Physic 231 Lecture 33
|
|
- Evan Phillips
- 5 years ago
- Views:
Transcription
1 Physc 231 Lecture 33 Man pnts f tday s lecture: eat and heat capacty: Q cm Phase transtns and latent heat: Q Lm ( ) eat flw Q k 2 1 t L Examples f heat cnductvty, R values fr nsulatrs Cnvectn R L / k Radatn P σ e 4 where σ 5.67x10-8 W / ( K 4 )
2 eat and heat capacty We saw that fr atms r mlecules n an deal gas s <KE>f/2k B. In general, the atms r mlecules n matter ncrease n energy f the bject s heated. hs s heat energy. f s the number f degrees f freedm (3 fr atm). eat Q s the energy that flws frm a ht bject t a cld bject slely because f the dfference n. When the heat flw s suffcent, the tw bjects reach the same temperature and we say they are n thermal equlbrum at the same. Fr a mnatmc deal gas at cnstant vlume Q E th U U f U f 2 Nk b f f 2 Nk b f 2 Nk b Q f 2 Nk f b 2 nr nc c mlar,v f/2r s the heat capacty per mle at mlar,v cnstant vlume fr an deal gas Fr many ther materals, the relatnshp between heat transferred and temperature change s gven by: (usually transferred at cnstant V r P) Q cm c sthe specfc m s the mass and cm heat capacty per unt mass the ttal ( f ) heat capacty f the bject.
3 Example f equlbratn and energy cnservatn t a fabrcatn plant, a ht frgng has a mass f 75 kg and a specfc heat capacty f 430 J/(kg C). harden t, the frgng s quenched by mmersn n 710 kg f l that has a temperature f 32 C and a specfc heat capacty f 645 cal/(kg C). he fnal temperature f the l and frgng at thermal equlbrum s 47 C. ssumng that heat flws nly between the frgng and the l, determne the ntal temperature f the frgng. Energy cnservatn: Q c m Q c m Q + Q 0 l ( ) l l l ( f l ) 4.19J cal f cl 645cal/(kg C) 2700kJ/(kg C) ( ) ( ) c m c m f l l f l f + f ( ) c m l l f l c m ( ) c m l l f l c m Q Q l m m l c 75 kg 710 kg ( )( ) C) ( 75kg) 430J/kg/ C 2700J / (kg C) 710kg C 47 C 939 C c l 645cal/kg/ C + 430J / (kg f l,0,0? 47 C 32 C
4 Quz 100 kg mass f water at a temperature f 30 C s drpped nt a thermally slated vessel cntanng 100 kg f water whch s a temperature f 10 C. fter system cmes t thermal equlbrum the fnal temperature s (useful nfrmatn: c water 4186 J/(kg C)) a) 10 C b) 15 C c) 20 C d) 25 C ( ) + c water 100kg( f 10 C) 0 c water 100kg f 30 C / / f 30 C + f 10 C 0 / / f ( 30 C +10 C) / 2 20 C
5 Questn 13.1 hermal Cntact I w bjects are made f the same materal, but have dfferent masses and temperatures. If the bjects are brught nt thermal cntact, whch ne wll have the temperature change f greater magntude? a) the ne wth the hgher ntal temperature b) the ne wth the lwer ntal temperature c) the ne wth the greater mass d) the ne wth the smaller mass e) the ne wth the hgher specfc heat Q heavy + Q lght 0 cm ( heavy f ) heavy + cm ( lght f ) lght 0 cm heavy ( f ) heavy cm ( lght f ) ( lght f ) lght m heavy m lght ( f ) heavy
6 Phase transtns he calrc curve that descrbes vs. Q. Regns wth a lnear ncrease crrespnd t a cnstant heat capacty where Q cm Q Q /(cm) he flat regns ccur when the system has a phase transtn. Fr water, there s ne where ce changes t water and ther where water changes t steam. If the pressure remans cnstant durng the phase change, the temperatures wll reman cnstant. he heat requred t change a mass m f the matter s gven by the latent heat L fr the phase change. Q Lm 4 5 Lfusn 33.5x10 J / kg Lvaprzat n 22.6x10 J / kg
7 Example When t rans, water vapr n the ar cndenses nt lqud water, and the energy s released. (a) w much energy s released when m (ne nch) f ran falls ver an area f 2.59x10 6 m 2 (ne square mle)? (b) If the average energy needed t heat ne hme fr a year s 1.5x10 11 J, hw many hmes can be heated wth the energy determned n part (a)? a) m water ρ water V water 1000kg / m 3 ( 2.59x10 6 m 2 )(.0254m) 6.58x10 7 kg Q released L vaprzatn m water ( 22.6x10 5 J / kg) ( 6.58x10 7 kg) 1.5x10 14 J b) n huses 1.5x10 11 J 1.5x10 14 J n huses 1000
8 eat flw here are three majr prcesses that transfer heat frm ne pnt t anther. Cnductn Cnvectn Radatn Cnvectn results frm the fact that ht bjects generally expand. hs decreases ther densty. If ths ccurs n a flud, the less dense ht flud rses and the clder denser flud falls.
9 Cnductn Cnductn cncerns the transfer f heat thrugh materals wthut cnvectn. Cnsder an cncrete wall f a heated garage. he utsde f the garage s at temperature 1 and the nterr f the garage s a temperature 2. he cnductve heat flw thrugh a prtn f the wall wth area s gven by: ( ) Q k 2 1 k t L L s the heat flw thrugh the wall, k s the thermal cnductvty f cncrete, and L s the thckness f the cncrete wall. Example: Calculate the heat flw thrugh a 2 m 2 sectn f a 20 cm thck cncrete wall when the utsde temperature s 0 C and the nsde temperature s 20 C. ssume the thermal cnductvty f the cncrete s 1.3 J/(s m C) Q t k L 1.3J / (s m C) 2m 2 0.2m ( )( 20 C) 260W
10 Quz w materals have the same nsulatng value f the same amunt f heat per secnd per square meter flws thrugh each due t the same temperature dfference. Ignrng ar cnvectn, what thckness f bdy fat s requred t gve the same nsulatng value as a nch thckness f ar? (k fat 0.2 J/(sm C), k ar J/(sm C)) a) 0.09 nches b) 0.7 nches c). 2.3 nches d) 4.2 nches want fat ar / / / / k fat L fat k ar L ar k fat L fat k ar L ar multply bth sdes f eq. by L fat L ar k fat L L fat ar L fat / / / k ar L fat L ar k fat k ar k ar L L fat ar L ar / k ar / / k ar ( 0.01nch) nch
11 Layered materals R values Cnsder the layered nsulatng structure at the rght. he area f each layer s the same. Each layer can have a dfferent thckness L and heat cnductvty k. ere the mprtant thng t remember s that we are cncerned wth a steady state slutn. here s n buld up f heat n any f these layers. Fr each layer ne has: L R k L L k t Q ere R t the R value f the th nsulatng layer. Large R value means better nsulatn and less heat lss n wnter. he ttal temperature dfference fr a layered structure s gven by the sum. R t Q R R.e.
12 Example f a layered structure w rds, ne f alumnum and the ther f cpper are jned end t end. he crss-sectnal area f each s 4.0x10-4 m 2, and the length f each s 0.04 m. he free end f the alumnum rd s kept at 302 C, whle the free end f the cpper rd s kept at 25 C. he lss f heat thrugh the sdes f the rds may be gnred. (a) What s the temperature at the alumnum-cpper nterface? (b) w much heat s cnducted thrugh the unt n 2.0 s? (k alum 238 J/(s m C), k Cu 397 J/(s m C)) a) alum R alum L alum k alum Cu L Cu k Cu alum Cu L alum k alum L Cu k Cu k Cu k alum alum + Cu Cu ( alum Cu +1) 2.67 Cu Cu C 25 C C nterface 25 C C C b) k Cu Cu 397 4x W 412W L Cu.04
13 Example f a layered structure w rds, ne f alumnum and the ther f cpper are jned end t end. he crss-sectnal area f each s 4.0x10-4 m 2, and the length f each s 0.04 m. he free end f the alumnum rd s kept at 302 C, whle the free end f the cpper rd s kept at 25 C. he lss f heat thrugh the sdes f the rds may be gnred. What s the temperature at the alumnum-cpper nterface between Cpper and lumnum? Useful nfrmatn: k alum 238J/(sm C) and : k Cu 397J/(sm C). a) alum R alum Cu R Cu R alum L alum.04m k alum 238J / (s m C) 1.681x10 4 s m 2 C / J R Cu L Cu.04m k Cu 397J / (s m C) 1.008x10 4 s m 2 C / J tt R tt R tt R Cu + R lum 2.69x10 4 s m 2 C / J tt R tt nt erface 25 C + Cu 25 C + R Cu nt erface 25 C + tt R tt R Cu 25 C + (302 25) C
Physics 231 Lecture 31
Physics 31 Lecture 31 Mi Main pints f tday s lecture: Heat and heat capacity: Q = cmδt Phase transitins and latent heat: Q = LΔm Mechanisms f heat flw. Cnductive heat flw ΔQ kat ( T1 ) H = = Δt L Examples
More informationConduction Heat Transfer
Cnductn Heat Transfer Practce prblems A steel ppe f cnductvty 5 W/m-K has nsde and utsde surface temperature f C and 6 C respectvely Fnd the heat flw rate per unt ppe length and flux per unt nsde and per
More information3-42. Chapter 15 Steady Heat Conduction. Heat Conduction in Cylinders and Spheres
Chapter 5 Steady Heat Cnductn Heat Cnductn n Cylnders and Spheres 3-64C When the dameter f cylnder s very small cmpared t ts length, t can be treated as an ndefntely lng cylnder. Cylndrcal rds can als
More informationLecture 12. Heat Exchangers. Heat Exchangers Chee 318 1
Lecture 2 Heat Exchangers Heat Exchangers Chee 38 Heat Exchangers A heat exchanger s used t exchange heat between tw fluds f dfferent temperatures whch are separated by a sld wall. Heat exchangers are
More informationDepartment of Civil Engineering & Applied Mechanics McGill University, Montreal, Quebec Canada
Department f Cvl Engneerng & Appled Mechancs McGll Unversty, Mntreal, Quebec Canada CIVE 90 THEMODYNAMICS & HEAT TANSFE Assgnment #6 SOUTIONS. Cnsder a.-m hgh and -m-wde duble-pane wndw cnsstng f tw 3-mmthck
More informationChapter 3, Solution 1C.
COSMOS: Cmplete Onlne Slutns Manual Organzatn System Chapter 3, Slutn C. (a If the lateral surfaces f the rd are nsulated, the heat transfer surface area f the cylndrcal rd s the bttm r the tp surface
More informationChem 204A, Fall 2004, Mid-term (II)
Frst tw letters f yur last name Last ame Frst ame McGll ID Chem 204A, Fall 2004, Md-term (II) Read these nstructns carefully befre yu start tal me: 2 hurs 50 mnutes (6:05 PM 8:55 PM) 1. hs exam has ttal
More informationChapter 6 : Gibbs Free Energy
Wnter 01 Chem 54: ntrductry hermdynamcs Chapter 6 : Gbbs Free Energy... 64 Defntn f G, A... 64 Mawell Relatns... 65 Gbbs Free Energy G(,) (ure substances)... 67 Gbbs Free Energy fr Mtures... 68 ΔG f deal
More informationTransient Conduction: Spatial Effects and the Role of Analytical Solutions
Transent Cnductn: Spatal Effects and the Rle f Analytcal Slutns Slutn t the Heat Equatn fr a Plane Wall wth Symmetrcal Cnvectn Cndtns If the lumped capactance apprxmatn can nt be made, cnsderatn must be
More information_J _J J J J J J J J _. 7 particles in the blue state; 3 particles in the red state: 720 configurations _J J J _J J J J J J J J _
Dsrder and Suppse I have 10 partcles that can be n ne f tw states ether the blue state r the red state. Hw many dfferent ways can we arrange thse partcles amng the states? All partcles n the blue state:
More informationComparison of Building Codes and Insulation in China and Iceland
Prceedngs Wrld Gethermal Cngress 00 Bal, Indnesa, 5-9 prl 00 Cmparsn f Buldng Cdes and Insulatn n Chna and Iceland Hayan Le and Pall Valdmarssn Tanjn Gethermal esearch & Tranng Centre, Tanjn Unversty,
More informationApproach: (Equilibrium) TD analysis, i.e., conservation eqns., state equations Issues: how to deal with
Schl f Aerspace Chemcal D: Mtvatn Prevus D Analyss cnsdered systems where cmpstn f flud was frzen fxed chemcal cmpstn Chemcally eactng Flw but there are numerus stuatns n prpulsn systems where chemcal
More informationSection 3: Detailed Solutions of Word Problems Unit 1: Solving Word Problems by Modeling with Formulas
Sectn : Detaled Slutns f Wrd Prblems Unt : Slvng Wrd Prblems by Mdelng wth Frmulas Example : The factry nvce fr a mnvan shws that the dealer pad $,5 fr the vehcle. If the stcker prce f the van s $5,, hw
More informationChapter 7. Systems 7.1 INTRODUCTION 7.2 MATHEMATICAL MODELING OF LIQUID LEVEL SYSTEMS. Steady State Flow. A. Bazoune
Chapter 7 Flud Systems and Thermal Systems 7.1 INTODUCTION A. Bazune A flud system uses ne r mre fluds t acheve ts purpse. Dampers and shck absrbers are eamples f flud systems because they depend n the
More informationPage 1. Physics 131: Lecture 14. Today s Agenda. Things that stay the same. Impulse and Momentum Non-constant forces
Physcs 131: Lecture 14 Today s Agenda Imulse and Momentum Non-constant forces Imulse-momentum momentum thm Conservaton of Lnear momentum Eternal/Internal forces Eamles Physcs 201: Lecture 1, Pg 1 Physcs
More informationFinal Exam Spring 2014 SOLUTION
Appled Opts H-464/564 C 594 rtland State nverst A. La Rsa Fnal am Sprng 14 SOLTION Name There are tw questns 1%) plus an ptnal bnus questn 1%) 1. Quarter wave plates and half wave plates The fgures belw
More informationCIRCLE YOUR DIVISION: Div. 1 (9:30 am) Div. 2 (11:30 am) Div. 3 (2:30 pm) Prof. Ruan Prof. Naik Mr. Singh
Frst CIRCLE YOUR DIVISION: Dv. 1 (9:30 am) Dv. (11:30 am) Dv. 3 (:30 m) Prf. Ruan Prf. Na Mr. Sngh Schl f Mechancal Engneerng Purdue Unversty ME315 Heat and Mass ransfer Eam #3 Wednesday Nvember 17 010
More informationPhys 344 Ch 5 Lect 4 Feb 28 th,
hys 44 Ch 5 Lect 4 Feb 8 th, 009 1 Wed /4 Fr /6 Mn /9 Wed /11 Fr / 1 55 Dlute Slutn 56 Chemcal Equlbrum Revew Exam (C 107 S 60, 61 Bltzmann Statstcs Bnus: hys Sr hess resentatns @ 4pm HW17: 7,76,8 HW18:8,84,86,88,89,91
More informationBME 5742 Biosystems Modeling and Control
BME 5742 Bsystems Mdeln and Cntrl Cell Electrcal Actvty: In Mvement acrss Cell Membrane and Membrane Ptental Dr. Zv Rth (FAU) 1 References Hppensteadt-Peskn, Ch. 3 Dr. Rbert Farley s lecture ntes Inc Equlbra
More informationPhysics 3 (PHYF144) Chap 2: Heat and the First Law of Thermodynamics System. Quantity Positive Negative
Physcs (PHYF hap : Heat and the Frst aw of hermodynamcs -. Work and Heat n hermodynamc Processes A thermodynamc system s a system that may exchange energy wth ts surroundngs by means of heat and work.
More informationThermodynamics of Materials
Thermdynamcs f Materals 14th Lecture 007. 4. 8 (Mnday) FUGACITY dg = Vd SdT dg = Vd at cnstant T Fr an deal gas dg = (RT/)d = RT dln Ths s true fr deal gases nly, but t wuld be nce t have a smlar frm fr
More informationCHAPTER 3 ANALYSIS OF KY BOOST CONVERTER
70 CHAPTER 3 ANALYSIS OF KY BOOST CONERTER 3.1 Intrductn The KY Bst Cnverter s a recent nventn made by K.I.Hwu et. al., (2007), (2009a), (2009b), (2009c), (2010) n the nn-slated DC DC cnverter segment,
More informationWp/Lmin. Wn/Lmin 2.5V
UNIVERITY OF CALIFORNIA Cllege f Engneerng Department f Electrcal Engneerng and Cmputer cences Andre Vladmrescu Hmewrk #7 EEC Due Frday, Aprl 8 th, pm @ 0 Cry Prblem #.5V Wp/Lmn 0.0V Wp/Lmn n ut Wn/Lmn.5V
More informationEdexcel GCSE Physics
Edexcel GCSE Physics Tpic 10: Electricity and circuits Ntes (Cntent in bld is fr Higher Tier nly) www.pmt.educatin The Structure f the Atm Psitively charged nucleus surrunded by negatively charged electrns
More informationSIMULATION OF THREE PHASE THREE LEG TRANSFORMER BEHAVIOR UNDER DIFFERENT VOLTAGE SAG TYPES
SIMULATION OF THREE PHASE THREE LEG TRANSFORMER BEHAVIOR UNDER DIFFERENT VOLTAGE SAG TYPES Mhammadreza Dlatan Alreza Jallan Department f Electrcal Engneerng, Iran Unversty f scence & Technlgy (IUST) e-mal:
More informationDesign of Analog Integrated Circuits
Desgn f Analg Integrated Crcuts I. Amplfers Desgn f Analg Integrated Crcuts Fall 2012, Dr. Guxng Wang 1 Oerew Basc MOS amplfer structures Cmmn-Surce Amplfer Surce Fllwer Cmmn-Gate Amplfer Desgn f Analg
More informationAP CHEMISTRY CHAPTER 6 NOTES THERMOCHEMISTRY
AP CHEMISTRY CHAPTER 6 NOTES THERMOCHEMISTRY Energy- the capacity t d wrk r t prduce heat 1 st Law f Thermdynamics: Law f Cnservatin f Energy- energy can be cnverted frm ne frm t anther but it can be neither
More informationWYSE Academic Challenge 2004 Sectional Physics Solution Set
WYSE Acadec Challenge 004 Sectnal Physcs Slutn Set. Answer: e. The axu pssble statc rctn r ths stuatn wuld be: ax µ sn µ sg (0.600)(40.0N) 4.0N. Snce yur pushng rce s less than the axu pssble rctnal rce,
More informationSpring 2002 Lecture #17
1443-51 Sprng 22 Lecture #17 r. Jaehn Yu 1. Cndtns fr Equlbrum 2. Center f Gravty 3. Elastc Prpertes f Slds Yung s dulus Shear dulus ulk dulus Tday s Hmewrk Assgnment s the Hmewrk #8!!! 2 nd term eam n
More informationCompressibility Effects
Definitin f Cmpressibility All real substances are cmpressible t sme greater r lesser extent; that is, when yu squeeze r press n them, their density will change The amunt by which a substance can be cmpressed
More informationChapter 11: Atmosphere
Chapter 11: Atmsphere Sectin 1: Atmspheric Basics Objectives 1. Describe the cmpsitin f the atmsphere. 2. Cmpare and cntrast the varius layers f the atmsphere. 3. Identify three methds f transferring energy
More informationDepartment of Civil Engineering & Applied Mechanics McGill University, Montreal, Quebec Canada
Department f Ciil ngeerg Applied Mechanics McGill Uniersity, Mntreal, Quebec Canada CI 90 THRMODYNAMICS HAT TRANSFR Assignment #4 SOLUTIONS. A 68-kg man whse aerage bdy temperature is 9 C drks L f cld
More informationRecitation 06. n total = P total V/RT = (0.425 atm * 10.5 L) / ( L atm mol -1 K -1 * 338 K) = mol
Recitatin 06 Mixture f Ideal Gases 1. Chapter 5: Exercise: 69 The partial pressure f CH 4 (g) is 0.175 atm and that f O 2 (g) is 0.250 atm in a mixture f the tw gases. a. What is the mle fractin f each
More informationCHAPTER 13 Temperature and Kinetic Theory. Units
CHAPTER 13 Temperature and Kinetic Thery Units Atmic Thery f Matter Temperature and Thermmeters Thermal Equilibrium and the Zerth Law f Thermdynamics Thermal Expansin Thermal Stress The Gas Laws and Abslute
More informationPhysics 262/266. George Mason University. Prof. Paul So
Physics 262/266 Gerge Masn University Prf. Paul S PHYS 262/266 Annuncements WELCOME TO A NEW SEMESTER! Curse Website - http://cmplex.gmu.edu/www-phys/phys262 - http://cmplex.gmu.edu/www-phys/phys266 Recitatins
More informationChapter Outline 4/28/2014. P-V Work. P-V Work. Isolated, Closed and Open Systems. Exothermic and Endothermic Processes. E = q + w
Islated, Clsed and Open Systems 9.1 Energy as a Reactant r a Prduct 9.2 Transferring Heat and Ding Wrk 9.5 Heats f Reactin and Calrimetry 9.6 Hess s Law and Standard Heats f Reactin 9.7 Heats f Reactin
More informationAnalytical Modeling of Natural Convection in Horizontal Annuli
Analytcal Mdelng f Natural Cnvectn n Hrzntal Annul Peter Teertstra, M. Mchael Yvanvch, J. Rchard Culham Mcrelectrncs Heat Transfer Labratry Department f Mechancal Engneerng Unversty f Waterl Waterl, Ontar,
More informationWeek3, Chapter 4. Position and Displacement. Motion in Two Dimensions. Instantaneous Velocity. Average Velocity
Week3, Chapter 4 Moton n Two Dmensons Lecture Quz A partcle confned to moton along the x axs moves wth constant acceleraton from x =.0 m to x = 8.0 m durng a 1-s tme nterval. The velocty of the partcle
More informationChapter 19. Electrochemistry. Dr. Al Saadi. Electrochemistry
Chapter 19 lectrchemistry Part I Dr. Al Saadi 1 lectrchemistry What is electrchemistry? It is a branch f chemistry that studies chemical reactins called redx reactins which invlve electrn transfer. 19.1
More informationA) 0.77 N B) 0.24 N C) 0.63 N D) 0.31 N E) 0.86 N. v = ω k = 80 = 32 m/s. Ans: (32) 2 = 0.77 N
Q1. A transverse sinusidal wave travelling n a string is given by: y (x,t) = 0.20 sin (2.5 x 80 t) (SI units). The length f the string is 2.0 m and its mass is 1.5 g. What is the magnitude f the tensin
More informationCircuits Op-Amp. Interaction of Circuit Elements. Quick Check How does closing the switch affect V o and I o?
Crcuts Op-Amp ENGG1015 1 st Semester, 01 Interactn f Crcut Elements Crcut desgn s cmplcated by nteractns amng the elements. Addng an element changes vltages & currents thrughut crcut. Example: clsng a
More informationIntroduction to Electronic circuits.
Intrductn t Electrnc crcuts. Passve and Actve crcut elements. Capactrs, esstrs and Inductrs n AC crcuts. Vltage and current dvders. Vltage and current surces. Amplfers, and ther transfer characterstc.
More informationPrinciples of Food and Bioprocess Engineering (FS 231) Solutions to Example Problems on Heat Transfer
Prncples of Food and Boprocess Engneerng (FS 31) Solutons to Example Problems on Heat Transfer 1. We start wth Fourer s law of heat conducton: Q = k A ( T/ x) Rearrangng, we get: Q/A = k ( T/ x) Here,
More informationCHEMISTRY Midterm #2 answer key October 25, 2005
CHEMISTRY 123-01 Mdterm #2 answer key October 25, 2005 Statstcs: Average: 70 pts (70%); Hghest: 97 pts (97%); Lowest: 33 pts (33%) Number of students performng at or above average: 62 (63%) Number of students
More informationCANKAYA UNIVERSITY FACULTY OF ENGINEERING MECHANICAL ENGINEERING DEPARTMENT ME 313 HEAT TRANSFER
CANKAYA UNIVERSITY FACUTY OF ENGINEERING MECHANICA ENGINEERING DEPARTMENT ME 313 HEAT TRANSFER CHAPTER-3 EXAMPES 1) Cnsider a slab f thicness as illustrated in figure belw. A fluid at temperature T 1 with
More informationName ID # For relatively dilute aqueous solutions the molality and molarity are approximately equal.
Name ID # 1 CHEMISTRY 212, Lect. Sect. 002 Dr. G. L. Roberts Exam #1/Sprng 2000 Thursday, February 24, 2000 CLOSED BOOK EXM No notes or books allowed. Calculators may be used. tomc masses of nterest are
More informationHomework Chapter 21 Solutions!!
Homework Chapter 1 Solutons 1.7 1.13 1.17 1.19 1.6 1.33 1.45 1.51 1.71 page 1 Problem 1.7 A mole sample of oxygen gas s confned to a 5 lter vessel at a pressure of 8 atm. Fnd the average translatonal knetc
More informationGeneral Chemistry II, Unit I: Study Guide (part I)
1 General Chemistry II, Unit I: Study Guide (part I) CDS Chapter 14: Physical Prperties f Gases Observatin 1: Pressure- Vlume Measurements n Gases The spring f air is measured as pressure, defined as the
More informationA Proposal of Heating Load Calculation considering Stack Effect in High-rise Buildings
A Prpsal f Heatng Lad Calculatn cnsderng Stack Effect n Hgh-rse Buldngs *Dsam Sng 1) and Tae-Hyuk Kang 2) 1) Department f Archtectural Engneerng, Sungkyunkwan Unversty, 2066 Sebu-r, Jangan-gu, Suwn, 440-746,
More informationCHEM Thermodynamics. Change in Gibbs Free Energy, G. Review. Gibbs Free Energy, G. Review
Review Accrding t the nd law f Thermdynamics, a prcess is spntaneus if S universe = S system + S surrundings > 0 Even thugh S system
More informationThermal-Fluids I. Chapter 18 Transient heat conduction. Dr. Primal Fernando Ph: (850)
hermal-fluds I Chapter 18 ransent heat conducton Dr. Prmal Fernando prmal@eng.fsu.edu Ph: (850) 410-6323 1 ransent heat conducton In general, he temperature of a body vares wth tme as well as poston. In
More informationChapter 17: Thermodynamics: Spontaneous and Nonspontaneous Reactions and Processes
Chapter 17: hermdynamics: Spntaneus and Nnspntaneus Reactins and Prcesses Learning Objectives 17.1: Spntaneus Prcesses Cmparing and Cntrasting the hree Laws f hermdynamics (1 st Law: Chap. 5; 2 nd & 3
More informationCTN 2/23/16. EE 247B/ME 218: Introduction to MEMS Design Lecture 11m2: Mechanics of Materials. Copyright 2016 Regents of the University of California
Vlume Change fr a Unaxal Stress Istrpc lastcty n 3D Istrpc = same n all drectns The cmplete stress-stran relatns fr an strpc elastc Stresses actng n a dfferental vlume element sld n 3D: (.e., a generalzed
More informationThermodynamics and Equilibrium
Thermdynamics and Equilibrium Thermdynamics Thermdynamics is the study f the relatinship between heat and ther frms f energy in a chemical r physical prcess. We intrduced the thermdynamic prperty f enthalpy,
More informationThermodynamics Partial Outline of Topics
Thermdynamics Partial Outline f Tpics I. The secnd law f thermdynamics addresses the issue f spntaneity and invlves a functin called entrpy (S): If a prcess is spntaneus, then Suniverse > 0 (2 nd Law!)
More informationPhys 344 Ch 5 Lect 5 Feb 28 th,
hys 44 Ch 5 Lect 5 Feb 8 th, 009 1 Wed. /4 Fr. /6 Mn. /9 Wed. /11 Fr. / 1 5.5 Dlute lutn 5.6 Checal Equlbru Revew Exa (C 10.7 6.0, 6.1 ltzann tatstcs nus: hys. r. hess resentatns @ 4p HW17: 7,76,8 HW18:8,84,86,88,89,91
More informationA/2 l,k. Problem 1 STRATEGY. KNOWN Resistance of a complete spherical shell: r rk. Inner and outer radii
Prblem 1 STRATEGY KNOWN Resstance f a cmplete sphercal shell: R ( r r / (4 π r rk sphere Inner an uter ra r an r, SOLUTION Part 1: Resstance f a hemsphercal shell: T calculate the resstance f the hemsphere,
More informationPhy 212: General Physics II 1 Chapter 18 Worksheet 3/20/2008
Phy 1: General Physics II 1 hapter 18 rksheet 3/0/008 Thermal Expansin: 1. A wedding ring cmpsed f pure gld (inner diameter = 1.5 x 10 - m) is placed n a persn s finger (diameter = 1.5 x 10 - m). Bth the
More informationV. Electrostatics Lecture 27a: Diffuse charge at electrodes
V. Electrstatcs Lecture 27a: Dffuse charge at electrdes Ntes by MIT tudent We have talked abut the electrc duble structures and crrespndng mdels descrbng the n and ptental dstrbutn n the duble layer. Nw
More information6. ELUTRIATION OF PARTICLES FROM FLUIDIZED BEDS
6. ELUTRIATION OF PARTICLES FROM FLUIDIZED BEDS Elutratn s the prcess n whch fne partcles are carred ut f a fludzed bed due t the flud flw rate passng thrugh the bed. Typcally, fne partcles are elutrated
More information( ) 1/ 2. ( P SO2 )( P O2 ) 1/ 2.
Chemstry 360 Dr. Jean M. Standard Problem Set 9 Solutons. The followng chemcal reacton converts sulfur doxde to sulfur troxde. SO ( g) + O ( g) SO 3 ( l). (a.) Wrte the expresson for K eq for ths reacton.
More informationPART I: MULTIPLE CHOICE (32 questions, each multiple choice question has a 2-point value, 64 points total).
CHEMISTRY 123-07 Mdterm #2 answer key November 04, 2010 Statstcs: Average: 68 p (68%); Hghest: 91 p (91%); Lowest: 37 p (37%) Number of students performng at or above average: 58 (53%) Number of students
More informationGasometric Determination of NaHCO 3 in a Mixture
60 50 40 0 0 5 15 25 35 40 Temperature ( o C) 9/28/16 Gasometrc Determnaton of NaHCO 3 n a Mxture apor Pressure (mm Hg) apor Pressure of Water 1 NaHCO 3 (s) + H + (aq) Na + (aq) + H 2 O (l) + CO 2 (g)
More informationExamples: 1. How much heat is given off by a 50.0 g sample of copper when it cools from 80.0 to 50.0 C?
NOTES: Thermchemistry Part 1 - Heat HEAT- TEMPERATURE - Thermchemistry: the study f energy (in the frm f heat) changes that accmpany physical & chemical changes heat flws frm high t lw (ht cl) endthermic
More informationWater vapour balance in a building moisture exposure for timber structures
Jnt Wrkshp f COST Actns TU1 and E55 September 21-22 9, Ljubljana, Slvena Water vapur balance n a buldng msture expsure fr tmber structures Gerhard Fnk ETH Zurch, Swtzerland Jchen Köhler ETH Zurch, Swtzerland
More informationVan der Waals-coupled electronic states in incommensurate double-walled carbon nanotubes
Kahu Lu* 1, Chenha Jn* 1, Xapng Hng 1, Jhn Km 1, Alex Zettl 1,2, Enge Wang 3, Feng Wang 1,2 Van der Waals-cupled electrnc states n ncmmensurate duble-walled carbn nantubes S1. Smulated absrptn spectra
More informationLecture 12: Chemical reaction equilibria
3.012 Fundamentals f Materials Science Fall 2005 Lecture 12: 10.19.05 Chemical reactin equilibria Tday: LAST TIME...2 EQUATING CHEMICAL POTENTIALS DURING REACTIONS...3 The extent f reactin...3 The simplest
More informationconvection coefficient. The different property values of water at 20 C are given by: u W/m K, h=8062 W/m K
Practice rblems fr Cnvective Heat Transfer 1. Water at 0 C flws ver a flat late 1m 1m at 10 C with a free stream velcity f 4 m/s. Determine the thickness f bndary layers, lcal and average vale f drag cefficient
More informationMeasurement of Radiation: Exposure. Purpose. Quantitative description of radiation
Measurement of Radaton: Exposure George Starkschall, Ph.D. Department of Radaton Physcs U.T. M.D. Anderson Cancer Center Purpose To ntroduce the concept of radaton exposure and to descrbe and evaluate
More informationThermodynamics EAS 204 Spring 2004 Class Month Day Chapter Topic Reading Due 1 January 12 M Introduction 2 14 W Chapter 1 Concepts Chapter 1 19 M MLK
Thermdynamics EAS 204 Spring 2004 Class Mnth Day Chapter Tpic Reading Due 1 January 12 M Intrductin 2 14 W Chapter 1 Cncepts Chapter 1 19 M MLK Hliday n class 3 21 W Chapter 2 Prperties Chapter 2 PS1 4
More informationMODULE 7 HEAT EXCHANGERS
MODULE 7 HEAT EXCHANGERS 7. What are heat exchangers? Heat exchangers are practcal devces used t transfer energy frm ne flud t anther. Arund the husehld, we are accustmed t seeng the cndensers and evapratrs
More informationChapter 3 The Kinetic Theory of Gases 3.1. Ideal Gases Experimental Laws and the Equation of State
Chater 3 The Knetc Theory of Gases 3.1. Ideal Gases 3.1.1. Exermental Laws and the Equaton of State 3.1.2. Molecular Model of an Ideal Gas 3.3. Mean Free Path 3.4. The Boltzmann Dstrbuton Law and The Dstrbuton
More informationCHAPTER 7 ENERGY BALANCES SYSTEM SYSTEM. * What is energy? * Forms of Energy. - Kinetic energy (KE) - Potential energy (PE) PE = mgz
SYSTM CHAPTR 7 NRGY BALANCS 1 7.1-7. SYSTM nergy & 1st Law of Thermodynamcs * What s energy? * Forms of nergy - Knetc energy (K) K 1 mv - Potental energy (P) P mgz - Internal energy (U) * Total nergy,
More information1.1. Basic Mechanisms of Heat Transfer
1.1. Basc Mechansms f Heat Transfer The basc mechansms f heat transfer are generally cnsdered t be cnductn, cnvectn, blng, cndensatn, and radatn. Of these, radatn s usually sgnfcant nly at temperatures
More informationChapter 4. Unsteady State Conduction
Chapter 4 Unsteady State Cnductin Chapter 5 Steady State Cnductin Chee 318 1 4-1 Intrductin ransient Cnductin Many heat transfer prblems are time dependent Changes in perating cnditins in a system cause
More informationChemistry 114 First Hour Exam
Chemistry 114 First Hur Exam Please shw all wrk fr partial credit Name: (4 pints) 1. (12 pints) Espress is made by frcing very ht water under high pressure thrugh finely grund, cmpacted cffee. (Wikipedia)
More informationIGEE 401 Power Electronic Systems. Solution to Midterm Examination Fall 2004
Jós, G GEE 401 wer Electrnc Systems Slutn t Mdterm Examnatn Fall 2004 Specal nstructns: - Duratn: 75 mnutes. - Materal allwed: a crb sheet (duble sded 8.5 x 11), calculatr. - Attempt all questns. Make
More informationProblem 1 Known: Dimensions and materials of the composition wall, 10 studs each with 2.5m high
Prblem Knwn: Dimensins and materials f the cmpsitin wall, 0 studs each with.5m high Unknwn:. Thermal resistance assciate with wall when surfaces nrmal t the directin f heat flw are isthermal. Thermal resistance
More informationChapter 23 Electromagnetic Waves Lecture 14
Chapter 23 Electrmagnetic Waves Lecture 14 23.1 The Discvery f Electrmagnetic Waves 23.2 Prperties f Electrmagnetic Waves 23.3 Electrmagnetic Waves Carry Energy and Mmentum 23.4 Types f Electrmagnetic
More information55:041 Electronic Circuits
55:04 Electrnc Crcuts Feedback & Stablty Sectns f Chapter 2. Kruger Feedback & Stablty Cnfguratn f Feedback mplfer S S S S fb Negate feedback S S S fb S S S S S β s the feedback transfer functn Implct
More informationChapter 20 The First Law of Thermodynamics
Chapter he Frst aw o hermodynamcs. developng the concept o heat. etendng our concept o work to thermal processes 3. ntroducng the rst law o thermodynamcs. Heat and Internal Energy Internal energy: s the
More informationThermochemistry. Thermochemistry
Thermchemistry Petrucci, Harwd and Herring: Chapter 7 CHEM 1000A 3.0 Thermchemistry 1 Thermchemistry The study energy in chemical reactins A sub-discipline thermdynamics Thermdynamics studies the bulk
More informationThermodynamics Second Law Entropy
Thermodynamcs Second Law Entropy Lana Sherdan De Anza College May 8, 2018 Last tme the Boltzmann dstrbuton (dstrbuton of energes) the Maxwell-Boltzmann dstrbuton (dstrbuton of speeds) the Second Law of
More informationInstructions: Show all work for complete credit. Work in symbols first, plugging in numbers and performing calculations last. / 26.
CM ROSE-HULMAN INSTITUTE OF TECHNOLOGY Name Circle sectin: 01 [4 th Lui] 02 [5 th Lui] 03 [4 th Thm] 04 [5 th Thm] 05 [4 th Mech] ME301 Applicatins f Thermdynamics Exam 1 Sep 29, 2017 Rules: Clsed bk/ntes
More informationQ1. In figure 1, Q = 60 µc, q = 20 µc, a = 3.0 m, and b = 4.0 m. Calculate the total electric force on q due to the other 2 charges.
Phys10 Secnd Majr-08 Zer Versin Crdinatr: Dr. I. M. Nasser Saturday, May 3, 009 Page: 1 Q1. In figure 1, Q = 60 µc, q = 0 µc, a = 3.0 m, and b = 4.0 m. Calculate the ttal electric frce n q due t the ther
More informationMatter Content from State Frameworks and Other State Documents
Atms and Mlecules Mlecules are made f smaller entities (atms) which are bnded tgether. Therefre mlecules are divisible. Miscnceptin: Element and atm are synnyms. Prper cnceptin: Elements are atms with
More informationOutline. Unit Eight Calculations with Entropy. The Second Law. Second Law Notes. Uses of Entropy. Entropy is a Property.
Unt Eght Calculatons wth Entropy Mechancal Engneerng 370 Thermodynamcs Larry Caretto October 6, 010 Outlne Quz Seven Solutons Second law revew Goals for unt eght Usng entropy to calculate the maxmum work
More information(element) But, we do NOT know G!!! Correct, but not applicable! Free Energy Problems: o r. products. reactants. o f. reactants.
SANDARD fr hemcal Rxns prducts G p G reactants r But, we d NO knw G!!! rrect, but nt applcable! prducts G f G reactants f f (element) 0 f standard Gbbs free energy f frmatn Free Energy Prblems: 5. Prf.
More informationPhysics 207: Lecture 20. Today s Agenda Homework for Monday
Physcs 207: Lecture 20 Today s Agenda Homework for Monday Recap: Systems of Partcles Center of mass Velocty and acceleraton of the center of mass Dynamcs of the center of mass Lnear Momentum Example problems
More informationLecture 13: Electrochemical Equilibria
3.012 Fundamentals f Materials Science Fall 2005 Lecture 13: 10.21.05 Electrchemical Equilibria Tday: LAST TIME...2 An example calculatin...3 THE ELECTROCHEMICAL POTENTIAL...4 Electrstatic energy cntributins
More informationHeat is energy and is measured in joules (J) or kilojoules (kj). The symbol for heat is H.
Causes f Change Calrimetry Hw Des Energy Affect Change? Heat vs. Temerature HEAT TEMPERATURE Definitin: Deends n: Examles: Heat is energy and is measured in jules (J) r kiljules (kj). The symbl fr heat
More informationEntropy, Free Energy, and Equilibrium
Nv. 26 Chapter 19 Chemical Thermdynamics Entrpy, Free Energy, and Equilibrium Nv. 26 Spntaneus Physical and Chemical Prcesses Thermdynamics: cncerned with the questin: can a reactin ccur? A waterfall runs
More informationPhysics 107 HOMEWORK ASSIGNMENT #20
Physcs 107 HOMEWORK ASSIGNMENT #0 Cutnell & Jhnsn, 7 th etn Chapter 6: Prblems 5, 7, 74, 104, 114 *5 Cncept Smulatn 6.4 prves the ptn f explrng the ray agram that apples t ths prblem. The stance between
More information( ) kt. Solution. From kinetic theory (visualized in Figure 1Q9-1), 1 2 rms = 2. = 1368 m/s
.9 Kinetic Mlecular Thery Calculate the effective (rms) speeds f the He and Ne atms in the He-Ne gas laser tube at rm temperature (300 K). Slutin T find the rt mean square velcity (v rms ) f He atms at
More informationEnergy Inputs and Outputs
Energy Inputs and Outputs Sun Earth ultravilet visible infrared Bth Sun and Earth behave as blackbdies (absrb 100% incident radiatin; emit radiatin at all wavelengths in all directins) Earth receives energy
More informationEnergy & Work
rk Dne by a Cntant Frce 6.-6.4 Energy & rk F N m jule () J rk Dne by a Cntant Frce Example Pullng a Sutcae-n-heel Fnd the wrk dne the rce 45.0-N, the angle 50.0 degree, and the dplacement 75.0 m. 3 ( F
More informationelement k Using FEM to Solve Truss Problems
sng EM t Slve Truss Prblems A truss s an engneerng structure cmpsed straght members, a certan materal, that are tpcall pn-ned at ther ends. Such members are als called tw-rce members snce the can nl transmt
More informationStudy Group Report: Plate-fin Heat Exchangers: AEA Technology
Study Grup Reprt: Plate-fin Heat Exchangers: AEA Technlgy The prblem under study cncerned the apparent discrepancy between a series f experiments using a plate fin heat exchanger and the classical thery
More informationChapter 17 Free Energy and Thermodynamics
Chemistry: A Mlecular Apprach, 1 st Ed. Nivald Tr Chapter 17 Free Energy and Thermdynamics Ry Kennedy Massachusetts Bay Cmmunity Cllege Wellesley Hills, MA 2008, Prentice Hall First Law f Thermdynamics
More informationELABORATING AND ANALYSING THE REAL BALANCE OF HEAT FOR THE STEAM GENERATOR RGL10/D-D
Annals f te Unversty f Petrşan, Mecancal Engneerng, 10 (2008), 155-160 155 ELABORATING AND ANALYSING THE REAL BALANCE OF HEAT FOR THE STEAM GENERATOR RGL10/D-D DAN CODRUŢ PETRILEAN 1 Abstract: Te real
More information