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1 University of Rhode Island PHY 204: Elementary Physics II Physics Course Materials RC Circuits Gerhard Müller University of Rhode Island, Creative Commons License This work is licensed under a Creative Commons Attribution-Noncommercial-hare Alike 4.0 License. Follow this and additional works at: Abstract Part eleven of course materials for Elementary Physics II (PHY 204), taught by Gerhard Müller at the University of Rhode Island. Documents will be updated periodically as more entries become presentable. ome of the slides contain figures from the textbook, Paul A. Tipler and Gene Mosca. Physics for cientists and Engineers, 5 th /6 th editions. The copyright to these figures is owned by W.H. Freeman. We acknowledge permission from W.H. Freeman to use them on this course web page. The textbook figures are not to be used or copied for any purpose outside this class without direct permission from W.H. Freeman. Recommended Citation Müller, Gerhard, "11. RC Circuits" (2015). PHY 204: Elementary Physics II. Paper This Course Material is brought to you for free and open access by the Physics Course Materials at DigitalCommons@URI. It has been accepted for inclusion in PHY 204: Elementary Physics II by an authorized administrator of DigitalCommons@URI. For more information, please contact digitalcommons@etal.uri.edu.
2 RC Circuit: Fundamentals pecifications: E (emf) R (resistance) C (capacitance) witch : a: charging b: discharging a b I(t) ε R C +Q(t) Q(t) Time-dependent quantities: Q(t): instantaneous charge on capacitor I(t) = dq : instantaneous current dt V R (t) = I(t)R: instantaneous voltage across resistor V C (t) = Q(t) : instantaneous voltage across capacitor C 18/9/2015 [tsl166 1/17]
3 RC Circuit: Charging the Capacitor Loop rule: E IR Q C = 0 Differential equation: R dq dt + Q C = E dq dt = EC Q Z RC Q Z dq t «0 EC Q = dt EC Q ln = t 0 RC EC RC Charge on capacitor: Q(t) = EC h1 e t/rci Current through resistor: I(t) dq dt = E R e t/rc EC Q EC = e t/rc ε C Q(t) ε R I(t) t t 18/9/2015 [tsl167 2/17]
4 RC Circuit: Discharging the Capacitor Loop rule: IR + Q C = 0 Differential equation: R dq dt + Q C = 0 dq dt = Q Z RC Q Z dq t «Q = dt Q ln = t RC EC RC EC Charge on capacitor: Q(t) = ECe t/rc 0 Current through resistor: I(t) dq dt = E R e t/rc Q EC = e t/rc ε C Q(t) ε R I(t) t t 18/9/2015 [tsl168 3/17]
5 RC Circuit: Energy Transfer While Charging Loop rule: IR + Q C = E (I is positive) IE: rate at which emf source delivers energy IV R = I 2 R: rate at which energy is dissipated in resistor IV C = IQ C : rate at which energy is stored in capacitor Balance of energy transfer: I 2 R + IQ C = IE a b I(t) ε R C +Q(t) Q(t) 18/9/2015 [tsl169 4/17]
6 RC Circuit: Energy Transfer While Discharging Loop rule: IR + Q C = 0 (I is negative) IV R = I 2 R: rate at which energy is dissipated in resistor IV C = IQ C : rate at which capacitor releases energy Balance of energy transfer: I 2 R + IQ C = 0 a b I(t) ε R C +Q(t) Q(t) 18/9/2015 [tsl170 5/17]
7 RC Circuit: ome Physical Properties pecification of RC circuit by 3 device properties: E [V] (emf) R [Ω] (resistance) ε R C +Q(t) Q(t) C [F] (capacitance) I(t) Physical properties of RC circuit during charging process determined by 3 combinations of the device properties: E/R = I(t = 0): rate at which current flows onto capacitor initially EC = Q(t = ): total charge placed on capacitor ultimately RC = τ: time it takes to place 63% of the charge onto the capacitor [1 e 1 = ] 18/9/2015 [tsl171 6/17]
8 RC Circuit: Application (1) This circuit has been running for a very long time. (a) Find the current through the 18V battery. (b) Find the total power dissipated in the resistors. (c) Find the charge stored on the capacitor. 4V 18V 5nF 18/9/2015 [tsl172 7/17]
9 RC Circuit: Application (2) The switches are closed at t = 0. This begins the charging process in each RC circuit. Name the circuit in which... (i) the charge flows into the capacitor at the highest rate initially, (ii) the capacitor has the most charge ultimately, (iii) the capacitor is 63% full in the shortest time. (a) 0.5Ω 0.25Ω (b) 2V 1nF 0.5V 1nF (c) (d) 0.5Ω 4V 1nF 1V 1nF 18/9/2015 [tsl173 8/17]
10 RC Circuit: Application (3) At time t = 0 the capacitor in this circuit is discharged and the switch is being closed. Find the current I 1 (a) at t = 0, (b) at t =. I 1 Find the current I 2 (c) at t = 0, (d) at t =. 12V I 2 5nF 18/9/2015 [tsl174 9/17]
11 RC Circuit: Application (4) In this 3-loop RC circuit, the switch is closed at time t = 0. (a) Find the currents I 1, I 2, I 3 just after the switch has been closed. (b) Find the currents I 1, I 2, I 3 a very long time later. I 1 I 2 I 3 6nF 12V 18/9/2015 [tsl175 10/17]
12 RC Circuit: Application (5) In the RC circuit shown, the switch has been open for a long time. (a) Find the currents I 1 and I 2 immediately after the switch has been closed. (b) Find the currents I 1 and I 2 a very long time later. 24V 4Ω I 3 µ F 4Ω I /9/2015 [tsl176 11/17]
13 RC Circuit: Application (6) In the RC circuit shown, both switches are initially open and the capacitor is discharged. (a) Close switch 1 and find the currents I 1 and I 2 immediately afterwards. (b) Find the currents I 1 I 2 and the charge Q on the capacitor a very long time later. (c) Now close switch 2 also and find the currents I 1 and I 2 immediately afterwards. (d) Find the currents I 1, I 2 and the charge Q on the capacitor a very long time later. 1 2 I 1 10 µ F 4Ω I 2 1V 2V 18/9/2015 [tsl177 12/17]
14 RC Circuit: Application (7) In the RC circuit shown, the switch has been open for a long time. Find the currents I 1, I 2, I 3 and the charge Q on the capacitor (a) right after the switch has been closed, (b) a very long time later. R I I 1 2 ε R C R R = C = 6 µ F ε = 12V R I 3 R 18/9/2015 [tsl178 13/17]
15 RC Circuit: Application (8) The circuit shown is that of a flashing lamp, such as are attached to barrels at highway construction sites. The power is supplied by a battery with E = 95V. The fluorescent lamp L is connected in parallel to the capacitor with C = 0.15µF of an RC circuit. Current passes through the lamp only when the potential difference across it reaches the breakdown voltage V L = 72V. In this event, the capacitor discharges through the lamp, and the lamp flashes briefly. uppose that two flashes per second are needed. What should the resistance R be? R ε = 95V L C = 0.15 µ F 18/9/2015 [tsl179 14/17]
16 Circuit of Capacitors and Diodes The circuit shown contains two identical capacitors and two ideal diodes. A 100V battery is connected to the two input terminals a and b. Find the voltage at the output terminals c and d (1) if a is the positive input terminal, (2) if b is the positive input terminal. Note: An ideal diode is a perfect one-way street for electric currents. It lets a current through unimpeded in the direction of the arrow and totally blocks any current in the oppositie direction. a C = 4µ F D c D C = 4µF b d 18/9/2015 [tsl121 15/17]
17 Unit Exam II: Problem #3 (pring 13) Consider the RC circuit shown. The switch has been closed for a long time. (a) Find the current I B flowing through the battery. (b) Find the voltage V C across the capacitor. (c) Find the charge Q on the capacitor. (d) Find the current I 3 flowing through the 3Ω-resistor right after the switch has been opened. 4Ω 4Ω 12V 10nF 12V 10nF 1Ω 3Ω 3Ω 18/9/2015 [tsl458 16/17]
18 Intermediate Exam II: Problem #3 (pring 05) This RC circuit has been running for a long time. (a) Find the current I 2 through the resistor R 2. (b) Find the voltage V C across the capacitor. 12V R = 1 C = 7nF R = 4Ω 2 18/9/2015 [tsl338 17/17]
19 Intermediate Exam II: Problem #3 (pring 05) This RC circuit has been running for a long time. (a) Find the current I 2 through the resistor R 2. (b) Find the voltage V C across the capacitor. 12V R = 1 C = 7nF R = 4Ω 2 olution: (a) I C = 0, I 2 = E = 12V R 1 + R 2 6Ω = 2A. 18/9/2015 [tsl338 17/17]
20 Intermediate Exam II: Problem #3 (pring 05) This RC circuit has been running for a long time. (a) Find the current I 2 through the resistor R 2. (b) Find the voltage V C across the capacitor. 12V R = 1 C = 7nF R = 4Ω 2 olution: (a) I C = 0, I 2 = E = 12V R 1 + R 2 6Ω = 2A. (b) V C = V 2 = I 2 R 2 = (2A)(4Ω) = 8V. 18/9/2015 [tsl338 17/17]
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University of Rhode Island DigitalCommons@URI PHY 204: Elementary Physics II Physics Course Materials 2015 16. Faraday's Law Gerhard Müller University of Rhode Island, gmuller@uri.edu Creative Commons
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