COMPILATION OF AUTOMATA FROM MORPHOLOGICAL TWO-LEVEL RULES
|
|
- Brianne Holland
- 5 years ago
- Views:
Transcription
1 Kimmo Koskenniemi Re se ar ch Unit for Co mp ut at io na l Li ng ui st ic s University of Helsinki, Hallituskatu 11 SF Helsinki, Finland COMPILATION OF AUTOMATA FROM MORPHOLOGICAL TWO-LEVEL RULES 1. INTRODUCTION T h e t w o - l e v e l m o d e l is a f r a m e w o r k for d e s c r i b i n g word inflection. The mo de l co ns is ts of a l e xicon system and a f o r m a l i s m for t w o - l e v e l rules. The l e xicon system defines all p o s s i b l e l e x i c a l r e p r e s e n t a t i o n s of w o r d - f o r m s w h e r e a s the r u l e s e x p r e s s the p e r m i t t e d r e l a t i o n s b e t w e e n l e x i c a l and surface representations. Word recognition is thus reduced into the question of finding a p e r m i s s i b l e le xi ca l repr es en ta ti on which is in a proper rela t i o n to the surface form. Similarly, ge ne ra ti on is the inverse where the l e xical representation is k n o w n and the ta s k is to f i nd a s u r f a c e r e p r e s e n t a t i o n w h i c h is in a proper relation to it. W i t h i n the t w o - l e v e l mo de l these r e lations pertaining to the r u l e c o m p o n e n t h a v e b e e n e x p r e s s e d in two ways. A r u l e f o r m a l i s m ha s b e e n us e d for c o m m u n i c a t i n g the idea of the r u l e s, w h e r e a s t h e a c t u a l i m p l e m e n t a t i o n s h a v e b e e n a c c o m p l i s h e d by h a n d - c o d i n g t h e r u l e s as f i n i t e s t a t e automata. The c l o s e c o nnection be tw ee n rules and finite state mach in es has fa ci li ta te d this hand-coding. Expressing rules as numbers in a transition matr ix is, of course, not optimal. A l t h o u g h it has p r o v e n to be feasible, it is tedious. It al s o tends to dist r a c t the linguist's thoughts f r o m m o r p h o p h o n o l o g i c a 1 v a r i a t i o n s to t e c h n i c a l m a t t e r s. F u r t h e r m o r e, h a n d c o m p i l e d a u t o m a t a are o f t e n no t q u i t e c o n s i s t e n t w i t h i n t e n d e d rules. D i s c r e p a n c i e s a r i s e b e c a u s e the design of rule au to ma ta is often affected by assumptions Compilation of automata from morphological two-level rules Kimmo Koskenniemi, pages
2 on the r e g u l a r i t y of a c t u a l w o r d - f o r m s. Th us, s u c h a u t o m a t a u s u a l l y function c o r r e c t l y with most of the data but they ha v e a less cl ea r rela t i o n with orig i n a l intended rules. The rule comp i l e r de sc ri be d b e l o w rectifies this p r o b l e m by letting the ling uist write rules in a true rule f o r m a l i s m w h i l e the computer prod uces the automata m e c h anically. These can then be used in c o n v e n t i o n a l t w o - l e v e l programs, both for t e s t i n g a n d a n d f o r p r o d u c t i o n use. S e v e r a l t w o - l e v e l d e scriptions are now on their way towards c o m p l e t i o n using the c o m p i l e r. 2. THE FORMALISM OF TWO-LEVEL RULES T h e a c t u a l r u l e f o r m a l i s m s u p p o r t e d by the t w o - l e v e l c o m p i l e r d i f f e r s o n l y s l i g h t l y f r o m the o r i g i n a l f o r m a l i s m prop os ed in Koskenniemi (1983). One of the di ff er en ce s is the us e of l i n e a r r e p r e s e n t a t i o n for p a irs, t h u s a :o is u s e d i n s t e a d of F u r t h e r m o r e, the e q u a l s i g n is no l o n g e r u s e d for denoting the full lexical or surface alphabet. A surface v o w e l is w r i t t e n s i m p l y as :V an d a l e x i c a l a as a :. O t h e r basic elem e n t s are as they used to be; (1) A s e q u e n c e of e l e m e n t s a r e w r i t t e n o n e a f t e r a n o t h e r, t h u s :V :V s t a n d s for two s u c c e s s i v e surface vowels. (2) A l t e r n a t i v e e l e m e n t s are separated by a v e r t i c a l bar and e n c l o s e d in s q u a r e b r a c k e t s, e.g. [:i :j] st ands for either a su rf ac e i or a su rf ac e j. (3) Iteration is indicated with a superscript asterisk or p l u s sign, e.g. :C* s t a n d s for z e r o or m o r e surface c o nsonants whereas :C'* requires at least one surface consonant. R u l e s w i t h o p e r a t o r s => <= an d <=> e x i s t as b e f o r e and they are interpreted as before. A rule: I : j => :V :V -1^4-144
3 s t a t e s t h a t e v e r y o c c u r r e n c e of a p a i r I:j m u s t be in a c o n t e x t of.. :V :V.. i.e. b e t w e e n two s u r f a c e v o w e l s. A rule: I:j <= :V :V s t a t e s th a t b e t w e e n s u r f a c e v o w e l s a l e x i c a l I has no o t h e r p o s s i b l e r e al iz at io ns than a j. Ru le s with operators <=> are c o mbinations of those with <= and =>. There is one new type of rules with an operator >v<=. This r u l e f o r b i d s a n y o c c u r r e n c e s of LC C P RC, i.e. it f o r b i d s C P in the context LC RC. A n o t h e r d i f f e r e n c e is in the f o r m a l i s m for c o l l a p s i n g s e v e r a l s i m i l a r r u l e s i n to o n e rule. T h e i n i t i a l f o r m a l i s m used an g l e brackets, but this has been replaced by e q u i v a l e n t means using so c a l l e d "where" clauses. If W denotes a morphop h o n e m e for v o w e l d o u b l i n g t h e n a r u l e for v o w e l d o u b l i n g is expressed in the present f o r m a l i s m as: W : x <=> :x wh er e x in V; T h e d e f i n i t i o n of the r u l e c o m p o n e n t of t w o - l e v e l d e scriptions cons is ts of six sections: - a surface alph ab et as a list of surface characters - s u b s e t s of the s u r f a c e a l p h a b e t w h i c h ar e us e d in the rules - a lexical alphabet - subsets of the lexical alphabet - d e finitions for a b b r e v i a t i o n s or subexpressions used in. the rules - two-level rules. A sample two-level description is gi ve n below:
4 Lexical Alphabet a b c d e f g h i j k l m n o p q r s t u v w X y z S a o al a2 E I = W; Lexical Sets V = a e i o u y ^ a o a l a 2 E I W ; C = b c d f g h j k l m n p q r s t v w x z ; Di ac ri ti cs = / "; Surface Alphabet a b c d e f g h i j k l m n o p q r s t u v w X y X a a 5; Surface Sets V = a e i o u y ^ a o ; C = b c d f g h j k l m n p q r s t v w x z ; Definitions Defaults = al:a a2:a E:e I;i; Rules "Vowel doubling" W:X => :X ; where X in V; "Suppressed doubling" W:0 <=> I;; I: ; W ; V ; " Stem final V" [al:0 a2: o E:0 i;e] < = > I :; " Plural I" I:j <=> :V :V; N o t e t h a t s u r f a c e a n d l e x i c a l a l p h a b e t s a r e d e c l a r e d s e p a r a t e l y. T h i s g u a r a n t e e s t h a t the r o l e of e a c h s e g m e n t is u n i q u e l y determined. The sets are separate a l s o because it is no t a l w a y s e v i d e n t e.g. w h i c h s e g m e n t s a r e c o n s i d e r e d to be v o w e l s on the le xi ca l level. The first rule represents a set of s e v e r a l rules; W:a => :a ; W:e => :e ; W:6 => :6 ; i s i n t e r p r e t e d d u m m y v a r i a b l e X o c c u r s on b o t h s i d e s of the ru le. If it w o u l d -1A6-146
5 occur o n l y on the context side then the a b b r e v i a t i o n denotes o n e s i n g l e r u l e w i t h m a n y c o n t e x t p a r t s (one fo r e a c h possibility of X ). Another effect of the e x pansion of "where" c l a u s e s is the i n t r o d u c t i o n of s o m e n e w c h a r a c t e r pairs. P a i r s W:a, W:e, W:o do no t o c c u r a n y w h e r e in the d e s c r i p t i o n but t h e y are i m p l i c i t l y included. 3. STEPS OF THE COMPILATION The c o m p i l a t i o n of the t w o - l e v e l de s c r i p t i o n into finite s t a t e a u t o m a t a p r o c e e d s in s e v e r a l steps. T h e c o m p u t a t i o n relies e s s e n t i a l l y on Ron Kaplan's program pa ck ag es (FSM, FST) for m a n i p u l a t i n g f i n i t e s t a t e m a c h i n e s a n d t r a n s d u c e r s. T h e c o l l e c t i o n of r u l e s ha s to be t r e a t e d as a w h o l e b e c a u s e the set of c h a r a c t e r p a i r s (CPS) m i g h t be c h a n g e d if s o m e r u l e s ar e a l t e r e d t h us c h a n g i n g the i n t e r p r e t a t i o n of s o m e o t h e r rules. The steps of the c o m p i l a t i o n are: ( 1 ) ( 2 ) (3) (4) (5) T r a n s f o r m a t i o n of the t w o - l e v e l r u l e d e s c r i p t i o n i n t o a r e c u r s i v e l i s t e x p r e s s i o n w h e r e r u l e components and pairs are identified. Expa ns io n of "where" clauses in the rules. C o l l e c t i n g a l l pairs e x p l i c i t l y ment ioned in rules and d e f i n i t i o n s in a d d i t i o n to the d e f a u l t set of a l l x:x w h e r e x is b o t h a l e x i c a l and a s u r f a c e c h a r a c t e r. C o m p u t i n g the e x a c t i n t e r p r e t a t i o n of p a i r s w h i c h a r e not c o n c r e t e p a i r s (whe re b o t h the l e x i c a l an d the lexical comp onents are single characters). Some p a i r s l i k e :V l e a v e o n e l e v e l f u l l y o p e n a n d o t h e r s may use the defined subsets such as W:V (character W c o r r e s p o n d i n g to a n y of the v o w e l s b u t not to a z e r o 0). A l l s u c h ( p a r t i a l l y ) u n s p e c i f i e d p a i r s X:Y d e n o t e the s u b s e t of C P S c o n s i s t i n g of p a i r s x:y w h e r e x is X or is in X an d y is Y or is in Y. E x p a n d e a c h a b b r e v i a t i o n of the a b o v e t y p e in t o an alternation. Insert the defined e x pression in pl a c e of the name of the expression
6 (6) C o m p i l e the c o mponents of the rules (correspondence parts, left cont exts and right contexts) into finite state machines. (7) Sp li t ru les with the operator <=> into one rule with operator => and another with <=. (8) E x p a n d r u l e s w i t h o p e r a t o r <= and w i t h m u l t i p l e cont ex ts into distinct rules with one context each. (9) Compile the individual comp on en t rules separately. (10) M e r g e the au to ma ta re su lt in g from a s i n g l e or ig in al rule into one rule au tomaton by in tersecting them. In the p r e s e n t v e r s i o n of the c o m p i l e r e a c h r u l e as d e f i n e d by the u s er is c o m p i l e d into a s i n g l e a u t o m a t o n. If the e x p a n s i o n or c o m p i l a t i o n s p l i t s the r u l e in t o s u b p a r t s t h e s e are f i n a l l y c o m b i n e d in t o a s i n g l e m a c h i n e by the c o m p i l e r. T h e c o m p i l a t i o n is d o n e on a X e r o x 1108 L i s p m a c h i n e w i t h p r o g r a m s w r i t t e n in I n t e r l i s p - D. T h e r e s u l t i n g a u t o m a t a c a n t h e n be us e d e i t h e r on the L i s p M a c h i n e or t r a n s p o r t e d to o t h e r sy st em s. In o r d e r to be u s e d by the p r e s e n t v e r s i o n of the Pascal t w o - l e v e l pr o g r a m the automata are c o n v e r t e d into a t a b u l a r f o r m a t w h i c h c a n be r e a d i l y used. T h e f o r m a t is s l i g h t l y di ff er en t from the o r iginal one g i v e n in Koskenniemi (1983) b u t it is s i g n i f i c a n t l y f a s t e r to r e a d in. S u c h automata ha ve been s u c c e s s f u l l y used on MS-DOS mi cr o comp uters s u c h as I B M PC a n d O l i v e t t i M 2 4. M a r t t i N y m a n a t t h e U n i v e r s i t y of H e l s i n k i working on one d e scription for M o d e r n Gr ee k and another for C l a s s i c a l Greek and Jo rm a L u utonen at the U n i v e r s i t y of T u r k u is w o r k i n g on o n e for C h e r e m i s. O l l i B l å b e r g has r e f o r m u l a t e d his Swedish d e s c ription in terms of the present compiler. T h e c o m p i l e r w a s w r i t t e n d u r i n g the s u m m e r at the C e n t e r for S t u d i e s on L a n g u a g e a n d I n f o r m a t i o n at S t a n f o r d University. In ad di ti on to the finite state package written by Ron K a p l a n the c o m p i l e r ut il iz es Kaplan's concept of co mp il in g c o m p l e x rules with operator => and s e v e r a l context parts. The c o m p i l e r w a s p r e s e n t e d at a s y m p o s i u m o n f i n i t e s t a t e m o r p h o l o g y on July, at CSLI. The co mp il er has a l so s t i m u l a t e d some p a r a l l e l efforts (Bear, in press, Ritchie et. al. 1985, Kinnunen, in preparation)
7 REFERENCES Bear, John, (in press). A m o r p h o l o g i c a l r e c o g n i z e r w i t h syntactic and p h o n o l o g i c a l rules. P r oceedings of COLING- 86, Bonn. Kinnunen, Maarit, (in preparation). M o r f o l o g i s t e n saantojen kaan ta mi ne n a a r e l l i s i k s i automaateiksi. (The c o m p i l a t i o n of m o r p h o l o g i c a l r u l e s into f i n i t e s t a t e a u t o m a t a ) M a s t e r s t h e s i s. D e p a r t m e n t of C o m p u t e r S c i e n c e, U n i v e r s i t y of Helsinki. K o s k e n n i e m i, K T w o - l e v e l m o r p h o l o g y : A g e n e r a l c o m p u t a t i o n a l m o d e l f o r w o r d - f o r m r e c o g n i t i o n a n d production. Publications, No. 11, U n i v e r s i t y of Helsinki, De partment of Ge ne ra l Linguistics. Helsinki. ---, A g e n e r a l c o m p u t a t i o n a l m o d e l for w o r d - f o r m recognition and production. P r o c eedings of COLING-84. pp R i t c h i e, G.D., S.G. P u l m a n, and G.J. R u s s e l, D i c t i o n a r y and m o r p h o l o g i c a l a n a l y z e r ( P r o t o t y p e ), U s e r guide: V e r s i o n D e p a r t m e n t of A r t i f i c i a l I n t e l l i g e n c e, University of Edinburgh. - 1 ^ 9-149
A L A BA M A L A W R E V IE W
A L A BA M A L A W R E V IE W Volume 52 Fall 2000 Number 1 B E F O R E D I S A B I L I T Y C I V I L R I G HT S : C I V I L W A R P E N S I O N S A N D TH E P O L I T I C S O F D I S A B I L I T Y I N
More informationP a g e 5 1 of R e p o r t P B 4 / 0 9
P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e
More informationOH BOY! Story. N a r r a t iv e a n d o bj e c t s th ea t e r Fo r a l l a g e s, fr o m th e a ge of 9
OH BOY! O h Boy!, was or igin a lly cr eat ed in F r en ch an d was a m a jor s u cc ess on t h e Fr en ch st a ge f or young au di enc es. It h a s b een s een by ap pr ox i ma t ely 175,000 sp ect at
More informationP a g e 3 6 of R e p o r t P B 4 / 0 9
P a g e 3 6 of R e p o r t P B 4 / 0 9 p r o t e c t h um a n h e a l t h a n d p r o p e r t y fr om t h e d a n g e rs i n h e r e n t i n m i n i n g o p e r a t i o n s s u c h a s a q u a r r y. J
More informationSoftware Process Models there are many process model s in th e li t e ra t u re, s om e a r e prescriptions and some are descriptions you need to mode
Unit 2 : Software Process O b j ec t i ve This unit introduces software systems engineering through a discussion of software processes and their principal characteristics. In order to achieve the desireable
More informationT h e C S E T I P r o j e c t
T h e P r o j e c t T H E P R O J E C T T A B L E O F C O N T E N T S A r t i c l e P a g e C o m p r e h e n s i v e A s s es s m e n t o f t h e U F O / E T I P h e n o m e n o n M a y 1 9 9 1 1 E T
More information176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s
A g la di ou s F. L. 462 E l ec tr on ic D ev el op me nt A i ng er A.W.S. 371 C. A. M. A l ex an de r 236 A d mi ni st ra ti on R. H. (M rs ) A n dr ew s P. V. 326 O p ti ca l Tr an sm is si on A p ps
More informationUse precise language and domain-specific vocabulary to inform about or explain the topic. CCSS.ELA-LITERACY.WHST D
Lesson eight What are characteristics of chemical reactions? Science Constructing Explanations, Engaging in Argument and Obtaining, Evaluating, and Communicating Information ENGLISH LANGUAGE ARTS Reading
More informationGeometric Predicates P r og r a m s need t o t es t r ela t ive p os it ions of p oint s b a s ed on t heir coor d ina t es. S im p le exa m p les ( i
Automatic Generation of SS tag ed Geometric PP red icates Aleksandar Nanevski, G u y B lello c h and R o b ert H arp er PSCICO project h ttp: / / w w w. cs. cm u. ed u / ~ ps ci co Geometric Predicates
More information(C) Pavel Sedach and Prep101 1
(C) Pavel Sedach and Prep101 1 (C) Pavel Sedach and Prep101 1 (C) Pavel Sedach and Prep101 2 (C) Pavel Sedach and Prep101 2 (C) Pavel Sedach and Prep101 3 (C) Pavel Sedach and Prep101 3 (C) Pavel Sedach
More informationTable of C on t en t s Global Campus 21 in N umbe r s R e g ional Capac it y D e v e lopme nt in E-L e ar ning Structure a n d C o m p o n en ts R ea
G Blended L ea r ni ng P r o g r a m R eg i o na l C a p a c i t y D ev elo p m ent i n E -L ea r ni ng H R K C r o s s o r d e r u c a t i o n a n d v e l o p m e n t C o p e r a t i o n 3 0 6 0 7 0 5
More informationSTANDARDIZATION OF BLENDED NECTAR USING BANANA PSEUDOSTEM SAP AND MANGO PULP SANTOSH VIJAYBHAI PATEL
STANDARDIZATION OF BLENDED NECTAR USING BANANA PSEUDOSTEM SAP AND MANGO PULP BY SANTOSH VIJAYBHAI PATEL B.Sc. (Hons.) Horticulture DEPARTMENT OF POST HARVEST TECHNOLOGY ASPEE COLLEGE OF HORTICULTURE AND
More informationc. What is the average rate of change of f on the interval [, ]? Answer: d. What is a local minimum value of f? Answer: 5 e. On what interval(s) is f
Essential Skills Chapter f ( x + h) f ( x ). Simplifying the difference quotient Section. h f ( x + h) f ( x ) Example: For f ( x) = 4x 4 x, find and simplify completely. h Answer: 4 8x 4 h. Finding the
More informationLast 4 Digits of USC ID:
Chemistry 05 B Practice Exam Dr. Jessica Parr First Letter of last Name PLEASE PRINT YOUR NAME IN BLOCK LETTERS Name: Last 4 Digits of USC ID: Lab TA s Name: Question Points Score Grader 8 2 4 3 9 4 0
More informationI M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o
I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o u l d a l w a y s b e t a k e n, i n c l u d f o l
More informationNucleus. Electron Cloud
Atomic Structure I. Picture of an Atom Nucleus Electron Cloud II. Subatomic particles Particle Symbol Charge Relative Mass (amu) protons p + +1 1.0073 neutrons n 0 1.0087 electrons e - -1 0.00054858 Compare
More informationSolutions and Ions. Pure Substances
Class #4 Solutions and Ions CHEM 107 L.S. Brown Texas A&M University Pure Substances Pure substance: described completely by a single chemical formula Fixed composition 1 Mixtures Combination of 2 or more
More informationlectures accompanying the book: Solid State Physics: An Introduction, by Philip ofmann (2nd edition 2015, ISBN-10: 3527412824, ISBN-13: 978-3527412822, Wiley-VC Berlin. www.philiphofmann.net 1 Bonds between
More information9/20/2017. Elements are Pure Substances that cannot be broken down into simpler substances by chemical change (contain Only One Type of Atom)
CAPTER 6: TE PERIODIC TABLE Elements are Pure Substances that cannot be broken down into simpler substances by chemical change (contain Only One Type of Atom) The Periodic Table (Mendeleev) In 1872, Dmitri
More informationGuide to the Extended Step-Pyramid Periodic Table
Guide to the Extended Step-Pyramid Periodic Table William B. Jensen Department of Chemistry University of Cincinnati Cincinnati, OH 452201-0172 The extended step-pyramid table recognizes that elements
More informationo Alphabet Recitation
Letter-Sound Inventory (Record Sheet #1) 5-11 o Alphabet Recitation o Alphabet Recitation a b c d e f 9 h a b c d e f 9 h j k m n 0 p q k m n 0 p q r s t u v w x y z r s t u v w x y z 0 Upper Case Letter
More informationMarks for each question are as indicated in [] brackets.
Name Student Number CHEMISTRY 140 FINAL EXAM December 10, 2002 Numerical answers must be given with appropriate units and significant figures. Please place all answers in the space provided for the question.
More informationThe Periodic Table of Elements
The Periodic Table of Elements 8 Uuo Uus Uuh (9) Uup (88) Uuq (89) Uut (8) Uub (8) Rg () 0 Ds (9) 09 Mt (8) 08 Hs (9) 0 h () 0 Sg () 0 Db () 0 Rf () 0 Lr () 88 Ra () 8 Fr () 8 Rn () 8 At (0) 8 Po (09)
More informationThe distribution of characters, bi- and trigrams in the Uppsala 70 million words Swedish newspaper corpus
Uppsala University Department of Linguistics The distribution of characters, bi- and trigrams in the Uppsala 70 million words Swedish newspaper corpus Bengt Dahlqvist Abstract The paper describes some
More informationThe Periodic Table. Periodic Properties. Can you explain this graph? Valence Electrons. Valence Electrons. Paramagnetism
Periodic Properties Atomic & Ionic Radius Energy Electron Affinity We want to understand the variations in these properties in terms of electron configurations. The Periodic Table Elements in a column
More informationH STO RY OF TH E SA NT
O RY OF E N G L R R VER ritten for the entennial of th e Foundin g of t lair oun t y on ay 8 82 Y EEL N E JEN K RP O N! R ENJ F ] jun E 3 1 92! Ph in t ed b y h e t l a i r R ep u b l i c a n O 4 1922
More informationCHEM 251 (Fall-2003) Final Exam (100 pts)
CEM 251 (Fall-2003) Final Exam (100 pts) Name: -------------------------------------------------------------------------------, SSN -------------------------------- LAST NAME, First (Circle the alphabet
More information02/05/09 Last 4 Digits of USC ID: Dr. Jessica Parr
Chemistry 05 B First Letter of PLEASE PRINT YOUR NAME IN BLOCK LETTERS Exam last Name Name: 02/05/09 Last 4 Digits of USC ID: Dr. Jessica Parr Lab TA s Name: Question Points Score Grader 2 2 9 3 9 4 2
More informationI N A C O M P L E X W O R L D
IS L A M I C E C O N O M I C S I N A C O M P L E X W O R L D E x p l o r a t i o n s i n A g-b eanste d S i m u l a t i o n S a m i A l-s u w a i l e m 1 4 2 9 H 2 0 0 8 I s l a m i c D e v e l o p m e
More informationAgenda Rationale for ETG S eek ing I d eas ETG fram ew ork and res u lts 2
Internal Innovation @ C is c o 2 0 0 6 C i s c o S y s t e m s, I n c. A l l r i g h t s r e s e r v e d. C i s c o C o n f i d e n t i a l 1 Agenda Rationale for ETG S eek ing I d eas ETG fram ew ork
More informationPERIODIC TABLE OF THE ELEMENTS
Useful Constants and equations: K = o C + 273 Avogadro's number = 6.022 x 10 23 d = density = mass/volume R H = 2.178 x 10-18 J c = E = h = hc/ h = 6.626 x 10-34 J s c = 2.998 x 10 8 m/s E n = -R H Z 2
More informationElement Cube Project (x2)
Element Cube Project (x2) Background: As a class, we will construct a three dimensional periodic table by each student selecting two elements in which you will need to create an element cube. Helpful Links
More informationSpeed of light c = m/s. x n e a x d x = 1. 2 n+1 a n π a. He Li Ne Na Ar K Ni 58.
Physical Chemistry II Test Name: KEY CHEM 464 Spring 18 Chapters 7-11 Average = 1. / 16 6 questions worth a total of 16 points Planck's constant h = 6.63 1-34 J s Speed of light c = 3. 1 8 m/s ħ = h π
More informationBeechwood Music Department Staff
Beechwood Music Department Staff MRS SARAH KERSHAW - HEAD OF MUSIC S a ra h K e rs h a w t r a i n e d a t t h e R oy a l We ls h C o l le g e of M u s i c a n d D ra m a w h e re s h e ob t a i n e d
More informationCATAVASII LA NAȘTEREA DOMNULUI DUMNEZEU ȘI MÂNTUITORULUI NOSTRU, IISUS HRISTOS. CÂNTAREA I-A. Ήχος Πα. to os se e e na aș te e e slă ă ă vi i i i i
CATAVASII LA NAȘTEREA DOMNULUI DUMNEZEU ȘI MÂNTUITORULUI NOSTRU, IISUS HRISTOS. CÂNTAREA I-A Ήχος α H ris to os s n ș t slă ă ă vi i i i i ți'l Hris to o os di in c ru u uri, în tâm pi i n ți i'l Hris
More informationChemistry 431 Practice Final Exam Fall Hours
Chemistry 431 Practice Final Exam Fall 2018 3 Hours R =8.3144 J mol 1 K 1 R=.0821 L atm mol 1 K 1 R=.08314 L bar mol 1 K 1 k=1.381 10 23 J molecule 1 K 1 h=6.626 10 34 Js N A = 6.022 10 23 molecules mol
More informationExecutive Committee and Officers ( )
Gifted and Talented International V o l u m e 2 4, N u m b e r 2, D e c e m b e r, 2 0 0 9. G i f t e d a n d T a l e n t e d I n t e r n a t i o n a2 l 4 ( 2), D e c e m b e r, 2 0 0 9. 1 T h e W o r
More informationTHIS PAGE DECLASSIFIED IAW EO IRIS u blic Record. Key I fo mation. Ma n: AIR MATERIEL COMM ND. Adm ni trative Mar ings.
T H S PA G E D E CLA SSFED AW E O 2958 RS u blc Recod Key fo maon Ma n AR MATEREL COMM ND D cumen Type Call N u b e 03 V 7 Rcvd Rel 98 / 0 ndexe D 38 Eneed Dae RS l umbe 0 0 4 2 3 5 6 C D QC d Dac A cesson
More informationCHEM 10113, Quiz 5 October 26, 2011
CHEM 10113, Quiz 5 October 26, 2011 Name (please print) All equations must be balanced and show phases for full credit. Significant figures count, show charges as appropriate, and please box your answers!
More informationMade the FIRST periodic table
Made the FIRST periodic table 1869 Mendeleev organized the periodic table based on the similar properties and relativities of certain elements Later, Henri Moseley organized the elements by increasing
More informationC o r p o r a t e l i f e i n A n c i e n t I n d i a e x p r e s s e d i t s e l f
C H A P T E R I G E N E S I S A N D GROWTH OF G U IL D S C o r p o r a t e l i f e i n A n c i e n t I n d i a e x p r e s s e d i t s e l f i n a v a r i e t y o f f o r m s - s o c i a l, r e l i g i
More informationMANY ELECTRON ATOMS Chapter 15
MANY ELECTRON ATOMS Chapter 15 Electron-Electron Repulsions (15.5-15.9) The hydrogen atom Schrödinger equation is exactly solvable yielding the wavefunctions and orbitals of chemistry. Howev er, the Schrödinger
More informationCHEM 108 (Spring-2008) Exam. 3 (105 pts)
CHEM 08 (Spring-008) Exam. (05 pts) Name: --------------------------------------------------------------------------, CLID # -------------------------------- LAST NAME, First (Circle the alphabet segment
More informationDangote Flour Mills Plc
SUMMARY OF OFFER Opening Date 6 th September 27 Closing Date 27 th September 27 Shares on Offer 1.25bn Ord. Shares of 5k each Offer Price Offer Size Market Cap (Post Offer) Minimum Offer N15. per share
More informationFaculty of Natural and Agricultural Sciences Chemistry Department. Semester Test 1. Analytical Chemistry CMY 283. Time: 120 min Marks: 100 Pages: 6
Faculty of Natural and Agricultural Sciences Chemistry Department Semester Test 1 Analytical Chemistry CMY 283 Date: 5 September 2016 Lecturers : Prof P Forbes, Dr Laurens, Mr SA Nsibande Time: 120 min
More informationAtoms and the Periodic Table
Atoms and the Periodic Table Parts of the Atom Proton Found in the nucleus Number of protons defines the element Charge +1, mass 1 Parts of the Atom Neutron Found in the nucleus Stabilizes the nucleus
More informationRadiometric Dating (tap anywhere)
Radiometric Dating (tap anywhere) Protons Neutrons Electrons Elements on the periodic table are STABLE Elements can have radioactive versions of itself called ISOTOPES!! Page 1 in your ESRT has your list!
More informationFaculty of Natural and Agricultural Sciences Chemistry Department. Semester Test 1 MEMO. Analytical Chemistry CMY 283
Faculty of Natural and Agricultural Sciences Chemistry Department Semester Test 1 MEMO Analytical Chemistry CMY 283 Date: 5 September 2016 Lecturers : Prof P Forbes, Dr Laurens, Mr SA Nsibande Time: 90
More informationChemistry 2 Exam Roane State Academic Festival. Name (print neatly) School
Name (print neatly) School There are fifteen question on this exam. Each question is weighted equally. n the answer sheet, write your name in the space provided and your answers in the blanks provided.
More informationUse precise language and domain-specific vocabulary to inform about or explain the topic. CCSS.ELA-LITERACY.WHST D
Lesson seven What is a chemical reaction? Science Constructing Explanations, Engaging in Argument and Obtaining, Evaluating, and Communicating Information ENGLISH LANGUAGE ARTS Reading Informational Text,
More informationCh. 9 NOTES ~ Chemical Bonding NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics.
Ch. 9 NOTES ~ Chemical Bonding NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. I. Review: Comparison of ionic and molecular compounds Molecular compounds Ionic
More information(please print) (1) (18) H IIA IIIA IVA VA VIA VIIA He (2) (13) (14) (15) (16) (17)
CHEM 10113, Quiz 3 September 28, 2011 Name (please print) All equations must be balanced and show phases for full credit. Significant figures count, show charges as appropriate, and please box your answers!
More informationIf anything confuses you or is not clear, raise your hand and ask!
CHM 1045 Dr. Light s Section December 10, 2002 FINAL EXAM Name (please print) Recitation Section Meeting Time This exam consists of six pages. Make sure you have one of each. Print your name at the top
More informationINSTRUCTIONS: Exam III. November 10, 1999 Lab Section
CHEM 1215 Exam III John III. Gelder November 10, 1999 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 7 different pages. The last page includes a periodic table and
More informationLab Day and Time: Instructions. 1. Do not open the exam until you are told to start.
Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this
More informationK E L LY T H O M P S O N
K E L LY T H O M P S O N S E A O LO G Y C R E ATO R, F O U N D E R, A N D PA R T N E R K e l l y T h o m p s o n i s t h e c r e a t o r, f o u n d e r, a n d p a r t n e r o f S e a o l o g y, a n e x
More information2 tel
Us. Timeless, sophisticated wall decor that is classic yet modern. Our style has no limitations; from traditional to contemporar y, with global design inspiration. The attention to detail and hand- craf
More information8. Relax and do well.
CHEM 1225 Exam III John III. Gelder April 8, 1999 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 7 different pages. The last two pages includes a periodic table and
More informationCHEM 107 (Spring-2004) Exam 2 (100 pts)
CHEM 107 (Spring-2004) Exam 2 (100 pts) Name: ------------------------------------------------------------------------, SSN -------------------------------- LAST NAME, First (Circle the alphabet segment
More informationAdvanced Chemistry. Mrs. Klingaman. Chapter 5: Name:
Advanced Chemistry Mrs. Klingaman Chapter 5: The Periodic Law Name: _ Mods: Chapter 5: The Periodic Law Reading Guide 5.1 History of the Periodic Table (pgs. 125-129) 1) What did Dimitri Mendeleev notice
More informationM10/4/CHEMI/SPM/ENG/TZ2/XX+ CHEMISTRY. Wednesday 12 May 2010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES
M10/4/CHEMI/SPM/ENG/TZ/XX+ 106116 CHEMISTRY standard level Paper 1 Wednesday 1 May 010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES Do not open this examination paper until instructed to do so. Answer
More informationChapter 12 The Atom & Periodic Table- part 2
Chapter 12 The Atom & Periodic Table- part 2 Electrons found outside the nucleus; negatively charged Protons found in the nucleus; positive charge equal in magnitude to the electron s negative charge Neutrons
More informationLab Day and Time: Instructions. 1. Do not open the exam until you are told to start.
Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this
More informationLab Day and Time: Instructions. 1. Do not open the exam until you are told to start.
Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this
More informationsingle-layer transition metal dichalcogenides MC2
single-layer transition metal dichalcogenides MC2 Period 1 1 H 18 He 2 Group 1 2 Li Be Group 13 14 15 16 17 18 B C N O F Ne 3 4 Na K Mg Ca Group 3 4 5 6 7 8 9 10 11 12 Sc Ti V Cr Mn Fe Co Ni Cu Zn Al Ga
More informationSecondary Support Pack. be introduced to some of the different elements within the periodic table;
Secondary Support Pack INTRODUCTION The periodic table of the elements is central to chemistry as we know it today and the study of it is a key part of every student s chemical education. By playing the
More informationUsing the Periodic Table
MATH SKILLS TRANSPARENCY WORKSHEET Using the Periodic Table 6 Use with Chapter 6, Section 6.2 1. Identify the number of valence electrons in each of the following elements. a. Ne e. O b. K f. Cl c. B g.
More informationChemistry 185 Exam #2 - A November 5, Lab Day and Time: Instructions. 1. Do not open the exam until you are told to start.
Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this
More informationTopic 3: Periodicity OBJECTIVES FOR TODAY: Fall in love with the Periodic Table, Interpret trends in atomic radii, ionic radii, ionization energies &
Topic 3: Periodicity OBJECTIVES FOR TODAY: Fall in love with the Periodic Table, Interpret trends in atomic radii, ionic radii, ionization energies & electronegativity The Periodic Table What is the periodic
More informationCHEM 172 EXAMINATION 1. January 15, 2009
CHEM 17 EXAMINATION 1 January 15, 009 Dr. Kimberly M. Broekemeier NAME: Circle lecture time: 9:00 11:00 Constants: c = 3.00 X 10 8 m/s h = 6.63 X 10-34 J x s J = kg x m /s Rydberg Constant = 1.096776 x
More informationHANDOUT SET GENERAL CHEMISTRY II
HANDOUT SET GENERAL CHEMISTRY II Periodic Table of the Elements 1 2 3 4 5 6 7 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 IA VIIIA 1 2 H He 1.00794 IIA IIIA IVA VA VIA VIIA 4.00262 3 Li 6.941 11 Na 22.9898
More informationCMSC 313 Lecture 17 Postulates & Theorems of Boolean Algebra Semiconductors CMOS Logic Gates
CMSC 313 Lecture 17 Postulates & Theorems of Boolean Algebra Semiconductors CMOS Logic Gates UMBC, CMSC313, Richard Chang Last Time Overview of second half of this course Logic gates &
More informationPOLYTECHNIC OF NAMIBIA
POLYTECHNIC OF NAMIBIA DEPARTMENT OF HEALTH SCIENCES BACHELOR OF ENVIRONMENTAL HEALTH SCIENCES HEALTH SCIENCE CHEMISTRY (HSC 511S) NQF level 5 SECOND OPPORTUNITY EXAMINATION November 2014 TIME: MARKS:
More information7. Relax and do well.
CHEM 1215 Exam II John II. Gelder October 7, 1998 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 5 different pages. The last page includes a periodic table and a solubility
More informationCircle the letters only. NO ANSWERS in the Columns!
Chemistry 1304.001 Name (please print) Exam 5 (100 points) April 18, 2018 On my honor, I have neither given nor received unauthorized aid on this exam. Signed Date Circle the letters only. NO ANSWERS in
More information5 questions, 3 points each, 15 points total possible. 26 Fe Cu Ni Co Pd Ag Ru 101.
Physical Chemistry II Lab CHEM 4644 spring 2017 final exam KEY 5 questions, 3 points each, 15 points total possible h = 6.626 10-34 J s c = 3.00 10 8 m/s 1 GHz = 10 9 s -1. B= h 8π 2 I ν= 1 2 π k μ 6 P
More informationK. 27 Co. 28 Ni. 29 Cu Rb. 46 Pd. 45 Rh. 47 Ag Cs Ir. 78 Pt.
1 IA 1 ydrogen 1.01 Atomic number Element symbol Element name Atomic mass VIIIA 1 1.01 IIA IIIA IVA VA VIA VIIA 2 e 4.00 Metalloids 3 Li 6.94 4 Be 9.01 5 B 10.81 6 C 12.01 7 N 14.01 8 O 16.00 9 F 19.00
More information2 (27) 3 (26) 4 (21) 5 (18) 6 (8) Total (200) Periodic Table
Chem 3311 Sammakia Fall 2009 Midterm 1 Student ID page points: 2 (27) 3 (26) 4 (21) 5 (18) 6 (8) Total (200) Periodic Table e Li Be B C N O F Ne Na Mg Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn
More informationInstructions. 1. Do not open the exam until you are told to start.
Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this
More informationMetallurgical Chemistry. An Audio Course for Students
Laval University From the SelectedWorks of Fathi Habashi February, 1987 Metallurgical Chemistry. An Audio Course for Students Fathi Habashi Available at: https://works.bepress.com/fathi_habashi/27/ METALLURGICAL
More informationCHEM 130 Exp. 8: Molecular Models
CHEM 130 Exp. 8: Molecular Models In this lab, we will learn and practice predicting molecular structures from molecular formulas. The Periodic Table of the Elements IA 1 H IIA IIIA IVA VA VIA VIIA 3 5
More informationLab Day and Time: Instructions. 1. Do not open the exam until you are told to start. Page # Points possible Points awarded
Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this
More information1 of 5 14/10/ :21
X-ray absorption s, characteristic X-ray lines... 4.2.1 Home About Table of Contents Advanced Search Copyright Feedback Privacy You are here: Chapter: 4 Atomic and nuclear physics Section: 4.2 Absorption
More informationCHEM Come to the PASS workshop with your mock exam complete. During the workshop you can work with other students to review your work.
It is most beneficial to you to write this mock midterm UNDER EXAM CONDITIONS. This means: Complete the midterm in 1.5 hours. Work on your own. Keep your notes and textbook closed. Attempt every question.
More informationWhy all the repeating Why all the repeating Why all the repeating Why all the repeating
Why all the repeating Why all the repeating Why all the repeating Why all the repeating Patterns What Patterns have you observed in your life? Where to Get Help If you don t understand concepts in chapter
More informationCHM 101 PRACTICE TEST 1 Page 1 of 4
CHM 101 PRACTICE TEST 1 Page 1 of 4 Please show calculations (stuffed equations) on all mathematical problems!! On the actual test, "naked answers, with no work shown, will receive no credit even if correct.
More information8. Relax and do well.
CHEM 15 Exam II John II. Gelder March 4, 1999 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 7 different pages. The last two pages includes a periodic table, a solubility
More informationF l a s h-b a s e d S S D s i n E n t e r p r i s e F l a s h-b a s e d S S D s ( S o-s ltiad t e D r i v e s ) a r e b e c o m i n g a n a t t r a c
L i f e t i m e M a n a g e m e n t o f F l a-b s ah s e d S S D s U s i n g R e c o v e r-a y w a r e D y n a m i c T h r o t t l i n g S u n g j i n L e, e T a e j i n K i m, K y u n g h o, Kainmd J
More informationCHEM 107 (Spring-2005) Exam 3 (100 pts)
CHEM 107 (Spring-2005) Exam 3 (100 pts) Name: ------------------------------------------------------------------------, Clid # ------------------------------ LAST NAME, First (Circle the alphabet segment
More informationEKOLOGIE EN SYSTEMATIEK. T h is p a p e r n o t to be c i t e d w ith o u t p r i o r r e f e r e n c e to th e a u th o r. PRIMARY PRODUCTIVITY.
EKOLOGIE EN SYSTEMATIEK Ç.I.P.S. MATHEMATICAL MODEL OF THE POLLUTION IN NORT H SEA. TECHNICAL REPORT 1971/O : B i o l. I T h is p a p e r n o t to be c i t e d w ith o u t p r i o r r e f e r e n c e to
More information8. Relax and do well.
CHEM 1225 Exam I John I. Gelder February 4, 1999 Name KEY TA's Name Lab Section Please sign your name below to give permission to post your course scores on homework, laboratories and exams. If you do
More informationLesson Ten. What role does energy play in chemical reactions? Grade 8. Science. 90 minutes ENGLISH LANGUAGE ARTS
Lesson Ten What role does energy play in chemical reactions? Science Asking Questions, Developing Models, Investigating, Analyzing Data and Obtaining, Evaluating, and Communicating Information ENGLISH
More information4.01 Elements, Symbols and Periodic Table
.0 Elements, Symbols and Periodic Table Dr. Fred O. Garces Chemistry 00 Miramar College.0 Elements, symbols and the Periodic Table Aug The Elements: Building block of Matter The periodic table of the chemical
More informationBuilding Harmony and Success
Belmont High School Quantum Building Harmony and Success October 2016 We acknowledge the traditional custodians of this land and pay our respects to elders past and present Phone: (02) 49450600 Fax: (02)
More informationNAME: FIRST EXAMINATION
1 Chemistry 64 Winter 1994 NAME: FIRST EXAMINATION THIS EXAMINATION IS WORTH 100 POINTS AND CONTAINS 4 (FOUR) QUESTIONS THEY ARE NOT EQUALLY WEIGHTED! YOU SHOULD ATTEMPT ALL QUESTIONS AND ALLOCATE YOUR
More informationAtomic Structure & Interatomic Bonding
Atomic Structure & Interatomic Bonding Chapter Outline Review of Atomic Structure Atomic Bonding Atomic Structure Atoms are the smallest structural units of all solids, liquids & gases. Atom: The smallest
More informationPART 1 Introduction to Theory of Solids
Elsevier UK Job code: MIOC Ch01-I044647 9-3-2007 3:03p.m. Page:1 Trim:165 240MM TS: Integra, India PART 1 Introduction to Theory of Solids Elsevier UK Job code: MIOC Ch01-I044647 9-3-2007 3:03p.m. Page:2
More information30 Zn(s) 45 Rh. Pd(s) Ag(s) Cd(s) In(s) Sn(s) white. 77 Ir. Pt(s) Au. Hg(l) Tl. 109 Mt. 111 Uuu. 112 Uub. 110 Uun. 65 Tb. 62 Sm. 64 Gd. 63 Eu.
Enthalpy changes: experimentally it is much easier to measure heat flow at const pressure - this is enthalpy q p = )H : also nearly all chemical reactions are done at constant pressure. Enthalpy (heat)
More informationDO NOW: Retrieve your projects. We will be reviewing them again today. Textbook pg 23, answer questions 1-3. Use the section 1.2 to help you.
DO NOW: Retrieve your projects. We will be reviewing them again today. Textbook pg, answer questions. Use the section. to help you. Chapter test is FRIDAY. The Periodic Table of Elements 8 Uuo Uus Uuh
More informationCLASS TEST GRADE 11. PHYSICAL SCIENCES: CHEMISTRY Test 4: Matter and materials 1
CLASS TEST GRADE PHYSICAL SCIENCES: CHEMISTRY Test 4: Matter and materials MARKS: 45 TIME: hour INSTRUCTIONS AND INFORMATION. Answer ALL the questions. 2. You may use non-programmable calculators. 3. You
More information