ECE-202 Exam 1 January 31, Name: (Please print clearly.) CIRCLE YOUR DIVISION DeCarlo DeCarlo 7:30 MWF 1:30 TTH
|
|
- Caren Thornton
- 5 years ago
- Views:
Transcription
1 ECE-0 Exam January 3, 08 Name: (Pleae print clearly.) CIRCLE YOUR DIVISION 0 0 DeCarlo DeCarlo 7:30 MWF :30 TTH INSTRUCTIONS There are multiple choice worth 5 point each and workout problem worth 40 point. Allow 0 minute for workout problem a you can obtain partial credit. Thi i a cloed book, cloed note exam. No crap paper or calculator are permitted. Nothing i to be on the eat beide you no coat, book, phone, etc. Carefully mark your multiple choice anwer on the cantron and alo on the text booklet a you will need to put the cantron inide the tet booklet and turn both in at the end of the exam. No turned in exam mean a zero at leat on workout. When the exam end, all writing i to top. No writing while turning in the exam/cantron or rik an F in the exam. Again, turn in the exam booklet with the cantron inide the exam. There are two exam form and thi i neceary for the proper grading of your cantron. All tudent are expected to abide by the cutomary ethical tandard of the univerity, i.e., your anwer mut reflect only your own knowledge and reaoning ability. A a reminder, at the very minimum, cheating will reult in a zero on the exam and poibly an F in the coure. Communicating with any of your clamate, in any language, by any mean, for any reaon, at any time between the official tart of the exam and the official end of the exam i ground for immediate ejection from the exam ite and lo of all credit for thi exercie. The profeor reerve the right to move tudent around during the exam. Do not open, begin, or peek inide thi exam until you are intructed to do o.
2 ECE-0 Spring 08 Exam. The repreentation of the ignal, f (t), hown below and whoe value i for t, in term of caled and hifted tep and ramp i: () r(t +) r(t ) + u(t ) () r(t +) r(t ) + 4u(t ) (3) r(t ) r(t +) (4) r(t ) r(t +) + 4u(t +) (5) r(t +) r(t ) + 4u(t) (6) r(t +) r(t ) + u(t ) (7) r(t +) r(t ) (8) r(t +) r(t ) (9) None of above.5.5 f(t) time in ec Solution. By inpection, f (t) = r(t +) r(t ) Anwer: (8)
3 ECE-0 Spring 08 3 Exam. The ignal, f (t), hown below, i zero for t < 0 and jump to at t = 0 ; it value i for t. The Laplace tranform of f (t) i F() = : () + () + (3) + ( e ) (4) + ( e ) (7) + (+ e ) (5) ( e ) (8) + ( e ) (6) (+ e ) (9) None of above.5.5 f(t) time in ec Solution. By inpection, f (t) = u(t) + r(t) r(t ) implie F() = + e. Anwer: (4)
4 ECE-0 Spring 08 4 Exam 3. In the circuit below, L = H, C = 0.5 F, and G = 0.5 mho. The value of the input impedance, Z in (), at = i: () () (3) 3 (4) 4 (5) 5 (6) 6 (7) 0.5 (8) 0.5 (9) None of above Solution 3. Z in () = L + C + G. Thu at =, Z in () = L + = + = 4 Ω.. Anwer: (4) C + G 4. The ignal below i f (t) = F() = : in(πt) 0 t 0 otherwie. The Laplace tranform of thi ignal i () e π + π () e π + π (4) + e π + π (5) e π π (7) + e π π (8) + e π π (3) + e (6) e π + π π π (9) None of above
5 ECE-0 Spring 08 5 Exam.5.5 f(t) time in ec Solution 4. f (t) = in(πt)u(t) + in( π (t ) )u(t ) in which cae F() = + e Anwer: (4) π + π. 5. Suppoe L f (t) { } = ln () + a () (4) + a (5) { } i: + a. Then L te at f (t) ( + a) (3) + a (7) (8) (6) (9) None of above
6 ECE-0 Spring 08 6 Exam { } = ln { } = Solution 5. L e at f (t) + a. Therefore, L te at f (t) d d ln + a = + a ( + a) =. Anwer (4) + a 6. An integro-differential equation for a linear 0 circuit i given by t 4 v C (τ )dτ 0 + d dt v C (t) + 4v C (t) = u(t) Suppoe v C (0 ) = 0 and!v C (0 ) = V/. Then v C (t) ha a term of the form Kte at u(t) where (K,a) = : () (,) () (,) (3) (4,) (4) ( 4,) (5) (,) (6) (,) (7) (,) (8) (,) (9) None of above Solution 6. The above equation implie that v!! C (t) + 4!v C (t) + 4v C (t) = δ (t). In the -world V C () v C (0 )!v C (0 ) + 4V C () v C (0 ) + 4V C () =. If v C (0 ) = 0, then ( )V C () = +!v C (0 ) implie V C () = +!v C (0 ) v C (t) = ( +!v C (0 ))te t u(t) V. Anwer: (3) = +!v C (0 ) ( + ) which implie that 7. A circuit characterizing the decay of the ordinary attention pan of a tudent in a DeCarlo circuit cla i H()= a term of the form Ae t u(t) where A = : 0. The tep repone of the aociated tranfer function ha ( +)( +3) () 0 () 5 (3) 5 (4) 0 (5) 5 (6) 4 (7) 5 (8) 4 (9) None of above
7 ECE-0 Spring 08 7 Exam Solution 7. (Tranfer function, tep repone, partial fraction expanion ditinct pole, invere tranform) L[StepRepone]= H() 0 = ( +)( +3) = StepRepone = 5e t +5e 3t u(t). ANSWER: (7). 8. In the circuit below, R = 0.5 Ω, g m =, and C = 0.5 F. The Thevenin equivalent open circuit voltage at the output terminal A-B i: V () in () V in V (3) in (4) V in 4V (5) in (6) 4V in 8V (7) in (8) 8V in (9) none of above Solution 8. V out = R V out V in I in + C + G g m + CV out g m V out = I in implie (C + G g m )V out = I in + GV in. Thu G C + G g m V in = I in V in. Concluion: Z th = and V oc = V in. ANSWER: (7) 9. Referring again to problem 8, the Thevenin Equivalent impedance een at the A-B terminal i: 4 () () (3) (4) (5) (6) (7) (8) (9) none of above Anwer: (6)
8 ECE-0 Spring 08 8 Exam 0. In the circuit below, R = Ω, C = 0.5 F, and v in (t) = 4δ (t) V and v C (0 ) = 8 V. Then v C (t) ha a term of the form Ke at u(t) where (K,a) = : () (,4) () (6,) (3) (4,4) (4) (4,) (5) (,4) (6) (8, 4) (7) ( 8,4) (8) (8,4) (9) None of above Solution 0. Initial capacitor model, complete repone, impedance, voltage diviion. Uing the current ource model of the capacitor we have that 4 4 V C () = + 4 V in () + Cv C (0 ) + 4 = V in () + v C (0 ) + 4. Hence, if v in (t) = Kδ (t) V C () = 4K + v C (0 ) ( + 4) ANSWER: (8) = and v C (t) = 8e 4t u(t) V.. In the circuit below, I in () = 0, L = 0.5 H, Z() = Y() = , and i L (0 ) = A. Then i L (t) ha a term of the form K co(ω t)u(t) where (K,ω ) = : () (,3) () (,9) (3) (,9) (4) (,3)
9 ECE-0 Spring 08 9 Exam (5) ( 6,3) (6) (6,9) (7) (6,3) (8) ( 6,9) (9) None of above Solution. ( Z() + 0.5) = + 9 = + 9, i.e., I L () = Li L (0 ) Z() = i L (t) = 6co(3t)u(t). Anwer: (5). In the circuit below, I in () =, i L (0 ) = 0, L = 0.5 H and Y() = Then v L (t) ha a term of the form Ke at in(ω t)u(t) where (K,a,ω ) = : () (3,,4) () (,,) (3) (3,,) (4) (4,,) (5) (4,,4) (6) (6,,) (7) (8,,) (8) (8,,4) (9) None of above Solution. Here, Y eq () = Y() + = = Z eq () = ( + ) +. Uing the voltage ource model, V L () = Z eq ()I in () = ( + ) + = 6 ( + ) +. Hence v L (t) = 6e t in(t)u(t) A.
10 ECE-0 Spring 08 0 Exam Anwer: (6)
11 ECE-0 Spring 08 Exam Workout Problem: (40 point) Part. (a) (6 pt) Compute the tranfer function H () = V out () V in () of the circuit below in term of the literal G = R, G, C, and. Your final reult hould be of the form: H() = K ( +??)( +??). (b) (4 pt) Compute the value of G = R, G, C, and, o that H () = under the contraint that = F. ( +)( + 4) Part ( pt). (a) (8 pt) Compute the tranfer function H () = V out () V in () in term of the literal G, C, and. Your final reult hould be of the form: H() = K +? +????. of the circuit below (b) (4 pt) Compute the value of G, C, and o that H () = 4 + under the contraint ( + 4) that G = mho.
12 ECE-0 Spring 08 Exam Part 3. (8 pt) The output of the circuit of Part replace the voltage ource of the circuit of Part and thu drive the circuit of part without any loading effect. Thi i called a cacade connection. (a) What i the new tranfer function, H new (), of the cacaded circuit? (b) Compute the tep repone of the new circuit. (c) Compute the impule repone of the new circuit. Solution Part, (a) and (b): (0 pt) (a) (6 pt) H() = V out () V in () = Y in () Y f () = = G = R + G + G C C R + C = + G C ( R C +) + G + G + G (Thi i the correct form that wa required.)
13 ECE-0 Spring 08 3 Exam (b) (4 pt) H() = G + G + G C G = + G + G C = ( +)( + 4). Cae : G = R = mho, G = 4 mho, C = F, and = F. Cae : However, you could alo have et + G = + o that G = mho. Then C = 4 and C = 0.5 F. Solution Part, (a) and (b): ( pt) (a) (8 pt) C V in = ( + G)(V out V in ) ((C + ) + G)V in = ( + G)V out. Hence, H() = (C + ) + G + G = (C + ) + G (C + ) + G. (Thi i the correct form that wa required.) (b) (4 pt) H() = (C + ) G + (C + ) ( +) + G = 4 ( + 4). Thu C + = 4 C = 3 in which cae G = G = and G = 4. Set G = mho. Then, C C + 4 C = 0.75 F and = 0.5 F. Solution part 3 (8 pt): (a) (4 pt) H new () = H ()H () = 8. (All or nothing.) ( + 4) 8 (b) (4 pt) Step Repone i the invere tranform of ( + 4) which i Step-Rep = 8te 4t u(t) V. (c) (0 pt) Impule Repone i the invere tranform of H new (). H new () = 8 ( + 4) = A B ( + 4) = Impule Repone ( + 4) = 8e 4t u(t) + 3te 4t u(t). = 8e 4t u(t) + 3te 4t u(t). You could alo have ued the relationhip: Derivative(tep repone) = impule repone, provided you accounted for the derivative of the tep function properly and explained what you did.
14 ECE-0 Spring 08 4 Exam (3 pt for B, 4 pt for A, and 3 pt for the correct invere. - for ign error. If the tudent make up a repone with no partial fraction expanion, the grade i zero.)
ECE-202 FINAL December 13, 2016 CIRCLE YOUR DIVISION
ECE-202 Final, Fall 16 1 ECE-202 FINAL December 13, 2016 Name: (Pleae print clearly.) Student Email: CIRCLE YOUR DIVISION DeCarlo- 8:30-9:30 Talavage-9:30-10:30 2021 2022 INSTRUCTIONS There are 35 multiple
More informationECE-202 FINAL April 30, 2018 CIRCLE YOUR DIVISION
ECE 202 Final, Spring 8 ECE-202 FINAL April 30, 208 Name: (Please print clearly.) Student Email: CIRCLE YOUR DIVISION DeCarlo- 7:30-8:30 DeCarlo-:30-2:45 2025 202 INSTRUCTIONS There are 34 multiple choice
More informationECE Linear Circuit Analysis II
ECE 202 - Linear Circuit Analyi II Final Exam Solution December 9, 2008 Solution Breaking F into partial fraction, F 2 9 9 + + 35 9 ft δt + [ + 35e 9t ]ut A 9 Hence 3 i the correct anwer. Solution 2 ft
More informationEE-202 Exam III April 13, 2006
EE-202 Exam III April 13, 2006 Name: (Please print clearly) Student ID: CIRCLE YOUR DIVISION DeCarlo 2:30 MWF Furgason 3:30 MWF INSTRUCTIONS There are 10 multiple choice worth 5 points each and there is
More informationEE-202 Exam II March 3, 2008
EE-202 Exam II March 3, 2008 Name: (Please print clearly) Student ID: CIRCLE YOUR DIVISION MORNING 8:30 MWF AFTERNOON 12:30 MWF INSTRUCTIONS There are 12 multiple choice worth 5 points each and there is
More informationLecture 4 : Transform Properties and Interpretations. Continued to the Next (Higher) Level. 1. Example 1. Demo of the mult-by-t property.
Lecture 4 : Tranform Propertie and Interpretation Continued to the Next (Higher) Level 1. Example 1. Demo of the mult-by-t property. (i) Conider above graph of f (t) and g(t) = tf (t). Set K = 1. (ii)
More informationMidterm Test Nov 10, 2010 Student Number:
Mathematic 265 Section: 03 Verion A Full Name: Midterm Tet Nov 0, 200 Student Number: Intruction: There are 6 page in thi tet (including thi cover page).. Caution: There may (or may not) be more than one
More informationEE-202 Exam III April 10, 2008
EE-202 Exam III April 10, 2008 Name: (Please print clearly) Student ID: CIRCLE YOUR DIVISION Morning 8:30 MWF Afternoon 12:30 MWF INSTRUCTIONS There are 13 multiple choice worth 5 points each and there
More informationEE-202 Exam III April 13, 2015
EE-202 Exam III April 3, 205 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo-7:30-8:30 Furgason 3:30-4:30 DeCarlo-:30-2:30 202 2022 2023 INSTRUCTIONS There are 2 multiple choice
More informationMAE140 Linear Circuits Fall 2012 Final, December 13th
MAE40 Linear Circuit Fall 202 Final, December 3th Intruction. Thi exam i open book. You may ue whatever written material you chooe, including your cla note and textbook. You may ue a hand calculator with
More informationQuestion 1 Equivalent Circuits
MAE 40 inear ircuit Fall 2007 Final Intruction ) Thi exam i open book You may ue whatever written material you chooe, including your cla note and textbook You may ue a hand calculator with no communication
More informationIntroduction to Laplace Transform Techniques in Circuit Analysis
Unit 6 Introduction to Laplace Tranform Technique in Circuit Analyi In thi unit we conider the application of Laplace Tranform to circuit analyi. A relevant dicuion of the one-ided Laplace tranform i found
More information1. /25 2. /30 3. /25 4. /20 Total /100
Circuit Exam 2 Spring 206. /25 2. /30 3. /25 4. /20 Total /00 Name Pleae write your name at the top of every page! Note: ) If you are tuck on one part of the problem, chooe reaonable value on the following
More informationME 375 FINAL EXAM Wednesday, May 6, 2009
ME 375 FINAL EXAM Wedneday, May 6, 9 Diviion Meckl :3 / Adam :3 (circle one) Name_ Intruction () Thi i a cloed book examination, but you are allowed three ingle-ided 8.5 crib heet. A calculator i NOT allowed.
More informationEE-202 Exam III April 6, 2017
EE-202 Exam III April 6, 207 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo--202 DeCarlo--2022 7:30 MWF :30 T-TH INSTRUCTIONS There are 3 multiple choice worth 5 points each and
More informationEE-202 Exam III April 15, 2010
EE-0 Exam III April 5, 00 Name: SOLUTION (No period) (Please print clearly) Student ID: CIRCLE YOUR DIVISION Morning 8:30 MWF Afternoon 3:30 MWF INSTRUCTIONS There are 9 multiple choice worth 5 points
More informationME 375 EXAM #1 Tuesday February 21, 2006
ME 375 EXAM #1 Tueday February 1, 006 Diviion Adam 11:30 / Savran :30 (circle one) Name Intruction (1) Thi i a cloed book examination, but you are allowed one 8.5x11 crib heet. () You have one hour to
More informationName: (Please print clearly) Student ID: CIRCLE YOUR DIVISION INSTRUCTIONS
EE 202 Exam III April 13 2011 Name: (Please print clearly) Student ID: CIRCLE YOUR DIVISION Morning 7:30 MWF Furgason INSTRUCTIONS Afternoon 3:30 MWF DeCarlo There are 10 multiple choice worth 5 points
More informationSIMON FRASER UNIVERSITY School of Engineering Science ENSC 320 Electric Circuits II. R 4 := 100 kohm
SIMON FRASER UNIVERSITY School of Engineering Science ENSC 320 Electric Circuit II Solution to Aignment 3 February 2003. Cacaded Op Amp [DC&L, problem 4.29] An ideal op amp ha an output impedance of zero,
More informationMain Topics: The Past, H(s): Poles, zeros, s-plane, and stability; Decomposition of the complete response.
EE202 HOMEWORK PROBLEMS SPRING 18 TO THE STUDENT: ALWAYS CHECK THE ERRATA on the web. Quote for your Parent' Partie: 1. Only with nodal analyi i the ret of the emeter a poibility. Ray DeCarlo 2. (The need
More informationSIMON FRASER UNIVERSITY School of Engineering Science ENSC 320 Electric Circuits II. Solutions to Assignment 3 February 2005.
SIMON FRASER UNIVERSITY School of Engineering Science ENSC 320 Electric Circuit II Solution to Aignment 3 February 2005. Initial Condition Source 0 V battery witch flip at t 0 find i 3 (t) Component value:
More informationECE-320 Linear Control Systems. Spring 2014, Exam 1. No calculators or computers allowed, you may leave your answers as fractions.
ECE-0 Linear Control Sytem Spring 04, Exam No calculator or computer allowed, you may leave your anwer a fraction. All problem are worth point unle noted otherwie. Total /00 Problem - refer to the unit
More informationProperties of Z-transform Transform 1 Linearity a
Midterm 3 (Fall 6 of EEG:. Thi midterm conit of eight ingle-ided page. The firt three page contain variou table followed by FOUR eam quetion and one etra workheet. You can tear out any page but make ure
More informationMA 266 FINAL EXAM INSTRUCTIONS May 2, 2005
MA 66 FINAL EXAM INSTRUCTIONS May, 5 NAME INSTRUCTOR. You mut ue a # pencil on the mark ene heet anwer heet.. If the cover of your quetion booklet i GREEN, write in the TEST/QUIZ NUMBER boxe and blacken
More informationGiven the following circuit with unknown initial capacitor voltage v(0): X(s) Immediately, we know that the transfer function H(s) is
EE 4G Note: Chapter 6 Intructor: Cheung More about ZSR and ZIR. Finding unknown initial condition: Given the following circuit with unknown initial capacitor voltage v0: F v0/ / Input xt 0Ω Output yt -
More informationinto a discrete time function. Recall that the table of Laplace/z-transforms is constructed by (i) selecting to get
Lecture 25 Introduction to Some Matlab c2d Code in Relation to Sampled Sytem here are many way to convert a continuou time function, { h( t) ; t [0, )} into a dicrete time function { h ( k) ; k {0,,, }}
More informationEXAM 4 -A2 MATH 261: Elementary Differential Equations MATH 261 FALL 2010 EXAMINATION COVER PAGE Professor Moseley
EXAM 4 -A MATH 6: Elementary Differential Equation MATH 6 FALL 00 EXAMINATION COVER PAGE Profeor Moeley PRINT NAME ( ) Lat Name, Firt Name MI (What you wih to be called) ID # EXAM DATE Friday, Nov. 9,
More informationME 375 FINAL EXAM SOLUTIONS Friday December 17, 2004
ME 375 FINAL EXAM SOLUTIONS Friday December 7, 004 Diviion Adam 0:30 / Yao :30 (circle one) Name Intruction () Thi i a cloed book eamination, but you are allowed three 8.5 crib heet. () You have two hour
More informationEXAM 4 -B2 MATH 261: Elementary Differential Equations MATH 261 FALL 2012 EXAMINATION COVER PAGE Professor Moseley
EXAM 4 -B MATH 6: Elementary Differential Equation MATH 6 FALL 0 EXAMINATION COVER PAGE Profeor Moeley PRINT NAME ( ) Lat Name, Firt Name MI (What you wih to be called) ID # EXAM DATE Friday, Nov. 9, 0
More informationR. W. Erickson. Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder
R. W. Erickon Department of Electrical, Computer, and Energy Engineering Univerity of Colorado, Boulder Cloed-loop buck converter example: Section 9.5.4 In ECEN 5797, we ued the CCM mall ignal model to
More informationName: Solutions Exam 2
Intruction. Anwer each of the quetion on your own paper. Put your name on each page of your paper. Be ure to how your work o that partial credit can be adequately aeed. Credit will not be given for anwer
More informationECE382/ME482 Spring 2004 Homework 4 Solution November 14,
ECE382/ME482 Spring 2004 Homework 4 Solution November 14, 2005 1 Solution to HW4 AP4.3 Intead of a contant or tep reference input, we are given, in thi problem, a more complicated reference path, r(t)
More informationDigital Control System
Digital Control Sytem Summary # he -tranform play an important role in digital control and dicrete ignal proceing. he -tranform i defined a F () f(k) k () A. Example Conider the following equence: f(k)
More informationEE C128 / ME C134 Problem Set 1 Solution (Fall 2010) Wenjie Chen and Jansen Sheng, UC Berkeley
EE C28 / ME C34 Problem Set Solution (Fall 200) Wenjie Chen and Janen Sheng, UC Berkeley. (0 pt) BIBO tability The ytem h(t) = co(t)u(t) i not BIBO table. What i the region of convergence for H()? A bounded
More information7.2 INVERSE TRANSFORMS AND TRANSFORMS OF DERIVATIVES 281
72 INVERSE TRANSFORMS AND TRANSFORMS OF DERIVATIVES 28 and i 2 Show how Euler formula (page 33) can then be ued to deduce the reult a ( a) 2 b 2 {e at co bt} {e at in bt} b ( a) 2 b 2 5 Under what condition
More informationName: Solutions Exam 3
Intruction. Anwer each of the quetion on your own paper. Put your name on each page of your paper. Be ure to how your work o that partial credit can be adequately aeed. Credit will not be given for anwer
More informationLecture 6: Resonance II. Announcements
EES 5 Spring 4, Lecture 6 Lecture 6: Reonance II EES 5 Spring 4, Lecture 6 Announcement The lab tart thi week You mut how up for lab to tay enrolled in the coure. The firt lab i available on the web ite,
More information8. [12 Points] Find a particular solution of the differential equation. t 2 y + ty 4y = t 3, y h = c 1 t 2 + c 2 t 2.
Intruction. Anwer each of the quetion on your own paper. Put your name on each page of your paper. Be ure to how your work o that partial credit can be adequately aeed. Credit will not be given for anwer
More informationTMA4125 Matematikk 4N Spring 2016
Norwegian Univerity of Science and Technology Department of Mathematical Science TMA45 Matematikk 4N Spring 6 Solution to problem et 6 In general, unle ele i noted, if f i a function, then F = L(f denote
More informationonline learning Unit Workbook 4 RLC Transients
online learning Pearon BTC Higher National in lectrical and lectronic ngineering (QCF) Unit 5: lectrical & lectronic Principle Unit Workbook 4 in a erie of 4 for thi unit Learning Outcome: RLC Tranient
More informationRoot Locus Diagram. Root loci: The portion of root locus when k assume positive values: that is 0
Objective Root Locu Diagram Upon completion of thi chapter you will be able to: Plot the Root Locu for a given Tranfer Function by varying gain of the ytem, Analye the tability of the ytem from the root
More informationSolutions. Digital Control Systems ( ) 120 minutes examination time + 15 minutes reading time at the beginning of the exam
BSc - Sample Examination Digital Control Sytem (5-588-) Prof. L. Guzzella Solution Exam Duration: Number of Quetion: Rating: Permitted aid: minute examination time + 5 minute reading time at the beginning
More informationName: Solutions Exam 2
Name: Solution Exam Intruction. Anwer each of the quetion on your own paper. Put your name on each page of your paper. Be ure to how your work o that partial credit can be adequately aeed. Credit will
More information18.03SC Final Exam = x 2 y ( ) + x This problem concerns the differential equation. dy 2
803SC Final Exam Thi problem concern the differential equation dy = x y ( ) dx Let y = f (x) be the olution with f ( ) = 0 (a) Sketch the iocline for lope, 0, and, and ketch the direction field along them
More informationLecture 28. Passive HP Filter Design
Lecture 28. Paive HP Filter Deign STRATEGY: Convert HP pec to Equivalent NLP pec. Deign an appropriate 3dB NLP tranfer function. Realize the 3dB NLP tranfer function a a circuit. Convert the 3dB NLP circuit
More informationS.E. Sem. III [EXTC] Circuits and Transmission Lines
S.E. Sem. III [EXTC] Circuit and Tranmiion Line Time : Hr.] Prelim Quetion Paper Solution [Mark : 80 Q.(a) Tet whether P() = 5 4 45 60 44 48 i Hurwitz polynomial. (A) P() = 5 4 45 60 44 48 5 45 44 4 60
More informationSolving Differential Equations by the Laplace Transform and by Numerical Methods
36CH_PHCalter_TechMath_95099 3//007 :8 PM Page Solving Differential Equation by the Laplace Tranform and by Numerical Method OBJECTIVES When you have completed thi chapter, you hould be able to: Find the
More informationSOLUTIONS FOR HOMEWORK SECTION 6.4 AND 6.5
SOLUTIONS FOR HOMEWORK SECTION 6.4 AND 6.5 Problem : For each of the following function do the following: (i) Write the function a a piecewie function and ketch it graph, (ii) Write the function a a combination
More informationChapter 2 Sampling and Quantization. In order to investigate sampling and quantization, the difference between analog
Chapter Sampling and Quantization.1 Analog and Digital Signal In order to invetigate ampling and quantization, the difference between analog and digital ignal mut be undertood. Analog ignal conit of continuou
More informationNOTE: The items d) and e) of Question 4 gave you bonus marks.
MAE 40 Linear ircuit Summer 2007 Final Solution NOTE: The item d) and e) of Quetion 4 gave you bonu mark. Quetion [Equivalent irciut] [4 mark] Find the equivalent impedance between terminal A and B in
More information5.1 Introduction. 5.2 Definition of Laplace transorm
5.1 Introduction In thi chapter, we will introduce Laplace tranform. Thi i an extremely important technique. For a given et of initial condition, it will give the total repone of the circuit compriing
More informationEE/ME/AE324: Dynamical Systems. Chapter 8: Transfer Function Analysis
EE/ME/AE34: Dynamical Sytem Chapter 8: Tranfer Function Analyi The Sytem Tranfer Function Conider the ytem decribed by the nth-order I/O eqn.: ( n) ( n 1) ( m) y + a y + + a y = b u + + bu n 1 0 m 0 Taking
More informationThe Laplace Transform , Haynes Miller and Jeremy Orloff
The Laplace Tranform 8.3, Hayne Miller and Jeremy Orloff Laplace tranform baic: introduction An operator take a function a input and output another function. A tranform doe the ame thing with the added
More informationSampling and the Discrete Fourier Transform
Sampling and the Dicrete Fourier Tranform Sampling Method Sampling i mot commonly done with two device, the ample-and-hold (S/H) and the analog-to-digital-converter (ADC) The S/H acquire a CT ignal at
More information55:041 Electronic Circuits
55:04 Electronic ircuit Frequency epone hapter 7 A. Kruger Frequency epone- ee page 4-5 of the Prologue in the text Important eview co Thi lead to the concept of phaor we encountered in ircuit In Linear
More information( ) ( ) ω = X x t e dt
The Laplace Tranform The Laplace Tranform generalize the Fourier Traform for the entire complex plane For an ignal x(t) the pectrum, or it Fourier tranform i (if it exit): t X x t e dt ω = For the ame
More informationEECS2200 Electric Circuits. RLC Circuit Natural and Step Responses
5--4 EECS Electric Circuit Chapter 6 R Circuit Natural and Step Repone Objective Determine the repone form of the circuit Natural repone parallel R circuit Natural repone erie R circuit Step repone of
More informationR L R L L sl C L 1 sc
2260 N. Cotter PRACTICE FINAL EXAM SOLUTION: Prob 3 3. (50 point) u(t) V i(t) L - R v(t) C - The initial energy tored in the circuit i zero. 500 Ω L 200 mh a. Chooe value of R and C to accomplih the following:
More informationChapter 5 Consistency, Zero Stability, and the Dahlquist Equivalence Theorem
Chapter 5 Conitency, Zero Stability, and the Dahlquit Equivalence Theorem In Chapter 2 we dicued convergence of numerical method and gave an experimental method for finding the rate of convergence (aka,
More informationLaplace Transformation
Univerity of Technology Electromechanical Department Energy Branch Advance Mathematic Laplace Tranformation nd Cla Lecture 6 Page of 7 Laplace Tranformation Definition Suppoe that f(t) i a piecewie continuou
More informationMathematical modeling of control systems. Laith Batarseh. Mathematical modeling of control systems
Chapter two Laith Batareh Mathematical modeling The dynamic of many ytem, whether they are mechanical, electrical, thermal, economic, biological, and o on, may be decribed in term of differential equation
More informationECE : Linear Circuit Analysis II
Purdue University School of Electrical and Computer Engineering ECE 20200 : Linear Circuit Analysis II Summer 2014 Instructor: Aung Kyi San Instructions: Midterm Examination I July 2, 2014 1. Wait for
More informationCONTROL SYSTEMS. Chapter 2 : Block Diagram & Signal Flow Graphs GATE Objective & Numerical Type Questions
ONTOL SYSTEMS hapter : Bloc Diagram & Signal Flow Graph GATE Objective & Numerical Type Quetion Quetion 6 [Practice Boo] [GATE E 994 IIT-Kharagpur : 5 Mar] educe the ignal flow graph hown in figure below,
More informationControl Systems Engineering ( Chapter 7. Steady-State Errors ) Prof. Kwang-Chun Ho Tel: Fax:
Control Sytem Engineering ( Chapter 7. Steady-State Error Prof. Kwang-Chun Ho kwangho@hanung.ac.kr Tel: 0-760-453 Fax:0-760-4435 Introduction In thi leon, you will learn the following : How to find the
More informationECE 202 Fall 2013 Final Exam
ECE 202 Fall 2013 Final Exam December 12, 2013 Circle your division: Division 0101: Furgason (8:30 am) Division 0201: Bermel (9:30 am) Name (Last, First) Purdue ID # There are 18 multiple choice problems
More informationFunction and Impulse Response
Tranfer Function and Impule Repone Solution of Selected Unolved Example. Tranfer Function Q.8 Solution : The -domain network i hown in the Fig... Applying VL to the two loop, R R R I () I () L I () L V()
More informationLinear System Fundamentals
Linear Sytem Fundamental MEM 355 Performance Enhancement of Dynamical Sytem Harry G. Kwatny Department of Mechanical Engineering & Mechanic Drexel Univerity Content Sytem Repreentation Stability Concept
More informationLTV System Modelling
Helinki Univerit of Technolog S-72.333 Potgraduate Coure in Radiocommunication Fall 2000 LTV Stem Modelling Heikki Lorentz Sonera Entrum O heikki.lorentz@onera.fi Januar 23 rd 200 Content. Introduction
More informationSection Induction motor drives
Section 5.1 - nduction motor drive Electric Drive Sytem 5.1.1. ntroduction he AC induction motor i by far the mot widely ued motor in the indutry. raditionally, it ha been ued in contant and lowly variable-peed
More informationDelhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:
Serial : LS_N_A_Network Theory_098 Delhi Noida Bhopal Hyderabad Jaipur Lucknow ndore Pune Bhubanewar Kolkata Patna Web: E-mail: info@madeeay.in Ph: 0-4546 CLASS TEST 08-9 NSTRUMENTATON ENGNEERNG Subject
More informationDelhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:
Serial :. PT_EE_A+C_Control Sytem_798 Delhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubanewar olkata Patna Web: E-mail: info@madeeay.in Ph: -4546 CLASS TEST 8-9 ELECTRICAL ENGINEERING Subject
More information6.447 rad/sec and ln (% OS /100) tan Thus pc. the testing point is s 3.33 j5.519
9. a. 3.33, n T ln(% OS /100) 2 2 ln (% OS /100) 0.517. Thu n 6.7 rad/ec and the teting point i 3.33 j5.519. b. Summation of angle including the compenating zero i -106.691, The compenator pole mut contribute
More informationHomework #7 Solution. Solutions: ΔP L Δω. Fig. 1
Homework #7 Solution Aignment:. through.6 Bergen & Vittal. M Solution: Modified Equation.6 becaue gen. peed not fed back * M (.0rad / MW ec)(00mw) rad /ec peed ( ) (60) 9.55r. p. m. 3600 ( 9.55) 3590.45r.
More informationDigital Control System
Digital Control Sytem - A D D A Micro ADC DAC Proceor Correction Element Proce Clock Meaurement A: Analog D: Digital Continuou Controller and Digital Control Rt - c Plant yt Continuou Controller Digital
More informationLecture 10 Filtering: Applied Concepts
Lecture Filtering: Applied Concept In the previou two lecture, you have learned about finite-impule-repone (FIR) and infinite-impule-repone (IIR) filter. In thee lecture, we introduced the concept of filtering
More informationChapter 4. The Laplace Transform Method
Chapter 4. The Laplace Tranform Method The Laplace Tranform i a tranformation, meaning that it change a function into a new function. Actually, it i a linear tranformation, becaue it convert a linear combination
More information( 1) EE 313 Linear Signals & Systems (Fall 2018) Solution Set for Homework #10 on Laplace Transforms
EE 33 Linear Signal & Sytem (Fall 08) Solution Set for Homework #0 on Laplace Tranform By: Mr. Houhang Salimian & Prof. Brian L. Evan Problem. a) xt () = ut () ut ( ) From lecture Lut { ()} = and { } t
More informationCHE302 LECTURE V LAPLACE TRANSFORM AND TRANSFER FUNCTION. Professor Dae Ryook Yang
CHE3 ECTURE V APACE TRANSFORM AND TRANSFER FUNCTION Profeor Dae Ryook Yang Fall Dept. of Chemical and Biological Engineering Korea Univerity CHE3 Proce Dynamic and Control Korea Univerity 5- SOUTION OF
More informationProblem Weight Score Total 100
EE 350 EXAM IV 15 December 2010 Last Name (Print): First Name (Print): ID number (Last 4 digits): Section: DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO Problem Weight Score 1 25 2 25 3 25 4 25 Total
More informationWolfgang Hofle. CERN CAS Darmstadt, October W. Hofle feedback systems
Wolfgang Hofle Wolfgang.Hofle@cern.ch CERN CAS Darmtadt, October 9 Feedback i a mechanim that influence a ytem by looping back an output to the input a concept which i found in abundance in nature and
More information6.302 Feedback Systems Recitation 6: Steady-State Errors Prof. Joel L. Dawson S -
6302 Feedback ytem Recitation 6: teadytate Error Prof Joel L Dawon A valid performance metric for any control ytem center around the final error when the ytem reache teadytate That i, after all initial
More informationEE 4343/ Control System Design Project
Copyright F.L. Lewi 2004 All right reerved EE 4343/5320 - Control Sytem Deign Project Updated: Sunday, February 08, 2004 Background: Analyi of Linear ytem, MATLAB Review of Baic Concept LTI Sytem LT I
More informationSpring 2014 EE 445S Real-Time Digital Signal Processing Laboratory. Homework #0 Solutions on Review of Signals and Systems Material
Spring 4 EE 445S Real-Time Digital Signal Proceing Laboratory Prof. Evan Homework # Solution on Review of Signal and Sytem Material Problem.. Continuou-Time Sinuoidal Generation. In practice, we cannot
More informationApproximate Analytical Solution for Quadratic Riccati Differential Equation
Iranian J. of Numerical Analyi and Optimization Vol 3, No. 2, 2013), pp 21-31 Approximate Analytical Solution for Quadratic Riccati Differential Equation H. Aminikhah Abtract In thi paper, we introduce
More informationÇankaya University ECE Department ECE 376 (MT)
Çankaya Univerity ECE Department ECE 376 (M) Student Name : Date : 13.4.15 Student Number : Open Source Exam Quetion 1. (7 Point) he time waveform of the ignal et, and t t are given in Fig. 1.1. a. Identify
More informationModeling in the Frequency Domain
T W O Modeling in the Frequency Domain SOLUTIONS TO CASE STUDIES CHALLENGES Antenna Control: Tranfer Function Finding each tranfer function: Pot: V i θ i 0 π ; Pre-Amp: V p V i K; Power Amp: E a V p 50
More informationThe state variable description of an LTI system is given by 3 1O. Statement for Linked Answer Questions 3 and 4 :
CHAPTER 6 CONTROL SYSTEMS YEAR TO MARKS MCQ 6. The tate variable decription of an LTI ytem i given by Jxo N J a NJx N JN K O K OK O K O xo a x + u Kxo O K 3 a3 OKx O K 3 O L P L J PL P L P x N K O y _
More informationThe Laplace Transform
The Laplace Tranform Prof. Siripong Potiuk Pierre Simon De Laplace 749-827 French Atronomer and Mathematician Laplace Tranform An extenion of the CT Fourier tranform to allow analyi of broader cla of CT
More informationBASIC INDUCTION MOTOR CONCEPTS
INDUCTION MOTOS An induction motor ha the ame phyical tator a a ynchronou machine, with a different rotor contruction. There are two different type of induction motor rotor which can be placed inide the
More informationWhat lies between Δx E, which represents the steam valve, and ΔP M, which is the mechanical power into the synchronous machine?
A 2.0 Introduction In the lat et of note, we developed a model of the peed governing mechanim, which i given below: xˆ K ( Pˆ ˆ) E () In thee note, we want to extend thi model o that it relate the actual
More informationElectrical Circuits II (ECE233b)
Electrcal Crcut II (ECE33b) Applcaton of Laplace Tranform to Crcut Analy Anet Dounav The Unverty of Wetern Ontaro Faculty of Engneerng Scence Crcut Element Retance Tme Doman (t) v(t) R v(t) = R(t) Frequency
More informationCSE 355 Homework Two Solutions
CSE 355 Homework Two Solution Due 2 Octoer 23, tart o cla Pleae note that there i more than one way to anwer mot o thee quetion. The ollowing only repreent a ample olution. () Let M e the DFA with tranition
More informationDelhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:
Serial : LS_B_EC_Network Theory_0098 CLASS TEST (GATE) Delhi Noida Bhopal Hyderabad Jaipur Lucknow ndore Pune Bhubanewar Kolkata Patna Web: E-mail: info@madeeay.in Ph: 0-4546 CLASS TEST 08-9 ELECTRONCS
More informationWhat is automatic control all about? Welcome to Automatic Control III!! "Automatic control is the art of getting things to behave as you want.
What i automatic control all about? Welcome to Automatic Control III!! Lecture Introduction and linear ytem theory Thoma Schön Diviion of Sytem and Control Department of Information Technology Uppala Univerity.
More informationGEORGIA INSTITUTE OF TECHNOLOGY SCHOOL of ELECTRICAL & COMPUTER ENGINEERING FINAL EXAM. COURSE: ECE 3084A (Prof. Michaels)
GEORGIA INSTITUTE OF TECHNOLOGY SCHOOL of ELECTRICAL & COMPUTER ENGINEERING FINAL EXAM DATE: 30-Apr-14 COURSE: ECE 3084A (Prof. Michaels) NAME: STUDENT #: LAST, FIRST Write your name on the front page
More informationMassachusetts Institute of Technology Dynamics and Control II
I E Maachuett Intitute of Technology Department of Mechanical Engineering 2.004 Dynamic and Control II Laboratory Seion 5: Elimination of Steady-State Error Uing Integral Control Action 1 Laboratory Objective:
More informationR. W. Erickson. Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder
R. W. Erickon Department of Electrical, Computer, and Energy Engineering Univerity of Colorado, Boulder ZOH: Sampled Data Sytem Example v T Sampler v* H Zero-order hold H v o e = 1 T 1 v *( ) = v( jkω
More informationtime? How will changes in vertical drop of the course affect race time? How will changes in the distance between turns affect race time?
Unit 1 Leon 1 Invetigation 1 Think About Thi Situation Name: Conider variou port that involve downhill racing. Think about the factor that decreae or increae the time it take to travel from top to bottom.
More informationPractice Problems - Week #7 Laplace - Step Functions, DE Solutions Solutions
For Quetion -6, rewrite the piecewie function uing tep function, ketch their graph, and find F () = Lf(t). 0 0 < t < 2. f(t) = (t 2 4) 2 < t In tep-function form, f(t) = u 2 (t 2 4) The graph i the olid
More informationMATHEMATICAL MODELS OF PHYSICAL SYSTEMS
hapter MATHEMATIAL MODELS OF PHYSIAL SYSTEMS.. INTODUTION For the analyi and deign of control ytem, we need to formulate a mathematical decription of the ytem. The proce of obtaining the deired mathematical
More information