Direct methods for symmetric eigenvalue problems
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1 Direct methods for symmetric eigenvalue problems, PhD McMaster University School of Computational Engineering and Science February 4, 2008
2 1 Theoretical background Posing the question Perturbation theory 2 Direct and iterative methods Transformation to tridiagonal form Counting the eigenvalues Finding the eigenvectors 3 Bisection with inverse iteration 4
3 Theoretical background Posing the question Perturbation theory Theoretical background (A is real, symmetric) Eigenvalue: Ax = λx A λi is singular n eigenvalues (with multiplicities) Characteristic polynomial: p(λ) = det(a λi) If Q T Q = I then A and Q T AQ have the same eigenvalues If P is nonsingular then A and P T AP have the same inertia Eigendecomposition (Av i = λ i v i ): A = n λ i v i vi T i=1 The v i s should be orthogonal
4 Theoretical background Posing the question Perturbation theory Posing the question Find all the eigenvalues Find some eigenvalues Find largest/smallest eigenvalue(s) Find largest/smallest magnitude eigenvalue(s) Find eigenvalue(s) around a given number Find the corresponding eigenvectors Find the eigenvalues in [α, β] Count the eigenvalues in [α, β]
5 Theoretical background Posing the question Perturbation theory Perturbation theory Eigenvalues are well-conditioned (Weyl) λ i (A) λ i (A + E) E 2 Eigenvectors can be ill-conditioned ε ε ε Problem: distance between eigenvalues Problem: small eigenvalues Shifting: λ(a αi) = λ(a) α
6 Direct and iterative methods Transformation to tridiagonal form Counting the eigenvalues Finding the eigenvectors Direct and iterative methods Eigenvalues are roots of polynomials Every method has to iterate Direct transforms the matrix to a simpler form (tridiagonal) finds all the eigenvalues and eigenvectors (almost) always works converges quickly Iterative only multiplication by A or A T does not access the elements of A only a few eigenvectors/values
7 Direct and iterative methods Transformation to tridiagonal form Counting the eigenvalues Finding the eigenvectors Tridiagonalization (Hessenberg reduction) Householder reflections ( ) I 2uu T = }{{} Q } {{ } A With this Q, due to symmetry: QAQ = Cost 4 3 n3, or 8 3 n3 if Q is needed for the eigenvectors LAPACK: ssytrd, Matlab: hess
8 Direct and iterative methods Transformation to tridiagonal form Counting the eigenvalues Finding the eigenvectors Count the eigenvalues in [α, β) Factorize A αi = L α D α L T α Number of negative eigenvalues in D α gives the number of eigenvalues of A that are smaller than α Factorize A βi = L β D β L T β Number of negative eigenvalues in D β gives the number of eigenvalues of A that are smaller than β The difference gives the number of eigenvalues in [α, β) Cost: two LDL factorizations (can exploit structure)
9 Direct and iterative methods Transformation to tridiagonal form Counting the eigenvalues Finding the eigenvectors Finding the eigenvectors Solve (A λi)v = 0 λ is only approximate extremely ill-conditioned system only if λ is an exact eigenvalue Inverse iteration repeat w i+1 = (A αi) 1 v i v i+1 = w i+1 w i+1 2 fast convergence can be modified to find the eigenvalues, too
10 Bisection with inverse iteration Bisection with inverse iteration 4
11 Bisection with inverse iteration Factor A i = Q i R i, set A i+1 = R i Q i, repeat Shifting: A i α i I = Q i R i, A i+1 = R i Q i + α i I If α i is close to an eigenvalue then convergence is fast (quadratic) Fastest method for eigenvalues Fastest method for eigenvectors if n 25 Total cost: 4 3 n3 + O(n 2 ), cubic! convergence LAPACK: xsteqr, xsterf, Matlab: eig
12 Choosing the shift Bisection with inverse iteration A = a 1 c 1 c 1 a 2 c c n 2 a n 1 c n 1 c n 1 a n Single shift: α = a n Wilkinson shift: ( an 1 c α is the eigenvalue of n 1 c n 1 a n ) closest to a n
13 Bisection with inverse iteration Partition the into two halves Solve the smaller problems recursively Assemble the results Cost: O(n 2.3 ) on average Fastest method for eigenvectors if n 25 Not easy to implement in a stable way Efficiently parallelizable LAPACK: xstevd
14 Bisection with inverse iteration Bisection with inverse iteration Count the eigenvalues in [α, β) Bisect the interval, count the eigenvalues in the subintervals, then repeat LDL T is too expensive in general Transform A to tridiagonal form first Cost: O(nk) for k eigenvalues Excellent parallelization Only linear convergence (due to bisection) Compute eigenvectors with inverse iteration LAPACK: xstebz, xstein
15 Bisection with inverse iteration Transform A to (almost) diagonal form Zero out a jk, j k with Givens rotation ( ) cos θ sin θ T ( ) ( Ajj A jk cos θ sin θ sin θ cos θ A kj A kk sin θ cos θ Costs O(n) flops per rotation How to choose A jk? off(a) := j<k A 2 jk ) ( ) λ1 0 = 0 λ 2 off(a ) 2 = off(a) 2 A 2 jk Always the largest A jk : too expensive Row-wise: cheap but still efficient (5-10 sweeps) In general Jacobi is too slow, but very accurate
16 Transform A to tridiagonal form Only eigenvalues: use QR Eigenvalues and eigenvectors: use D&C Small eigenvalues with high accuracy: use Jacobi Eigenvalues in [α, β): use bisection Most algorithms are available in LAPACK
17 Z. Bai, J. Demmel, J. Dongarra, A. Ruhe, and H. van der Vorst, editors. Templates for the Solution of Algebraic Eigenvalue Problems: A Practical Guide. SIAM, Philadelphia, James W. Demmel. Applied Numerical Linear Algebra. SIAM, Philadelphia, 1997.
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