# Study Guide for Math 095

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1 Study Guide for Math 095 David G. Radcliffe November 7, The Real Number System Writing a fraction in lowest terms. 1. Find the largest number that will divide into both the numerator and the denominator. This number is called the greatest common factor (GCF). 2. Divide both the numerator and the denominator by the GCF = = 2 3 Multiplying fractions. a b c d = a c b d = = 8 15 Dividing fractions. To divide two fractions, invert the second fraction and multiply = = = = =

2 2 1 THE REAL NUMBER SYSTEM Adding fractions with the same denominators. a b + c b = a + c b = 6 7. Adding fractions with different denominators. a b + c d = a d + b c b d = = = Subtracting fractions with the same denominators. a b c b = a c b = Subtracting fractions with different denominators. a b c d = a d b c b d = = 15 8 = Order of operations. If parentheses or fraction bars are present, simplify within parentheses, innermost first, and above and below fraction bars separately, in the following order. 1. Apply all exponents. 2. Do any multiplications or divisions in the order in which they occur, working from left to right. 3. Do any additions or subtractions in the order in which they occur, working from left to right. If no parentheses or fraction bars are present, start with Step 1. Example: 7 2 ( ) 2 = = = = 36.

4 4 2 SOLVING EQUATIONS AND INEQUALITIES Multiplicative inverses. A pair of numbers are multiplicative inverses (or reciprocals) of each other if their product is 1. The reciprocal of x is 1 x, and the reciprocal of a b is b a. Axioms of addition and multiplication. Addition Multiplication Commutative x + y = y + x xy = yx Associative (x + y) + z = x + (y + z) (xy)z = x(yz) Identity x + 0 = x x 1 = x Inverse x + ( x) = 0 x 1 x = 1 (x 0) Distributive x(y + z) = xy + xz 2 Solving Equations and Inequalities Addition property of equality. The same quantity may be added to (or subtracted from) both sides of an equation. For example, 2x 4 = 3 and 2x = have the same solution. Multiplication property of equality. Both sides of an equation may be multiplied or divided by the same nonzero number. Solving a linear equation. 1. Multiply both sides by the least common denominator (LCD) in order to remove fractions. 2. Use the distributive law to remove all parentheses. 3. Move the variable terms (such as 2x) to one side of the equation, and constant terms (such as 6) to the other side, by using the Addition Property of Equality. 4. Combine like terms on each side of the equation. 5. Divide both sides by the coefficient of the variable. 6. Check the solution by substituting into the original equation.

5 5 Example: (1/2)x + 3(2x 1) = 14 2x x + 6(2x 1) = 28 4x (1) x + 12x 6 = 28 4x (2) x + 12x + 4x = (3) 17x = 34 (4) x = 34/17 = 2 (5) Check: (1/2) 2 + 3(2 2 1) = (6) 1 + 3(3) = = 10 Solving word problems. 1. Read the problem carefully. Determine which information is given to you in the problem, and which information you are asked to find. 2. Choose a variable to represent the unknown quantity. State explicitly what the variable represents (e.g. Let x = number of dimes). 3. Translate the problem into an equation. Drawing a picture is often helpful. 4. Solve the equation. 5. Answer the question asked in the problem! 6. Check your solution by using the original words of the problem. Translating key words and phrases. Algebraic Key words and phrases Verbal description Statement Equality Equals, equals to, is, are, The sales price S is \$10 S = L 10 was, will be, represents less than the list price L. Addition Sum, plus, greater than, The sum of 5 and x 5 + x increased by, more than, Seven more than y y + 7 exceeds, total of x exceeds y by 2 x = y + 2

6 6 2 SOLVING EQUATIONS AND INEQUALITIES Subtraction Difference, subtracted from The difference of 4 and b 4 b less, minus, decreased by, Three less than z z 3 reduced by, the remainder The width reduced by 1 w 1 Multiplication Product, multiplied by, Two times x 2x twice, times, percent of Five percent of x.05x Division x Quotient, divided by, The quotient of x and 8 8 ratio, per The ratio of x to y x/y Ratio and proportion. A ratio is a quotient of two quantities. They are often expressed using the word per. (Miles per gallon, ten percent, etc.) Ratios may be expressed in many ways, including: a to b, a : b, a/b, and a b. A proportion is a statement that two ratios are equal. a Cross multiplication. b = c if and only if ad = bc. For example, to d solve 6 x = 4, we could cross multiply to obtain 6 3 = x 4. 3 Addition property of inequality. The same quantity may be added to (or subtracted from) both sides of an inequality. For example, the inequalities x < y and x + 3 < y + 3 are equivalent. Multiplication property of inequality. Both sides of an inequality may be multiplied or divided by a positive number. When you multiply or divide by a negative number, the direction of the inequality is reversed. For example, 2x < 8 is equivalent to x < 4, but 2x < 8 is equivalent to x > 4. In the second case, the < switches to a > because we are dividing by 2. Solving an inequality. You solve an inequality in exactly the same way that you solve an equation, with only two exceptions:

7 7 1. If you multiply or divide both sides by a negative number, you must reverse the inequality. 2. If you exchange the sides of an inequality, you must reverse the inequality (for example, 2 x becomes x 2). Note that adding and subtracting will never reverse the direction of an inequality. Example: Solve 2 3x 10 + x Solution: 2 3x 10 + x 3x x x 8 x 2 3 Polynomials and Exponents Adding polynomials. To add two polynomials, add like terms. Subtracting polynomials. To subtract two polynomials, change all the signs on the second polynomial and add the two polynomials. (x 2 4x) (3x 2 9x) = (x 2 4x) + ( 3x 2 + 9x) = (1 3)x 2 + ( 4 + 9)x = 2x 2 + 5x Negative base of exponents. { ( a) n a n if n is even, = a n if n is odd.

8 8 3 POLYNOMIALS AND EXPONENTS Rules of exponents. Product rule a m a n = a m+n Zero exponent a 0 = 1 Negative exponent a n = 1 ( a ) ( n b a n, = b a a m Quotient rule a n = am n Power of a product (ab) n = a n b n ( a ) n a n Power of a quotient = b Power to a power b n (a m ) n = a mn ) n Multiplying polynomials. Multiply each term of the second polynomial by every term of the first polynomial, and add the products. When each polynomial has only two terms, this reduces to the FOIL method. FOIL is an abbreviation for first, outer, inner, last. (2x + 3)(4x + y) = 2x(4x) + 2x(y) + 3(4x) + 3(y) = 8x 2 + 2xy + 12x + 3y Square of a binomial. (x + y) 2 = x 2 + 2xy + y 2 (x y) 2 = x 2 2xy + y 2 Do not forget the middle term! In general, (x + y) 2 x 2 + y 2. Changing from negative to positive exponents. A factor may be moved from the numerator to the denominator, or from the denominator to the numerator, by changing the sign of the exponent. a m b n = bn a m, 3 3 x 6 4y 9 = x6 y Dividing a monomial by a monomial. First divide the numerical coefficients, then divide each variable using the quotient rule. 12x 8 y 6 ( ) ( ) ( ) 12 x 8 y 6 3x 7 y = 3 x 7 = 4x 8 7 y 6 1 = 4xy 5 y

9 9 Dividing a polynomial by a monomial. To divide a polynomial by a monomial, divide each term of the polynomial by the monomial. Example: 16a 5 12a 4 + 8a 2 4a 3 = 16a5 4a 3 12a4 4a 3 + 8a2 4a 3 = 4a 2 3a + 2 a Long division. Long division should be used when the divisor has more than one term. The first step is to arrange the term in order of descending powers. Use a coefficient of zero for any missing terms. Example: Divide 4x x by 2x + 3. Solution: 2x 2 3x x + 3 2x 2 3x + 2 2x + 3 ) 4x 3 5x + 1 4x 3 6x 2 6x 2 5x 6x 2 + 9x 4x + 1 4x 6 5 4x 3 /2x = 2x 2 2x 2 (2x + 3) = 4x 3 + 6x 2 6x 2 /2x = 3x 3x(2x + 3) = 6x 2 9x 4x/2x = 2 2(2x + 3) = 4x + 6 Note that we change signs before adding.

10 10 4 FACTORING AND APPLICATIONS 4 Factoring and Applications Factoring polynomials 1. Remove common factors. (a) 6x 3 4x = 2x(3x 2 ) 2x(2) = 2x(3x 2 2) (b) (4x 5)(2x) + (4x 5)(y) = (4x 5)(2x + y) (c) 10x 2 y 3 12x 3 z 2 = (2x 2 )(5y 3 ) (2x 2 )(6xz 2 ) = (2x 2 )(5y 3 6xz 2 ) 2. Check for special factorizations. Difference of two squares x 2 y 2 = (x y)(x + y) Difference of two cubes x 3 y 3 = (x y)(x 2 + xy + y 2 ) Sum of two cubes x 3 + y 3 = (x + y)(x 2 xy + y 2 ) 3. If there is a trinomial of degree two, use trial and error. (a) To factor x 2 + Ax + B, find two numbers whose sum is A and whose product is B. i. x 2 + 9x + 18 = (x + 6)(x + 3) ii. x 2 3x 40 = (x + 5)(x 8) (b) Factoring a trinomial of the form Ax 2 + Bx + C: 5x x 6 = (5x 2)(x + 3) Product of the two firsts = First term of trinomial Product of the two lasts = Last term of trinomial Sum of inner and outer products = Middle term of trinomial 4. If there are four terms, try to factor by grouping.

11 11 Step 1 Write the four terms so that the first two terms have a common factor and the last two terms have a common factor. Step 2 Factor each group of two terms. Step 3 Factor a common binomial factor from the results of Step 2. Example: Factor 6x 2 + 4xy 9x 6y Solution: 6x 2 + 4xy 9x 6y = (6x 2 + 4xy) (9x + 6y) = 2x(3x + 2y) 3(3x + 2y) = (2x 3)(3x + 2y) Zero factor property. If the product of two or more numbers is zero, then one of the factors must be equal to zero. In symbols, if ab = 0, then either a = 0 or b = 0. Solving quadratic equations by factoring. 1. Move all terms to one side of the equals sign, leaving 0 on the other side. 2. Factor completely. 3. Set each factor to 0, and solve the resulting equations. Example: Solve 2x = 9x Solution: 2x 2 9x + 4 = 0 (2x 1)(x 4) = 0 2x 1 = 0 or x 4 = 0 x = 1/2, 4 Pythagorean theorem. If a triangle has longest side of length c and two other sides of lengths a and b, then c 2 = a 2 + b 2

12 12 5 RATIONAL EXPRESSIONS 5 Rational Expressions A rational expression is the quotient of two polynomials P Q. If Q = 0 then P is undefined. To determine when a rational expression is undefined, set the denominator equal to zero and Q solve. Reducing to lowest terms. To write a rational expression in lowest terms, (1) factor the numerator and denominator, and (2) cancel common factors from the numerator and denominator. x 2 5x + 6 x 2 4 = (x 2)(x 3) (x 2)(x + 2) = x 3 x + 2 Multiplication of rational expressions. 1. Factor completely. 2. Multiply numerators and multiply denominators. 3. Write in lowest terms. To divide two fractions, invert the second fraction and multiply. Finding the least common denominator. 1. Completely factor all denominators. 2. Take each different factor the greatest number of times that it appears as a factor in any of the denominators. 3. The least common denominator is the product of all factors to the greatest power found in step 2. Adding fractions with different denominators. 1. Find the least common denominator (LCD). 2. Rewrite each rational expression as a fraction with the LCD as the denominator.

13 13 3. Add the numerators to get the numerator of the sum. The least common denominator is the denominator of the sum. 4. Reduce, if possible. Simplifying complex fractions. Find the least common denominator of all fractions appearing in the complex fraction. Multiply the numerator and denominator by this LCD = = = Solving equations with rational expressions. 1. Find the least common denominator. 2. Multiply both sides by the LCD in order to clear fractions. 3. Solve the resulting equation. 4. Reject any solutions which make a denominator equal to 0. These solutions are called extraneous. Example: Solve 1 x + 2 x + 2 = 4x 9 x 2 + 2x Solution: 1 x + 2 x + 2 = 4x 9 x(x + 2) 1 2 4x 9 x(x + 2) + x(x + 2) = x(x + 2) x x + 2 x(x + 2) (x + 2) + 2x = 4x 9 3x + 2 = 4x 9 3x 4x = 2 9 x = 11 x = 11

14 14 6 GRAPHING LINEAR EQUATIONS 6 Graphing Linear Equations Finding intercepts of a line. To find the x-intercept of a line, set y = 0 in the given equation and solve for x. To find the y-intercept of a line, set x = 0 in the given equation and solve for y. Horizontal and vertical lines. The equation of a horizontal line is of the form y = k, and the equation of a vertical line is of the form x = k. The slope of a horizontal line is zero, and the slope of a vertical line is undefined. Slope of a line. slope = difference in y-values difference in x-values = y 2 y 1 x 2 x 1 For example, the slope of the line through (1, 5) and (4, 2) is (2 5) (4 1) = 1. To find the slope of a line from its equation, solve for y. The slope is the coefficient of x. Slope intercept form. When the equation of a line is in the form y = mx + b, the slope of the line is m and the y intercept is (0, b). For example, the line y = 3x 7 has a slope of 3 and a y-intercept of (0, 7). Point slope form. An equation of the line with slope m going through (x 1, y 1 ) is y y 1 = m(x x 1 ) Example: Find the equation of the line through (2, 3) with slope 1 2. Solution: y ( 3) = 1 (x 2) 2 Equation of line through two points. To find the equation of a line through two given points, find the slope using the formula m = (y y 1 )/(x x 1 ). Substitute the slope and the coordinates of either of the two points into the point slope formula. Example: Find the equation of the line through (1, 3) and (4, 9). slope = = 2

15 15 y y 1 = m(x x 1 ) m = 2, x 1 = 1, y 1 = 3 y 3 = 2(x 1) y 3 = 2x 2 y = 2x + 1 Parallel and perpendicular lines. Two lines with the same slope are parallel. Two lines that have slopes with a product of 1 are perpendicular. 7 Linear Systems Solving systems by graphing. One way to find the solution of a system of two linear equations is to graph the equations on the same axes. The coordinates of the point where the lines intersect give the solution. Example: The lines x + y = 8 and x y = 2 intersect at (5, 3), so the solution to this system of equations is x = 5, y = 3. Inconsistent and dependent equations. A system of equations is inconsistent if it has no solution. A system of equations with infinitely many solutions is called dependent. Solving systems by addition. Step 1 Write both equations in the form Ax + By = C. Step 2 Multiply one or both equations by appropriate numbers so that the coefficients of x (or y) are negatives of each other. Step 3 Add the equations to get an equation with only one variable. Step 4 Solve the equation from Step 3. Step 5 Substitute the solution from Step 4 into either of the original equations to find the value of the remaining variable. Step 6 Write the solution as an ordered pair and check the answer.

16 16 8 ROOTS AND RADICALS Solving systems by substitution. Step 1 Solve one of the equations for either variable. Step 2 Substitute for that variable in the other equation. The result should be an equation with just one variable. Step 3 Solve the equation from Step 2. Step 4 Substitute the result from Step 3 into the equation from Step 1 to find the value of the other variable. Step 5 Check the solution in both of the given equations. Solving word problems with two variables. Step 1 Choose a different variable for each of the two unknown values you are asked to find. Write down what each variable is to represent. Step 2 Translate the problem into two equations using both variables. Step 3 Solve the system of two equations. Step 4 Answer the question or questions asked in the problem. Step 5 Check your solution by using the original words of the problem. 8 Roots and Radicals Square roots. A square root of a number is one of its two equal factors. For example, 5 is a square root of 25 because 5 5 = 25. Every positive number has two square roots; one is positive, the other negative. The symbol x denotes the non-negative square root only. When we speak of the square root of a number, we mean the nonnegative square root. Thus, the square root of 4 is 2, not 2. Definition of nth root. Let a and b be real numbers and let n 2 be a positive integer. If a = b n then b is an nth root of a. If n = 2, then the root is a square root. If n = 3, then the root is a cube root. Existence of nth roots. positive integer. Let a be a real number, and let n 2 be a

19 19 x = b ± b 2 4ac ; a = 2, b = 5, c = 1 2a x = ( 5) ± ( 5) 2 4(2)(1) 2(2) x = 5 ± = 5 ± 17 4 The imaginary unit. i = 1 and i 2 = 1. Complex numbers. A complex number is a number of the form a+bi, where a and b are real numbers. The real part of the complex number a+bi is a, and the imaginary part is b. Complex numbers allow us to define the square root of any negative number. For example, 64 = 64 1 = 8i. Addition and subtraction of complex numbers. 1. To add complex numbers, add their real parts and add their imaginary parts. 2. To subtract complex numbers, change the number following the subtraction sign to its negative, and then add. Example: (2 6i) + (7 + 4i) = (2 + 7) + ( 6 + 4)i = 9 2i Multiplication of complex numbers. Multiplication of complex numbers is performed in the same way as multiplication of polynomials (i.e. using FOIL), except that i 2 must be replaced with 1. Example: (2 + 3i)(7 4i) = i + 3i 7 3i 4i = 14 8i + 21i 12i 2 = 14 8i + 21i + 12 = i Complex conjugate. The conjugate of a complex number is formed by reversing the sign of its imaginary part. The conjugate of a + bi is a bi, and the conjugate of a bi is a + bi.

20 20 9 QUADRATIC EQUATIONS The product of a complex number and its conjugate is real. In fact, (a + bi)(a bi) = a 2 + b 2. Division of complex numbers. To divide a complex number by a real number, divide the real and the imaginary parts of the complex number by the real number. To divide two complex numbers, multiply both the numerator and the denominator by the conjugate of the denominator. Example: 1 + 2i 2 3i = 1 + 2i 2 3i 2 + 3i 2 + 3i 2 + 3i + 4i + 6i2 = 4 + 6i 6i 9i 2 = 2 + 7i 6 = i 13 = i

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