19. Oscillations. Objectives. By Liew Sau Poh. Outcomes. Outcomes. Periodic Motion Characteristics of SHM. Position VS.

Size: px
Start display at page:

Download "19. Oscillations. Objectives. By Liew Sau Poh. Outcomes. Outcomes. Periodic Motion Characteristics of SHM. Position VS."

Transcription

1 9. Oscillions By iew Su Poh Ojecies 9. Chrcerisics of siple hronic oion 9. Kineics of siple hronic oion 9.3 Enery in siple hronic oion 9.4 Syses in siple hronic oion 9.5 Dpe oscillions 9.6 Force oscillions n Resonnce Oucoes ) efine siple hronic oion y ens of he equion = ) Show h = o sin s soluion of = c) erie n use he forul = ( ) ) escrie, wih rphicl illusrions, he riion in isplceen, elociy n ccelerion wih ie e) escrie, wih rphicl illusrions, he riion in elociy n ccelerion wih isplceen f) erie n use he epressions for ineic enery n poenil enery ) escrie, wih rphicl illusrions, he riion in ineic enery n poenil enery wih ie n isplceen 3 Oucoes h) erie n use epressions for he perios of oscillions for sprin-ss n siple penulu syses i) escrie he chnes in pliue n enery for pe oscillin syse j) isinuish eween uner pin, criicl pin n oer pin ) isinuish eween free oscillions n force oscillions l) se he coniions for resonnce o occur 4 9. Chrcerisics of SHM his ype of oion is he os persie oion in he unierse. ll os oscille uner hronic oion. We cn oel his oion wih liner resorin force. Perioic Moion Moion h repes in reulr pern oer n oer in is clle perioic oion. Siple hronic oion is specific ype of perioic oion h hs siple sine or cosine we shpe. 5 6 Posiion VS. ie rph Wh is he siple heicl for of SHM oion? he isplceen of he oscillin ss ries sinusoilly s funcion of ie. Here Oscillin ss on Sprin Perioic Moion Siple Hronic Moion 7 8

2 9 he resorin force of n iel sprin is ien y: F = - where is he sprin consn n is he isplceen of he sprin fro is unsrine lenh. he inus sin inices h he resorin force lwys poins in opposie irecion o he isplceen of he sprin. Siple Hronic Moion When here is resorin force, F = -, siple hronic oion occurs. 9. Kineics of SHM Siple Hronic Moion F s = - (SHM) occurs when he force cin on oy is proporionl o he F s = isplceen of he oy fro soe equiliriu F s = + posiion (e. sprin or penulu). - = 9. Kineics of SHM = - (/) f we ry = cos(w+f) s soluion o his equion, we oin: So 3 sin ( SHM ) cos 9.3 Enery in SHM Equion for Siple Hronic Moion 9. Kineics of SHM - F s = - = F s = F s = + When he loc che o he sprin (lef) is isplce sll isnce fro equiliriu, he sprin eers resorin force which is proporionl o he isplceen: 9.3 Enery in SHM ol Enery = Kineic Enery + Poenil Enery E = K + U 4 K U 9.3 Enery in SHM Moion K K sin sin U U cos cos E consn rne of oion E U consn 5 6 urnin poin urnin poin

3 KE n PE Conersion pliue F s = F s = - KE U KE U cos cos pliue is he niue of he iu isplceen. F s = = KE U 8 Perio, Frequency, f For ny ojec in siple hronic oion, he ie require o coplee one cycle is he perio. he frequency f of he siple hronic oion is he nuer of cycles of he oion per secon. f 9 Enery of he Siple Hronic Oscillor For isplceen = cos (w+f), we cn sy h ineic enery, KE is: PE E E E ol ol ol KE PE. KE cos sin Poenil enery (elsic) PE is: sin cos hus, ol enery is proporionl o pliue. Enery rnsfer / KE, U = correspons o he sreche sprin. 3 / - KE, U + = correspons o equiliriu posiion of sprin. nulr Frequency 4 Since / or f / ( resorin force )

4 9.4 Syses in SHM. Penulus. he Siple Penulu. he Physicl Penulu 3.. SHM & Unifor Circulr Moion 3. Dpe SHM 4. Force Oscillions & Resonnce Griionl Penulu Siple Penulu: o of ss hun on n unsrechle ssless srin of lenh. 5 6 Siple Penulu he Siple Penulu 7 SHM for sll F sin ccelerion ~ - isplceen SHM F 8 sin Bu Coprin = (sin ) in r penulu lein ril of in: Physicl Penulu rii oy pioe ou poin oher hn is cener of ss (co). SHM for sll h F sin h F Pio Cener of Mss ccelerion ~ - isplceen SHM h 9 3 quic eho o esure h he orsionl Penulu Siple Hronic Moion orsion Penulu: 33 Sprin: 34 ny Oscillin Syse: ineri sprininess h

5 SHM & Unifor Circulr Moion he projecion of poin oin in unifor circulr oion on ieer of he circle in which he oion occurs eecues SHM. SHM & Unifor Circulr Moion he reference poin of rius. he projecion of on ieer of he circle eecues SHM. he eecuion of unifor circulr oion escries SHM. 35 hp://posiron.ps.uci.eu/~iry/usic/hl/eos/siplehronicmoion/circul r.hl SHM & Unifor Circulr Moion. he projecion of on ieer of he circle eecues SHM. c o s 36 UC rine Physics of Music Siple Hronic Moion pple Deonsrions rius = n le SHM & Unifor Circulr Moion he projecion of poin oin in unifor circulr oion on ieer of he circle in which he oion occurs eecues SHM. Mesureens of he nle eween Clliso n Jupier: Glileo (6) () () () plne s in c o s rius = 37 cos 38 erh Equions of Moion (SHM) Displceen-ie Grph = cos = - sin = cos = - cos = ± ( - ).5 = - [he efiniion] Velociy-ie Grph ccelerion-ie Grph = sin = cos 4 4

6 Velociy-Displceen Grph ccelerion-displceen Grph = ± ).5 = [he efiniion] Phse Relionship Free oscillions When syse oscilles wihou eernl forces cin on i, he syse is in free oscillion. he pliue of oscillion is consn, which will no rop. Displceen, ie Dpe Oscillions n ny rel syses, nonconserie forces re presen his is no loner n iel syse (he ype we he el wih so fr) Fricion is coon nonconserie force n his cse, he echnicl enery of he syse iinishes in ie, he oion is si o e pe 9.5 Dpe Oscillions Dpe hronic oion is hronic oion wih fricionl or r force. f he pin is oifies he unpe oscillion Dpe SHM SHM in which ech oscillion is reuce y n eernl force. F Dpe SHM Fne Resorin Force SHM F Dpin Force n opposie irecion o elociy Does neie wor Reuces he echnicl enery D ifferenil equion 49 5

7 9.5 Dpe Oscillions rph for pe oscillion he pliue ecreses wih ie he lue she lines represen he enelope of he oion 9.5 Dpe Oscillion One eple of pe oion occurs when n ojec is che o sprin n suere in iscous liqui he rerin force cn e epresse s R = - where is consn n is clle he pin coefficien Dpe Oscillion Howeer, if he pin is lre, i no loner reseles SHM ll. : unerpin: here re few sll oscillions efore he oscillor coes o res Dpe Oscillion B: criicl pin: his is he fses wy o e o equiliriu. C: oerpin: he syse is slowe so uch h i es lon ie o e o equiliriu Dpe Oscillion here re syses where pin is unwne, such s clocs n wches. hen here re syses in which i is wne, n ofen nees o e s close o criicl pin s possile, such s uooile shoc sorers n erhque proecion for uilins. 9.5 Dpe Oscillion n Orer Hooeneous iner Differenil Equion: Soluion of Differenil Equion: ( ) e cos where: = SHM Dpe Oscillions uo Shoc sorers ( ) e cos 57 sll pin he nurl frequency " criiclly pe" " oer pe " Eponenil soluion o he DE 58 ypicl uooile shoc sorers re esine o prouce slihly uner-pe oion

8 9.6 Force Oscillions & Resonnce Force oscillions occur when here is perioic riin force. his force y or y no he he se perio s he nurl frequency of he syse. f he frequency is he se s he nurl frequency, he pliue ecoes quie lre. his is clle resonnce. 9.6 Force Oscillions & Resonnce is possile o copense for he loss of enery in pe syse y pplyin n eernl force he pliue of he oion reins consn if he enery inpu per cycle ecly equls he ecrese in echnicl enery in ech cycle h resuls fro resisie forces Force Oscillions & Resonnce fer riin force on n iniilly sionry ojec eins o c, he pliue of he oscillion will increse fer sufficienly lon perio of ie, E riin = E los o inernl hen sey-se coniion is reche he oscillions will procee wih consn pliue Force Oscillions & Resonnce When he frequency of he riin force is ner o he nurl frequency (» ) n increse in pliue occurs his ric increse in he pliue is clle resonnce he nurl frequency is lso clle he resonnce frequency of he syse 9.6 Force Oscillions & Resonnce he shrpness of he resonn pe epens on he pin. f he pin is sll (), i cn e quie shrp; if he pin is lrer (B), i is less shrp. Eernl frequency f ie pin, resonnce cn e wne or unwne. Musicl insruens n V/rio receiers 6 epen on i. 9.6 Force Oscillions & Resonnce Ech oscillion is rien y n eernl force o inin oion in he presence of pin: F cos w = riin frequency Force Oscillions & Resonnce Ech oscillion is rien y n eernl force o inin oion in he presence of pin. 65 n Orer nhooeneous iner Differenil Equion: F cos 9.6 Force Oscillions & Resonnce 66 n Orer Hooeneous iner Differenil Equion: Sey-Se Soluion of Differenil Equion: ( ) cos where: n F F cos w = nurl frequency w = riin frequency

9 9.6 Force Oscillions & Resonnce he nurl frequency, w, is he frequency of oscillion when here is no eernl riin force or pin. F less pin ore pin w = nurl frequency w = riin frequency When w = w resonnce occurs! Sop he SHM cuse y wins on hihrise uilin 4 on weih oune on sprin on hih floor of he Ciicorp uilin in New Yor. he weih is force o oscille he se frequency s he uilin u 9 erees ou of 7 phse. 69 Sury OSCON Free Dpe Displceen, Force Oscillions n Resonnce less pin 7 ie ore pin

Chapter 10. Simple Harmonic Motion and Elasticity. Goals for Chapter 10

Chapter 10. Simple Harmonic Motion and Elasticity. Goals for Chapter 10 Chper 0 Siple Hronic Moion nd Elsiciy Gols or Chper 0 o ollow periodic oion o sudy o siple hronic oion. o sole equions o siple hronic oion. o use he pendulu s prooypicl syse undergoing siple hronic oion.

More information

P441 Analytical Mechanics - I. Coupled Oscillators. c Alex R. Dzierba

P441 Analytical Mechanics - I. Coupled Oscillators. c Alex R. Dzierba Lecure 3 Mondy - Deceber 5, 005 Wrien or ls upded: Deceber 3, 005 P44 Anlyicl Mechnics - I oupled Oscillors c Alex R. Dzierb oupled oscillors - rix echnique In Figure we show n exple of wo coupled oscillors,

More information

Practice Problems - Week #4 Higher-Order DEs, Applications Solutions

Practice Problems - Week #4 Higher-Order DEs, Applications Solutions Pracice Probles - Wee #4 Higher-Orer DEs, Applicaions Soluions 1. Solve he iniial value proble where y y = 0, y0 = 0, y 0 = 1, an y 0 =. r r = rr 1 = rr 1r + 1, so he general soluion is C 1 + C e x + C

More information

3 Motion with constant acceleration: Linear and projectile motion

3 Motion with constant acceleration: Linear and projectile motion 3 Moion wih consn ccelerion: Liner nd projecile moion cons, In he precedin Lecure we he considered moion wih consn ccelerion lon he is: Noe h,, cn be posiie nd neie h leds o rie of behiors. Clerl similr

More information

TEST - 4 (Paper-I) ANSWERS PHYSICS CHEMISTRY MATHEMATICS

TEST - 4 (Paper-I) ANSWERS PHYSICS CHEMISTRY MATHEMATICS TEST - 4 (Pper-I) NSWERS PHYSICS CHEMISTRY MTHEMTICS. (4). (). () 4. () 5. () 6. (4) 7. () 8. () 9. (). (). (). (). () 4. () 5. () 6. (4) 7. () 8. (4) 9. (). (). (). (). () 4. (4) 5. (4) 6. () 7. () 8.

More information

Forms of Energy. Mass = Energy. Page 1. SPH4U: Introduction to Work. Work & Energy. Particle Physics:

Forms of Energy. Mass = Energy. Page 1. SPH4U: Introduction to Work. Work & Energy. Particle Physics: SPH4U: Inroducion o ork ork & Energy ork & Energy Discussion Definiion Do Produc ork of consn force ork/kineic energy heore ork of uliple consn forces Coens One of he os iporn conceps in physics Alernive

More information

Chapter 2. Motion along a straight line. 9/9/2015 Physics 218

Chapter 2. Motion along a straight line. 9/9/2015 Physics 218 Chper Moion long srigh line 9/9/05 Physics 8 Gols for Chper How o describe srigh line moion in erms of displcemen nd erge elociy. The mening of insnneous elociy nd speed. Aerge elociy/insnneous elociy

More information

t v a t area Dynamic Physics for Simulation and Game Programming F a m v v a t x x v t Discrete Dynamics

t v a t area Dynamic Physics for Simulation and Game Programming F a m v v a t x x v t Discrete Dynamics Dynic Physics for Siulion n Ge Progring F Discree Dynics. Force equls ss ies ccelerion (F=) v v v v Mike Biley This work is license uner Creive Coons Aribuion-NonCoercil- NoDerivives.0 Inernionl License

More information

Physics Worksheet Lesson 4: Linear Motion Section: Name:

Physics Worksheet Lesson 4: Linear Motion Section: Name: Physics Workshee Lesson 4: Liner Moion Secion: Nme: 1. Relie Moion:. All moion is. b. is n rbirry coorine sysem wih reference o which he posiion or moion of somehing is escribe or physicl lws re formule.

More information

An object moving with speed v around a point at distance r, has an angular velocity. m/s m

An object moving with speed v around a point at distance r, has an angular velocity. m/s m Roion The mosphere roes wih he erh n moions wihin he mosphere clerly follow cure phs (cyclones, nicyclones, hurricnes, ornoes ec.) We nee o epress roion quniiely. For soli objec or ny mss h oes no isor

More information

Motion. Part 2: Constant Acceleration. Acceleration. October Lab Physics. Ms. Levine 1. Acceleration. Acceleration. Units for Acceleration.

Motion. Part 2: Constant Acceleration. Acceleration. October Lab Physics. Ms. Levine 1. Acceleration. Acceleration. Units for Acceleration. Moion Accelerion Pr : Consn Accelerion Accelerion Accelerion Accelerion is he re of chnge of velociy. = v - vo = Δv Δ ccelerion = = v - vo chnge of velociy elpsed ime Accelerion is vecor, lhough in one-dimensionl

More information

Simple Harmonic Motion

Simple Harmonic Motion Sipe Hronic Moion 75 6 Sipe Hronic Moion Periodic nd Oscior (Vibror) Moion () oion, which repe isef over nd over in fer reur inerv of ie is ced periodic oion Revouion of erh round he sun (period one er),

More information

1. Consider a PSA initially at rest in the beginning of the left-hand end of a long ISS corridor. Assume xo = 0 on the left end of the ISS corridor.

1. Consider a PSA initially at rest in the beginning of the left-hand end of a long ISS corridor. Assume xo = 0 on the left end of the ISS corridor. In Eercise 1, use sndrd recngulr Cresin coordine sysem. Le ime be represened long he horizonl is. Assume ll ccelerions nd decelerions re consn. 1. Consider PSA iniilly res in he beginning of he lef-hnd

More information

A Kalman filtering simulation

A Kalman filtering simulation A Klmn filering simulion The performnce of Klmn filering hs been esed on he bsis of wo differen dynmicl models, ssuming eiher moion wih consn elociy or wih consn ccelerion. The former is epeced o beer

More information

Homework 2 Solutions

Homework 2 Solutions Mah 308 Differenial Equaions Fall 2002 & 2. See he las page. Hoework 2 Soluions 3a). Newon s secon law of oion says ha a = F, an we know a =, so we have = F. One par of he force is graviy, g. However,

More information

2D Motion WS. A horizontally launched projectile s initial vertical velocity is zero. Solve the following problems with this information.

2D Motion WS. A horizontally launched projectile s initial vertical velocity is zero. Solve the following problems with this information. Nme D Moion WS The equions of moion h rele o projeciles were discussed in he Projecile Moion Anlsis Acii. ou found h projecile moes wih consn eloci in he horizonl direcion nd consn ccelerion in he ericl

More information

Viscous Damping Summary Sheet No Damping Case: Damped behaviour depends on the relative size of ω o and b/2m 3 Cases: 1.

Viscous Damping Summary Sheet No Damping Case: Damped behaviour depends on the relative size of ω o and b/2m 3 Cases: 1. Viscous Daping: && + & + ω Viscous Daping Suary Shee No Daping Case: & + ω solve A ( ω + α ) Daped ehaviour depends on he relaive size of ω o and / 3 Cases:. Criical Daping Wee 5 Lecure solve sae BC s

More information

Gravity and SHM Review Questions

Gravity and SHM Review Questions Graviy an SHM Review Quesions 1. The mass of Plane X is one-enh ha of he Earh, an is iameer is one-half ha of he Earh. The acceleraion ue o raviy a he surface of Plane X is mos nearly m/s (B) 4m/s (C)

More information

Motion in a Straight Line

Motion in a Straight Line Moion in Srigh Line. Preei reched he mero sion nd found h he esclor ws no working. She wlked up he sionry esclor in ime. On oher dys, if she remins sionry on he moing esclor, hen he esclor kes her up in

More information

ENGR 1990 Engineering Mathematics The Integral of a Function as a Function

ENGR 1990 Engineering Mathematics The Integral of a Function as a Function ENGR 1990 Engineering Mhemics The Inegrl of Funcion s Funcion Previously, we lerned how o esime he inegrl of funcion f( ) over some inervl y dding he res of finie se of rpezoids h represen he re under

More information

0 for t < 0 1 for t > 0

0 for t < 0 1 for t > 0 8.0 Sep nd del funcions Auhor: Jeremy Orloff The uni Sep Funcion We define he uni sep funcion by u() = 0 for < 0 for > 0 I is clled he uni sep funcion becuse i kes uni sep = 0. I is someimes clled he Heviside

More information

PHYSICS 1210 Exam 1 University of Wyoming 14 February points

PHYSICS 1210 Exam 1 University of Wyoming 14 February points PHYSICS 1210 Em 1 Uniersiy of Wyoming 14 Februry 2013 150 poins This es is open-noe nd closed-book. Clculors re permied bu compuers re no. No collborion, consulion, or communicion wih oher people (oher

More information

Physics 100: Lecture 1

Physics 100: Lecture 1 Physics : Lecure Agen for Toy Aice Scope of his course Mesuremen n Unis Funmenl unis Sysems of unis Conering beween sysems of unis Dimensionl Anlysis -D Kinemics (reiew) Aerge & insnneous elociy n ccelerion

More information

Chapter Direct Method of Interpolation

Chapter Direct Method of Interpolation Chper 5. Direc Mehod of Inerpolion Afer reding his chper, you should be ble o:. pply he direc mehod of inerpolion,. sole problems using he direc mehod of inerpolion, nd. use he direc mehod inerpolns o

More information

The Spring. Consider a spring, which we apply a force F A to either stretch it or compress it

The Spring. Consider a spring, which we apply a force F A to either stretch it or compress it The Spring Consider spring, which we pply force F A to either stretch it or copress it F A - unstretched -F A 0 F A k k is the spring constnt, units of N/, different for different terils, nuber of coils

More information

September 20 Homework Solutions

September 20 Homework Solutions College of Engineering nd Compuer Science Mechnicl Engineering Deprmen Mechnicl Engineering A Seminr in Engineering Anlysis Fll 7 Number 66 Insrucor: Lrry Creo Sepember Homework Soluions Find he specrum

More information

e t dt e t dt = lim e t dt T (1 e T ) = 1

e t dt e t dt = lim e t dt T (1 e T ) = 1 Improper Inegrls There re wo ypes of improper inegrls - hose wih infinie limis of inegrion, nd hose wih inegrnds h pproch some poin wihin he limis of inegrion. Firs we will consider inegrls wih infinie

More information

Magnetostatics Bar Magnet. Magnetostatics Oersted s Experiment

Magnetostatics Bar Magnet. Magnetostatics Oersted s Experiment Mgneosics Br Mgne As fr bck s 4500 yers go, he Chinese discovered h cerin ypes of iron ore could rc ech oher nd cerin mels. Iron filings "mp" of br mgne s field Crefully suspended slivers of his mel were

More information

HW #1 Solutions. Lewis Structures: Using the above rules, determine the molecular structure for Cl2CO. Hint: C is at the center.

HW #1 Solutions. Lewis Structures: Using the above rules, determine the molecular structure for Cl2CO. Hint: C is at the center. HW # Soluions Cron Mss Prolem: ssuming n erge surfce pressure of m, n erge ropospheric emperure of 55 K, n glol CO mixing rio of 385 ppm, wh is he curren mospheric Cron reseroir (in unis of g m -? Compre

More information

Page 1. Motion in a Circle... Dynamics of Circular Motion. Motion in a Circle... Motion in a Circle... Discussion Problem 21: Motion in a Circle

Page 1. Motion in a Circle... Dynamics of Circular Motion. Motion in a Circle... Motion in a Circle... Discussion Problem 21: Motion in a Circle Dynics of Circulr Motion A boy ties rock of ss to the end of strin nd twirls it in the erticl plne. he distnce fro his hnd to the rock is. he speed of the rock t the top of its trectory is. Wht is the

More information

SOME USEFUL MATHEMATICS

SOME USEFUL MATHEMATICS SOME USEFU MAHEMAICS SOME USEFU MAHEMAICS I is esy o mesure n preic he behvior of n elecricl circui h conins only c volges n currens. However, mos useful elecricl signls h crry informion vry wih ime. Since

More information

PHY2048 Exam 1 Formula Sheet Vectors. Motion. v ave (3 dim) ( (1 dim) dt. ( (3 dim) Equations of Motion (Constant Acceleration)

PHY2048 Exam 1 Formula Sheet Vectors. Motion. v ave (3 dim) ( (1 dim) dt. ( (3 dim) Equations of Motion (Constant Acceleration) Insrucors: Field/Mche PHYSICS DEPATMENT PHY 48 Em Ferur, 5 Nme prin, ls firs: Signure: On m honor, I he neiher gien nor receied unuhoried id on his eminion. YOU TEST NUMBE IS THE 5-DIGIT NUMBE AT THE TOP

More information

Average & instantaneous velocity and acceleration Motion with constant acceleration

Average & instantaneous velocity and acceleration Motion with constant acceleration Physics 7: Lecure Reminders Discussion nd Lb secions sr meeing ne week Fill ou Pink dd/drop form if you need o swich o differen secion h is FULL. Do i TODAY. Homework Ch. : 5, 7,, 3,, nd 6 Ch.: 6,, 3 Submission

More information

6. Gas dynamics. Ideal gases Speed of infinitesimal disturbances in still gas

6. Gas dynamics. Ideal gases Speed of infinitesimal disturbances in still gas 6. Gs dynmics Dr. Gergely Krisóf De. of Fluid echnics, BE Februry, 009. Seed of infiniesiml disurbnces in sill gs dv d, dv d, Coninuiy: ( dv)( ) dv omenum r r heorem: ( ( dv) ) d 3443 4 q m dv d dv llievi

More information

Minimum Squared Error

Minimum Squared Error Minimum Squred Error LDF: Minimum Squred-Error Procedures Ide: conver o esier nd eer undersood prolem Percepron y i > for ll smples y i solve sysem of liner inequliies MSE procedure y i = i for ll smples

More information

(b) 10 yr. (b) 13 m. 1.6 m s, m s m s (c) 13.1 s. 32. (a) 20.0 s (b) No, the minimum distance to stop = 1.00 km. 1.

(b) 10 yr. (b) 13 m. 1.6 m s, m s m s (c) 13.1 s. 32. (a) 20.0 s (b) No, the minimum distance to stop = 1.00 km. 1. Answers o Een Numbered Problems Chper. () 7 m s, 6 m s (b) 8 5 yr 4.. m ih 6. () 5. m s (b).5 m s (c).5 m s (d) 3.33 m s (e) 8. ().3 min (b) 64 mi..3 h. ().3 s (b) 3 m 4..8 mi wes of he flgpole 6. (b)

More information

Minimum Squared Error

Minimum Squared Error Minimum Squred Error LDF: Minimum Squred-Error Procedures Ide: conver o esier nd eer undersood prolem Percepron y i > 0 for ll smples y i solve sysem of liner inequliies MSE procedure y i i for ll smples

More information

MTH 146 Class 11 Notes

MTH 146 Class 11 Notes 8.- Are of Surfce of Revoluion MTH 6 Clss Noes Suppose we wish o revolve curve C round n is nd find he surfce re of he resuling solid. Suppose f( ) is nonnegive funcion wih coninuous firs derivive on he

More information

UNIT # 01 (PART II) JEE-Physics KINEMATICS EXERCISE I. 2h g. 8. t 1 = (4 1)i ˆ (2 2) ˆj (3 3)kˆ 1. ˆv = 2 2h g. t 2 = 2 3h g

UNIT # 01 (PART II) JEE-Physics KINEMATICS EXERCISE I. 2h g. 8. t 1 = (4 1)i ˆ (2 2) ˆj (3 3)kˆ 1. ˆv = 2 2h g. t 2 = 2 3h g J-Physics UNI # (PR II) KINMICS XRCIS I ( )i ˆ ( ) ˆj ( )kˆ i. ˆ ˆ ˆ j i ˆ ˆ j ˆ 6i ˆ 8ˆj 8. h h h C h h.. elociy m/s h D. ˆ i i cos6ˆi sin 6ˆj f ˆ i ˆj i ˆ ˆj i ˆ ˆj i ˆ ˆj f i ˆj ˆj m/s. For,, nd d d

More information

Phys 110. Answers to even numbered problems on Midterm Map

Phys 110. Answers to even numbered problems on Midterm Map Phys Answers o een numbered problems on Miderm Mp. REASONING The word per indices rio, so.35 mm per dy mens.35 mm/d, which is o be epressed s re in f/cenury. These unis differ from he gien unis in boh

More information

Technical Vibration - text 2 - forced vibration, rotational vibration

Technical Vibration - text 2 - forced vibration, rotational vibration Technicl Viion - e - foced viion, oionl viion 4. oced viion, viion unde he consn eenl foce The viion unde he eenl foce. eenl The quesion is if he eenl foce e is consn o vying. If vying, wh is he foce funcion.

More information

Thus the force is proportional but opposite to the displacement away from equilibrium.

Thus the force is proportional but opposite to the displacement away from equilibrium. Chaper 3 : Siple Haronic Moion Hooe s law saes ha he force (F) eered by an ideal spring is proporional o is elongaion l F= l where is he spring consan. Consider a ass hanging on a he spring. In equilibriu

More information

1.0 Electrical Systems

1.0 Electrical Systems . Elecricl Sysems The ypes of dynmicl sysems we will e sudying cn e modeled in erms of lgeric equions, differenil equions, or inegrl equions. We will egin y looking fmilir mhemicl models of idel resisors,

More information

CHAPTER 2: Describing Motion: Kinematics in One Dimension

CHAPTER 2: Describing Motion: Kinematics in One Dimension CHAPTER : Describing Moion: Kinemics in One Dimension Answers o Quesions A cr speeomeer mesures only spee I oes no gie ny informion bou he irecion, n so oes no mesure elociy By efiniion, if n objec hs

More information

Physic 231 Lecture 4. Mi it ftd l t. Main points of today s lecture: Example: addition of velocities Trajectories of objects in 2 = =

Physic 231 Lecture 4. Mi it ftd l t. Main points of today s lecture: Example: addition of velocities Trajectories of objects in 2 = = Mi i fd l Phsic 3 Lecure 4 Min poins of od s lecure: Emple: ddiion of elociies Trjecories of objecs in dimensions: dimensions: g 9.8m/s downwrds ( ) g o g g Emple: A foobll pler runs he pern gien in he

More information

ME 141. Engineering Mechanics

ME 141. Engineering Mechanics ME 141 Engineeing Mechnics Lecue 13: Kinemics of igid bodies hmd Shhedi Shkil Lecue, ep. of Mechnicl Engg, UET E-mil: sshkil@me.bue.c.bd, shkil6791@gmil.com Websie: eche.bue.c.bd/sshkil Couesy: Veco Mechnics

More information

MATH 124 AND 125 FINAL EXAM REVIEW PACKET (Revised spring 2008)

MATH 124 AND 125 FINAL EXAM REVIEW PACKET (Revised spring 2008) MATH 14 AND 15 FINAL EXAM REVIEW PACKET (Revised spring 8) The following quesions cn be used s review for Mh 14/ 15 These quesions re no cul smples of quesions h will pper on he finl em, bu hey will provide

More information

14. The fundamental theorem of the calculus

14. The fundamental theorem of the calculus 4. The funmenl heorem of he clculus V 20 00 80 60 40 20 0 0 0.2 0.4 0.6 0.8 v 400 200 0 0 0.2 0.5 0.8 200 400 Figure : () Venriculr volume for subjecs wih cpciies C = 24 ml, C = 20 ml, C = 2 ml n (b) he

More information

Generalization of a nonlinear friction relation for a dimer sliding on a periodic substrate

Generalization of a nonlinear friction relation for a dimer sliding on a periodic substrate Eur. Phys. J. B 6, 59 6 (008 DOI: 0.0/epj/e008-009-9 THE EUROPEAN PHYSICAL JOURNAL B Generlizion of nonliner fricion relion for dimer sliding on periodic susre M. Tiwri,,S.Gonçles, nd V.M. Kenkre Consorium

More information

Mathematical Modeling

Mathematical Modeling ME pplie Engineering nlsis Chper Mhemicl Moeling Professor Ti-Rn Hsu, Ph.D. Deprmen of Mechnicl n erospce Engineering Sn Jose Se Universi Sn Jose, Cliforni, US Jnur Chper Lerning Ojecives Mhemicl moeling

More information

More on Magnetically C Coupled Coils and Ideal Transformers

More on Magnetically C Coupled Coils and Ideal Transformers Appenix ore on gneiclly C Couple Coils Iel Trnsformers C. Equivlen Circuis for gneiclly Couple Coils A imes, i is convenien o moel mgneiclly couple coils wih n equivlen circui h oes no involve mgneic coupling.

More information

Laplace Examples, Inverse, Rational Form

Laplace Examples, Inverse, Rational Form Lecure 3 Ouline: Lplce Exple, Invere, Rionl For Announceen: Rein: 6: Lplce Trnfor pp. 3-33, 55.5-56.5, 7 HW 8 poe, ue nex We. Free -y exenion OcenOne Roo Tour will e fer cl y 7 (:3-:) Lunch provie ferwr.

More information

Physics 101 Lecture 4 Motion in 2D and 3D

Physics 101 Lecture 4 Motion in 2D and 3D Phsics 11 Lecure 4 Moion in D nd 3D Dr. Ali ÖVGÜN EMU Phsics Deprmen www.ogun.com Vecor nd is componens The componens re he legs of he righ ringle whose hpoenuse is A A A A A n ( θ ) A Acos( θ) A A A nd

More information

Faraday s Law. To be able to find. motional emf transformer and motional emf. Motional emf

Faraday s Law. To be able to find. motional emf transformer and motional emf. Motional emf Objecie F s w Tnsfome Moionl To be ble o fin nsfome. moionl nsfome n moionl. 331 1 331 Mwell s quion: ic Fiel D: Guss lw :KV : Guss lw H: Ampee s w Poin Fom Inegl Fom D D Q sufce loop H sufce H I enclose

More information

f t f a f x dx By Lin McMullin f x dx= f b f a. 2

f t f a f x dx By Lin McMullin f x dx= f b f a. 2 Accumulion: Thoughs On () By Lin McMullin f f f d = + The gols of he AP* Clculus progrm include he semen, Sudens should undersnd he definie inegrl s he ne ccumulion of chnge. 1 The Topicl Ouline includes

More information

Transient State Analysis of a damped & forced oscillator

Transient State Analysis of a damped & forced oscillator 1 DSRC Transien Sae Analysis of a daped & forced oscillaor P.K.Shara 1* 1. M-56, Fla No-3, Madhusudan Nagar, Jagannah coplex, Uni-4, Odisha, India. Asrac: This paper deals wih he ehaviour of an oscillaor

More information

Released Assessment Questions, 2017 QUESTIONS

Released Assessment Questions, 2017 QUESTIONS Relese Assessmen Quesions, 17 QUESTIONS Gre 9 Assessmen of Mhemis Aemi Re he insruions elow. Along wih his ookle, mke sure ou hve he Answer Bookle n he Formul Shee. You m use n spe in his ook for rough

More information

FM Applications of Integration 1.Centroid of Area

FM Applications of Integration 1.Centroid of Area FM Applicions of Inegrion.Cenroid of Are The cenroid of ody is is geomeric cenre. For n ojec mde of uniform meril, he cenroid coincides wih he poin which he ody cn e suppored in perfecly lnced se ie, is

More information

Electric Potential. Electric Potential Video: Section 1 4. Electric Fields and WORK 9/3/2014. IB Physics SL (Year Two) Wednesday, September 3, 2014

Electric Potential. Electric Potential Video: Section 1 4. Electric Fields and WORK 9/3/2014. IB Physics SL (Year Two) Wednesday, September 3, 2014 9/3/014 lectric Potentil IB Physics SL (Yer Two) Wenesy, Septemer 3, 014 lectric Potentil Vieo: Section 1 4 lectric Fiels n WORK In orer to rin two like chres ner ech other work must e one. In orer to

More information

Introduction to Numerical Analysis. In this lesson you will be taken through a pair of techniques that will be used to solve the equations of.

Introduction to Numerical Analysis. In this lesson you will be taken through a pair of techniques that will be used to solve the equations of. Inroducion o Nuerical Analysis oion In his lesson you will be aen hrough a pair of echniques ha will be used o solve he equaions of and v dx d a F d for siuaions in which F is well nown, and he iniial

More information

φ p ( B) AR polynomial of B of order p, p Non-seasonal differencing operator = 1 B

φ p ( B) AR polynomial of B of order p, p Non-seasonal differencing operator = 1 B ARIMA Noion The ARIMA roceure coues he reer esies for given sesonl or non-sesonl univrie ARIMA oel. I lso coues he fie vlues, forecsing vlues, n oher rele vribles for he oel. The following noion is use

More information

SHM SHM. T is the period or time it takes to complete 1 cycle. T = = 2π. f is the frequency or the number of cycles completed per unit time.

SHM SHM. T is the period or time it takes to complete 1 cycle. T = = 2π. f is the frequency or the number of cycles completed per unit time. SHM A ω = k d x x = Acos ( ω +) dx v = = ω Asin( ω + ) vax = ± ωa dv a = = ω Acos + k + x Apliude ( ω ) = 0 a ax = ± ω A SHM x = Acos is he period or ie i akes o coplee cycle. ω = π ( ω +) π = = π ω k

More information

LECTURE 5. is defined by the position vectors r, 1. and. The displacement vector (from P 1 to P 2 ) is defined through r and 1.

LECTURE 5. is defined by the position vectors r, 1. and. The displacement vector (from P 1 to P 2 ) is defined through r and 1. LECTURE 5 ] DESCRIPTION OF PARTICLE MOTION IN SPACE -The displcemen, veloci nd cceleion in -D moion evel hei veco nue (diecion) houh he cuion h one mus p o hei sin. Thei full veco menin ppes when he picle

More information

Lecture 3: 1-D Kinematics. This Week s Announcements: Class Webpage: visit regularly

Lecture 3: 1-D Kinematics. This Week s Announcements: Class Webpage:   visit regularly Lecure 3: 1-D Kinemics This Week s Announcemens: Clss Webpge: hp://kesrel.nm.edu/~dmeier/phys121/phys121.hml isi regulrly Our TA is Lorrine Bowmn Week 2 Reding: Chper 2 - Gincoli Week 2 Assignmens: Due:

More information

Derivation of the differential equation of motion

Derivation of the differential equation of motion Divion of h iffnil quion of oion Fis h noions fin h will us fo h ivion of h iffnil quion of oion. Rollo is hough o -insionl isk. xnl ius of h ll isnc cn of ll (O) - IDU s cn of gviy (M) θ ngl of inclinion

More information

RESPONSE UNDER A GENERAL PERIODIC FORCE. When the external force F(t) is periodic with periodτ = 2π

RESPONSE UNDER A GENERAL PERIODIC FORCE. When the external force F(t) is periodic with periodτ = 2π RESPONSE UNDER A GENERAL PERIODIC FORCE When he exernl force F() is periodic wih periodτ / ω,i cn be expnded in Fourier series F( ) o α ω α b ω () where τ F( ) ω d, τ,,,... () nd b τ F( ) ω d, τ,,... (3)

More information

Version 001 test-1 swinney (57010) 1. is constant at m/s.

Version 001 test-1 swinney (57010) 1. is constant at m/s. Version 001 es-1 swinne (57010) 1 This prin-ou should hve 20 quesions. Muliple-choice quesions m coninue on he nex column or pge find ll choices before nswering. CubeUniVec1x76 001 10.0 poins Acubeis1.4fee

More information

(3.2.3) r x x x y y y. 2. Average Velocity and Instantaneous Velocity 2 1, (3.2.2)

(3.2.3) r x x x y y y. 2. Average Velocity and Instantaneous Velocity 2 1, (3.2.2) Lecture 3- Kinemtics in Two Dimensions Durin our preious discussions we he been tlkin bout objects moin lon the striht line. In relity, howeer, it rrely hppens when somethin moes lon the striht pth. For

More information

When e = 0 we obtain the case of a circle.

When e = 0 we obtain the case of a circle. 3.4 Conic sections Circles belong to specil clss of cures clle conic sections. Other such cures re the ellipse, prbol, n hyperbol. We will briefly escribe the stnr conics. These re chosen to he simple

More information

( ) ( ) ( ) ( u) ( u) = are shown in Figure =, it is reasonable to speculate that. = cos u ) and the inside function ( ( t) du

( ) ( ) ( ) ( u) ( u) = are shown in Figure =, it is reasonable to speculate that. = cos u ) and the inside function ( ( t) du Porlan Communiy College MTH 51 Lab Manual The Chain Rule Aciviy 38 The funcions f ( = sin ( an k( sin( 3 38.1. Since f ( cos( k ( = cos( 3. Bu his woul imply ha k ( f ( = are shown in Figure =, i is reasonable

More information

Exam #2 PHYSICS 211 Monday July 6 th, 2009 Please write down your name also on the back page of this exam

Exam #2 PHYSICS 211 Monday July 6 th, 2009 Please write down your name also on the back page of this exam Exa #2 PHYSICS 211 Monday July 6 h, 29 NME Please wrie down your nae also on he back pae of his exa 1. The fiure ives how he force varies as a funcion of he posiion. Such force is acin on a paricle, which

More information

5.1-The Initial-Value Problems For Ordinary Differential Equations

5.1-The Initial-Value Problems For Ordinary Differential Equations 5.-The Iniil-Vlue Problems For Ordinry Differenil Equions Consider solving iniil-vlue problems for ordinry differenil equions: (*) y f, y, b, y. If we know he generl soluion y of he ordinry differenil

More information

Introduction to Mechanical Vibrations and Structural Dynamics

Introduction to Mechanical Vibrations and Structural Dynamics Inroducion o Mechanical Viraions and Srucural Dynaics The one seeser schedule :. Viraion - classificaion. ree undaped single DO iraion, equaion of oion, soluion, inegraional consans, iniial condiions..

More information

Motion on a Curve and Curvature

Motion on a Curve and Curvature Moion on Cue nd Cuue his uni is bsed on Secions 9. & 9.3, Chpe 9. All ssigned edings nd execises e fom he exbook Objecies: Mke cein h you cn define, nd use in conex, he ems, conceps nd fomuls lised below:

More information

X Fx = F A. If applied force is small, book does not move (static), a x =0, then f=f s

X Fx = F A. If applied force is small, book does not move (static), a x =0, then f=f s A Appl ewton s nd Lw X 0 X A I pplied orce is sll, boo does not ove sttic, 0, then s A Increse pplied orce, boo still does not ove Increse A ore, now boo oves, 0 > A A here is soe iu sttic rictionl orce,

More information

CHAPTER 11 PARAMETRIC EQUATIONS AND POLAR COORDINATES

CHAPTER 11 PARAMETRIC EQUATIONS AND POLAR COORDINATES CHAPTER PARAMETRIC EQUATIONS AND POLAR COORDINATES. PARAMETRIZATIONS OF PLANE CURVES., 9, _ _ Ê.,, Ê or, Ÿ. 5, 7, _ _.,, Ÿ Ÿ Ê Ê 5 Ê ( 5) Ê ˆ Ê 6 Ê ( 5) 7 Ê Ê, Ÿ Ÿ $ 5. cos, sin, Ÿ Ÿ 6. cos ( ), sin (

More information

The solution is often represented as a vector: 2xI + 4X2 + 2X3 + 4X4 + 2X5 = 4 2xI + 4X2 + 3X3 + 3X4 + 3X5 = 4. 3xI + 6X2 + 6X3 + 3X4 + 6X5 = 6.

The solution is often represented as a vector: 2xI + 4X2 + 2X3 + 4X4 + 2X5 = 4 2xI + 4X2 + 3X3 + 3X4 + 3X5 = 4. 3xI + 6X2 + 6X3 + 3X4 + 6X5 = 6. [~ o o :- o o ill] i 1. Mrices, Vecors, nd Guss-Jordn Eliminion 1 x y = = - z= The soluion is ofen represened s vecor: n his exmple, he process of eliminion works very smoohly. We cn elimine ll enries

More information

Physics 2A HW #3 Solutions

Physics 2A HW #3 Solutions Chper 3 Focus on Conceps: 3, 4, 6, 9 Problems: 9, 9, 3, 41, 66, 7, 75, 77 Phsics A HW #3 Soluions Focus On Conceps 3-3 (c) The ccelerion due o grvi is he sme for boh blls, despie he fc h he hve differen

More information

when t = 2 s. Sketch the path for the first 2 seconds of motion and show the velocity and acceleration vectors for t = 2 s.(2/63)

when t = 2 s. Sketch the path for the first 2 seconds of motion and show the velocity and acceleration vectors for t = 2 s.(2/63) . The -coordine of pricle in curiliner oion i gien b where i in eer nd i in econd. The -coponen of ccelerion in eer per econd ured i gien b =. If he pricle h -coponen = nd when = find he gniude of he eloci

More information

Sph3u Practice Unit Test: Kinematics (Solutions) LoRusso

Sph3u Practice Unit Test: Kinematics (Solutions) LoRusso Sph3u Prcice Uni Te: Kinemic (Soluion) LoRuo Nme: Tuey, Ocober 3, 07 Ku: /45 pp: /0 T&I: / Com: Thi i copy of uni e from 008. Thi will be imilr o he uni e you will be wriing nex Mony. you cn ee here re

More information

Contraction Mapping Principle Approach to Differential Equations

Contraction Mapping Principle Approach to Differential Equations epl Journl of Science echnology 0 (009) 49-53 Conrcion pping Principle pproch o Differenil Equions Bishnu P. Dhungn Deprmen of hemics, hendr Rn Cmpus ribhuvn Universiy, Khmu epl bsrc Using n eension of

More information

Axis. Axis. Axis. Solid cylinder (or disk) about. Hoop about. Annular cylinder (or ring) about central axis. central axis.

Axis. Axis. Axis. Solid cylinder (or disk) about. Hoop about. Annular cylinder (or ring) about central axis. central axis. Insucos: Fiel/che/Deweile PYSICS DEPATENT PY 48 Em ch 5, 5 Nme pin, ls fis: Signue: On m hono, I he neihe gien no eceie unuhoie i on his eminion. YOU TEST NUBE IS TE 5-DIGIT NUBE AT TE TOP OF EAC PAGE.

More information

The Natural Logarithm

The Natural Logarithm The Naural Logarihm 5-4-007 The Power Rule says n = n + n+ + C provie ha n. The formula oes no apply o. An anierivaive F( of woul have o saisfy F( =. Bu he Funamenal Theorem implies ha if > 0, hen Thus,

More information

Lecture 23 Damped Motion

Lecture 23 Damped Motion Differenial Equaions (MTH40) Lecure Daped Moion In he previous lecure, we discussed he free haronic oion ha assues no rearding forces acing on he oving ass. However No rearding forces acing on he oving

More information

Introduction. Voice Coil Motors. Introduction - Voice Coil Velocimeter Electromechanical Systems. F = Bli

Introduction. Voice Coil Motors. Introduction - Voice Coil Velocimeter Electromechanical Systems. F = Bli UNIVERSITY O TECHNOLOGY, SYDNEY ACULTY O ENGINEERING 4853 Elecroechncl Syses Voce Col Moors Topcs o cover:.. Mnec Crcus 3. EM n Voce Col 4. orce n Torque 5. Mhecl Moel 6. Perornce Voce cols re wely use

More information

Name: Per: L o s A l t o s H i g h S c h o o l. Physics Unit 1 Workbook. 1D Kinematics. Mr. Randall Room 705

Name: Per: L o s A l t o s H i g h S c h o o l. Physics Unit 1 Workbook. 1D Kinematics. Mr. Randall Room 705 Nme: Per: L o s A l o s H i g h S c h o o l Physics Uni 1 Workbook 1D Kinemics Mr. Rndll Room 705 Adm.Rndll@ml.ne www.laphysics.com Uni 1 - Objecies Te: Physics 6 h Ediion Cunel & Johnson The objecies

More information

PHYS 601 HW3 Solution

PHYS 601 HW3 Solution 3.1 Norl force using Lgrnge ultiplier Using the center of the hoop s origin, we will describe the position of the prticle with conventionl polr coordintes. The Lgrngin is therefore L = 1 2 ṙ2 + 1 2 r2

More information

Properties of Logarithms. Solving Exponential and Logarithmic Equations. Properties of Logarithms. Properties of Logarithms. ( x)

Properties of Logarithms. Solving Exponential and Logarithmic Equations. Properties of Logarithms. Properties of Logarithms. ( x) Properies of Logrihms Solving Eponenil nd Logrihmic Equions Properies of Logrihms Produc Rule ( ) log mn = log m + log n ( ) log = log + log Properies of Logrihms Quoien Rule log m = logm logn n log7 =

More information

Section 14 Forces in Circular Motion

Section 14 Forces in Circular Motion Secion 14 orces in Circular Moion Ouline 1 Unifor Circular Moion Non-unifor Circular Moion Phsics 04A Class Noes Wh do objecs do wha he do? The answer we have been invesigaing is forces If forces can eplain

More information

Introduction to LoggerPro

Introduction to LoggerPro Inroducion o LoggerPro Sr/Sop collecion Define zero Se d collecion prmeers Auoscle D Browser Open file Sensor seup window To sr d collecion, click he green Collec buon on he ool br. There is dely of second

More information

CHAPTER 2 KINEMATICS IN ONE DIMENSION ANSWERS TO FOCUS ON CONCEPTS QUESTIONS

CHAPTER 2 KINEMATICS IN ONE DIMENSION ANSWERS TO FOCUS ON CONCEPTS QUESTIONS Physics h Ediion Cunell Johnson Young Sdler Soluions Mnul Soluions Mnul, Answer keys, Insrucor's Resource Mnul for ll chpers re included. Compleed downlod links: hps://esbnkre.com/downlod/physics-h-ediion-soluions-mnulcunell-johnson-young-sdler/

More information

Chapter 3: Motion in One Dimension

Chapter 3: Motion in One Dimension Lecure : Moion in One Dimension Chper : Moion in One Dimension In his lesson we will iscuss moion in one imension. The oles one o he Phsics subjecs is he Mechnics h inesiges he moion o bo. I els no onl

More information

PHYSICS 211 MIDTERM I 21 April 2004

PHYSICS 211 MIDTERM I 21 April 2004 PHYSICS MIDERM I April 004 Exm is closed book, closed notes. Use only your formul sheet. Write ll work nd nswers in exm booklets. he bcks of pges will not be grded unless you so request on the front of

More information

A 1.3 m 2.5 m 2.8 m. x = m m = 8400 m. y = 4900 m 3200 m = 1700 m

A 1.3 m 2.5 m 2.8 m. x = m m = 8400 m. y = 4900 m 3200 m = 1700 m PHYS : Soluions o Chper 3 Home Work. SSM REASONING The displcemen is ecor drwn from he iniil posiion o he finl posiion. The mgniude of he displcemen is he shores disnce beween he posiions. Noe h i is onl

More information

What distance must an airliner travel down a runway before reaching

What distance must an airliner travel down a runway before reaching 2 LEARNING GALS By sudying his chper, you will lern: How o describe srigh-line moion in erms of erge elociy, insnneous elociy, erge ccelerion, nd insnneous ccelerion. How o inerpre grphs of posiion ersus

More information

SPH4U. Conservation of Energy. Review: Springs. More Spring Review. 1-D Variable Force Example: Spring. Page 1. For a spring we recall that F x = -kx.

SPH4U. Conservation of Energy. Review: Springs. More Spring Review. 1-D Variable Force Example: Spring. Page 1. For a spring we recall that F x = -kx. -D Variable Force Exaple: Spring SPH4U Conseration of Energ For a spring we recall that F x = -kx. F(x) x x x relaxe position -kx F = - k x the ass F = - k x Reiew: Springs Hooke s Law: The force exerte

More information

Math 211A Homework. Edward Burkard. = tan (2x + z)

Math 211A Homework. Edward Burkard. = tan (2x + z) Mth A Homework Ewr Burkr Eercises 5-C Eercise 8 Show tht the utonomous system: 5 Plne Autonomous Systems = e sin 3y + sin cos + e z, y = sin ( + 3y, z = tn ( + z hs n unstble criticl point t = y = z =

More information

An Introduction to Trigonometry

An Introduction to Trigonometry n Introduction to Trigonoetry First of ll, let s check out the right ngled tringle below. The LETTERS, B & C indicte the ngles nd the letters, b & c indicte the sides. c b It is iportnt to note tht side

More information

Characteristic Function for the Truncated Triangular Distribution., Myron Katzoff and Rahul A. Parsa

Characteristic Function for the Truncated Triangular Distribution., Myron Katzoff and Rahul A. Parsa Secion on Survey Reserch Mehos JSM 009 Chrcerisic Funcion for he Trunce Tringulr Disriuion Jy J. Kim 1 1, Myron Kzoff n Rhul A. Prs 1 Nionl Cener for Helh Sisics, 11Toleo Ro, Hysville, MD. 078 College

More information

3.4 Conic sections. In polar coordinates (r, θ) conics are parameterized as. Next we consider the objects resulting from

3.4 Conic sections. In polar coordinates (r, θ) conics are parameterized as. Next we consider the objects resulting from 3.4 Conic sections Net we consier the objects resulting from + by + cy + + ey + f 0. Such type of cures re clle conics, becuse they rise from ifferent slices through cone In polr coorintes r, θ) conics

More information