Spring 2019 United Soccer Peoria Game Schedule

Size: px
Start display at page:

Download "Spring 2019 United Soccer Peoria Game Schedule"

Transcription

1 Please leave the following at home: Animals, drugs/alcohol, scooters/skateboards/bicycles. Please remember: 1. These are kids. 2. This is a game. 3. The coaches volunteer. 4. The referees are human. 5. These are not professional sports. Spring 2019 United Soccer Peoria Game Schedule *Coaches & players only on one sideline; both teams' spectators on opposite sideline. **No spectators behind the goals. At CCV STARS it's

2 Boys: 4 yrs. old-kindergarten Field 6A 6B 6A 6A 6B 6A 6A 6B 6A 6A 6B 6A 8:00 8:00 8:45 9:30 9:30 10:15 11:00 11:00 11:45 12:30 12:30 1:15 2/23 AN DU PT KQ BI GX HW OS FM EV LR CJ 3/2 SX KL IJ AF TU QV MN BG CH DE RW OP 3/9 CD IN KP ST AB QR EF GH LM JO UV WX 3/16 NP MO IK VX QS EG AC FH RT UW BD JL 3/23 AD BC JK QT NO EH IL UX RS MP FG VW 3/30 IM KO AE JN QU TX CG BF SW RV LP DH 4/6 KN BE AH QX TW JM SV IP LO CF RU DG 4/13 JP LN CE QW KM AG TV SU RX IO DF BH A Morrell I Gilles Q Thammavongsa B Buckley J Wall R Smith C Hayes K Cox S Osborne D Fechner L Holte T Bosse E Demos M Edmonson U Garrish F Hague N Bolstad V Frevert G Lehmer O Valentine W Conklin H Thomas P Endicott X Quintana

3 Girls: 4 yrs. old-kindergarten Field 6C 6B 6C 6C 6B 6C 6C 6B 6C 6C 6B 6C 8:00 8:45 8:45 9:30 10:15 10:15 11:00 11:45 11:45 12:30 1:15 1:15 2/23 AN EV GX PT OS HW KQ CJ DU FM BI LR 3/2 MN AF CH TU SX QV DE BG IJ KL OP RW 3/9 WX IN AB QR JO GH CD UV KP ST LM EF 3/16 UW MO AC FH JL RT QS IK EG BD VX NP 3/23 NO RS AD QT EH UX JK MP BC VW FG IL 3/30 AE SW RV JN QU LP TX CG DH KO IM BF 4/6 TW SV AH JP DG KN JM CF BE QX LO RU 4/13 AG SU CE BH LN DF QW RX IO JP KM TV A Olsen I Weedman Q Handley B Clements J Boyd R Robinson C Fetter K Trevillian S Wolfe D Coughlin L Meehan T Henjum E Griffin M Rideout U Paliotto F Moss N Stone V Holland G Bishop O Tues TBD W Presco H Colclough P Barone X Lebers

4 Boys: 1st/2nd Grade Field 7A 7B 7A 7B 7A 7B 7A 7B 7A 7B 8:00 8:00 8:55 8:55 9:50 9:50 10:45 10:45 11:40 11:40 2/23 IJ *DF BH ST AE CG LR MQ KO NP 3/2 KT CH OP *MR EF DG BI LS AJ NQ 3/9 BE KR FJ MN CD QS AH PT LO GI 3/16 NT LM KQ AG BC OS EI DJ PR FH 3/23 GH EJ BD PS LN OT AC KM FI QR 3/30 LP KN *AD HI CE BF GJ QT MO RS 4/6 PQ OR MT DI AB NS CJ EH KL FG 4/13 NR LT BJ EG *FA OQ DH CI *KP MS 4/27 BG DE CF KS MP HJ *LQ NO RT AI A Witt H Zarob TOURNAMENT (2 games each) N Kwiat B Morrell I Souza O Zahlmann C Hague J Baggett P Griffiths D Saka Q Polk E Matthews K Feagins R Monday TBD F Woodhull L Kenick S Thomas G Robertson M Wineinger T Randell

5 Girls: 1st/2nd Grade Field 7C 1B 7C 1B 7C 1B 7C 1B 7C 1B 8:00 8:00 8:55 8:55 9:50 9:50 10:45 10:45 11:40 11:40 2/23 BH CG LR IJ MQ ST DF NP AE KO 3/2 LS BI AJ *CH KT MR OP EF DG NQ 3/9 KR PT LO GI FJ CD BE QS AH MN 3/16 AG LM KQ NT OS EI PR DJ FH BC 3/23 *LN EJ AC KM BD OT GH PS *FI QR 3/30 CE GJ HI KN BF MO LP AD QT RS 4/6 KL NS FG DI AB OR PQ CJ EH MT 4/13 *KP EG MS DH OQ LT *AF BJ NR CI 4/27 *IA LQ **RT *BG CF HJ MP NO KS DE A Colclough H McCracken TOURNAMENT (2 games each) N Young B Ritzheimer I Edmonson O Krpata C Wilmsen J Smith P Stevens D Rolfes Q O'Connor E Turner K DiSalvo R Martinez F Demos L Settle S Moniz G Lavery M Sorensen T Schlingof **First team listed wears practice vests.

6 Boys: 3rd/4th Grade Field 3A 3A 2A 2A 2A 2A 8:00 9:05 9:05 10:10 11:15 12:20 2/23 AB KL IJ GH CD EF 3/2 AL BG FK DI EJ CH 3/9 CF IL BE AD HK GJ 3/16 FJ AK DH BL CG EI 3/23 JL BC HI AE GK DF 3/30 CL AJ FI BK EH DG 4/6 AC IG HL DE JK BF 4/13 FH EG BJ DL CK AI 4/27 GL AF HJ IK BD CE A Saulnier TOURNAMENT (2 games each) G Travers B Zarob H Martin C Canedo I Hayes D Chaves J Smith E Stevens K Ellefritz F Pors L Wednesday TBD

7 Girls: 3rd/4th Grade Field 2A 2B 2B 2B 2B 2B 2A 2B 8:00 8:00 9:05 10:10 11:15 12:20 1:25 1:25 2/23 MN KL *AB CD OP GH IJ EF 3/2 AC NP BD IK EG MO FH JL 3/9 JK BC MP AD FG EH IL NO 3/16 KO LP CG AE DH BF IM JN 3/23 CK GO AI HP BJ FN EM DL 3/30 KP AF BG DE *CH JO IN LM 4/6 CF JM AH KN DG IP LO BE 4/13 KM AG CE *JP *IO **LN BH *DF 4/27 A Chaydez TOURNAMENT (Quarter-Finals) TOURNAMENT (two games each) I Fleming B Handley J Salmans C Bosse K Neese D Edmonson L Fulmer E Dinbokowitz M Scheffler F Chisholm N McInerney G Galarza O Sixel H Bushbaum P Matthews **First team listed wears practice vests.

8 Boys: 5th/6th Grade Field 4B 4B 4B 4B 4B 8:00 9:05 10:10 11:15 12:20 2/23 CH AJ DG BI EF 3/2 GI FJ AH BE CD 3/9 AG BC DJ EI FH 3/16 AE IJ CG DF BH 3/23 GJ BF CE HI AD 3/30 BD GH EJ AC FI 4/6 EH FG AB DI CJ 4/13 BJ DH CI *AF EG 4/27 AI CF *BG HJ DE A Saulnier TOURNAMENT (two games each) F Segura B Heil G Totherow C Blosser H Warren D Kitchen I Hayes E Chaves J Belle

9 Girls: 5th/6th Grade Field 4A 3B 4A 3B 4A 4A 4A 8:00 8:00 9:05 9:05 10:10 11:15 12:20 2/23 KL EF MN AB IJ GH CD 3/2 EI FK BH GJ CM DN AL 3/9 JM AC KN BD IL EG FH 3/16 FM CJ GN AH BI DK EL 3/23 *EH JK LN BC IM FG AD 3/30 AJ FL CE BK DI GM HN 4/6 *IK JN LM DH BF CG AE 4/13 AK BL DG FJ CI EN HM 4/27 JL DE AF CH IN KM *BG A Figg TOURNAMENT (two games each) H Aspaas B Stewart I Neese C Schuff J Watson D Loper K Beaumont E Zacharias L Beaubien F McMillon M Tolentino I G Johnson N Tolentino II

10 Boys: 7th/8th Grade Field PEO-3 PEO-3 PEO-3 SUR-10 SUR-10 10:30 12:00 1:30 tbd tbd 2/23 EF CD AB - - 3/2 BD AF CE - - 3/9 A B CD E (earlier) F 3/16 CF BE AD - - 3/23 E AB F C D 3/30 BC AE DF - - 4/6 C EF D A B 4/13 DE BF AC - - 4/27 TOURNAMENT TOURNAMENT A Gordon D Allmond E Surprise 1 B St. Clair E Luzuriaga F Surprise 2 C Young F Carpenter G Surprise 3 H Surprise 4 PEO-CCV Peoria 7007 W Happy Valley Rd, Peoria, SUR-CCV Surprise W Cholla St, Surprise, 85379

11 Girls: 7th/8th Grade Field PEO-1 PEO-1 PEO-1 PEO-1 8:00 9:30 11:00 12:30 2/23 EF AB GH CD 3/2 FH EG BD AC 3/9 EH BC FG AD 3/16 DH AE CG BF 3/23 CH AF DE BG 3/30 CF BE DG AH 4/6 DF AG CE BH 4/13 4/27 A Beaumont Chamionship Series - TBD Chamionship Series -TBD Chamionship Series - TBD E Bishop B Johnson F Chandler C Olson G Bell D Kohatsu H Parrish PEO-CCV Peoria 7007 W Happy Valley Rd, Peoria, 85383

12 High School Training Academy Field Time 5A/B 7:00am-9:00am 2/23 Team 1 Team 2 3/2 Team 1 Team 2 3/9 Team 1 Team 2 3/16 Team 1 Team 2 3/23 Team 1 Team 2 3/30 Team 1 Team 2 4/6 Team 1 Team 2 4/13 Team 1 Team 2 4/27 No Games (Easter) NIGHT TOURNAMENT

Spring 2019 United Soccer Peoria Game Schedule

Spring 2019 United Soccer Peoria Game Schedule Please leave the following at home: Animals, drugs/alcohol, scooters/skateboards/bicycles. Please remember: 1. These are kids. 2. This is a game. 3. The coaches volunteer. 4. The referees are human. 5.

More information

Fall 2018 United Soccer Peoria Game Schedule

Fall 2018 United Soccer Peoria Game Schedule Please leave the following at home: Animals, drugs/alcohol, scooters/skateboards/bicycles. Please remember: 1. These are kids. 2. This is a game. 3. The coaches volunteer. 4. The referees are human. 5.

More information

Spring 2018 United Soccer Peoria Game Schedule

Spring 2018 United Soccer Peoria Game Schedule Please leave the following at home: Animals, drugs/alcohol, scooters/skateboards/bicycles. Please remember: 1. These are kids. 2. This is a game. 3. The coaches volunteer. 4. The referees are human. 5.

More information

Spring 2018 United Soccer Peoria Game Schedule

Spring 2018 United Soccer Peoria Game Schedule Please leave the following at home: Animals, drugs/alcohol, scooters/skateboards/bicycles. Please remember: 1. These are kids. 2. This is a game. 3. The coaches volunteer. 4. The referees are human. 5.

More information

Chapter 30 Design and Analysis of

Chapter 30 Design and Analysis of Chapter 30 Design and Analysis of 2 k DOEs Introduction This chapter describes design alternatives and analysis techniques for conducting a DOE. Tables M1 to M5 in Appendix E can be used to create test

More information

Spring 2017 United Soccer Peoria Game Schedule

Spring 2017 United Soccer Peoria Game Schedule Please leave the following at home: Animals, drugs/alcohol, scooters/skateboards/bicycles. Please remember: 1. These are kids. 2. This is a game. 3. The coaches volunteer. 4. The referees are human. 5.

More information

NVLAP Proficiency Test Round 14 Results. Rolf Bergman CORM 16 May 2016

NVLAP Proficiency Test Round 14 Results. Rolf Bergman CORM 16 May 2016 NVLAP Proficiency Test Round 14 Results Rolf Bergman CORM 16 May 2016 Outline PT 14 Structure Lamp Types Lab Participation Format for results PT 14 Analysis Average values of labs Average values of lamps

More information

Parts Manual. EPIC II Critical Care Bed REF 2031

Parts Manual. EPIC II Critical Care Bed REF 2031 EPIC II Critical Care Bed REF 2031 Parts Manual For parts or technical assistance call: USA: 1-800-327-0770 2013/05 B.0 2031-109-006 REV B www.stryker.com Table of Contents English Product Labels... 4

More information

Answers Investigation 3

Answers Investigation 3 Answers Investigation Applications. a., b. s = n c. The numbers seem to be increasing b a greater amount each time. The square number increases b consecutive odd integers:,, 7,, c X X=. a.,,, b., X 7 X=

More information

Chapter 2 Segment Measurement and Coordinate Graphing

Chapter 2 Segment Measurement and Coordinate Graphing Geometry Concepts Chapter 2 Segment Measurement and Coordinate Graphing 2.2 Find length segments (1.3) 2.3 Compare lengths of segments (1.3) 2.3 Find midpoints of segments (1.7) 2.5 Calculate coordinates

More information

Answers. Investigation 3. ACE Assignment Choices. Applications. = = 210 (Note: students

Answers. Investigation 3. ACE Assignment Choices. Applications. = = 210 (Note: students Answers Investigation ACE Assignment Choices Problem. Core,,, Other Applications ; Connections, ; Etensions 7, ; unassigned choices from previous problems Problem. Core, Other Connections 7; Etensions

More information

DIFFERENTIAL GEOMETRY HW 7

DIFFERENTIAL GEOMETRY HW 7 DIFFERENTIAL GEOMETRY HW 7 CLAY SHONKWILER 1 Show that within a local coordinate system x 1,..., x n ) on M with coordinate vector fields X 1 / x 1,..., X n / x n, if we pick n 3 smooth real-valued functions

More information

Executive Committee and Officers ( )

Executive Committee and Officers ( ) Gifted and Talented International V o l u m e 2 4, N u m b e r 2, D e c e m b e r, 2 0 0 9. G i f t e d a n d T a l e n t e d I n t e r n a t i o n a2 l 4 ( 2), D e c e m b e r, 2 0 0 9. 1 T h e W o r

More information

Redacted for Privacy

Redacted for Privacy AN ABSTRACT OF THE THESIS OF Terrence A. Smith for the degree of Master of Science in Industrial Engineering presented February 26, 1993. Title: An Experimental Investigation of Scheduling Non- Identical

More information

GEOMETRY HW 8. 1 x z

GEOMETRY HW 8. 1 x z GEOMETRY HW 8 CLAY SHONKWILER Consider the Heisenberg group x z 0 y which is a Lie group diffeomorphic to R 3 a: Find the left invariant vector fields X, Y, Z on R 3 whose value at the identity is the

More information

Day 66 Bellringer. 1. Construct a perpendicular bisector to the given lines. Page 1

Day 66 Bellringer. 1. Construct a perpendicular bisector to the given lines. Page 1 Day 66 Bellringer 1. Construct a perpendicular bisector to the given lines. a) b) HighSchoolMathTeachers@2018 Page 1 Day 66 Bellringer c) d) HighSchoolMathTeachers@2018 Page 2 Day 66 Bellringer 2. Identify

More information

P a g e 5 1 of R e p o r t P B 4 / 0 9

P a g e 5 1 of R e p o r t P B 4 / 0 9 P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e

More information

CSSTP. Given CSSTP. Statements Reasons. Given CSSTP. Mult. Prop. = Div. Prop. = Sym. Prop. = or 1 Mult. Prop. = Div. Prop. =

CSSTP. Given CSSTP. Statements Reasons. Given CSSTP. Mult. Prop. = Div. Prop. = Sym. Prop. = or 1 Mult. Prop. = Div. Prop. = : If the triangles are similar (~), then all of the sides must be congruent proportional (create equal scale fractions). Example: A~ F Before you start your proof, it is important to plan! Setup the three

More information

A L A BA M A L A W R E V IE W

A L A BA M A L A W R E V IE W A L A BA M A L A W R E V IE W Volume 52 Fall 2000 Number 1 B E F O R E D I S A B I L I T Y C I V I L R I G HT S : C I V I L W A R P E N S I O N S A N D TH E P O L I T I C S O F D I S A B I L I T Y I N

More information

T h e C S E T I P r o j e c t

T h e C S E T I P r o j e c t T h e P r o j e c t T H E P R O J E C T T A B L E O F C O N T E N T S A r t i c l e P a g e C o m p r e h e n s i v e A s s es s m e n t o f t h e U F O / E T I P h e n o m e n o n M a y 1 9 9 1 1 E T

More information

OH BOY! Story. N a r r a t iv e a n d o bj e c t s th ea t e r Fo r a l l a g e s, fr o m th e a ge of 9

OH BOY! Story. N a r r a t iv e a n d o bj e c t s th ea t e r Fo r a l l a g e s, fr o m th e a ge of 9 OH BOY! O h Boy!, was or igin a lly cr eat ed in F r en ch an d was a m a jor s u cc ess on t h e Fr en ch st a ge f or young au di enc es. It h a s b een s een by ap pr ox i ma t ely 175,000 sp ect at

More information

Trade Patterns, Production networks, and Trade and employment in the Asia-US region

Trade Patterns, Production networks, and Trade and employment in the Asia-US region Trade Patterns, Production networks, and Trade and employment in the Asia-U region atoshi Inomata Institute of Developing Economies ETRO Development of cross-national production linkages, 1985-2005 1985

More information

LESSON 2 5 CHAPTER 2 OBJECTIVES

LESSON 2 5 CHAPTER 2 OBJECTIVES LESSON 2 5 CHAPTER 2 OBJECTIVES POSTULATE a statement that describes a fundamental relationship between the basic terms of geometry. THEOREM a statement that can be proved true. PROOF a logical argument

More information

CHAPTER 5 : THE STRAIGHT LINE

CHAPTER 5 : THE STRAIGHT LINE EXERCISE 1 CHAPTER 5 : THE STRAIGHT LINE 1. In the diagram, PQ is a straight line. P 4 2 4 3 2 1 0 1 2 2 2. Find (a) the -intercept, (b) the gradient, of the straight line. Q (5,18) Q Answer :a).. b) 3

More information

176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s

176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s A g la di ou s F. L. 462 E l ec tr on ic D ev el op me nt A i ng er A.W.S. 371 C. A. M. A l ex an de r 236 A d mi ni st ra ti on R. H. (M rs ) A n dr ew s P. V. 326 O p ti ca l Tr an sm is si on A p ps

More information

THE TRANSLATION PLANES OF ORDER 49 AND THEIR AUTOMORPHISM GROUPS

THE TRANSLATION PLANES OF ORDER 49 AND THEIR AUTOMORPHISM GROUPS MATHEMATICS OF COMPUTATION Volume 67, Number 223, July 1998, Pages 1207 1224 S 0025-5718(98)00961-2 THE TRANSLATION PLANES OF ORDER 49 AND THEIR AUTOMORPHISM GROUPS C. CHARNES AND U. DEMPWOLFF Abstract.

More information

mdpt. of TW = ( _ 0 + 1, _ 2 think and discuss Rects.: quads. with 4 rt. exercises guided practice bisect each other TQ = 1_ 2 QS = 1_ (380) = 190 ft

mdpt. of TW = ( _ 0 + 1, _ 2 think and discuss Rects.: quads. with 4 rt. exercises guided practice bisect each other TQ = 1_ 2 QS = 1_ (380) = 190 ft 19. m W = 3(4) + 7 = 99 0. x = 6 RS = 7(6) + 6 = 48, TV = 9(6) - 6 = 48 y = 4.5 RV = 8(4.5) - 8 = 8, ST = 6(4.5) + 1 = 8 RS TV, ST RV RSTV is a (Thm. 6-3-) 1. m = 1 m G = (1) + 31 = 55, m J = 7(1) - 9

More information

$%! & (, -3 / 0 4, 5 6/ 6 +7, 6 8 9/ 5 :/ 5 A BDC EF G H I EJ KL N G H I. ] ^ _ ` _ ^ a b=c o e f p a q i h f i a j k e i l _ ^ m=c n ^

$%! & (, -3 / 0 4, 5 6/ 6 +7, 6 8 9/ 5 :/ 5 A BDC EF G H I EJ KL N G H I. ] ^ _ ` _ ^ a b=c o e f p a q i h f i a j k e i l _ ^ m=c n ^ ! #" $%! & ' ( ) ) (, -. / ( 0 1#2 ' ( ) ) (, -3 / 0 4, 5 6/ 6 7, 6 8 9/ 5 :/ 5 ;=? @ A BDC EF G H I EJ KL M @C N G H I OPQ ;=R F L EI E G H A S T U S V@C N G H IDW G Q G XYU Z A [ H R C \ G ] ^ _ `

More information

35H MPa Hydraulic Cylinder 3.5 MPa Hydraulic Cylinder 35H-3

35H MPa Hydraulic Cylinder 3.5 MPa Hydraulic Cylinder 35H-3 - - - - ff ff - - - - - - B B BB f f f f f f f 6 96 f f f f f f f 6 f LF LZ f 6 MM f 9 P D RR DD M6 M6 M6 M. M. M. M. M. SL. E 6 6 9 ZB Z EE RC/ RC/ RC/ RC/ RC/ ZM 6 F FP 6 K KK M. M. M. M. M M M M f f

More information

GUIDE. mirfieldshow.com. Sponsored by. Orange Design Studio.

GUIDE. mirfieldshow.com. Sponsored by. Orange Design Studio. GUIDE mfhw.m Sp b O D S. Fh F m F C 1 3 5 7 9 b f M MIRFIELD COAT OF ARMS Th m w ff Fb 26, 1935. Th m f h mp f h w m h m. Th p S Jh H, wh pp h Pp h 13h h b f h ph hh. Hv W H Wh h? O, h wm mh, hp h f h.

More information

h : sh +i F J a n W i m +i F D eh, 1 ; 5 i A cl m i n i sh» si N «q a : 1? ek ser P t r \. e a & im a n alaa p ( M Scanned by CamScanner

h : sh +i F J a n W i m +i F D eh, 1 ; 5 i A cl m i n i sh» si N «q a : 1? ek ser P t r \. e a & im a n alaa p ( M Scanned by CamScanner m m i s t r * j i ega>x I Bi 5 n ì r s w «s m I L nk r n A F o n n l 5 o 5 i n l D eh 1 ; 5 i A cl m i n i sh» si N «q a : 1? { D v i H R o s c q \ l o o m ( t 9 8 6) im a n alaa p ( M n h k Em l A ma

More information

DEPARTMENT OF MATHEMATICS

DEPARTMENT OF MATHEMATICS Wynberg Boys High School DEPARTMENT OF MATHEMATICS Name: Teacher: Class: PAPER 2 GRADE 9 MATHEMATICS JUNE 2017 MARKS: 75 TIME: 1 1 2 hours EXAMINER: Mr Biggs This examination booklet consists of 12 pages.

More information

95 Holt McDougal Geometry

95 Holt McDougal Geometry 1. It is given that KN is the perpendicular bisector of J and N is the perpendicular bisector of K. B the Perpendicular Bisector Theorem, JK = K and K =. Thus JK = b the Trans. Prop. of =. B the definition

More information

CHAPTER 4. Chapter Opener PQ (3, 3) Lesson 4.1

CHAPTER 4. Chapter Opener PQ (3, 3) Lesson 4.1 CHAPTER 4 Chapter Opener Chapter Readiness Quiz (p. 17) 1. D. H; PQ **** is horizontal, so subtract the x-coordinates. PQ 7 5 5. B; M 0 6, 4 (, ) Lesson 4.1 4.1 Checkpoint (pp. 17 174) 1. Because this

More information

Chapter 6, Solution 1. Joint B: Joint C: Joint FBDs: F = 800 lb T. F = 1700 lb C lb lb F

Chapter 6, Solution 1. Joint B: Joint C: Joint FBDs: F = 800 lb T. F = 1700 lb C lb lb F \ COSMOS: Complete Online Solutions Manual Organization Sstem Chapter 6, Solution 1. Joint FBDs: Joint B: FAB 800 lb F = = 1 8 17 BC so F = 100 lb T AB F = 1700 lb C BC Joint C: FAC Cx 1700 lb = = 8 1

More information

I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o

I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o u l d a l w a y s b e t a k e n, i n c l u d f o l

More information

page 1 Total ( )

page 1 Total ( ) A B C D E F Costs budget of [Claimant / Defendant] dated [ ] Estimated page 1 Work done / to be done Pre-action Disbs ( ) Time ( ) Disbs ( ) Time ( ) Total ( ) 1 Issue /statements of case 0.00 0.00 CMC

More information

W= -b'e + af + cg + dh, X= a'e + bf + dg' - ch', Y = -d'e - cf+ ag' - bh, Z = e'e - df + bg + ah',

W= -b'e + af + cg + dh, X= a'e + bf + dg' - ch', Y = -d'e - cf+ ag' - bh, Z = e'e - df + bg + ah', PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 88, Number 4. August 1983 LAGRANGE IDENTITY FOR POLYNOMIALS AND Ô-CODES OF LENGTHS It AND 13/ C. H. YANG Abstract. It is known that application of

More information

Pre-Test. Use the following figure to answer Questions 1 through 6. B C. 1. What is the center of the circle? The center of the circle is point G.

Pre-Test. Use the following figure to answer Questions 1 through 6. B C. 1. What is the center of the circle? The center of the circle is point G. Pre-Test Name Date Use the following figure to answer Questions 1 through 6. A B C F G E D 1. What is the center of the circle? The center of the circle is point G. 2. Name a radius of the circle. A radius

More information

o C *$ go ! b», S AT? g (i * ^ fc fa fa U - S 8 += C fl o.2h 2 fl 'fl O ' 0> fl l-h cvo *, &! 5 a o3 a; O g 02 QJ 01 fls g! r«'-fl O fl s- ccco

o C *$ go ! b», S AT? g (i * ^ fc fa fa U - S 8 += C fl o.2h 2 fl 'fl O ' 0> fl l-h cvo *, &! 5 a o3 a; O g 02 QJ 01 fls g! r«'-fl O fl s- ccco > p >>>> ft^. 2 Tble f Generl rdnes. t^-t - +«0 -P k*ph? -- i t t i S i-h l -H i-h -d. *- e Stf H2 t s - ^ d - 'Ct? "fi p= + V t r & ^ C d Si d n. M. s - W ^ m» H ft ^.2. S'Sll-pl e Cl h /~v S s, -P s'l

More information

necessita d'interrogare il cielo

necessita d'interrogare il cielo gigi nei necessia d'inegae i cie cic pe sax span s inuie a dispiegaa fma dea uce < affeandi ves i cen dea uce isnane " sienzi dei padi sie veic dei' anima 5 J i f H 5 f AL J) i ) L '3 J J "' U J J ö'

More information

Conditional Statement: Statements in if-then form are called.

Conditional Statement: Statements in if-then form are called. Monday 9/21 2.2 and 2.4 Wednesday 9/23 2.5 and 2.6 Conditional and Algebraic Proofs Algebraic Properties and Geometric Proofs Unit 2 Angles and Proofs Packet pages 1-3 Textbook Pg 85 (14, 17, 20, 25, 27,

More information

Distance. Warm Ups. Learning Objectives I can find the distance between two points. Football Problem: Bailey. Watson

Distance. Warm Ups. Learning Objectives I can find the distance between two points. Football Problem: Bailey. Watson Distance Warm Ups Learning Objectives I can find the distance between two points. Football Problem: Bailey Watson. Find the distance between the points (, ) and (4, 5). + 4 = c 9 + 6 = c 5 = c 5 = c. Using

More information

J JUL - 25-JUL 2016 HOUSEHOLD FINANCES RESEARCH

J JUL - 25-JUL 2016 HOUSEHOLD FINANCES RESEARCH J00 JUL JUL 0 Table XF0 In terms of your finances, how often if at all, do you and your household find yourselves without enough money to buy enough food? BASE: ALL ADULTS AGED + IN GREAT BRITAIN Page

More information

) = (3.5, 3) 5-3. check it out!

) = (3.5, 3) 5-3. check it out! 44. Let be the irumenter of the. Given: = m; so by the properties of -6-9,. So = + = _ 5- = _ () = 4 m. medians and altitudes of Triangles hek it out! 1a. KZ + ZW = KW _ KW + ZW = KW ZW KW 7 KW 1 = KW

More information

1. Determine the Zero-Force Members in the plane truss.

1. Determine the Zero-Force Members in the plane truss. 1. Determine the Zero-orce Members in the plane truss. 1 . Determine the forces in members G, CG, BC, and E for the loaded crane truss. Use the Method of Joints. 3. Determine the forces in members CG and

More information

1-2 Measuring and Constructing Segments

1-2 Measuring and Constructing Segments 1-2 Measuring and Constructing Segments Lesson Presentation Lesson Quiz Objectives Use length and midpoint of a segment. Construct midpoints and congruent segments. Vocabulary coordinate midpoint distance

More information

Remote Sensing Applications for the Historic Environment

Remote Sensing Applications for the Historic Environment m S App H Em L H Em m S 4 C B P m k m m. B m S App H Em L H Em m S 4 m C A Im H Em. B m m H Lp U S D m S C U P m k B m S App H Em L H Em m S 4 m A m A W k? A pp :. Tpp. Px. mk.. S S mk.. Cp S mk B m m

More information

5 H o w t o u s e t h e h o b 1 8

5 H o w t o u s e t h e h o b 1 8 P l a s r a d h i s m a n u a l f i r s. D a r C u s m r, W w u l d l i k y u bb a si n p r hf r m a n cf r m y u r p r d u c h a h a s b n m a n u f a c u r d m d r n f a c i l iu n id s r s r i c q u

More information

1-2 Measuring and Constructing Segments

1-2 Measuring and Constructing Segments 1-2 Measuring and Constructing Segments Warm Up Lesson Presentation Lesson Quiz Objectives Use length and midpoint of a segment. Construct midpoints and congruent segments. Vocabulary coordinate midpoint

More information

W I T H M i A. L I O E T O W A R D ISTOlNrE ^ I S T D C H A. n i T Y F O R - A L L. "

W I T H M i A. L I O E T O W A R D ISTOlNrE ^ I S T D C H A. n i T Y F O R - A L L. J/ H L D N D H Y F L L L N LLL KN NY H Y 2 95 HL N NG F L G NG F LNDD H H J F NH D K GN L _ L L :? H F K b H Y L DD Y N? N L L LD H LL LLL LNNG LL J K N 3 ND DL6 N Lb L F KF FH D LD3 D ND ND F ND LKKN

More information

,,,,..,,., {. (, ),, {,.,.,..,,.,.,,....... {.. : N {, Z {, Q {, Q p { p{ {. 3, R {, C {. : ord p {. 8, (k) {.42,!() { {. 24, () { {. 24, () { {. 25,., () { {. 26,. 9, () { {. 27,. 23, '() { ( ) {. 28,

More information

Graphing Square Roots - Class Work Graph the following equations by hand. State the domain and range of each using interval notation.

Graphing Square Roots - Class Work Graph the following equations by hand. State the domain and range of each using interval notation. Graphing quare Roots - lass Work Graph the following equations by hand. tate the domain and range of each using interval notation. 1. y = x + 2 2. f x = x 1. y = x + 4. g x = 2 x 1 5. y = x + 2 + 4 6.

More information

1. Determine the Zero-Force Members in the plane truss.

1. Determine the Zero-Force Members in the plane truss. 1. Determine the Zero-orce Members in the plane truss. 1 . Determine the force in each member of the loaded truss. Use the Method of Joints. 3. Determine the force in member GM by the Method of Section.

More information

M $ 4 65\ K;$ 5, 65\ M $ C! 4 /2 K;$ M $ /+5\ 8$ A5 =+0,7 ;* C! 4.4/ =! K;$,7 $,+7; ;J zy U;K z< mj ]!.,,+7;

M $ 4 65\ K;$ 5, 65\ M $ C! 4 /2 K;$ M $ /+5\ 8$ A5 =+0,7 ;* C! 4.4/ =! K;$,7 $,+7; ;J zy U;K z< mj ]!.,,+7; V 3U. T, SK I 1393/08/21 :,F! 1393/10/29 ::!n> 2 1 /M + - /E+4q; Z R :'!3Qi M $,7 8$ 4,!AK 4 4/ * /;K "FA ƒf\,7 /;G2 @;J\ M $ 4 65\ K;$ 5, 65\ M $ C! 4 /2 K;$ M $ /+5\ 8$ A5 =+0,7 ;* C! 4.4/ =! K;$,7 $,+7;

More information

St Andrew s Academy Mathematics Department Higher Mathematics VECTORS

St Andrew s Academy Mathematics Department Higher Mathematics VECTORS St Andrew s Academy Mathematics Department Higher Mathematics VECTORS hsn.uk.net Higher Mathematics Vectors Contents Vectors 1 1 Vectors and Scalars EF 1 Components EF 1 Magnitude EF 4 Equal Vectors EF

More information

Quintic Quasitopological Gravity

Quintic Quasitopological Gravity Quintic Quasitopological Gravity Luis Guajardo 1 in collaboration with Adolfo Cisterna 2 Mokthar Hassaïne 1 Julio Oliva 3 1 Universidad de Talca 2 Universidad Central de Chile 3 Universidad de Concepción

More information

Vectors Higher Mathematics Supplementary Resources. Section A

Vectors Higher Mathematics Supplementary Resources. Section A Education Resources Vectors Higher Mathematics Supplementar Resources Section This section is designed to provide eamples which develop routine skills necessar for completion of this section. R I have

More information

FAIR FOOD GRADE 8 SOCIAL STUDIES ICONIC EDIBLES LIGHTS CAMERA ACTION!

FAIR FOOD GRADE 8 SOCIAL STUDIES ICONIC EDIBLES LIGHTS CAMERA ACTION! FAIR FOO GRAE 8 SOCIA IES ICONIC EIBES IGHTS CAMERA ACTION! F F G Egh Icc Eb gh Cm Ac! I h w: cm c fm b q f h S F f Tx. Az h cb f v c hc gp. cb vpm h c h q Amc c. W, pc, cm b cc b f h Tx S F. m w f j v

More information

f;g,7k ;! / C+!< 8R+^1 ;0$ Z\ \ K S;4 i!;g + 5 ;* \ C! 1+M, /A+1+> 0 /A+>! 8 J 4! 9,7 )F C!.4 ;* )F /0 u+\ 30< #4 8 J C!

f;g,7k ;! / C+!< 8R+^1 ;0$ Z\ \ K S;4 i!;g + 5 ;* \ C! 1+M, /A+1+> 0 /A+>! 8 J 4! 9,7 )F C!.4 ;* )F /0 u+\ 30< #4 8 J C! 393/09/0 393//07 :,F! ::!n> b]( a.q 5 O +D5 S ١ ; ;* :'!3Qi C+0;$ < "P 4 ; M V! M V! ; a 4 / ;0$ f;g,7k ;! / C+!< 8R+^ ;0$ Z\ \ K S;4 "* < 8c0 5 *

More information

); 5 units 5. x = 3 6. r = 5 7. n = 2 8. t =

); 5 units 5. x = 3 6. r = 5 7. n = 2 8. t = . Sample answer: dilation with center at the origin and a scale factor of 1 followed b a translation units right and 1 unit down 5. Sample answer: reflection in the -axis followed b a dilation with center

More information

126 Holt McDougal Geometry

126 Holt McDougal Geometry test prep 51. m Q = m S 3x + 5 = 5x - 5 30 = x x = 15 5. J 53. 6.4 P = + + + = + + + = (5 + 8.) = 6.4 challenge and extend 54. Let given pts. be (0, 5), (4, 0), (8, 5), and possible 4th pts. be X, Y, Z.

More information

Which statement is true about parallelogram FGHJ and parallelogram F ''G''H''J ''?

Which statement is true about parallelogram FGHJ and parallelogram F ''G''H''J ''? Unit 2 Review 1. Parallelogram FGHJ was translated 3 units down to form parallelogram F 'G'H'J '. Parallelogram F 'G'H'J ' was then rotated 90 counterclockwise about point G' to obtain parallelogram F

More information

Inspiration and formalism

Inspiration and formalism Inspirtion n formlism Answers Skills hek P(, ) Q(, ) PQ + ( ) PQ A(, ) (, ) grient ( ) + Eerise A opposite sies of regulr hegon re equl n prllel A ED i FC n ED ii AD, DA, E, E n FC No, sies of pentgon

More information

Cedar Millwork Products

Cedar Millwork Products 1 BUILD SOME CHARACTER Edmund Allen s Cedar millwork products will set your design apart by adding the beauty, warmth, elegance of design, and functionality only natural Western Red Cedar can provide.

More information

Class IX : Math Chapter 11: Geometric Constructions Top Concepts 1. To construct an angle equal to a given angle. Given : Any POQ and a point A.

Class IX : Math Chapter 11: Geometric Constructions Top Concepts 1. To construct an angle equal to a given angle. Given : Any POQ and a point A. 1 Class IX : Math Chapter 11: Geometric Constructions Top Concepts 1. To construct an angle equal to a given angle. Given : Any POQ and a point A. Required : To construct an angle at A equal to POQ. 1.

More information

I N A C O M P L E X W O R L D

I N A C O M P L E X W O R L D IS L A M I C E C O N O M I C S I N A C O M P L E X W O R L D E x p l o r a t i o n s i n A g-b eanste d S i m u l a t i o n S a m i A l-s u w a i l e m 1 4 2 9 H 2 0 0 8 I s l a m i c D e v e l o p m e

More information

Ratios and Units of Measurement - Step-by-Step Lesson. Lesson 1 Ratio Problem: a) How many feet are there in 2 meters?

Ratios and Units of Measurement - Step-by-Step Lesson. Lesson 1 Ratio Problem: a) How many feet are there in 2 meters? Ratios and Units of Measurement - Step-by-Step Lesson Lesson 1 Ratio Problem: a) How many feet are there in 2 meters? Explanation: Step 1) We know that : 1 m = 3.3 ft Step 2) We have to convert meters

More information

Geometry: A Complete Course

Geometry: A Complete Course Geometry: omplete ourse (with Trigonometry) Module - Student WorkText Written by: Thomas. lark Larry. ollins RRT 4/2010 6. In the figure below, and share the common segment. Prove the following conditional

More information

Exhibit 2-9/30/15 Invoice Filing Page 1841 of Page 3660 Docket No

Exhibit 2-9/30/15 Invoice Filing Page 1841 of Page 3660 Docket No xhibit 2-9/3/15 Invie Filing Pge 1841 f Pge 366 Dket. 44498 F u v 7? u ' 1 L ffi s xs L. s 91 S'.e q ; t w W yn S. s t = p '1 F? 5! 4 ` p V -', {} f6 3 j v > ; gl. li -. " F LL tfi = g us J 3 y 4 @" V)

More information

Ranking accounting, banking and finance journals: A note

Ranking accounting, banking and finance journals: A note MPRA Munich Personal RePEc Archive Ranking accounting, banking and finance ournals: A note George Halkos and Nickolaos Tzeremes University of Thessaly, Department of Economics January 2012 Online at https://mpra.ub.uni-muenchen.de/36166/

More information

F l a s h-b a s e d S S D s i n E n t e r p r i s e F l a s h-b a s e d S S D s ( S o-s ltiad t e D r i v e s ) a r e b e c o m i n g a n a t t r a c

F l a s h-b a s e d S S D s i n E n t e r p r i s e F l a s h-b a s e d S S D s ( S o-s ltiad t e D r i v e s ) a r e b e c o m i n g a n a t t r a c L i f e t i m e M a n a g e m e n t o f F l a-b s ah s e d S S D s U s i n g R e c o v e r-a y w a r e D y n a m i c T h r o t t l i n g S u n g j i n L e, e T a e j i n K i m, K y u n g h o, Kainmd J

More information

5-1 Perpendicular and Angle Bisectors

5-1 Perpendicular and Angle Bisectors 5-1 Perpendicular and Angle Bisectors Warm Up Lesson Presentation Lesson Quiz Geometry Warm Up Construct each of the following. 1. A perpendicular bisector. 2. An angle bisector. 3. Find the midpoint and

More information

`G 12 */" T A5&2/, ]&>b ; A%/=W, 62 S 35&.1?& S + ( A; 2 ]/0 ; 5 ; L) ( >>S.

`G 12 */ T A5&2/, ]&>b ; A%/=W, 62 S 35&.1?& S + ( A; 2 ]/0 ; 5 ; L) ( >>S. 01(( +,-. ()*) $%&' "#! : : % $& - "#$ :, (!" -&. #0 12 + 34 2567 () *+ '!" #$%& ; 2 "1? + @)&2 A5&2 () 25& 89:2 *2 72, B97I J$K

More information

CfE Higher Mathematics Course Materials Topic 2: Vectors

CfE Higher Mathematics Course Materials Topic 2: Vectors SCHOLAR Study Guide CfE Higher Mathematics Course Materials Topic : Vectors Authored by: Margaret Ferguson Reviewed by: Jillian Hornby Previously authored by: Jane S Paterson Dorothy A Watson Heriot-Watt

More information

Future Self-Guides. E,.?, :0-..-.,0 Q., 5...q ',D5', 4,] 1-}., d-'.4.., _. ZoltAn Dbrnyei Introduction. u u rt 5,4) ,-,4, a. a aci,, u 4.

Future Self-Guides. E,.?, :0-..-.,0 Q., 5...q ',D5', 4,] 1-}., d-'.4.., _. ZoltAn Dbrnyei Introduction. u u rt 5,4) ,-,4, a. a aci,, u 4. te SelfGi ZltAn Dbnyei Intdtin ; ) Q) 4 t? ) t _ 4 73 y S _ E _ p p 4 t t 4) 1_ ::_ J 1 `i () L VI O I4 " " 1 D 4 L e Q) 1 k) QJ 7 j ZS _Le t 1 ej!2 i1 L 77 7 G (4) 4 6 t (1 ;7 bb F) t f; n (i M Q) 7S

More information

P a g e 3 6 of R e p o r t P B 4 / 0 9

P a g e 3 6 of R e p o r t P B 4 / 0 9 P a g e 3 6 of R e p o r t P B 4 / 0 9 p r o t e c t h um a n h e a l t h a n d p r o p e r t y fr om t h e d a n g e rs i n h e r e n t i n m i n i n g o p e r a t i o n s s u c h a s a q u a r r y. J

More information

ANSWER KEY. LEARNING ACTIVITY 1 Challenge a. A + B = (The sum of its adjacent interior angles between two parallel sides is + B = B = B =

ANSWER KEY. LEARNING ACTIVITY 1 Challenge a. A + B = (The sum of its adjacent interior angles between two parallel sides is + B = B = B = LEARNING ACTIVITY 1 Challenge 1.1 ANSWER KEY 1. a. A + B (The sum of its adjacent interior angles between two parallel sides is + B B B C + D (The sum of its adjacent interior angles between two parallel

More information

123 Holt McDougal Geometry

123 Holt McDougal Geometry 44. - 0 - -4 y x heck students estimates; possible answer: pentagon is not equiangular; m = 100 ; m = 113 ; m = 113 ; m = 101 ; m = 113 ; yes, pentagon is not equiangular. 45a. heptagon b. (7 - )180 =

More information

In this chapter trusses, frames and machines will be examines as engineering structures.

In this chapter trusses, frames and machines will be examines as engineering structures. In the previous chapter we have employed the equations of equilibrium in order to determine the support / joint reactions acting on a single rigid body or a system of connected members treated as a single

More information

CAT. NO /irtl,417~ S- ~ I ';, A RIDER PUBLICATION BY H. A. MIDDLETON

CAT. NO /irtl,417~ S- ~ I ';, A RIDER PUBLICATION BY H. A. MIDDLETON CAT. NO. 139-3 THIRD SUPPLEMENT I /irtl,417~ S- ~ I ';,... 0 f? BY H. A. MIDDLETON.. A RIDER PUBLICATION B36 B65 B152 B309 B319 B329 B719 D63 D77 D152 DA90 DAC32 DAF96 DC70 DC80 DCC90 DD6 DD7 DF62 DF91

More information

E.., (2) g t = e 2' g E. g t = g ij (t u k )du i du j, i j k =1 2. (u 1 0 0) u2 2 U, - v, w, g 0 (v w) = g ij (0 u k 0)v i w j = 0, (t) = g ij (t u k

E.., (2) g t = e 2' g E. g t = g ij (t u k )du i du j, i j k =1 2. (u 1 0 0) u2 2 U, - v, w, g 0 (v w) = g ij (0 u k 0)v i w j = 0, (t) = g ij (t u k 2007 10 (545) 517.929..,.. 1. g t M, d dt g t = ;2 Ric(g t ) (1) Ric(g) g.,, -, - (., [1], [2]).,,.,, f t - (M G), g t = ft G,, (1)., -, -, (, ), - (,, [3]). t - E 3, g t, t E 3, (1). t -., -. (M g) Ric

More information

Y'* C 0!),.1 / ; ')/ Y 0!)& 1 0R NK& A Y'. 1 ^. ]'Q 1 I1 )H ;". D* 1 = Z)& ^. H N[Qt C =

Y'* C 0!),.1 / ; ')/ Y 0!)& 1 0R NK& A Y'. 1 ^. ]'Q 1 I1 )H ;. D* 1 = Z)& ^. H N[Qt C = (-) 393 F!/ $5 $% T K&L =>-? J (&A )/>2 I B!" GH 393/05/07 :K 393/07/23 :7b +B 0 )NO M / Y'* C a23 N/ * = = Z)& ^. ;$ 0'* Y'2 8 OI 53 = ;" ~" O* Y.b ;" ; ')/ Y'* C 0!),. / ; ')/ Y 0!)& 0R NK& A Y'. ^.

More information

Math 3 Review Sheet Ch. 3 November 4, 2011

Math 3 Review Sheet Ch. 3 November 4, 2011 Math 3 Review Sheet Ch. 3 November 4, 2011 Review Sheet: Not all the problems need to be completed. However, you should look over all of them as they could be similar to test problems. Easy: 1, 3, 9, 10,

More information

Discovery Guide. Beautiful, mysterious woman pursued by gunmen. Sounds like a spy story...

Discovery Guide. Beautiful, mysterious woman pursued by gunmen. Sounds like a spy story... Dv G W C T Gp, A T Af Hk T 39 Sp. M Mx Hk p j p v, f M P v...(!) Af Hk T 39 Sp, B,,, UNMISSABLE! T - f 4 p v 150 f-p f x v. Bf, k 4 p v 150. H k f f x? D,,,, v? W k, pf p f p? W f f f? W k k p? T p xp

More information

~,. :'lr. H ~ j. l' ", ...,~l. 0 '" ~ bl '!; 1'1. :<! f'~.., I,," r: t,... r':l G. t r,. 1'1 [<, ."" f'" 1n. t.1 ~- n I'>' 1:1 , I. <1 ~'..

~,. :'lr. H ~ j. l' , ...,~l. 0 ' ~ bl '!; 1'1. :<! f'~.., I,, r: t,... r':l G. t r,. 1'1 [<, . f' 1n. t.1 ~- n I'>' 1:1 , I. <1 ~'.. ,, 'l t (.) :;,/.I I n ri' ' r l ' rt ( n :' (I : d! n t, :?rj I),.. fl.),. f!..,,., til, ID f-i... j I. 't' r' t II!:t () (l r El,, (fl lj J4 ([) f., () :. -,,.,.I :i l:'!, :I J.A.. t,.. p, - ' I I I

More information

Courtenay Lawn Bowling Club Spring General Meeting Sunday, April 9th, 2017 Florence Filberg Centre Lower Level Meeting Room

Courtenay Lawn Bowling Club Spring General Meeting Sunday, April 9th, 2017 Florence Filberg Centre Lower Level Meeting Room Courtenay Lawn Bowling Club Spring General Meeting Sunday, April 9th, 2017 Florence Filberg Centre Lower Level Meeting Room Executive in attendance: Frank, Dean, Michael, Archie, Myrna, Dick Regrets: April.

More information

St Andrew s Academy Mathematics Department Higher Mathematics

St Andrew s Academy Mathematics Department Higher Mathematics St Andrew s Academy Mathematics Department Higher Mathematics VECTORS hsn.uk.net Higher Mathematics Vectors Contents Vectors 1 1 Vectors and Scalars EF 1 Components EF 1 3 Magnitude EF 3 4 Equal Vectors

More information

Name. 9. Find the diameter and radius of A, B, and C. State the best term for the given figure in the diagram.

Name. 9. Find the diameter and radius of A, B, and C. State the best term for the given figure in the diagram. Name LESSON 10.1 State the best term for the given figure in the diagram. 9. Find the diameter and radius of A, B, and C. 10. Describe the point of intersection of all three circles. 11. Describe all the

More information

Chapter 6. Worked-Out Solutions. Chapter 6 Maintaining Mathematical Proficiency (p. 299)

Chapter 6. Worked-Out Solutions. Chapter 6 Maintaining Mathematical Proficiency (p. 299) hapter 6 hapter 6 Maintaining Mathematical Proficiency (p. 99) 1. Slope perpendicular to y = 1 x 5 is. y = x + b 1 = + b 1 = 9 + b 10 = b n equation of the line is y = x + 10.. Slope perpendicular to y

More information

Years. Marketing without a plan is like navigating a maze; the solution is unclear.

Years. Marketing without a plan is like navigating a maze; the solution is unclear. F Q 2018 E Mk l lk z; l l Mk El M C C 1995 O Y O S P R j lk q D C Dl Off P W H S P W Sl M Y Pl Cl El M Cl FIRST QUARTER 2018 E El M & D I C/O Jff P RGD S C D M Sl 57 G S Alx ON K0C 1A0 C Tl: 6134821159

More information

Honors Geometry Mid-Term Exam Review

Honors Geometry Mid-Term Exam Review Class: Date: Honors Geometry Mid-Term Exam Review Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. 1. Classify the triangle by its sides. The

More information

I n t e r n a t i o n a l E l e c t r o n i c J o u r n a l o f E l e m e n t a r y E.7 d u, c ai ts is ou n e, 1 V3 1o-2 l6, I n t h i s a r t

I n t e r n a t i o n a l E l e c t r o n i c J o u r n a l o f E l e m e n t a r y E.7 d u, c ai ts is ou n e, 1 V3 1o-2 l6, I n t h i s a r t I n t e r n a t i o n a l E l e c t r o n i c J o ue rlne am l e not fa r y E d u c a t i o n, 2 0 1 4, 1 37-2 ( 16 ). H o w R e a d i n g V o l u m e A f f e c t s b o t h R e a d i n g F l u e n c y

More information

J# k# JOH Q } ` = ~ [~ H < [24-294] Neglect of mathematics works injury to all knowledge. Jx K # ~ [~ H

More information

U a C o & I & I b t - - -, _...

U a C o & I & I b t - - -, _... U C & I &,.. - -, -, 4 - -,-. -... -., -. -- -.. - - -. - -. - -.- - - - - - -.- - -. - - - -, - - - - I b j - - -, _....... . B N y y M N K y q S N I y d U d.. C y - T W A I C Iy d I d CWW W ~ d ( b y

More information

Skills Practice Skills Practice for Lesson 11.1

Skills Practice Skills Practice for Lesson 11.1 Skills Practice Skills Practice for Lesson.1 Name ate Riding a Ferris Wheel Introduction to ircles Vocabulary Identify an instance of each term in the diagram. 1. circle X T 2. center of the circle H I

More information

INVERSION IN THE PLANE BERKELEY MATH CIRCLE

INVERSION IN THE PLANE BERKELEY MATH CIRCLE INVERSION IN THE PLANE BERKELEY MATH CIRCLE ZVEZDELINA STANKOVA MILLS COLLEGE/UC BERKELEY SEPTEMBER 26TH 2004 Contents 1. Definition of Inversion in the Plane 1 Properties of Inversion 2 Problems 2 2.

More information

ENGINEERING MECHANICS STATIC

ENGINEERING MECHANICS STATIC Trusses Simple trusses The basic element of a truss is the triangle, three bars joined by pins at their ends, fig. a below, constitutes a rigid frame. The term rigid is used to mean noncollapsible and

More information