lectue Main points o today s lectue: Angula momentum: L Newton s law o univesal gavitation: GMm F PE GMm Keple s laws and the elation between the obital peiod and obital adius. T π GM 4 3 Rolling

More information

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line 1 CIRCULAR MOTION 1. ANGULAR DISPLACEMENT Intoduction: Angle subtended by position vecto of a paticle moving along any abitay path w..t. some fixed point is called angula displacement. (a) Paticle moving

More information

Chapter 1: Mathematical Concepts and Vectors

Chapter 1: Mathematical Concepts and Vectors Chapte : Mathematical Concepts and Vectos giga G 9 mega M 6 kilo k 3 centi c - milli m -3 mico μ -6 nano n -9 in =.54 cm m = cm = 3.8 t mi = 58 t = 69 m h = 36 s da = 86,4 s ea = 365.5 das You must know

More information