AP PHYSICS B 2014 SCORING GUIDELINES
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1 AP PHYSICS B 2014 SCORING GUIDELINES Question 3 10 points total Distribution of points (a) i. 2 points For correctly ranking all 4 labeled points 1 A 2 B 4 C 3 D Note: one point is earned for a ranking that identifies A and C as having the lowest and highest temperatures, respectively, but incorrectly ranks B and D. For example: 1 A 3 B 4 C 2 D or 1 A 2 B 3 C 2 D A and C cannot have the same ranking as other points (e.g., 1 A 1 B 2 C 2 D) 2 points ii. For using the ideal gas law with correct substitutions for P, V, and n to get the correct answer PV = nrt PV T = nr P0( 4V0) 4PV 0 0 4PV 0 0 TD = = or 3R 3 R (3 mol) i R Note: mole units need not be explicitly stated (b) 2 points For selecting BC only For providing a correct explanation Examples: For the gas to do positive work on its surroundings (or for work done on the gas to be negative), PD V must be positive so D V must be positive. An expanding gas exerts a force in the direction of motion, doing positive work. (c) 2 points Positive is the only box checked for which the Justify section will be read For a correct explanation that mentions internal energy increases with the temperature increase. For a correct explanation that mentions the work is zero Example: The volume does not change in process AB, hence the work done is zero. The temperature increase in AB means the internal energy increases. Since the work done is zero, the positive change in internal energy must be provided by heating The College Board.
2 AP PHYSICS B 2014 SCORING GUIDELINES Question 3 (continued) (d) 3 points Distribution of points For a correct expression of net work done on the gas from segments BC and DA of the graph W =-PDV - PDV ( ) ( ) net BC DA For correctly substituting the values of P and D V into the above equation Wnet =-( 3P0)( 3V0) -( P0)( - 3V0) =- 9PV PV 0 0 =- 6PV 0 0 For having a final answer that is negative Alternate Solution Alternate points For a correct expression or statement that the net work done on the gas is given by the area enclosed by the entire path Wnet =-( DPi DV) For correctly substituting the values of P and D V into the above equation Wnet =-(3 P0 -P0) i(4 V0 - V0) =- 2P0i 3V0 =-6PV 0 0 For having a negative answer 2014 The College Board.
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9 AP PHYSICS B 2014 SCORING COMMENTARY Question 3 Overview The intent of this question was to assess the students' understanding of thermodynamic cycles. Part (a) tested their interpretation of a PV diagram and the ideal gas law. Part (b) tested their ability to determine whether work was done on or by a gas. Part (c) tested their understanding of the first law of thermodynamics, heat, and internal energy. Finally, part (d) tested the students' ability to find the work done on a gas using a PV diagram. Sample: B3 A Score: 10 This was an excellent response earning full credit on all parts. In part (b) the reasoning explains all four segments in the cycle. It is actually only necessary to explain the positive work in the correctly checked segment BC. Part (c) has excellent reasoning in symbolic form that was easy for the graders to follow. Part (d) also has a well presented step-by-step reasoning. Sample: B3 B Score: 7 Part (a)(ii) lost because the given value of the number of moles was not used. Part (b) earned full credit in another straightforward argument. In part (c) the first statement contradicts an otherwise fine answer, and only was earned. Part (d) did not earn the final point for an indication that the net work was negative. Sample: B3 C Score: 3 In part (a), the temperatures were ranked correctly and T D was correctly determined, so 3 points were earned. The correct choice was not selected in part (b). In part (c) the correct choice was made, but points are only awarded for the explanation, which was not correct. No credit was earned for the equation in part (d) The College Board.
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