New Zealand Institute of Physics

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1 New Zealan Institute of Physics ASSESSMENT SCHEDULE Physics Level v2 Demonstrate unerstaning of physics in an integrate context Note: Minor computational errors will not be penalise. A wrong answer will be accepte as correct provie there is sufficient evience that the mistake is not ue to a lack of unerstaning. Such evience inclues: the last written step before the answer is given has no unexpane brackets or terms an oes not require rearranging. the power of any number that is multiplie by a power of 0 is correct. Correct units an significant figures are require only in the questions that specifically ask for them.

2 2 Evience Statement u&sf Qa(ii) roune to 2 sf plus 5 correct units Correct One v vertical 38 tan (b) The only force acting on the ball is gravity an so it has constant horizontal spee an constant vertical acceleration. These are the require conitions for projectile motion. (c) v i t + ½at ½ m Only force acting is gravity Correct working Correct conitions, correct reason (e) The strings gain elastic potential energy as they stretch from the kinetic energy of the arm which came from the chemical potential energy in the arm muscles of the player. This elastic potential energy is change to kinetic energy of the ball as the strings regain their normal length. Iea of elastic potential energy Correct irection Iea of elastic potential energy being change to kinetic energy Explanation is clear an complete (f) p Ft t s (g) p p f p i m 7 m m m kg kg (h) τ F Nm 230 Nm (i) The player must hol the racquet in such a way that an equal an opposite torque on the racquet is create. Some iea of balance torques Iea of player creating equal an opposite torque

3 3 Two (b) The force on the electrons all aroun the loop will be at right angles to the magnetic fiel. This means that along QR the electrons will be pushe from one sie of the wire to the other sie, not along the wire. Therefore there will be no separation of charge along the wire an so no voltage across the length of the wire. The magnetic fiel irection is the same for both PQ an RS. The irection of motion of PQ is opposite to RS. This means that whichever irection the electrons are pushe in PQ they will be pushe in the opposite irection in RS. This means that if Q has a positive potential R will be negative an this is the conition for voltages in series. (c) V BvL V being pushe in the same irection aroun the loop by both forces. for one sie only not being pushe own the wire. (Do not accept no push on electrons.) being pushe in the same irection aroun the loop by both forces is linke to the opposite irection of movement of the two sies of the loop. Iea of force on electrons across the wire meaning that there is no movement of electrons along the wire an hence no voltage. F c mv 2 r N 2 consistent with length QR not being halve (e) R parallel R total R Ω (f) I R V A 29.2 (g) I R V R V R 3.0 V r V r IR R I 3.0 ( ) A OR I R V R V R V parallel I total R parallel R I R A Correct concept for calculating V R Correct V R

4 4 Two + (h) R parallel R2 R R (i) (j) R Ω If R is reuce the total resistance in the circuit is reuce an so the current rawn from the battery is increase. This means that the voltage across R is also increase. The wavelength of light is much shorter than the wavelength of raio waves. As amount waves can iffract epens on their wavelength, the raio waves are able to iffract aroun the upper part of the stan much more than the light waves an are able to reach the receiver. Iea of reucing R reucing the total resistance in the circuit. Knowlege that wavelength is the key concept. Iea of changing the resistance changing the current from the battery an hence the voltage across R. Link mae between longer wavelength an more iffraction. Explanation is clear an complete.

5 5 Three + i i i m (b) n p sinθ p n a sinθ a θ p 45, n a, θ a 90 n p o sin (c) Magnifie image always prouce. Because the image is virtual the image istance is negative. m i i o 8 o o Recognition that the image istance is negative. consistent with a positive i being use. Correct answer o mm Grae Distribution: Explain Type (0 questions) Calculate (4 questions) A M E u&sf b e 2b 2j 3c b i 2a 2b 2i 2j 2a 2i f h 2e 2f a c 2c 2 2h 3a 3b g 2g 3 Sufficiency Statement Achievement: Merit Excellence: 8 correct answers 2 correct answers of which 6 must be at the merit level or above 2 correct answers of which 8 must be at the merit level or above an of these 8, 3 must be at the excellence level Or an alternative but equivalent format: Total Opportunities at each level: Total : Total : 4 Total : 6 Sufficiency 8 6A + 6M 4A+5M+3E

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