Sph3u Practice Unit Test: Kinematics (Solutions) LoRusso


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1 Sph3u Prcice Uni Te: Kinemic (Soluion) LoRuo Nme: Tuey, Ocober 3, 07 Ku: /45 pp: /0 T&I: / Com: Thi i copy of uni e from 008. Thi will be imilr o he uni e you will be wriing nex Mony. you cn ee here re quie few queion on he e. When you wrie uni e you houl lwy mke ure you nwer he following queion fir. Sr wih he queion h re worh he mo in he knowlege ecion. Then focu on pplicion / Thinking & Inveigion queion. Since we only hve one pplicion queion per e uully, ech queion i worh ignificn moun becue i mrke in epre cegory. The me pplie o he T&I queion. Then complee he hor nwer muliple choice followe by he regulr muliple choice l. Why o he muliple choice queion l? ecue you cn lwy gue if you run ou of ime. Muliple Choice [ku: 9] Ienify he leer of he choice h be complee he emen or nwer he queion Which of he following i "clr" quniy?. ince. iplcemen b. velociy e. none of he bove c. ccelerion The erm "uniform moion" men. ccelerion i conn. iplcemen i conn b. pee i conn e. velociy i zero c. velociy i conn The lope of poiionime grph lwy repreen. iplcemen. chnge in velociy b. ince e. ccelerion c. velociy The re uner velociyime grph lwy repreen. iplcemen. ccelerion b. chnge in velociy e. chnge in ccelerion c. ince The poiionime grph picure below repreen he moion of wo objec, n. Which of he following emen concerning he objec' moion i rue?. Objec rvel he greer ince. b. Objec h he greer pee. c. Objec leve he reference poin n erlier ime.. oh objec hve he me pee he poin where he line cro. e. Objec i rvelling for longer perio of ime. The poiionime grph h epic bll hrown vericlly upwr h reurn o he me poiion i 7... D e. E c. C The poiionime grph h repreen "uniform moion" i.. D b. e. E c. C
2 8. Conier he following velociyime grph n elec he emen h i rue. 9.. no ime cn he moion be coniere "uniform." b. The objec reurn o i originl poiion. c. The objec rvel in one irecion n hen he oher.. The objec i ccelering hroughou he enire recore ime. e. The objec pee up n ler low own. Four of he five grph picure below coul ll repreen he me moion. Which grph oe no belong o hi group? Thi queion cully h concepul problem. n D repreen negive ccelerion ( frownie bi) n, C, n E repreen poiive ccelerion miley bi herefore he queion i no cler... D b. e. E c. C Shor nwer Muliple Choice (RFS i NOT require) [ku: 8] 0. cycli rie bicycle 4.0 km we, hen 3.0 km norh. Wh i he cycli' iplcemen?. 7.0 km [37 N of W]. 5.0 km [37 W of N] b. 7.0 km [37 W of N] e..0 km [37 W of N] c. 5.0 km [37 N of W] b nθ b 3.0km[ N] + b θ 4.0km[ W] θ n θ 37. cr rive 6.0 km [E], hen 8.0 km [S] in ol ime of 0.30 h. Wh i he cr' verge pee?. 33 km/h. 47 km/h [E of S] b. 47 km/h e. 47 km/h [S of E] c. 33 km/h [E of S] ol vvg ol + b vvg ol vvg 0.30 v 47 km/ h vg
3 . If n objec ccelere 6. m/ [N], how long will i ke o rech velociy of 5 m/ [N] if ring from re? b. 4.0 m/ e. 4.0 c m/ [ N] Δv Δ v 0 m/ Δv Δ [ ] v 5 m/ N Δ 6. Δ n objec i hrown vericlly upwr 5.0 m/. If i experience n ccelerion ue o grviy of 9.8 m/ [own], wh i he objec' velociy 3.0 ler?. m/ [own]. 4 m/ [own] b. m/ [up] e. zero (i h hi he groun) c. 4 m/ [up] v m/ v v+ 9.8 m/ v ( 9.8)( 3.0) 3.0 v 4.4 m/ 4. one i hrown vericlly ownwr wih pee of 0 m/ from brige. ccelering uner grviy (9.8 m/ ), he one rike he wer.8 ler. From wh heigh bove he wer w he one hrown? (ume ignificn igi.). 50 m. 5 m b. 34 m e. 3 m c. 7 m v 0 m/ v m/.8 ( 0)(.8) + ( 9.8)(.8) 34m
4 5. The igrm below how he fir hree leg of rip: o, o C, n C o D. If peron reurn from poin D o poin, wh i he iplcemen for hi fourh n finl leg?. 7 km [37 W of N]. 7 km [37 E of S] b. 5 km [37 W of N] e. 5 km [37 N of E] c. 5 km [37 E of S] x 3km θ y 4km x + y + 5m ( 3) ( 4) nθ θ n θ 37 0 x y 3 4
5 Problem Solving (ll queion houl be complee in he RFS form). Mr. LoRuo i ning in he hll checking ex mege when Mr. ee run by n hou NO PERSONL ELECTRONIC DEVICES!!! hen grb he cell phone n run hrough he hll conn pee of 4.00 m/, lughing mniclly ll he while. Mr. LoRuo innneouly che fer him ccelering re of.0 m/ houing him Wi!!! I w exing my mom!!! Deermine: [ku: 8] ) how long i ke for Mr. LoRuo o cch up o Mr. ee. (inclue igrm) b) how fr Mr. LoRuo h o run o cch up o him. (Expre your nwer in pr ) n b) o he correc number of ig. fig.) L v 4.0 m/ x LoRuo ee v L vl L + LL x 4.0 x 0+ (.0) ( ) x.0 () Sub () ino () Sub 4.0 ino () x 4.0( 4.0) x 6m 4.0 vl 0 m/ L.0 m/ L x L
6 . fer Mr. LoRuo inercep n rerieve hi phone from Mr. ee, he op hen urn n run he oher wy for 4, ccelering re of.5 m/ which poin he rip n lie forwr for noher 3.0 before he come o op righ Mr. orki fee. [ku: 0] ) How fr i Mr. LoRuo run before he rippe? (inclue igrm) b) How f w he going before he rippe? c) How fr i he lie? ) Wh w hi re of ccelerion uring he lie? Secion v v Secion v 0 m/.5 m/? 4.0 v 0 m/?? 3.0 ) Fin b) Fin v c) Fin ) Fin v v + Δv v + LL ( v + v ) v ( 0) + (.5)( 4.0) Δ ( 0)( 4.0) + (.5)( 4.0) v 6.0 m/ ( )( 3.0 ) v v Δ m v v 6.0 / m 9.0m ( 0) ( 6.0) ( 3.0).0 m/ pplicion When kyiver jump from n irplne he cn rech pee ner 40 km/h uring he freefll porion of he ive. Once he prchue i eploye he prchui pee ecree o 0 km/h. Explin why hen in phyic we conier he ccelerion uring he freefll o be negive n he ccelerion uring he ime he prchue i eploye o be poiive by uing your knowlege of vecor n kinemic. Since he kyiver jump from plne he ccelerion ue o grviy cue he iver pee o incree in he negive irecion. Therefore he iver velociy coninue o become more negive over ime. If he iver i rveling pee of 40km/h, hi/her velociy woul be 40km/h or 40km/h [D]. Once he/he pull eploy he prchue, he pee begin o ecree mening h he velociy i becoming le negive. i.e. chnging from 40km/h o 0km/h. Therefore from vecor perpecive he chnge in velociy i poiive (i.e. Δ v v v ( 0) ( 40) + 30 m/ ) Since he velociy chnge i poiive, Δv herefore he ccelerion mu be poiive ( ) Δ
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