Emission of K -, L - and M - Auger Electrons from Cu Atoms. Abstract

Size: px
Start display at page:

Download "Emission of K -, L - and M - Auger Electrons from Cu Atoms. Abstract"

Transcription

1 Emission of K -, L - nd M - uger Electrons from Cu toms Mohmed ssd bdel-rouf Physics Deprtment, Science College, UEU, l in 17551, United rb Emirtes ssd@ueu.c.e bstrct The emission of uger electrons from the K-, L- nd M-sheels of two configurtions of copper toms is investigted in detil within the frme work of the momentum verge technique. b initio clcultions for the bound stte wvefunctions of the ionized toms re performed using Gussin computer code. The continuum wvefunctions of the emitted electrons re determined by employing n effective potentil vritionl pproch. Slight differences hve been noticed between the results of both configurtions. The trnsition rtes, energies nd widths of ll possible uger electrons re listed in Tbles. Slight differences hve been noticed between the results of the two types of copper toms Key Words: uger Spectroscopy PCS: 82.80P, H 1

2 1. Introduction Inner shell ioniztions of toms nd molecules could be initited vi electron, positron or photon interctions. In ll cses holes re creted followed by rerrngement processes. The most interesting process is the one in which n electron from n outer shell flls to fill hole. The energy difference between the two sttes is bsorbed by n electron belonging to higher orbit. Immeditely fter bsorption the electron leves the interction region yielding doubly ionized tom. The trnsition rte, (0), of the flying electron, usully referred to (fter the discoverer of the phenomenon by uger 1923 nd 1925) s uger electron, leds to vluble informtion bout the electronic structure of the originl system. This provides us with plusible explntion for the vigorous interest shown by industril institutions in the development nd employment of uger scnners. (For recent review of the dt, see Sfronov et l 2001). The min gol of the present work is to determine the uger rtes, energies nd widths of ll possible trnsitions from the K-, L- nd M-shells of two configurtions of copper toms. For this purpose, the momentum verge technique is employed, whilst the wvefunctions of the bound electrons re obtined using n b initio Gussin computer code. The continuum wvefunctions of the emitted electrons re evluted by employing n effective potentil vritionl pproch suggested by bdel-rouf et l (1999, 2002) for solving the corresponding Schrödinger eqution. In section 2 the mthemticl formlism is shortly presented. Section 3 contins the results nd discussions of our dt. Concluding remrks re lso given in the sme section 2

3 2. Mthemticl Formlism Theoreticlly, the uger trnsition rte (0) is determined by (Wentzel 1927): (0) = π τ 2 <φ 3 (r 1 ) φ c(r 2 ) r1 1 r2 φ 1(r 1 ) φ 2(r 2 ) > 2, (1) where τ = h 0 /2πe 2 = h 2 /4 π 2 me 4 = 2.42x10-17 sec, is the time tomic unit, φ c is the wvefunction of the emitted uger electron, (lso referred to s the continuum wvefunction). φ 3 is the wvefunction describing the electron tht filled the hole. The wvefunctions φ 1 nd φ 2 represent the originl bound sttes of these two electrons. They re determined in the present work using Gussin computer code. The wvefunction of the uger electron φ c > is clculted by solving Schrödinger s eqution (H-E) φ c > = 0 >, (2) where H is given by 2 h 2 H = V ( r) r 2m +. (3) V(r) is the effective potentil seen by the continuum electron t distnce r from the infinitely hevy nucleus of the doubly ionized tom. Following McGuire (1972), in the ngulr momentum verge scheme, the uger rte for the trnsition n 1 l 1 n 2 l 2 n 3 l 3 n c l c is connected with the two electrons uger rte (0) by two different forms: Cse I: n 1 l 1 n 2 l 2 = [(h 3 +1) (4 l 1 +2-h 1 ) (4l h 2 )] / [(4l 1 +2) (4l 2 +2)] ( i f ), (4) (0) 3

4 where h 3, h 1, nd h 2 re the numbers of holes in the subshells n 3 l 3, n 1 l 1 nd n 2 l 2, respectively. lso, the indices i nd ƒ specify n initil nd finl stte, respectively. Cse II: n 1 l 1 = n 2 l 2 = [(h 3 +1) (4 l 1 +2-h 1 ) (4l h 1 )] / [(4l 1 +2) (4l 1 +2)] ( i f ), (5) (0) Where (0) ( ) n1l1n 2l 2 n3l3ncl = (1/2) (2l c c + 1) (2l 1 + 1) (2l 1 + 1) h, g hg [Im( h, g)] 2 (6) h nd g re the spin nd orbitl quntum numbers. The corresponding uger widths re determined by Γ ( i) ( i f ) = f 3. Results nd Discussions In this section we present the finl results obtined fter lengthy investigtions of the problem under considertion. These re the uger rtes, uger widths Γ, nd uger energies E chrcteristic to K -, L - nd M - inner shell ioniztions for two configurtions of the copper tom, (to be referred to in the Tbles s Cu I nd Cu II). The following three subsections contin the results nd discussions of our uger trnsitions clculted for the inner shell ioniztions mentioned bove for Cu I nd Cu II. 4

5 3.1. K-Shell uger Trnsitions In Tble 1 we list the uger trnsition rtes 's (mesured in sec-1) corresponding the initil stte 1s 1 2s 2 2p 6 3s 2 3p 6 3d 10 4s 1 of Cu I. The uger trnsitions corresponding to the initil stte 1s 1 2s 2 2p 6 3s 2 3p 6 3d 9 4s 2 of Cu II re given in Tble 2. (Remember tht the superscripts refer to the numbers of electrons in the occupied orbits). From the Tbles we conclude the following remrks: (1) The trnsitions (1s 2s2s), (1s 2s2p), (1s 2p2p), nd (1s 2p3p) represent the dominnt contributions to the uger widths of the initil stte. The third trnsition is the lrgest one. (2) For Cu I nd Cu II, the uger rtes in which the outer electron is involved (e.g. (1s 3d4s) nd (1s 3d3d)) provide smll contributions to the uger widths, whilst (1s 3d4s) hs the smllest contribution in cse of Cu I nd (1s 4s4s) yields the smllest contribution for Cu II. The rtio of the uger widths of Cu I nd Cu II is (3) The resultnt trnsition energies for Cu I show tht E c increses with n nd l for identicl or different effective electrons. For exmple E c = Ry for the trnsition (1s 2s2s), E c = Ry for the trnsition (1s 2p2p) nd E c = Ry for the trnsition (1s 3s3s). E c = Ry for the trnsition (1s 3p3p) nd E c = Ry for the trnsition (1s 3d3d). Similr behvior is concluded from Tble 2. 5

6 Tble 1: uger trnsition rtes in sec -1 for initil sttes of Cu (I), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (I) Initil Stte : 1s 1 2s 2 2p 6 3s 2 3p 6 3d 10 4s 1 Finl Stte l c E c (Ry) 1s 2 2p 6 3s 2 3p 6 3d 10 4s (13) 1s 2 2s 2 2p 4 3s 2 3p 6 3d 10 4s (13) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s (11) 1s 1 2s 2 2p 6 3s 2 3p 4 3d 8 4s (7) (8) (10) 1s 2 2s 1 2p 5 3s 2 3p 6 3d 10 4s (13) 1s 2 2s 1 2p 6 3s 1 3p 6 3d 10 4s (12) 1s 2 2s 1 2p 6 3s 2 3p 6 3d 10 4s (13) 1s 2 2s 1 2p 6 3s 2 3p 6 3d 9 4s (12) 1s 2 2s 1 2p 6 3s 2 3p 6 3d (11) 1s 2 2s 2 2p 5 3s 1 3p 6 3d 10 4s (13) 1s 2 2s 2 2p 5 3s 2 3p 5 3d 10 4s (13) 1s 2 2s 2 2p 5 3s 2 3p 6 3d 9 4s (11) (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (11) 1s 2 s 2 2p 6 3s 2 3p 6 3d 10 4s (10) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 9 4s (11) 1s 2 2s 2 2p 6 3s 1 3p 6 3d (10) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s s 2 2s 2 2p 6 3s 2 3p 5 3d (10) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (9) Г =7.445(14) 6

7 Tble 2: uger trnsition rtes in sec -1 for CU (II), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (II) Initil Stte : 1s 1 2s 2 2p 6 3s 2 3p 6 3d 9 4s 2 Finl Stte l c E c (Ry) 1s 2 2p 6 3s 2 3p 6 3d 9 4s (13) 1s 2 2s 2 2p 4 3s 2 3p 6 3d 9 4s (13) (12) 1s 2 2s 2 2p 6 3p 6 3d 9 4s (12) 1s 2 2s 2 2p 6 3s 2 3p 4 3d 9 4s (11) (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 7 4s (7) (7) (10) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 9 4s (13) 1s 2 2s 1 2p 6 3s 1 3p 6 3d 9 4s (12) 1s 2 2s 1 2p 6 3s 2 3p 5 3d 9 4s (13) 1s 2 2s 1 2p 6 3s 2 3p 6 3d 8 4s (12) 1s 2 2s 1 2p 6 3s 2 3p 6 3d 8 4s (11) 1s 2 2s 2 2p 5 3s 1 3p 6 3d 9 4s (13) 1s 2 2s 2 2p 5 3s 2 3p 5 3d 9 4s (13) (14) 1s 2 2s 2 2p 5 3s 2 3p 6 3d 8 4s (11) (12) 1s 2 2s 2 2p 5 3s 2 3p 6 3d 9 4s (11) 1s 2 2s 2 2p 6 3s 1 3p 5 3d 9 4s (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 9 4s (10) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 8 4s (10) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 8 4s (10) (11) 1s 2 2s 2 2p 6 3s 1 3p 5 3d 8 4s (10) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 8 4s (9) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (8) Г =7.0988(14) 7

8 3.2. L -Shell uger Trnsitions In this cse two holes re possible, nmely 2s hole or 2p hole, leding to two sets of uger trnsitions, (corresponding to two initil ionized sttes) in ech configurtion of the copper tom. Tbles (3), (4) contin ll possible trnsitions for Cu I ions nd Tbles (5), (6) demonstrte ll possible uger trnsitions in cse of Cu II ions. Tble 3: uger trnsition rtes in sec -1 resulting from 2s-hole in Cu (I), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (I) Initil Stte : 1s 2 2s 1 2p 6 3s 2 3p 6 3d 10 4s 1 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 5 3s 1 3p 6 3d 10 4s (11) 1s 2 2s 2 2p 5 3s 2 3p 5 3d 10 4s (12) (12) 1s 2 2s 2 2p 5 3s 2 3p 5 3d 9 4s (11) (12) 1s 2 2s 2 2p 5 3s 2 3p 5 3d (10) 1s 2 2s 2 2p 6 3p 6 3d 10 4s (14) 1s 2 2s 2 2p 6 3s 1 3p 5 3d 10 4s (14) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 9 4s ( 14) 1s 2 2s 2 2p 6 3s 1 3p 6 3d (13) 1s 2 2s 2 2p 6 3s 2 3p 4 3d 10 4s (12) (12) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (13) (14) 1s 2 2s 2 2p 6 3s 2 3p 5 3d (12) 1s 2 s 2 2p 6 3s 2 3p 6 3d 8 4s (12) (12) (13) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (12) Г = (14) 8

9 Tble 4: uger trnsition rtes in sec -1 resulting from 2p-hole in Cu (I), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (I) Initil Stte : 1s 2 2s 2 2p 5 3s 2 3p 6 3d 10 4s 1 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 6 3p 6 3d 10 4s (11) 1s 2 2s 2 2p 6 3s 1 3p 5 3d 10 4s (13) (13) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 9 4s (13) (13) 1s 2 2s 2 2p 6 3s 1 3p 6 3d (10) 1s 2 2s 2 2p 6 3s23p 4 3d 10 4s (14) (13) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (13) (14) (13) 1s 2 2s 2 2p 6 3s 2 3p 5 3d (12) (9) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 8 4s (12) (14) (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (10) (10) Г = (15) 9

10 Tble 5: uger trnsition rtes in sec -1 resulting from 2s-hole in Cu (II), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (II) Initil Stte : 1s 2 2s 1 2p 6 3s 2 3p 6 3d 9 4s 2 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 5 3s 1 3p 6 3d 9 4s (11) 1s 2 2s 2 2p 5 3s 2 3p 5 3d 9 4s (12) (12) 1s 2 2s 2 2p 5 3s 2 3p 6 3d 8 4s (11) (12) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (10) 1s 2 2s 2 2p 6 3p 6 3d 9 4s (14) 1s 2 2s 2 2p 6 3s 1 3p 5 3d 9 4s (14) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 8 4s (14) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 9 4s (12) 1s 2 2s 2 2p 6 3s 2 3p 4 3d 9 4s (12) (12) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (13) (14) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (12) 1s 2 s 2 2p 6 3s 2 3p 6 3d 7 4s (12) (11) (13) 1s 2 s 2 2p 6 3s 2 3p 6 3d 8 4s (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (10) Г = (14) 10

11 Tble 6: uger trnsition rtes in sec -1 resulting from 2p-hole in Cu (II), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (II) Initil Stte : 1s 2 2s 2 2p 5 3s 2 3p 6 3d 9 4s 2 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 6 3p 6 3d 9 4s (11) 1s 2 2s 2 2p 6 3s 1 3p 5 3d 9 4s (13) (13) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 8 4s (13) (12) 1s 2 2s 2 2p 6 3s 1 3p 6 3d 9 4s (10) 1s 2 2s 2 2p 6 3s23p 4 3d 9 4s (14) (13) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 8 4s (13) (14) (13) 1s 2 2s 2 2p 6 3s 2 3p 5 3d (12) (12) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 7 4s (12) (14) (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 8 4s (10) (10) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (10) Г = (14) From Tbles 3 nd 5 we notice the following points: (1)The dominnt contributions to the uger widths of the 2s ionized forms of the Cu I nd Cu II re obtined from the trnsitions (2s 3s3s), (2s 3s3p), (2s 3s3d) nd (2s 3p3d). The second trnsition yields the mximum contributions. 11

12 (2) The rtio between Г 's of the configurtions Cu I nd Cu II is equl to similr vlue ws obtined for 1s ionized toms, where the difference between the two set of trnsitions is miniml. The following remrks cn be lso noticed from Tbles 4 nd 6: (1)The dominnt contributions to the vlues of the uger widths, Г 's, corresponding to the 2p innershell ioniztions of Cu I nd Cu II re delivered by the trnsition (2p 3s3p), (2p 3p3p), (2p 3p3d) nd (2p 3d3d). The uger trnsition rtes (2p 3p3p) nd 3p3d) re superior. (2p (2)The rtio between the Г 's, of Cu I nd Cu II corresponding to the 2ptrnsitions is , which lies in the sme order of mgnitude of the rtions determined for 1s hole nd 2s hole trnsitions M - Shell uger Trnsitions The emitted uger electrons in this cse cn be originted by ny M-subshell hole, prt from 3d one. This is ttributed to the fct tht no trnsitions corresponding 3d-hole re llowed. Thus, only 3s or 3p hole decy is possible. The 3s 3p3p is energeticlly forbidden. ll possible 3s - uger trnsition rtes nd the corresponding widths of the initil sttes 1s 2 2s 2 p 6 3s 1 3p 6 3d 10 4s 1 nd 1s 2 2s 2 p 6 3s 1 3p 6 3d 9 4s 2 of Cu I nd Cu II, respectively, re given in Tbles 7 nd 8 12

13 Tble7: uger trnsition rtes in sec -1 resulting from 3s-hole in Cu (I), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (I) Initil Stte : 1s 2 2s 2 2p 6 3s 1 3p 6 3d 10 4s 1 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (12) (12) 1s 2 2s 2 2p 6 3s 2 3p 5 3d (11) 1s 2 2s 2 2p 6 3s 2 3p 4 3d 8 4s (12) (13) (14) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (14) Г = (14) Tble 8: uger trnsition rtes in sec -1 resulting from 3s-hole in Cu (II), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (II) Initil Stte : 1s 2 2s 2 2p 6 3s 1 3p 6 3d 9 4s 2 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 8 4s (12) (12) 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s (11) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 7 4s (12) (13) (14) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 8 4s (14) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (12) Г = (14) 13

14 Tbles 7 nd 8 led to the following remrks: (1) The two uger trnsitions (3s 3d3d) nd (3s 4s3d) yield the dominnt contributions to the uger widths of both Cu I nd Cu II. (2) The energy of the continuum electron increses s n or l increses for equivlent or nonequivlent effective electrons. (3) The mximum vlues of E c re Ry for Cu I nd Ry for Cu II. (4) In generl the continuum energies of the 3s trnsitions re smller thn the continuum energies of the previously clculted trnsitions. (5) The rtio of Г 's of the two copper configurtions is which is nerly equl to the rtios clculted for the 1s hole, 2s hole nd 2p hole trnsitions. The results of 3p hole decys in Cu I nd Cu II re ccumulted in Tbles 9 nd 10. From the Tbles we conclude the following points: (1) The number of possible 3p uger trnsitions is reduced to (3p 3d3d) nd (3p 3d4s). lso the trnsition (3p 4s4s) is llowed. The first of these three trnsitions possesses the lrges contribution to the widths in both Cu I nd Cu II. (2) The uger trnsition (3p 3d3d) is the lrges trnsition corresponding to continuum energy E c 65 ev, which represents the pek of the uger spectrum. 14

15 Tble 9: uger trnsition rtes in sec -1 resulting from 3s-hole in Cu (I), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (I) Initil Stte : 1s 2 2s 2 2p 6 3s 2 3p 5 3d 10 4s 1 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 8 4s (14) Scientific Reserch nd Essys (15) (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (13) (12) Г = (15) Tble10: uger trnsition rtes in sec -1 resulting from 3p-hole in Cu (II), the energy of the emitted electron (in Ry) nd the ngulr momentum of this electron (c). The number between prentheses is the power of 10. Cu (I) Initil Stte : 1s 2 2s 2 2p 6 3s 2 3p 5 3d 9 4s 2 Finl Stte l c E c (Ry) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 7 4s (14) (15) (12) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 8 4s (14) (13) 1s 2 2s 2 2p 6 3s 2 3p 6 3d (10) Г = (15) 15

16 References bdel-rouf M.., El-Bkry S. Y. nd El-Bkry M. Y (2002)., Mod. Phys. Lett., 14: 877. bdel-rouf M.., El-Bkry S. Y. nd El-Bkry M. Y Ind. J. Phys B. (1999), 73: 711. uger P., J. Compt. Rend (1923), 117: 169. uger P. (1925), J. Phys. Rdium 6: 205. McGuire E. J., uger nd Coster Kronig Trnsitions in Inner Shell tomic Processes, ed. B. Crsmnn, cdemic Press-(1972). Sfronov U. I., Johnson W. R. nd lbritton J. R. (2001), t. Dt Nucl. Dt Tbles, 77: 215. Wentzel G. (1927), Zeitsch. Phys., 43:

Name Solutions to Test 3 November 8, 2017

Name Solutions to Test 3 November 8, 2017 Nme Solutions to Test 3 November 8, 07 This test consists of three prts. Plese note tht in prts II nd III, you cn skip one question of those offered. Some possibly useful formuls cn be found below. Brrier

More information

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B PHY 249, Fll 216 Exm 1 Solutions nswer 1 is correct for ll problems. 1. Two uniformly chrged spheres, nd B, re plced t lrge distnce from ech other, with their centers on the x xis. The chrge on sphere

More information

Problem Set 3 Solutions

Problem Set 3 Solutions Chemistry 36 Dr Jen M Stndrd Problem Set 3 Solutions 1 Verify for the prticle in one-dimensionl box by explicit integrtion tht the wvefunction ψ ( x) π x is normlized To verify tht ψ ( x) is normlized,

More information

DETERMINATION OF MECHANICAL PROPERTIES OF NANOSTRUCTURES WITH COMPLEX CRYSTAL LATTICE USING MOMENT INTERACTION AT MICROSCALE

DETERMINATION OF MECHANICAL PROPERTIES OF NANOSTRUCTURES WITH COMPLEX CRYSTAL LATTICE USING MOMENT INTERACTION AT MICROSCALE Determintion RevAdvMterSci of mechnicl 0(009) -7 properties of nnostructures with complex crystl lttice using DETERMINATION OF MECHANICAL PROPERTIES OF NANOSTRUCTURES WITH COMPLEX CRYSTAL LATTICE USING

More information

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

SUMMER KNOWHOW STUDY AND LEARNING CENTRE SUMMER KNOWHOW STUDY AND LEARNING CENTRE Indices & Logrithms 2 Contents Indices.2 Frctionl Indices.4 Logrithms 6 Exponentil equtions. Simplifying Surds 13 Opertions on Surds..16 Scientific Nottion..18

More information

PHYS Summer Professor Caillault Homework Solutions. Chapter 2

PHYS Summer Professor Caillault Homework Solutions. Chapter 2 PHYS 1111 - Summer 2007 - Professor Cillult Homework Solutions Chpter 2 5. Picture the Problem: The runner moves long the ovl trck. Strtegy: The distnce is the totl length of trvel, nd the displcement

More information

Intro to Nuclear and Particle Physics (5110)

Intro to Nuclear and Particle Physics (5110) Intro to Nucler nd Prticle Physics (5110) Feb, 009 The Nucler Mss Spectrum The Liquid Drop Model //009 1 E(MeV) n n(n-1)/ E/[ n(n-1)/] (MeV/pir) 1 C 16 O 0 Ne 4 Mg 7.7 14.44 19.17 8.48 4 5 6 6 10 15.4.41

More information

THE EXISTENCE-UNIQUENESS THEOREM FOR FIRST-ORDER DIFFERENTIAL EQUATIONS.

THE EXISTENCE-UNIQUENESS THEOREM FOR FIRST-ORDER DIFFERENTIAL EQUATIONS. THE EXISTENCE-UNIQUENESS THEOREM FOR FIRST-ORDER DIFFERENTIAL EQUATIONS RADON ROSBOROUGH https://intuitiveexplntionscom/picrd-lindelof-theorem/ This document is proof of the existence-uniqueness theorem

More information

Electron Correlation Methods

Electron Correlation Methods Electron Correltion Methods HF method: electron-electron interction is replced by n verge interction E HF c E 0 E HF E 0 exct ground stte energy E HF HF energy for given bsis set HF Ec 0 - represents mesure

More information

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3 2 The Prllel Circuit Electric Circuits: Figure 2- elow show ttery nd multiple resistors rrnged in prllel. Ech resistor receives portion of the current from the ttery sed on its resistnce. The split is

More information

Quantum Mechanics Qualifying Exam - August 2016 Notes and Instructions

Quantum Mechanics Qualifying Exam - August 2016 Notes and Instructions Quntum Mechnics Qulifying Exm - August 016 Notes nd Instructions There re 6 problems. Attempt them ll s prtil credit will be given. Write on only one side of the pper for your solutions. Write your lis

More information

Lecture 13 - Linking E, ϕ, and ρ

Lecture 13 - Linking E, ϕ, and ρ Lecture 13 - Linking E, ϕ, nd ρ A Puzzle... Inner-Surfce Chrge Density A positive point chrge q is locted off-center inside neutrl conducting sphericl shell. We know from Guss s lw tht the totl chrge on

More information

State space systems analysis (continued) Stability. A. Definitions A system is said to be Asymptotically Stable (AS) when it satisfies

State space systems analysis (continued) Stability. A. Definitions A system is said to be Asymptotically Stable (AS) when it satisfies Stte spce systems nlysis (continued) Stbility A. Definitions A system is sid to be Asymptoticlly Stble (AS) when it stisfies ut () = 0, t > 0 lim xt () 0. t A system is AS if nd only if the impulse response

More information

Math 116 Final Exam April 26, 2013

Math 116 Final Exam April 26, 2013 Mth 6 Finl Exm April 26, 23 Nme: EXAM SOLUTIONS Instructor: Section:. Do not open this exm until you re told to do so. 2. This exm hs 5 pges including this cover. There re problems. Note tht the problems

More information

Scientific notation is a way of expressing really big numbers or really small numbers.

Scientific notation is a way of expressing really big numbers or really small numbers. Scientific Nottion (Stndrd form) Scientific nottion is wy of expressing relly big numbers or relly smll numbers. It is most often used in scientific clcultions where the nlysis must be very precise. Scientific

More information

Fig. 1. Open-Loop and Closed-Loop Systems with Plant Variations

Fig. 1. Open-Loop and Closed-Loop Systems with Plant Variations ME 3600 Control ystems Chrcteristics of Open-Loop nd Closed-Loop ystems Importnt Control ystem Chrcteristics o ensitivity of system response to prmetric vritions cn be reduced o rnsient nd stedy-stte responses

More information

( dg. ) 2 dt. + dt. dt j + dh. + dt. r(t) dt. Comparing this equation with the one listed above for the length of see that

( dg. ) 2 dt. + dt. dt j + dh. + dt. r(t) dt. Comparing this equation with the one listed above for the length of see that Arc Length of Curves in Three Dimensionl Spce If the vector function r(t) f(t) i + g(t) j + h(t) k trces out the curve C s t vries, we cn mesure distnces long C using formul nerly identicl to one tht we

More information

Chapter 6 Notes, Larson/Hostetler 3e

Chapter 6 Notes, Larson/Hostetler 3e Contents 6. Antiderivtives nd the Rules of Integrtion.......................... 6. Are nd the Definite Integrl.................................. 6.. Are............................................ 6. Reimnn

More information

Vibrational Relaxation of HF (v=3) + CO

Vibrational Relaxation of HF (v=3) + CO Journl of the Koren Chemicl Society 26, Vol. 6, No. 6 Printed in the Republic of Kore http://dx.doi.org/.52/jkcs.26.6.6.462 Notes Vibrtionl Relxtion of HF (v3) + CO Chng Soon Lee Deprtment of Chemistry,

More information

Higher Checklist (Unit 3) Higher Checklist (Unit 3) Vectors

Higher Checklist (Unit 3) Higher Checklist (Unit 3) Vectors Vectors Skill Achieved? Know tht sclr is quntity tht hs only size (no direction) Identify rel-life exmples of sclrs such s, temperture, mss, distnce, time, speed, energy nd electric chrge Know tht vector

More information

Massachusetts Institute of Technology Quantum Mechanics I (8.04) Spring 2005 Solutions to Problem Set 6

Massachusetts Institute of Technology Quantum Mechanics I (8.04) Spring 2005 Solutions to Problem Set 6 Msschusetts Institute of Technology Quntum Mechnics I (8.) Spring 5 Solutions to Problem Set 6 By Kit Mtn. Prctice with delt functions ( points) The Dirc delt function my be defined s such tht () (b) 3

More information

Lecture 20: Numerical Integration III

Lecture 20: Numerical Integration III cs4: introduction to numericl nlysis /8/0 Lecture 0: Numericl Integrtion III Instructor: Professor Amos Ron Scribes: Mrk Cowlishw, Yunpeng Li, Nthnel Fillmore For the lst few lectures we hve discussed

More information

3.1 Review of Sine, Cosine and Tangent for Right Angles

3.1 Review of Sine, Cosine and Tangent for Right Angles Foundtions of Mth 11 Section 3.1 Review of Sine, osine nd Tngent for Right Tringles 125 3.1 Review of Sine, osine nd Tngent for Right ngles The word trigonometry is derived from the Greek words trigon,

More information

New data structures to reduce data size and search time

New data structures to reduce data size and search time New dt structures to reduce dt size nd serch time Tsuneo Kuwbr Deprtment of Informtion Sciences, Fculty of Science, Kngw University, Hirtsuk-shi, Jpn FIT2018 1D-1, No2, pp1-4 Copyright (c)2018 by The Institute

More information

Ph2b Quiz - 1. Instructions

Ph2b Quiz - 1. Instructions Ph2b Winter 217-18 Quiz - 1 Due Dte: Mondy, Jn 29, 218 t 4pm Ph2b Quiz - 1 Instructions 1. Your solutions re due by Mondy, Jnury 29th, 218 t 4pm in the quiz box outside 21 E. Bridge. 2. Lte quizzes will

More information

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives Block #6: Properties of Integrls, Indefinite Integrls Gols: Definition of the Definite Integrl Integrl Clcultions using Antiderivtives Properties of Integrls The Indefinite Integrl 1 Riemnn Sums - 1 Riemnn

More information

Math& 152 Section Integration by Parts

Math& 152 Section Integration by Parts Mth& 5 Section 7. - Integrtion by Prts Integrtion by prts is rule tht trnsforms the integrl of the product of two functions into other (idelly simpler) integrls. Recll from Clculus I tht given two differentible

More information

Terminal Velocity and Raindrop Growth

Terminal Velocity and Raindrop Growth Terminl Velocity nd Rindrop Growth Terminl velocity for rindrop represents blnce in which weight mss times grvity is equl to drg force. F 3 π3 ρ L g in which is drop rdius, g is grvittionl ccelertion,

More information

13: Diffusion in 2 Energy Groups

13: Diffusion in 2 Energy Groups 3: Diffusion in Energy Groups B. Rouben McMster University Course EP 4D3/6D3 Nucler Rector Anlysis (Rector Physics) 5 Sept.-Dec. 5 September Contents We study the diffusion eqution in two energy groups

More information

1. Weak acids. For a weak acid HA, there is less than 100% dissociation to ions. The B-L equilibrium is:

1. Weak acids. For a weak acid HA, there is less than 100% dissociation to ions. The B-L equilibrium is: th 9 Homework: Reding, M&F, ch. 15, pp. 584-598, 602-605 (clcultions of ph, etc., for wek cids, wek bses, polyprotic cids, nd slts; fctors ffecting cid strength). Problems: Nkon, ch. 18, #1-10, 16-18,

More information

The final exam will take place on Friday May 11th from 8am 11am in Evans room 60.

The final exam will take place on Friday May 11th from 8am 11am in Evans room 60. Mth 104: finl informtion The finl exm will tke plce on Fridy My 11th from 8m 11m in Evns room 60. The exm will cover ll prts of the course with equl weighting. It will cover Chpters 1 5, 7 15, 17 21, 23

More information

Lecture 3 ( ) (translated and slightly adapted from lecture notes by Martin Klazar)

Lecture 3 ( ) (translated and slightly adapted from lecture notes by Martin Klazar) Lecture 3 (5.3.2018) (trnslted nd slightly dpted from lecture notes by Mrtin Klzr) Riemnn integrl Now we define precisely the concept of the re, in prticulr, the re of figure U(, b, f) under the grph of

More information

Jack Simons, Henry Eyring Scientist and Professor Chemistry Department University of Utah

Jack Simons, Henry Eyring Scientist and Professor Chemistry Department University of Utah 1. Born-Oppenheimer pprox.- energy surfces 2. Men-field (Hrtree-Fock) theory- orbitls 3. Pros nd cons of HF- RHF, UHF 4. Beyond HF- why? 5. First, one usully does HF-how? 6. Bsis sets nd nottions 7. MPn,

More information

Review of Calculus, cont d

Review of Calculus, cont d Jim Lmbers MAT 460 Fll Semester 2009-10 Lecture 3 Notes These notes correspond to Section 1.1 in the text. Review of Clculus, cont d Riemnn Sums nd the Definite Integrl There re mny cses in which some

More information

Physics 202H - Introductory Quantum Physics I Homework #08 - Solutions Fall 2004 Due 5:01 PM, Monday 2004/11/15

Physics 202H - Introductory Quantum Physics I Homework #08 - Solutions Fall 2004 Due 5:01 PM, Monday 2004/11/15 Physics H - Introductory Quntum Physics I Homework #8 - Solutions Fll 4 Due 5:1 PM, Mondy 4/11/15 [55 points totl] Journl questions. Briefly shre your thoughts on the following questions: Of the mteril

More information

IN GAUSSIAN INTEGERS X 3 + Y 3 = Z 3 HAS ONLY TRIVIAL SOLUTIONS A NEW APPROACH

IN GAUSSIAN INTEGERS X 3 + Y 3 = Z 3 HAS ONLY TRIVIAL SOLUTIONS A NEW APPROACH INTEGERS: ELECTRONIC JOURNAL OF COMBINATORIAL NUMBER THEORY 8 (2008), #A2 IN GAUSSIAN INTEGERS X + Y = Z HAS ONLY TRIVIAL SOLUTIONS A NEW APPROACH Elis Lmpkis Lmpropoulou (Term), Kiprissi, T.K: 24500,

More information

Do the one-dimensional kinetic energy and momentum operators commute? If not, what operator does their commutator represent?

Do the one-dimensional kinetic energy and momentum operators commute? If not, what operator does their commutator represent? 1 Problem 1 Do the one-dimensionl kinetic energy nd momentum opertors commute? If not, wht opertor does their commuttor represent? KE ˆ h m d ˆP i h d 1.1 Solution This question requires clculting the

More information

University of Washington Department of Chemistry Chemistry 453 Winter Quarter 2009

University of Washington Department of Chemistry Chemistry 453 Winter Quarter 2009 University of Wshington Deprtment of Chemistry Chemistry Winter Qurter 9 Homework Assignment ; Due t pm on //9 6., 6., 6., 8., 8. 6. The wve function in question is: ψ u cu ( ψs ψsb * cu ( ψs ψsb cu (

More information

Analogy Between Particle in a Box and Jahn Teller Effect

Analogy Between Particle in a Box and Jahn Teller Effect Anlogy Between Prticle in Box nd Jhn Teller Effect MNMurty MNMurtyis Professor in Physics t Ntionl Institute of Science nd Technology, Plur Hills, Berhmpur, Odish. The energy levels of prticle in box re

More information

Rel Gses 1. Gses (N, CO ) which don t obey gs lws or gs eqution P=RT t ll pressure nd tempertures re clled rel gses.. Rel gses obey gs lws t extremely low pressure nd high temperture. Rel gses devited

More information

interatomic distance

interatomic distance Dissocition energy of Iodine molecule using constnt devition spectrometer Tbish Qureshi September 2003 Aim: To verify the Hrtmnn Dispersion Formul nd to determine the dissocition energy of I 2 molecule

More information

Homework 4 , (1) 1+( NA +N D , (2)

Homework 4 , (1) 1+( NA +N D , (2) Homework 4. Problem. Find the resistivity ρ (in ohm-cm) for piece of Si doped with both cceptors (N A = 9 cm 3 ) nd donors (N D = 6 cm 3 ). Since the electron nd hole mobilities depend on the concentrtion

More information

Operations with Polynomials

Operations with Polynomials 38 Chpter P Prerequisites P.4 Opertions with Polynomils Wht you should lern: How to identify the leding coefficients nd degrees of polynomils How to dd nd subtrct polynomils How to multiply polynomils

More information

Math 1B, lecture 4: Error bounds for numerical methods

Math 1B, lecture 4: Error bounds for numerical methods Mth B, lecture 4: Error bounds for numericl methods Nthn Pflueger 4 September 0 Introduction The five numericl methods descried in the previous lecture ll operte by the sme principle: they pproximte the

More information

P 3 (x) = f(0) + f (0)x + f (0) 2. x 2 + f (0) . In the problem set, you are asked to show, in general, the n th order term is a n = f (n) (0)

P 3 (x) = f(0) + f (0)x + f (0) 2. x 2 + f (0) . In the problem set, you are asked to show, in general, the n th order term is a n = f (n) (0) 1 Tylor polynomils In Section 3.5, we discussed how to pproximte function f(x) round point in terms of its first derivtive f (x) evluted t, tht is using the liner pproximtion f() + f ()(x ). We clled this

More information

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique? XII. LINEAR ALGEBRA: SOLVING SYSTEMS OF EQUATIONS Tody we re going to tlk bout solving systems of liner equtions. These re problems tht give couple of equtions with couple of unknowns, like: 6 2 3 7 4

More information

Classical Mechanics. From Molecular to Con/nuum Physics I WS 11/12 Emiliano Ippoli/ October, 2011

Classical Mechanics. From Molecular to Con/nuum Physics I WS 11/12 Emiliano Ippoli/ October, 2011 Clssicl Mechnics From Moleculr to Con/nuum Physics I WS 11/12 Emilino Ippoli/ October, 2011 Wednesdy, October 12, 2011 Review Mthemtics... Physics Bsic thermodynmics Temperture, idel gs, kinetic gs theory,

More information

Quantum Physics II (8.05) Fall 2013 Assignment 2

Quantum Physics II (8.05) Fall 2013 Assignment 2 Quntum Physics II (8.05) Fll 2013 Assignment 2 Msschusetts Institute of Technology Physics Deprtment Due Fridy September 20, 2013 September 13, 2013 3:00 pm Suggested Reding Continued from lst week: 1.

More information

Physics 201 Lab 3: Measurement of Earth s local gravitational field I Data Acquisition and Preliminary Analysis Dr. Timothy C. Black Summer I, 2018

Physics 201 Lab 3: Measurement of Earth s local gravitational field I Data Acquisition and Preliminary Analysis Dr. Timothy C. Black Summer I, 2018 Physics 201 Lb 3: Mesurement of Erth s locl grvittionl field I Dt Acquisition nd Preliminry Anlysis Dr. Timothy C. Blck Summer I, 2018 Theoreticl Discussion Grvity is one of the four known fundmentl forces.

More information

Lecture 12 Krane Enge Cohen Williams

Lecture 12 Krane Enge Cohen Williams Lecture 1 Krne Enge Cohen Willims -decy Energetics 8.1 10.1 Systemtics 8.3 10.3 6. Coulomb effects 8.4 10.5 10.4 6.3 ngulr mom. 8.5 10.6 10.5 6.4 g-decy Multipole rdn. 10. 9.5 1.1 Decy constnts 10.3 9.5

More information

Phys 7221, Fall 2006: Homework # 6

Phys 7221, Fall 2006: Homework # 6 Phys 7221, Fll 2006: Homework # 6 Gbriel González October 29, 2006 Problem 3-7 In the lbortory system, the scttering ngle of the incident prticle is ϑ, nd tht of the initilly sttionry trget prticle, which

More information

Quantum Physics I (8.04) Spring 2016 Assignment 8

Quantum Physics I (8.04) Spring 2016 Assignment 8 Quntum Physics I (8.04) Spring 206 Assignment 8 MIT Physics Deprtment Due Fridy, April 22, 206 April 3, 206 2:00 noon Problem Set 8 Reding: Griffiths, pges 73-76, 8-82 (on scttering sttes). Ohnin, Chpter

More information

Prep Session Topic: Particle Motion

Prep Session Topic: Particle Motion Student Notes Prep Session Topic: Prticle Motion Number Line for AB Prticle motion nd similr problems re on the AP Clculus exms lmost every yer. The prticle my be prticle, person, cr, etc. The position,

More information

The Properties of Stars

The Properties of Stars 10/11/010 The Properties of Strs sses Using Newton s Lw of Grvity to Determine the ss of Celestil ody ny two prticles in the universe ttrct ech other with force tht is directly proportionl to the product

More information

ODE: Existence and Uniqueness of a Solution

ODE: Existence and Uniqueness of a Solution Mth 22 Fll 213 Jerry Kzdn ODE: Existence nd Uniqueness of Solution The Fundmentl Theorem of Clculus tells us how to solve the ordinry differentil eqution (ODE) du = f(t) dt with initil condition u() =

More information

A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H. Thomas Shores Department of Mathematics University of Nebraska Spring 2007

A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H. Thomas Shores Department of Mathematics University of Nebraska Spring 2007 A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H Thoms Shores Deprtment of Mthemtics University of Nebrsk Spring 2007 Contents Rtes of Chnge nd Derivtives 1 Dierentils 4 Are nd Integrls 5 Multivrite Clculus

More information

USA Mathematical Talent Search Round 1 Solutions Year 21 Academic Year

USA Mathematical Talent Search Round 1 Solutions Year 21 Academic Year 1/1/21. Fill in the circles in the picture t right with the digits 1-8, one digit in ech circle with no digit repeted, so tht no two circles tht re connected by line segment contin consecutive digits.

More information

Lecture 1. Functional series. Pointwise and uniform convergence.

Lecture 1. Functional series. Pointwise and uniform convergence. 1 Introduction. Lecture 1. Functionl series. Pointwise nd uniform convergence. In this course we study mongst other things Fourier series. The Fourier series for periodic function f(x) with period 2π is

More information

PHY4605 Introduction to Quantum Mechanics II Spring 2005 Final exam SOLUTIONS April 22, 2005

PHY4605 Introduction to Quantum Mechanics II Spring 2005 Final exam SOLUTIONS April 22, 2005 . Short Answer. PHY4605 Introduction to Quntum Mechnics II Spring 005 Finl exm SOLUTIONS April, 005 () Write the expression ψ ψ = s n explicit integrl eqution in three dimensions, ssuming tht ψ represents

More information

The area under the graph of f and above the x-axis between a and b is denoted by. f(x) dx. π O

The area under the graph of f and above the x-axis between a and b is denoted by. f(x) dx. π O 1 Section 5. The Definite Integrl Suppose tht function f is continuous nd positive over n intervl [, ]. y = f(x) x The re under the grph of f nd ove the x-xis etween nd is denoted y f(x) dx nd clled the

More information

Multivariate problems and matrix algebra

Multivariate problems and matrix algebra University of Ferrr Stefno Bonnini Multivrite problems nd mtrix lgebr Multivrite problems Multivrite sttisticl nlysis dels with dt contining observtions on two or more chrcteristics (vribles) ech mesured

More information

MATH 144: Business Calculus Final Review

MATH 144: Business Calculus Final Review MATH 144: Business Clculus Finl Review 1 Skills 1. Clculte severl limits. 2. Find verticl nd horizontl symptotes for given rtionl function. 3. Clculte derivtive by definition. 4. Clculte severl derivtives

More information

Improper Integrals. Type I Improper Integrals How do we evaluate an integral such as

Improper Integrals. Type I Improper Integrals How do we evaluate an integral such as Improper Integrls Two different types of integrls cn qulify s improper. The first type of improper integrl (which we will refer to s Type I) involves evluting n integrl over n infinite region. In the grph

More information

Chapter 5. , r = r 1 r 2 (1) µ = m 1 m 2. r, r 2 = R µ m 2. R(m 1 + m 2 ) + m 2 r = r 1. m 2. r = r 1. R + µ m 1

Chapter 5. , r = r 1 r 2 (1) µ = m 1 m 2. r, r 2 = R µ m 2. R(m 1 + m 2 ) + m 2 r = r 1. m 2. r = r 1. R + µ m 1 Tor Kjellsson Stockholm University Chpter 5 5. Strting with the following informtion: R = m r + m r m + m, r = r r we wnt to derive: µ = m m m + m r = R + µ m r, r = R µ m r 3 = µ m R + r, = µ m R r. 4

More information

MATHS NOTES. SUBJECT: Maths LEVEL: Higher TEACHER: Aidan Roantree. The Institute of Education Topics Covered: Powers and Logs

MATHS NOTES. SUBJECT: Maths LEVEL: Higher TEACHER: Aidan Roantree. The Institute of Education Topics Covered: Powers and Logs MATHS NOTES The Institute of Eduction 06 SUBJECT: Mths LEVEL: Higher TEACHER: Aidn Rontree Topics Covered: Powers nd Logs About Aidn: Aidn is our senior Mths techer t the Institute, where he hs been teching

More information

Module 6: LINEAR TRANSFORMATIONS

Module 6: LINEAR TRANSFORMATIONS Module 6: LINEAR TRANSFORMATIONS. Trnsformtions nd mtrices Trnsformtions re generliztions of functions. A vector x in some set S n is mpped into m nother vector y T( x). A trnsformtion is liner if, for

More information

September 13 Homework Solutions

September 13 Homework Solutions College of Engineering nd Computer Science Mechnicl Engineering Deprtment Mechnicl Engineering 5A Seminr in Engineering Anlysis Fll Ticket: 5966 Instructor: Lrry Cretto Septemer Homework Solutions. Are

More information

The graphs of Rational Functions

The graphs of Rational Functions Lecture 4 5A: The its of Rtionl Functions s x nd s x + The grphs of Rtionl Functions The grphs of rtionl functions hve severl differences compred to power functions. One of the differences is the behvior

More information

CHM Physical Chemistry I Chapter 1 - Supplementary Material

CHM Physical Chemistry I Chapter 1 - Supplementary Material CHM 3410 - Physicl Chemistry I Chpter 1 - Supplementry Mteril For review of some bsic concepts in mth, see Atkins "Mthemticl Bckground 1 (pp 59-6), nd "Mthemticl Bckground " (pp 109-111). 1. Derivtion

More information

University of Alabama Department of Physics and Astronomy. PH126: Exam 1

University of Alabama Department of Physics and Astronomy. PH126: Exam 1 University of Albm Deprtment of Physics nd Astronomy PH 16 LeClir Fll 011 Instructions: PH16: Exm 1 1. Answer four of the five questions below. All problems hve equl weight.. You must show your work for

More information

Sufficient condition on noise correlations for scalable quantum computing

Sufficient condition on noise correlations for scalable quantum computing Sufficient condition on noise correltions for sclble quntum computing John Presill, 2 Februry 202 Is quntum computing sclble? The ccurcy threshold theorem for quntum computtion estblishes tht sclbility

More information

Applications of Bernoulli s theorem. Lecture - 7

Applications of Bernoulli s theorem. Lecture - 7 Applictions of Bernoulli s theorem Lecture - 7 Prcticl Applictions of Bernoulli s Theorem The Bernoulli eqution cn be pplied to gret mny situtions not just the pipe flow we hve been considering up to now.

More information

FBR Neutronics: Breeding potential, Breeding Ratio, Breeding Gain and Doubling time

FBR Neutronics: Breeding potential, Breeding Ratio, Breeding Gain and Doubling time FBR eutronics: Breeding potentil, Breeding Rtio, Breeding Gin nd Doubling time K.S. Rjn Proessor, School o Chemicl & Biotechnology SASTRA University Joint Inititive o IITs nd IISc Funded by MHRD Pge 1

More information

Conservation Law. Chapter Goal. 5.2 Theory

Conservation Law. Chapter Goal. 5.2 Theory Chpter 5 Conservtion Lw 5.1 Gol Our long term gol is to understnd how mny mthemticl models re derived. We study how certin quntity chnges with time in given region (sptil domin). We first derive the very

More information

The Wave Equation I. MA 436 Kurt Bryan

The Wave Equation I. MA 436 Kurt Bryan 1 Introduction The Wve Eqution I MA 436 Kurt Bryn Consider string stretching long the x xis, of indeterminte (or even infinite!) length. We wnt to derive n eqution which models the motion of the string

More information

Duality # Second iteration for HW problem. Recall our LP example problem we have been working on, in equality form, is given below.

Duality # Second iteration for HW problem. Recall our LP example problem we have been working on, in equality form, is given below. Dulity #. Second itertion for HW problem Recll our LP emple problem we hve been working on, in equlity form, is given below.,,,, 8 m F which, when written in slightly different form, is 8 F Recll tht we

More information

W. We shall do so one by one, starting with I 1, and we shall do it greedily, trying

W. We shall do so one by one, starting with I 1, and we shall do it greedily, trying Vitli covers 1 Definition. A Vitli cover of set E R is set V of closed intervls with positive length so tht, for every δ > 0 nd every x E, there is some I V with λ(i ) < δ nd x I. 2 Lemm (Vitli covering)

More information

Precalculus Spring 2017

Precalculus Spring 2017 Preclculus Spring 2017 Exm 3 Summry (Section 4.1 through 5.2, nd 9.4) Section P.5 Find domins of lgebric expressions Simplify rtionl expressions Add, subtrct, multiply, & divide rtionl expressions Simplify

More information

Riemann Sums and Riemann Integrals

Riemann Sums and Riemann Integrals Riemnn Sums nd Riemnn Integrls Jmes K. Peterson Deprtment of Biologicl Sciences nd Deprtment of Mthemticl Sciences Clemson University August 26, 2013 Outline 1 Riemnn Sums 2 Riemnn Integrls 3 Properties

More information

APPROXIMATE INTEGRATION

APPROXIMATE INTEGRATION APPROXIMATE INTEGRATION. Introduction We hve seen tht there re functions whose nti-derivtives cnnot be expressed in closed form. For these resons ny definite integrl involving these integrnds cnnot be

More information

1.2. Linear Variable Coefficient Equations. y + b "! = a y + b " Remark: The case b = 0 and a non-constant can be solved with the same idea as above.

1.2. Linear Variable Coefficient Equations. y + b ! = a y + b  Remark: The case b = 0 and a non-constant can be solved with the same idea as above. 1 12 Liner Vrible Coefficient Equtions Section Objective(s): Review: Constnt Coefficient Equtions Solving Vrible Coefficient Equtions The Integrting Fctor Method The Bernoulli Eqution 121 Review: Constnt

More information

Math 8 Winter 2015 Applications of Integration

Math 8 Winter 2015 Applications of Integration Mth 8 Winter 205 Applictions of Integrtion Here re few importnt pplictions of integrtion. The pplictions you my see on n exm in this course include only the Net Chnge Theorem (which is relly just the Fundmentl

More information

Lecture 09: Myhill-Nerode Theorem

Lecture 09: Myhill-Nerode Theorem CS 373: Theory of Computtion Mdhusudn Prthsrthy Lecture 09: Myhill-Nerode Theorem 16 Ferury 2010 In this lecture, we will see tht every lnguge hs unique miniml DFA We will see this fct from two perspectives

More information

#6A&B Magnetic Field Mapping

#6A&B Magnetic Field Mapping #6A& Mgnetic Field Mpping Gol y performing this lb experiment, you will: 1. use mgnetic field mesurement technique bsed on Frdy s Lw (see the previous experiment),. study the mgnetic fields generted by

More information

Riemann Sums and Riemann Integrals

Riemann Sums and Riemann Integrals Riemnn Sums nd Riemnn Integrls Jmes K. Peterson Deprtment of Biologicl Sciences nd Deprtment of Mthemticl Sciences Clemson University August 26, 203 Outline Riemnn Sums Riemnn Integrls Properties Abstrct

More information

Minimal DFA. minimal DFA for L starting from any other

Minimal DFA. minimal DFA for L starting from any other Miniml DFA Among the mny DFAs ccepting the sme regulr lnguge L, there is exctly one (up to renming of sttes) which hs the smllest possile numer of sttes. Moreover, it is possile to otin tht miniml DFA

More information

University of Washington Department of Chemistry Chemistry 453 Winter Quarter 2010 Homework Assignment 4; Due at 5p.m. on 2/01/10

University of Washington Department of Chemistry Chemistry 453 Winter Quarter 2010 Homework Assignment 4; Due at 5p.m. on 2/01/10 University of Wshington Deprtment of Chemistry Chemistry 45 Winter Qurter Homework Assignment 4; Due t 5p.m. on // We lerned tht the Hmiltonin for the quntized hrmonic oscilltor is ˆ d κ H. You cn obtin

More information

Simulation of Eclipsing Binary Star Systems. Abstract

Simulation of Eclipsing Binary Star Systems. Abstract Simultion of Eclipsing Binry Str Systems Boris Yim 1, Kenny Chn 1, Rphel Hui 1 Wh Yn College Kowloon Diocesn Boys School Abstrct This report briefly introduces the informtion on eclipsing binry str systems.

More information

2.57/2.570 Midterm Exam No. 1 March 31, :00 am -12:30 pm

2.57/2.570 Midterm Exam No. 1 March 31, :00 am -12:30 pm 2.57/2.570 Midterm Exm No. 1 Mrch 31, 2010 11:00 m -12:30 pm Instructions: (1) 2.57 students: try ll problems (2) 2.570 students: Problem 1 plus one of two long problems. You cn lso do both long problems,

More information

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department Statistical Physics I Spring Term Solutions to Problem Set #1

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department Statistical Physics I Spring Term Solutions to Problem Set #1 MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Deprtment 8.044 Sttisticl Physics I Spring Term 03 Problem : Doping Semiconductor Solutions to Problem Set # ) Mentlly integrte the function p(x) given in

More information

How to simulate Turing machines by invertible one-dimensional cellular automata

How to simulate Turing machines by invertible one-dimensional cellular automata How to simulte Turing mchines by invertible one-dimensionl cellulr utomt Jen-Christophe Dubcq Déprtement de Mthémtiques et d Informtique, École Normle Supérieure de Lyon, 46, llée d Itlie, 69364 Lyon Cedex

More information

We divide the interval [a, b] into subintervals of equal length x = b a n

We divide the interval [a, b] into subintervals of equal length x = b a n Arc Length Given curve C defined by function f(x), we wnt to find the length of this curve between nd b. We do this by using process similr to wht we did in defining the Riemnn Sum of definite integrl:

More information

Goals: Determine how to calculate the area described by a function. Define the definite integral. Explore the relationship between the definite

Goals: Determine how to calculate the area described by a function. Define the definite integral. Explore the relationship between the definite Unit #8 : The Integrl Gols: Determine how to clculte the re described by function. Define the definite integrl. Eplore the reltionship between the definite integrl nd re. Eplore wys to estimte the definite

More information

1B40 Practical Skills

1B40 Practical Skills B40 Prcticl Skills Comining uncertinties from severl quntities error propgtion We usully encounter situtions where the result of n experiment is given in terms of two (or more) quntities. We then need

More information

CS 373, Spring Solutions to Mock midterm 1 (Based on first midterm in CS 273, Fall 2008.)

CS 373, Spring Solutions to Mock midterm 1 (Based on first midterm in CS 273, Fall 2008.) CS 373, Spring 29. Solutions to Mock midterm (sed on first midterm in CS 273, Fll 28.) Prolem : Short nswer (8 points) The nswers to these prolems should e short nd not complicted. () If n NF M ccepts

More information

Section 14.3 Arc Length and Curvature

Section 14.3 Arc Length and Curvature Section 4.3 Arc Length nd Curvture Clculus on Curves in Spce In this section, we ly the foundtions for describing the movement of n object in spce.. Vector Function Bsics In Clc, formul for rc length in

More information

Lecture 08: Feb. 08, 2019

Lecture 08: Feb. 08, 2019 4CS4-6:Theory of Computtion(Closure on Reg. Lngs., regex to NDFA, DFA to regex) Prof. K.R. Chowdhry Lecture 08: Fe. 08, 2019 : Professor of CS Disclimer: These notes hve not een sujected to the usul scrutiny

More information

- 5 - TEST 2. This test is on the final sections of this session's syllabus and. should be attempted by all students.

- 5 - TEST 2. This test is on the final sections of this session's syllabus and. should be attempted by all students. - 5 - TEST 2 This test is on the finl sections of this session's syllbus nd should be ttempted by ll students. Anything written here will not be mrked. - 6 - QUESTION 1 [Mrks 22] A thin non-conducting

More information

Physics Graduate Prelim exam

Physics Graduate Prelim exam Physics Grdute Prelim exm Fll 2008 Instructions: This exm hs 3 sections: Mechnics, EM nd Quntum. There re 3 problems in ech section You re required to solve 2 from ech section. Show ll work. This exm is

More information

Riemann is the Mann! (But Lebesgue may besgue to differ.)

Riemann is the Mann! (But Lebesgue may besgue to differ.) Riemnn is the Mnn! (But Lebesgue my besgue to differ.) Leo Livshits My 2, 2008 1 For finite intervls in R We hve seen in clss tht every continuous function f : [, b] R hs the property tht for every ɛ >

More information