SSC Mains Mock Test 226 [Answer with Solution]

Size: px
Start display at page:

Download "SSC Mains Mock Test 226 [Answer with Solution]"

Transcription

1 SS Mins Mock Test [nswe with Solution]. () Requied weight +.. () The sum of ges of the two olde plyes 0 + yes vege ge incesed months So, totl ge incesed months Sum of the ges of two new plyes yes + months vege of the ges of the two new plyes yes + m onth s 9 yes months. () The vege ge of olde membes incese by yes so, Incese in ge diff. between the ge of olde nd new membe yes. () Zinc oppe Totl / / / / / / / / / : 0. () Zinc oppe Tin Led Totl weight of led pe kg. () Milk Wte Totl on't clculte milk s it is not sked % of wte % 7 7. () Milk Wte Totl ( + ) + ( + ) 9 :. () 0% + 0% % 9. () % 0% Pice Quntity Goss eceipt % decese 0 0. () % of students pssed in both subjects % () 0% Initil xy Finl xy. () % () S 0 90 / 0 00.% ` 00. () Equivlent discount ctul cost 00 7 Tnspottion cost 0 00 Totl ctul cost % %

2 () Rtio P Rtio P/9 0 Rtio 0P/9. () P / wok in 0 dys wok in 0 dys Q / wok in. dys in. dys R / in dys in 9 dys S / in 7 dys in dys Q 7. () 0 m dys. () 0 w dys m 0 ` 9.0 w 0 Efficiency 0 m + 0 w w + 0 w w 0 dys Wok eming No. of dys 7 dys 9. () 0. () + + ( + ) Totl mount efficiency of she of Efficiency of P+Q Q+R 0/7 P + Q + R 0 `70 (P + Q) + (Q + R) + R R 0 R 9 R Q R in 0 0 dys Q in 0 dys iffeence dys. () (Totl) Efficiency (Totl) Efficiency ( + ) so, wok will be finished by in. (). () 0 dys 7/ Wok done by in / hou 0 0 Remining wok 0 wok will be done by in 9 minute P 0 0 Q / th wok 0 0 Time tken hs 0 pm 0. () Fist tp 0 Second tp 0 Wok done is minutes ( + ) Remining wok 0 Time tken by second tp to fill the emining 0 pt of the tnk minutes. () h minute h min

3 . () : b : 9 : b : c : 7 : d : c 7 : 0 7 : c : d : 7 b c d 7 : : 0 : 7. () : b b : c b c so, : b : c : c. () Gold oppe Totl Requied tio ( + ) : ( + ) : 7 9. () Pice of blck shocks Pice of bown shocks hecking by options Initil Pice Finl Pice % Incese () + + [ ] (b) [] (c) + + [ ] (d) [ ] Hence, nswe is () 0. () Velocity istnce ( fo sme time velocity is diectly popotionl to distnce) so, ( ) Velocity 0 0 km/h. () x y. () h min h 0 min 0 V T V T 0 V km/h x iection of cuent 00 m y (x y) 00 + (x + y) Subtcting we get, 00 y y () + m/ min 0 m/min. km/h so, Stem, Stem Speed of cuent km/h. () In 00 m bets by 0 m. In 00 m bets by 0 m. In 00 m bets by m. In 00 m bets by m. In 00 m bets by m. In 90 m bets by bets by m.. () Let the sum be ` 00. () 000 Inteest on months t 7 % Inteest on months t % Given Totl 0 Remining

4 % 7. () R % 000 % Inst. 7 + Inst Inst T Inst () % 0 00 /0 / () 0% 0 0. () iffeence between I & SI /0 /0 0 0 /0 0 + iff iff. iff. 9 9 yes. () Rest Totl Rest Totl () Totl,000,000,000 Rtio 9 7 Suppose the totl pofit so, pofit of + + 7% Rest % pofit of P. () P P P P P P P 0 P. () put x, y z x z x z y z. () + b + c + d put b c d /. () Put x, y, z x + y b x y c x + y ² + b² + c² b bc c b + b c + c 7 ² 7y². () x x + k (x )..x + () (x ) 7. () (x ) + (y ) + (z ) 0 If + b + c 0 then 0, b 0, c 0 x, y, z 9 9 x x b x c b c c b put, b c then x 9 only option () is stisfy. 9. () xy (x + y) (given)...(i). () b c x y x y...(ii) Put, x in (i) & (ii) y y? y y

5 0. () cubing both side y y y y y y y y y y x 7 0. () 7 0 x x x. () () / / () (). () R 0, R 0 R 0, R R 0, R 0 ( + + ) 0 7. () z x oys z x Gils Gils pt z x x z z 7. () e of cicle longest chod cm. () Oute di inne di R dius dius 0 so, bedth cm 9. () dius of font wheel x cm dius of e wheel y cm distnce coveed by font wheel n n x distnce coveed by e wheel in one ound y No. of times fo e wheel n x nx times y y 70. () : : 7. () Volume 9h h 9h 7. () 9 m d m + R 0 ( + R ) 0

6 + R R 0 cubing both side + R + R( + R) R R 0 7. () h : h : [h x, x] : : Volume 07 cm 7. () (x) x 07 x 07 7 x 7 Height cm ] x 77. () 7. () () n (/) n 0 n P 0º O Q S In PQR, 0º QR QPR º In QPS, QSP 90º ( Othocente) QPS 0 (90 + 0) QPS 0º so, RPS 0 º 70º R R R l 90 0.S. Rl cm 79. () I 0º 0º I 90º + 90º + º 7. () 7. () 7 cm s m/sec l b m. m () 00 cm/sec T T sec 00 0 min / cm x/ x/ y z/ I z O y x?...(i) I x z Put in (i), y x z y x + y ( I is incente) (ngle mde by sme chod is hlf) y z x z x x

7 0. (). () O O O O º E O 7º 0º º ( is sque) O 0º ( O is equiltel ) O O + O (Exteio ngle is equl to the + 0 7º sum of inteio opposite ngle). () x. () sec sec Put, 0º y option () (stisfy) 7. (). () h 90 x/ x/ h tn x h...(i) tn (90 ) h x...(ii) (i) multiplying by (ii) x x h h x 9 x 0 m. () O ~ O x x x 9 stisfying by the options x, 9. () None of these. () cos sin cos sin cos sin sin cos sin sin cos sin sin sin cosec 0º 0º : 0 m : : : : : : () vege of,,, 0 kg Individul vege : : 90. () ost pice 00 SP. 0 P SP 00 0 : 7 7

8 Pofit % 9. () MP SP gin % P MP : P : : 9. () Speed decese wgeon 9. () k 9 k % 0 wgeon () w w (speed in zeo) wgeon (speed is minimum) 0 m 0 m mn 0 m Rel speed 0 0 m/ s 7 km/h Rel speed S T S M 9 speed of tin speed of tin 9 km/h 9. () x b b cubing both side x b b b b b b x bx x + bx 9. () 0 G () Totl 0,000 0,000 0,000 0,000,000,000,000 Pofit she of () cos ( + ) cos ( + ) 9. () () h h 00 0 height.7 m ( ) R + R h 0 R R 0 R Rh h R 00. () 7 b 7 b + b nswe Key. (). (). (). (). (). () 7. (). () 9. () 0. (). (). (). (). (). (). () 7. (). () 9. () 0. (). (). (). (). (). (). () 7. (). () 9. () 0. (). (). (). (). (). (). () 7. (). () 9. () 0. (). (). (). (). (). (). () 7. (). () 9. () 0. (). (). (). (). (). (). () 7. (). () 9. () 0. (). (). (). (). (). (). () 7. (). () 9. () 70. () 7. () 7. () 7. () 7. () 7. () 7. () 77. () 7. () 79. () 0. (). (). (). (). (). (). () 7. (). () 9. () 90. () 9. () 9. () 9. () 9. () 9. () 9. () 97. () 9. () 99. () 00.() h

SSC [PRE+MAINS] Mock Test 131 [Answer with Solution]

SSC [PRE+MAINS] Mock Test 131 [Answer with Solution] SS [PRE+MINS] Mock Test [nswe with Solution]. () Put 0 in the given epession we get, LHS 0 0. () Given. () Putting nd b in b + bc + c 0 we get, + c 0 c /, b, c / o,, b, c. () bc b c c b 0. b b b b nd hee,

More information

SSC TIER II (MATHS) MOCK TEST - 31 (SOLUTION)

SSC TIER II (MATHS) MOCK TEST - 31 (SOLUTION) 007, OUTRM LINES, ST FLOOR, OOSITE MUKHERJEE NGR OLIE STTION, DELHI-0009 SS TIER II (MTHS) MOK TEST - (SOLUTION). () We know tht x + y + z xyz (x + y + z) (x + y + z xy yz zx) (x + y + z)[(x + y + z) (xy

More information

Topics for Review for Final Exam in Calculus 16A

Topics for Review for Final Exam in Calculus 16A Topics fo Review fo Finl Em in Clculus 16A Instucto: Zvezdelin Stnkov Contents 1. Definitions 1. Theoems nd Poblem Solving Techniques 1 3. Eecises to Review 5 4. Chet Sheet 5 1. Definitions Undestnd the

More information

GEOMETRY Properties of lines

GEOMETRY Properties of lines www.sscexmtuto.com GEOMETRY Popeties of lines Intesecting Lines nd ngles If two lines intesect t point, ten opposite ngles e clled veticl ngles nd tey ve te sme mesue. Pependicul Lines n ngle tt mesues

More information

STD: XI MATHEMATICS Total Marks: 90. I Choose the correct answer: ( 20 x 1 = 20 ) a) x = 1 b) x =2 c) x = 3 d) x = 0

STD: XI MATHEMATICS Total Marks: 90. I Choose the correct answer: ( 20 x 1 = 20 ) a) x = 1 b) x =2 c) x = 3 d) x = 0 STD: XI MATHEMATICS Totl Mks: 90 Time: ½ Hs I Choose the coect nswe: ( 0 = 0 ). The solution of is ) = b) = c) = d) = 0. Given tht the vlue of thid ode deteminnt is then the vlue of the deteminnt fomed

More information

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS JEE(MAIN) 05 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 0 th APRIL, 05) PART B MATHEMATICS CODE-D. Let, b nd c be three non-zero vectors such tht no two of them re colliner nd, b c b c. If is the ngle

More information

Homework 3 MAE 118C Problems 2, 5, 7, 10, 14, 15, 18, 23, 30, 31 from Chapter 5, Lamarsh & Baratta. The flux for a point source is:

Homework 3 MAE 118C Problems 2, 5, 7, 10, 14, 15, 18, 23, 30, 31 from Chapter 5, Lamarsh & Baratta. The flux for a point source is: . Homewok 3 MAE 8C Poblems, 5, 7, 0, 4, 5, 8, 3, 30, 3 fom Chpte 5, msh & Btt Point souces emit nuetons/sec t points,,, n 3 fin the flux cuent hlf wy between one sie of the tingle (blck ot). The flux fo

More information

(A) 6.32 (B) 9.49 (C) (D) (E) 18.97

(A) 6.32 (B) 9.49 (C) (D) (E) 18.97 Univesity of Bhin Physics 10 Finl Exm Key Fll 004 Deptment of Physics 13/1/005 8:30 10:30 e =1.610 19 C, m e =9.1110 31 Kg, m p =1.6710 7 Kg k=910 9 Nm /C, ε 0 =8.8410 1 C /Nm, µ 0 =4π10 7 T.m/A Pt : 10

More information

SOLUTIONS TO CONCEPTS CHAPTER 11

SOLUTIONS TO CONCEPTS CHAPTER 11 SLUTINS T NEPTS HPTE. Gvittionl fce of ttction, F.7 0 0 0.7 0 7 N (0.). To clculte the gvittionl fce on t unline due to othe ouse. F D G 4 ( / ) 8G E F I F G ( / ) G ( / ) G 4G 4 D F F G ( / ) G esultnt

More information

SSC Mains Mock Test 227 [Answer with Solution]

SSC Mains Mock Test 227 [Answer with Solution] SS Mins Mock Test 7 [nswer with Solution]. (D) E ccording to question, G 00 00 8 0 G GF, F D Let, GF GF Now, eterior ngle FGE FGE FEG Now, eterior ngle D In DE, + + 80º 80º 7 5º (ppro.). () I st digit

More information

U>, and is negative. Electric Potential Energy

U>, and is negative. Electric Potential Energy Electic Potentil Enegy Think of gvittionl potentil enegy. When the lock is moved veticlly up ginst gvity, the gvittionl foce does negtive wok (you do positive wok), nd the potentil enegy (U) inceses. When

More information

1 (=0.5) I3 a 7 I4 a 15 I5 a (=0.5) c 4 N 10 1 (=0.5) N 6 A 52 S 2

1 (=0.5) I3 a 7 I4 a 15 I5 a (=0.5) c 4 N 10 1 (=0.5) N 6 A 52 S 2 Answers: (98-84 HKMO Finl Events) Creted by Mr. Frncis Hung Lst updted: December 05 Individul Events SI 900 I 0 I (=0.5) I 7 I4 5 I5 80 b 7 b b 5 b 6 b 8 b 4 c c 4 c 0 x (=0.5) c 4 N 0 d 9 d 5 d 5 y d

More information

10 m, so the distance from the Sun to the Moon during a solar eclipse is. The mass of the Sun, Earth, and Moon are = =

10 m, so the distance from the Sun to the Moon during a solar eclipse is. The mass of the Sun, Earth, and Moon are = = Chpte 1 nivesl Gvittion 11 *P1. () The un-th distnce is 1.4 nd the th-moon 8 distnce is.84, so the distnce fom the un to the Moon duing sol eclipse is 11 8 11 1.4.84 = 1.4 The mss of the un, th, nd Moon

More information

Trigonometric Functions

Trigonometric Functions Exercise. Degrees nd Rdins Chpter Trigonometric Functions EXERCISE. Degrees nd Rdins 4. Since 45 corresponds to rdin mesure of π/4 rd, we hve: 90 = 45 corresponds to π/4 or π/ rd. 5 = 7 45 corresponds

More information

Answers to test yourself questions

Answers to test yourself questions Answes to test youself questions opic Descibing fields Gm Gm Gm Gm he net field t is: g ( d / ) ( 4d / ) d d Gm Gm Gm Gm Gm Gm b he net potentil t is: V d / 4d / d 4d d d V e 4 7 9 49 J kg 7 7 Gm d b E

More information

SSC MAINS (MATHS) MOCK TEST-14 (SOLUTION)

SSC MAINS (MATHS) MOCK TEST-14 (SOLUTION) SSC MINS (MTHS) MOCK TEST- (SOLUTION). () b c a a c b b c a a c b 0 a b c a b c. (C) y hours 8 min 8 60 5 hrs. b c a a a c b b a b c 0 c hours 0 min 0 60 0 hrs. (a b c) a b c 0 V V T T /5 0 / 6 5 6 5 a

More information

Physics 1502: Lecture 2 Today s Agenda

Physics 1502: Lecture 2 Today s Agenda 1 Lectue 1 Phsics 1502: Lectue 2 Tod s Agend Announcements: Lectues posted on: www.phs.uconn.edu/~cote/ HW ssignments, solutions etc. Homewok #1: On Mstephsics this Fid Homewoks posted on Msteingphsics

More information

SSC MAINS (MATHS) MOCK TEST-10 (SOLUTION)

SSC MAINS (MATHS) MOCK TEST-10 (SOLUTION) SS MINS (MTHS) MOK TEST-0 (SOLUTION). () x 8 y 8 Sum x and y together can finish the job. () 8 M 60 60 minutes M W W 00 50 (00 x) (50 50) 00 50 (00 x) 00 00 x 00 x 00 Extra workers needed 00. () x can

More information

AQA Maths M2. Topic Questions from Papers. Circular Motion. Answers

AQA Maths M2. Topic Questions from Papers. Circular Motion. Answers AQA Mths M Topic Questions fom Ppes Cicul Motion Answes PhysicsAndMthsTuto.com PhysicsAndMthsTuto.com Totl 6 () T cos30 = 9.8 Resolving veticlly with two tems Coect eqution 9.8 T = cos30 T =.6 N AG 3 Coect

More information

SSC MAINS (MATHS) MOCK TEST-1 (SOLUTION)

SSC MAINS (MATHS) MOCK TEST-1 (SOLUTION) 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 SSC MINS (MTHS) MOCK TEST- (SOLUTION). (B) Order of surds re,,. LCM of, nd is. So, convert ec surd into surd of order 0 0 0 6

More information

CHAPTER 29 ELECTRIC FIELD AND POTENTIAL EXERCISES

CHAPTER 29 ELECTRIC FIELD AND POTENTIAL EXERCISES HPTER ELETRI FIELD ND POTENTIL EXERISES. oulob Newton l M L T 4 k F.. istnce between k so, foce k ( F ( The weight of boy 4 N 4 N wt of boy So,. foce between chges 4 So, foce between chges.6 weight of

More information

CHAPTER? 29 ELECTRIC FIELD AND POTENTIAL EXERCISES = 2, N = (5.6) 1 = = = = = Newton

CHAPTER? 29 ELECTRIC FIELD AND POTENTIAL EXERCISES = 2, N = (5.6) 1 = = = = = Newton Downloe fo HPTER? ELETRI FIELD ND POTENTIL EXERISES. oulob Newton l M L T 4 k F.. istnce between k so, foce k ( F ( The weight of boy 4 N 4 N wt of boy.5 So, foce between chges 4 So, foce between chges

More information

3 x x 3x x. 3x x x 6 x 3. PAKTURK 8 th National Interschool Maths Olympiad, h h

3 x x 3x x. 3x x x 6 x 3. PAKTURK 8 th National Interschool Maths Olympiad, h h PAKTURK 8 th Ntionl Interschool Mths Olmpid,.9. Q: Evlute 6.9. 6 6 6... 8 8...... Q: Evlute bc bc. b. c bc.9.9b.9.9bc Q: Find the vlue of h in the eqution h 7 9 7.. bc. bc bc. b. c bc bc bc bc......9 h

More information

Marking Scheme. Mathematics Class X ( ) Section A

Marking Scheme. Mathematics Class X ( ) Section A Marking Scheme Mathematics Class X (017-18) Section A S.No. Answer Marks 1. Non terminating repeating decimal expansion.. k ±4 3. a 11 5 4. (0, 5) 5. 9 : 49 6. 5 Section B 7. LCM (p, q) a 3 b 3 HCF (p,

More information

MATHEMATICS IV 2 MARKS. 5 2 = e 3, 4

MATHEMATICS IV 2 MARKS. 5 2 = e 3, 4 MATHEMATICS IV MARKS. If + + 6 + c epesents cicle with dius 6, find the vlue of c. R 9 f c ; g, f 6 9 c 6 c c. Find the eccenticit of the hpeol Eqution of the hpeol Hee, nd + e + e 5 e 5 e. Find the distnce

More information

SSC (Tier-II) (Mock Test Paper - 2) [SOLUTION]

SSC (Tier-II) (Mock Test Paper - 2) [SOLUTION] SS (Tier-II) - 0 (Mock Test Paper - ) [SOLUTION]. () 7 7 7 7 7 8 8 7 8 7 7 9 R R 8 8 8. (D) Let the first odd integer the second odd integer + Difference between the squares of these two consecutive odd

More information

SAMPLE QUESTION PAPER Class-X ( ) Mathematics. Time allowed: 3 Hours Max. Marks: 80

SAMPLE QUESTION PAPER Class-X ( ) Mathematics. Time allowed: 3 Hours Max. Marks: 80 SAMPLE QUESTION PAPER Class-X (017 18) Mathematics Time allowed: 3 Hours Max. Marks: 80 General Instructions: (i) All questions are compulsory. (ii) The question paper consists of 30 questions divided

More information

SOLUTION OF TRIANGLE GENERAL NOTATION : 1. In a triangle ABC angles at vertices are usually denoted by A, B, C

SOLUTION OF TRIANGLE GENERAL NOTATION : 1. In a triangle ABC angles at vertices are usually denoted by A, B, C GENERL NOTTION : SOLUTION OF TRINGLE In tringle BC ngles t vertices re usully denoted by, B, C PGE # sides opposite to these vertices re denoted by, b, c respectively Circumrdius is denoted by R 3 Inrdius

More information

Higher Checklist (Unit 3) Higher Checklist (Unit 3) Vectors

Higher Checklist (Unit 3) Higher Checklist (Unit 3) Vectors Vectors Skill Achieved? Know tht sclr is quntity tht hs only size (no direction) Identify rel-life exmples of sclrs such s, temperture, mss, distnce, time, speed, energy nd electric chrge Know tht vector

More information

Algebra Based Physics. Gravitational Force. PSI Honors universal gravitation presentation Update Fall 2016.notebookNovember 10, 2016

Algebra Based Physics. Gravitational Force. PSI Honors universal gravitation presentation Update Fall 2016.notebookNovember 10, 2016 Newton's Lw of Univesl Gvittion Gvittionl Foce lick on the topic to go to tht section Gvittionl Field lgeb sed Physics Newton's Lw of Univesl Gvittion Sufce Gvity Gvittionl Field in Spce Keple's Thid Lw

More information

ICSE Solved Paper, 2018

ICSE Solved Paper, 2018 ICSE Solved Paper, 018 Class-X Mathematics (Maximum Marks : 80) (Time allowed : Two hours and a half) Answers to this Paper must be written on the paper provided separately. You will not be allowed to

More information

Equations from the Millennium Theory of Inertia and Gravity. Copyright 2004 Joseph A. Rybczyk

Equations from the Millennium Theory of Inertia and Gravity. Copyright 2004 Joseph A. Rybczyk Equtions fo the illenniu heoy of Ineti nd vity Copyight 004 Joseph A. Rybzyk ollowing is oplete list of ll of the equtions used o deived in the illenniu heoy of Ineti nd vity. o ese of efeene the equtions

More information

This immediately suggests an inverse-square law for a "piece" of current along the line.

This immediately suggests an inverse-square law for a piece of current along the line. Electomgnetic Theoy (EMT) Pof Rui, UNC Asheville, doctophys on YouTube Chpte T Notes The iot-svt Lw T nvese-sque Lw fo Mgnetism Compe the mgnitude of the electic field t distnce wy fom n infinite line

More information

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES THE 08 09 KENNESW STTE UNIVERSITY HIGH SHOOL MTHEMTIS OMPETITION PRT I MULTIPLE HOIE For ech of the following questions, crefully blcken the pproprite box on the nswer sheet with # pencil. o not fold,

More information

SAINT IGNATIUS COLLEGE

SAINT IGNATIUS COLLEGE SAINT IGNATIUS COLLEGE Directions to Students Tril Higher School Certificte 0 MATHEMATICS Reding Time : 5 minutes Totl Mrks 00 Working Time : hours Write using blue or blck pen. (sketches in pencil). This

More information

School of Electrical and Computer Engineering, Cornell University. ECE 303: Electromagnetic Fields and Waves. Fall 2007

School of Electrical and Computer Engineering, Cornell University. ECE 303: Electromagnetic Fields and Waves. Fall 2007 School of Electicl nd Compute Engineeing, Conell Univesity ECE 303: Electomgnetic Fields nd Wves Fll 007 Homewok 4 Due on Sep. 1, 007 by 5:00 PM Reding Assignments: i) Review the lectue notes. ii) Relevnt

More information

Physics 11b Lecture #11

Physics 11b Lecture #11 Physics 11b Lectue #11 Mgnetic Fields Souces of the Mgnetic Field S&J Chpte 9, 3 Wht We Did Lst Time Mgnetic fields e simil to electic fields Only diffeence: no single mgnetic pole Loentz foce Moving chge

More information

1 Using Integration to Find Arc Lengths and Surface Areas

1 Using Integration to Find Arc Lengths and Surface Areas Novembe 9, 8 MAT86 Week Justin Ko Using Integtion to Find Ac Lengths nd Sufce Aes. Ac Length Fomul: If f () is continuous on [, b], then the c length of the cuve = f() on the intevl [, b] is given b s

More information

Individual Group. Individual Events I1 If 4 a = 25 b 1 1. = 10, find the value of.

Individual Group. Individual Events I1 If 4 a = 25 b 1 1. = 10, find the value of. Answers: (000-0 HKMO Het Events) Creted y: Mr. Frnis Hung Lst udted: July 0 00-0 33 3 7 7 5 Individul 6 7 7 3.5 75 9 9 0 36 00-0 Grou 60 36 3 0 5 6 7 7 0 9 3 0 Individul Events I If = 5 = 0, find the vlue

More information

MCR 3U Exam Review. 1. Determine which of the following equations represent functions. Explain. Include a graph. 2. y x

MCR 3U Exam Review. 1. Determine which of the following equations represent functions. Explain. Include a graph. 2. y x MCR U MCR U Em Review Introduction to Functions. Determine which of the following equtions represent functions. Eplin. Include grph. ) b) c) d) 0. Stte the domin nd rnge for ech reltion in question.. If

More information

Paper: 02 Class-X-Math: Summative Assessment - I

Paper: 02 Class-X-Math: Summative Assessment - I 1 P a g e Paper: 02 Class-X-Math: Summative Assessment - I Total marks of the paper: 90 Total time of the paper: 3.5 hrs Questions: 1] The relation connecting the measures of central tendencies is [Marks:1]

More information

Mathematics Extension Two

Mathematics Extension Two Student Number 04 HSC TRIAL EXAMINATION Mthemtics Etension Two Generl Instructions Reding time 5 minutes Working time - hours Write using blck or blue pen Bord-pproved clcultors my be used Write your Student

More information

Mark Scheme (Results) January 2008

Mark Scheme (Results) January 2008 Mk Scheme (Results) Jnuy 00 GCE GCE Mthemtics (6679/0) Edecel Limited. Registeed in Englnd nd Wles No. 4496750 Registeed Office: One90 High Holbon, London WCV 7BH Jnuy 00 6679 Mechnics M Mk Scheme Question

More information

Level I MAML Olympiad 2001 Page 1 of 6 (A) 90 (B) 92 (C) 94 (D) 96 (E) 98 (A) 48 (B) 54 (C) 60 (D) 66 (E) 72 (A) 9 (B) 13 (C) 17 (D) 25 (E) 38

Level I MAML Olympiad 2001 Page 1 of 6 (A) 90 (B) 92 (C) 94 (D) 96 (E) 98 (A) 48 (B) 54 (C) 60 (D) 66 (E) 72 (A) 9 (B) 13 (C) 17 (D) 25 (E) 38 Level I MAML Olympid 00 Pge of 6. Si students in smll clss took n em on the scheduled dte. The verge of their grdes ws 75. The seventh student in the clss ws ill tht dy nd took the em lte. When her score

More information

are its positions as it is moving in anti-clockwise direction through angles 1, 2, 3 &

are its positions as it is moving in anti-clockwise direction through angles 1, 2, 3 & T: Introduction: The word trigonometry is derived from Greek words trigon meaning a triangle and metron meaning measurement. In this branch of mathematics, we study relationship of sides and angles of

More information

Trigonometry Revision Sheet Q5 of Paper 2

Trigonometry Revision Sheet Q5 of Paper 2 Trigonometry Revision Sheet Q of Pper The Bsis - The Trigonometry setion is ll out tringles. We will normlly e given some of the sides or ngles of tringle nd we use formule nd rules to find the others.

More information

PLEASE DO NOT TURN THIS PAGE UNTIL INSTRUCTED TO DO SO THEN ENSURE THAT YOU HAVE THE CORRECT EXAM PAPER

PLEASE DO NOT TURN THIS PAGE UNTIL INSTRUCTED TO DO SO THEN ENSURE THAT YOU HAVE THE CORRECT EXAM PAPER OLLSCOIL NA ÉIREANN, CORCAIGH THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA OLLSCOILE, CORCAIGH UNIVERSITY COLLEGE, CORK 4/5 Autumn Suppement 5 MS Integ Ccuus nd Diffeenti Equtions Pof. P.J. Rippon

More information

KEY CONCEPTS. satisfies the differential equation da. = 0. Note : If F (x) is any integral of f (x) then, x a

KEY CONCEPTS. satisfies the differential equation da. = 0. Note : If F (x) is any integral of f (x) then, x a KEY CONCEPTS THINGS TO REMEMBER :. The re ounded y the curve y = f(), the -is nd the ordintes t = & = is given y, A = f () d = y d.. If the re is elow the is then A is negtive. The convention is to consider

More information

FORM FIVE ADDITIONAL MATHEMATIC NOTE. ar 3 = (1) ar 5 = = (2) (2) (1) a = T 8 = 81

FORM FIVE ADDITIONAL MATHEMATIC NOTE. ar 3 = (1) ar 5 = = (2) (2) (1) a = T 8 = 81 FORM FIVE ADDITIONAL MATHEMATIC NOTE CHAPTER : PROGRESSION Arithmetic Progression T n = + (n ) d S n = n [ + (n )d] = n [ + Tn ] S = T = T = S S Emple : The th term of n A.P. is 86 nd the sum of the first

More information

10 If 3, a, b, c, 23 are in A.S., then a + b + c = 15 Find the perimeter of the sector in the figure. A. 1:3. A. 2.25cm B. 3cm

10 If 3, a, b, c, 23 are in A.S., then a + b + c = 15 Find the perimeter of the sector in the figure. A. 1:3. A. 2.25cm B. 3cm HK MTHS Pper II P. If f ( x ) = 0 x, then f ( y ) = 6 0 y 0 + y 0 y 0 8 y 0 y If s = ind the gretest vlue of x + y if ( x, y ) is point lying in the region O (including the boundry). n [ + (n )d ], then

More information

Electric Field F E. q Q R Q. ˆ 4 r r - - Electric field intensity depends on the medium! origin

Electric Field F E. q Q R Q. ˆ 4 r r - - Electric field intensity depends on the medium! origin 1 1 Electic Field + + q F Q R oigin E 0 0 F E ˆ E 4 4 R q Q R Q - - Electic field intensity depends on the medium! Electic Flux Density We intoduce new vecto field D independent of medium. D E So, electic

More information

Individual Events I3 a 10 I4. d 90 angle 57 d Group Events. d 220 Probability

Individual Events I3 a 10 I4. d 90 angle 57 d Group Events. d 220 Probability Answers: (98-8 HKMO Finl Events) Creted by: Mr. Frncis Hung Lst updted: 8 Jnury 08 I 800 I Individul Events I 0 I4 no. of routes 6 I5 + + b b 0 b b c *8 missing c 0 c c See the remrk 600 d d 90 ngle 57

More information

Chapter 28 Sources of Magnetic Field

Chapter 28 Sources of Magnetic Field Chpte 8 Souces of Mgnetic Field - Mgnetic Field of Moving Chge - Mgnetic Field of Cuent Element - Mgnetic Field of Stight Cuent-Cying Conducto - Foce Between Pllel Conductos - Mgnetic Field of Cicul Cuent

More information

On the diagram below the displacement is represented by the directed line segment OA.

On the diagram below the displacement is represented by the directed line segment OA. Vectors Sclrs nd Vectors A vector is quntity tht hs mgnitude nd direction. One exmple of vector is velocity. The velocity of n oject is determined y the mgnitude(speed) nd direction of trvel. Other exmples

More information

Lesson-5 ELLIPSE 2 1 = 0

Lesson-5 ELLIPSE 2 1 = 0 Lesson-5 ELLIPSE. An ellipse is the locus of point which moves in plne such tht its distnce from fied point (known s the focus) is e (< ), times its distnce from fied stright line (known s the directri).

More information

OBJECTIVE TEST. Answer all questions C. N3, D. N3, Simplify Express the square root of in 4

OBJECTIVE TEST. Answer all questions C. N3, D. N3, Simplify Express the square root of in 4 . In a particular year, the exchange rate of Naira (N) varies directly with the Dollar ($). If N is equivalent to $8, find the Naira equivalent of $6. A. N8976 B. N049 C. N40. D. N.7. If log = x, log =

More information

CHAPTER 7 Applications of Integration

CHAPTER 7 Applications of Integration CHAPTER 7 Applitions of Integtion Setion 7. Ae of Region Between Two Cuves.......... Setion 7. Volume: The Disk Method................. Setion 7. Volume: The Shell Method................ Setion 7. A Length

More information

Solutions to Midterm Physics 201

Solutions to Midterm Physics 201 Solutions to Midtem Physics. We cn conside this sitution s supeposition of unifomly chged sphee of chge density ρ nd dius R, nd second unifomly chged sphee of chge density ρ nd dius R t the position of

More information

3.1 Review of Sine, Cosine and Tangent for Right Angles

3.1 Review of Sine, Cosine and Tangent for Right Angles Foundtions of Mth 11 Section 3.1 Review of Sine, osine nd Tngent for Right Tringles 125 3.1 Review of Sine, osine nd Tngent for Right ngles The word trigonometry is derived from the Greek words trigon,

More information

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions )

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions ) - TRIGONOMETRY Pge P ( ) In tringle PQR, R =. If tn b c = 0, 0, then Q nd tn re the roots of the eqution = b c c = b b = c b = c [ AIEEE 00 ] ( ) In tringle ABC, let C =. If r is the inrdius nd R is the

More information

MATHEMATICS (Part II) (Fresh / New Course)

MATHEMATICS (Part II) (Fresh / New Course) Sig. of Supdt... MRD-XII-(A) MATHEMATICS Roll No... Time Allowed : Hrs. MATHEMATICS Totl Mrks: 00 NOTE : There re THREE sections in this pper i.e. Section A, B nd C. Time : 0 Mins. Section A Mrks: 0 NOTE

More information

Equations, expressions and formulae

Equations, expressions and formulae Get strted 2 Equtions, epressions nd formule This unit will help you to work with equtions, epressions nd formule. AO1 Fluency check 1 Work out 2 b 2 c 7 2 d 7 2 2 Simplify by collecting like terms. b

More information

GEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS:

GEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS: GEOMETRICL PROPERTIES OF NGLES ND CIRCLES, NGLES PROPERTIES OF TRINGLES, QUDRILTERLS ND POLYGONS: 1.1 TYPES OF NGLES: CUTE NGLE RIGHT NGLE OTUSE NGLE STRIGHT NGLE REFLEX NGLE 40 0 4 0 90 0 156 0 180 0

More information

review To find the coefficient of all the terms in 15ab + 60bc 17ca: Coefficient of ab = 15 Coefficient of bc = 60 Coefficient of ca = -17

review To find the coefficient of all the terms in 15ab + 60bc 17ca: Coefficient of ab = 15 Coefficient of bc = 60 Coefficient of ca = -17 1. Revision Recall basic terms of algebraic expressions like Variable, Constant, Term, Coefficient, Polynomial etc. The coefficients of the terms in 4x 2 5xy + 6y 2 are Coefficient of 4x 2 is 4 Coefficient

More information

SOLUTIONS TO CONCEPTS CHAPTER

SOLUTIONS TO CONCEPTS CHAPTER 1. m = kg S = 10m Let, ccelertion =, Initil velocity u = 0. S= ut + 1/ t 10 = ½ ( ) 10 = = 5 m/s orce: = = 5 = 10N (ns) SOLUIONS O CONCEPS CHPE 5 40000. u = 40 km/hr = = 11.11 m/s. 3600 m = 000 kg ; v

More information

Physics 505 Fall 2005 Midterm Solutions. This midterm is a two hour open book, open notes exam. Do all three problems.

Physics 505 Fall 2005 Midterm Solutions. This midterm is a two hour open book, open notes exam. Do all three problems. Physics 55 Fll 5 Midtem Solutions This midtem is two hou open ook, open notes exm. Do ll thee polems. [35 pts] 1. A ectngul ox hs sides of lengths, nd c z x c [1] ) Fo the Diichlet polem in the inteio

More information

SSC [PRE+MAINS] Mock Test 230 [Answer with Solution]

SSC [PRE+MAINS] Mock Test 230 [Answer with Solution] SS [PRE+MAINS] Mock Test 0 [Answer with Solution]. () (x ) (x + ) (x ) (x + ) (x + x ) (x + x ) x + x x + x + x x x x + x + x x x + So, cofficient of x. () HF of fraction. () HF of,, LM of,8, t t x v x

More information

Mathematics Extension 1

Mathematics Extension 1 04 Bored of Studies Tril Emintions Mthemtics Etension Written by Crrotsticks & Trebl. Generl Instructions Totl Mrks 70 Reding time 5 minutes. Working time hours. Write using blck or blue pen. Blck pen

More information

CBSE-XII-2015 EXAMINATION. Section A. 1. Find the sum of the order and the degree of the following differential equation : = 0

CBSE-XII-2015 EXAMINATION. Section A. 1. Find the sum of the order and the degree of the following differential equation : = 0 CBSE-XII- EXMINTION MTHEMTICS Pper & Solution Time : Hrs. M. Mrks : Generl Instruction : (i) ll questions re compulsory. There re questions in ll. (ii) This question pper hs three sections : Section, Section

More information

MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS WEEK 11 WRITTEN EXAMINATION 2 SOLUTIONS SECTION 1 MULTIPLE CHOICE QUESTIONS

MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS WEEK 11 WRITTEN EXAMINATION 2 SOLUTIONS SECTION 1 MULTIPLE CHOICE QUESTIONS MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS WEEK WRITTEN EXAMINATION SOLUTIONS FOR ERRORS AND UPDATES, PLEASE VISIT WWW.TSFX.COM.AU/MC-UPDATES SECTION MULTIPLE CHOICE QUESTIONS QUESTION QUESTION

More information

JEE Advnced Mths Assignment Onl One Correct Answer Tpe. The locus of the orthocenter of the tringle formed the lines (+P) P + P(+P) = 0, (+q) q+q(+q) = 0 nd = 0, where p q, is () hperol prol n ellipse

More information

Drill Exercise Find the coordinates of the vertices, foci, eccentricity and the equations of the directrix of the hyperbola 4x 2 25y 2 = 100.

Drill Exercise Find the coordinates of the vertices, foci, eccentricity and the equations of the directrix of the hyperbola 4x 2 25y 2 = 100. Drill Exercise - 1 1 Find the coordintes of the vertices, foci, eccentricit nd the equtions of the directrix of the hperol 4x 5 = 100 Find the eccentricit of the hperol whose ltus-rectum is 8 nd conjugte

More information

Time : 2 Hours (Pages 3) Max. Marks : 40. Q.1. Solve the following : (Any 5) 5 In PQR, m Q = 90º, m P = 30º, m R = 60º. If PR = 8 cm, find QR.

Time : 2 Hours (Pages 3) Max. Marks : 40. Q.1. Solve the following : (Any 5) 5 In PQR, m Q = 90º, m P = 30º, m R = 60º. If PR = 8 cm, find QR. Q.P. SET CODE Q.1. Solve the following : (ny 5) 5 (i) (ii) In PQR, m Q 90º, m P 0º, m R 60º. If PR 8 cm, find QR. O is the centre of the circle. If m C 80º, the find m (arc C) and m (arc C). Seat No. 01

More information

CBSE Sample Question Paper 1 ( )

CBSE Sample Question Paper 1 ( ) CBSE Sample Question Paper (07-8 Time: Hours Maximum Marks: 80 General Instructions: (i All questions are compulsory. (ii The question paper consists of 0 questions divided into four sections A, B, C and

More information

If C = 60 and = P, find the value of P. c 2 = a 2 + b 2 2abcos 60 = a 2 + b 2 ab a 2 + b 2 = c 2 + ab. c a

If C = 60 and = P, find the value of P. c 2 = a 2 + b 2 2abcos 60 = a 2 + b 2 ab a 2 + b 2 = c 2 + ab. c a Answers: (000-0 HKMO Finl Events) Creted : Mr. Frncis Hung Lst updted: 0 June 08 Individul Events I P I P I P I P 5 7 0 0 S S S S Group Events G G G G 80 00 0 c 8 c c c d d 6 d 5 d 85 Individul Event I.,

More information

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES PAIR OF LINEAR EQUATIONS IN TWO VARIABLES. Two liner equtions in the sme two vriles re lled pir of liner equtions in two vriles. The most generl form of pir of liner equtions is x + y + 0 x + y + 0 where,,,,,,

More information

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives Block #6: Properties of Integrls, Indefinite Integrls Gols: Definition of the Definite Integrl Integrl Clcultions using Antiderivtives Properties of Integrls The Indefinite Integrl 1 Riemnn Sums - 1 Riemnn

More information

Algebraic Expressions

Algebraic Expressions Algebraic Expressions 1. Expressions are formed from variables and constants. 2. Terms are added to form expressions. Terms themselves are formed as product of factors. 3. Expressions that contain exactly

More information

6. Gravitation. 6.1 Newton's law of Gravitation

6. Gravitation. 6.1 Newton's law of Gravitation Gvittion / 1 6.1 Newton's lw of Gvittion 6. Gvittion Newton's lw of gvittion sttes tht evey body in this univese ttcts evey othe body with foce, which is diectly popotionl to the poduct of thei msses nd

More information

MT EDUCARE LTD. SUMMATIVE ASSESSMENT Roll No. Code No. 31/1

MT EDUCARE LTD. SUMMATIVE ASSESSMENT Roll No. Code No. 31/1 CBSE - X MT EDUCARE LTD. SUMMATIVE ASSESSMENT - 03-4 Roll No. Code No. 3/ Series RLH Please check that this question paper contains 6 printed pages. Code number given on the right hand side of the question

More information

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 4 UNIT (ADDITIONAL) Time allowed Three hours (Plus 5 minutes reading time)

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 4 UNIT (ADDITIONAL) Time allowed Three hours (Plus 5 minutes reading time) HIGHER SCHOOL CERTIFICATE EXAMINATION 999 MATHEMATICS UNIT (ADDITIONAL) Time llowed Three hours (Plus 5 minutes reding time) DIRECTIONS TO CANDIDATES Attempt ALL questions ALL questions re of equl vlue

More information

FSK 116 Semester 1 Mathematics and Other Essentials. Priorities

FSK 116 Semester 1 Mathematics and Other Essentials. Priorities FSK 6 Semeste Mthemtics nd Othe Essentils Pioities Know how YOUR clculto woks nd lwys hve YOUR clculto with you. Alwys hve pencil (nd n ese) t hnd when doing Physics. Geek Alphbet Alph Et Nu Tu Bet Thet

More information

IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB

IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB ` K UKATP ALLY CE NTRE IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB 7-8 FIITJEE KUKATPALLY CENTRE: # -97, Plot No, Opp Ptel Kunt Hud Prk, Vijngr Colon, Hderbd - 5 7 Ph: -66 Regd

More information

Fluids & Bernoulli s Equation. Group Problems 9

Fluids & Bernoulli s Equation. Group Problems 9 Goup Poblems 9 Fluids & Benoulli s Eqution Nme This is moe tutoil-like thn poblem nd leds you though conceptul development of Benoulli s eqution using the ides of Newton s 2 nd lw nd enegy. You e going

More information

π,π is the angle FROM a! TO b

π,π is the angle FROM a! TO b Mth 151: 1.2 The Dot Poduct We hve scled vectos (o, multiplied vectos y el nume clled scl) nd dded vectos (in ectngul component fom). Cn we multiply vectos togethe? The nswe is YES! In fct, thee e two

More information

Chapter y. 8. n cd (x y) 14. (2a b) 15. (a) 3(x 2y) = 3x 3(2y) = 3x 6y. 16. (a)

Chapter y. 8. n cd (x y) 14. (2a b) 15. (a) 3(x 2y) = 3x 3(2y) = 3x 6y. 16. (a) Chapter 6 Chapter 6 opener A. B. C. D. 6 E. 5 F. 8 G. H. I. J.. 7. 8 5. 6 6. 7. y 8. n 9. w z. 5cd.. xy z 5r s t. (x y). (a b) 5. (a) (x y) = x (y) = x 6y x 6y = x (y) = (x y) 6. (a) a (5 a+ b) = a (5

More information

Prerequisite Knowledge Required from O Level Add Math. d n a = c and b = d

Prerequisite Knowledge Required from O Level Add Math. d n a = c and b = d Prerequisite Knowledge Required from O Level Add Mth ) Surds, Indices & Logrithms Rules for Surds. b= b =. 3. 4. b = b = ( ) = = = 5. + b n = c+ d n = c nd b = d Cution: + +, - Rtionlising the Denomintor

More information

THEORY OF EQUATIONS OBJECTIVE PROBLEMS. If the eqution x 6x 0 0 ) - ) 4) -. If the sum of two oots of the eqution k is -48 ) 6 ) 48 4) 4. If the poduct of two oots of 4 ) -4 ) 4) - 4. If one oot of is

More information

EECS 141 Due 04/19/02, 5pm, in 558 Cory

EECS 141 Due 04/19/02, 5pm, in 558 Cory UIVERSITY OF CALIFORIA College of Engineering Deprtment of Electricl Engineering nd Computer Sciences Lst modified on April 8, 2002 y Tufn Krlr (tufn@eecs.erkeley.edu) Jn M. Rey, Andrei Vldemirescu Homework

More information

(a) Counter-Clockwise (b) Clockwise ()N (c) No rotation (d) Not enough information

(a) Counter-Clockwise (b) Clockwise ()N (c) No rotation (d) Not enough information m m m00 kg dult, m0 kg bby. he seesw stts fom est. Which diection will it ottes? ( Counte-Clockwise (b Clockwise ( (c o ottion ti (d ot enough infomtion Effect of Constnt et oque.3 A constnt non-zeo toque

More information

1 cos. cos cos cos cos MAT 126H Solutions Take-Home Exam 4. Problem 1

1 cos. cos cos cos cos MAT 126H Solutions Take-Home Exam 4. Problem 1 MAT 16H Solutions Tke-Home Exm 4 Problem 1 ) & b) Using the hlf-ngle formul for cosine, we get: 1 cos 1 4 4 cos cos 8 4 nd 1 8 cos cos 16 4 c) Using the hlf-ngle formul for tngent, we get: cot ( 3π 1 )

More information

Math 1102: Calculus I (Math/Sci majors) MWF 3pm, Fulton Hall 230 Homework 2 solutions

Math 1102: Calculus I (Math/Sci majors) MWF 3pm, Fulton Hall 230 Homework 2 solutions Mth 1102: Clculus I (Mth/Sci mjors) MWF 3pm, Fulton Hll 230 Homework 2 solutions Plese write netly, nd show ll work. Cution: An nswer with no work is wrong! Do the following problems from Chpter III: 6,

More information

PHYS Summer Professor Caillault Homework Solutions. Chapter 2

PHYS Summer Professor Caillault Homework Solutions. Chapter 2 PHYS 1111 - Summer 2007 - Professor Cillult Homework Solutions Chpter 2 5. Picture the Problem: The runner moves long the ovl trck. Strtegy: The distnce is the totl length of trvel, nd the displcement

More information

LA0011_11GB. Formulas and Units. Rotation 2 W. W = work in Ws = J = Nm. = ang. velocity in rad./sec. f = frequency in rev./sec.

LA0011_11GB. Formulas and Units. Rotation 2 W. W = work in Ws = J = Nm. = ang. velocity in rad./sec. f = frequency in rev./sec. Tnsmission technicl clcultions Min Fomuls Size designtions nd units ccoding to the SI-units Line moement: s m/s t s t m s 1 m t m/s t P F W F m N Rottion ω π f d/s ω π f m/s M F P M ω W M J ω J ω W Ws

More information

ICSE Board Class IX Mathematics Paper 4 Solution

ICSE Board Class IX Mathematics Paper 4 Solution ICSE Bord Clss IX Mthemtics Pper Solution SECTION A (0 Mrks) Q.. () Consider x y 6 5 5 x y 6 5 5 0 6 0 6 x y 6 50 8 5 6 7 6 x y 6 7 6 x y 6 x 7,y (b) Dimensions of the brick: Length (l) = 0 cm, bredth

More information

d 4 x x 170 n 20 R 8 A 200 h S 1 y 5000 x 3240 A 243

d 4 x x 170 n 20 R 8 A 200 h S 1 y 5000 x 3240 A 243 nswes: (1984-8 HKMO Final Events) eated by: M. Fancis Hung Last updated: 4 pil 017 Individual Events SI a I1 a I a 1 I3 a 4 I4 a I t 8 b 4 b 0 b 1 b 16 b 10 u 13 c c 9 c 3 c 199 c 96 v 4 d 1 d d 16 d 4

More information

Get Solution of These Packages & Learn by Video Tutorials on EXERCISE-1

Get Solution of These Packages & Learn by Video Tutorials on  EXERCISE-1 FEE Downlod Study Pckge fom website: www.tekoclsses.com & www.mthsbysuhg.com Get Solution of These Pckges & Len by Video Tutoils on www.mthsbysuhg.com EXECISE- * MAK IS MOE THAN ONE COECT QUESTIONS. SECTION

More information

1. If y 2 2x 2y + 5 = 0 is (A) a circle with centre (1, 1) (B) a parabola with vertex (1, 2) 9 (A) 0, (B) 4, (C) (4, 4) (D) a (C) c = am m.

1. If y 2 2x 2y + 5 = 0 is (A) a circle with centre (1, 1) (B) a parabola with vertex (1, 2) 9 (A) 0, (B) 4, (C) (4, 4) (D) a (C) c = am m. SET I. If y x y + 5 = 0 is (A) circle with centre (, ) (B) prbol with vertex (, ) (C) prbol with directrix x = 3. The focus of the prbol x 8x + y + 7 = 0 is (D) prbol with directrix x = 9 9 (A) 0, (B)

More information

Time : 3 hours 03 - Mathematics - March 2007 Marks : 100 Pg - 1 S E CT I O N - A

Time : 3 hours 03 - Mathematics - March 2007 Marks : 100 Pg - 1 S E CT I O N - A Time : hours 0 - Mthemtics - Mrch 007 Mrks : 100 Pg - 1 Instructions : 1. Answer ll questions.. Write your nswers ccording to the instructions given below with the questions.. Begin ech section on new

More information

CBSE Board Class X Mathematics

CBSE Board Class X Mathematics CBSE Board Class X Mathematics Time: 3 hrs Total Marks: 80 General Instructions: 1. All questions are compulsory.. The question paper consists of 30 questions divided into four sections A, B, C, and D.

More information