NO. ANSWER MARK 1. (a) Reflection 1 (b) At P and is virtual 1 (c) Upright//same size//laterally inverted 1 (d) 8:00 1 TOTAL 4

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1 SCHEME ANSWER STRUCTURE TRIAL SBP 206. (a) Reflection (b) At P and is virtual (c) Upright//same size//laterally inverted (d) 8:00 TOTAL 4 2. (a) (i) Uniform acceleration / Velocity increases uniformly Reject: acceleration / velocity increase (ii) Gravitational potential energy Kinetic energy (b) mgh = ½ mv 2 (m) (0)(0)= ½ (m)v 2 v = 4.4 m s - (awu) (c) no change TOTAL 5 3. (a) Number of complete oscillation in one second. (b) - Higher energy / short wavelength / less diffract - Travel further (c) - Time between source and rock layer = 0.2 s - Depth, = vt = 4000 x 0.2 = 800 m (awu) TOTAL 6 4. (a) Amount of heat required to change the phase of kg of solid to liquid at constant temperature that is melting point. (b) (i) Q = Pt = 000 x (70 50) = J (awu) (ii) m = X X = 0.6 m X = 0.6, m = = = 0.24 kg (awu) (iii) It takes time for the heat to be distributed to all part of the ice. TOTAL 7

2 5. (a) Upward force due to displaced fluid (air). (b) (i) Volume of air displaced in Diagram 5.2 is bigger than that in Diagram 5. (ii) Buoyant force in Diagram 5.2 is bigger than that in Diagram 5. (iii) Pulling force in Diagram 5.2 is more than in Diagram 5. (c) The bigger the volume of the air displaced, the bigger the buoyant force (d) The bigger the buoyant force the bigger the pulling force (e) Easier Because the density of air is less // Smaller buoyant force TOTAL 8 6. (a) V is directly proportional to I provided that the physical quantities and temperature remains constant. (b) (i) Diagram 6. bulbs are connected in parallel and D6.2 bulbs are connected in series (ii) (Brightness (of bulbs) in) D6. is more than Diagram 6.2 // viceversa (iii) (Potential difference in) Diagram 6. is more than Diagram 6.2 // vice-versa (c) (i) When bulbs are arranged in parallel, brightness of bulb increased // vice-versa (ii) Bulbs in parallel, potential difference more / equal to p.d. of the battery // vice-versa (d) Q > P =R (e) Effective resistance of P and R is more than Q // Current, I is more in bulb Q / vice-versa TOTAL 8 Awesome physics_ 2

3 7. (a) (i) Current produced due to the cutting/changing of magnetic flux (ii) North (b) Note: Vertical position of coil- V =0 amplitude (M) Horizontal position of coil- V= max (+ve) or max (-ve)amplitude (M) (c) (i) - The greater the number of turns of coil - more cutting of magnetic flux (ii) - soft iron core (iii) - concentrate the magnetic flux - curved/magnadur magnet (or sketch by student) - to produce radial magnetic field 2 TOTAL 0 8. (a) Nuclear fission is the splitting of a heavy nucleus into two lighter nuclei, which subsequently emit either two or three neutrons and release of large amounts of energy. (b) To slow down the neutron (c) Nuclear energy-heat energy electrical energy (d) E = mc 2 = (2.998 x 0-28 )(3 x 0 8 ) 2 = x 0 - J (awu) (e) (i) - Boron / cadmium - to absorb some of the neutrons // reduce the rate of the fission reaction (ii) - heavy water - high specific heat capacity (iii) - Thick - to prevent leakage of radiation from the reactor core (f) R TOTAL 2 Awesome physics_ 3

4 TRIAL MSAB (a) One colour / single wavelength (b) M bend downward (toward normal) when enter prism. M2 bend downward (away normal) when out from prism. 2 (c) A light spot / a beam / a dot (d) A spectrum / 7colours light (rejects Rainbow) TOTAL 5 3. (a) 28 o C (b) Same / unchanged / equal / remain / constant (c) 0. (3.6.0) / 0. (2.6) / 0. (3.6.0) 60 / 0. (2.6) 60 / 00 (3.6.0) / 00 (2.6) / 00 (3.6.0) 60 / 00 (2.6) 60 (d) State the answer J OR 0.26 kw min / 260 W min / 5.6 kj (must with unit) Q = m = 0.05 (awu) = J kg / 32 kj kg - - (awu) TOTAL 6 Awesome physics_ 4

5 4. (a) P: AND Q: NOR (b) (i) Input Output of LED Switch X Switch Y Red Yellow Green M: Red M2: Yellow M3: Green (ii) Green (iii) Limit the current TOTAL 7 5. (a) Friction (force) (b) (i) 5. (a) < 5. (b) / 5. (a) is smaller / less / lower / vice-versa (ii) 5. (a) < 5. (b) / 5. (a) is smaller / less / lower / vice-versa (iii) 5. (a) < 5. (b) / 5. (a) is smaller / less / lower / vice-versa (c) (i) acceleration increases, resultant force increases / or vice-versa (d) (ii) Forces in equilibrium / balanced forces / unbalanced forces - Stay stationary / no move / rest - F < friction / unable to overcome friction TOTAL 8 Awesome physics_ 5

6 UPSS 2 SEM 2 F4 205 MRSM TGB. (a) Convex lens (b) Refraction of light (c) (i) Increase // larger // bigger (ii) More light pass through the convex lens // More light can be captured (entered) TOTAL 4 2. (a) Simple mercury barometer (b) Less than 76 cm (c) (i) 0 cm Hg (ii) 26 cm Hg (d) 5 P = ρgh =.0 x (0) (h) =.0 x 0.0 x 0 h = 0000 = 0 m 5 5 (awu) TOTAL 6 3. (a) Aerofoil (b) (i) The speed of air flow at above is lower than above // vice versa (ii) The air pressure above is higher than below // vice versa (iii) (c) (i) When speed of air increase, the pressure of air decrease // vice versa (ii) Bernoulli s principle TOTAL 6 Awesome physics_ 6

7 4. (a) (i) Refraction of light (b) (i) The bending of the pencil in Diagram 4.2 is higher // more than in Diagram 4. // vice versa (ii) The density of distilled water is less than the sea water. (iii) The densities of water increase, the bending of the pencil increase // vice versa (c) (i) 2 (ii) Real depth H η = = Apparent depth h = h 0.4 h = = 0.3 m.33 (awu) TOTAL 8 5. (a) The angle of incidence when the angle of refraction is 90 o. (b) No refraction occur // light does not bend at 0 o. (c) (i) The angle of incidence at point B in semicircular block P equal with Q (ii) The critical angle of semicircular block P higher than semicircular block Q. (iii) The density of the glass block P lower than Q (iv) Density of the glass block increase, the critical angle decrease (d) (i) Refraction (ii) Total internal reflection TOTAL 8 Awesome physics_ 7

8 PHY-STAR MRSM TGB 206. (a) A substance which has unstable nucleus that always decay to be more stable by emitting radioactive emissions. (b) P - gamma ray Q - beta particle (c) P has no charge / neutral Q is negatively charged (d) (i) Beta particle Can penetrate the box (ii) Long half life long lasting // no need to replace frequently (iii) Solid state easy to handle (e) Y TOTAL 2 TRIAL SBP 20. (a) Lights with one colour or one wavelength (b) Constructive interference takes place and bright fringes are observed. Destructive interference takes place and dark fringes are observed. (c) x = =.35 mm =.35 x 0 m ax 0.5 x 0 x.35 x 0 = = D.5-7 = 4.5 x 0 m (awu) TOTAL 5 Awesome physics_ 8

9 2. (a) Convex mirror (b) It can provide a wider field of view than plan mirror (c) (i) 3 (ii) Virtual, upright and diminished (d) Size of image increase TOTAL 7 Awesome physics_ 9

10 ESSAY SECTION B TRIAL STATE KEDAH 205. (a) Depth // density // acceleration due to gravity (b) (i) Size : P < Q Depth : P > Q Pressure : P > Q (ii) The bigger the depth, the smaller the size of the air bubble (iii) The bigger the depth, the higher the pressure on the air bubble (iv) The higher the pressure, the smaller the volume (c) When the volume of a gas is decreased, the same number of molecules move in a smaller space. The molecules collide more frequently with the walls of the bubble. A larger force acts on the walls of the bubble. Therefore pressure increases. (max. 3) (d) Modification Characteristics Attire: Water proof // Tight fitting Extra equipment: Flippers Gas tank: Light material Smaller size Contains oxygen rich air at high pressure Reason Does not become wet // Does not absorb water // Less water resistance Help the diver to swim under water Smaller weight // Smaller load for the diver to carry Reduces the weight of the tank Diver can stay longer under water Note : Extra equipment includes mask, pressure gauge, dive 0 watch, dive light, buoyancy control device, signalling device etc TOTAL 20 Awesome physics_ 0

11 NO ANSWER MARK 2. (a) A substance that has a conductivity between the conductivity of an insulator and a conductor / metal (b) (i) To increase the conductivity // To reduce the resistivity (ii) Doping with boron produces a p-type semiconductor Majority charge carriers are holes Doping with phosphorus produces a n-type semiconductor Majority charge carriers are electrons (c) During the first half cycle : - the resistance of the diode is low - a current flows in the circuit // the diode is forward biased During the next half cycle : - the resistance of the diode is very high - no current flows in the circuit // the diode is reverse biased (d). thermistor replaces the resistor 2. resistor replaces the LDR 3. bell replaces the bulb 4. complete circuit When the surrounding is hot : 5. the resistance of the thermistor decreases 6. the potential difference across the thermistor decreases 7. the potential difference across the resistor increases 8. the base current increases the transistor is switched on 9. the collector current flows 0. the bell ring 0 TOTAL 20 Awesome physics_

12 ESSAY SECTION c TRIAL SBP (a) Archimedes Principle (b) Total density of ship < density of water Buoyant Force = Total weight of ship (ii) Virtual, Upright, Same size 2 (c) (i) To ensure the ship will not be overload // ensure the safety of ship (ii) To enable the ship to travel safely in different densities of sea water (d) Decision making (e) Characteristics Streamlined shape High strength of metal Wide base cross section area High volume of air space in the ship Reason To reduce water resistance To withstand high water pressure So that ship can float//prevent from overturn // ship more stable // ship not sink deeper Produce air buoyant force// ship can float Structure P Streamlined shape, High strength of metal, Wide base cross section area, High volume of air space in the ship Volume of water displaced = Volume of wooden block m 3 V = = = 3.75 x 0 m ρ Weight of load + Weight of wooden block = weight of water displaced Weight of load + Weight of wooden block = ρvg -3 Weight of load + (3 x 0) = 000 x 3.75 x 0 x 0 Weight of load + (3 x 0) = 37.5 Weight of load = = 7.5 N Mass of load = 0.75 kg (awu) TOTAL 20 Awesome physics_ 2

13 EDITED: FINAL F5 2. (a) (i) Unstable isotope that decay and emit radioactive emissions. (ii) Radioisotope source is placed below the card. Geiger-Muller tube is placed vertically above the card A high readings indicates that the card is thinner or low (b) Making decision Characteristic Reason Physical state: Solid Easy to manage// easy to handle Emitted ray: Beta ray less dangerous// harmful // low ionising power Half-life: long Can use for longer time // save cost // no need to replace often Penetrating power: Can penetrate through Moderate the card Choose Y It is a solid, emits beta ray, moderate penetrating power and long half-life. (c) 0 Axis Shape N = initial activity T½ (d) Time taken = 4T½ = 4 4 = 6 days 4 (awu) TOTAL 20 Awesome physics_ 3