Convection and conduction and lumped models

Size: px
Start display at page:

Download "Convection and conduction and lumped models"

Transcription

1 MIT Hea ranfer Dynamc mdel 4.3./SG nvecn and cndcn and lmped mdel. Hea cnvecn If we have a rface wh he emperare and a rrndng fld wh he emperare a where a hgher han we have a hea flw a Φ h [W] () where he area f he rface and h he ceffcen f hea ranfer. a h Fgre : Hea cnvecn If he rrndng fld crclaed by a fan r pmp we are alkng f frced cnvecn. If he fld mn a rel f byancy frce, we are alkng f free (r naral) cnvecn. The hery fr he calclan f he ceffcen f hea ranfer he man bjec f he dcplne f Hea Tranfer. gd nrdcn can be een n Hea and Ma Tranfer by Incrpera and DeW, Wley,. Fr many prpe ne can e emaed vale - ypcal vale are gven n able : Prce h [W/(m K)] Free cnvecn Gae -5 Lqd 5- Frced cnvecn Gae 5-5 Lqd - Table : Typcal vale f he cnvecn hea ranfer ceffcen. Hea cndcn nder a ld cylnder a hwn n fgre. he ne end he emperare kep n and n he her end a and >. The rd nlaed n de,.e. hea nly ranmed n he hrnal drecn, frm he h end he clder end. k L Fgre : Hea cndcn n a ld cylnder (r fla plae wh hckne L)

2 MIT Hea ranfer Dynamc mdel 4.3./SG The hea flw can be calclaed a k Φ [W] () L where k he ceffcen f cndcvy fr he maeral ed, L he lengh and he cr ecnal area f he cylnder. Typcal vale fr k gven n able Maeral k [W/(m K)] Mneral fber.3-.5 Wd.-.6 Sanle Seel 3- Seel 4-6 lmnm bber 33 Table : Typcal vale f he cnvecn hea ranfer ceffcen 3. Thermal reance we wll ee laer n h paper cnvenen make an analgy elecrc crc. Eqan () can be rewren Φ a [W] (3) cnv where cnv he cnvecve reance hea ranfer. Y mgh remember Ohm Law ayng ha Vlage = eance me rren r U =. Or = U/ whch he ame a (3) f we be he hea flw wh he elecrc crren, he vlage drp by he emperare drp and he elecrc reance by he hermal reance. h cnv [K/W] (4) Fr cnvecn we have cnv = /(h ).e. he hgher h and/r he lwer reance, whch gve meanng. Fr he hea cndcn prblem we can make he ame analgy gvng he reance hea ranfer by cndcn L k cnd [K/W] (5) We wll e h analgy laer draw eqvalen hermal crc wh lmped capacance and reance elemen. 4. Mlple lmped parameer mdel Nw le ry cmbne he w prncple, ncldng he law f energy balance:

3 MIT Hea ranfer Dynamc mdel /SG Fgre 3 hw a mdel f a dble wall nlaed n he pace beween he w hermal heavy brck wall. h h Fgre 3: Dble wall (belw: n elecrc mdel f he wall) The elecrc analgy hw ha he prblem can be lked lke an elecrc crc wh 3 reance and w capacr We nw ame, ha he emperare n he w brck wall are alm even drbed, e. hee w wall can be lked lke lmped. Energy balance fr he nner wall, n. gve: Φ Φ (6) where Φ h (7) k Φ (8) ρ (9) c Energy balance fr he er wall, n. gve: Φ Φ () where Φ h () () ρ c Thee eqan can be lved n Smlnk, ee fgre 4

4 MIT Hea ranfer Dynamc mdel /SG Fgre 4: Mdel f he dble wall [ ] PHI [W] 3 Pl f emperare Pl hea flw me, a [h] PHI PHI PHI Fgre 5: el, baed n nal emperare = Daa fr he mdel: h_ = 8; % [W/(mK)] ef. f hea ranfer, nner h_ = ; % [W/(mK)] ef. f hea ranfer, er = ; % [m] rea k =.5; % [W/(m*K)] ef. f hea cndcn =.; % [m] Thckne, nlan _ = ; % [ ] Inner emperare _ = ; % [ ] Oer emperare c_ = 88; % [J/(kgK)] Spec. hea cap., nner wall c_ = 88; % [J/(kgK)] Spec. hea cap., er wall rh_ = 45; % [kg/m3] Deny, nner wall rh_ = 45; % [kg/m3] Deny, er wall _ =.; % [m] Thckne, nner wall _ =.; % [m] Thckne, er wall m_ m_ =rh_*_*; % [J/K] Hea capacy, nner wall =rh_*_*; % [J/K] Hea capacy, er wall n=; % Inal emperare, nner wall n=; % Inal emperare, er wall The ln f a gven nal vale prblem hwn n fgre Sae-Space frmlan pecal way f preenng he eqan called ae pace. On vecr frm lk lke h x x B y x D The bld ymbl ndcae array r marce

5 MIT Hea ranfer Dynamc mdel /SG Her x =, a clmn vecr repreenng he emperaren n he fve ne. a w dmennal vecr repreenng he amben emperare g. The y vecr an p vecr here he w emperare. Ung he example abve, wh he fve ne, we ge: If we defne h and k and h Then we have frm (6) (9) and frm () (): Then and B l n hen and D In h frmlan he Smlnk mdel mple: Fgre 6: Sae-Space frmlan

6 MIT Hea ranfer Dynamc mdel /SG The cnen n he Sae-Space blck a fllw _ = -(/(_*_)+/(_*_)); _ = /(_*_); _ = /(_*_); _ = -(/(_*_)+/(_*_)); B_ = /(_*_); B_ = ; B_ = ; B_ = /(_*_); =[ ; ] B =[B_ B_; B_ B_] =[ ; ] D =[ ; ] % Spdaa: mme =5*36; m('m wall', mme) fgre() h=pl(a/36, (:,), 'r-',a/36, (:,), 'b-'); e(h,'lnewdh',) grd % æer grd ax([-nf nf 3]) xlabel('a [h]') ylabel(' [ ]') legend('_','_') Pl % Sae-Space frmlan % 3.3./SG cle all clear clc 3 5 h_ = 8; % [W/(mK)] ef. f hea ranfer, nner h_ = ; % [W/(mK)] ef. f hea ranfer, er = ; % [m] rea k =.5; % [W/(m*K)] ef. f hea cndcn =.; % [m] Thckne, nlan _ = ; % [ ] Inner emperare _ = ; % [ ] Oer emperare c_ = 88; % [J/(kgK)] Spec. hea cap., nner wall c_ = 88; % [J/(kgK)] Spec. hea cap., er wall rh_ = 45; % [kg/m3] Deny, nner wall rh_ = 45; % [kg/m3] Deny, er wall _ =.; % [m] Thckne, nner wall _ =.; % [m] Thckne, er wall [ ] a [h] m_ m _ =rh_*_*; % [J/K] Hea capacy, nner wall =rh_*_*; % [J/K] Hea capacy, er wall = c_*m_; % [J/K] Hea capacy, nner wall = c_*m_; % [J/K] Hea capacy, er wall _ = /(h_*); % [K/W] Thermal reance, nner cnvecn _ = /(k*); % [K/W] Thermal reance, nlan _ = /(h_*); % [K/W] Thermal reance, er cnvecn n=; % Inal emperare, nner wall n=; % Inal emperare, er wall

a. (1) Assume T = 20 ºC = 293 K. Apply Equation 2.22 to find the resistivity of the brass in the disk with

a. (1) Assume T = 20 ºC = 293 K. Apply Equation 2.22 to find the resistivity of the brass in the disk with Aignmen #5 EE7 / Fall 0 / Aignmen Sluin.7 hermal cnducin Cnider bra ally wih an X amic fracin f Zn. Since Zn addiin increae he number f cnducin elecrn, we have cale he final ally reiiviy calculaed frm

More information

Energy Storage Devices

Energy Storage Devices Energy Srage Deces Objece f ecure Descrbe The cnsrucn f an nducr Hw energy s sred n an nducr The elecrcal prperes f an nducr Relanshp beween lage, curren, and nducance; pwer; and energy Equalen nducance

More information

Dishonest casino as an HMM

Dishonest casino as an HMM Dshnes casn as an HMM N = 2, ={F,L} M=2, O = {h,} A = F B= [. F L F L 0.95 0.0 0] h 0.5 0. L 0.05 0.90 0.5 0.9 c Deva ubramanan, 2009 63 A generave mdel fr CpG slands There are w hdden saes: CpG and nn-cpg.

More information

R th is the Thevenin equivalent at the capacitor terminals.

R th is the Thevenin equivalent at the capacitor terminals. Chaper 7, Slun. Applyng KV Fg. 7.. d 0 C - Takng he derae f each erm, d 0 C d d d r C Inegrang, () ln I 0 - () I 0 e - C C () () r - I 0 e - () V 0 e C C Chaper 7, Slun. h C where h s he Theenn equalen

More information

Problem 1 Known: Dimensions and materials of the composition wall, 10 studs each with 2.5m high

Problem 1 Known: Dimensions and materials of the composition wall, 10 studs each with 2.5m high Prblem Knwn: Dimensins and materials f the cmpsitin wall, 0 studs each with.5m high Unknwn:. Thermal resistance assciate with wall when surfaces nrmal t the directin f heat flw are isthermal. Thermal resistance

More information

The Components of Vector B. The Components of Vector B. Vector Components. Component Method of Vector Addition. Vector Components

The Components of Vector B. The Components of Vector B. Vector Components. Component Method of Vector Addition. Vector Components Upcming eens in PY05 Due ASAP: PY05 prees n WebCT. Submiing i ges yu pin ward yur 5-pin Lecure grade. Please ake i seriusly, bu wha cuns is wheher r n yu submi i, n wheher yu ge hings righ r wrng. Due

More information

Cooling of a hot metal forging. , dt dt

Cooling of a hot metal forging. , dt dt Tranen Conducon Uneady Analy - Lumped Thermal Capacy Model Performed when; Hea ranfer whn a yem produced a unform emperaure drbuon n he yem (mall emperaure graden). The emperaure change whn he yem condered

More information

Lecture 4 ( ) Some points of vertical motion: Here we assumed t 0 =0 and the y axis to be vertical.

Lecture 4 ( ) Some points of vertical motion: Here we assumed t 0 =0 and the y axis to be vertical. Sme pins f erical min: Here we assumed and he y axis be erical. ( ) y g g y y y y g dwnwards 9.8 m/s g Lecure 4 Accelerain The aerage accelerain is defined by he change f elciy wih ime: a ; In analgy,

More information

Kinematics Review Outline

Kinematics Review Outline Kinemaics Review Ouline 1.1.0 Vecrs and Scalars 1.1 One Dimensinal Kinemaics Vecrs have magniude and direcin lacemen; velciy; accelerain sign indicaes direcin + is nrh; eas; up; he righ - is suh; wes;

More information

Different kind of oscillation

Different kind of oscillation PhO 98 Theorecal Qeson.Elecrcy Problem (8 pons) Deren knd o oscllaon e s consder he elecrc crc n he gre, or whch mh, mh, nf, nf and kω. The swch K beng closed he crc s copled wh a sorce o alernang crren.

More information

2015 Sectional Physics Exam Solution Set

2015 Sectional Physics Exam Solution Set . Crrec answer: D Ne: [quan] denes: uns quan WYSE cadec Challenge 05 Secnal Phscs Ea SOLUTION SET / / / / rce lengh lengh rce enu ass lengh e a) / ass ass b) energ c) wrk lengh e pwer energ e d) (crrec

More information

10.7 Temperature-dependent Viscoelastic Materials

10.7 Temperature-dependent Viscoelastic Materials Secin.7.7 Temperaure-dependen Viscelasic Maerials Many maerials, fr example plymeric maerials, have a respnse which is srngly emperaure-dependen. Temperaure effecs can be incrpraed in he hery discussed

More information

D Solute mass diffusivity ( m ) D Mass diffusivity ( m s ) Gc Pr. Sc Sr Re g. q Radiative heat flux. U Reference velocity ( m s )

D Solute mass diffusivity ( m ) D Mass diffusivity ( m s ) Gc Pr. Sc Sr Re g. q Radiative heat flux. U Reference velocity ( m s ) ISSN (e): 5 35 Vlme 7 Isse 6 Jne 7 Inernanal Jrnal f mpanal Engneerng Research (IJER) Nare f assn Fld n ransen Free nvecn Fl Pas ards an Implsvel Sared Vercall Inclned Plae: hermal Dffsn and agnec Feld

More information

Physic 231 Lecture 33

Physic 231 Lecture 33 Physc 231 Lecture 33 Man pnts f tday s lecture: eat and heat capacty: Q cm Phase transtns and latent heat: Q Lm ( ) eat flw Q k 2 1 t L Examples f heat cnductvty, R values fr nsulatrs Cnvectn R L / k Radatn

More information

Solution in semi infinite diffusion couples (error function analysis)

Solution in semi infinite diffusion couples (error function analysis) Soluon n sem nfne dffuson couples (error funcon analyss) Le us consder now he sem nfne dffuson couple of wo blocks wh concenraon of and I means ha, n a A- bnary sysem, s bondng beween wo blocks made of

More information

Notes on Inductance and Circuit Transients Joe Wolfe, Physics UNSW. Circuits with R and C. τ = RC = time constant

Notes on Inductance and Circuit Transients Joe Wolfe, Physics UNSW. Circuits with R and C. τ = RC = time constant Nes n Inducance and cu Tansens Je Wlfe, Physcs UNSW cus wh and - Wha happens when yu clse he swch? (clse swch a 0) - uen flws ff capac, s d Acss capac: Acss ess: c d s d d ln + cns. 0, ln cns. ln ln ln

More information

(V 1. (T i. )- FrC p. ))= 0 = FrC p (T 1. (T 1s. )+ UA(T os. (T is

(V 1. (T i. )- FrC p. ))= 0 = FrC p (T 1. (T 1s. )+ UA(T os. (T is . Yu are repnible fr a reacr in which an exhermic liqui-phae reacin ccur. The fee mu be preheae he hrehl acivain emperaure f he caaly, bu he pruc ream mu be cle. T reuce uiliy c, yu are cniering inalling

More information

Module 4. Analysis of Statically Indeterminate Structures by the Direct Stiffness Method. Version 2 CE IIT, Kharagpur

Module 4. Analysis of Statically Indeterminate Structures by the Direct Stiffness Method. Version 2 CE IIT, Kharagpur Mdle Analysis f Saically Indeerminae Srcres by he Direc Siffness Mehd Versin CE IIT, Kharagr Lessn The Direc Siffness Mehd: Temerare Changes and Fabricain Errrs in Trss Analysis Versin CE IIT, Kharagr

More information

A Demand System for Input Factors when there are Technological Changes in Production

A Demand System for Input Factors when there are Technological Changes in Production A Demand Syem for Inpu Facor when here are Technologcal Change n Producon Movaon Due o (e.g.) echnologcal change here mgh no be a aonary relaonhp for he co hare of each npu facor. When emang demand yem

More information

Online Supplement for Dynamic Multi-Technology. Production-Inventory Problem with Emissions Trading

Online Supplement for Dynamic Multi-Technology. Production-Inventory Problem with Emissions Trading Onlne Supplemen for Dynamc Mul-Technology Producon-Invenory Problem wh Emssons Tradng by We Zhang Zhongsheng Hua Yu Xa and Baofeng Huo Proof of Lemma For any ( qr ) Θ s easy o verfy ha he lnear programmng

More information

In the complete model, these slopes are ANALYSIS OF VARIANCE FOR THE COMPLETE TWO-WAY MODEL. (! i+1 -! i ) + [(!") i+1,q - [(!

In the complete model, these slopes are ANALYSIS OF VARIANCE FOR THE COMPLETE TWO-WAY MODEL. (! i+1 -! i ) + [(!) i+1,q - [(! ANALYSIS OF VARIANCE FOR THE COMPLETE TWO-WAY MODEL The frs hng o es n wo-way ANOVA: Is here neracon? "No neracon" means: The man effecs model would f. Ths n urn means: In he neracon plo (wh A on he horzonal

More information

Energy & Work

Energy & Work rk Dne by a Cntant Frce 6.-6.4 Energy & rk F N m jule () J rk Dne by a Cntant Frce Example Pullng a Sutcae-n-heel Fnd the wrk dne the rce 45.0-N, the angle 50.0 degree, and the dplacement 75.0 m. 3 ( F

More information

SPH3U1 Lesson 06 Kinematics

SPH3U1 Lesson 06 Kinematics PROJECTILE MOTION LEARNING GOALS Students will: Describe the mtin f an bject thrwn at arbitrary angles thrugh the air. Describe the hrizntal and vertical mtins f a prjectile. Slve prjectile mtin prblems.

More information

2010 Sectional Physics Solution Set

2010 Sectional Physics Solution Set . Crrec nwer: D WYSE CDEMIC CHLLENGE Secnl hyc E 00 Slun Se y 0 y 4.0 / 9.8 /.45 y. Crrec nwer: y 8 0 / 8 /. Crrec nwer: E y y 0 ( 4 / ) ( 4.9 / ) 5.6 y y 4. Crrec nwer: E 5. Crrec nwer: The e rce c n

More information

Square law expression is non linear between I D and V GS. Need to operate in appropriate region for linear behaviour. W L

Square law expression is non linear between I D and V GS. Need to operate in appropriate region for linear behaviour. W L MOS Feld-Effec Trassrs (MOSFETs ecure # 4 MOSFET as a Amplfer k ( S Square law express s lear bewee ad. Need perae apprprae reg fr lear behaur. Cpyrgh 004 by Oxfrd Uersy Press, c. MOSFET as a Amplfer S

More information

Subject: Turbojet engines (continued); Design parameters; Effect of mass flow on thrust.

Subject: Turbojet engines (continued); Design parameters; Effect of mass flow on thrust. 16.50 Leure 19 Subje: Turbje engines (ninued; Design parameers; Effe f mass flw n hrus. In his haper we examine he quesin f hw hse he key parameers f he engine bain sme speified perfrmane a he design ndiins,

More information

Graduate Macroeconomics 2 Problem set 5. - Solutions

Graduate Macroeconomics 2 Problem set 5. - Solutions Graduae Macroeconomcs 2 Problem se. - Soluons Queson 1 To answer hs queson we need he frms frs order condons and he equaon ha deermnes he number of frms n equlbrum. The frms frs order condons are: F K

More information

( )a = "t = 1 E =" B E = 5016 V. E = BHv # 3. 2 %r. c.) direction of induced current in the loop for : i.) "t < 1

( )a = t = 1 E = B E = 5016 V. E = BHv # 3. 2 %r. c.) direction of induced current in the loop for : i.) t < 1 99 3 c dr b a µ r.? d b µ d d cdr a r & b d & µ c µ c b dr µ c µ c b & ' ln' a +*+* b ln r ln a a r a ' µ c b 'b* µ c ln' * & ln, &a a+ ncreang no he page o nduced curren wll creae a - feldou of he page

More information

Physics 20 Lesson 9H Rotational Kinematics

Physics 20 Lesson 9H Rotational Kinematics Phyc 0 Len 9H Ranal Knemac In Len 1 9 we learned abu lnear mn knemac and he relanhp beween dplacemen, velcy, acceleran and me. In h len we wll learn abu ranal knemac. The man derence beween he w ype mn

More information

PRINCE SULTAN UNIVERSITY Department of Mathematical Sciences Final Examination Second Semester (072) STAT 271.

PRINCE SULTAN UNIVERSITY Department of Mathematical Sciences Final Examination Second Semester (072) STAT 271. PRINCE SULTAN UNIVERSITY Deparmen f Mahemaical Sciences Final Examinain Secnd Semeser 007 008 (07) STAT 7 Suden Name Suden Number Secin Number Teacher Name Aendance Number Time allwed is ½ hurs. Wrie dwn

More information

5.1 Angles and Their Measure

5.1 Angles and Their Measure 5. Angles and Their Measure Secin 5. Nes Page This secin will cver hw angles are drawn and als arc lengh and rains. We will use (hea) represen an angle s measuremen. In he figure belw i describes hw yu

More information

by Lauren DeDieu Advisor: George Chen

by Lauren DeDieu Advisor: George Chen b Laren DeDe Advsor: George Chen Are one of he mos powerfl mehods o nmercall solve me dependen paral dfferenal eqaons PDE wh some knd of snglar shock waves & blow-p problems. Fed nmber of mesh pons Moves

More information

Wp/Lmin. Wn/Lmin 2.5V

Wp/Lmin. Wn/Lmin 2.5V UNIVERITY OF CALIFORNIA Cllege f Engneerng Department f Electrcal Engneerng and Cmputer cences Andre Vladmrescu Hmewrk #7 EEC Due Frday, Aprl 8 th, pm @ 0 Cry Prblem #.5V Wp/Lmn 0.0V Wp/Lmn n ut Wn/Lmn.5V

More information

ELEG 205 Fall Lecture #10. Mark Mirotznik, Ph.D. Professor The University of Delaware Tel: (302)

ELEG 205 Fall Lecture #10. Mark Mirotznik, Ph.D. Professor The University of Delaware Tel: (302) EEG 05 Fall 07 ecure #0 Mark Mirznik, Ph.D. Prfessr The Universiy f Delaware Tel: (3083-4 Email: mirzni@ece.udel.edu haper 7: apacirs and Inducrs The apacir Symbl Wha hey really lk like The apacir Wha

More information

(,,, ) (,,, ). In addition, there are three other consumers, -2, -1, and 0. Consumer -2 has the utility function

(,,, ) (,,, ). In addition, there are three other consumers, -2, -1, and 0. Consumer -2 has the utility function MACROECONOMIC THEORY T J KEHOE ECON 87 SPRING 5 PROBLEM SET # Conder an overlappng generaon economy le ha n queon 5 on problem e n whch conumer lve for perod The uly funcon of he conumer born n perod,

More information

2/20/2013. EE 101 Midterm 2 Review

2/20/2013. EE 101 Midterm 2 Review //3 EE Mderm eew //3 Volage-mplfer Model The npu ressance s he equalen ressance see when lookng no he npu ermnals of he amplfer. o s he oupu ressance. I causes he oupu olage o decrease as he load ressance

More information

Differentiation Applications 1: Related Rates

Differentiation Applications 1: Related Rates Differentiatin Applicatins 1: Related Rates 151 Differentiatin Applicatins 1: Related Rates Mdel 1: Sliding Ladder 10 ladder y 10 ladder 10 ladder A 10 ft ladder is leaning against a wall when the bttm

More information

Chapter 6 : Gibbs Free Energy

Chapter 6 : Gibbs Free Energy Wnter 01 Chem 54: ntrductry hermdynamcs Chapter 6 : Gbbs Free Energy... 64 Defntn f G, A... 64 Mawell Relatns... 65 Gbbs Free Energy G(,) (ure substances)... 67 Gbbs Free Energy fr Mtures... 68 ΔG f deal

More information

Section 3: Detailed Solutions of Word Problems Unit 1: Solving Word Problems by Modeling with Formulas

Section 3: Detailed Solutions of Word Problems Unit 1: Solving Word Problems by Modeling with Formulas Sectn : Detaled Slutns f Wrd Prblems Unt : Slvng Wrd Prblems by Mdelng wth Frmulas Example : The factry nvce fr a mnvan shws that the dealer pad $,5 fr the vehcle. If the stcker prce f the van s $5,, hw

More information

Thermal-Fluids I. Chapter 18 Transient heat conduction. Dr. Primal Fernando Ph: (850)

Thermal-Fluids I. Chapter 18 Transient heat conduction. Dr. Primal Fernando Ph: (850) hermal-fluds I Chapter 18 ransent heat conducton Dr. Prmal Fernando prmal@eng.fsu.edu Ph: (850) 410-6323 1 ransent heat conducton In general, he temperature of a body vares wth tme as well as poston. In

More information

, where. This is a highpass filter. The frequency response is the same as that for P.P.14.1 RC. Thus, the sketches of H and φ are shown below.

, where. This is a highpass filter. The frequency response is the same as that for P.P.14.1 RC. Thus, the sketches of H and φ are shown below. hapter 4, Slutn. H ( H(, where H π H ( φ H ( tan - ( Th a hghpa lter. The requency repne the ame a that r P.P.4. except that. Thu, the ketche H and φ are hwn belw. H.77 / φ 9 45 / hapter 4, Slutn. H(,

More information

Digital Integrated CircuitDesign

Digital Integrated CircuitDesign Dgal Inegraed CrcuDesgn Lecure 6 BJT Inverer Swchng Tmes µ s 01. 1 3 4 6 2 Adb Abrshamfar EE Deparmen IUST Cnens BJT Inverer Cuff Regn ( 1 ) Acve Regn ( 1 2 ) Sauran Regn ( 3 4 ) Acve Regn ( 4 ) Recvery

More information

IrrItrol Products 2016 catalog

IrrItrol Products 2016 catalog l Ps Valves 205, 200 an 2500 eies Valves M Pa Nmbe -205F 1" n-line E Valve w/ FC - se 2500 eies 3* -200 1" E n-line Valve w/ FC F x F 3-200F 1" n-line Valve w/ FC F x F -2500 1" E Valve w/ FC F x F -2500F

More information

Lecture 12. Heat Exchangers. Heat Exchangers Chee 318 1

Lecture 12. Heat Exchangers. Heat Exchangers Chee 318 1 Lecture 2 Heat Exchangers Heat Exchangers Chee 38 Heat Exchangers A heat exchanger s used t exchange heat between tw fluds f dfferent temperatures whch are separated by a sld wall. Heat exchangers are

More information

convection coefficient. The different property values of water at 20 C are given by: u W/m K, h=8062 W/m K

convection coefficient. The different property values of water at 20 C are given by: u W/m K, h=8062 W/m K Practice rblems fr Cnvective Heat Transfer 1. Water at 0 C flws ver a flat late 1m 1m at 10 C with a free stream velcity f 4 m/s. Determine the thickness f bndary layers, lcal and average vale f drag cefficient

More information

( ) [ ] MAP Decision Rule

( ) [ ] MAP Decision Rule Announcemens Bayes Decson Theory wh Normal Dsrbuons HW0 due oday HW o be assgned soon Proec descrpon posed Bomercs CSE 90 Lecure 4 CSE90, Sprng 04 CSE90, Sprng 04 Key Probables 4 ω class label X feaure

More information

CS434a/541a: Pattern Recognition Prof. Olga Veksler. Lecture 4

CS434a/541a: Pattern Recognition Prof. Olga Veksler. Lecture 4 CS434a/54a: Paern Recognon Prof. Olga Veksler Lecure 4 Oulne Normal Random Varable Properes Dscrmnan funcons Why Normal Random Varables? Analycally racable Works well when observaon comes form a corruped

More information

Physics Courseware Physics I Constant Acceleration

Physics Courseware Physics I Constant Acceleration Physics Curseware Physics I Cnsan Accelerain Equains fr cnsan accelerain in dimensin x + a + a + ax + x Prblem.- In he 00-m race an ahlee acceleraes unifrmly frm res his p speed f 0m/s in he firs x5m as

More information

Unit-I (Feedback amplifiers) Features of feedback amplifiers. Presentation by: S.Karthie, Lecturer/ECE SSN College of Engineering

Unit-I (Feedback amplifiers) Features of feedback amplifiers. Presentation by: S.Karthie, Lecturer/ECE SSN College of Engineering Uni-I Feedback ampliiers Feaures eedback ampliiers Presenain by: S.Karhie, Lecurer/ECE SSN Cllege Engineering OBJECTIVES T make he sudens undersand he eec negaive eedback n he llwing ampliier characerisics:

More information

Chapter 7 AC Power and Three-Phase Circuits

Chapter 7 AC Power and Three-Phase Circuits Chaper 7 AC ower and Three-hae Crcu Chaper 7: Oulne eance eacance eal power eacve power ower n AC Crcu ower and Energy Gven nananeou power p, he oal energy w ranferred o a load beween and : w p d The average

More information

Motion of Wavepackets in Non-Hermitian. Quantum Mechanics

Motion of Wavepackets in Non-Hermitian. Quantum Mechanics Moon of Wavepaces n Non-Herman Quanum Mechancs Nmrod Moseyev Deparmen of Chemsry and Mnerva Cener for Non-lnear Physcs of Complex Sysems, Technon-Israel Insue of Technology www.echnon echnon.ac..ac.l\~nmrod

More information

Conduction Heat Transfer

Conduction Heat Transfer Cnductn Heat Transfer Practce prblems A steel ppe f cnductvty 5 W/m-K has nsde and utsde surface temperature f C and 6 C respectvely Fnd the heat flw rate per unt ppe length and flux per unt nsde and per

More information

DESIGN OF TENSION MEMBERS

DESIGN OF TENSION MEMBERS CHAPTER Srcral Seel Design LRFD Mehod DESIGN OF TENSION MEMBERS Third Ediion A. J. Clark School of Engineering Deparmen of Civil and Environmenal Engineering Par II Srcral Seel Design and Analysis 4 FALL

More information

AP Physics Kinematic Wrap Up

AP Physics Kinematic Wrap Up AP Physics Kinematic Wrap Up S what d yu need t knw abut this mtin in tw-dimensin stuff t get a gd scre n the ld AP Physics Test? First ff, here are the equatins that yu ll have t wrk with: v v at x x

More information

RAMIFICATIONS of POSITION SERVO LOOP COMPENSATION

RAMIFICATIONS of POSITION SERVO LOOP COMPENSATION RAMIFICATIONS f POSITION SERO LOOP COMPENSATION Gerge W. Yunk, P.E. Lfe Fellw IEEE Indural Cnrl Cnulg, Inc. Fnd du Lac, Wcn Fr many year dural pg er dre dd n ue er cmpena he frward p lp. Th wa referred

More information

" 1 = # $H vap. Chapter 3 Problems

 1 = # $H vap. Chapter 3 Problems Chapter 3 rblems rblem At 1 atmsphere pure Ge melts at 1232 K and bils at 298 K. he triple pint ccurs at =8.4x1-8 atm. Estimate the heat f vaprizatin f Ge. he heat f vaprizatin is estimated frm the Clausius

More information

A/2 l,k. Problem 1 STRATEGY. KNOWN Resistance of a complete spherical shell: r rk. Inner and outer radii

A/2 l,k. Problem 1 STRATEGY. KNOWN Resistance of a complete spherical shell: r rk. Inner and outer radii Prblem 1 STRATEGY KNOWN Resstance f a cmplete sphercal shell: R ( r r / (4 π r rk sphere Inner an uter ra r an r, SOLUTION Part 1: Resstance f a hemsphercal shell: T calculate the resstance f the hemsphere,

More information

β A Constant-G m Biasing

β A Constant-G m Biasing p 2002 EE 532 Anal IC Des II Pae 73 Cnsan-G Bas ecall ha us a PTAT cuen efeence (see p f p. 66 he nes) bas a bpla anss pes cnsan anscnucance e epeaue (an als epenen f supply lae an pcess). Hw h we achee

More information

H = d d q 1 d d q N d d p 1 d d p N exp

H = d d q 1 d d q N d d p 1 d d p N exp 8333: Sacal Mechanc I roblem Se # 7 Soluon Fall 3 Canoncal Enemble Non-harmonc Ga: The Hamlonan for a ga of N non neracng parcle n a d dmenonal box ha he form H A p a The paron funcon gven by ZN T d d

More information

1.2.1 Vectors. 1 P age. Examples What is the reference vector angle for a vector that points 50 degrees east of south?

1.2.1 Vectors. 1 P age. Examples What is the reference vector angle for a vector that points 50 degrees east of south? 1.2.1 Vectrs Definitins Vectrs are represented n paper by arrws directin = magnitude = Examples f vectrs: Examples What is the reference vectr angle fr a vectr that pints 50 degrees east f suth? What is

More information

Chapter 9 Compressible Flow 667

Chapter 9 Compressible Flow 667 Chapter 9 Cmpreible Flw 667 9.57 Air flw frm a tank thrugh a nzzle int the tandard atmphere, a in Fig. P9.57. A nrmal hck tand in the exit f the nzzle, a hwn. Etimate (a) the tank preure; and (b) the ma

More information

Physics 107 HOMEWORK ASSIGNMENT #20

Physics 107 HOMEWORK ASSIGNMENT #20 Physcs 107 HOMEWORK ASSIGNMENT #0 Cutnell & Jhnsn, 7 th etn Chapter 6: Prblems 5, 7, 74, 104, 114 *5 Cncept Smulatn 6.4 prves the ptn f explrng the ray agram that apples t ths prblem. The stance between

More information

Copyright 2012 by the American Society for Pharmacology and Experimental Therapeutics.

Copyright 2012 by the American Society for Pharmacology and Experimental Therapeutics. DMD Fast This Forwar. article has not Publishe been copyeite on an February formatte. 16, The final 2012 version as oi:10.1124/m.111.042994 may iffer from this version. D, D:, z > z < ^ < ^ < :, ' < ^&

More information

Graphene nanoplatelets induced heterogeneous bimodal structural magnesium matrix composites with enhanced mechanical properties

Graphene nanoplatelets induced heterogeneous bimodal structural magnesium matrix composites with enhanced mechanical properties raphene nanoplaele nce heerogeneo bmoal rcral magnem marx compoe wh enhance mechancal propere Shln Xang a, b, Xaojn Wang a, *, anoj pa b, Kn W a, Xaoh H a, ngy Zheng a a School of aeral Scence an ngneerng,

More information

ε (5) 4. Radiative Heat Transfer 4.1 Fundamentals of thermal radiation (1) W/m / K Stefan-Boltzmann-constant

ε (5) 4. Radiative Heat Transfer 4.1 Fundamentals of thermal radiation (1) W/m / K Stefan-Boltzmann-constant . Radatve Heat ranfer. Fundamental of thermal radaton 0 ( λ) q I dλ σ () max 8 σ 5,67 0 W/m / K Stefan-Boltzmann-contant λ ( λ) q I dλ () λ 0 emperature q λ / q Sun 6000 K 0, µm Hot materal 600 K 0 µm

More information

Introduction ( Week 1-2) Course introduction A brief introduction to molecular biology A brief introduction to sequence comparison Part I: Algorithms

Introduction ( Week 1-2) Course introduction A brief introduction to molecular biology A brief introduction to sequence comparison Part I: Algorithms Course organzaon Inroducon Wee -2) Course nroducon A bref nroducon o molecular bology A bref nroducon o sequence comparson Par I: Algorhms for Sequence Analyss Wee 3-8) Chaper -3, Models and heores» Probably

More information

Chapter 3, Solution 1C.

Chapter 3, Solution 1C. COSMOS: Cmplete Onlne Slutns Manual Organzatn System Chapter 3, Slutn C. (a If the lateral surfaces f the rd are nsulated, the heat transfer surface area f the cylndrcal rd s the bttm r the tp surface

More information

ECE-320: Linear Control Systems Homework 1. 1) For the following transfer functions, determine both the impulse response and the unit step response.

ECE-320: Linear Control Systems Homework 1. 1) For the following transfer functions, determine both the impulse response and the unit step response. Due: Mnday Marh 4, 6 at the beginning f la ECE-: Linear Cntrl Sytem Hmewrk ) Fr the fllwing tranfer funtin, determine bth the imule rene and the unit te rene. Srambled Anwer: H ( ) H ( ) ( )( ) ( )( )

More information

AE/ME 339. K. M. Isaac. 8/31/2004 topic4: Implicit method, Stability, ADI method. Computational Fluid Dynamics (AE/ME 339) MAEEM Dept.

AE/ME 339. K. M. Isaac. 8/31/2004 topic4: Implicit method, Stability, ADI method. Computational Fluid Dynamics (AE/ME 339) MAEEM Dept. AE/ME 339 Comptatonal Fld Dynamcs (CFD) Comptatonal Fld Dynamcs (AE/ME 339) Implct form of dfference eqaton In the prevos explct method, the solton at tme level n,,n, depended only on the known vales of,

More information

Ordinary Differential Equations in Neuroscience with Matlab examples. Aim 1- Gain understanding of how to set up and solve ODE s

Ordinary Differential Equations in Neuroscience with Matlab examples. Aim 1- Gain understanding of how to set up and solve ODE s Ordnary Dfferenal Equaons n Neuroscence wh Malab eamples. Am - Gan undersandng of how o se up and solve ODE s Am Undersand how o se up an solve a smple eample of he Hebb rule n D Our goal a end of class

More information

Chapter 5: 8, 16, 25, 27, 28, 35, 36, 49, 52, 57, 72, 82 and 87.

Chapter 5: 8, 16, 25, 27, 28, 35, 36, 49, 52, 57, 72, 82 and 87. aper : 8,,, 7, 8,,, 9,, 7, 7, 8 and 87. -8 e fne dfference frulan f sead w-densnal ea cnducn n a edu w ea eneran and cnsan eral cnducv s ven b, n n,, n n, n, n, n, n recanular crdnaes. s relan can be dfed

More information

PEGN 513 Reservoir Simulation I Fall 2009

PEGN 513 Reservoir Simulation I Fall 2009 Hmer #3 l The smples rm r aerld a lear cre ally saraed h l ad a resdal aer sara h gravy r capllary eecs s represeed by he -dmesal Bcley-Levere maeral balace eqa () Eplc sl Csderg he space dscreza sh Fgre

More information

Module 7: Solved Problems

Module 7: Solved Problems Mdule 7: Slved Prblems 1 A tn-walled nentr tube eat exanger f 019-m lengt s t be used t eat denzed water frm 40 t 60 at a flw rate f 5 kg/s te denzed water flws trug te nner tube f 30-mm dameter wle t

More information

Steady State Conduction

Steady State Conduction ECE309 Intrductin t Thermdynamics and Heat Transfer Spring 005 Tutrial # 7 Steady State Cnductin Prblem 1 Cnsider a naked persn standing in a rm at 0 C with an expsed surface area f 17m The deep bdy temperature

More information

DEEP UNFOLDING FOR MULTICHANNEL SOURCE SEPARATION SUPPLEMENTARY MATERIAL

DEEP UNFOLDING FOR MULTICHANNEL SOURCE SEPARATION SUPPLEMENTARY MATERIAL DEEP UNFOLDING FOR MULTICHANNEL SOURCE SEPARATION SUPPLEMENTARY MATERIAL Sco Wsdom, John Hershey 2, Jonahan Le Roux 2, and Shnj Waanabe 2 Deparmen o Elecrcal Engneerng, Unversy o Washngon, Seale, WA, USA

More information

Chapter 6. Dielectrics and Capacitance

Chapter 6. Dielectrics and Capacitance Chapter 6. Dielectrics and Capacitance Hayt; //009; 6- Dielectrics are insulating materials with n free charges. All charges are bund at mlecules by Culmb frce. An applied electric field displaces charges

More information

Physics 201 Lecture 15

Physics 201 Lecture 15 Phscs 0 Lecue 5 l Goals Lecue 5 v Elo consevaon of oenu n D & D v Inouce oenu an Iulse Coens on oenu Consevaon l oe geneal han consevaon of echancal eneg l oenu Consevaon occus n sses wh no ne eenal foces

More information

HEAT CONDUCTION PROBLEM IN A TWO-LAYERED HOLLOW CYLINDER BY USING THE GREEN S FUNCTION METHOD

HEAT CONDUCTION PROBLEM IN A TWO-LAYERED HOLLOW CYLINDER BY USING THE GREEN S FUNCTION METHOD Journal of Appled Mahemacs and Compuaonal Mechancs 3, (), 45-5 HEAT CONDUCTION PROBLEM IN A TWO-LAYERED HOLLOW CYLINDER BY USING THE GREEN S FUNCTION METHOD Sansław Kukla, Urszula Sedlecka Insue of Mahemacs,

More information

7-84. Chapter 7 External Forced Convection

7-84. Chapter 7 External Forced Convection Chapter 7 External Frced Cnvectin 7-99 Wind i blwing ver the rf f a hue. The rate f heat tranfer thrugh the rf and the ct f thi heat l fr -h perid are t be deterined. Auptin Steady perating cnditin exit.

More information

Problem 1. Refracting Surface (Modified from Pedrotti 2-2)

Problem 1. Refracting Surface (Modified from Pedrotti 2-2) .70 Optc Hmewrk # February 8, 04 Prblem. Reractng Surace (Me rm Pertt -) Part (a) Fermat prncple requre that every ray that emanate rm the bject an pae thrugh the mage pnt mut be chrnu (.e., have equal

More information

( ) () we define the interaction representation by the unitary transformation () = ()

( ) () we define the interaction representation by the unitary transformation () = () Hgher Order Perurbaon Theory Mchael Fowler 3/7/6 The neracon Represenaon Recall ha n he frs par of hs course sequence, we dscussed he chrödnger and Hesenberg represenaons of quanum mechancs here n he chrödnger

More information

Chapter 5: Force and Motion I-a

Chapter 5: Force and Motion I-a Chapter 5: rce and Mtin I-a rce is the interactin between bjects is a vectr causes acceleratin Net frce: vectr sum f all the frces n an bject. v v N v v v v v ttal net = i = + + 3 + 4 i= Envirnment respnse

More information

Circuits Op-Amp. Interaction of Circuit Elements. Quick Check How does closing the switch affect V o and I o?

Circuits Op-Amp. Interaction of Circuit Elements. Quick Check How does closing the switch affect V o and I o? Crcuts Op-Amp ENGG1015 1 st Semester, 01 Interactn f Crcut Elements Crcut desgn s cmplcated by nteractns amng the elements. Addng an element changes vltages & currents thrughut crcut. Example: clsng a

More information

4F-5 : Performance of an Ideal Gas Cycle 10 pts

4F-5 : Performance of an Ideal Gas Cycle 10 pts 4F-5 : Perfrmance f an Cycle 0 pts An ideal gas, initially at 0 C and 00 kpa, underges an internally reversible, cyclic prcess in a clsed system. The gas is first cmpressed adiabatically t 500 kpa, then

More information

Let s start from a first-order low pass filter we already discussed.

Let s start from a first-order low pass filter we already discussed. EEE0 Netrk Analy II Dr. harle Km Nte09: Actve Flter ---Part. gher-order Actve Flter The rt-rder lter d nt harply dvde the pa band and the tp band. One apprach t btan a harper trantn beteen the pa band

More information

1/2 and e0 e s ' 1+ imm w 4 M s 3 πρ0 r 3 m. n 0 ktr. .Also,since n 0 ktr 1,wehave. 4 3 M sπρ 0 r 3. ktr. 3 M sπρ 0

1/2 and e0 e s ' 1+ imm w 4 M s 3 πρ0 r 3 m. n 0 ktr. .Also,since n 0 ktr 1,wehave. 4 3 M sπρ 0 r 3. ktr. 3 M sπρ 0 Chapter 6 6.1 Shw that fr a very weak slutin drplet (m 4 3 πr3 ρ 0 M s ), (6.8) can be written as e 0 ' 1+ a r b r 3 where a σ 0 /n 0 kt and b imm w / 4 3 M sπρ 0. What is yur interpretatin f thecnd and

More information

Optimal Control. Lecture. Prof. Daniela Iacoviello

Optimal Control. Lecture. Prof. Daniela Iacoviello Opmal Cnrl Lecure Pr. Danela Iacvell Gradng Prjec + ral eam Eample prjec: Read a paper n an pmal cnrl prblem 1 Sudy: backgrund mvans mdel pmal cnrl slun resuls 2 Smulans Yu mus gve me al leas en days bere

More information

Name Student ID. A student uses a voltmeter to measure the electric potential difference across the three boxes.

Name Student ID. A student uses a voltmeter to measure the electric potential difference across the three boxes. Name Student ID II. [25 pt] Thi quetin cnit f tw unrelated part. Part 1. In the circuit belw, bulb 1-5 are identical, and the batterie are identical and ideal. Bxe,, and cntain unknwn arrangement f linear

More information

Scattering at an Interface: Oblique Incidence

Scattering at an Interface: Oblique Incidence Course Insrucor Dr. Raymond C. Rumpf Offce: A 337 Phone: (915) 747 6958 E Mal: rcrumpf@uep.edu EE 4347 Appled Elecromagnecs Topc 3g Scaerng a an Inerface: Oblque Incdence Scaerng These Oblque noes may

More information

AP Statistics Notes Unit Two: The Normal Distributions

AP Statistics Notes Unit Two: The Normal Distributions AP Statistics Ntes Unit Tw: The Nrmal Distributins Syllabus Objectives: 1.5 The student will summarize distributins f data measuring the psitin using quartiles, percentiles, and standardized scres (z-scres).

More information

https://goo.gl/eaqvfo SUMMER REV: Half-Life DUE DATE: JULY 2 nd

https://goo.gl/eaqvfo SUMMER REV: Half-Life DUE DATE: JULY 2 nd NAME: DUE DATE: JULY 2 nd AP Chemistry SUMMER REV: Half-Life Why? Every radiistpe has a characteristic rate f decay measured by its half-life. Half-lives can be as shrt as a fractin f a secnd r as lng

More information

Lecture 3: Resistive forces, and Energy

Lecture 3: Resistive forces, and Energy Lecure 3: Resisive frces, and Energy Las ie we fund he velciy f a prjecile ving wih air resisance: g g vx ( ) = vx, e vy ( ) = + v + e One re inegrain gives us he psiin as a funcin f ie: dx dy g g = vx,

More information

10. A.C CIRCUITS. Theoretically current grows to maximum value after infinite time. But practically it grows to maximum after 5τ. Decay of current :

10. A.C CIRCUITS. Theoretically current grows to maximum value after infinite time. But practically it grows to maximum after 5τ. Decay of current : . A. IUITS Synopss : GOWTH OF UNT IN IUIT : d. When swch S s closed a =; = d. A me, curren = e 3. The consan / has dmensons of me and s called he nducve me consan ( τ ) of he crcu. 4. = τ; =.63, n one

More information

Appendix H: Rarefaction and extrapolation of Hill numbers for incidence data

Appendix H: Rarefaction and extrapolation of Hill numbers for incidence data Anne Chao Ncholas J Goell C seh lzabeh L ander K Ma Rober K Colwell and Aaron M llson 03 Rarefacon and erapolaon wh ll numbers: a framewor for samplng and esmaon n speces dversy sudes cology Monographs

More information

Observer Design for Nonlinear Systems using Linear Approximations

Observer Design for Nonlinear Systems using Linear Approximations Observer Desgn for Nonlnear Ssems sng Lnear Appromaons C. Navarro Hernandez, S.P. Banks and M. Aldeen Deparmen of Aomac Conrol and Ssems Engneerng, Unvers of Sheffeld, Mappn Sree, Sheffeld S 3JD. e-mal:

More information

Lecture 17: Free Energy of Multi-phase Solutions at Equilibrium

Lecture 17: Free Energy of Multi-phase Solutions at Equilibrium Lecture 17: 11.07.05 Free Energy f Multi-phase Slutins at Equilibrium Tday: LAST TIME...2 FREE ENERGY DIAGRAMS OF MULTI-PHASE SOLUTIONS 1...3 The cmmn tangent cnstructin and the lever rule...3 Practical

More information

CONVEX COMBINATIONS OF ANALYTIC FUNCTIONS

CONVEX COMBINATIONS OF ANALYTIC FUNCTIONS rnat. J. Math. & Math. S. Vl. 6 N. (983) 33534 335 ON THE RADUS OF UNVALENCE OF CONVEX COMBNATONS OF ANALYTC FUNCTONS KHALDA. NOOR, FATMA M. ALOBOUD and NAEELA ALDHAN Mathematcs Department Scence Cllege

More information

CIRCLE YOUR DIVISION: Div. 1 (9:30 am) Div. 2 (11:30 am) Div. 3 (2:30 pm) Prof. Ruan Prof. Naik Mr. Singh

CIRCLE YOUR DIVISION: Div. 1 (9:30 am) Div. 2 (11:30 am) Div. 3 (2:30 pm) Prof. Ruan Prof. Naik Mr. Singh Frst CIRCLE YOUR DIVISION: Dv. 1 (9:30 am) Dv. (11:30 am) Dv. 3 (:30 m) Prf. Ruan Prf. Na Mr. Sngh Schl f Mechancal Engneerng Purdue Unversty ME315 Heat and Mass ransfer Eam #3 Wednesday Nvember 17 010

More information

Principles of Food and Bioprocess Engineering (FS 231) Solutions to Example Problems on Heat Transfer

Principles of Food and Bioprocess Engineering (FS 231) Solutions to Example Problems on Heat Transfer Prncples of Food and Boprocess Engneerng (FS 31) Solutons to Example Problems on Heat Transfer 1. We start wth Fourer s law of heat conducton: Q = k A ( T/ x) Rearrangng, we get: Q/A = k ( T/ x) Here,

More information

Control Systems. Mathematical Modeling of Control Systems.

Control Systems. Mathematical Modeling of Control Systems. Conrol Syem Mahemacal Modelng of Conrol Syem chbum@eoulech.ac.kr Oulne Mahemacal model and model ype. Tranfer funcon model Syem pole and zero Chbum Lee -Seoulech Conrol Syem Mahemacal Model Model are key

More information