MATH2000 Flux integrals and Gauss divergence theorem (solutions)
|
|
- Dorthy Long
- 6 years ago
- Views:
Transcription
1 DEPARTMENT O MATHEMATIC MATH lux integrals and Gauss divergence theorem (solutions ( The hemisphere can be represented as We have by direct calculation in terms of spherical coordinates. = {(r, θ, φ r, θ π, φ π/}. div d = 3 div = 3(x + y + z = 3r π/ π ( π/ ( π = 3 sin φ dφ = 3 π 5 = 6π 5. r r sin φ dr dθ dφ ( dθ r dr Now to evaluate n d. In this case the surface comprises of two parts: the base of the hemisphere which lies in the x-y plane, denoted, and the part of the sphere itself, denoted. o that n d = n d + n d where n and n are outwardly pointing unit normal vectors to the surfaces and respectively. We expect the integral n d to be zero since the k component of is when is restricted to the x-y plane, so there is no flux across that surface. To verify this by direct calculation, we must first parametrise the surface. ince it is just a circular disc in the x-y plane, we have We then take the tangent vectors r(r, θ = r cos θi + r sin θj, r, θ π. r θ = r sin θi + r cos θj r r = cos θi + sin θj
2 We can calculate r r r θ = rk. However, this is directed into the solid. We require this vector to be directed outwards from the solid, so instead we ll take r θ r r = rk. In terms of our parametrisation, (r, θ = r 3 cos 3 θi + r 3 sin 3 θj, so that the dot product (r, θ (r θ r r = which tells us that the flux across will be zero as originally thought. To calculate the flux across, we parametrise (compare with the spherical coordinate transformation as r(θ, φ = cos θ sin φi + sin θ sin φj + cos φk, θ π, φ π/. The tangent vectors are r θ = sin θ sin φi + cos θ sin φj r φ = cos θ cos φi + sin θ cos φj sin φk. To find a vector normal to the surface, take r φ r θ = cos θ sin φi + sin θ sin φj + sin φ cos φk. We should check the direction to make sure it is directed outwards from the surface. Take for example the parameter values φ = π/ and θ =. This gives r φ r θ = i which is directed out, so the direction is ok. In terms of the parameters, we can write so that the dot product (θ, φ = cos 3 θ sin 3 φi + sin 3 θ sin 3 φj + cos 3 φk. (θ, φ (r φ r θ = cos θ sin 5 φ + sin θ sin 5 φ + sin φ cos φ. The flux integral we need to evaluate is then π π/ Using cos θ = ( + cos θ we have ((cos θ + sin θ sin 5 φ + sin φ cos φ dφ dθ. cos θ = ( + cos θ( + cos θ = ( + cos θ + cos θ = ( + cos θ + ( + cos θ = cos θ + cos θ. 8
3 It follows that cos θ + sin θ = cos θ + ( cos θ( cos θ = cos θ + cos θ = ( + cos θ cos θ + cos θ = 3 + cos θ. inally note that we can write sin 5 φ = sin φ( cos φ + cos φ. Putting this together, the flux across is = π π/ + π π/ ( π + ( π ( 3 + cos θ sin φ( cos φ + cos φ dφ dθ sin φ cos φ dφ dθ ( π/ cos θ dθ sin φ( cos φ + cos φdφ ( 3 + ( π/ dθ sin φ cos φ dφ Using the substitution u = cos φ in both φ integrals gives ( [3 = θ + ] π sin θ ( u + u du + 6 = 3π [ u 3 u3 + ] [ ] 5 u5 + π 5 u5 = 3π ( π 5 5 = 6π 5. ( π u du Therefore n d = n d + n d = + 6π 5 = 6π 5. o we have shown that for this example both sides of the equation in Gauss theorem are equal. 3
4 ( Note that in this case we cannot use Gauss divergence theorem since the vector field = i is undefined at any point in the y-z plane (ie. when x =, part of which lies in x the region enclosed by the surface. We must evaluate n d directly. ince the surface is the unit sphere, the position vector r = xi + yj + zk will also be an outwardly pointing unit normal (since x + y + z = on the surface. Taking n = r, we have that n =. Therefore the flux evaluates to n d = d (3 A diagram of the solid is as follows: = surface area of the unit sphere = π. Z X.5.5 Y The outward flux can be calculated as n where is the closed surface of the box, is the vector field, and n is an outwardly pointing unit normal vector. The surface consists of six open surfaces: the six faces of the box. We can evaluate the flux integral directly by calculating the outward flux through each face: n = n d+ n d+ 3 n d+ n d+ 5 n d+ 6 n d.
5 We represent each open surface follows: is the base of the box which lies in the plane z = 3 (and is therefore parallel to the x-y plane. An outwardly pointing unit normal is n = k. Restricted to, the vector field is given by Therefore over, = xi + yj + 9k, for x 3, y. n = (xi + yj + 9k ( k = 9. n d = ( 9 d = 9 d. ince d is just the area of, which is a rectangle of area =, so d = n d = 9 = 8. is the lid of the box which lies in the plane z = 5. An outwardly pointing unit normal is n = k. Restricted to, the vector field is given by Therefore over, = xi + yj + 5k, for x 3, y. n = (xi + yj + 5k k = 5. n d = (5 d = 5 d. ince d is just the area of, which is a rectangle of area =, so d = n d = 5 = 3. 3 is the back of the box which lies in the plane x =. An outwardly pointing unit normal is n = i. Restricted to 3, the vector field is given by = i + yj + 3zk, for y, 3 z 5. 5
6 Therefore over 3, n = (i + yj + 3zk ( i = n d = ( d = d. ince d is just the area of 3, which is a rectangle of area =, so 3 3 d = 3 n d =. is the front of the box which lies in the plane x = 3. An outwardly pointing unit normal is n = i. Restricted to, the vector field is given by Therefore over, = 3i + yj + 3zk, for y, 3 z 5. n = (3i + yj + 3zk (i = 3. n d = (3 d = 3 d. ince d is just the area of, which is a rectangle of area =, so d = n d = 3 = 6. 5 is the left side of the box which lies in the plane y = (the x-z plane. An outwardly pointing unit normal is n = j. Restricted to 5, the vector field is given by = xi + 3zk, for x 3, 3 z 5. Therefore over 5, n = (xi + 3zk ( j =. n d = ( d =
7 6 is the right side of the box which lies in the plane y =. An outwardly pointing unit normal is n = j. Restricted to 6, the vector field is given by Therefore over 6, = xi + j + 3zk, for x 3, 3 z 5. n = (xi + j + 3zk (j = n d = ( d = d. ince d is just the area of 6, which is a rectangle of area =, so 6 6 d = 6 n d = = 8. Putting all of this information together gives n = n d+ n d+ n d+ 3 n d+ 5 n d+ 6 n d = ( = 6. Using the divergence theorem, we can also calculate the outward flux as div d, where is the region enclosed by (ie. the box. We can calculate The outward flux is then div = x (x + y (y + (3z = = 6. z div d = 6 d = 6 (vol. of box = 6 ( = 6. We have therefore verified the divergence theorem. In this case, it is a lot less work to calculate the volume integral compared to the flux integral. 7
8 ( Use the divergence theorem. The region (in this case a sphere of radius 5 can be represented as = {(r, θ, φ r 5, φ π, θ π} in term of spherical polar coordinates. We also have div = x (3x + y (y + (5z = =. z Hence by the divergence theorem the flux out of the surface is π div d = = ( π π 5 ( π dθ = π 5 3 = π. r sin φ dr dφ dθ ( 5 sin φ dφ r dr Alternatively, we could make the observation that div d = d = volume of sphere of radius 5 ( = 3 π53 = π. (5 We need to find n d. By Gauss divergence theorem this is equal to div d. div = x (x + y (3y + z (6z = =. In cylindrical polar coordinates, the cone is z = (r cos θ + (r sin θ = r z = r in this case since z. The region in R 3 is = {(r, θ, z z, θ π, r z}. 8
9 o flux = = = 5 = 5 π z π [ 3 z3 = 8π 3. z dz ] r dr dθ dz z dθ dz π π (6 = (x 3 + xy + xz i + (x y + y 3 + yz j + (x z + y z + z 3 k so The sphere is described by div = x (x3 + xy + xz + y (x y + y 3 + yz + z (x z + y z + z 3 dθ = (3x + y + z + (x + 3y + z +(x + y + 3z = 5r. = {(r, θ, φ r a, θ π, φ π}. o by Gauss divergence theorem, the flux across the surface of the sphere = a π π a = 5 r dr [ ] a = 5 5 r5 (5r r sin φ dφ dθ dr π = 5 5 a5 π = πa 5. dθ π [θ] π [ cos φ]π sin φ dφ 9
ES.182A Topic 45 Notes Jeremy Orloff
E.8A Topic 45 Notes Jeremy Orloff 45 More surface integrals; divergence theorem Note: Much of these notes are taken directly from the upplementary Notes V0 by Arthur Mattuck. 45. Closed urfaces A closed
More informationOne side of each sheet is blank and may be used as scratch paper.
Math 244 Spring 2017 (Practice) Final 5/11/2017 Time Limit: 2 hours Name: No calculators or notes are allowed. One side of each sheet is blank and may be used as scratch paper. heck your answers whenever
More informationMATH 228: Calculus III (FALL 2016) Sample Problems for FINAL EXAM SOLUTIONS
MATH 228: Calculus III (FALL 216) Sample Problems for FINAL EXAM SOLUTIONS MATH 228 Page 2 Problem 1. (2pts) Evaluate the line integral C xy dx + (x + y) dy along the parabola y x2 from ( 1, 1) to (2,
More informationMath 3435 Homework Set 11 Solutions 10 Points. x= 1,, is in the disk of radius 1 centered at origin
Math 45 Homework et olutions Points. ( pts) The integral is, x + z y d = x + + z da 8 6 6 where is = x + z 8 x + z = 4 o, is the disk of radius centered on the origin. onverting to polar coordinates then
More informationMa 1c Practical - Solutions to Homework Set 7
Ma 1c Practical - olutions to omework et 7 All exercises are from the Vector Calculus text, Marsden and Tromba (Fifth Edition) Exercise 7.4.. Find the area of the portion of the unit sphere that is cut
More informationThe Divergence Theorem
Math 1a The Divergence Theorem 1. Parameterize the boundary of each of the following with positive orientation. (a) The solid x + 4y + 9z 36. (b) The solid x + y z 9. (c) The solid consisting of all points
More informationMath 233. Practice Problems Chapter 15. i j k
Math 233. Practice Problems hapter 15 1. ompute the curl and divergence of the vector field F given by F (4 cos(x 2 ) 2y)i + (4 sin(y 2 ) + 6x)j + (6x 2 y 6x + 4e 3z )k olution: The curl of F is computed
More informationName: Date: 12/06/2018. M20550 Calculus III Tutorial Worksheet 11
1. ompute the surface integral M255 alculus III Tutorial Worksheet 11 x + y + z) d, where is a surface given by ru, v) u + v, u v, 1 + 2u + v and u 2, v 1. olution: First, we know x + y + z) d [ ] u +
More informationCalculus III. Math 233 Spring Final exam May 3rd. Suggested solutions
alculus III Math 33 pring 7 Final exam May 3rd. uggested solutions This exam contains twenty problems numbered 1 through. All problems are multiple choice problems, and each counts 5% of your total score.
More informationMath 23b Practice Final Summer 2011
Math 2b Practice Final Summer 211 1. (1 points) Sketch or describe the region of integration for 1 x y and interchange the order to dy dx dz. f(x, y, z) dz dy dx Solution. 1 1 x z z f(x, y, z) dy dx dz
More informationMath 234 Review Problems for the Final Exam
Math 234 eview Problems for the Final Eam Marc Conrad ecember 13, 2007 irections: Answer each of the following questions. Pages 1 and 2 contain the problems. The solutions are on pages 3 through 7. Problem
More informationSolutions for the Practice Final - Math 23B, 2016
olutions for the Practice Final - Math B, 6 a. True. The area of a surface is given by the expression d, and since we have a parametrization φ x, y x, y, f x, y with φ, this expands as d T x T y da xy
More informationHOMEWORK 8 SOLUTIONS
HOMEWOK 8 OLUTION. Let and φ = xdy dz + ydz dx + zdx dy. let be the disk at height given by: : x + y, z =, let X be the region in 3 bounded by the cone and the disk. We orient X via dx dy dz, then by definition
More informationPage Problem Score Max Score a 8 12b a b 10 14c 6 6
Fall 14 MTH 34 FINAL EXAM December 8, 14 Name: PID: Section: Instructor: DO NOT WRITE BELOW THIS LINE. Go to the next page. Page Problem Score Max Score 1 5 5 1 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1 5 11 1 3 1a
More informationPRACTICE PROBLEMS. Please let me know if you find any mistakes in the text so that i can fix them. 1. Mixed partial derivatives.
PRACTICE PROBLEMS Please let me know if you find any mistakes in the text so that i can fix them. 1.1. Let Show that f is C 1 and yet How is that possible? 1. Mixed partial derivatives f(x, y) = {xy x
More informationv n ds where v = x z 2, 0,xz+1 and S is the surface that
M D T P. erif the divergence theorem for d where is the surface of the sphere + + = a.. Calculate the surface integral encloses the solid region + +,. (a directl, (b b the divergence theorem. v n d where
More informationMath 11 Fall 2016 Final Practice Problem Solutions
Math 11 Fall 216 Final Practice Problem olutions Here are some problems on the material we covered since the second midterm. This collection of problems is not intended to mimic the final in length, content,
More informationS12.1 SOLUTIONS TO PROBLEMS 12 (ODD NUMBERS)
OLUTION TO PROBLEM 2 (ODD NUMBER) 2. The electric field is E = φ = 2xi + 2y j and at (2, ) E = 4i + 2j. Thus E = 2 5 and its direction is 2i + j. At ( 3, 2), φ = 6i + 4 j. Thus the direction of most rapid
More informationMATHS 267 Answers to Stokes Practice Dr. Jones
MATH 267 Answers to tokes Practice Dr. Jones 1. Calculate the flux F d where is the hemisphere x2 + y 2 + z 2 1, z > and F (xz + e y2, yz, z 2 + 1). Note: the surface is open (doesn t include any of the
More informationMATH 52 FINAL EXAM SOLUTIONS
MAH 5 FINAL EXAM OLUION. (a) ketch the region R of integration in the following double integral. x xe y5 dy dx R = {(x, y) x, x y }. (b) Express the region R as an x-simple region. R = {(x, y) y, x y }
More informationG G. G. x = u cos v, y = f(u), z = u sin v. H. x = u + v, y = v, z = u v. 1 + g 2 x + g 2 y du dv
1. Matching. Fill in the appropriate letter. 1. ds for a surface z = g(x, y) A. r u r v du dv 2. ds for a surface r(u, v) B. r u r v du dv 3. ds for any surface C. G x G z, G y G z, 1 4. Unit normal N
More information( ) = x( u, v) i + y( u, v) j + z( u, v) k
Math 8 ection 16.6 urface Integrals The relationship between surface integrals and surface area is much the same as the relationship between line integrals and arc length. uppose f is a function of three
More informationPractice Problems for Exam 3 (Solutions) 1. Let F(x, y) = xyi+(y 3x)j, and let C be the curve r(t) = ti+(3t t 2 )j for 0 t 2. Compute F dr.
1. Let F(x, y) xyi+(y 3x)j, and let be the curve r(t) ti+(3t t 2 )j for t 2. ompute F dr. Solution. F dr b a 2 2 F(r(t)) r (t) dt t(3t t 2 ), 3t t 2 3t 1, 3 2t dt t 3 dt 1 2 4 t4 4. 2. Evaluate the line
More informationMULTIVARIABLE INTEGRATION
MULTIVARIABLE INTEGRATION (SPHERICAL POLAR COORDINATES) Question 1 a) Determine with the aid of a diagram an expression for the volume element in r, θ, ϕ. spherical polar coordinates, ( ) [You may not
More informationContents. MATH 32B-2 (18W) (L) G. Liu / (TA) A. Zhou Calculus of Several Variables. 1 Multiple Integrals 3. 2 Vector Fields 9
MATH 32B-2 (8W) (L) G. Liu / (TA) A. Zhou Calculus of Several Variables Contents Multiple Integrals 3 2 Vector Fields 9 3 Line and Surface Integrals 5 4 The Classical Integral Theorems 9 MATH 32B-2 (8W)
More informationMath 20A lecture 22 Integral theorems in 3D
Math 2A lecture 22 p. 1/12 Math 2A lecture 22 Integral theorems in 3D T.J. Barnet-Lamb tbl@brandeis.edu Brandeis University Math 2A lecture 22 p. 2/12 Announcements Homework eleven due Friday. Homework
More informationNote: Each problem is worth 14 points except numbers 5 and 6 which are 15 points. = 3 2
Math Prelim II Solutions Spring Note: Each problem is worth points except numbers 5 and 6 which are 5 points. x. Compute x da where is the region in the second quadrant between the + y circles x + y and
More informationJim Lambers MAT 280 Summer Semester Practice Final Exam Solution. dy + xz dz = x(t)y(t) dt. t 3 (4t 3 ) + e t2 (2t) + t 7 (3t 2 ) dt
Jim Lambers MAT 28 ummer emester 212-1 Practice Final Exam olution 1. Evaluate the line integral xy dx + e y dy + xz dz, where is given by r(t) t 4, t 2, t, t 1. olution From r (t) 4t, 2t, t 2, we obtain
More information53. Flux Integrals. Here, R is the region over which the double integral is evaluated.
53. Flux Integrals Let be an orientable surface within 3. An orientable surface, roughly speaking, is one with two distinct sides. At any point on an orientable surface, there exists two normal vectors,
More informationMATH 280 Multivariate Calculus Fall Integration over a surface. da. A =
MATH 28 Multivariate Calculus Fall 212 Integration over a surface Given a surface S in space, we can (conceptually) break it into small pieces each of which has area da. In me cases, we will add up these
More informationCalculus III 2004 Summer Practice Final 8/3/2004
.. Calculus III 4 ummer Practice Final 8/3/4. Compute the following limits if they exist: (a) lim (x,y) (,) e xy x+. cos x (b) lim x. (x,y) (,) x 4 +y 4 (a) ince lim (x,y) (,) exy and lim x + 6 in a (x,y)
More information( ) ( ) ( ) ( ) Calculus III - Problem Drill 24: Stokes and Divergence Theorem
alculus III - Problem Drill 4: tokes and Divergence Theorem Question No. 1 of 1 Instructions: (1) Read the problem and answer choices carefully () Work the problems on paper as needed () Pick the 1. Use
More informationAssignment 11 Solutions
. Evaluate Math 9 Assignment olutions F n d, where F bxy,bx y,(x + y z and is the closed surface bounding the region consisting of the solid cylinder x + y a and z b. olution This is a problem for which
More information7a3 2. (c) πa 3 (d) πa 3 (e) πa3
1.(6pts) Find the integral x, y, z d S where H is the part of the upper hemisphere of H x 2 + y 2 + z 2 = a 2 above the plane z = a and the normal points up. ( 2 π ) Useful Facts: cos = 1 and ds = ±a sin
More informationFigure 25:Differentials of surface.
2.5. Change of variables and Jacobians In the previous example we saw that, once we have identified the type of coordinates which is best to use for solving a particular problem, the next step is to do
More informationFinal exam (practice 1) UCLA: Math 32B, Spring 2018
Instructor: Noah White Date: Final exam (practice 1) UCLA: Math 32B, Spring 218 This exam has 7 questions, for a total of 8 points. Please print your working and answers neatly. Write your solutions in
More informationMath Review for Exam 3
1. ompute oln: (8x + 36xy)ds = Math 235 - Review for Exam 3 (8x + 36xy)ds, where c(t) = (t, t 2, t 3 ) on the interval t 1. 1 (8t + 36t 3 ) 1 + 4t 2 + 9t 4 dt = 2 3 (1 + 4t2 + 9t 4 ) 3 2 1 = 2 3 ((14)
More informationIntegral Theorems. September 14, We begin by recalling the Fundamental Theorem of Calculus, that the integral is the inverse of the derivative,
Integral Theorems eptember 14, 215 1 Integral of the gradient We begin by recalling the Fundamental Theorem of Calculus, that the integral is the inverse of the derivative, F (b F (a f (x provided f (x
More informationMath Exam IV - Fall 2011
Math 233 - Exam IV - Fall 2011 December 15, 2011 - Renato Feres NAME: STUDENT ID NUMBER: General instructions: This exam has 16 questions, each worth the same amount. Check that no pages are missing and
More informationx + ye z2 + ze y2, y + xe z2 + ze x2, z and where T is the
1.(8pts) Find F ds where F = x + ye z + ze y, y + xe z + ze x, z and where T is the T surface in the pictures. (The two pictures are two views of the same surface.) The boundary of T is the unit circle
More informationMAC2313 Final A. (5 pts) 1. How many of the following are necessarily true? i. The vector field F = 2x + 3y, 3x 5y is conservative.
MAC2313 Final A (5 pts) 1. How many of the following are necessarily true? i. The vector field F = 2x + 3y, 3x 5y is conservative. ii. The vector field F = 5(x 2 + y 2 ) 3/2 x, y is radial. iii. All constant
More informationSOLUTIONS TO THE FINAL EXAM. December 14, 2010, 9:00am-12:00 (3 hours)
SOLUTIONS TO THE 18.02 FINAL EXAM BJORN POONEN December 14, 2010, 9:00am-12:00 (3 hours) 1) For each of (a)-(e) below: If the statement is true, write TRUE. If the statement is false, write FALSE. (Please
More informationName: Instructor: Lecture time: TA: Section time:
Math 222 Final May 11, 29 Name: Instructor: Lecture time: TA: Section time: INSTRUCTIONS READ THIS NOW This test has 1 problems on 16 pages worth a total of 2 points. Look over your test package right
More informationLine and Surface Integrals. Stokes and Divergence Theorems
Math Methods 1 Lia Vas Line and urface Integrals. tokes and Divergence Theorems Review of urves. Intuitively, we think of a curve as a path traced by a moving particle in space. Thus, a curve is a function
More information(a) The points (3, 1, 2) and ( 1, 3, 4) are the endpoints of a diameter of a sphere.
MATH 4 FINAL EXAM REVIEW QUESTIONS Problem. a) The points,, ) and,, 4) are the endpoints of a diameter of a sphere. i) Determine the center and radius of the sphere. ii) Find an equation for the sphere.
More informationDO NOT BEGIN THIS TEST UNTIL INSTRUCTED TO START
Math 265 Student name: KEY Final Exam Fall 23 Instructor & Section: This test is closed book and closed notes. A (graphing) calculator is allowed for this test but cannot also be a communication device
More informationKeble College - Hilary 2015 CP3&4: Mathematical methods I&II Tutorial 4 - Vector calculus and multiple integrals II
Keble ollege - Hilary 2015 P3&4: Mathematical methods I&II Tutorial 4 - Vector calculus and multiple integrals II Tomi Johnson 1 Prepare full solutions to the problems with a self assessment of your progress
More information1. (a) (5 points) Find the unit tangent and unit normal vectors T and N to the curve. r (t) = 3 cos t, 0, 3 sin t, r ( 3π
1. a) 5 points) Find the unit tangent and unit normal vectors T and N to the curve at the point P 3, 3π, r t) 3 cos t, 4t, 3 sin t 3 ). b) 5 points) Find curvature of the curve at the point P. olution:
More informationEE2007: Engineering Mathematics II Vector Calculus
EE2007: Engineering Mathematics II Vector Calculus Ling KV School of EEE, NTU ekvling@ntu.edu.sg Rm: S2-B2a-22 Ver: August 28, 2010 Ver 1.6: Martin Adams, Sep 2009 Ver 1.5: Martin Adams, August 2008 Ver
More information6. Vector Integral Calculus in Space
6. Vector Integral alculus in pace 6A. Vector Fields in pace 6A-1 Describegeometricallythefollowingvectorfields: a) xi +yj +zk ρ b) xi zk 6A-2 Write down the vector field where each vector runs from (x,y,z)
More informationMathematics (Course B) Lent Term 2005 Examples Sheet 2
N12d Natural Sciences, Part IA Dr M. G. Worster Mathematics (Course B) Lent Term 2005 Examples Sheet 2 Please communicate any errors in this sheet to Dr Worster at M.G.Worster@damtp.cam.ac.uk. Note that
More informationMATH H53 : Final exam
MATH H53 : Final exam 11 May, 18 Name: You have 18 minutes to answer the questions. Use of calculators or any electronic items is not permitted. Answer the questions in the space provided. If you run out
More informationSolutions to the Final Exam, Math 53, Summer 2012
olutions to the Final Exam, Math 5, ummer. (a) ( points) Let be the boundary of the region enclosedby the parabola y = x and the line y = with counterclockwise orientation. alculate (y + e x )dx + xdy.
More informationEE2007: Engineering Mathematics II Vector Calculus
EE2007: Engineering Mathematics II Vector Calculus Ling KV School of EEE, NTU ekvling@ntu.edu.sg Rm: S2-B2b-22 Ver 1.1: Ling KV, October 22, 2006 Ver 1.0: Ling KV, Jul 2005 EE2007/Ling KV/Aug 2006 EE2007:
More informationMATH 0350 PRACTICE FINAL FALL 2017 SAMUEL S. WATSON. a c. b c.
MATH 35 PRACTICE FINAL FALL 17 SAMUEL S. WATSON Problem 1 Verify that if a and b are nonzero vectors, the vector c = a b + b a bisects the angle between a and b. The cosine of the angle between a and c
More informationMath 31CH - Spring Final Exam
Math 3H - Spring 24 - Final Exam Problem. The parabolic cylinder y = x 2 (aligned along the z-axis) is cut by the planes y =, z = and z = y. Find the volume of the solid thus obtained. Solution:We calculate
More information1 + f 2 x + f 2 y dy dx, where f(x, y) = 2 + 3x + 4y, is
1. The value of the double integral (a) 15 26 (b) 15 8 (c) 75 (d) 105 26 5 4 0 1 1 + f 2 x + f 2 y dy dx, where f(x, y) = 2 + 3x + 4y, is 2. What is the value of the double integral interchange the order
More informationMultiple Integrals and Vector Calculus (Oxford Physics) Synopsis and Problem Sets; Hilary 2015
Multiple Integrals and Vector Calculus (Oxford Physics) Ramin Golestanian Synopsis and Problem Sets; Hilary 215 The outline of the material, which will be covered in 14 lectures, is as follows: 1. Introduction
More informationThe Basic Definition of Flux
The Basic Definition of Flux Imagine holding a rectangular wire loop of area A in front of a fan. The volume of air flowing through the loop each second depends on the angle between the loop and the direction
More informationProblem Solving 1: Line Integrals and Surface Integrals
A. Line Integrals MASSACHUSETTS INSTITUTE OF TECHNOLOY Department of Physics Problem Solving 1: Line Integrals and Surface Integrals The line integral of a scalar function f ( xyz),, along a path C is
More informationPractice Problems for the Final Exam
Math 114 Spring 2017 Practice Problems for the Final Exam 1. The planes 3x + 2y + z = 6 and x + y = 2 intersect in a line l. Find the distance from the origin to l. (Answer: 24 3 ) 2. Find the area of
More informationMATH 332: Vector Analysis Summer 2005 Homework
MATH 332, (Vector Analysis), Summer 2005: Homework 1 Instructor: Ivan Avramidi MATH 332: Vector Analysis Summer 2005 Homework Set 1. (Scalar Product, Equation of a Plane, Vector Product) Sections: 1.9,
More informationLine, surface and volume integrals
www.thestudycampus.com Line, surface and volume integrals In the previous chapter we encountered continuously varying scalar and vector fields and discussed the action of various differential operators
More informationMATH 280 Multivariate Calculus Fall Integrating a vector field over a curve
MATH 280 Multivariate alculus Fall 2012 Definition Integrating a vector field over a curve We are given a vector field F and an oriented curve in the domain of F as shown in the figure on the left below.
More informationxy 2 e 2z dx dy dz = 8 3 (1 e 4 ) = 2.62 mc. 12 x2 y 3 e 2z 2 m 2 m 2 m Figure P4.1: Cube of Problem 4.1.
Problem 4.1 A cube m on a side is located in the first octant in a Cartesian coordinate system, with one of its corners at the origin. Find the total charge contained in the cube if the charge density
More information(a) 0 (b) 1/4 (c) 1/3 (d) 1/2 (e) 2/3 (f) 3/4 (g) 1 (h) 4/3
Math 114 Practice Problems for Test 3 omments: 0. urface integrals, tokes Theorem and Gauss Theorem used to be in the Math40 syllabus until last year, so we will look at some of the questions from those
More informationRead this cover page completely before you start.
I affirm that I have worked this exam independently, without texts, outside help, integral tables, calculator, solutions, or software. (Please sign legibly.) Read this cover page completely before you
More informationProblem Points S C O R E
MATH 34F Final Exam March 19, 13 Name Student I # Your exam should consist of this cover sheet, followed by 7 problems. Check that you have a complete exam. Unless otherwise indicated, show all your work
More information14.7 The Divergence Theorem
14.7 The Divergence Theorem The divergence of a vector field is a derivative of a sort that measures the rate of flow per unit of volume at a point. A field where such flow doesn't occur is called 'divergence
More informationSections minutes. 5 to 10 problems, similar to homework problems. No calculators, no notes, no books, no phones. No green book needed.
MTH 34 Review for Exam 4 ections 16.1-16.8. 5 minutes. 5 to 1 problems, similar to homework problems. No calculators, no notes, no books, no phones. No green book needed. Review for Exam 4 (16.1) Line
More informationMath 234 Exam 3 Review Sheet
Math 234 Exam 3 Review Sheet Jim Brunner LIST OF TOPIS TO KNOW Vector Fields lairaut s Theorem & onservative Vector Fields url Divergence Area & Volume Integrals Using oordinate Transforms hanging the
More informationMath Double Integrals in Polar Coordinates
Math 213 - Double Integrals in Polar Coordinates Peter A. Perry University of Kentucky October 22, 2018 Homework Re-read section 15.3 Begin work on 1-4, 5-31 (odd), 35, 37 from 15.3 Read section 15.4 for
More information14.1. Multiple Integration. Iterated Integrals and Area in the Plane. Iterated Integrals. Iterated Integrals. MAC2313 Calculus III - Chapter 14
14 Multiple Integration 14.1 Iterated Integrals and Area in the Plane Objectives Evaluate an iterated integral. Use an iterated integral to find the area of a plane region. Copyright Cengage Learning.
More informationF ds, where F and S are as given.
Math 21a Integral Theorems Review pring, 29 1 For these problems, find F dr, where F and are as given. a) F x, y, z and is parameterized by rt) t, t, t t 1) b) F x, y, z and is parameterized by rt) t,
More informationMultiple Integrals and Vector Calculus: Synopsis
Multiple Integrals and Vector Calculus: Synopsis Hilary Term 28: 14 lectures. Steve Rawlings. 1. Vectors - recap of basic principles. Things which are (and are not) vectors. Differentiation and integration
More informationMath 11 Fall 2007 Practice Problem Solutions
Math 11 Fall 27 Practice Problem olutions Here are some problems on the material we covered since the second midterm. This collection of problems is not intended to mimic the final in length, content,
More informationMath 11 Fall 2018 Practice Final Exam
Math 11 Fall 218 Practice Final Exam Disclaimer: This practice exam should give you an idea of the sort of questions we may ask on the actual exam. Since the practice exam (like the real exam) is not long
More informationMath 263 Final. (b) The cross product is. i j k c. =< c 1, 1, 1 >
Math 63 Final Problem 1: [ points, 5 points to each part] Given the points P : (1, 1, 1), Q : (1,, ), R : (,, c 1), where c is a parameter, find (a) the vector equation of the line through P and Q. (b)
More informationFigure 21:The polar and Cartesian coordinate systems.
Figure 21:The polar and Cartesian coordinate systems. Coordinate systems in R There are three standard coordinate systems which are used to describe points in -dimensional space. These coordinate systems
More informationSolutions to Sample Questions for Final Exam
olutions to ample Questions for Final Exam Find the points on the surface xy z 3 that are closest to the origin. We use the method of Lagrange Multipliers, with f(x, y, z) x + y + z for the square of the
More informationdensity = N A where the vector di erential aread A = ^n da, and ^n is the normaltothat patch of surface. Solid angle
Gauss Law Field lines and Flux Field lines are drawn so that E is tangent to the field line at every point. Field lines give us information about the direction of E, but also about its magnitude, since
More informationMath 350 Solutions for Final Exam Page 1. Problem 1. (10 points) (a) Compute the line integral. F ds C. z dx + y dy + x dz C
Math 35 Solutions for Final Exam Page Problem. ( points) (a) ompute the line integral F ds for the path c(t) = (t 2, t 3, t) with t and the vector field F (x, y, z) = xi + zj + xk. (b) ompute the line
More informationMcGill University April 20, Advanced Calculus for Engineers
McGill University April 0, 016 Faculty of Science Final examination Advanced Calculus for Engineers Math 64 April 0, 016 Time: PM-5PM Examiner: Prof. R. Choksi Associate Examiner: Prof. A. Hundemer Student
More information29.3. Integral Vector Theorems. Introduction. Prerequisites. Learning Outcomes
Integral ector Theorems 9. Introduction arious theorems exist relating integrals involving vectors. Those involving line, surface and volume integrals are introduced here. They are the multivariable calculus
More information1. Find and classify the extrema of h(x, y) = sin(x) sin(y) sin(x + y) on the square[0, π] [0, π]. (Keep in mind there is a boundary to check out).
. Find and classify the extrema of hx, y sinx siny sinx + y on the square[, π] [, π]. Keep in mind there is a boundary to check out. Solution: h x cos x sin y sinx + y + sin x sin y cosx + y h y sin x
More informationSummary: Curvilinear Coordinates
Physics 2460 Electricity and Magnetism I, Fall 2007, Lecture 10 1 Summary: Curvilinear Coordinates 1. Summary of Integral Theorems 2. Generalized Coordinates 3. Cartesian Coordinates: Surfaces of Constant
More information1. For each function, find all of its critical points and then classify each point as a local extremum or saddle point.
Solutions Review for Exam # Math 6. For each function, find all of its critical points and then classify each point as a local extremum or saddle point. a fx, y x + 6xy + y Solution.The gradient of f is
More information(b) Find the range of h(x, y) (5) Use the definition of continuity to explain whether or not the function f(x, y) is continuous at (0, 0)
eview Exam Math 43 Name Id ead each question carefully. Avoid simple mistakes. Put a box around the final answer to a question (use the back of the page if necessary). For full credit you must show your
More informationon an open connected region D, then F is conservative on D. (c) If curl F=curl G on R 3, then C F dr = C G dr for all closed path C.
. (5%) Determine the statement is true ( ) or false ( ). 微甲 -4 班期末考解答和評分標準 (a) If f(x, y) is continuous on the rectangle R = {(x, y) a x b, c y d} except for finitely many points, then f(x, y) is integrable
More informationPage Points Score Total: 210. No more than 200 points may be earned on the exam.
Name: PID: Section: Recitation Instructor: DO NOT WRITE BELOW THIS LINE. GO ON TO THE NEXT PAGE. Page Points Score 3 18 4 18 5 18 6 18 7 18 8 18 9 18 10 21 11 21 12 21 13 21 Total: 210 No more than 200
More informationSOME PROBLEMS YOU SHOULD BE ABLE TO DO
OME PROBLEM YOU HOULD BE ABLE TO DO I ve attempted to make a list of the main calculations you should be ready for on the exam, and included a handful of the more important formulas. There are no examples
More informationTom Robbins WW Prob Lib1 Math , Fall 2001
Tom Robbins WW Prob Lib Math 220-2, Fall 200 WeBWorK assignment due 9/7/0 at 6:00 AM..( pt) A child walks due east on the deck of a ship at 3 miles per hour. The ship is moving north at a speed of 7 miles
More information18.02 Multivariable Calculus Fall 2007
MIT OpenCourseWare http://ocw.mit.edu 18.02 Multivariable Calculus Fall 2007 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. V9. Surface Integrals Surface
More informationMATH 2400 Final Exam Review Solutions
MATH Final Eam eview olutions. Find an equation for the collection of points that are equidistant to A, 5, ) and B6,, ). AP BP + ) + y 5) + z ) 6) y ) + z + ) + + + y y + 5 + z 6z + 9 + 6 + y y + + z +
More informationFinal Exam Review Sheet : Comments and Selected Solutions
MATH 55 Applied Honors alculus III Winter Final xam Review heet : omments and elected olutions Note: The final exam will cover % among topics in chain rule, linear approximation, maximum and minimum values,
More informationEXAM 2 ANSWERS AND SOLUTIONS, MATH 233 WEDNESDAY, OCTOBER 18, 2000
EXAM 2 ANSWERS AND SOLUTIONS, MATH 233 WEDNESDAY, OCTOBER 18, 2000 This examination has 30 multiple choice questions. Problems are worth one point apiece, for a total of 30 points for the whole examination.
More informationGeometry and Motion Selected answers to Sections A and C Dwight Barkley 2016
MA34 Geometry and Motion Selected answers to Sections A and C Dwight Barkley 26 Example Sheet d n+ = d n cot θ n r θ n r = Θθ n i. 2. 3. 4. Possible answers include: and with opposite orientation: 5..
More informationSummary for Vector Calculus and Complex Calculus (Math 321) By Lei Li
Summary for Vector alculus and omplex alculus (Math 321) By Lei Li 1 Vector alculus 1.1 Parametrization urves, surfaces, or volumes can be parametrized. Below, I ll talk about 3D case. Suppose we use e
More informationMAT 211 Final Exam. Spring Jennings. Show your work!
MAT 211 Final Exam. pring 215. Jennings. how your work! Hessian D = f xx f yy (f xy ) 2 (for optimization). Polar coordinates x = r cos(θ), y = r sin(θ), da = r dr dθ. ylindrical coordinates x = r cos(θ),
More informationNote 2 - Flux. Mikael B. Steen August 22, 2011
Note 2 - Flux Mikael B. teen August 22, 211 1 What is flux? In physics flux is the measure of the flow of some quantity through a surface. For example imagine the flow of air or water through a filter.
More information