Giambattista, Ch 3 Problems: 9, 15, 21, 27, 35, 37, 42, 43, 47, 55, 63, 76
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1 Giambaisa, Ch 3 Problems: 9, 15, 21, 27, 35, 37, 42, 43, 47, 55, 63, Sraeg Le be direced along he +x-axis and le be 60.0 CCW from Find he magniude of 6.0 B A x 15. (a) Sraeg Since he angle is below he +x-axis, i is negaive. Compue he componens. C x = 1.8 C = (b) Sraeg The componens of are given. Use he Phagorean heorem. Compue he magniude and direcion of (c) Sraeg Add he componens of he vecors o find he componens of he vecor sum. Use he Phagorean heorem. Give he angle wih respec o he axis o which i lies closes. Find he magniude and direcion of and (d) Sraeg Use he componens of o find hose of
2 Compue he magniude and direcion. (e) Sraeg Use he componens of o find hose of Compue he componens. x-comp and -comp 21. Sraeg Draw diagrams of he siuaion. Use he definiions of average speed and average veloci. (a) Find he runner s average speed. C (b) Find he locaion of he runner on he rack. he runner has gone around once plus imes. Find he angle shown in he diagram. Find he radius of he rack. r θ r i Find Find he runner s average veloci. 27.(a) Sraeg Find he average speed b dividing he oal disance raveled b he oal ime. Each disance is given b he produc of he speed and ime. diagram. (b) Sraeg Use he definiion of average veloci. Draw a
3 Compue he disance of each leg of he rip, hen draw he diagram. N 36.0 km km Find Le eas be in he +x direcion and norh be in he + direcion. 35. Sraeg Since he paricle is moving o he eas and is acceleraed o he souh, is veloci in 8.00 s will be beween eas and souh. Use he componen mehod. Le norh be in he +-direcion and eas be in he +x-direcion. 37. Sraeg Use Eqs. (3-13) and (3-14). Se since he verical componen of he veloci is zero a he maximum heigh. (a) Find he maximum heigh. v i 19.6 m 30.0 v ix (b) A he ball s highes poin, so he speed v equals
4 42.Sraeg In each case, use Eq. (3-12) o find he ime i akes for he sone o reach he base of he gorge. (a) (b) Solve for using he quadraic formula. (c) v i sin v i cos 30 Solve for using he quadraic formula. Find he horizonal disance. 43. Sraeg Solve for he ime and subsiue he resul ino Eq. (3-12). Then, solve for o find he required disance from he cannon. Subsiue Cannon 18.0 m/s N
5 Use he quadraic formula. Since he cannon won fire backward, ne such ha is cener is 37.1 m in fron of he cannon. So, ou ell he ringmaser o place he 47.(a) Sraeg Consider each quani s dependence on ime. x so x increases linearl wih ime. According o Eq. (3-12), is parabolic. Since he ne acceleraion of he sone in he horizonal direcion is zero, is consan. v sars posiive and decreases linearl. v x (b) Sraeg Find in erms of and Solve for he iniial speed. v i sin 25.0 i 25 v i co So, he iniial veloci is (c) Sraeg Find h using he resul for found in par (b). Use Eq. (3-12). (d) Sraeg Se o find he ime when he sone reaches is maximum heigh.
6 Use Eq. (3 10) o find he ime. Find H. 55.Sraeg Consider he relaive moion of he ship and he waer. The relaive speeds are: Subrac (1) from (2). 63.Sraeg Consider he relaive moion of he waer (w) and Sheena (s). Le he +-direcion be upsream and he +x-direcion be oward he opposie bank (b). (a) Find he x-componen mi/h The -componen is mi/h Use he Phagorean heorem. (b) (c) (d) The upsream componen of her veloci relaive o he waer mus be equal in magniude o he veloci of he curren relaive o he bank, or
7 76.Sraeg The projecile mus be displaced 75.0 m vericall in he same amoun of ime ha i ravels 350 m horizonall. The projecile ma hi he headquarers on is wa up, on is wa down, or a is maximum heigh. Use and Eq. (3-12). Solve for he iniial speed,
and v y . The changes occur, respectively, because of the acceleration components a x and a y
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