E. Incorrect! Plug n = 1, 2, 3, & 4 into the general term formula. n =, then the first four terms are found by

Size: px
Start display at page:

Download "E. Incorrect! Plug n = 1, 2, 3, & 4 into the general term formula. n =, then the first four terms are found by"

Transcription

1 Calculus II - Problem Solvig Drill 8: Sequeces, Series, ad Covergece Questio No. of 0. Fid the first four terms of the sequece whose geeral term is give by a ( ) : Questio #0 (A) (B) (C) (D) (E) 8,,, 4 8,,, 4 8,,, 4 8,,, 4 8 4,,, A. Icorrect! The sigs are the terms are icorrect. B. Correct! This is the correct aswer foud by pluggig,,, & 4 ito the geeral formula. Feedback o Each Aswer C. Icorrect! The sigs are the terms are icorrect. D. Icorrect! The sigs are the terms are icorrect. E. Icorrect! Plug,,, & 4 ito the geeral term formula. If the geeral term is give by a ( ), the the first four terms are foud by 8 pluggig,,, & 4 ito the formula. We have a, a, a, ad 4 4 a. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

2 Questio No. of 0. Fid the first four terms of the sequece whose geeral term is give by a ( ) : Questio #0 (A),, 9, 64 (B),, 9, 64 (C),, 9, 64 (D),, 9, 64 (E),, 9, 64 A. Correct This is the correct aswer foud by pluggig,,, & 4 ito the geeral formula. B. Icorrect! The sigs are the terms are icorrect. Feedback o Each Aswer C. Icorrect! The sigs are the terms are icorrect. D. Icorrect! The sigs are the terms are icorrect. E. Icorrect! The sigs are the terms are icorrect. If the geeral term is give by a ( ), the the first four terms are foud by pluggig,,, & 4 ito the formula. We have a, a, a 9, ad 4 64 a. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

3 Questio No. of 0. Fid a geeral formula for the sequece 4 8,,,,... 5 Questio #0 (A) (B) (C) (D) a a a + + a (E) Ca t be determied A. Icorrect! Try to recogize a patter. It might help to rewrite / as 6/4. B. Icorrect! Try to recogize a patter. It might help to rewrite / as 6/4. Feedback o Each Aswer C. Correct! This is the correct aswer. It is foud by recogizig the patter. D. Icorrect! Try to recogize a patter. It might help to rewrite / as 6/4. E. Icorrect! Oe of the give aswers is correct. Please try agai. We begi by rewritig the sequece 4 8,,,,... 5 as 4 6 8,,,, We may ow recogize the umerator as ad the deomiator as +. Therefore, the geeral term is a. + Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

4 Questio No. 4 of 0 4. Cosider the sequece with geeral term sequece coverge to? a +. What value does this Questio #04 (A) + (B) (C) (D) (E) + A. Icorrect! Take the limit as approaches ifiity. B. Icorrect! Take the limit as approaches ifiity. Feedback o Each Aswer C. Correct! This is the correct aswer. It is foud by takig the limit as approaches ifiity. D. Icorrect! Take the limit as approaches ifiity. E. Icorrect! Take the limit as approaches ifiity. a + lim a lim. + We fid the value that We have coverges to by takig the limit as approaches. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

5 Questio No. 5 of 0 5. The sequece with geeral term a is: Questio #05 (A) Bouded (B) Mootoic (C) Bouded ad mootoic (D) Not mootoic ad ot bouded (E) Noe of these. A. Icorrect! The sequece is ot bouded. B. Correct! This is the correct aswer. The sequece is mootoic, but ot bouded. Feedback o Each Aswer C. Icorrect! The sequece is ot bouded. D. Icorrect! The sequece is mootoic. E. Icorrect! Oe of the give choices is correct. Please try agai. Give a, it is clear that the sequece is ot bouded sice approaches as gets larger ad larger. Sice this is a strictly icreasig sequece, it is mootoic. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

6 Questio No. 6 of 0 6. a is called Questio #06 (A) A ifiite series (B) A ifiite sequece (C) A geeral term (D) A fiite series (E) A fiite sequece A. Correct! This is the correct aswer. This is a ifiite series. B. Icorrect! A sequece is a list of terms, ot the sum. Feedback o Each Aswer choice C. Icorrect! The geeral term is part of this expressio, but the overall expressio is a ifiite series. D. Icorrect! A fiite series would ot have ifiity as the upper limit. E. Icorrect! A sequece is a list of terms, ot the sum. Expressios i the form a are called ifiite series. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

7 Questio No. 7 of 0 7. What coclusio ca be made about the covergece or divergece of usig the divergece test? Questio #07 (A) Coverge (B) Both coverge ad diverge (C) Diverge (D) Neither coverge or diverge (E) No coclusio ca be made A. Icorrect! Take the limit of the geeral term a approaches ifiity. B. Icorrect! It is ot possible to both coverge ad diverge at the same time. Feedback o Each Aswer C. Correct! This is the correct aswer. Sice the limit of () as approaches ifiity is ot zero, the series diverges. D. Icorrect! The series must either coverge or diverge. E. Icorrect! Take the limit of the geeral term a approaches ifiity. Give, we fid that lim( ). By the divergece test, the series diverges. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

8 Questio No. 8 of 0 8. What coclusio ca be made about the covergece or divergece of usig the divergece test? Questio #08 (A) Coverge (B) Both coverge ad diverge (C) Diverge (D) Neither coverge or diverge (E) No coclusio ca be made A. Icorrect! The series does ot coverge. Remember that just because / has a limitig value of 0, this does ot guaratee covergece. B. Icorrect! It is ot possible to both coverge ad diverge at the same time. A Feedback o Each Aswer C. Icorrect! The series actually does diverge. However, this caot be determied based o the divergece test. D. Icorrect! The series must either coverge or diverge. E. Correct! This is the correct aswer. Based o this tutorial, eve though the limitig value of / is 0, o coclusio ca be made about the covergece without further aalysis. Give, we have lim 0. However, this does ot guaratee covergece accordig to the divergece test. Therefore, o coclusio ca be made based o the divergece test. This series is actually a special case of a ifiite series called the Harmoic series ad is kow to diverge. Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

9 Questio No. 9 of 0 9. Fid the value of (A) i 0 i Questio #09 (B) (C) (D) (E) The series does ot coverge A. Correct! This is the correct aswer. Sice the series is a coverget geometric series, its sum ca be foud easily. B. Icorrect! The series is a covergig geometric series. A Feedback o Each Aswer C. Icorrect! The series is a covergig geometric series. D. Icorrect! The series is a covergig geometric series. E. Icorrect! The series does coverge. It is a geometric series. Note that i 0 i is a geometric series with a ad a r that the series coverges to. r. Sice < r <, we kow Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

10 Questio No. 0 of 0 Questio #0 0. Fid the value of (A) 5 (B) 0 (C) i 0 i 5 (D) 5 (E) The series does ot coverge A. Icorrect! The series is a covergig geometric series. Feedback o Each Aswer B. Correct! This is the correct aswer. Sice the series is a coverget geometric series, its sum ca be foud easily. C. Icorrect! The series is a covergig geometric series. D. Icorrect! The series is a covergig geometric series. E. Icorrect! The series does coverge. It is a geometric series. Note that i 0 i 5 is a geometric series with a 5 ad a 5 0 r kow that the series coverges to. r. Sice < r <, we Solutio RapidLearigCeter.com Rapid Learig Ic. All Rights Reserved

An alternating series is a series where the signs alternate. Generally (but not always) there is a factor of the form ( 1) n + 1

An alternating series is a series where the signs alternate. Generally (but not always) there is a factor of the form ( 1) n + 1 Calculus II - Problem Solvig Drill 20: Alteratig Series, Ratio ad Root Tests Questio No. of 0 Istructios: () Read the problem ad aswer choices carefully (2) Work the problems o paper as eeded (3) Pick

More information

10.6 ALTERNATING SERIES

10.6 ALTERNATING SERIES 0.6 Alteratig Series Cotemporary Calculus 0.6 ALTERNATING SERIES I the last two sectios we cosidered tests for the covergece of series whose terms were all positive. I this sectio we examie series whose

More information

6.3 Testing Series With Positive Terms

6.3 Testing Series With Positive Terms 6.3. TESTING SERIES WITH POSITIVE TERMS 307 6.3 Testig Series With Positive Terms 6.3. Review of what is kow up to ow I theory, testig a series a i for covergece amouts to fidig the i= sequece of partial

More information

INFINITE SEQUENCES AND SERIES

INFINITE SEQUENCES AND SERIES 11 INFINITE SEQUENCES AND SERIES INFINITE SEQUENCES AND SERIES 11.4 The Compariso Tests I this sectio, we will lear: How to fid the value of a series by comparig it with a kow series. COMPARISON TESTS

More information

10.5 Positive Term Series: Comparison Tests Contemporary Calculus 1

10.5 Positive Term Series: Comparison Tests Contemporary Calculus 1 0. Positive Term Series: Compariso Tests Cotemporary Calculus 0. POSITIVE TERM SERIES: COMPARISON TESTS This sectio discusses how to determie whether some series coverge or diverge by comparig them with

More information

Calculus II - Problem Drill 21: Power Series, Taylor and Maclaurin Polynomial Series

Calculus II - Problem Drill 21: Power Series, Taylor and Maclaurin Polynomial Series Calculus II - Problem Drill : Power Series, Taylor ad Maclauri Polyomial Series Questio No. of 0 Istructios: () Read the problem ad aswer choices carefully () Work the problems o paper as 3 4 3 4. Fill

More information

9.3 The INTEGRAL TEST; p-series

9.3 The INTEGRAL TEST; p-series Lecture 9.3 & 9.4 Math 0B Nguye of 6 Istructor s Versio 9.3 The INTEGRAL TEST; p-series I this ad the followig sectio, you will study several covergece tests that apply to series with positive terms. Note

More information

JANE PROFESSOR WW Prob Lib1 Summer 2000

JANE PROFESSOR WW Prob Lib1 Summer 2000 JANE PROFESSOR WW Prob Lib Summer 000 Sample WeBWorK problems. WeBWorK assigmet Series6CompTests due /6/06 at :00 AM..( pt) Test each of the followig series for covergece by either the Compariso Test or

More information

Physics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing

Physics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing Physics 6A Solutios to Homework Set # Witer 0. Boas, problem. 8 Use equatio.8 to fid a fractio describig 0.694444444... Start with the formula S = a, ad otice that we ca remove ay umber of r fiite decimals

More information

PLEASE MARK YOUR ANSWERS WITH AN X, not a circle! 1. (a) (b) (c) (d) (e) 3. (a) (b) (c) (d) (e) 5. (a) (b) (c) (d) (e) 7. (a) (b) (c) (d) (e)

PLEASE MARK YOUR ANSWERS WITH AN X, not a circle! 1. (a) (b) (c) (d) (e) 3. (a) (b) (c) (d) (e) 5. (a) (b) (c) (d) (e) 7. (a) (b) (c) (d) (e) Math 0560, Exam 3 November 6, 07 The Hoor Code is i effect for this examiatio. All work is to be your ow. No calculators. The exam lasts for hour ad 5 mi. Be sure that your ame is o every page i case pages

More information

Review for Test 3 Math 1552, Integral Calculus Sections 8.8,

Review for Test 3 Math 1552, Integral Calculus Sections 8.8, Review for Test 3 Math 55, Itegral Calculus Sectios 8.8, 0.-0.5. Termiology review: complete the followig statemets. (a) A geometric series has the geeral form k=0 rk.theseriescovergeswhe r is less tha

More information

Solutions to Tutorial 5 (Week 6)

Solutions to Tutorial 5 (Week 6) The Uiversity of Sydey School of Mathematics ad Statistics Solutios to Tutorial 5 (Wee 6 MATH2962: Real ad Complex Aalysis (Advaced Semester, 207 Web Page: http://www.maths.usyd.edu.au/u/ug/im/math2962/

More information

Math 113 Exam 3 Practice

Math 113 Exam 3 Practice Math Exam Practice Exam will cover.-.9. This sheet has three sectios. The first sectio will remid you about techiques ad formulas that you should kow. The secod gives a umber of practice questios for you

More information

Calculus II Homework: The Comparison Tests Page 1. a n. 1 n 2 + n + 1. n= n. n=1

Calculus II Homework: The Comparison Tests Page 1. a n. 1 n 2 + n + 1. n= n. n=1 Calculus II Homework: The Compariso Tests Page Questios l coverget or diverget? + 7 3 + 5 coverget or diverget? Example Suppose a ad b are series with positive terms ad b is kow to be coverget. a If a

More information

Quiz 5 Answers MATH 141

Quiz 5 Answers MATH 141 Quiz 5 Aswers MATH 4 8 AM Questio so the series coverges. + ( + )! ( + )! ( + )! = ( + )( + ) = 0 < We ca rewrite this series as the geometric series (x) which coverges whe x < or whe x

More information

4x 2. (n+1) x 3 n+1. = lim. 4x 2 n+1 n3 n. n 4x 2 = lim = 3

4x 2. (n+1) x 3 n+1. = lim. 4x 2 n+1 n3 n. n 4x 2 = lim = 3 Exam Problems (x. Give the series (, fid the values of x for which this power series coverges. Also =0 state clearly what the radius of covergece is. We start by settig up the Ratio Test: x ( x x ( x x

More information

SCORE. Exam 2. MA 114 Exam 2 Fall 2016

SCORE. Exam 2. MA 114 Exam 2 Fall 2016 MA 4 Exam Fall 06 Exam Name: Sectio ad/or TA: Do ot remove this aswer page you will retur the whole exam. You will be allowed two hours to complete this test. No books or otes may be used. You may use

More information

Testing for Convergence

Testing for Convergence 9.5 Testig for Covergece Remember: The Ratio Test: lim + If a is a series with positive terms ad the: The series coverges if L . The test is icoclusive if L =. a a = L This

More information

Ma 530 Introduction to Power Series

Ma 530 Introduction to Power Series Ma 530 Itroductio to Power Series Please ote that there is material o power series at Visual Calculus. Some of this material was used as part of the presetatio of the topics that follow. What is a Power

More information

10.1 Sequences. n term. We will deal a. a n or a n n. ( 1) n ( 1) n 1 2 ( 1) a =, 0 0,,,,, ln n. n an 2. n term.

10.1 Sequences. n term. We will deal a. a n or a n n. ( 1) n ( 1) n 1 2 ( 1) a =, 0 0,,,,, ln n. n an 2. n term. 0. Sequeces A sequece is a list of umbers writte i a defiite order: a, a,, a, a is called the first term, a is the secod term, ad i geeral eclusively with ifiite sequeces ad so each term Notatio: the sequece

More information

1 Lecture 2: Sequence, Series and power series (8/14/2012)

1 Lecture 2: Sequence, Series and power series (8/14/2012) Summer Jump-Start Program for Aalysis, 202 Sog-Yig Li Lecture 2: Sequece, Series ad power series (8/4/202). More o sequeces Example.. Let {x } ad {y } be two bouded sequeces. Show lim sup (x + y ) lim

More information

Definition An infinite sequence of numbers is an ordered set of real numbers.

Definition An infinite sequence of numbers is an ordered set of real numbers. Ifiite sequeces (Sect. 0. Today s Lecture: Review: Ifiite sequeces. The Cotiuous Fuctio Theorem for sequeces. Usig L Hôpital s rule o sequeces. Table of useful its. Bouded ad mootoic sequeces. Previous

More information

Infinite Sequences and Series

Infinite Sequences and Series Chapter 6 Ifiite Sequeces ad Series 6.1 Ifiite Sequeces 6.1.1 Elemetary Cocepts Simply speakig, a sequece is a ordered list of umbers writte: {a 1, a 2, a 3,...a, a +1,...} where the elemets a i represet

More information

Series Review. a i converges if lim. i=1. a i. lim S n = lim i=1. 2 k(k + 2) converges. k=1. k=1

Series Review. a i converges if lim. i=1. a i. lim S n = lim i=1. 2 k(k + 2) converges. k=1. k=1 Defiitio: We say that the series S = Series Review i= a i is the sum of the first terms. i= a i coverges if lim S exists ad is fiite, where The above is the defiitio of covergece for series. order to see

More information

Series Solutions (BC only)

Series Solutions (BC only) Studet Study Sessio Solutios (BC oly) We have itetioally icluded more material tha ca be covered i most Studet Study Sessios to accout for groups that are able to aswer the questios at a faster rate. Use

More information

7 Sequences of real numbers

7 Sequences of real numbers 40 7 Sequeces of real umbers 7. Defiitios ad examples Defiitio 7... A sequece of real umbers is a real fuctio whose domai is the set N of atural umbers. Let s : N R be a sequece. The the values of s are

More information

Alternating Series. 1 n 0 2 n n THEOREM 9.14 Alternating Series Test Let a n > 0. The alternating series. 1 n a n.

Alternating Series. 1 n 0 2 n n THEOREM 9.14 Alternating Series Test Let a n > 0. The alternating series. 1 n a n. 0_0905.qxd //0 :7 PM Page SECTION 9.5 Alteratig Series Sectio 9.5 Alteratig Series Use the Alteratig Series Test to determie whether a ifiite series coverges. Use the Alteratig Series Remaider to approximate

More information

Part I: Covers Sequence through Series Comparison Tests

Part I: Covers Sequence through Series Comparison Tests Part I: Covers Sequece through Series Compariso Tests. Give a example of each of the followig: (a) A geometric sequece: (b) A alteratig sequece: (c) A sequece that is bouded, but ot coverget: (d) A sequece

More information

Please do NOT write in this box. Multiple Choice. Total

Please do NOT write in this box. Multiple Choice. Total Istructor: Math 0560, Worksheet Alteratig Series Jauary, 3000 For realistic exam practice solve these problems without lookig at your book ad without usig a calculator. Multiple choice questios should

More information

The Interval of Convergence for a Power Series Examples

The Interval of Convergence for a Power Series Examples The Iterval of Covergece for a Power Series Examples To review the process: How to Test a Power Series for Covergece. Fid the iterval where the series coverges absolutely. We have to use the Ratio or Root

More information

Infinite Sequence and Series

Infinite Sequence and Series Chapter 7 Ifiite Sequece ad Series 7. Sequeces A sequece ca be thought of as a list of umbers writte i a defiite order: a,a 2,a 3,a 4,...,a,... The umber a is called the first term, a 2 is the secod term,

More information

CHAPTER 10 INFINITE SEQUENCES AND SERIES

CHAPTER 10 INFINITE SEQUENCES AND SERIES CHAPTER 10 INFINITE SEQUENCES AND SERIES 10.1 Sequeces 10.2 Ifiite Series 10.3 The Itegral Tests 10.4 Compariso Tests 10.5 The Ratio ad Root Tests 10.6 Alteratig Series: Absolute ad Coditioal Covergece

More information

Notice that this test does not say anything about divergence of an alternating series.

Notice that this test does not say anything about divergence of an alternating series. MATH 572H Sprig 20 Worksheet 7 Topics: absolute ad coditioal covergece; power series. Defiitio. A series b is called absolutely coverget if the series b is coverget. If the series b coverges, while b diverges,

More information

In this section, we show how to use the integral test to decide whether a series

In this section, we show how to use the integral test to decide whether a series Itegral Test Itegral Test Example Itegral Test Example p-series Compariso Test Example Example 2 Example 3 Example 4 Example 5 Exa Itegral Test I this sectio, we show how to use the itegral test to decide

More information

MA541 : Real Analysis. Tutorial and Practice Problems - 1 Hints and Solutions

MA541 : Real Analysis. Tutorial and Practice Problems - 1 Hints and Solutions MA54 : Real Aalysis Tutorial ad Practice Problems - Hits ad Solutios. Suppose that S is a oempty subset of real umbers that is bouded (i.e. bouded above as well as below). Prove that if S sup S. What ca

More information

Series: Infinite Sums

Series: Infinite Sums Series: Ifiite Sums Series are a way to mae sese of certai types of ifiitely log sums. We will eed to be able to do this if we are to attai our goal of approximatig trascedetal fuctios by usig ifiite degree

More information

Section 11.8: Power Series

Section 11.8: Power Series Sectio 11.8: Power Series 1. Power Series I this sectio, we cosider geeralizig the cocept of a series. Recall that a series is a ifiite sum of umbers a. We ca talk about whether or ot it coverges ad i

More information

d) If the sequence of partial sums converges to a limit L, we say that the series converges and its

d) If the sequence of partial sums converges to a limit L, we say that the series converges and its Ifiite Series. Defiitios & covergece Defiitio... Let {a } be a sequece of real umbers. a) A expressio of the form a + a +... + a +... is called a ifiite series. b) The umber a is called as the th term

More information

Quiz No. 1. ln n n. 1. Define: an infinite sequence A function whose domain is N 2. Define: a convergent sequence A sequence that has a limit

Quiz No. 1. ln n n. 1. Define: an infinite sequence A function whose domain is N 2. Define: a convergent sequence A sequence that has a limit Quiz No.. Defie: a ifiite sequece A fuctio whose domai is N 2. Defie: a coverget sequece A sequece that has a limit 3. Is this sequece coverget? Why or why ot? l Yes, it is coverget sice L=0 by LHR. INFINITE

More information

Read carefully the instructions on the answer book and make sure that the particulars required are entered on each answer book.

Read carefully the instructions on the answer book and make sure that the particulars required are entered on each answer book. THE UNIVERSITY OF WARWICK FIRST YEAR EXAMINATION: Jauary 2009 Aalysis I Time Allowed:.5 hours Read carefully the istructios o the aswer book ad make sure that the particulars required are etered o each

More information

MATH 31B: MIDTERM 2 REVIEW

MATH 31B: MIDTERM 2 REVIEW MATH 3B: MIDTERM REVIEW JOE HUGHES. Evaluate x (x ) (x 3).. Partial Fractios Solutio: The umerator has degree less tha the deomiator, so we ca use partial fractios. Write x (x ) (x 3) = A x + A (x ) +

More information

MAT1026 Calculus II Basic Convergence Tests for Series

MAT1026 Calculus II Basic Convergence Tests for Series MAT026 Calculus II Basic Covergece Tests for Series Egi MERMUT 202.03.08 Dokuz Eylül Uiversity Faculty of Sciece Departmet of Mathematics İzmir/TURKEY Cotets Mootoe Covergece Theorem 2 2 Series of Real

More information

INFINITE SEQUENCES AND SERIES

INFINITE SEQUENCES AND SERIES INFINITE SEQUENCES AND SERIES INFINITE SEQUENCES AND SERIES I geeral, it is difficult to fid the exact sum of a series. We were able to accomplish this for geometric series ad the series /[(+)]. This is

More information

Chapter 6: Numerical Series

Chapter 6: Numerical Series Chapter 6: Numerical Series 327 Chapter 6 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals

More information

THE INTEGRAL TEST AND ESTIMATES OF SUMS

THE INTEGRAL TEST AND ESTIMATES OF SUMS THE INTEGRAL TEST AND ESTIMATES OF SUMS. Itroductio Determiig the exact sum of a series is i geeral ot a easy task. I the case of the geometric series ad the telescoig series it was ossible to fid a simle

More information

Chapter 10: Power Series

Chapter 10: Power Series Chapter : Power Series 57 Chapter Overview: Power Series The reaso series are part of a Calculus course is that there are fuctios which caot be itegrated. All power series, though, ca be itegrated because

More information

Solutions to Practice Midterms. Practice Midterm 1

Solutions to Practice Midterms. Practice Midterm 1 Solutios to Practice Midterms Practice Midterm. a False. Couterexample: a =, b = b False. Couterexample: a =, b = c False. Couterexample: c = Y cos. = cos. + 5 = 0 sice both its exist. + 5 cos π. 5 + 5

More information

MA131 - Analysis 1. Workbook 3 Sequences II

MA131 - Analysis 1. Workbook 3 Sequences II MA3 - Aalysis Workbook 3 Sequeces II Autum 2004 Cotets 2.8 Coverget Sequeces........................ 2.9 Algebra of Limits......................... 2 2.0 Further Useful Results........................

More information

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics:

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics: Chapter 6 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals (which is what most studets

More information

MA131 - Analysis 1. Workbook 9 Series III

MA131 - Analysis 1. Workbook 9 Series III MA3 - Aalysis Workbook 9 Series III Autum 004 Cotets 4.4 Series with Positive ad Negative Terms.............. 4.5 Alteratig Series.......................... 4.6 Geeral Series.............................

More information

Ma 530 Infinite Series I

Ma 530 Infinite Series I Ma 50 Ifiite Series I Please ote that i additio to the material below this lecture icorporated material from the Visual Calculus web site. The material o sequeces is at Visual Sequeces. (To use this li

More information

Chapter 7: Numerical Series

Chapter 7: Numerical Series Chapter 7: Numerical Series Chapter 7 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals

More information

Series III. Chapter Alternating Series

Series III. Chapter Alternating Series Chapter 9 Series III With the exceptio of the Null Sequece Test, all the tests for series covergece ad divergece that we have cosidered so far have dealt oly with series of oegative terms. Series with

More information

SCORE. Exam 2. MA 114 Exam 2 Fall 2016

SCORE. Exam 2. MA 114 Exam 2 Fall 2016 Exam 2 Name: Sectio ad/or TA: Do ot remove this aswer page you will retur the whole exam. You will be allowed two hours to complete this test. No books or otes may be used. You may use a graphig calculator

More information

Practice Test Problems for Test IV, with Solutions

Practice Test Problems for Test IV, with Solutions Practice Test Problems for Test IV, with Solutios Dr. Holmes May, 2008 The exam will cover sectios 8.2 (revisited) to 8.8. The Taylor remaider formula from 8.9 will ot be o this test. The fact that sums,

More information

Are the following series absolutely convergent? n=1. n 3. n=1 n. ( 1) n. n=1 n=1

Are the following series absolutely convergent? n=1. n 3. n=1 n. ( 1) n. n=1 n=1 Absolute covergece Defiitio A series P a is called absolutely coverget if the series of absolute values P a is coverget. If the terms of the series a are positive, absolute covergece is the same as covergece.

More information

Math 181, Solutions to Review for Exam #2 Question 1: True/False. Determine whether the following statements about a series are True or False.

Math 181, Solutions to Review for Exam #2 Question 1: True/False. Determine whether the following statements about a series are True or False. Math 8, Solutios to Review for Exam #2 Questio : True/False. Determie whether the followig statemets about a series are True or False. X. The series a diverges if lim s 5.! False: The series coverges to

More information

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + 62. Power series Defiitio 16. (Power series) Give a sequece {c }, the series c x = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + is called a power series i the variable x. The umbers c are called the coefficiets of

More information

Lecture 2 Appendix B: Some sample problems from Boas, Chapter 1. Solution: We want to use the general expression for the form of a geometric series

Lecture 2 Appendix B: Some sample problems from Boas, Chapter 1. Solution: We want to use the general expression for the form of a geometric series Lecture Appedix B: ome sample problems from Boas, Chapter Here are some solutios to the sample problems assiged for Chapter, 6 ad 9 : 5 olutio: We wat to use the geeral expressio for the form of a geometric

More information

f x x c x c x c... x c...

f x x c x c x c... x c... CALCULUS BC WORKSHEET ON POWER SERIES. Derive the Taylor series formula by fillig i the blaks below. 4 5 Let f a a c a c a c a4 c a5 c a c What happes to this series if we let = c? f c so a Now differetiate

More information

Carleton College, Winter 2017 Math 121, Practice Final Prof. Jones. Note: the exam will have a section of true-false questions, like the one below.

Carleton College, Winter 2017 Math 121, Practice Final Prof. Jones. Note: the exam will have a section of true-false questions, like the one below. Carleto College, Witer 207 Math 2, Practice Fial Prof. Joes Note: the exam will have a sectio of true-false questios, like the oe below.. True or False. Briefly explai your aswer. A icorrectly justified

More information

Solutions to Tutorial 3 (Week 4)

Solutions to Tutorial 3 (Week 4) The Uiversity of Sydey School of Mathematics ad Statistics Solutios to Tutorial Week 4 MATH2962: Real ad Complex Aalysis Advaced Semester 1, 2017 Web Page: http://www.maths.usyd.edu.au/u/ug/im/math2962/

More information

11.6 Absolute Convergence and the Ratio and Root Tests

11.6 Absolute Convergence and the Ratio and Root Tests .6 Absolute Covergece ad the Ratio ad Root Tests The most commo way to test for covergece is to igore ay positive or egative sigs i a series, ad simply test the correspodig series of positive terms. Does

More information

Math 106 Fall 2014 Exam 3.1 December 10, 2014

Math 106 Fall 2014 Exam 3.1 December 10, 2014 Math 06 Fall 0 Exam 3 December 0, 0 Determie if the series is coverget or diverget by makig a compariso DCT or LCT) with a suitable b Fill i the blaks with your aswer For Coverget or Diverget write Coverget

More information

sin(n) + 2 cos(2n) n 3/2 3 sin(n) 2cos(2n) n 3/2 a n =

sin(n) + 2 cos(2n) n 3/2 3 sin(n) 2cos(2n) n 3/2 a n = 60. Ratio ad root tests 60.1. Absolutely coverget series. Defiitio 13. (Absolute covergece) A series a is called absolutely coverget if the series of absolute values a is coverget. The absolute covergece

More information

n n 2 n n + 1 +

n n 2 n n + 1 + Istructor: Marius Ioescu 1. Let a =. (5pts) (a) Prove that for every ε > 0 there is N 1 such that a +1 a < ε if N. Solutio: Let ε > 0. The a +1 a < ε is equivalet with + 1 < ε. Simplifyig, this iequality

More information

Sequences. Notation. Convergence of a Sequence

Sequences. Notation. Convergence of a Sequence Sequeces A sequece is essetially just a list. Defiitio (Sequece of Real Numbers). A sequece of real umbers is a fuctio Z (, ) R for some real umber. Do t let the descriptio of the domai cofuse you; it

More information

5.6 Absolute Convergence and The Ratio and Root Tests

5.6 Absolute Convergence and The Ratio and Root Tests 5.6 Absolute Covergece ad The Ratio ad Root Tests Bria E. Veitch 5.6 Absolute Covergece ad The Ratio ad Root Tests Recall from our previous sectio that diverged but ( ) coverged. Both of these sequeces

More information

9/24/13 Section 8.1: Sequences

9/24/13 Section 8.1: Sequences WebAssig Sectio 8.1: Sequeces (Homework) Curret Score : 21 / 65 Due : Friday, October 25 2013 12:05 PM CDT Jey Griffi Calculus 2, sectio Sectio 400, Fall 2013 Istructor: Richard Madrid 1. 5/5 poits Previous

More information

5 Sequences and Series

5 Sequences and Series Bria E. Veitch 5 Sequeces ad Series 5. Sequeces A sequece is a list of umbers i a defiite order. a is the first term a 2 is the secod term a is the -th term The sequece {a, a 2, a 3,..., a,..., } is a

More information

11.6 Absolute Convrg. (Ratio & Root Tests) & 11.7 Strategy for Testing Series

11.6 Absolute Convrg. (Ratio & Root Tests) & 11.7 Strategy for Testing Series 11.6 Absolute Covrg. (Ratio & Root Tests) & 11.7 Strategy for Testig Series http://screecast.com/t/ri3unwu84 Give ay series Σ a, we ca cosider the correspodig series 1 a a a a 1 2 3 whose terms are the

More information

= lim. = lim. 3 dx = lim. [1 1 b 3 ]=1. 3. Determine if the following series converge or diverge. Justify your answers completely.

= lim. = lim. 3 dx = lim. [1 1 b 3 ]=1. 3. Determine if the following series converge or diverge. Justify your answers completely. MTH Lecture 2: Solutios to Practice Problems for Exam December 6, 999 (Vice Melfi) ***NOTE: I ve proofread these solutios several times, but you should still be wary for typographical (or worse) errors..

More information

Z ß cos x + si x R du We start with the substitutio u = si(x), so du = cos(x). The itegral becomes but +u we should chage the limits to go with the ew

Z ß cos x + si x R du We start with the substitutio u = si(x), so du = cos(x). The itegral becomes but +u we should chage the limits to go with the ew Problem ( poits) Evaluate the itegrals Z p x 9 x We ca draw a right triagle labeled this way x p x 9 From this we ca read off x = sec, so = sec ta, ad p x 9 = R ta. Puttig those pieces ito the itegralrwe

More information

Chapter 6 Infinite Series

Chapter 6 Infinite Series Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat

More information

Math 106 Fall 2014 Exam 3.2 December 10, 2014

Math 106 Fall 2014 Exam 3.2 December 10, 2014 Math 06 Fall 04 Exam 3 December 0, 04 Determie if the series is coverget or diverget by makig a compariso (DCT or LCT) with a suitable b Fill i the blaks with your aswer For Coverget or Diverget write

More information

REVIEW 1, MATH n=1 is convergent. (b) Determine whether a n is convergent.

REVIEW 1, MATH n=1 is convergent. (b) Determine whether a n is convergent. REVIEW, MATH 00. Let a = +. a) Determie whether the sequece a ) is coverget. b) Determie whether a is coverget.. Determie whether the series is coverget or diverget. If it is coverget, fid its sum. a)

More information

M17 MAT25-21 HOMEWORK 5 SOLUTIONS

M17 MAT25-21 HOMEWORK 5 SOLUTIONS M17 MAT5-1 HOMEWORK 5 SOLUTIONS 1. To Had I Cauchy Codesatio Test. Exercise 1: Applicatio of the Cauchy Codesatio Test Use the Cauchy Codesatio Test to prove that 1 diverges. Solutio 1. Give the series

More information

Midterm Exam #2. Please staple this cover and honor pledge atop your solutions.

Midterm Exam #2. Please staple this cover and honor pledge atop your solutions. Math 50B Itegral Calculus April, 07 Midterm Exam # Name: Aswer Key David Arold Istructios. (00 poits) This exam is ope otes, ope book. This icludes ay supplemetary texts or olie documets. You are ot allowed

More information

SOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1.

SOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1. SOLUTIONS TO EXAM 3 Problem Fid the sum of the followig series 2 + ( ) 5 5 2 5 3 25 2 2 This series diverges Solutio: Note that this defies two coverget geometric series with respective radii r 2/5 < ad

More information

n=1 a n is the sequence (s n ) n 1 n=1 a n converges to s. We write a n = s, n=1 n=1 a n

n=1 a n is the sequence (s n ) n 1 n=1 a n converges to s. We write a n = s, n=1 n=1 a n Series. Defiitios ad first properties A series is a ifiite sum a + a + a +..., deoted i short by a. The sequece of partial sums of the series a is the sequece s ) defied by s = a k = a +... + a,. k= Defiitio

More information

Not for reproduction

Not for reproduction STRATEGY FOR TESTING SERIES We ow have several ways of testig a series for covergece or divergece; the problem is to decide which test to use o which series. I this respect testig series is similar to

More information

Math 210A Homework 1

Math 210A Homework 1 Math 0A Homework Edward Burkard Exercise. a) State the defiitio of a aalytic fuctio. b) What are the relatioships betwee aalytic fuctios ad the Cauchy-Riema equatios? Solutio. a) A fuctio f : G C is called

More information

f(x) dx as we do. 2x dx x also diverges. Solution: We compute 2x dx lim

f(x) dx as we do. 2x dx x also diverges. Solution: We compute 2x dx lim Math 3, Sectio 2. (25 poits) Why we defie f(x) dx as we do. (a) Show that the improper itegral diverges. Hece the improper itegral x 2 + x 2 + b also diverges. Solutio: We compute x 2 + = lim b x 2 + =

More information

Additional Notes on Power Series

Additional Notes on Power Series Additioal Notes o Power Series Mauela Girotti MATH 37-0 Advaced Calculus of oe variable Cotets Quick recall 2 Abel s Theorem 2 3 Differetiatio ad Itegratio of Power series 4 Quick recall We recall here

More information

Roberto s Notes on Infinite Series Chapter 1: Sequences and series Section 3. Geometric series

Roberto s Notes on Infinite Series Chapter 1: Sequences and series Section 3. Geometric series Roberto s Notes o Ifiite Series Chapter 1: Sequeces ad series Sectio Geometric series What you eed to kow already: What a ifiite series is. The divergece test. What you ca le here: Everythig there is to

More information

Math 112 Fall 2018 Lab 8

Math 112 Fall 2018 Lab 8 Ma Fall 08 Lab 8 Sums of Coverget Series I Itroductio Ofte e fuctios used i e scieces are defied as ifiite series Determiig e covergece or divergece of a series becomes importat ad it is helpful if e sum

More information

Arkansas Tech University MATH 2924: Calculus II Dr. Marcel B. Finan

Arkansas Tech University MATH 2924: Calculus II Dr. Marcel B. Finan Arkasas Tech Uiversity MATH 94: Calculus II Dr Marcel B Fia 85 Power Series Let {a } =0 be a sequece of umbers The a power series about x = a is a series of the form a (x a) = a 0 + a (x a) + a (x a) +

More information

MIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS

MIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS MIDTERM 3 CALCULUS MATH 300 FALL 08 Moday, December 3, 08 5:5 PM to 6:45 PM Name PRACTICE EXAM S Please aswer all of the questios, ad show your work. You must explai your aswers to get credit. You will

More information

Section 5.5. Infinite Series: The Ratio Test

Section 5.5. Infinite Series: The Ratio Test Differece Equatios to Differetial Equatios Sectio 5.5 Ifiite Series: The Ratio Test I the last sectio we saw that we could demostrate the covergece of a series a, where a 0 for all, by showig that a approaches

More information

1 Introduction to Sequences and Series, Part V

1 Introduction to Sequences and Series, Part V MTH 22 Calculus II Essex Couty College Divisio of Mathematics ad Physics Lecture Notes #8 Sakai Web Project Material Itroductio to Sequeces ad Series, Part V. The compariso test that we used prior, relies

More information

Math 163 REVIEW EXAM 3: SOLUTIONS

Math 163 REVIEW EXAM 3: SOLUTIONS Math 63 REVIEW EXAM 3: SOLUTIONS These otes do ot iclude solutios to the Cocept Check o p8. They also do t cotai complete solutios to the True-False problems o those pages. Please go over these problems

More information

Strategy for Testing Series

Strategy for Testing Series Strategy for Testig Series We ow have several ways of testig a series for covergece or divergece; the problem is to decide which test to use o which series. I this respect testig series is similar to itegratig

More information

9.3 Power Series: Taylor & Maclaurin Series

9.3 Power Series: Taylor & Maclaurin Series 9.3 Power Series: Taylor & Maclauri Series If is a variable, the a ifiite series of the form 0 is called a power series (cetered at 0 ). a a a a a 0 1 0 is a power series cetered at a c a a c a c a c 0

More information

Sequences. A Sequence is a list of numbers written in order.

Sequences. A Sequence is a list of numbers written in order. Sequeces A Sequece is a list of umbers writte i order. {a, a 2, a 3,... } The sequece may be ifiite. The th term of the sequece is the th umber o the list. O the list above a = st term, a 2 = 2 d term,

More information

Math 113 Exam 4 Practice

Math 113 Exam 4 Practice Math Exam 4 Practice Exam 4 will cover.-.. This sheet has three sectios. The first sectio will remid you about techiques ad formulas that you should kow. The secod gives a umber of practice questios for

More information

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and MATH01 Real Aalysis (2008 Fall) Tutorial Note #7 Sequece ad Series of fuctio 1: Poitwise Covergece ad Uiform Covergece Part I: Poitwise Covergece Defiitio of poitwise covergece: A sequece of fuctios f

More information

MH1101 AY1617 Sem 2. Question 1. NOT TESTED THIS TIME

MH1101 AY1617 Sem 2. Question 1. NOT TESTED THIS TIME MH AY67 Sem Questio. NOT TESTED THIS TIME ( marks Let R be the regio bouded by the curve y 4x x 3 ad the x axis i the first quadrat (see figure below. Usig the cylidrical shell method, fid the volume of

More information

Math 113 Exam 3 Practice

Math 113 Exam 3 Practice Math Exam Practice Exam 4 will cover.-., 0. ad 0.. Note that eve though. was tested i exam, questios from that sectios may also be o this exam. For practice problems o., refer to the last review. This

More information

Solutions to Homework 7

Solutions to Homework 7 Solutios to Homework 7 Due Wedesday, August 4, 004. Chapter 4.1) 3, 4, 9, 0, 7, 30. Chapter 4.) 4, 9, 10, 11, 1. Chapter 4.1. Solutio to problem 3. The sum has the form a 1 a + a 3 with a k = 1/k. Sice

More information

Math 116 Second Midterm November 13, 2017

Math 116 Second Midterm November 13, 2017 Math 6 Secod Midterm November 3, 7 EXAM SOLUTIONS. Do ot ope this exam util you are told to do so.. Do ot write your ame aywhere o this exam. 3. This exam has pages icludig this cover. There are problems.

More information