Where, m = slope of line = constant c = Intercept on y axis = effort required to start the machine

Size: px
Start display at page:

Download "Where, m = slope of line = constant c = Intercept on y axis = effort required to start the machine"

Transcription

1 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Important Instructions to examiners: ) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. ) The model answer and the answer written by candidate may vary but the examiner may try to assess the understanding level of the candidate. 3) The language errors such as grammatical, spelling errors should not be given more importance. (Not applicable for subject English and Communication Skills.) ) While assessing figures, examiner may give credit for principal components indicated in the figure. The figures drawn by the candidate and those in the model answer may vary. The examiner may give credit for any equivalent figure drawn. 5) Credits may be given step wise for numerical problems. In some cases, the assumed constant values may vary and there may be some difference in the candidate s answers and the model answer. 6) In case of some questions credit may be given by judgment on part of examiner of relevant answer based on candidate s understanding. 7) For programming language papers, credit may be given to any other program based on equivalent concept Q. Answer any TEN of the following : 0 a) Explain the term law of machine. The relation between the load lifted (W) and the effort applied (P) is known as the law of machine. This relationship, when plotted on a graph results in a straight line as shown below. The equation of this straight line is P ( mw c) N Where, m = slope of line = constant c = Intercept on y axis = effort required to start the machine b) How will you find whether machine is reversible or not? By calculating the efficiency of machine, we can decide whether the machine is reversible or not. If %ƞ < 50% machine is non-reversible i.e. self-locking machine. If %ƞ > 50% machine is reversible. Page

2 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. c) State VR of Simple axle & wheel. VR of Simple axle & Wheel = D/d Whether, D = Diameter of Effort Wheel d = Diameter of load drum d) Differentiate between statics & dynamics. Statics is the branch of applied mechanics which deals with forces & their action on bodies at rest. Dynamics is the branch of applied mechanics which deals with forces & their action on bodies in motion. e) What is Unit Newton force? Unit Newton force is that force which when acts on a body of mass Kg produces an acceleration of m/sec in it. f) State parallelogram law of forces. Derive the equations for magnitude & direction of resultant force. Parallelogram of forces states, If two forces acting at & away from point be represented in magnitude & direction by the two adjacent sides of parallelogram, then the diagonal of the parallelogram passing through the point of intersection of the two forces, represents the resultant in magnitude & direction. Let s consider two concurrent forces P & Q acting at & away from O as shown in Fig.. Let these two forces be represented in magnitude & direction by two adjacent sides OA & OB of the parallelogram OACB. Thus the line joining O & C represents the resultant R in magnitude & direction, according to law. Draw CD perpendicular to meet OA produced. Draw AC parallel to OB & OB = AC = Q Page

3 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. OA = P & OC = R AD = Q cos Ɵ & CD = Q sin Ɵ In right angled triangle ODC, OC = OD + DC = (OA + AD) + DC = (P+Q cos Ɵ) + (Q sinɵ) = P + Q cos Ɵ + PQ cos Ɵ + Q sin Ɵ = P + Q (cos Ɵ + sin Ɵ) + PQ cos Ɵ R = P + Q + PQ cos Ɵ----- (cos Ɵ + sin Ɵ = ) R P Q PQ cos Magnitude of R ½ Let, Ɵ = Angle between the two forces P & Q. If P, Q & Ɵ are known, the magnitude of R can be found out. Let R make an angle α with the direction of P. In right angle triangle ODC, CD CD Qsin tan OD OA AD P Q cos Qsin P Qcos Direction of R tan ½ g) State Varignon s theorem. Varignon s theorem states, The algebraic sum of moments of all forces about any point is equal to moment of resultant about the same point. Let, MFA = Algebraic sum of moments of all forces about point A MRA = Moment of Resultant about point A Then, MFA = MRA h) What are the limitations of Lami s theorem? ) This theorem is applicable only for three forces. ) This theorem is applicable when forces are concurrent. 3) This theorem is applicable only when body is in equilibrium. ) This theorem is not applicable for non-concurrent force system. M each (any two) Page 3

4 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. i) Differentiate between resultant & equilibrant. Resultant Equilibrant ) Resultant is a single force which can produce the same effect on the body as it is produced by all forces acting ) Equilibrant is a single force which when acts with other forces brings the set of forces & body in equilibrium. together. ) It is donated by R. ) It is denoted by E. 3) It causes displacement of 3) It keeps the body at rest. body. ) The set of forces which causes the displacement of a body are called as components ) The set of forces which keeps the body at rest are called as components of a equilibrant or of a resultant or component equilibrant forces. forces. 5) M each (any two) j) What are the two advantages of friction? ) One can walk easily on rough surface than smooth surface. ) Moving vehicle on road can be stopped suddenly by applying brakes. 3) One can hammer nail into wall. ) One can easily hold pen, pencil & can write on paper. M each (any two) k) Define angle of repose. Angle of repose is defined as the angle made by the inclined plane with the horizontal plane at which the body placed on an inclined plane is just on the point of moving down the plane, under the action of its own weight. Page

5 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. l) What is relation between coefficient of friction & angle of repose? Relation between coefficient of friction & angle of repose is given by tan Where, µ = Coefficient of friction & α = Angle of repose. m) Calculate & show the centroid of circle of 50 mm diameter. d 50 x y 5mm n) Differentiate between centroid & centre of gravity. Centroid :- It is defined as the point through which the entire area of a plane figure is assumed to act, for all positions of the lamina. e. g. Triangle, Square Centre of Gravity :- It is defined as the point through which the whole weight of the body is assumed to act, irrespective of the position of a body. e.g. Cone, Cylinder. Page 5

6 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. Answer any FOUR of the following : 6 a) The velocity ratio of a certain machine is 50. Determine the effort required to lift a load of 500 N if the efficiency of the machine is 0%. MA % X 00 VR MA 0 X MA 0 W But, MA P P P 75N b) Certain machine has a law of machine P = 0.05 W + 0 N, with VR = 60. Calculate its efficiency at a load of KN. ) Using Law of machine P = (0.05 W + 0) N. = ((0.05 X 000) + 0) N Putting W = 000 N = 5 N ) W 000 MA. P 5 MA. % X 00 X 00 VR 60 % % c) In a lifting machine, a load of 0 KN is raised by effort of 300 N. If the efficiency is 75%. Calculate MA & VR, if the machine lifts a load by effort of 550 N. Find the law of machine. W 0000 MA P 300 MA % X 00 VR VR. Page 6

7 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. Law of machine is P mw C 300 m(0000) c () 550 m(0000) c () Subtracting equation () from () m = 0.05 Putting value of m in equation (), 300 = (0.05 X 0000) + C C = 50 N Hence, law of machine is, P = (0.05)W + 50 N d) In a differential axle & wheel, the dia. of wheel is 00 mm & that of axle is 00 mm & 80 mm, if an effort of 50 N can lift a load of 500 N, find VR & efficiency of the machine. () VR of differential axle & wheel is given by - D X00 VR d d VR MA MA.. 30 % X 00 X 00 VR.. 0 % 75% e) A screw jack has effort wheel dia of 00 mm & pitch is 5 mm. Find VR, if load of 000 N is lifted by an effort of 50 N. Find the efficiency of a machine. ) VR of simple screw jack is given by D VR p VR X 00 5 VR = 5.66 Page 7

8 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. ) W 000 MA P 50 3) MA...0 % X 00 X 00 VR % 3.83% f) In a Westion s pulley block, the radius of the smaller wheel is ¾ than that of a larger wheel. What load is lifted by the pulley block with an effort of 00 N at an efficiency of 50 %. Let, r = Radius of smaller wheel R = Radius of larger wheel d = Diameter of smaller wheel D = Diameter of bigger wheel 3 r R d 3 D X 3 d D D D VR 8 D d 3 3 D D MA % X 00 VR MA 50 X 00 8 MA W But, MA P W 00 W 00N Page 8

9 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.3 Answer any FOUR of the following : 6 a) Find the components of the force 00 KN (push) acting at 70 with x axis. Fx F cos 00X cos 90 Fx 0N Fy F sin 00X sin 90 Fy 00N b) What are the components of 60 N force acting horizontal in two directions on either side, at an angle of 30 each? F sin 60sin 30 F 3.6N sin( ) sin(30 30) F F sin 60sin N sin( ) sin(30 30) c) Find the algebraic sum of moment of all forces shown in Fig. about the point C. Page 9

10 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.3 Mc = ( X 0) + ( X 0) + (3 X 0.866) Mc =.598 Nm (Clockwise) d) Four forces of 30 N (upward), 0 N (downward), 70 N (upward) & 60 N (downward) are acting in a series. Distances between the forces are 00 mm, 600 mm, 800 mm respectively. Find the moment of a couple. Taking moment of all forces about 30 N force i.e. about point A M = (30 X 0) + (0 X 00) (70 X 000) + (60 X 800) M = 5000 Nm (Clockwise) Page 0

11 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.3 e) Find the angle between two equal forces P, if the resultant is also equal to P. Using Law of parallelogram of forces R P Q PQ P P P PP cos ( 0.5) cos cos P P P P cos P P ( cos ) ( cos ) ( cos ) 0.5 cos 0 f) Find the resultant of all the forces as shown in Fig.. Mark its position & direction on a sketch. ) Resolving all forces Fx cos cos 0 8.N Fy 800sin sin N ) Magnitude of Resultant R ( Fx) ( Fy) ( 8.) (33.3) R 36.79N Page

12 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.3 3) Since Fx is ve & Fy is +ve, R lies in Second quadrant ) Position of Resultant Fy 33.3 tan tan Fx Q. Answer any FOUR of the following : 6 a) Find the resultant & magnitude & direction of the forces acting on a regular pentagon shown in Fig. 3 ) Resolving all forces Fx 8 6cos36 cos7 cos7 3.7kN Fy 6sin 36 sin 7 sin 7 9.3kN ) Magnitude of Resultant R ( Fx) ( Fy) (3.7) (9.3) R 6.33kN 3) Since Fx is +ve & Fy is +ve, R lies in First quadrant ) Position of Resultant Fy 9.3 tan tan Fx Page

13 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. b) Six parallel forces of magnitude 000 N, 500 N, 800 N, 000 N, 00 N, 700 N are acting at, 3, 5, 7, 8 m from the first force. Forces st, 3 rd, & 5 th are acting upwards while other acting vertically downwards. Find the resultant force analytically. ) Magnitude of Resultant R = = -000 N = 000 N ( ) - ve sign indicates Resultant acts vertically downwards. ) Position of Resultant Considering Varignon s theorem of moment & taking moment of all about 000 N force. Let, R acts at x distance from 000 N force. Σ MF = MR (000 X 0) + (500 X ) - (800 X 3) = R X x + (000 X 5) (00 X 7) + (700 X 8) 0900 = 000 X x x = 0.9 m Hence, R must be located at 0.9 m distance from 000 N force, so as to produce clockwise moment. c) Write any four properties of a couple. ) The resultant of the forces of a couple is zero. ) T he moment of a couple is equal to the product of one of the force & arm of couple. 3) Moment of a couple about any point is constant. Page 3

14 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. ) A couple can be balanced only by another couple of equal & opposite moment. 5) Two or more couples are said to be equal when they have same sense & moment. M each (any four) 6) Any number of coplanar couples can be represented by a single couple, the moment of which is equal to the algebraic sum of the moment of all the couples. Page

15 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. d) Find graphically the resultant of a concurrent force system. See Fig. Page 5

16 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. e) Find support reactions of the beam graphically. See Fig. 5 Page 6

17 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q. f) Calculate reactions at roller support & hinge support by graphical method of Fig. 6. Page 7

18 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.5 Answer any FOUR of the following : 6 a) A horizontal force P as shown in Fig. 7 keeps the weight of 00 N in equilibrium. Find the magnitude P & tension in the string T. Using Lami s theorem, W T P sin00 sin 90 sin70 00 T P sin00 sin 90 sin70 Using term () and () 00 T sin00 sin 90 sin90 T 00X sin00 T = 0.5 N Using term () and (3) 00 sin 90 P sin70 sin70 P 00X sin00 P = 7.63 N Page 8

19 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.5 b) A sphere of weight 00 N rests in a groove of smooth inclined surfaces which are making 60 & 30 inclination to the horizontal. Find the reactions at the contact surfaces. Using Lami s theorem, 00 RA RB sin 90 sin50 sin0 () () (3) Using term () and () 00 RA sin 90 sin50 sin50 RA X00 sin 90 R 00N A Using term () and (3) 00 RB sin 90 sin0 sin0 RB X00 sin 90 R 36.0N B M each (RA & RB) c) A beam of span m is simply supported at its ends. It carries concentrated load of 5 KN & 0 KN at m & m from left hand support respectively. It carries UDL of 0 KN/m from the right end. Determine reactions at the support. Page 9

20 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.5 ) Equivalent point load and it s position Equivalent point load = Intensity of udl X span of udl = 0 X = 0 KN Position from equivalent point load from RA = m + m+ Span of udl / = + (/) = 3 m ) Applying equilibrium conditions Σ Fy = 0 and Σ M = 0 Σ Fy = 0 RA RB = 0 RA + RB = 55 KN () Σ MA = 0 Taking moment of all point A (RA x 0) + (5 X ) + (0 X ) + (0 X 3) (RB X ) = 0 RB = 8.75 KN Putting value of RB in eqn. () RA = 55 RA = 6.5 KN d) A parcel weighing 00 N is just on the point of moving horizontally by a force of 5 N. What is coefficient of friction? For limiting equilibrium Σ Fy = 0 + R W = 0 R = W = 00 N R = 00 N Σ Fx = 0 + P F = 0 5 R 5 X 00 Page 0

21 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q e) Find the value of W if the body is in limiting equilibrium. See Fig. 8. For limiting equilibrium Σ Fy = 0 + R W 50 = 0 R = W () Σ Fx = 0 +F 33.0 = 0 F = 33.0 N But, F = μr 33.0 = 0.5 X R R = 33.0 / 0.5 R = Putting value of R in equation () = W + 50 W = 8.08 N f) A 00 N block is at rest on a 30 incline. The coefficient of friction between block & the incline is 0.0. Compute the value of a horizontal force P that causes motion to impend up the incline. Consider inclined plane as x-x axis and perpendicular to it as y-y axis. For limiting equilibrium Σ Fy = 0 + R (0.5 ) P = 0 R = (0.5) P () Page

22 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.5 Σ Fx = 0 + (0.866) P - F 00 = 0 + (0.866) P = (0.0 X ( P) Putting value of R P = N Q.6 Answer any FOUR of the following : a) A L section consists of two legs 00 mm X 0 mm each with 0 mm as overall depth. ) Area calculation A = 00 X 0 = 000 mm A = 00 X 0 = 000 mm A = A + A = 000 mm ) Position of x X = 00 / = 50 mm X = 0 / = 0 mm Page

23 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.6 A x A x x A (000X50) (000X0) x 000 x 30mm 3) Position of y y = 0 / = 0 mm y = 0 + (00/) = 70 mm A y A y y A (000X0) (000X70) y 000 y 0mm b) Find the centroidal position of shaded area with respect to AB. See Fig. 9 ) Area calculation A = 00 X 500 = mm A = ½ X 0 X 500 = 5000 mm A = A - A = 5000 mm ) Position of x X = 00 / = 50 mm X = 80 + (/3) X 0 = mm Page 3

24 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.6 A x A x x A (50000X50) (5000X93.333) x 5000 x 5.85mm Hence, Centroidal position of shaded area with respect to AB = 5.85 mm c) Locate centroid of shaded area. See Fig. 0 ) Let, Fig. Quarter circle and Fig. Triangle Area Calculation r (00) A mm A bh X 00 X mm A A A mm ) x calculation r X00 x.mm 3 3 b 00 x mm 3 3 A x A x ( X.) (5000X ) x A x mm ½ Page

25 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.6 3) y calculation r X00 y.mm 3 3 b 00 y mm 3 3 A y A y ( X.) (5000X ) y A y mm Hence, centroid (G) for given section lies at G( xy, ) = ( mm from y axis & mm from x axis) ½ d) A solid cone of height 0 cm is placed on a cube of side 0 cm as shown in Fig.. Locate the position of CG with respect to tip of the cone. ) Volume Calculation V 0X 0X cm V (/ 3) r h (/ 3) (0) X cm V V V 88.79cm ) y calculation 0 y 0 50cm h 0 y h 0 30cm Page 5

26 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.6 V y y V y V y 3.6cm e) Find the centre of gravity of composite solid w.r.t. x & y axis. See Fig.. ) Figure is y-y axis and hence, x = Maximum horizontal dimension / = 00 / = 00 mm ) Volume Calculation 3 (00) V r h X mm (/3) (/3) (50) 3767 V r mm V V V X0 mm 3) y calculation y 50mm y mm V y y V y V y 33.7mm Page 6

27 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.6 f) A frustum of solid circular cone of top diameter 30 cm, bottom diameter 60 cm & height of 50 cm. Find the centre of gravity of the frustum. Let, Full cone as Fig. & cut cone as Fig. ) Figure is y-y axis and hence, x = Maximum horizontal dimension / = 60 / = 30 cm h = 50 cm, h = Height of cut cone In triangle, ABE & CDE h h h h 30 h h h h h h h h h h h h h 50 h h 50cm h cm Page 7

28 (ISO/IEC Certified) Model Answer: Summer 07 Code: 70 Q.6 ) Volume Calculation 3 (/ 3) (/ 3) (30) V r h X cm 3 (/ 3) (/ 3) (5) V r h X cm V V V 650 cm 3 3) y calculation h 00 y 5cm h 50 V y V y y V y h cm y 9.6cm Page 8

Subject : Engineering Mechanics Subject Code : 1704 Page No: 1 / 6 ----------------------------- Important Instructions to examiners: 1) The answers should be examined by key words and not as word-to-word

More information

Model Answers Attempt any TEN of the following :

Model Answers Attempt any TEN of the following : (ISO/IEC - 70-005 Certified) Model Answer: Winter 7 Sub. Code: 17 Important Instructions to Examiners: 1) The answers should be examined by key words and not as word-to-word as given in the model answer

More information

Vidyalanakar F.Y. Diploma : Sem. II [AE/CE/CH/CR/CS/CV/EE/EP/FE/ME/MH/MI/PG/PT/PS] Engineering Mechanics

Vidyalanakar F.Y. Diploma : Sem. II [AE/CE/CH/CR/CS/CV/EE/EP/FE/ME/MH/MI/PG/PT/PS] Engineering Mechanics Vidyalanakar F.Y. Diploma : Sem. II [AE/CE/CH/CR/CS/CV/EE/EP/FE/ME/MH/MI/PG/PT/PS] Engineering Mechanics Time : 3 Hrs.] Prelim Question Paper Solution [Marks : 100 Q.1 Attempt any TEN of the following

More information

1. Attempt any ten of the following : 20

1. Attempt any ten of the following : 20 *17204* 17204 21314 3 Hours/100 Marks Seat No. Instructions : (1) All questions are compulsory. (2) Answer each next main question on a new page. (3) Illustrate your answers with neat sketches wherever

More information

Engineering Mechanics

Engineering Mechanics F.Y. Diploma : Sem. II [AE/CE/CH/CR/CS/CV/EE/EP/FE/ME/MH/MI/PG/PT/PS] Engineering Mechanics Time : 3 Hrs.] Prelim Question Paper Solution [Marks : 00 Q. Attempt any TEN of the following : [20] Q.(a) Difference

More information

Sample Test Paper - I

Sample Test Paper - I Scheme - G Sample Test Paper - I Course Name : Civil, Chemical, Mechanical and Electrical Engineering Group Course Code : AE/CE/CH/CR/CS/CV/EE/EP/FE/ME/MH/MI/PG/PT/PS Semester : Second Subject Title :

More information

Hours / 100 Marks Seat No.

Hours / 100 Marks Seat No. 17204 15116 3 Hours / 100 Seat No. Instructions (1) All Questions are Compulsory. (2) Answer each next main Question on a new page. (3) Illustrate your answers with neat sketches wherever necessary. (4)

More information

KINGS COLLEGE OF ENGINEERING ENGINEERING MECHANICS QUESTION BANK UNIT I - PART-A

KINGS COLLEGE OF ENGINEERING ENGINEERING MECHANICS QUESTION BANK UNIT I - PART-A KINGS COLLEGE OF ENGINEERING ENGINEERING MECHANICS QUESTION BANK Sub. Code: CE1151 Sub. Name: Engg. Mechanics UNIT I - PART-A Sem / Year II / I 1.Distinguish the following system of forces with a suitable

More information

VALLIAMMAI ENGINEERING COLLEGE SRM NAGAR, KATTANKULATHUR DEPARTMENT OF MECHANICAL ENGINEERING

VALLIAMMAI ENGINEERING COLLEGE SRM NAGAR, KATTANKULATHUR DEPARTMENT OF MECHANICAL ENGINEERING VALLIAMMAI ENGINEERING COLLEGE SRM NAGAR, KATTANKULATHUR 603203 DEPARTMENT OF MECHANICAL ENGINEERING BRANCH: MECHANICAL YEAR / SEMESTER: I / II UNIT 1 PART- A 1. State Newton's three laws of motion? 2.

More information

ENGINEERING MECHANICS - Question Bank

ENGINEERING MECHANICS - Question Bank E Semester-_IST YEAR (CIVIL, MECH, AUTO, CHEM, RUER, PLASTIC, ENV,TT,AERO) ENGINEERING MECHANICS - Question ank All questions carry equal marks(10 marks) Q.1 Define space,time matter and force, scalar

More information

Hours / 100 Marks Seat No.

Hours / 100 Marks Seat No. 17204 15162 3 Hours / 100 Marks Seat No. Instructions : (1) All Questions are compulsory. (2) Answer each next main Question on a new page. (3) Illustrate your answers with neat sketches wherever necessary.

More information

where G is called the universal gravitational constant.

where G is called the universal gravitational constant. UNIT-I BASICS & STATICS OF PARTICLES 1. What are the different laws of mechanics? First law: A body does not change its state of motion unless acted upon by a force or Every object in a state of uniform

More information

2015 ENGINEERING MECHANICS

2015 ENGINEERING MECHANICS Set No - 1 I B.Tech I Semester Regular/Supple. Examinations Nov./Dec. 2015 ENGINEERING MECHANICS (Common to CE, ME, CSE, PCE, IT, Chem. E, Aero E, AME, Min E, PE, Metal E, Textile Engg.) Time: 3 hours

More information

Questions from all units

Questions from all units Questions from all units S.NO 1. 1 UNT NO QUESTON Explain the concept of force and its characteristics. BLOOMS LEVEL LEVEL 2. 2 Explain different types of force systems with examples. Determine the magnitude

More information

Dept of ECE, SCMS Cochin

Dept of ECE, SCMS Cochin B B2B109 Pages: 3 Reg. No. Name: APJ ABDUL KALAM TECHNOLOGICAL UNIVERSITY SECOND SEMESTER B.TECH DEGREE EXAMINATION, MAY 2017 Course Code: BE 100 Course Name: ENGINEERING MECHANICS Max. Marks: 100 Duration:

More information

JNTU World. Subject Code: R13110/R13

JNTU World. Subject Code: R13110/R13 Set No - 1 I B. Tech I Semester Regular Examinations Feb./Mar. - 2014 ENGINEERING MECHANICS (Common to CE, ME, CSE, PCE, IT, Chem E, Aero E, AME, Min E, PE, Metal E) Time: 3 hours Max. Marks: 70 Question

More information

PESIT- Bangalore South Campus Dept of science & Humanities Sub: Elements Of Civil Engineering & Engineering Mechanics 1 st module QB

PESIT- Bangalore South Campus Dept of science & Humanities Sub: Elements Of Civil Engineering & Engineering Mechanics 1 st module QB PESIT- Bangalore South Campus Dept of science & Humanities Sub: Elements Of Civil Engineering & Engineering Mechanics 1 st module QB Sub Code: 15CIV13/23 1. Briefly give the scope of different fields in

More information

PART-A. a. 60 N b. -60 N. c. 30 N d. 120 N. b. How you can get direction of Resultant R when number of forces acting on a particle in plane.

PART-A. a. 60 N b. -60 N. c. 30 N d. 120 N. b. How you can get direction of Resultant R when number of forces acting on a particle in plane. V.S.. ENGINEERING OLLEGE, KRUR EPRTMENT OF MEHNIL ENGINEERING EMI YER: 2009-2010 (EVEN SEMESTER) ENGINEERING MEHNIS (MEH II SEM) QUESTION NK UNIT I PRT- EM QUESTION NK 1. efine Mechanics 2. What is meant

More information

2015 ENGINEERING MECHANICS

2015 ENGINEERING MECHANICS Set No - 1 I B. Tech I Semester Supplementary Examinations Aug. 2015 ENGINEERING MECHANICS (Common to CE, ME, CSE, PCE, IT, Chem E, Aero E, AME, Min E, PE, Metal E) Time: 3 hours Max. Marks: 70 Question

More information

2016 ENGINEERING MECHANICS

2016 ENGINEERING MECHANICS Set No 1 I B. Tech I Semester Regular Examinations, Dec 2016 ENGINEERING MECHANICS (Com. to AE, AME, BOT, CHEM, CE, EEE, ME, MTE, MM, PCE, PE) Time: 3 hours Max. Marks: 70 Question Paper Consists of Part-A

More information

ISBN :

ISBN : ISBN : 978-81-909042-4-7 - www.airwalkpublications.com ANNA UNIVERSITY - R2013 GE6253 ENGINEERING MECHANICS UNIT I: BASICS AND STATICS OF PARTICLES 12 Introduction Units and Dimensions Laws of Mechanics

More information

2. a) Explain the equilibrium of i) Concurrent force system, and ii) General force system.

2. a) Explain the equilibrium of i) Concurrent force system, and ii) General force system. Code No: R21031 R10 SET - 1 II B. Tech I Semester Supplementary Examinations Dec 2013 ENGINEERING MECHANICS (Com to ME, AE, AME, MM) Time: 3 hours Max. Marks: 75 Answer any FIVE Questions All Questions

More information

K.GNANASEKARAN. M.E.,M.B.A.,(Ph.D)

K.GNANASEKARAN. M.E.,M.B.A.,(Ph.D) DEPARTMENT OF MECHANICAL ENGG. Engineering Mechanics I YEAR 2th SEMESTER) Two Marks Question Bank UNIT-I Basics and statics of particles 1. Define Engineering Mechanics Engineering Mechanics is defined

More information

Statics deal with the condition of equilibrium of bodies acted upon by forces.

Statics deal with the condition of equilibrium of bodies acted upon by forces. Mechanics It is defined as that branch of science, which describes and predicts the conditions of rest or motion of bodies under the action of forces. Engineering mechanics applies the principle of mechanics

More information

Lesson Plan. Name of the Faculty : SANDEEP (VTF in CIVIL ENGG.) Lesson plan duration : 15 Weeks(July 2018 to Nov 2018)

Lesson Plan. Name of the Faculty : SANDEEP (VTF in CIVIL ENGG.) Lesson plan duration : 15 Weeks(July 2018 to Nov 2018) Lesson Plan Name of the Faculty : SANDEEP (VTF in CIVIL ENGG.) Discipline : CIVIL Engg. Semester : 3 rd Subject : Applied Mechanics Lesson plan duration : 15 s(july 2018 to Nov 2018) - 1 2 3 Theory Practical

More information

Set No - 1 I B. Tech I Semester Regular Examinations Jan./Feb ENGINEERING MECHANICS

Set No - 1 I B. Tech I Semester Regular Examinations Jan./Feb ENGINEERING MECHANICS 3 Set No - 1 I B. Tech I Semester Regular Examinations Jan./Feb. 2015 ENGINEERING MECHANICS (Common to CE, ME, CSE, PCE, IT, Chem E, Aero E, AME, Min E, PE, Metal E) Time: 3 hours Question Paper Consists

More information

Coplanar Concurrent Forces 7) Find magnitude and direction of the resultant force of the force system as shown in

Coplanar Concurrent Forces 7) Find magnitude and direction of the resultant force of the force system as shown in ALPHA COLLEGE OF ENGINEERING & TECHNOLOGY SUBJECT: Engineering Mechanics(3300008) Introduction 1) Define the terms. (WINTER 2013) [1] Kinematics [2] Freebody diagram [3] Equilibrunt [4] Couple [5] Limiting

More information

Mathematics. Statistics

Mathematics. Statistics Mathematics Statistics Table of Content. Introduction.. arallelogram law of forces. 3. Triangle law of forces. 4. olygon law of forces. 5. Lami's theorem. 6. arallel forces. 7. Moment. 8. Couples. 9. Triangle

More information

Sub. Code:

Sub. Code: Important Instructions to examiners: ) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. ) The model answer and the answer written by candidate may

More information

STATICS. FE Review. Statics, Fourteenth Edition R.C. Hibbeler. Copyright 2016 by Pearson Education, Inc. All rights reserved.

STATICS. FE Review. Statics, Fourteenth Edition R.C. Hibbeler. Copyright 2016 by Pearson Education, Inc. All rights reserved. STATICS FE Review 1. Resultants of force systems VECTOR OPERATIONS (Section 2.2) Scalar Multiplication and Division VECTOR ADDITION USING EITHER THE PARALLELOGRAM LAW OR TRIANGLE Parallelogram Law: Triangle

More information

Code No: R Set No. 1

Code No: R Set No. 1 Code No: R05010302 Set No. 1 I B.Tech Supplimentary Examinations, February 2008 ENGINEERING MECHANICS ( Common to Mechanical Engineering, Mechatronics, Metallurgy & Material Technology, Production Engineering,

More information

.VALLIAMMAI ENGINEERING COLLEGE

.VALLIAMMAI ENGINEERING COLLEGE .VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur 603 203 DEPARTMENT OF GENERAL ENGINEERING QUESTION BANK II SEMESTER GE 8292- Engineering Mechanics Regulation 2017 Academic Year 2017 18 VALLIAMMAI

More information

C7047. PART A Answer all questions, each carries 5 marks.

C7047. PART A Answer all questions, each carries 5 marks. 7047 Reg No.: Total Pages: 3 Name: Max. Marks: 100 PJ DUL KLM TEHNOLOGIL UNIVERSITY FIRST SEMESTER.TEH DEGREE EXMINTION, DEEMER 2017 ourse ode: E100 ourse Name: ENGINEERING MEHNIS PRT nswer all questions,

More information

ENGINEERING MECHANICS SOLUTIONS UNIT-I

ENGINEERING MECHANICS SOLUTIONS UNIT-I LONG QUESTIONS ENGINEERING MECHANICS SOLUTIONS UNIT-I 1. A roller shown in Figure 1 is mass 150 Kg. What force P is necessary to start the roller over the block A? =90+25 =115 = 90+25.377 = 115.377 = 360-(115+115.377)

More information

ENGINEERING MECHANICS

ENGINEERING MECHANICS Set No - 1 I B. Tech II Semester Regular/Supply Examinations July/Aug. - 2015 ENGINEERING MECHANICS (Common to ECE, EEE, EIE, Bio-Tech, E Com.E, Agri. E) Time: 3 hours Max. Marks: 70 Question Paper Consists

More information

JNTU World. Subject Code: R13110/R13 '' '' '' ''' '

JNTU World. Subject Code: R13110/R13 '' '' '' ''' ' Set No - 1 I B. Tech I Semester Supplementary Examinations Sept. - 2014 ENGINEERING MECHANICS (Common to CE, ME, CSE, PCE, IT, Chem E, Aero E, AME, Min E, PE, Metal E) Time: 3 hours Max. Marks: 70 Question

More information

Engineering Mechanics Questions for Online Examination (Unit-I)

Engineering Mechanics Questions for Online Examination (Unit-I) Engineering Mechanics Questions for Online Examination (Unit-I) [1] If two equal forces are acting at a right angle, having resultant force of (20)½,then find out magnitude of each force.( Ans. (10)½)

More information

A TEXTBOOK APPLIED MECHANICS

A TEXTBOOK APPLIED MECHANICS A TEXTBOOK OF APPLIED MECHANICS A TEXTBOOK OF APPLIED MECHANICS (Including Laboratory Practicals) S.I. UNITS By R.K. RAJPUT M.E. (Heat Power Engg.) Hons. Gold Medallist ; Grad. (Mech. Engg. & Elect. Engg.)

More information

This lesson is an important one since it will deal with forces acting in conjunction with one another, against one another, and the resultant of a

This lesson is an important one since it will deal with forces acting in conjunction with one another, against one another, and the resultant of a 1 This lesson is an important one since it will deal with forces acting in conjunction with one another, against one another, and the resultant of a number of forces acting through a common point (known

More information

SECOND ENGINEER REG. III/2 APPLIED MECHANICS

SECOND ENGINEER REG. III/2 APPLIED MECHANICS SECOND ENGINEER REG. III/2 APPLIED MECHANICS LIST OF TOPICS Static s Friction Kinematics Dynamics Machines Strength of Materials Hydrostatics Hydrodynamics A STATICS 1 Solves problems involving forces

More information

Assignment No. 1 RESULTANT OF COPLANAR FORCES

Assignment No. 1 RESULTANT OF COPLANAR FORCES Assignment No. 1 RESULTANT OF COPLANAR FORCES Theory Questions: 1) Define force and body. (Dec. 2004 2 Mks) 2) State and explain the law of transmissibility of forces. (May 2009 4 Mks) Or 3) What is law

More information

E.G.S. PILLAY ENGINEERING COLLEGE (An Autonomous Institution, Affiliated to Anna University, Chennai) Nagore Post, Nagapattinam , Tamilnadu.

E.G.S. PILLAY ENGINEERING COLLEGE (An Autonomous Institution, Affiliated to Anna University, Chennai) Nagore Post, Nagapattinam , Tamilnadu. Academic Year: 017-018 1701GEX04 ENGINEERING MECHANICS Programme: Question Bank B.E Mechanical Year / Semester: I / II Course Coordinator: Mr.S.K.Krishnakumar/ Mr.V.Manathunainathan Course Objectives To

More information

USHA RAMA COLLEGE OF ENGINEERING & TECHNOLOGY

USHA RAMA COLLEGE OF ENGINEERING & TECHNOLOGY Set No - 1 I B. Tech II Semester Supplementary Examinations Feb. - 2015 ENGINEERING MECHANICS (Common to ECE, EEE, EIE, Bio-Tech, E Com.E, Agri. E) Time: 3 hours Max. Marks: 70 Question Paper Consists

More information

E 490 FE Exam Prep. Engineering Mechanics

E 490 FE Exam Prep. Engineering Mechanics E 490 FE Exam Prep Engineering Mechanics 2008 E 490 Course Topics Statics Newton s Laws of Motion Resultant Force Systems Moment of Forces and Couples Equilibrium Pulley Systems Trusses Centroid of an

More information

if the initial displacement and velocities are zero each. [ ] PART-B

if the initial displacement and velocities are zero each. [ ] PART-B Set No - 1 I. Tech II Semester Regular Examinations ugust - 2014 ENGINEERING MECHNICS (Common to ECE, EEE, EIE, io-tech, E Com.E, gri. E) Time: 3 hours Max. Marks: 70 Question Paper Consists of Part- and

More information

GUJARAT TECHNOLOGICAL UNIVERSITY, AHMEDABAD.

GUJARAT TECHNOLOGICAL UNIVERSITY, AHMEDABAD. ENGINEERING MECHANICS 1. RATIONALE Engineering Mechanics is a branch of Applied Science where laws of physics are applied to solve engineering problems. Broadly speaking Engineering Mechanics can be classified

More information

UNIT 1: BASIC CONCEPTS

UNIT 1: BASIC CONCEPTS Civil & Engg. 1 UNIT 1: BASIC CONCETS 1. INTRODUCTION: Solids Rigid solids (Engg Mechanics deals with them) Deformable solids (Solid Mechanics deals with them) Matter (Substance) Fluids Liquids (Fluid

More information

Engineering Mechanics I Year B.Tech

Engineering Mechanics I Year B.Tech Engineering Mechanics I Year B.Tech By N.SRINIVASA REDDY., M.Tech. Sr. Assistant Professor Department of Mechanical Engineering Vardhaman College of Engineering Basic concepts of Mathematics & Physics

More information

ENGINEERING MECHANICS

ENGINEERING MECHANICS ENGINEERING MECHANICS ENGINEERING MECHANICS (In SI Units) For BE/B.Tech. Ist YEAR Strictly as per the latest syllabus prescribed by Mahamaya Technical University, Noida By Dr. R.K. BANSAL B.Sc. Engg.

More information

I B.TECH EXAMINATIONS, JUNE ENGINEERING MECHANICS (COMMON TO CE, ME, CHEM, MCT, MMT, AE, AME, MIE, MIM)

I B.TECH EXAMINATIONS, JUNE ENGINEERING MECHANICS (COMMON TO CE, ME, CHEM, MCT, MMT, AE, AME, MIE, MIM) Code.No: 09A1BS05 R09 SET-1 I B.TECH EXAMINATIONS, JUNE - 2011 ENGINEERING MECHANICS (COMMON TO CE, ME, CHEM, MCT, MMT, AE, AME, MIE, MIM) Time: 3 hours Max. Marks: 75 Answer any FIVE questions All questions

More information

Unit 1. (a) tan α = (b) tan α = (c) tan α = (d) tan α =

Unit 1. (a) tan α = (b) tan α = (c) tan α = (d) tan α = Unit 1 1. The subjects Engineering Mechanics deals with (a) Static (b) kinematics (c) Kinetics (d) All of the above 2. If the resultant of two forces P and Q is acting at an angle α with P, then (a) tan

More information

7.6 Journal Bearings

7.6 Journal Bearings 7.6 Journal Bearings 7.6 Journal Bearings Procedures and Strategies, page 1 of 2 Procedures and Strategies for Solving Problems Involving Frictional Forces on Journal Bearings For problems involving a

More information

Al-Saudia Virtual Academy Pakistan Online Tuition Online Tutor Pakistan

Al-Saudia Virtual Academy Pakistan Online Tuition Online Tutor Pakistan Al-Saudia Virtual Academy Pakistan Online Tuition Online Tutor Pakistan Statics What do you mean by Resultant Force? Ans: Resultant Force: The sum of all forces acting upon a body is called Resultant Force.

More information

Vector Mechanics: Statics

Vector Mechanics: Statics PDHOnline Course G492 (4 PDH) Vector Mechanics: Statics Mark A. Strain, P.E. 2014 PDH Online PDH Center 5272 Meadow Estates Drive Fairfax, VA 22030-6658 Phone & Fax: 703-988-0088 www.pdhonline.org www.pdhcenter.com

More information

The Moment of a Force

The Moment of a Force The Moment of a Force When we consider cases where forces act on a body of non-zero size (i.e. not a particle), the main new aspect that we need to take account of is that such a body can rotate, as well

More information

Reg. No. : Question Paper Code : B.E./B.Tech. DEGREE EXAMINATION, NOVEMBER/DECEMBER Second Semester.

Reg. No. : Question Paper Code : B.E./B.Tech. DEGREE EXAMINATION, NOVEMBER/DECEMBER Second Semester. Ws11 Reg. No. : Question Paper Code : 27275 B.E./B.Tech. DEGREE EXAMINATION, NOVEMBER/DECEMBER 2015. Second Semester Civil Engineering GE 6253 ENGINEERING MECHANICS (Common to all branches except Electrical

More information

YEAR 13 - Mathematics Pure (C3) Term 1 plan

YEAR 13 - Mathematics Pure (C3) Term 1 plan Week Topic YEAR 13 - Mathematics Pure (C3) Term 1 plan 2016-2017 1-2 Algebra and functions Simplification of rational expressions including factorising and cancelling. Definition of a function. Domain

More information

Unit 21 Couples and Resultants with Couples

Unit 21 Couples and Resultants with Couples Unit 21 Couples and Resultants with Couples Page 21-1 Couples A couple is defined as (21-5) Moment of Couple The coplanar forces F 1 and F 2 make up a couple and the coordinate axes are chosen so that

More information

TEST-1 MEACHNICAL (MEACHNICS)

TEST-1 MEACHNICAL (MEACHNICS) 1 TEST-1 MEACHNICAL (MEACHNICS) Objective Type Questions:- Q.1 The term force may be defined as an agent t which produces or tends to produce, destroys or tends to destroy motion. a) Agree b) disagree

More information

Dr. ANIL PATIL Associate Professor M.E.D., D.I.T., Dehradun

Dr. ANIL PATIL Associate Professor M.E.D., D.I.T., Dehradun by Dr. ANIL PATIL Associate Professor M.E.D., D.I.T., Dehradun 1 2 Mechanics The study of forces and their effect upon body under consideration Statics Deals with the forces which are acting on a body

More information

Motion in a straight line

Motion in a straight line Exam-style assessment Motion in a straight line 1. The speed-time graph shown relates to a car travelling between two sets of traffic lights. The car accelerates from rest and reaches a speed of 0 ms -1

More information

APPLIED MATHEMATICS IM 02

APPLIED MATHEMATICS IM 02 IM SYLLABUS (2013) APPLIED MATHEMATICS IM 02 SYLLABUS Applied Mathematics IM 02 Syllabus (Available in September) 1 Paper (3 hours) Applied Mathematics (Mechanics) Aims A course based on this syllabus

More information

STATICS. Bodies. Vector Mechanics for Engineers: Statics VECTOR MECHANICS FOR ENGINEERS: Design of a support

STATICS. Bodies. Vector Mechanics for Engineers: Statics VECTOR MECHANICS FOR ENGINEERS: Design of a support 4 Equilibrium CHAPTER VECTOR MECHANICS FOR ENGINEERS: STATICS Ferdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech University of Rigid Bodies 2010 The McGraw-Hill Companies,

More information

Core Mathematics M1. Dynamics (Planes)

Core Mathematics M1. Dynamics (Planes) Edexcel GCE Core Mathematics M1 Dynamics (Planes) Materials required for examination Mathematical Formulae (Green) Items included with question papers Nil Advice to Candidates You must ensure that your

More information

Statics Chapter II Fall 2018 Exercises Corresponding to Sections 2.1, 2.2, and 2.3

Statics Chapter II Fall 2018 Exercises Corresponding to Sections 2.1, 2.2, and 2.3 Statics Chapter II Fall 2018 Exercises Corresponding to Sections 2.1, 2.2, and 2.3 2 3 Determine the magnitude of the resultant force FR = F1 + F2 and its direction, measured counterclockwise from the

More information

The Great Indian Hornbill

The Great Indian Hornbill The Great Indian Hornbill Our mascot The Great Indian Hornbill is on the verge of extinction and features in International Union for Conservation of Nature (IUCN) red list of endangered species. Now these

More information

2008 FXA THREE FORCES IN EQUILIBRIUM 1. Candidates should be able to : TRIANGLE OF FORCES RULE

2008 FXA THREE FORCES IN EQUILIBRIUM 1. Candidates should be able to : TRIANGLE OF FORCES RULE THREE ORCES IN EQUILIBRIUM 1 Candidates should be able to : TRIANGLE O ORCES RULE Draw and use a triangle of forces to represent the equilibrium of three forces acting at a point in an object. State that

More information

Choose the correct answer

Choose the correct answer Choose the correct answer (1) In the opposite figure: The body is about to move downwards then the measure of the angle of the static friction equals.. a 6.87 b 41.41 c 48.59 d 5.1 (2) If q is the measure

More information

SN QUESTION YEAR MARK 1. State and prove the relationship between shearing stress and rate of change of bending moment at a section in a loaded beam.

SN QUESTION YEAR MARK 1. State and prove the relationship between shearing stress and rate of change of bending moment at a section in a loaded beam. ALPHA COLLEGE OF ENGINEERING AND TECHNOLOGY DEPARTMENT OF MECHANICAL ENGINEERING MECHANICS OF SOLIDS (21000) ASSIGNMENT 1 SIMPLE STRESSES AND STRAINS SN QUESTION YEAR MARK 1 State and prove the relationship

More information

Quizzam Module 1 : Statics

Quizzam Module 1 : Statics Structural Steel Design Quizzam odule : Statics NAE Draw shear and moment diagrams for the following loading conditions. Note the reactions. Calculate the maximum amount of internal bending moment. 0 500

More information

Anna University May/June 2013 Exams ME2151 Engineering Mechanics Important Questions.

Anna University May/June 2013 Exams ME2151 Engineering Mechanics Important Questions. Anna University May/June 2013 Exams ME2151 Engineering Mechanics Important Questions 1. Find the resultant force and its direction for the given figure 2. Two forces are acting at a point O as shown in

More information

STEP Support Programme. Mechanics STEP Questions

STEP Support Programme. Mechanics STEP Questions STEP Support Programme Mechanics STEP Questions This is a selection of mainly STEP I questions with a couple of STEP II questions at the end. STEP I and STEP II papers follow the same specification, the

More information

BTECH MECHANICAL PRINCIPLES AND APPLICATIONS. Level 3 Unit 5

BTECH MECHANICAL PRINCIPLES AND APPLICATIONS. Level 3 Unit 5 BTECH MECHANICAL PRINCIPLES AND APPLICATIONS Level 3 Unit 5 FORCES AS VECTORS Vectors have a magnitude (amount) and a direction. Forces are vectors FORCES AS VECTORS (2 FORCES) Forces F1 and F2 are in

More information

TUTORIAL SHEET 1. magnitude of P and the values of ø and θ. Ans: ø =74 0 and θ= 53 0

TUTORIAL SHEET 1. magnitude of P and the values of ø and θ. Ans: ø =74 0 and θ= 53 0 TUTORIAL SHEET 1 1. The rectangular platform is hinged at A and B and supported by a cable which passes over a frictionless hook at E. Knowing that the tension in the cable is 1349N, determine the moment

More information

ENGINEERING MECHANICS UNIT-I BASICS & STATICS OF PARTICLES 1. What is meant by mechanics? 2. What is meant by Engineering Mechanics? 3. State the different type of mechanics 4. Define Statics 5. Define

More information

LOVELY PROFESSIONAL UNIVERSITY BASIC ENGINEERING MECHANICS MCQ TUTORIAL SHEET OF MEC Concurrent forces are those forces whose lines of action

LOVELY PROFESSIONAL UNIVERSITY BASIC ENGINEERING MECHANICS MCQ TUTORIAL SHEET OF MEC Concurrent forces are those forces whose lines of action LOVELY PROFESSIONAL UNIVERSITY BASIC ENGINEERING MECHANICS MCQ TUTORIAL SHEET OF MEC 107 1. Concurrent forces are those forces whose lines of action 1. Meet on the same plane 2. Meet at one point 3. Lie

More information

Kinematics of. Motion. 8 l Theory of Machines

Kinematics of. Motion. 8 l Theory of Machines 8 l Theory of Machines Features 1. 1ntroduction.. Plane Motion. 3. Rectilinear Motion. 4. Curvilinear Motion. 5. Linear Displacement. 6. Linear Velocity. 7. Linear Acceleration. 8. Equations of Linear

More information

ME 6505 DYNAMICS OF MACHINES Fifth Semester Mechanical Engineering (Regulations 2013)

ME 6505 DYNAMICS OF MACHINES Fifth Semester Mechanical Engineering (Regulations 2013) ME 6505 DYNAMICS OF MACHINES Fifth Semester Mechanical Engineering (Regulations 2013) Unit II PART A 1. Define static balancing of shaft. (N/D 15) The net dynamic force acting on the shaft is equal to

More information

Cambridge International Examinations Cambridge International Advanced Level FURTHER MATHEMATICS 9231/23 Paper 2 October/November 2014 3 hours *8248777190* Additional Materials: Answer Booklet/Paper Graph

More information

Sub. Code:

Sub. Code: (ISO/IEC - 700-005 Certified) Model Answer: Summer 08 Code: 05 Important Instructions to examiners: ) The answers should be examined by key words and not as word-to-word as given in the model answer scheme.

More information

A.M. MONDAY, 25 January hours

A.M. MONDAY, 25 January hours GCE S/ level 980/01 MTHEMTICS M1 Mechanics 1.M. MONDY, 25 January 2010 1 1 2 hours W10 0980 01 1 DDITIONL MTERILS In addition to this examination paper, you will need: a 12 page answer book; a Formula

More information

MECHANICS OF SOLIDS Credit Hours: 6

MECHANICS OF SOLIDS Credit Hours: 6 MECHANICS OF SOLIDS Credit Hours: 6 Teaching Scheme Theory Tutorials Practical Total Credit Hours/week 4 0 6 6 Marks 00 0 50 50 6 A. Objective of the Course: Objectives of introducing this subject at second

More information

Chapter 8 - Rotational Dynamics and Equilibrium REVIEW

Chapter 8 - Rotational Dynamics and Equilibrium REVIEW Pagpalain ka! (Good luck, in Filipino) Date Chapter 8 - Rotational Dynamics and Equilibrium REVIEW TRUE/FALSE. Write 'T' if the statement is true and 'F' if the statement is false. 1) When a rigid body

More information

Practice. Newton s 3 Laws of Motion. Recall. Forces a push or pull acting on an object; a vector quantity measured in Newtons (kg m/s²)

Practice. Newton s 3 Laws of Motion. Recall. Forces a push or pull acting on an object; a vector quantity measured in Newtons (kg m/s²) Practice A car starts from rest and travels upwards along a straight road inclined at an angle of 5 from the horizontal. The length of the road is 450 m and the mass of the car is 800 kg. The speed of

More information

4.0 m s 2. 2 A submarine descends vertically at constant velocity. The three forces acting on the submarine are viscous drag, upthrust and weight.

4.0 m s 2. 2 A submarine descends vertically at constant velocity. The three forces acting on the submarine are viscous drag, upthrust and weight. 1 1 wooden block of mass 0.60 kg is on a rough horizontal surface. force of 12 N is applied to the block and it accelerates at 4.0 m s 2. wooden block 4.0 m s 2 12 N hat is the magnitude of the frictional

More information

Mathematics AS/P1/D17 AS PAPER 1

Mathematics AS/P1/D17 AS PAPER 1 Surname Other Names Candidate Signature Centre Number Candidate Number Examiner Comments Total Marks Mathematics AS PAPER 1 December Mock Exam (AQA Version) CM Time allowed: 1 hour and 30 minutes Instructions

More information

MARKS DISTRIBUTION AS PER CHAPTER (QUESTION ASKED IN GTU EXAM) Name Of Chapter. Applications of. Friction. Centroid & Moment.

MARKS DISTRIBUTION AS PER CHAPTER (QUESTION ASKED IN GTU EXAM) Name Of Chapter. Applications of. Friction. Centroid & Moment. Introduction Fundamentals of statics Applications of fundamentals of statics Friction Centroid & Moment of inertia Simple Stresses & Strain Stresses in Beam Torsion Principle Stresses DEPARTMENT OF CIVIL

More information

two forces and moments Structural Math Physics for Structures Structural Math

two forces and moments Structural Math Physics for Structures Structural Math RHITETURL STRUTURES: ORM, EHVIOR, ND DESIGN DR. NNE NIHOLS SUMMER 05 lecture two forces and moments orces & Moments rchitectural Structures 009abn Structural Math quantify environmental loads how big is

More information

FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Saturday, 14 December 2013, 1PM to 4 PM, AT 1003

FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Saturday, 14 December 2013, 1PM to 4 PM, AT 1003 FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Saturday, 14 December 2013, 1PM to 4 PM, AT 1003 NAME: STUDENT ID: INSTRUCTION 1. This exam booklet has 14 pages. Make sure none are missing 2. There is

More information

Advanced/Advanced Subsidiary. You must have: Mathematical Formulae and Statistical Tables (Blue)

Advanced/Advanced Subsidiary. You must have: Mathematical Formulae and Statistical Tables (Blue) Write your name here Surname Other names Pearson Edexcel International Advanced Level Centre Number Mechanics M2 Advanced/Advanced Subsidiary Candidate Number Tuesday 24 January 2017 Morning Time: 1 hour

More information

Upthrust and Archimedes Principle

Upthrust and Archimedes Principle 1 Upthrust and Archimedes Principle Objects immersed in fluids, experience a force which tends to push them towards the surface of the liquid. This force is called upthrust and it depends on the density

More information

Course Material Engineering Mechanics. Topic: Friction

Course Material Engineering Mechanics. Topic: Friction Course Material Engineering Mechanics Topic: Friction by Dr.M.Madhavi, Professor, Department of Mechanical Engineering, M.V.S.R.Engineering College, Hyderabad. Contents PART I : Introduction to Friction

More information

CHAPTER 8: ROTATIONAL OF RIGID BODY PHYSICS. 1. Define Torque

CHAPTER 8: ROTATIONAL OF RIGID BODY PHYSICS. 1. Define Torque 7 1. Define Torque 2. State the conditions for equilibrium of rigid body (Hint: 2 conditions) 3. Define angular displacement 4. Define average angular velocity 5. Define instantaneous angular velocity

More information

Mechanics M2 Advanced Subsidiary

Mechanics M2 Advanced Subsidiary Paper Reference(s) 6678 Edexcel GCE Mechanics M2 Advanced Subsidiary Wednesday 12 January 2005 Afternoon Time: 1 hour 30 minutes Materials required for examination Mathematical Formulae (Lilac or Green)

More information

BHASVIC MαTHS. Skills 1

BHASVIC MαTHS. Skills 1 Skills 1 Normally we work with equations in the form y = f(x) or x + y + z = 10 etc. These types of equations are called Cartesian Equations all the variables are grouped together into one equation, and

More information

Please Visit us at:

Please Visit us at: IMPORTANT QUESTIONS WITH ANSWERS Q # 1. Differentiate among scalars and vectors. Scalars Vectors (i) The physical quantities that are completely (i) The physical quantities that are completely described

More information

10.5. Forces are called coplanar when all of them acting on body lie in (a) one point

10.5. Forces are called coplanar when all of them acting on body lie in (a) one point 10.1. The unit of force in S.I. units is (a) kilogram (b) newton (c) watt (d) dyne (e) joule. 10.2. The unit of work or energy in S.I. units is (a) newton (b) pascal (c) kilogram metre (d) watt (e) joule.

More information

Coimisiún na Scrúduithe Stáit State Examinations Commission

Coimisiún na Scrúduithe Stáit State Examinations Commission 00. M3 Coimisiún na Scrúduithe Stáit State Examinations Commission LEAVING CERTIFICATE EXAMINATION, 00 APPLIED MATHEMATICS HIGHER LEVEL FRIDAY, 5 JUNE MORNING, 9.30 to.00 Six questions to be answered.

More information

Figure Two. Then the two vector equations of equilibrium are equivalent to three scalar equations:

Figure Two. Then the two vector equations of equilibrium are equivalent to three scalar equations: 2004- v 10/16 2. The resultant external torque (the vector sum of all external torques) acting on the body must be zero about any origin. These conditions can be written as equations: F = 0 = 0 where the

More information

Q.1 a) any six of the following 6x2= 12. i) Define - ( Each term 01 mark)

Q.1 a) any six of the following 6x2= 12. i) Define - ( Each term 01 mark) Important Instructions to examiners: 1) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. 2) The model answer and the answer written by candidate

More information