A unifying generalization of Sperner s theorem
|
|
- Leslie Bond
- 5 years ago
- Views:
Transcription
1 A uifyig geeralizatio of Sperer s theorem Matthias Beck, Xueqi Wag, ad Thomas Zaslavsky State Uiversity of New York at Bighamto matthias@math.bighamto.edu xwag@math.bighamto.edu zaslav@math.bighamto.edu Versio of August 30, 200. Abstract: Sperer s boud o the size of a atichai i the lattice PS of subsets of a fiite set S has bee geeralized i three differet directios: by Erdős to subsets of PS i which chais cotai at most r elemets; by Meshalki to certai classes of compositios of S; by Griggs, Stahl, ad Trotter through replacig the atichais by certai sets of pairs of disjoit elemets of PS. We uify Erdős s, Meshalki s, ad Griggs Stahl Trotter s iequalities with a commo geeralizatio. We similarly uify their accompayig LYM iequalities. Our bouds do ot i geeral appear to be the best possible. Keywords: Sperer s theorem, LYM iequality, atichai, r-family, r-chai-free, compositio of a set Mathematics Subject Classificatio. Primary 05D05; Secodary 06A07. Ruig head: A uifyig Sperer geeralizatio Address for editorial correspodece: Matthias Beck Departmet of Mathematical Scieces State Uiversity of New York Bighamto, NY U.S.A.
2 2. Sperer-type theorems Let S be a fiite set with elemets. I the lattice PS of all subsets of S oe tries to estimate the size of a subset with certai characteristics. The most famous such estimate cocers atichais, that is, subsets of PS i which ay two elemets are icomparable. We let x deote the greatest iteger x ad x the least iteger x. Theorem. Sperer [0]. Suppose A,..., A m S such that A k A j for k j. The m /2. Furthermore, this boud ca be attaied for ay. Sperer s theorem has bee geeralized i may differet directios. Here are three: Erdős exteded Sperer s iequality to subsets of PS i which chais cotai at most r elemets. Meshalki proved a Sperer-like iequality for families of compositios of S ito a fixed umber of parts, i which the sets i each part costitute a atichai. Fially, Griggs, Stahl, ad Trotter exteded Sperer s theorem by replacig the atichais by sets of pairs of disjoit elemets of PS satisfyig a itersectio coditio. I this paper we uify Erdős s, Meshalki s, ad the Griggs Stahl Trotter iequalities i a sigle geeralizatio. However, except i special cases amog which are geeralizatios of the kow bouds, our bouds are ot the best possible. For a precise statemet of Erdős s geeralizatio, call a subset of PS r-chai-free if its chais i.e., liearly ordered subsets cotai o more tha r elemets; that is, o chai has legth r. I particular, a atichai is -chai-free. The geeralizatio of Theorem. to r-chai-free families is Theorem.2 Erdős [3]. Suppose {A,..., A m } PS cotais o chais with r + elemets. The m is bouded by the sum of the r largest biomial coefficiets k, 0 k. The boud is attaiable for every ad r. Note that for r =, we obtai Sperer s theorem. Goig i a differet directio, Sperer s iequality ca be geeralized to certai ordered weak partitios of S. We defie a weak compositio of S ito p parts as a ordered p-tuple A,..., A p of sets A k, possibly void, such that A,..., A p are pairwise disjoit ad A A p = S. A Sperer-like iequality suitable for this settig was proposed by Sevast yaov ad proved by Meshalki see [8]. By a p-multiomial coefficiet for we mea a multiomial coefficiet, where ai 0 ad a + + a p =. Let [p] := {, 2,..., p}. Theorem.3 Meshalki. Let p 2. Suppose A j,..., A jp for j =,..., m are differet weak compositios of S ito p parts such that for all k [p] the set {A jk : j m} igorig repetitio forms a atichai. The m is bouded by the largest p-multiomial coefficiet for. Furthermore, the boud is attaiable for every ad p. The term r-family or k-family, depedig o the ame of the forbidde legth, has bee used i the past, but we thik it is time for a distictive ame.
3 A Uifyig Geeralizatio of Sperer s Theorem 3 This largest multiomial coefficiet ca be writte explicitly as! ρ p +! p ρ, p! where ρ = p p. To see why Meshalki s iequality geeralizes Sperer s Theorem, suppose A,..., A m S form a atichai. The S A,..., S A m also form a atichai. Hece the m weak compositios A j, S A j of S ito two parts satisfy Meshalki s coditios ad Sperer s iequality follows. Yet aother geeralizatio of Sperer s Theorem is Theorem.4 Griggs Stahl Trotter [4] Suppose {A j0,..., A jq } are m differet chais i PS such that A ji A kl for all i ad l ad all j k. The m q/2. Furthermore, this boud ca be attaied for all ad q. A equivalet, simplified form of this result i which A j = A j0, B j = S A jq, ad replaces q is Theorem.4. Let > 0. Suppose A j, B j are m pairs of sets such that A j B j = for all j, A j B k for all j k, ad all A j + B j. The m /2 ad this boud ca be attaied for every. Sperer s iequality follows as the special case i which A,..., A m S form a atichai ad B j = S A j. Theorems.2,.3, ad.4 are icomparable geeralizatios of Sperer s Theorem. We wish to combie ad hece further geeralize these geeralizatios. To state our mai result, we defie a weak partial compositio of S ito p parts as a ordered p-tuple A,..., A p such that A,..., A p are pairwise disjoit sets, possibly void hece the word weak, ad A A p S. If we do ot specify the superset S the we simply talk about a weak set compositio ito p parts this could be a weak compositio of ay set. Our geeralizatio of Sperer s iequality is: Theorem.5. Fix itegers p 2 ad r. Suppose A j,..., A jp for j =,..., m are differet weak set compositios ito p parts with the coditio that, for all k [p] ad all I [m] with I = r +, there exist distict i, j I such that either A ik = A jk or A ik l k A jl A jk l k A il, ad let := max j m A j + + A jp. The m is bouded by the sum of the r p largest p-multiomial coefficiets for itegers less tha or equal to. If r p is larger tha r+p p, the umber of p-multiomial coefficiets, the we regard the sequece of coefficiets as exteded by 0 s.
4 4 We heartily agree with those readers who fid the statemet of this theorem somewhat ureadable. We would first like to show that it does geeralize Theorems.2,.3, ad.4 simultaeously. The last follows easily as the case r =, p = 2. Theorem.3 ca be deduced by choosig r = ad restrictig the weak compositios to be compositios of a fixed set S with elemets. Fially, Theorem.2 follows by choosig p = 2 ad the weak compositios to be compositios of a fixed -set ito 2 parts. What we fid more iterestig, however, is that specializatios of Theorem.5 yield simply stated corollaries that combie two at a time of Theorems.2,.3, ad.4. Sectio 4 collects these corollaries. The coditio of the theorem implies that each set A k = {A jk : j [m]} igorig repetitio is r-chai-free. We suspect that the coverse is ot true i geeral. It is true if all the weak set compositios are weak compositios of the same set of order, as i Corollary 4.. All the theorems we have stated have each a slightly stroger compaio, a LYM iequality. I Sectio 2, we state these iequalities ad show how Theorems..5 ca be deduced from them. The proofs of Theorem.5 ad the correspodig LYM iequality are i Sectio 3. After the corollaries of Sectio 4, i Sectio 5 we show that some, at least, of our upper bouds caot be attaied. 2. LYM iequalities I attemptig to fid a ew proof of Theorem., Lubell, Yamamoto, ad Meshalki idepedetly came up with the followig refiemet: Theorem 2. Lubell [7], Yamamoto [], Meshalki [8]. Suppose A,..., A m S such that A k A j for k j. The. A k Sperer s iequality follows immediately by otig that max k k k= = /2. A LYM iequality correspodig to Theorem.2 appeared to our kowledge first i [9]: Theorem 2.2 Rota Harper. Suppose {A,..., A m } PS cotais o chais with r + elemets. The r. A k k= Deducig Erdős s Theorem.2 from this iequality is ot as straightforward as the coectio betwee Theorems 2. ad.. It ca be doe through Lemma 3., which we also eed i order to deduce Theorem.5.
5 A Uifyig Geeralizatio of Sperer s Theorem 5 The LYM compaio of Theorem.3 first appeared i [5]; agai, Meshalki s Theorem.3 follows immediately. Theorem 2.3 Hochberg Hirsch. Suppose A j,..., A jp for j =,..., m are differet weak compositios of S ito p parts such that for each k [p] the set {A jk : j m} igorig repetitios forms a atichai. The. A j,..., A jp The LYM iequality correspodig to Theorem.4 is due to Bollobás. Theorem 2.4 Bollobás [2]. Suppose A j, B j are m pairs of sets such that A j B j = for all j ad A j B k for all j k. The Aj + B j A j. Oce more, the correspodig upper boud, the Griggs Stahl Trotter Theorem.4, is a immediate cosequece. Naturally, there is a LYM iequality accompayig our mai Theorem.5. Like its sibligs, it costitutes a refiemet. Theorem 2.5. Let p 2 ad r. Suppose A j,..., A jp for j =,..., m are differet weak compositios of ay sets ito p parts satisfyig the same coditio as i Theorem.5. The Aj + + A jp A j,..., A jp r p. Example 2.. The complicated hypothesis of Theorem 2.5 caot be replaced by the assumptio that each A k is r-chai-free, because the there is o LYM boud idepedet of. Let p 2, S = [], ad A = {A, {}, { },..., { p + 2} : A A } where A is a largest r-chai-free family i [ p + ], specifically, A = j I P j [ p + ] where { p + r p + r p + r I =, +, } + r.
6 6 The LYM sum is A +p A A A,,..., There is o possible upper boud i terms of. = A! A + p! A A = p + j! j j + p! j I = p + p j + 2 p + j! j I as. 3. Proof of the mai theorems Proof of Theorem 2.5. Let S be a fiite set cotaiig all A jk for j =,..., m ad k =,..., p, ad let = S. We cout maximal chais i PS. Let us say a maximal chai separates the weak compositio A,..., A p if there exist elemets = X 0 X l X lp = S of the maximal chai such that A k X lk X lk for each k. There are 2 A + + A p A! A p! A A p! maximal chais separatig A,..., A p. To prove this, replace maximal chais {x } {x, x 2 } S by permutatios x, x 2,..., x of S. Choose A + + A p places for A A p ; the arrage A i ay order i the first A of these places, A 2 i the ext A 2, etc. Fially, arrage S A A p i the remaiig places. This costructs all maximal chais that separate A,..., A p. We claim that every maximal chai separates at most r p weak partial compositios of S. To prove this, assume that there is a maximal chai that separates N weak partial compositios A j,..., A jp. Cosider all first compoets A j ad suppose r + of them are differet, say A, A 2,..., A r+,. By the hypotheses of the theorem, there are i, i [r + ] such that A i meets some A i l where l > ad A i meets some A il where l >. By separatio, there are q ad q such that A i X q X 0 ad A i X q X 0, ad there are q l, q l, q l, q l such that q q l q l, q q l q l, ad A il X ql X ql ad A i l X q l X q l. Sice A i meets A i l, there is a elemet a i X q l X q l ; it follows that q l < q. Similarly, q l < q. But this is a cotradictio. It follows that, amogst the N sets A j, there are at most r differet sets. Hece by the pigeohole priciple there are N/r amog the N weak partial compositios that have the same first set A j.
7 A Uifyig Geeralizatio of Sperer s Theorem 7 Lookig ow at these N/r weak partial compositios, we ca repeat the argumet to coclude that there are N/r /r N/r 2 weak partial compositios for which both the A j s ad the A j2 s are idetical. Repeatig this process p times yields N/r p weak partial compositios ito p parts whose first p parts are idetical. But ow the hypotheses imply that the last parts of all these weak partial compositios are at most r differet sets; i other words, there are at most r distict weak partial compositios. Hece N/r p r, whece N r p. If we kow that all the compositios are weak but ot partial compositios of S, the the last parts of all these N/r p weak compositios are idetical. Thus N r p. Sice at most r p weak partial compositios of S are separated by each of the! maximal chais, from 2 we deduce that r p! A j! A jp! A j A jp! A j + + A jp The theorem follows. =! Aj + + A jp A j,..., A jp To deduce Theorem.5 from Theorem 2.5, we use the followig lemma, which origially appeared i somewhat differet ad icomplete form i [9], used there to prove Erdős s Theorem.2 by meas of Theorem 2.2, ad appeared i complete form i [6, Lemma 3..3]. We give a very short proof, which seems to be ew. Lemma 3. Harper Klai Rota. Suppose M,..., M N R satisfy M M 2 M N 0, ad let R be a iteger with R N. If q,..., q N [0, ] have sum the q + + q N R, q M + + q N M N M + + M R.. Proof. By assumptio, N q k k=r+ k= R q k. Hece, by the coditio o the M k, N N R q k M k M R q k M R q k k=r+ k=r+ k= which is equivalet to the coclusio. R q k M k, k= Proof of Theorem.5. Let S be ay fiite set that cotais all A jk. Write dow the LYM iequality from Theorem 2.5.
8 8 From the m weak partial compositios A j,..., A jp of S, collect those whose shape is a,..., a p ito the set Ca,..., a p. Label the p-multiomial coefficiets for itegers as M, M 2,... so that M M 2. If M k is, let q k := Ca,..., a p /M k. By Theorem 2.5, the q k s ad M k s satisfy all the coditios of Lemma 3. with N replaced by the umber of p-tuples a,..., a p whose sum is at most, that is +p p, ad R replaced by min, r p. Hece Ca,..., a p M + + M R. a + +a p The coclusio of the theorem ow follows, sice m = Ca,..., a p. a + +a p 4. Cosequeces As promised i Sectio, we ow state special cases of Theorems.5/2.5 that uify pairs of Theorems.2,.3, ad.4 as well as their LYM compaios. The first special case uifies Theorems.2/2.2 ad.3/2.3. It is a corollary of the proof of the mai theorems, ot of the theorems themselves. See [] for a short, direct proof. Corollary 4.. Suppose A j,..., A jp are m differet weak compositios of S ito p parts such that for each k [p ], the set {A jk : j m} is r-chai-free. The r p. A j,..., A jp Cosequetly, m is bouded by the sum of the r p largest p-multiomial coefficiets for. Proof. We ote that, for a family of m weak compositios of S, the coditio of Theorem 2.5 for a particular k [p ] is equivalet to {A jk } j beig r-chai-free. Thus by the hypothesis of the corollary, the hypothesis of the theorem is met for k =,..., p. The the proof of Theorem 2.5 goes through perfectly with the oly differece, explaied i the proof, that eve without a coditio o k = p we obtai N r p. I the proof of Theorem.5, uder our hypotheses the sets Ca,..., a p with a + + a p < are empty. Therefore we take oly the p-multiomial coefficiets for, labelled M M 2. I applyig Lemma 3. we take R = min, r p ad summatios over a + + a p =. With these alteratios the proof fits Corollary 4.. A good way to thik of Corollary 4. is as a theorem about partial weak compositios, obtaied by droppig the last part from each of the weak compositios i the corollary.
9 A Uifyig Geeralizatio of Sperer s Theorem 9 Corollary 4.2. Fix p 2 ad r. Suppose A j,..., A jp are m differet weak partial compositios of a -set S ito p parts such that for each k [p], the set {A jk : j m} is r-chai-free. The m is bouded by the sum of the r p largest p + -multiomial coefficiets for. A differece betwee this ad Theorem.5 is that Corollary 4.2 has a weaker ad simpler hypothesis but a much weaker boud. But the biggest differece is the omissio of a accompayig LYM iequality. Corollary 4. obviously implies oe, but it is weaker tha that i Theorem 2.5 because, sice the top umber i the latter ca be less tha, the deomiators are much smaller. We do ot preset i Corollary 4.2 a LYM iequality of the kid i Theorem 2.5 for the very good reaso that oe is possible; that is the meaig of Example 2.. The secod specializatio costitutes a weak commo refiemet of Theorems.2/2.2 ad.4/2.4. We call it weak because its specializatio to the case B j = S A j, which is the situatio of Theorems.2/2.2, is weaker tha those theorems. Corollary 4.3. Let r be a positive iteger. Suppose A j, B j are m pairs of sets such that A j B j = ad, for all I [m] with I = r +, there exist distict i, j I for which A j B k A k B j. Let = max j A j + B j. The Aj + B j A j r. Cosequetly, m is bouded by the sum of the r largest biomial coefficiets k for 0 k. This boud ca be attaied for all ad r. Proof. Set p = 2 i Theorems.5/2.5. To attai the boud, let A j rage over all k-subsets of [] ad let B j = [] A j. The last special case of Theorems.5/2.5 we would like to metio is that i which r = ; it uifies Theorems.3/2.3 ad.4/2.4. Corollary 4.4. Suppose A j,..., A jp are m differet weak set compositios ito p parts with the coditio that, for all k [p] ad all distict i, j [m], either A ik = A jk or A ik l k A jl A jk l k A il. ad let max j Aj + + A jp. The Aj + + A jp A j,..., A jp. Cosequetly, m is bouded by the largest p-multiomial coefficiet for. The boud ca be attaied for every ad p.
10 0 Proof. Everythig follows from Theorems.5/2.5 except the attaiability of the upper boud, which is a cosequece of Theorem The maximum umber of compositios Although the bouds i all the previously kow Sperer geeralizatios of Sectio ca be attaied, for the most part that seems ot to be the case i Theorem.5. The key difficulty appears i the combiatio of r-families with compositios as i Corollary 4.. We thik it makes o differece if we allow partial compositios but we have ot proved it. We begi with a refiemet of Lemma 3.. A weak set compositio has shape a,..., a p if A k = a k for all k. Lemma 5.. Give values of, r, ad p such that r p +p p, the boud i Corollary 4. ca be attaied oly by takig all weak compositios of shape a,..., a p that give p- multiomial coefficiet larger tha the r p +-st largest such coefficiet M r p +, ad oe whose shape gives a smaller coefficiet tha the r p -st largest such coefficiet M r p. Proof. First we eed to characterized sharpess i Lemma 3.. Our lemma is a slight improvemet o [6, Lemma 3..3]. Lemma 5.2. I Lemma 3., suppose that M R > 0. The there is equality i the coclusio if ad oly if q k = if M k > M R ad q k = 0 if M k < M R ad also, lettig M R + ad M R be the first ad last M k s equal to M R, q R q R = R R. I Lemma 5., all M k > 0 for k +p p. We assume N is o larger tha +p p. The cotrary case is easily derived from that oe. It is clear that, whe applyig Lemma 3., we have to have i our set of weak compositios all those of the shapes a,..., a p for which > Mr p ad oe for which < Mr p. The rest of the m weak compositios ca have ay shapes for which = Mr p. If M r p > M r p + this meas we must have all weak compositios with shapes for which > Mr p +. To explai why the boud caot usually be attaied, we eed to defie the first appearace of a size a i i the descedig order of p-multiomial coefficiets for. Fix p 3 ad ad let = νp + ρ where 0 ρ < p. I, the ai are the sizes. The multiset of sizes is the form of the coefficiet. Arrage the multiomial coefficiets i decreasig order: M M 2 M 3. There are may such orderigs; choose oe arbitrarily, fix it, ad call it the descedig order of coefficiets. Thus, for example, M = > M 2 = = M 3 = = M pp + if p ν,..., ν ν +, ν,..., ν, ν
11 A Uifyig Geeralizatio of Sperer s Theorem sice M 3,..., M pp + have the same form as M 2, ad M = ν +,..., ν = = M p ρ > M if p, p ρ+ where the form of M has ρ sizes equal to ν +, so M,..., M p all have the same form. ρ As we sca the descedig order of multiomial coefficiets, each possible size κ, 0 κ, appears first i a certai M i. We call M i the first appearace of κ ad label it L κ. For example, if p, L ν = M > L ν+ = L ν = M 2, while if p the L ν = L ν+ = M. It is clear that L ν > L ν >... ad L ν+ > L ν+2 >..., but the way i which the lower L κ s, where κ ν, iterleave the upper oes is ot obvious. We write L k for the k-th L κ i the descedig order of multiomial coefficiets. Thus L = L ν ; L 2 = L ν+ ad L 3 = L ν or vice versa if p, ad L 2 = L ν+ if p while L 3 = L ν+2 or L ν. Theorem 5.3. Give r 2, p 3, ad p, the boud i Corollary 4. caot be attaied if L r > M r p +. The proof depeds o the followig lemma. Lemma 5.4. Let r 2 ad p 3, ad let κ,..., κ r be the first r sizes that appear i the descedig order of p-multiomial coefficiets for. The umber of all coefficiets with sizes draw from κ,..., κ r is less tha r p ad their sum is less tha M + + M r p. Proof. Clearly, κ,..., κ r form a cosecutive set that icludes ν. Let κ be the smallest ad κ the largest. Oe ca verify that, i κ,...,κ,x ad κ,...,κ,y, it is impossible for both x ad y to lie i the iterval [κ, κ ] as log as r p 2 > 0. Proof of Theorem 5.3. Suppose the upper boud of Corollary 4. is attaied by a certai set of weak compositios of S, a -elemet set. For each of the first r sizes κ,..., κ r that appear i the descedig order of p-multiomial coefficiets, L κi has sizes draw from κ,..., κ r ad at least oe size κ i. Takig all coefficiets M k that have the same forms as the L κi, κ i will appear i each positio j i some M k. By hypothesis ad Lemma 5., amog our set of weak compositios, every κ i -subset of S appears i every positio i the weak compositios. If ay subset of S of a differet size from κ,..., κ r appeared i ay positio, there would be a chai of legth r i that positio. Therefore we ca oly have weak compositios whose sizes are amog the first r sizes. By Lemma 5.4, there are ot eough of these to attai the upper boud. Theorem 5.3 ca be hard to apply because we do ot kow M r p +. O the other had, we do kow L κ sice it equals κ,a 2,...,a p where a2,..., a p are as early equal as possible. A more practical criterio for oattaimet of the upper boud is therefore Corollary 5.5. Give r 2, p 3, ad p, the boud i Corollary 4. caot be attaied if L r > L r+.
12 2 Proof. It follows from Lemma 5.4 that L r+ is oe of the first r p coefficiets. Thus L r > L r+ M r p + ad Theorem 5.3 applies. It seems clear that L r will almost always be larger tha L r+ if r 3 or p so our boud will ot be attaied. However, cases of equality do exist. For istace, take p = 3, r = 3, ad = 0; the L 5 = L = 0 5,4, = 260 ad L 6 = L 6 = 0 6,2,2 = 260. Thus if r = 5, Corollary 5.5 does ot apply here. We thik the boud is still ot attaied but we caot prove it. We ca isolate the istaces of equality for each r, but as r grows larger the calculatios quickly become extesive. Thus we state the results oly for small values of r. Propositio 5.6. The boud i Corollary 4. caot be attaied if 2 r 5 ad p 3 ad r, except possibly whe r = 2, p, ad p = 3, 4, 5, or whe r = 4, p 4, ad = 2p, or whe r = 5, p = 3, ad = 0. Proof sketch. Suppose p. We have verified by log but routie calculatios which we omit that L = L 2 > L 3 > L 4 > L 5 > L 6 except that L 4 = L 5 if ρ = p ad p 4 ad ν = ad L 5 = L 6 whe p = ν = 3 ad ρ =. If p the L > L 2 = L 3 > L 4 > L 5 > L 6. This implies the propositio for r = 3, 4, or 5. We approach r = 2 differetly. The largest coefficiets are M = > M 2 = = = M pp + > M pp +2. ν,..., ν ν +, ν,..., ν, ν If pp + r p, the boud is uattaiable by Theorem 5.3. That is the case whe p 6. Refereces [] M. Beck ad T. Zaslavsky, A short geeralizatio of the Meshalki Hochberg Hirsch bouds o compoetwise atichais. I preparatio. [2] B. Bollobás, O geeralized graphs. Acta Math. Acad. Sci. Hug , [3] P. Erdős, O a lemma of Littlewood ad Offord. Bull. Amer. Math. Soc , [4] J. R. Griggs, J. Stahl, ad W. T. Trotter, A Sperer theorem o urelated chais of subsets. J. Combiatorial Theory Ser. A , [5] M. Hochberg ad W. M. Hirsch, Sperer families, s-systems, ad a theorem of Meshalki. A. New York Acad. Sci , [6] D. A. Klai ad G.-C. Rota, Itroductio to Geometric Probability. Cambridge Uiversity Press, Cambridge, Eg., 997. [7] D. A. Lubell, A short proof of Sperer s theorem. J. Combiatorial Theory 966, [8] L. D. Meshalki, Geeralizatio of Sperer s theorem o the umber of subsets of a fiite set. I Russia. Teor. Verojatost. i Primee 8 963, Eglish tras.: Theor. Probability Appl , [9] G.-C. Rota ad L. H. Harper, Matchig theory, a itroductio. I P. Ney, ed., Advaces i Probability ad Related Topics, Vol., pp Marcel Dekker, New York, 97. [0] E. Sperer, Ei Satz über Utermege eier edliche Mege. Math. Z , [] K. Yamamoto, Logarithmic order of free distributive lattices. J. Math. Soc. Japa 6 954,
A unifying generalization of Sperner s theorem
A uifyig geeralizatio of Sperer s theorem Matthias Beck 1, Xueqi Wag 2, ad Thomas Zaslavsky 34 Versio of 25 September 2003. Dedicated to the memories of Pál Erdős ad Lev Meshalki. Abstract: Sperer s boud
More informationDedicated to the memory of Lev Meshalkin.
A Meshalki Theorem for Projective Geometries Matthias Beck ad Thomas Zaslavsky 2 Departmet of Mathematical Scieces State Uiversity of New York at Bighamto Bighamto, NY, U.S.A. 3902-6000 matthias@math.bighamto.edu
More informationLargest families without an r-fork
Largest families without a r-for Aalisa De Bois Uiversity of Salero Salero, Italy debois@math.it Gyula O.H. Katoa Réyi Istitute Budapest, Hugary ohatoa@reyi.hu Itroductio Let [] = {,,..., } be a fiite
More informationWeek 5-6: The Binomial Coefficients
Wee 5-6: The Biomial Coefficiets March 6, 2018 1 Pascal Formula Theorem 11 (Pascal s Formula For itegers ad such that 1, ( ( ( 1 1 + 1 The umbers ( 2 ( 1 2 ( 2 are triagle umbers, that is, The petago umbers
More informationBertrand s Postulate
Bertrad s Postulate Lola Thompso Ross Program July 3, 2009 Lola Thompso (Ross Program Bertrad s Postulate July 3, 2009 1 / 33 Bertrad s Postulate I ve said it oce ad I ll say it agai: There s always a
More informationTHE ASYMPTOTIC COMPLEXITY OF MATRIX REDUCTION OVER FINITE FIELDS
THE ASYMPTOTIC COMPLEXITY OF MATRIX REDUCTION OVER FINITE FIELDS DEMETRES CHRISTOFIDES Abstract. Cosider a ivertible matrix over some field. The Gauss-Jorda elimiatio reduces this matrix to the idetity
More information4 The Sperner property.
4 The Sperer property. I this sectio we cosider a surprisig applicatio of certai adjacecy matrices to some problems i extremal set theory. A importat role will also be played by fiite groups. I geeral,
More informationSOME TRIBONACCI IDENTITIES
Mathematics Today Vol.7(Dec-011) 1-9 ISSN 0976-38 Abstract: SOME TRIBONACCI IDENTITIES Shah Devbhadra V. Sir P.T.Sarvajaik College of Sciece, Athwalies, Surat 395001. e-mail : drdvshah@yahoo.com The sequece
More informationHomework 3. = k 1. Let S be a set of n elements, and let a, b, c be distinct elements of S. The number of k-subsets of S is
Homewor 3 Chapter 5 pp53: 3 40 45 Chapter 6 p85: 4 6 4 30 Use combiatorial reasoig to prove the idetity 3 3 Proof Let S be a set of elemets ad let a b c be distict elemets of S The umber of -subsets of
More informationCommutativity in Permutation Groups
Commutativity i Permutatio Groups Richard Wito, PhD Abstract I the group Sym(S) of permutatios o a oempty set S, fixed poits ad trasiet poits are defied Prelimiary results o fixed ad trasiet poits are
More informationNo four subsets forming an N
No four subsets formig a N Jerrold R. Griggs Uiversity of South Carolia Columbia, SC 908 USA griggs@math.sc.edu Gyula O.H. Katoa Réyi Istitute Budapest, Hugary ohkatoa@reyi.hu Rev., May 3, 007 Abstract
More information# fixed points of g. Tree to string. Repeatedly select the leaf with the smallest label, write down the label of its neighbour and remove the leaf.
Combiatorics Graph Theory Coutig labelled ad ulabelled graphs There are 2 ( 2) labelled graphs of order. The ulabelled graphs of order correspod to orbits of the actio of S o the set of labelled graphs.
More informationSection 5.1 The Basics of Counting
1 Sectio 5.1 The Basics of Coutig Combiatorics, the study of arragemets of objects, is a importat part of discrete mathematics. I this chapter, we will lear basic techiques of coutig which has a lot of
More informationOn Random Line Segments in the Unit Square
O Radom Lie Segmets i the Uit Square Thomas A. Courtade Departmet of Electrical Egieerig Uiversity of Califoria Los Ageles, Califoria 90095 Email: tacourta@ee.ucla.edu I. INTRODUCTION Let Q = [0, 1] [0,
More informationResolution Proofs of Generalized Pigeonhole Principles
Resolutio Proofs of Geeralized Pigeohole Priciples Samuel R. Buss Departmet of Mathematics Uiversity of Califoria, Berkeley Győrgy Turá Departmet of Mathematics, Statistics, ad Computer Sciece Uiversity
More informationInfinite Sequences and Series
Chapter 6 Ifiite Sequeces ad Series 6.1 Ifiite Sequeces 6.1.1 Elemetary Cocepts Simply speakig, a sequece is a ordered list of umbers writte: {a 1, a 2, a 3,...a, a +1,...} where the elemets a i represet
More informationThe log-behavior of n p(n) and n p(n)/n
Ramauja J. 44 017, 81-99 The log-behavior of p ad p/ William Y.C. Che 1 ad Ke Y. Zheg 1 Ceter for Applied Mathematics Tiaji Uiversity Tiaji 0007, P. R. Chia Ceter for Combiatorics, LPMC Nakai Uivercity
More informationAn analog of the arithmetic triangle obtained by replacing the products by the least common multiples
arxiv:10021383v2 [mathnt] 9 Feb 2010 A aalog of the arithmetic triagle obtaied by replacig the products by the least commo multiples Bair FARHI bairfarhi@gmailcom MSC: 11A05 Keywords: Al-Karaji s triagle;
More informationProduct measures, Tonelli s and Fubini s theorems For use in MAT3400/4400, autumn 2014 Nadia S. Larsen. Version of 13 October 2014.
Product measures, Toelli s ad Fubii s theorems For use i MAT3400/4400, autum 2014 Nadia S. Larse Versio of 13 October 2014. 1. Costructio of the product measure The purpose of these otes is to preset the
More informationA 2nTH ORDER LINEAR DIFFERENCE EQUATION
A 2TH ORDER LINEAR DIFFERENCE EQUATION Doug Aderso Departmet of Mathematics ad Computer Sciece, Cocordia College Moorhead, MN 56562, USA ABSTRACT: We give a formulatio of geeralized zeros ad (, )-discojugacy
More informationMATH 324 Summer 2006 Elementary Number Theory Solutions to Assignment 2 Due: Thursday July 27, 2006
MATH 34 Summer 006 Elemetary Number Theory Solutios to Assigmet Due: Thursday July 7, 006 Departmet of Mathematical ad Statistical Scieces Uiversity of Alberta Questio [p 74 #6] Show that o iteger of the
More informationMath F215: Induction April 7, 2013
Math F25: Iductio April 7, 203 Iductio is used to prove that a collectio of statemets P(k) depedig o k N are all true. A statemet is simply a mathematical phrase that must be either true or false. Here
More information(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3
MATH 337 Sequeces Dr. Neal, WKU Let X be a metric space with distace fuctio d. We shall defie the geeral cocept of sequece ad limit i a metric space, the apply the results i particular to some special
More informationSequences and Series of Functions
Chapter 6 Sequeces ad Series of Fuctios 6.1. Covergece of a Sequece of Fuctios Poitwise Covergece. Defiitio 6.1. Let, for each N, fuctio f : A R be defied. If, for each x A, the sequece (f (x)) coverges
More informationAlmost intersecting families of sets
Almost itersectig families of sets Dáiel Gerber a Natha Lemos b Cory Palmer a Balázs Patkós a, Vajk Szécsi b a Hugaria Academy of Scieces, Alfréd Réyi Istitute of Mathematics, P.O.B. 17, Budapest H-1364,
More informationThe Boolean Ring of Intervals
MATH 532 Lebesgue Measure Dr. Neal, WKU We ow shall apply the results obtaied about outer measure to the legth measure o the real lie. Throughout, our space X will be the set of real umbers R. Whe ecessary,
More informationLecture Overview. 2 Permutations and Combinations. n(n 1) (n (k 1)) = n(n 1) (n k + 1) =
COMPSCI 230: Discrete Mathematics for Computer Sciece April 8, 2019 Lecturer: Debmalya Paigrahi Lecture 22 Scribe: Kevi Su 1 Overview I this lecture, we begi studyig the fudametals of coutig discrete objects.
More informationPairs of disjoint q-element subsets far from each other
Pairs of disjoit q-elemet subsets far from each other Hikoe Eomoto Departmet of Mathematics, Keio Uiversity 3-14-1 Hiyoshi, Kohoku-Ku, Yokohama, 223 Japa, eomoto@math.keio.ac.jp Gyula O.H. Katoa Alfréd
More informationLONG SNAKES IN POWERS OF THE COMPLETE GRAPH WITH AN ODD NUMBER OF VERTICES
J Lodo Math Soc (2 50, (1994, 465 476 LONG SNAKES IN POWERS OF THE COMPLETE GRAPH WITH AN ODD NUMBER OF VERTICES Jerzy Wojciechowski Abstract I [5] Abbott ad Katchalski ask if there exists a costat c >
More information6.3 Testing Series With Positive Terms
6.3. TESTING SERIES WITH POSITIVE TERMS 307 6.3 Testig Series With Positive Terms 6.3. Review of what is kow up to ow I theory, testig a series a i for covergece amouts to fidig the i= sequece of partial
More informationMathematical Induction
Mathematical Iductio Itroductio Mathematical iductio, or just iductio, is a proof techique. Suppose that for every atural umber, P() is a statemet. We wish to show that all statemets P() are true. I a
More informationTR/46 OCTOBER THE ZEROS OF PARTIAL SUMS OF A MACLAURIN EXPANSION A. TALBOT
TR/46 OCTOBER 974 THE ZEROS OF PARTIAL SUMS OF A MACLAURIN EXPANSION by A. TALBOT .. Itroductio. A problem i approximatio theory o which I have recetly worked [] required for its solutio a proof that the
More informationMath 2784 (or 2794W) University of Connecticut
ORDERS OF GROWTH PAT SMITH Math 2784 (or 2794W) Uiversity of Coecticut Date: Mar. 2, 22. ORDERS OF GROWTH. Itroductio Gaiig a ituitive feel for the relative growth of fuctios is importat if you really
More informationMath 61CM - Solutions to homework 3
Math 6CM - Solutios to homework 3 Cédric De Groote October 2 th, 208 Problem : Let F be a field, m 0 a fixed oegative iteger ad let V = {a 0 + a x + + a m x m a 0,, a m F} be the vector space cosistig
More informationLecture 2. The Lovász Local Lemma
Staford Uiversity Sprig 208 Math 233A: No-costructive methods i combiatorics Istructor: Ja Vodrák Lecture date: Jauary 0, 208 Origial scribe: Apoorva Khare Lecture 2. The Lovász Local Lemma 2. Itroductio
More informationDisjoint Systems. Abstract
Disjoit Systems Noga Alo ad Bey Sudaov Departmet of Mathematics Raymod ad Beverly Sacler Faculty of Exact Scieces Tel Aviv Uiversity, Tel Aviv, Israel Abstract A disjoit system of type (,,, ) is a collectio
More informationMath 451: Euclidean and Non-Euclidean Geometry MWF 3pm, Gasson 204 Homework 3 Solutions
Math 451: Euclidea ad No-Euclidea Geometry MWF 3pm, Gasso 204 Homework 3 Solutios Exercises from 1.4 ad 1.5 of the otes: 4.3, 4.10, 4.12, 4.14, 4.15, 5.3, 5.4, 5.5 Exercise 4.3. Explai why Hp, q) = {x
More informationSequences of Definite Integrals, Factorials and Double Factorials
47 6 Joural of Iteger Sequeces, Vol. 8 (5), Article 5.4.6 Sequeces of Defiite Itegrals, Factorials ad Double Factorials Thierry Daa-Picard Departmet of Applied Mathematics Jerusalem College of Techology
More informationMAT1026 Calculus II Basic Convergence Tests for Series
MAT026 Calculus II Basic Covergece Tests for Series Egi MERMUT 202.03.08 Dokuz Eylül Uiversity Faculty of Sciece Departmet of Mathematics İzmir/TURKEY Cotets Mootoe Covergece Theorem 2 2 Series of Real
More informationIt is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function.
MATH 532 Measurable Fuctios Dr. Neal, WKU Throughout, let ( X, F, µ) be a measure space ad let (!, F, P ) deote the special case of a probability space. We shall ow begi to study real-valued fuctios defied
More information1. By using truth tables prove that, for all statements P and Q, the statement
Author: Satiago Salazar Problems I: Mathematical Statemets ad Proofs. By usig truth tables prove that, for all statemets P ad Q, the statemet P Q ad its cotrapositive ot Q (ot P) are equivalet. I example.2.3
More informationInjections, Surjections, and the Pigeonhole Principle
Ijectios, Surjectios, ad the Pigeohole Priciple 1 (10 poits Here we will come up with a sloppy boud o the umber of parethesisestigs (a (5 poits Describe a ijectio from the set of possible ways to est pairs
More informationOn matchings in hypergraphs
O matchigs i hypergraphs Peter Frakl Tokyo, Japa peter.frakl@gmail.com Tomasz Luczak Adam Mickiewicz Uiversity Faculty of Mathematics ad CS Pozań, Polad ad Emory Uiversity Departmet of Mathematics ad CS
More informationCSE 191, Class Note 05: Counting Methods Computer Sci & Eng Dept SUNY Buffalo
Coutig Methods CSE 191, Class Note 05: Coutig Methods Computer Sci & Eg Dept SUNY Buffalo c Xi He (Uiversity at Buffalo CSE 191 Discrete Structures 1 / 48 Need for Coutig The problem of coutig the umber
More informationChapter IV Integration Theory
Chapter IV Itegratio Theory Lectures 32-33 1. Costructio of the itegral I this sectio we costruct the abstract itegral. As a matter of termiology, we defie a measure space as beig a triple (, A, µ), where
More informationA NOTE ON PASCAL S MATRIX. Gi-Sang Cheon, Jin-Soo Kim and Haeng-Won Yoon
J Korea Soc Math Educ Ser B: Pure Appl Math 6(1999), o 2 121 127 A NOTE ON PASCAL S MATRIX Gi-Sag Cheo, Ji-Soo Kim ad Haeg-Wo Yoo Abstract We ca get the Pascal s matrix of order by takig the first rows
More informationHoggatt and King [lo] defined a complete sequence of natural numbers
REPRESENTATIONS OF N AS A SUM OF DISTINCT ELEMENTS FROM SPECIAL SEQUENCES DAVID A. KLARNER, Uiversity of Alberta, Edmoto, Caada 1. INTRODUCTION Let a, I deote a sequece of atural umbers which satisfies
More informationConvergence of random variables. (telegram style notes) P.J.C. Spreij
Covergece of radom variables (telegram style otes).j.c. Spreij this versio: September 6, 2005 Itroductio As we kow, radom variables are by defiitio measurable fuctios o some uderlyig measurable space
More informationRandom Models. Tusheng Zhang. February 14, 2013
Radom Models Tusheg Zhag February 14, 013 1 Radom Walks Let me describe the model. Radom walks are used to describe the motio of a movig particle (object). Suppose that a particle (object) moves alog the
More informationMath 104: Homework 2 solutions
Math 04: Homework solutios. A (0, ): Sice this is a ope iterval, the miimum is udefied, ad sice the set is ot bouded above, the maximum is also udefied. if A 0 ad sup A. B { m + : m, N}: This set does
More informationw (1) ˆx w (1) x (1) /ρ and w (2) ˆx w (2) x (2) /ρ.
2 5. Weighted umber of late jobs 5.1. Release dates ad due dates: maximimizig the weight of o-time jobs Oce we add release dates, miimizig the umber of late jobs becomes a sigificatly harder problem. For
More informationIf a subset E of R contains no open interval, is it of zero measure? For instance, is the set of irrationals in [0, 1] is of measure zero?
2 Lebesgue Measure I Chapter 1 we defied the cocept of a set of measure zero, ad we have observed that every coutable set is of measure zero. Here are some atural questios: If a subset E of R cotais a
More information170 P. ERDŐS, r- FREUD ad N. HEGYVÁRI THEOREM 3. We ca costruct a ifiite permutatio satisfyig g ilog log ( 4) [ai, ai+i] < ie c yio i for all i. I the
Acta Math. Hug. 41(1-2), (1983), 169-176. ARITHMETICAL PROPERTIES OF PERMUTATIONS OF INTEGERS P. ERDŐS, member of the Academy, R. FREUD ad N. HEGYVARI (Budapest) For the fiite case let a1, a 2,..., a be
More information(ii) Two-permutations of {a, b, c}. Answer. (B) P (3, 3) = 3! (C) 3! = 6, and there are 6 items in (A). ... Answer.
SOLUTIONS Homewor 5 Due /6/19 Exercise. (a Cosider the set {a, b, c}. For each of the followig, (A list the objects described, (B give a formula that tells you how may you should have listed, ad (C verify
More informationChapter 6 Infinite Series
Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat
More informationDIVISIBILITY PROPERTIES OF GENERALIZED FIBONACCI POLYNOMIALS
DIVISIBILITY PROPERTIES OF GENERALIZED FIBONACCI POLYNOMIALS VERNER E. HOGGATT, JR. Sa Jose State Uiversity, Sa Jose, Califoria 95192 ad CALVIN T. LONG Washigto State Uiversity, Pullma, Washigto 99163
More informationSome remarks for codes and lattices over imaginary quadratic
Some remarks for codes ad lattices over imagiary quadratic fields Toy Shaska Oaklad Uiversity, Rochester, MI, USA. Caleb Shor Wester New Eglad Uiversity, Sprigfield, MA, USA. shaska@oaklad.edu Abstract
More informationThe Random Walk For Dummies
The Radom Walk For Dummies Richard A Mote Abstract We look at the priciples goverig the oe-dimesioal discrete radom walk First we review five basic cocepts of probability theory The we cosider the Beroulli
More informationON THE LEHMER CONSTANT OF FINITE CYCLIC GROUPS
ON THE LEHMER CONSTANT OF FINITE CYCLIC GROUPS NORBERT KAIBLINGER Abstract. Results of Lid o Lehmer s problem iclude the value of the Lehmer costat of the fiite cyclic group Z/Z, for 5 ad all odd. By complemetary
More informationMATH 304: MIDTERM EXAM SOLUTIONS
MATH 304: MIDTERM EXAM SOLUTIONS [The problems are each worth five poits, except for problem 8, which is worth 8 poits. Thus there are 43 possible poits.] 1. Use the Euclidea algorithm to fid the greatest
More informationThe Borel hierarchy classifies subsets of the reals by their topological complexity. Another approach is to classify them by size.
Lecture 7: Measure ad Category The Borel hierarchy classifies subsets of the reals by their topological complexity. Aother approach is to classify them by size. Filters ad Ideals The most commo measure
More informationExercises 1 Sets and functions
Exercises 1 Sets ad fuctios HU Wei September 6, 018 1 Basics Set theory ca be made much more rigorous ad built upo a set of Axioms. But we will cover oly some heuristic ideas. For those iterested studets,
More informationSquare-Congruence Modulo n
Square-Cogruece Modulo Abstract This paper is a ivestigatio of a equivalece relatio o the itegers that was itroduced as a exercise i our Discrete Math class. Part I - Itro Defiitio Two itegers are Square-Cogruet
More informationIntroduction To Discrete Mathematics
Itroductio To Discrete Mathematics Review If you put + pigeos i pigeoholes the at least oe hole would have more tha oe pigeo. If (r + objects are put ito boxes, the at least oe of the boxes cotais r or
More informationIntegrable Functions. { f n } is called a determining sequence for f. If f is integrable with respect to, then f d does exist as a finite real number
MATH 532 Itegrable Fuctios Dr. Neal, WKU We ow shall defie what it meas for a measurable fuctio to be itegrable, show that all itegral properties of simple fuctios still hold, ad the give some coditios
More informationRiesz-Fischer Sequences and Lower Frame Bounds
Zeitschrift für Aalysis ud ihre Aweduge Joural for Aalysis ad its Applicatios Volume 1 (00), No., 305 314 Riesz-Fischer Sequeces ad Lower Frame Bouds P. Casazza, O. Christese, S. Li ad A. Lider Abstract.
More informationA Proof of Birkhoff s Ergodic Theorem
A Proof of Birkhoff s Ergodic Theorem Joseph Hora September 2, 205 Itroductio I Fall 203, I was learig the basics of ergodic theory, ad I came across this theorem. Oe of my supervisors, Athoy Quas, showed
More informationCounting Well-Formed Parenthesizations Easily
Coutig Well-Formed Parethesizatios Easily Pekka Kilpeläie Uiversity of Easter Filad School of Computig, Kuopio August 20, 2014 Abstract It is well kow that there is a oe-to-oe correspodece betwee ordered
More informationThe multiplicative structure of finite field and a construction of LRC
IERG6120 Codig for Distributed Storage Systems Lecture 8-06/10/2016 The multiplicative structure of fiite field ad a costructio of LRC Lecturer: Keeth Shum Scribe: Zhouyi Hu Notatios: We use the otatio
More informationAs stated by Laplace, Probability is common sense reduced to calculation.
Note: Hadouts DO NOT replace the book. I most cases, they oly provide a guidelie o topics ad a ituitive feel. The math details will be covered i class, so it is importat to atted class ad also you MUST
More informationBijective Proofs of Gould s and Rothe s Identities
ESI The Erwi Schrödiger Iteratioal Boltzmagasse 9 Istitute for Mathematical Physics A-1090 Wie, Austria Bijective Proofs of Gould s ad Rothe s Idetities Victor J. W. Guo Viea, Preprit ESI 2072 (2008 November
More informationLecture 10: Mathematical Preliminaries
Lecture : Mathematical Prelimiaries Obective: Reviewig mathematical cocepts ad tools that are frequetly used i the aalysis of algorithms. Lecture # Slide # I this
More informationCIS Spring 2018 (instructor Val Tannen)
CIS 160 - Sprig 2018 (istructor Val Tae) Lecture 5 Thursday, Jauary 25 COUNTING We cotiue studyig how to use combiatios ad what are their properties. Example 5.1 How may 8-letter strigs ca be costructed
More informationCSE 1400 Applied Discrete Mathematics Number Theory and Proofs
CSE 1400 Applied Discrete Mathematics Number Theory ad Proofs Departmet of Computer Scieces College of Egieerig Florida Tech Sprig 01 Problems for Number Theory Backgroud Number theory is the brach of
More informationExpected Norms of Zero-One Polynomials
DRAFT: Caad. Math. Bull. July 4, 08 :5 File: borwei80 pp. Page Sheet of Caad. Math. Bull. Vol. XX (Y, ZZZZ pp. 0 0 Expected Norms of Zero-Oe Polyomials Peter Borwei, Kwok-Kwog Stephe Choi, ad Idris Mercer
More informationif > 6 is sucietly large). Nevertheless, Pichasi has show that the umber of radial poits of a o-colliear set P of poits i the plae that lie i a halfpl
Radial Poits i the Plae Jaos Pach y Micha Sharir z Jauary 6, 00 Abstract A radial poit for a ite set P i the plae is a poit q 6 P with the property that each lie coectig q to a poit of P passes through
More informationRandomized Algorithms I, Spring 2018, Department of Computer Science, University of Helsinki Homework 1: Solutions (Discussed January 25, 2018)
Radomized Algorithms I, Sprig 08, Departmet of Computer Sciece, Uiversity of Helsiki Homework : Solutios Discussed Jauary 5, 08). Exercise.: Cosider the followig balls-ad-bi game. We start with oe black
More informationOn the Linear Complexity of Feedback Registers
O the Liear Complexity of Feedback Registers A. H. Cha M. Goresky A. Klapper Northeaster Uiversity Abstract I this paper, we study sequeces geerated by arbitrary feedback registers (ot ecessarily feedback
More informationSeunghee Ye Ma 8: Week 5 Oct 28
Week 5 Summary I Sectio, we go over the Mea Value Theorem ad its applicatios. I Sectio 2, we will recap what we have covered so far this term. Topics Page Mea Value Theorem. Applicatios of the Mea Value
More informationIntermediate Math Circles November 4, 2009 Counting II
Uiversity of Waterloo Faculty of Mathematics Cetre for Educatio i Mathematics ad Computig Itermediate Math Circles November 4, 009 Coutig II Last time, after lookig at the product rule ad sum rule, we
More informationModel Theory 2016, Exercises, Second batch, covering Weeks 5-7, with Solutions
Model Theory 2016, Exercises, Secod batch, coverig Weeks 5-7, with Solutios 3 Exercises from the Notes Exercise 7.6. Show that if T is a theory i a coutable laguage L, haso fiite model, ad is ℵ 0 -categorical,
More informationChapter 7 COMBINATIONS AND PERMUTATIONS. where we have the specific formula for the binomial coefficients:
Chapter 7 COMBINATIONS AND PERMUTATIONS We have see i the previous chapter that (a + b) ca be writte as 0 a % a & b%þ% a & b %þ% b where we have the specific formula for the biomial coefficiets: '!!(&)!
More informationInternational Journal of Mathematical Archive-3(4), 2012, Page: Available online through ISSN
Iteratioal Joural of Mathematical Archive-3(4,, Page: 544-553 Available olie through www.ima.ifo ISSN 9 546 INEQUALITIES CONCERNING THE B-OPERATORS N. A. Rather, S. H. Ahager ad M. A. Shah* P. G. Departmet
More informationMetric Space Properties
Metric Space Properties Math 40 Fial Project Preseted by: Michael Brow, Alex Cordova, ad Alyssa Sachez We have already poited out ad will recogize throughout this book the importace of compact sets. All
More informationMA131 - Analysis 1. Workbook 3 Sequences II
MA3 - Aalysis Workbook 3 Sequeces II Autum 2004 Cotets 2.8 Coverget Sequeces........................ 2.9 Algebra of Limits......................... 2 2.0 Further Useful Results........................
More informationSequences A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence
Sequeces A sequece of umbers is a fuctio whose domai is the positive itegers. We ca see that the sequece 1, 1, 2, 2, 3, 3,... is a fuctio from the positive itegers whe we write the first sequece elemet
More informationAxioms of Measure Theory
MATH 532 Axioms of Measure Theory Dr. Neal, WKU I. The Space Throughout the course, we shall let X deote a geeric o-empty set. I geeral, we shall ot assume that ay algebraic structure exists o X so that
More informationBoundaries and the James theorem
Boudaries ad the James theorem L. Vesely 1. Itroductio The followig theorem is importat ad well kow. All spaces cosidered here are real ormed or Baach spaces. Give a ormed space X, we deote by B X ad S
More informationChain conditions. 1. Artinian and noetherian modules. ALGBOOK CHAINS 1.1
CHAINS 1.1 Chai coditios 1. Artiia ad oetheria modules. (1.1) Defiitio. Let A be a rig ad M a A-module. The module M is oetheria if every ascedig chai!!m 1 M 2 of submodules M of M is stable, that is,
More informationLet us consider the following problem to warm up towards a more general statement.
Lecture 4: Sequeces with repetitios, distributig idetical objects amog distict parties, the biomial theorem, ad some properties of biomial coefficiets Refereces: Relevat parts of chapter 15 of the Math
More informationProof of Fermat s Last Theorem by Algebra Identities and Linear Algebra
Proof of Fermat s Last Theorem by Algebra Idetities ad Liear Algebra Javad Babaee Ragai Youg Researchers ad Elite Club, Qaemshahr Brach, Islamic Azad Uiversity, Qaemshahr, Ira Departmet of Civil Egieerig,
More informationLecture Notes for Analysis Class
Lecture Notes for Aalysis Class Topological Spaces A topology for a set X is a collectio T of subsets of X such that: (a) X ad the empty set are i T (b) Uios of elemets of T are i T (c) Fiite itersectios
More informationABOUT CHAOS AND SENSITIVITY IN TOPOLOGICAL DYNAMICS
ABOUT CHAOS AND SENSITIVITY IN TOPOLOGICAL DYNAMICS EDUARD KONTOROVICH Abstract. I this work we uify ad geeralize some results about chaos ad sesitivity. Date: March 1, 005. 1 1. Symbolic Dyamics Defiitio
More information4.3 Growth Rates of Solutions to Recurrences
4.3. GROWTH RATES OF SOLUTIONS TO RECURRENCES 81 4.3 Growth Rates of Solutios to Recurreces 4.3.1 Divide ad Coquer Algorithms Oe of the most basic ad powerful algorithmic techiques is divide ad coquer.
More informationProbabilistic Methods in Combinatorics
Probabilistic Methods i Combiatorics Po-She Loh Jue 2009 Warm-up 2 Olympiad problems that ca probably be solved. (Leigrad Math Olympiad 987, Grade 0 elimiatio roud Let A,..., A s be subsets of {,..., M},
More informationComplex Numbers Solutions
Complex Numbers Solutios Joseph Zoller February 7, 06 Solutios. (009 AIME I Problem ) There is a complex umber with imagiary part 64 ad a positive iteger such that Fid. [Solutio: 697] 4i + + 4i. 4i 4i
More informationSolutions to Math 347 Practice Problems for the final
Solutios to Math 347 Practice Problems for the fial 1) True or False: a) There exist itegers x,y such that 50x + 76y = 6. True: the gcd of 50 ad 76 is, ad 6 is a multiple of. b) The ifiimum of a set is
More informationOn Some Properties of Digital Roots
Advaces i Pure Mathematics, 04, 4, 95-30 Published Olie Jue 04 i SciRes. http://www.scirp.org/joural/apm http://dx.doi.org/0.436/apm.04.46039 O Some Properties of Digital Roots Ilha M. Izmirli Departmet
More informationA sequence of numbers is a function whose domain is the positive integers. We can see that the sequence
Sequeces A sequece of umbers is a fuctio whose domai is the positive itegers. We ca see that the sequece,, 2, 2, 3, 3,... is a fuctio from the positive itegers whe we write the first sequece elemet as
More informationDefinition 4.2. (a) A sequence {x n } in a Banach space X is a basis for X if. unique scalars a n (x) such that x = n. a n (x) x n. (4.
4. BASES I BAACH SPACES 39 4. BASES I BAACH SPACES Sice a Baach space X is a vector space, it must possess a Hamel, or vector space, basis, i.e., a subset {x γ } γ Γ whose fiite liear spa is all of X ad
More information