CAMBRIDGE UNIVERSITY ENGINEERING DEPARTMENT. PART IA (First Year) Paper 4 : Mathematical Methods

Size: px
Start display at page:

Download "CAMBRIDGE UNIVERSITY ENGINEERING DEPARTMENT. PART IA (First Year) Paper 4 : Mathematical Methods"

Transcription

1 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young CMBRIDGE UNIVERSITY ENGINEERING DEPRTMENT PRT I (Frst Yer) Pper 4 : Mthemtl Methods Leture ourse : Fst Mths Course, Letures 8 Leturer : Prof. J. B. Young Shedule : Weeks 4, Mhelms 009 Reommended ook : Jmes G. Modern Engneerng Mthemts. rd Edton. ddson Wesley. 00.

2 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young

3 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young VECTOR LGEBR Vetor fundmentls. Defnton nd s rules of mnpulton. Emples of vetors. Representng vetors n omponent form Vetor multplton. The slr produt. The vetor produt. The slr trple produt.4 The vetor trple produt Vetor representton of lnes nd plnes. Strght lnes n D. Plnes 4 Vetors nd mtres 4. Mtr-vetor multplton 4. The trnspose of mtr 4. The determnnt of mtr 4.4 Slr nd vetor produts s mtr opertons 4.5 Smultneous equtons nd the nverse of mtr Referene : Jmes G., Modern Engneerng Mthemts, Chpters & 4 to 4.4.

4 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young

5 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young VECTOR FUNDMENTLS. Defnton nd s rules of mnpulton In mehns, Newton s Seond Lw s wrtten F m, mplyng tht when ody of mss m s ted on y fore F the ody eperenes n elerton n the sme dreton s the fore. Ths notton s fne so long s we re delng wth prolem n one sptl dmenson. When fed wth rel-world D prolem, however, we requre three slr equtons reltng the omponents of the fore n the three rtesn dretons (F, F y, F z ) to the orrespondng omponents of the elerton (, y, z ) : F m, Fy my, Fz mz. Vetor methods hve een developed s shorthnd so tht the three slr equtons n e repled y sngle vetor equton reltng the vetor fore F to the vetor elerton : F m Of ourse, the ppltons of vetor lger re not restrted to mehns. For our purposes, we tke the defnton of vetor s follows : Vetors re qunttes possessng oth mgntude nd dreton whh oey the prllelogrm rule of ddton. The prllelogrm rule s equvlent to ddng the vetors nose to tl so n prte t s eser to work n terms of trngle rule of ddton :

6 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young Severl vetors n e dded geometrlly y suessve ppltons of the trngle rule : Vetors re sutrted y ddng the negtve of the relevnt vetor : ( ). Thus, f nd re the sme vetors s n the dgrms ove : Vetors, lke slrs, oey the followng lger rules : ( ) ( ) k ( ) k k (where k s ny slr onstnt) In these notes : Vetors wll e represented y uprght old type : The mgntude of vetor wll e represented y pr of vertl lnes : vetor of unt length wll e represented y ret ^ : â s unt vetor prllel to. Two or more vetors whh re perpendulr to eh other re sd to e orthogonl. Orthogonl vetors of unt length re sd to e orthonorml. The vetors,, k re understood to e unt vetors n the dretons of the, y, z es of rght-hnded rtesn oordnte system.

7 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young. Emples of vetors () Poston reltve to spefed orgn. z r y The poston vetor r, llustrted wth respet to rtesn oordnte system. () Lner dsplement. Dsplements n e dded usng the trngle lw : km E km N km S Resultnt dsplement () Lner veloty nd lner elerton. (v) ngulr veloty nd ngulr elerton. The ngulr veloty vetor ω of rottng ody s the vetor whose : mgntude equls the ody s rte of rotton (e.g., n rdns per seond), nd dreton s tht n whh rght-hnd srew wth the sme spn s the ody would move through sttonry ork. ω v ω θ r O r snθ Vew wth vetor ω omng out of the pge Note tht v ω r snθ

8 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young (v) Fore. Fores n e dded usng the trngle lw. (v) The moment of fore. The vetor moment M of vetor fore F ppled t pont r out n orgn O s the vetor whose : mgntude equls the moment out O, nd dreton s tht n whh rght-hnd srew would move f twsted y the moment. Vetor moment M hs mgntude θ M F r sn θ O r F nd dreton nto the pge. (v) The dfferentl re on surfe. The dfferentl vetor re d s vetor whose : mgntude equls the re d of dfferentl element on the surfe, nd dreton s norml to, nd outwrd from, the sde of the surfe defned s postve. d d Qunttes tht hve mgntude nd dreton ut do not oey the prllelogrm lw re not vetors. For emple, the fnte ngulr rotton of ody s not vetor. Ths s euse the pplton of fnte rotton θ out the s followed y fnte rotton θ out the z s, sy, gves dfferent result from rotton θ out the z s followed y rotton θ out the s. However, the resultnt of two nfntesml rottons dθ nd dθ s ndependent of the order of pplton so tht ngulr velotes (of mgntude dθ /dt nd dθ /dt) do dd vetorlly (nd so ngulr veloty s vetor). It s mportnt to pprete tht the mgntude nd dreton of vetor s ndependent of the oordnte system used to desre t. Ths s the gret dvntge of workng wth vetors. For emple, the sttement s ompletely ndependent of ny oordnte system. Ths mens tht we n mnpulte vetors usng the rules of vetor lger wthout spefyng oordnte system. It s only when we ome to the stge of nsertng numerl vlues tht s t neessry to hoose oordnte system. 4

9 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young. Representng vetors n omponent form We n epress the mgntude nd dreton of vetor numerlly wth respet to ny hosen o-ordnte system. For rtesn system, we set up mutully perpendulr es, y nd z, nd defne, nd k to e vetors of unt length long the es. vetor n then e epressed s lner omnton of the vetors, nd k : k z y, nd re lled the omponents of. These lone re suffent to spefy the vetor one the oordnte es hve een defned, so s often represented y, or (,, ). The onventon s to use rght-hnded set of es, otned s follows. Drw es nd ( nd y) t rght ngles n plne. Drw s (z) norml to the plne n the dreton rght-hnded srew would move were s rotted to le on top of s. It wll now e found tht s s n the dreton rght-hnded srew would move f s were rotted to le on top of s. Smlrly, s s n the dreton rght-hnded srew would move f s were rotted to le on top of s. Note the yl order : rotted to gves, rotted to gves, rotted to gves. ddton of vetors s omplshed y ddng omponents. Thus, ) ( ) ( ) k ( or, lterntvely, or, more omptly, (,, ) 5

10 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young VECTOR MULTIPLICTION. The slr produt The slr produt of two vetors nd s wrtten where θ s the nluded ngle. os θ nd s defned y, θ The slr produt n e thought of s : The mgntude of multpled y the omponent of n the dreton of, or The mgntude of multpled y the omponent of n the dreton of. In formng the slr produt, we tke two vetors nd end up wth slr ( sngle numer). It n e seen from the defnton tht the order of the vetors does not mtter, lso, the slr produt oeys the so-lled dstrutve lw,. ( ) If nd re orthogonl, os θ 0 so 0. If nd re prllel, os θ so. If nd re nt-prllel, os θ so. The unt vetors n rtesn oordntes therefore oey the followng reltonshps : k k k k 0 6

11 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young 7 If we epress the vetors nd n rtesn form nd multply out, we otn, z z y y z y z y ) ( ) ( k k In prtulr, ) ( ) ( z y z y z y k k It s very esy to form the slr produt numerlly s shown y ths emple : ) ( ) ( 4) ( 4 The slr produt s n nvrnt. Ths mens t tkes the sme vlue whtever oordnte system s used. If, n the ove emple, we hd deded to use D polr rther thn rtesn oordntes, the omponents of nd would e dfferent ut the slr produt would stll e. s physl emple of the use of the slr produt suppose vetor fore F moves ody vetor dstne d, not neessrly n the sme dreton s the fore : The omponent of F prllel to the dreton of moton does work on the ody ut the norml omponent mkes no ontruton. Hene, the work done y the fore s, W F os θ d F d θ F d

12 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young. The vetor produt The vetor produt of two vetors nd (wrtten ross ) s defned to e vetor whose mgntude s gven y sn θ or nd pronouned where θ s the nluded ngle etween the vetors (suh tht θ < 80 when the tls of the vetors re mde to onde). The dreton of s perpendulr to oth nd, suh tht f we rotte to le on top of, the dreton of moton of rght-hnded srew s n the dreton of. θ In formng the vetor produt we tke two vetors nd otn nother vetor. It n e seen from the defnton tht the order of the vetors s mportnt nd tht, Lke the slr produt, the vetor produt oeys the dstrutve lw, ( ) If nd re orthogonl, sn θ so. If nd re prllel or nt-prllel, sn θ 0 so 0. The unt vetors n rtesn oordntes oey the followng reltonshps : k, k, k k, k, k 0, 0, k k 0 8

13 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young 9 Epressng the vetors nd n rtesn omponents nd multplyng out, we otn, ) ) k ( k ( k - ( - ( - ( ) ) ) Lke the slr produt, the vetor produt s nvrnt; ts vlue does not depend on the oordnte system used. In the ove form, the rtesn epnson for s qute dffult to rememer. The result n e found n the mthemts dt ook ut the esest wy of gettng the rtesn omponents orret s to rememer the representton of s determnnt (see lter f you don t know wht determnnt s) : k k k - ( - ( - ( ) ) ) The followng re emples of the use of the vetor produt : () The vetor re of prllelogrm : The mgntude of the re of the prllelogrm s sn θ. The vetor re (dreton out of the pge) s, (The order s mportnt) θ vetor re

14 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young () The vetor moment of fore : Moment out O s requred d r θ F Pont of pplton of fore O The mgntude of the moment out O of the fore F, ppled t pont on the ody defned y the poston vetor r, s M F r sn θ. The vetor moment (dreton nto the pge) s, M r F (The order s mportnt) () The veloty t pont n rottng ody : ω v O θ r ω r snθ When ody rottes wth ngulr veloty ω s shown, the mgntude of the veloty t the pont spefed y the poston vetor r s v ω r sn θ. The vetor veloty (dreton s shown) s, v ω r (The order s mportnt) 0

15 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young. The slr trple produt φ The prllelepped shown ove s defned y the three vetors, nd. The re of the se s (wth dreton upwrds ). The volume V of the prllelepped ( postve slr quntty) s therefore, V os φ ( ) ( ) s known s the slr trple produt. In ft, the rkets re unneessry s the epresson ould not e evluted n ny other wy. The volume n e evluted usng ny two of the vetors to form the se. Hene, we dedue tht hngng the vetors round n yl order does not hnge the vlue of the slr trple produt euse, ( ) ( ) ( ) V Chngng the yl order, however, hnges the sgn of the slr trple produt, From the ove reltonshps we otn, ( ) ( ) ( ) V ( ) ( ) ( ) whh shows tht we n nterhnge the nd the n slr trple produt wthout ffetng the vlue. Beuse of ths, the slr trple produt s sometmes wrtten [,,] s there n e no mguty. Note tht [,,] 0 f the three vetors re oplnr (the prllelepped volume s zero).

16 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young.4 The vetor trple produt The other possle omnton of three vetors s the vetor trple produt, ( ). The result of ths operton gves vetor whh s orthogonl to the vetors nd. We n derve n mportnt vetor dentty for smplfyng lultons where the vetor trple produt ppers. We do ths y onsderng the (or ) omponent n rtesn epnson : [ ( ) ] ( ) ( ) ( - ) ( - ) ( ) ( ) ( ) ( ) [( ) ( )] Note the lever trk n lne 4 where ws oth dded nd sutrted. The sme result s otned for the nd omponents (y symmetry), nd hene we otn the dentty : ( ) ( ) ( ) If, nsted, the frst two vetors re rketed, we esly fnd tht, ( ) ( ) ( ) ( ) s n emple of vetor mnpulton, we smplfy the epresson ( ) ( ) : ( ) ( ) ( ) (defnng ) ( ) (nterhngng the nd the ) [ ( )] [( ) ( )] (usng the vetor trple produt dentty) ( ) ( ) ( ) ( ) tully, n prte, t s rther eser to wrte, ( ) ( ) sn θ ( os θ) (!)

17 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young VECTOR REPRESENTTION OF LINES ND PLNES. Strght lnes n D z ( ) r y Two seprte ponts defne strght lne n D spe. Let nd e the poston vetors of the two known ponts nd let r e the poston vetor of generl pont on the lne. The vetor equton of the lne s then, r λ( ) where λ s slr prmeter. When λ 0, r, nd when λ, r. By hoosng vlues of λ etween nd, every pont on the lne s otned. If t (for tngentl) s unt vetor n the dreton of the lne, then the ove equton n e wrtten, r µ t where µ s dfferent slr prmeter (unless hppens to equl t). Note tht lnes n lwys e represented n terms of ust one slr prmeter. The vetor equton for lne s relly three slr equtons rolled nto one. To fnd the slr rtesn form, we deompose the vetor equton y wrtng, λ( ) y λ( ) z λ( ) more ompt wy of presentng these equtons s, y z ( )

18 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young z r y nother wy of wrtng the vetor equton of lne s, r where, s shown n the dgrm, s vetor tngentl to the lne nd s prtulr vetor norml to the lne (whh then defnes the lne). To onvne yourself tht the ove equton relly does represent lne, note tht the poston vetor of pont on the lne must stsfy, Equtng the two epressons for nd usng the dstrutve property of the vetor produt n reverse, we fnd, (r ) 0 Hene, (r ) s vetor prllel to nd so we n wrte r λ whh s the equton of lne, n the dreton of, pssng through the pont defned y the poston vetor. 4

19 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young. Plnes ( ) µ ( ) ( ) r λ ( ) O Three ponts defne plne so long s they do not le on sngle strght lne. If, nd re the poston vetors of the three known ponts, then t n e seen from the dgrm tht the poston vetor r of generl pont on the plne s gven y, r λ( ) µ( ) where λ nd µ re slr prmeters tht n tke ny vlues etween nd. Note tht plnes n lwys e spefed n terms of two slr prmeters. n (r ) d O r n lterntve form of the vetor equton for plne n e otned n terms of vetor n norml to the plne. s n e seen from the dgrm the equton s, (r ) n 0 Epndng n slr form, we otn the well-known rtesn equton for plne, n n y n z n If n s unt norml vetor ( n n n ), t n e seen from the dgrm tht the slr produt n d represents the perpendulr dstne d of the orgn O from the plne. 5

20 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young Two plnes defne lne unless they re prllel : Suppose we hve two plnes defned y the equtons r p nd r q. By omprson wth the generl equton, we see tht nd re vetors norml to the plnes (not unt vetors, neessrly). The lne of nterseton wll therefore e prllel to the vetor nd n e wrtten, r λ ( ) where s the poston vetor of ny pont lyng on the lne nd λ s slr prmeter. Note tht f the vetor produt 0 the two normls re n the sme dreton so the plnes re prllel nd do not nterset. Furthermore, f, p q the plnes re one nd the sme; nsted of lne, we hve plne of nterseton. Three plnes defne pont unless ther normls re oplnr : The pont of nterseton of three plnes n e found y solvng the three smultneous equtons, r p, r q nd r s. In rtesn omponent form, these re : y z p y z q y z s 6

21 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young Geometrlly, we epet unque soluton ( sngle pont of nterseton) unless : () The plnes re ll prllel ut seprte, so there s no nterseton, or () The plnes re ll the sme, so there s plne of nterseton, or () The three plnes nterset long sngle lne, so there s lne of nterseton, or (v) Two plnes re prllel, so there s no ommon nterseton, see elow, or (v) We get Tolerone stuton, see elow, so there s no ommon nterseton. In ll these spel ses, the normls to the three plnes n e moved so tht they re oplnr. Therefore, the volume of the prllelepped they form s zero. Hene, we n reognse the spel ses euse 0. 7

22 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young 4 VECTORS ND MTRICES 4. Mtr-vetor multplton The most generl wy n whh the omponents of vetor n e trnsformed y lner opertons nto the omponents of vetor s s follows : where, et re onstnt oeffents. In settng up shorthnd notton to epress these reltonshps, we defne the mtr s the rry of oeffents : n lso e wrtten where (,, ) enumertes the rows nd (,, ) the olumns. n esy wy of rememerng how the susrpts hnge s provded y the mnemon : Wrtng the vetors nd n olumn formt (.e., s mtres), we defne mtrvetor multplton so tht, In order to stsfy these equltes, the th omponent of the olumn vetor must e otned y multplyng the th row of the mtr y the olumn vetor n the sense tht, The mtr s sd to operte on the vetor to gve the vetor. Wth the understndng tht mtr-vetor multplton s mpled, we n now wrte, 8

23 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young 4. The trnspose of mtr The trnspose t of mtr s defned to e mtr n whh rows nd olumns re nterhnged (row of eomes olumn of t nd so on). Thus, t or t slr n e thought of s mtr, so t trnsposes nto tself, λ t λ. vetor s usully thought of s mtr, lthough ths s only onventon. If we need the omponents set out s row, we smply wrte the vetor s t, t ( ) Ths s the sme vetor ut epressed n dfferent wy. 4. The determnnt of mtr Every squre mtr hs numer ssoted wth t lled determnnt, wrtten or sometmes det. One gn, ths s done s onvenent shorthnd notton. The determnnt of mtr s defned s, The determnnt of mtr s then gven y, The determnnts re otned y rossng out the frst row nd eh olumn n turn of the orgnl mtr. They re lled the mnors of the determnnt. Wth the relevnt sgn n front (,, ) they re lled the oftors. The representton ove s lled epnson out the frst row. In ft, determnnt n e epnded out ny row or olumn so long s proper ttenton s gven to the sgns. 9

24 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young When the determnnts re multpled out, we fnd, ( ) ( ) ( ) ( ) ( ) Note the rght-hnded yl order n the frst rket nd the left-hnded yl order n the seond rket. n esy wy of otnng ths epresson s to wrte out the mtr wth the frst nd seond olumns repeted : d d d d4 d5 d6 * * * * * * * * * * * * * * * The vlue of the determnnt s then the sum of the three produts of the three numers down the dgonls, d, d, d, mnus the sum of the three produts of the three numers down the dgonls d4, d5, d Slr nd vetor produts s mtr opertons In order to epress the slr produt s the operton of mtr on vetor, we trnspose the frst vetor nto mtr. Thus, Note tht, t ( ) t t Epressng the vetor produt s the operton of mtr on vetor s rther more omplted. Thus,

25 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young Note tht the determnnt of ths mtr s zero so the mtr hs no nverse. Hene, gven the vetor nd the vetor produt we nnot solve for. One onsequene of ths s tht f, we nnot ssume tht. smlr stuton ests for slr produts. If nd re equl, we nnot ssume tht. s mentoned erler, the vetor produt n lso e epressed s determnnt : k k Ths leds us on to prove tht the slr trple produt n lso e epressed s determnnt : ( ) k k ( k) k It hs lredy een shown tht s the volume of the prllelepped formed y the vetors, nd, nd tht the sgn s hnged f we swp nd. From ths we dedue the rule for determnnts tht f two rows (or two olumns) re swpped, the sgn of the determnnt hnges. On the other hnd, yl permutton of rows nd olumns leves the vlue of determnnt unhnged. 4.5 Smultneous equtons nd the nverse of mtr So fr, the mtr hs een presented s wy of representng three lner equtons reltng eh omponent of vetor to the omponents of nother vetor. More generlly, however, ny set of three lner equtons n e wrtten n mtr notton. For emple, the equtons desrng the nterseton of three plnes ( r p, r q nd r s) re, y z p y z q y z s

26 Engneerng Prt I 009-0, Pper 4, Mthemtl Methods, Fst Course, J.B.Young In mtr form these re wrtten, z y s q p Formlly, we n otn the poston vetor of the pont of nterseton ( y z) t y fndng the nverse of the mtr nd usng t to operte on the vetor (p q s) t. Thus, z y s q p Ths proedure ssumes tht the mtr relly does hve n nverse. However, f the normls to the three plnes re oplnr, the volume of the prllelepped formed s zero, 0. But lso equls the determnnt of the mtr nd so we dedue tht f the determnnt of mtr s zero the nverse does not est. It s mportnt to note tht the equton nvolvng the nverse represents the forml soluton to the orgnl mtr equton. In prte, one never tully solves set of smultneous equtons y lultng the nverse of the mtr, prtulrly on omputer. Rther one uses muh more effent numerl tehnque suh s Gussn elmnton. s n emple, we hek to see f the followng equtons hve unque soluton : The equtons n e wrtten, Usng the dgonl multplton trk for lultng the determnnt of the mtr, we fnd, [ 0 6 ( ) 4 9 ] [9 0 4 ( ) 6] 0 So the nverse of the mtr does not est nd there s no unque soluton to the equtons.

VECTORS VECTORS VECTORS VECTORS. 2. Vector Representation. 1. Definition. 3. Types of Vectors. 5. Vector Operations I. 4. Equal and Opposite Vectors

VECTORS VECTORS VECTORS VECTORS. 2. Vector Representation. 1. Definition. 3. Types of Vectors. 5. Vector Operations I. 4. Equal and Opposite Vectors 1. Defnton A vetor s n entt tht m represent phsl quntt tht hs mgntude nd dreton s opposed to slr tht ls dreton.. Vetor Representton A vetor n e represented grphll n rrow. The length of the rrow s the mgntude

More information

Abhilasha Classes Class- XII Date: SOLUTION (Chap - 9,10,12) MM 50 Mob no

Abhilasha Classes Class- XII Date: SOLUTION (Chap - 9,10,12) MM 50 Mob no hlsh Clsses Clss- XII Dte: 0- - SOLUTION Chp - 9,0, MM 50 Mo no-996 If nd re poston vets of nd B respetvel, fnd the poston vet of pont C n B produed suh tht C B vet r C B = where = hs length nd dreton

More information

Learning Enhancement Team

Learning Enhancement Team Lernng Enhnement Tem Worsheet: The Cross Produt These re the model nswers for the worsheet tht hs questons on the ross produt etween vetors. The Cross Produt study gude. z x y. Loong t mge, you n see tht

More information

Lecture 7 Circuits Ch. 27

Lecture 7 Circuits Ch. 27 Leture 7 Cruts Ch. 7 Crtoon -Krhhoff's Lws Tops Dret Current Cruts Krhhoff's Two ules Anlyss of Cruts Exmples Ammeter nd voltmeter C ruts Demos Three uls n rut Power loss n trnsmsson lnes esstvty of penl

More information

Review of linear algebra. Nuno Vasconcelos UCSD

Review of linear algebra. Nuno Vasconcelos UCSD Revew of lner lgebr Nuno Vsconcelos UCSD Vector spces Defnton: vector spce s set H where ddton nd sclr multplcton re defned nd stsf: ) +( + ) (+ )+ 5) λ H 2) + + H 6) 3) H, + 7) λ(λ ) (λλ ) 4) H, - + 8)

More information

ESCI 342 Atmospheric Dynamics I Lesson 1 Vectors and Vector Calculus

ESCI 342 Atmospheric Dynamics I Lesson 1 Vectors and Vector Calculus ESI 34 tmospherc Dnmcs I Lesson 1 Vectors nd Vector lculus Reference: Schum s Outlne Seres: Mthemtcl Hndbook of Formuls nd Tbles Suggested Redng: Mrtn Secton 1 OORDINTE SYSTEMS n orthonorml coordnte sstem

More information

Rank One Update And the Google Matrix by Al Bernstein Signal Science, LLC

Rank One Update And the Google Matrix by Al Bernstein Signal Science, LLC Introducton Rnk One Updte And the Google Mtrx y Al Bernsten Sgnl Scence, LLC www.sgnlscence.net here re two dfferent wys to perform mtrx multplctons. he frst uses dot product formulton nd the second uses

More information

1.3 SCALARS AND VECTORS

1.3 SCALARS AND VECTORS Bridge Course Phy I PUC 24 1.3 SCLRS ND VECTORS Introdution: Physis is the study of nturl phenomen. The study of ny nturl phenomenon involves mesurements. For exmple, the distne etween the plnet erth nd

More information

Tutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4.

Tutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4. Mth 5 Tutoril Week 1 - Jnury 1 1 Nme Setion Tutoril Worksheet 1. Find ll solutions to the liner system by following the given steps x + y + z = x + y + z = 4. y + z = Step 1. Write down the rgumented mtrix

More information

ME 501A Seminar in Engineering Analysis Page 1

ME 501A Seminar in Engineering Analysis Page 1 More oundr-vlue Prolems nd genvlue Prolems n Os ovemer 9, 7 More oundr-vlue Prolems nd genvlue Prolems n Os Lrr retto Menl ngneerng 5 Semnr n ngneerng nlss ovemer 9, 7 Outlne Revew oundr-vlue prolems Soot

More information

7.2 Volume. A cross section is the shape we get when cutting straight through an object.

7.2 Volume. A cross section is the shape we get when cutting straight through an object. 7. Volume Let s revew the volume of smple sold, cylnder frst. Cylnder s volume=se re heght. As llustrted n Fgure (). Fgure ( nd (c) re specl cylnders. Fgure () s rght crculr cylnder. Fgure (c) s ox. A

More information

COMPLEX NUMBER & QUADRATIC EQUATION

COMPLEX NUMBER & QUADRATIC EQUATION MCQ COMPLEX NUMBER & QUADRATIC EQUATION Syllus : Comple numers s ordered prs of rels, Representton of comple numers n the form + nd ther representton n plne, Argnd dgrm, lger of comple numers, modulus

More information

Matrices SCHOOL OF ENGINEERING & BUILT ENVIRONMENT. Mathematics (c) 1. Definition of a Matrix

Matrices SCHOOL OF ENGINEERING & BUILT ENVIRONMENT. Mathematics (c) 1. Definition of a Matrix tries Definition of tri mtri is regulr rry of numers enlosed inside rkets SCHOOL OF ENGINEERING & UIL ENVIRONEN Emple he following re ll mtries: ), ) 9, themtis ), d) tries Definition of tri Size of tri

More information

Trigonometry. Trigonometry. Solutions. Curriculum Ready ACMMG: 223, 224, 245.

Trigonometry. Trigonometry. Solutions. Curriculum Ready ACMMG: 223, 224, 245. Trgonometry Trgonometry Solutons Currulum Redy CMMG:, 4, 4 www.mthlets.om Trgonometry Solutons Bss Pge questons. Identfy f the followng trngles re rght ngled or not. Trngles,, d, e re rght ngled ndted

More information

INTRODUCTION TO COMPLEX NUMBERS

INTRODUCTION TO COMPLEX NUMBERS INTRODUCTION TO COMPLEX NUMBERS The numers -4, -3, -, -1, 0, 1,, 3, 4 represent the negtve nd postve rel numers termed ntegers. As one frst lerns n mddle school they cn e thought of s unt dstnce spced

More information

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the

More information

" = #N d$ B. Electromagnetic Induction. v ) $ d v % l. Electromagnetic Induction and Faraday s Law. Faraday s Law of Induction

 = #N d$ B. Electromagnetic Induction. v ) $ d v % l. Electromagnetic Induction and Faraday s Law. Faraday s Law of Induction Eletromgnet Induton nd Frdy s w Eletromgnet Induton Mhel Frdy (1791-1867) dsoered tht hngng mgnet feld ould produe n eletr urrent n ondutor pled n the mgnet feld. uh urrent s lled n ndued urrent. The phenomenon

More information

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then. pril 8, 2017 Mth 9 Geometry Solving vetor prolems Prolem Prove tht if vetors nd stisfy, then Solution 1 onsider the vetor ddition prllelogrm shown in the Figure Sine its digonls hve equl length,, the prllelogrm

More information

Physics for Scientists and Engineers I

Physics for Scientists and Engineers I Phscs for Scentsts nd Engneers I PHY 48, Secton 4 Dr. Betr Roldán Cuen Unverst of Centrl Flord, Phscs Deprtment, Orlndo, FL Chpter - Introducton I. Generl II. Interntonl Sstem of Unts III. Converson of

More information

Module 3: Element Properties Lecture 5: Solid Elements

Module 3: Element Properties Lecture 5: Solid Elements Modue : Eement Propertes eture 5: Sod Eements There re two s fmes of three-dmenson eements smr to two-dmenson se. Etenson of trngur eements w produe tetrhedrons n three dmensons. Smr retngur preeppeds

More information

CISE 301: Numerical Methods Lecture 5, Topic 4 Least Squares, Curve Fitting

CISE 301: Numerical Methods Lecture 5, Topic 4 Least Squares, Curve Fitting CISE 3: umercl Methods Lecture 5 Topc 4 Lest Squres Curve Fttng Dr. Amr Khouh Term Red Chpter 7 of the tetoo c Khouh CISE3_Topc4_Lest Squre Motvton Gven set of epermentl dt 3 5. 5.9 6.3 The reltonshp etween

More information

e a = 12.4 i a = 13.5i h a = xi + yj 3 a Let r a = 25cos(20) i + 25sin(20) j b = 15cos(55) i + 15sin(55) j

e a = 12.4 i a = 13.5i h a = xi + yj 3 a Let r a = 25cos(20) i + 25sin(20) j b = 15cos(55) i + 15sin(55) j Vetors MC Qld-3 49 Chapter 3 Vetors Exerse 3A Revew of vetors a d e f e a x + y omponent: x a os(θ 6 os(80 + 39 6 os(9.4 omponent: y a sn(θ 6 sn(9 0. a.4 0. f a x + y omponent: x a os(θ 5 os( 5 3.6 omponent:

More information

Things to Memorize: A Partial List. January 27, 2017

Things to Memorize: A Partial List. January 27, 2017 Things to Memorize: A Prtil List Jnury 27, 2017 Chpter 2 Vectors - Bsic Fcts A vector hs mgnitude (lso clled size/length/norm) nd direction. It does not hve fixed position, so the sme vector cn e moved

More information

SECTION A STUDENT MATERIAL. Part 1. What and Why.?

SECTION A STUDENT MATERIAL. Part 1. What and Why.? SECTION A STUDENT MATERIAL Prt Wht nd Wh.? Student Mteril Prt Prolem n > 0 n > 0 Is the onverse true? Prolem If n is even then n is even. If n is even then n is even. Wht nd Wh? Eploring Pure Mths Are

More information

Reference : Croft & Davison, Chapter 12, Blocks 1,2. A matrix ti is a rectangular array or block of numbers usually enclosed in brackets.

Reference : Croft & Davison, Chapter 12, Blocks 1,2. A matrix ti is a rectangular array or block of numbers usually enclosed in brackets. I MATRIX ALGEBRA INTRODUCTION TO MATRICES Referene : Croft & Dvison, Chpter, Blos, A mtri ti is retngulr rr or lo of numers usull enlosed in rets. A m n mtri hs m rows nd n olumns. Mtri Alger Pge If the

More information

LECTURE 2 1. THE SPACE RELATED PROPRIETIES OF PHYSICAL QUANTITIES

LECTURE 2 1. THE SPACE RELATED PROPRIETIES OF PHYSICAL QUANTITIES LECTURE. THE SPCE RELTED PROPRIETIES OF PHYSICL QUNTITIES Phss uses phsl prmeters. In ths urse ne wll del nl wth slr nd vetr prmeters. Slr prmeters d nt depend n the spe dretn. Vetr prmeters depend n spe

More information

VECTOR ALGEBRA. Syllabus :

VECTOR ALGEBRA. Syllabus : MV VECTOR ALGEBRA Syllus : Vetors nd Slrs, ddition of vetors, omponent of vetor, omponents of vetor in two dimensions nd three dimensionl spe, slr nd vetor produts, slr nd vetor triple produt. Einstein

More information

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique? XII. LINEAR ALGEBRA: SOLVING SYSTEMS OF EQUATIONS Tody we re going to tlk out solving systems of liner equtions. These re prolems tht give couple of equtions with couple of unknowns, like: 6= x + x 7=

More information

6 Roots of Equations: Open Methods

6 Roots of Equations: Open Methods HK Km Slghtly modfed 3//9, /8/6 Frstly wrtten t Mrch 5 6 Roots of Equtons: Open Methods Smple Fed-Pont Iterton Newton-Rphson Secnt Methods MATLAB Functon: fzero Polynomls Cse Study: Ppe Frcton Brcketng

More information

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL: PYTHAGORAS THEOREM 1 WHAT S IN CHAPTER 1? 1 01 Squres, squre roots nd surds 1 02 Pythgors theorem 1 03 Finding the hypotenuse 1 04 Finding shorter side 1 05 Mixed prolems 1 06 Testing for right-ngled tringles

More information

6.5 Improper integrals

6.5 Improper integrals Eerpt from "Clulus" 3 AoPS In. www.rtofprolemsolving.om 6.5. IMPROPER INTEGRALS 6.5 Improper integrls As we ve seen, we use the definite integrl R f to ompute the re of the region under the grph of y =

More information

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point GCSE C Emple 7 Work out 9 Give your nswer in its simplest form Numers n inies Reiprote mens invert or turn upsie own The reiprol of is 9 9 Mke sure you only invert the frtion you re iviing y 7 You multiply

More information

1 4 6 is symmetric 3 SPECIAL MATRICES 3.1 SYMMETRIC MATRICES. Defn: A matrix A is symmetric if and only if A = A, i.e., a ij =a ji i, j. Example 3.1.

1 4 6 is symmetric 3 SPECIAL MATRICES 3.1 SYMMETRIC MATRICES. Defn: A matrix A is symmetric if and only if A = A, i.e., a ij =a ji i, j. Example 3.1. SPECIAL MATRICES SYMMETRIC MATRICES Def: A mtr A s symmetr f d oly f A A, e,, Emple A s symmetr Def: A mtr A s skew symmetr f d oly f A A, e,, Emple A s skew symmetr Remrks: If A s symmetr or skew symmetr,

More information

INSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad

INSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad INSTITUTE OF AERONAUTICAL ENGINEERING Dundgl, Hyderbd - 5 3 FRESHMAN ENGINEERING TUTORIAL QUESTION BANK Nme : MATHEMATICS II Code : A6 Clss : II B. Te II Semester Brn : FRESHMAN ENGINEERING Yer : 5 Fulty

More information

MATHEMATICS II PUC VECTOR ALGEBRA QUESTIONS & ANSWER

MATHEMATICS II PUC VECTOR ALGEBRA QUESTIONS & ANSWER MATHEMATICS II PUC VECTOR ALGEBRA QUESTIONS & ANSWER I One M Queston Fnd the unt veto n the deton of Let ˆ ˆ 9 Let & If Ae the vetos & equl? But vetos e not equl sne the oespondng omponents e dstnt e detons

More information

Jens Siebel (University of Applied Sciences Kaiserslautern) An Interactive Introduction to Complex Numbers

Jens Siebel (University of Applied Sciences Kaiserslautern) An Interactive Introduction to Complex Numbers Jens Sebel (Unversty of Appled Scences Kserslutern) An Interctve Introducton to Complex Numbers 1. Introducton We know tht some polynoml equtons do not hve ny solutons on R/. Exmple 1.1: Solve x + 1= for

More information

K 7. Quadratic Equations. 1. Rewrite these polynomials in the form ax 2 + bx + c = 0. Identify the values of a, b and c:

K 7. Quadratic Equations. 1. Rewrite these polynomials in the form ax 2 + bx + c = 0. Identify the values of a, b and c: Qudrti Equtions The Null Ftor Lw Let's sy there re two numers nd. If # = then = or = (or oth re ) This mens tht if the produt of two epressions is zero, then t lest one of the epressions must e equl to

More information

Project 6: Minigoals Towards Simplifying and Rewriting Expressions

Project 6: Minigoals Towards Simplifying and Rewriting Expressions MAT 51 Wldis Projet 6: Minigols Towrds Simplifying nd Rewriting Expressions The distriutive property nd like terms You hve proly lerned in previous lsses out dding like terms ut one prolem with the wy

More information

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e Green s Theorem. Let be the boundry of the unit squre, y, oriented ounterlokwise, nd let F be the vetor field F, y e y +, 2 y. Find F d r. Solution. Let s write P, y e y + nd Q, y 2 y, so tht F P, Q. Let

More information

REGULARIZATION IN QUANTUM GAUGE THEORY OF GRAVITATION WITH DE SITTER INNER SYMMETRY

REGULARIZATION IN QUANTUM GAUGE THEORY OF GRAVITATION WITH DE SITTER INNER SYMMETRY THEORETICAL PHYSICS REGULARIZATION IN QUANTUM GAUGE THEORY OF GRAVITATION WITH DE SITTER INNER SYMMETRY V. CHIRIÞOIU 1, G. ZET 1 Poltehn Unversty Tmºor, Tehnl Physs Deprtment, Romn E-ml: vorel.hrtou@et.upt.ro

More information

2 a Mythili Publishers, Karaikkudi

2 a Mythili Publishers, Karaikkudi Wnglsh Tuton Centre Puduvl + Mths Q & A Mthl Pulshers Krud. 8000 PROVE BY FACTOR METHOD OF DETERMINANTS. ). ). ). ). ) 6. ) ) ) ). ) ) 8. ) 9 ) 9. 8 0. 0 Solve ) PROPERTIES OF DETERMINANTS. 0 / / /. 0.

More information

12.4 Similarity in Right Triangles

12.4 Similarity in Right Triangles Nme lss Dte 12.4 Similrit in Right Tringles Essentil Question: How does the ltitude to the hpotenuse of right tringle help ou use similr right tringles to solve prolems? Eplore Identifing Similrit in Right

More information

Analytically, vectors will be represented by lowercase bold-face Latin letters, e.g. a, r, q.

Analytically, vectors will be represented by lowercase bold-face Latin letters, e.g. a, r, q. 1.1 Vector Alger 1.1.1 Sclrs A physicl quntity which is completely descried y single rel numer is clled sclr. Physiclly, it is something which hs mgnitude, nd is completely descried y this mgnitude. Exmples

More information

GAUSS ELIMINATION. Consider the following system of algebraic linear equations

GAUSS ELIMINATION. Consider the following system of algebraic linear equations Numercl Anlyss for Engneers Germn Jordnn Unversty GAUSS ELIMINATION Consder the followng system of lgebrc lner equtons To solve the bove system usng clsscl methods, equton () s subtrcted from equton ()

More information

Chapter Newton-Raphson Method of Solving a Nonlinear Equation

Chapter Newton-Raphson Method of Solving a Nonlinear Equation Chpter.4 Newton-Rphson Method of Solvng Nonlner Equton After redng ths chpter, you should be ble to:. derve the Newton-Rphson method formul,. develop the lgorthm of the Newton-Rphson method,. use the Newton-Rphson

More information

Vectors. a Write down the vector AB as a column vector ( x y ). A (3, 2) x point C such that BC = 3. . Go to a OA = a

Vectors. a Write down the vector AB as a column vector ( x y ). A (3, 2) x point C such that BC = 3. . Go to a OA = a Streth lesson: Vetors Streth ojetives efore you strt this hpter, mrk how onfident you feel out eh of the sttements elow: I n lulte using olumn vetors nd represent the sum nd differene of two vetors grphilly.

More information

5. Every rational number have either terminating or repeating (recurring) decimal representation.

5. Every rational number have either terminating or repeating (recurring) decimal representation. CHAPTER NUMBER SYSTEMS Points to Rememer :. Numer used for ounting,,,,... re known s Nturl numers.. All nturl numers together with zero i.e. 0,,,,,... re known s whole numers.. All nturl numers, zero nd

More information

Least squares. Václav Hlaváč. Czech Technical University in Prague

Least squares. Václav Hlaváč. Czech Technical University in Prague Lest squres Václv Hlváč Czech echncl Unversty n Prgue hlvc@fel.cvut.cz http://cmp.felk.cvut.cz/~hlvc Courtesy: Fred Pghn nd J.P. Lews, SIGGRAPH 2007 Course; Outlne 2 Lner regresson Geometry of lest-squres

More information

CENTROID (AĞIRLIK MERKEZİ )

CENTROID (AĞIRLIK MERKEZİ ) CENTOD (ĞLK MEKEZİ ) centrod s geometrcl concept rsng from prllel forces. Tus, onl prllel forces possess centrod. Centrod s tougt of s te pont were te wole wegt of pscl od or sstem of prtcles s lumped.

More information

Lecture 2e Orthogonal Complement (pages )

Lecture 2e Orthogonal Complement (pages ) Lecture 2e Orthogonl Complement (pges -) We hve now seen tht n orthonorml sis is nice wy to descrie suspce, ut knowing tht we wnt n orthonorml sis doesn t mke one fll into our lp. In theory, the process

More information

Effects of polarization on the reflected wave

Effects of polarization on the reflected wave Lecture Notes. L Ros PPLIED OPTICS Effects of polrzton on the reflected wve Ref: The Feynmn Lectures on Physcs, Vol-I, Secton 33-6 Plne of ncdence Z Plne of nterfce Fg. 1 Y Y r 1 Glss r 1 Glss Fg. Reflecton

More information

Proof that if Voting is Perfect in One Dimension, then the First. Eigenvector Extracted from the Double-Centered Transformed

Proof that if Voting is Perfect in One Dimension, then the First. Eigenvector Extracted from the Double-Centered Transformed Proof tht f Votng s Perfect n One Dmenson, then the Frst Egenvector Extrcted from the Doule-Centered Trnsformed Agreement Score Mtrx hs the Sme Rn Orderng s the True Dt Keth T Poole Unversty of Houston

More information

Principle Component Analysis

Principle Component Analysis Prncple Component Anlyss Jng Go SUNY Bufflo Why Dmensonlty Reducton? We hve too mny dmensons o reson bout or obtn nsghts from o vsulze oo much nose n the dt Need to reduce them to smller set of fctors

More information

Equations and Inequalities

Equations and Inequalities Equtions nd Inequlities Equtions nd Inequlities Curriculum Redy ACMNA: 4, 5, 6, 7, 40 www.mthletics.com Equtions EQUATIONS & Inequlities & INEQUALITIES Sometimes just writing vribles or pronumerls in

More information

GRAND PLAN. Visualizing Quaternions. I: Fundamentals of Quaternions. Andrew J. Hanson. II: Visualizing Quaternion Geometry. III: Quaternion Frames

GRAND PLAN. Visualizing Quaternions. I: Fundamentals of Quaternions. Andrew J. Hanson. II: Visualizing Quaternion Geometry. III: Quaternion Frames Visuliing Quternions Andrew J. Hnson Computer Siene Deprtment Indin Universit Siggrph Tutoril GRAND PLAN I: Fundmentls of Quternions II: Visuliing Quternion Geometr III: Quternion Frmes IV: Clifford Algers

More information

Linear Algebra Introduction

Linear Algebra Introduction Introdution Wht is Liner Alger out? Liner Alger is rnh of mthemtis whih emerged yers k nd ws one of the pioneer rnhes of mthemtis Though, initilly it strted with solving of the simple liner eqution x +

More information

DCDM BUSINESS SCHOOL NUMERICAL METHODS (COS 233-8) Solutions to Assignment 3. x f(x)

DCDM BUSINESS SCHOOL NUMERICAL METHODS (COS 233-8) Solutions to Assignment 3. x f(x) DCDM BUSINESS SCHOOL NUMEICAL METHODS (COS -8) Solutons to Assgnment Queston Consder the followng dt: 5 f() 8 7 5 () Set up dfference tble through fourth dfferences. (b) Wht s the mnmum degree tht n nterpoltng

More information

Section 1.3 Triangles

Section 1.3 Triangles Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior

More information

FUNDAMENTALS ON ALGEBRA MATRICES AND DETERMINANTS

FUNDAMENTALS ON ALGEBRA MATRICES AND DETERMINANTS Dol Bgyoko (0 FUNDAMENTALS ON ALGEBRA MATRICES AND DETERMINANTS Introducton Expressons of the form P(x o + x + x + + n x n re clled polynomls The coeffcents o,, n re ndependent of x nd the exponents 0,,,

More information

GM1 Consolidation Worksheet

GM1 Consolidation Worksheet Cmridge Essentils Mthemtis Core 8 GM1 Consolidtion Worksheet GM1 Consolidtion Worksheet 1 Clulte the size of eh ngle mrked y letter. Give resons for your nswers. or exmple, ngles on stright line dd up

More information

COMPLEX NUMBERS INDEX

COMPLEX NUMBERS INDEX COMPLEX NUMBERS INDEX. The hstory of the complex numers;. The mgnry unt I ;. The Algerc form;. The Guss plne; 5. The trgonometrc form;. The exponentl form; 7. The pplctons of the complex numers. School

More information

Improper Integrals. The First Fundamental Theorem of Calculus, as we ve discussed in class, goes as follows:

Improper Integrals. The First Fundamental Theorem of Calculus, as we ve discussed in class, goes as follows: Improper Integrls The First Fundmentl Theorem of Clculus, s we ve discussed in clss, goes s follows: If f is continuous on the intervl [, ] nd F is function for which F t = ft, then ftdt = F F. An integrl

More information

2.4 Linear Inequalities and Interval Notation

2.4 Linear Inequalities and Interval Notation .4 Liner Inequlities nd Intervl Nottion We wnt to solve equtions tht hve n inequlity symol insted of n equl sign. There re four inequlity symols tht we will look t: Less thn , Less thn or

More information

Mathematics. Area under Curve.

Mathematics. Area under Curve. Mthemtics Are under Curve www.testprepkrt.com Tle of Content 1. Introduction.. Procedure of Curve Sketching. 3. Sketching of Some common Curves. 4. Are of Bounded Regions. 5. Sign convention for finding

More information

Vectors and Tensors. R. Shankar Subramanian. R. Aris, Vectors, Tensors, and the Equations of Fluid Mechanics, Prentice Hall (1962).

Vectors and Tensors. R. Shankar Subramanian. R. Aris, Vectors, Tensors, and the Equations of Fluid Mechanics, Prentice Hall (1962). 005 Vectors nd Tensors R. Shnkr Subrmnn Good Sources R. rs, Vectors, Tensors, nd the Equtons of Flud Mechncs, Prentce Hll (96). nd ppendces n () R. B. Brd, W. E. Stewrt, nd E. N. Lghtfoot, Trnsport Phenomen,

More information

Proving the Pythagorean Theorem

Proving the Pythagorean Theorem Proving the Pythgoren Theorem W. Bline Dowler June 30, 2010 Astrt Most people re fmilir with the formul 2 + 2 = 2. However, in most ses, this ws presented in lssroom s n solute with no ttempt t proof or

More information

m A 1 1 A ! and AC 6

m A 1 1 A ! and AC 6 REVIEW SET A Using sle of m represents units, sketh vetor to represent: NON-CALCULATOR n eroplne tking off t n ngle of 8 ± to runw with speed of 6 ms displement of m in north-esterl diretion. Simplif:

More information

ragsdale (zdr82) HW6 ditmire (58335) 1 the direction of the current in the figure. Using the lower circuit in the figure, we get

ragsdale (zdr82) HW6 ditmire (58335) 1 the direction of the current in the figure. Using the lower circuit in the figure, we get rgsdle (zdr8) HW6 dtmre (58335) Ths prnt-out should hve 5 questons Multple-choce questons my contnue on the next column or pge fnd ll choces efore nswerng 00 (prt of ) 00 ponts The currents re flowng n

More information

Trigonometry Revision Sheet Q5 of Paper 2

Trigonometry Revision Sheet Q5 of Paper 2 Trigonometry Revision Sheet Q of Pper The Bsis - The Trigonometry setion is ll out tringles. We will normlly e given some of the sides or ngles of tringle nd we use formule nd rules to find the others.

More information

PART 1: VECTOR & TENSOR ANALYSIS

PART 1: VECTOR & TENSOR ANALYSIS PART : VECTOR & TENSOR ANALYSIS wth LINEAR ALGEBRA Obectves Introduce the concepts, theores, nd opertonl mplementton of vectors, nd more generlly tensors, n dvnced engneerng nlyss. The emphss s on geometrc

More information

Factorising FACTORISING.

Factorising FACTORISING. Ftorising FACTORISING www.mthletis.om.u Ftorising FACTORISING Ftorising is the opposite of expning. It is the proess of putting expressions into rkets rther thn expning them out. In this setion you will

More information

INTRODUCTION TO LINEAR ALGEBRA

INTRODUCTION TO LINEAR ALGEBRA ME Applied Mthemtics for Mechnicl Engineers INTRODUCTION TO INEAR AGEBRA Mtrices nd Vectors Prof. Dr. Bülent E. Pltin Spring Sections & / ME Applied Mthemtics for Mechnicl Engineers INTRODUCTION TO INEAR

More information

y z A left-handed system can be rotated to look like the following. z

y z A left-handed system can be rotated to look like the following. z Chpter 2 Crtesin Coördintes The djetive Crtesin bove refers to René Desrtes (1596 1650), who ws the first to oördintise the plne s ordered pirs of rel numbers, whih provided the first sstemti link between

More information

Chapter Newton-Raphson Method of Solving a Nonlinear Equation

Chapter Newton-Raphson Method of Solving a Nonlinear Equation Chpter 0.04 Newton-Rphson Method o Solvng Nonlner Equton Ater redng ths chpter, you should be ble to:. derve the Newton-Rphson method ormul,. develop the lgorthm o the Newton-Rphson method,. use the Newton-Rphson

More information

Chapter 9 Definite Integrals

Chapter 9 Definite Integrals Chpter 9 Definite Integrls In the previous chpter we found how to tke n ntiderivtive nd investigted the indefinite integrl. In this chpter the connection etween ntiderivtives nd definite integrls is estlished

More information

Concept of Activity. Concept of Activity. Thermodynamic Equilibrium Constants [ C] [ D] [ A] [ B]

Concept of Activity. Concept of Activity. Thermodynamic Equilibrium Constants [ C] [ D] [ A] [ B] Conept of Atvty Equlbrum onstnt s thermodynm property of n equlbrum system. For heml reton t equlbrum; Conept of Atvty Thermodynm Equlbrum Constnts A + bb = C + dd d [C] [D] [A] [B] b Conentrton equlbrum

More information

Fall 2012 Analysis of Experimental Measurements B. Eisenstein/rev. S. Errede. with respect to λ. 1. χ λ χ λ ( ) λ, and thus:

Fall 2012 Analysis of Experimental Measurements B. Eisenstein/rev. S. Errede. with respect to λ. 1. χ λ χ λ ( ) λ, and thus: More on χ nd errors : uppose tht we re fttng for sngle -prmeter, mnmzng: If we epnd The vlue χ ( ( ( ; ( wth respect to. χ n Tlor seres n the vcnt of ts mnmum vlue χ ( mn χ χ χ χ + + + mn mnmzes χ, nd

More information

New Algorithms: Linear, Nonlinear, and Integer Programming

New Algorithms: Linear, Nonlinear, and Integer Programming New Algorthms: ner, Nonlner, nd Integer Progrmmng Dhnnjy P. ehendle Sr Prshurmhu College, Tl Rod, Pune-400, Ind dhnnjy.p.mehendle@gml.om Astrt In ths pper we propose new lgorthm for lner progrmmng. Ths

More information

TOPIC: LINEAR ALGEBRA MATRICES

TOPIC: LINEAR ALGEBRA MATRICES Interntionl Blurete LECTUE NOTES for FUTHE MATHEMATICS Dr TOPIC: LINEA ALGEBA MATICES. DEFINITION OF A MATIX MATIX OPEATIONS.. THE DETEMINANT deta THE INVESE A -... SYSTEMS OF LINEA EQUATIONS. 8. THE AUGMENTED

More information

Trigonometry. Trigonometry. Curriculum Ready ACMMG: 223, 224, 245.

Trigonometry. Trigonometry. Curriculum Ready ACMMG: 223, 224, 245. Trgonometry Trgonometry Currulum Rey ACMMG: 223, 22, 2 www.mthlets.om Trgonometry TRIGONOMETRY Bslly, mny stutons n the rel worl n e relte to rght ngle trngle. Trgonometry souns ffult, ut t s relly just

More information

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique? XII. LINEAR ALGEBRA: SOLVING SYSTEMS OF EQUATIONS Tody we re going to tlk bout solving systems of liner equtions. These re problems tht give couple of equtions with couple of unknowns, like: 6 2 3 7 4

More information

CARLETON UNIVERSITY. 1.0 Problems and Most Solutions, Sect B, 2005

CARLETON UNIVERSITY. 1.0 Problems and Most Solutions, Sect B, 2005 RLETON UNIVERSIT eprtment of Eletronis ELE 2607 Swithing iruits erury 28, 05; 0 pm.0 Prolems n Most Solutions, Set, 2005 Jn. 2, #8 n #0; Simplify, Prove Prolem. #8 Simplify + + + Reue to four letters (literls).

More information

Definition of Tracking

Definition of Tracking Trckng Defnton of Trckng Trckng: Generte some conclusons bout the moton of the scene, objects, or the cmer, gven sequence of mges. Knowng ths moton, predct where thngs re gong to project n the net mge,

More information

Quiz: Experimental Physics Lab-I

Quiz: Experimental Physics Lab-I Mxmum Mrks: 18 Totl tme llowed: 35 mn Quz: Expermentl Physcs Lb-I Nme: Roll no: Attempt ll questons. 1. In n experment, bll of mss 100 g s dropped from heght of 65 cm nto the snd contner, the mpct s clled

More information

Lectures - Week 4 Matrix norms, Conditioning, Vector Spaces, Linear Independence, Spanning sets and Basis, Null space and Range of a Matrix

Lectures - Week 4 Matrix norms, Conditioning, Vector Spaces, Linear Independence, Spanning sets and Basis, Null space and Range of a Matrix Lectures - Week 4 Matrx norms, Condtonng, Vector Spaces, Lnear Independence, Spannng sets and Bass, Null space and Range of a Matrx Matrx Norms Now we turn to assocatng a number to each matrx. We could

More information

Section 8.3 Polar Form of Complex Numbers

Section 8.3 Polar Form of Complex Numbers 80 Chapter 8 Secton 8 Polar Form of Complex Numbers From prevous classes, you may have encountered magnary numbers the square roots of negatve numbers and, more generally, complex numbers whch are the

More information

Logarithms LOGARITHMS.

Logarithms LOGARITHMS. Logrithms LOGARITHMS www.mthletis.om.u Logrithms LOGARITHMS Logrithms re nother method to lulte nd work with eponents. Answer these questions, efore working through this unit. I used to think: In the

More information

Probability. b a b. a b 32.

Probability. b a b. a b 32. Proility If n event n hppen in '' wys nd fil in '' wys, nd eh of these wys is eqully likely, then proility or the hne, or its hppening is, nd tht of its filing is eg, If in lottery there re prizes nd lnks,

More information

Announcements. Image Formation: Outline. The course. Image Formation and Cameras (cont.)

Announcements. Image Formation: Outline. The course. Image Formation and Cameras (cont.) nnouncements Imge Formton nd Cmers (cont.) ssgnment : Cmer & Lenses, gd Trnsformtons, nd Homogrph wll be posted lter tod. CSE 5 Lecture 5 CS5, Fll CS5, Fll CS5, Fll The course rt : The phscs of mgng rt

More information

PHYSICS 212 MIDTERM II 19 February 2003

PHYSICS 212 MIDTERM II 19 February 2003 PHYSICS 1 MIDERM II 19 Feruary 003 Exam s losed ook, losed notes. Use only your formula sheet. Wrte all work and answers n exam ooklets. he aks of pages wll not e graded unless you so request on the front

More information

x=0 x=0 Positive Negative Positions Positions x=0 Positive Negative Positions Positions

x=0 x=0 Positive Negative Positions Positions x=0 Positive Negative Positions Positions Knemtc Quntte Lner Moton Phyc 101 Eyre Tme Intnt t Fundmentl Tme Interl Defned Poton x Fundmentl Dplcement Defned Aerge Velocty g Defned Aerge Accelerton g Defned Knemtc Quntte Scler: Mgntude Tme Intnt,

More information

Introduction to Olympiad Inequalities

Introduction to Olympiad Inequalities Introdution to Olympid Inequlities Edutionl Studies Progrm HSSP Msshusetts Institute of Tehnology Snj Simonovikj Spring 207 Contents Wrm up nd Am-Gm inequlity 2. Elementry inequlities......................

More information

CHENG Chun Chor Litwin The Hong Kong Institute of Education

CHENG Chun Chor Litwin The Hong Kong Institute of Education PE-hing Mi terntionl onferene IV: novtion of Mthemtis Tehing nd Lerning through Lesson Study- onnetion etween ssessment nd Sujet Mtter HENG hun hor Litwin The Hong Kong stitute of Edution Report on using

More information

Chapter 2. Vectors. 2.1 Vectors Scalars and Vectors

Chapter 2. Vectors. 2.1 Vectors Scalars and Vectors Chpter 2 Vectors 2.1 Vectors 2.1.1 Sclrs nd Vectors A vector is quntity hving both mgnitude nd direction. Emples of vector quntities re velocity, force nd position. One cn represent vector in n-dimensionl

More information

VECTORS AND TENSORS IV.1.1. INTRODUCTION

VECTORS AND TENSORS IV.1.1. INTRODUCTION Chpter IV Vector nd Tensor Anlyss IV. Vectors nd Tensors Septemer 5, 08 05 IV. VECTORS AND TENSORS IV... INTRODUCTION In mthemtcs nd mechncs, we he to operte wth qunttes whch requre dfferent mthemtcl ojects

More information

4. Eccentric axial loading, cross-section core

4. Eccentric axial loading, cross-section core . Eccentrc xl lodng, cross-secton core Introducton We re strtng to consder more generl cse when the xl force nd bxl bendng ct smultneousl n the cross-secton of the br. B vrtue of Snt-Vennt s prncple we

More information

Algebra Basics. Algebra Basics. Curriculum Ready ACMNA: 133, 175, 176, 177, 179.

Algebra Basics. Algebra Basics. Curriculum Ready ACMNA: 133, 175, 176, 177, 179. Curriulum Redy ACMNA: 33 75 76 77 79 www.mthletis.om Fill in the spes with nything you lredy know out Alger Creer Opportunities: Arhitets eletriins plumers et. use it to do importnt lultions. Give this

More information

MCA-205: Mathematics II (Discrete Mathematical Structures)

MCA-205: Mathematics II (Discrete Mathematical Structures) MCA-05: Mthemts II (Dsrete Mthemtl Strutures) Lesson No: I Wrtten y Pnkj Kumr Lesson: Group theory - I Vette y Prof. Kulp Sngh STRUCTURE.0 OBJECTIVE. INTRODUCTION. SOME DEFINITIONS. GROUP.4 PERMUTATION

More information

AP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals

AP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals AP Clulus BC Chpter 8: Integrtion Tehniques, L Hopitl s Rule nd Improper Integrls 8. Bsi Integrtion Rules In this setion we will review vrious integrtion strtegies. Strtegies: I. Seprte the integrnd into

More information

Applied Statistics Qualifier Examination

Applied Statistics Qualifier Examination Appled Sttstcs Qulfer Exmnton Qul_june_8 Fll 8 Instructons: () The exmnton contns 4 Questons. You re to nswer 3 out of 4 of them. () You my use ny books nd clss notes tht you mght fnd helpful n solvng

More information