Mechanics. Time (s) Distance (m) Velocity (m/s) Acceleration (m/s 2 ) = + displacement/time.

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1 Mechanics Symbols: Equations: Kinematics The Study of Motion s = distance or displacement v = final speed or velocity u = initial speed or velocity a = average acceleration s u+ v v v u v= also v= a = = t t t so v= u+ at u+ v s= vt or s= t 1 s= ut+ t = + v u as Constant Acceleration Time (s) Distance (m) Velocity (m/s) Acceleration (m/s ) Condition for applying equations for uniformly accelerated motion: must be constant, smooth acceleration equations use average acceleration = instantaneous if acceleration is constant a) What does the slope of a position-time graph represent? Instantaneous velocity - derivative b) What does the slope of a velocity-time graph represent? Instantaneous acceleration - derivative average vs. instantaneous: over a period of time vs. at one instant c) What does the area under a velocity time graph represent? displacement - integral Example: Two friends bicycle 3.0 kilometers north and then turn to bike 4.0 kilometers east in 5 minutes. a) What is their average speed? distance/time b) What is their average velocity? displacement/time Dropping 1. A stone is dropped from rest from the top of a tall building. After 3.00 s of free-fall, what is the displacement of the stone? What is its velocity? 7.0 km / 5 min = 0.8 km/min x 60 min/hr = 16.8 = 17 km/hr 5.0 km/ 5 min = 0.0 km/min x 60 min/hr = 1 km/hr s = ½ at = -45 m v = u + at v = -30 m/s Angle: 53 o west of north discuss change of frame of reference downward is positive Constant Velocity Time (s) Distance (m) Velocity (m/s) Acceleration (m/s ) How would these graphs change in the presence of air resistance? 1 Terminal velocity: no acceleration constant velocity F g = F air

2 Throwing Up Angled Projectile A ball is thrown straight up in the air (shown here stretched out for clarity.) Sketch velocity and acceleration vectors at each instant. A football game customarily begins with a coin toss to determine who kicks off. The referee tosses the coin up with an initial speed of 6.00 m/s. In the absence of air resistance, how high does the coin go above its point of release? How long is it in the air? v = u + as 0 = (6) + (-10)s s = 1.8 m v = u + at 0 = (-10)t t = 0.6 s x = 1. s 1. Break initial velocity into horiz and vert components. maximum height occurs after ½ time 3. maximum range occurs after fulltime and at air resistance: not as high nor as far show on diagram discuss change of frame of reference downward is positive A football was kicked with a speed of 5 m/s at an angle of 30.0 o to the horizontal. Determine how high it went and where it landed. Components time: Height: x: cos 30 0 = v i/5 m/s v = u + at v i = 1.7 m/s 0 = 1.5 m/s + (-10)(t) s = (1.5 m/s)(1.5 s) + ½ (-10 m/s )(1.5 s) Projectile Motion: resultant of two independent components of motion y: sin 30 0 = v i/5 m/s v i = 1.5 m/s t = 1.5 s total time = (1.5) =.5 s = 7.8 m Range: 1. Vertical: constant acceleration (in absence of air resistance) s = (1.7 m/s)(.5 s) + 0. Horizontal: constant velocity no horizontal acceleration s = 54 m Horizontal Projectile A ball is shot horizontally off a cliff that is 100. m high at a speed of 5 m/s. How long does it take to hit the ground? How far away from the base of the cliff does it land? y-direction: -100 = 0 + ½(-10)t t = 4.5 s x-direction: s = 5 (4.5) + 0 s = 113 m Statics and Dynamics The Study of Forces Newton s Laws of Motion 1. An object at rest remains at rest and an object in motion remains in motion at a constant speed in a straight line (constant velocity) unless acted on by unbalanced forces. (An object continues in uniform motion in a straight line or at rest unless a resultant (net) external force acts on it.). When unbalanced forces act on an object, the object will accelerate in the direction of the resultant (net) force. The acceleration will be directly proportional to the net force and inversely proportional to the object s mass. (The resultant force on an object is equal to the rate of change of momentum of the object.) 3. For every action on one object, there is an equal and opposite reaction on another object. (When two bodies A and B interact, the force that A exerts on B is equal and opposite to the force that B exerts on A.) 3 4

3 Newton s Second Law F = p / t For constant mass. Find the tension in each cable supporting the 600 N cat burglar pictured. F = (mv) / t F = m ( v / t) F = m a nd Law or 3 rd Law? Net force on ball: not zero so it accelerates not in equilibrium F net = F g = mg Action-Reaction pairs: Earth pulls ball down Ball pulls Earth up F EB = -F BE ma = -Ma F g Net force on block: zero at rest in equilibrium F net = F N - F g = 0 Action-Reaction pairs: Earth pulls block down Block pulls Earth up block pushes down on table table pushes up on block 3. A 0.0-kg floodlight in a park is supported at the end of a horizontal beam of negligible mass that is hinged to a pole, as shown. A cable at an angle of 30.0 with the beam helps to support the light. Find (a) the tension in the cable and (b) the horizontal and vertical forces exerted on the beam by the pole. H V d T N a) 400N b) R x = 346 R y = 0 Translational equilibrium: net force acting on object is zero no acceleration 1. Find the resistive force F caused by the drag of the water on the boat moving at a constant velocity in the diagram shown. 4. How would your answers change if the mass of the beam shown above was not negligible? T increase show how reaction force is oriented 5. Indicate the direction of the reaction force from the floor and the reaction force from the wall for the situation shown below. F W F N F g1 F g 5 6 F f

4 Mass 1) the amount of matter in an object ) the property of an object that determines its resistance to a change in its motion (a measure of the amount of inertia of an object) Property: Remains constant Weight, Mass, and the Normal Force Symbol : m Units : kg Weight: the force of gravity acting on an object Property: Varies from place to place Symbol : F g or W Units : N Calculate the force of friction acting on this box if it accelerates down the incline at a rate of 0.67 m/s. F net = ma = 4.5 (0.67) = 3.0 N F g = mg sin θ = 15 N F f = 1 N 4.5 kg 0 0 Elevators: In each case, the scale will read... the normal or reaction force, not the weight Uniform Circular Motion constant speed and constant radius Uniform Circular Motion Calculate the acceleration of the man in each case. Period time take for one complete cycle symbol: T units: s 1. The direction of the object s instantaneous velocity is always tangent to the circle in the direction of motion. Σ F = 0 Σ F = ma Σ F = m a Σ F = m a. Since the direction of the object s motion is always changing, its velocity is always changing therefore the object is always accelerating and is never in equilibrium. F N F g = 0 F N 700 = 0 F N F g = m a = 70 a F N F g = m a = 70 a F g = m a 700 = 70 a 3. Direction of net force towards the center - centripetal F N = 700 N a = +4.3 m/s a = m/s a = -10 m/s Formulas: Inclined Plane Assume the box shown is in equilibrium and draw the... Free-body diagram Head-to-tail vector diagram Concurrent vector diagram V bar = distance / time V bar = circumference / period V bar = πr / T V = πr / T V bar = πr / T a c = v / r a c = (πr / T) / r a c = (4π r / T ) / r a c = 4 π r / T F = m a F c = m a c F c = mv / r F N F f Concurrent vector diagram with perpendicular components The phrase centripetal force does not denote a new and separate force created by nature. The phrase merely labels the net force pointing toward the center of the circular path, and this net force is the vector sum of all the force components that point along the radial direction. 1. The model airplane shown has a mass of 0.90 kg and moves at a constant speed on a circle that is parallel to the ground. Find the tension T in the guideline (length = 17 m) for a speed of 19 m/s. θ F g θ 7 8

5 . At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders plastered against the wall. For a particular ride with a radius of 8.0 m and a top speed of 1 m/s, calculate the reaction force and the friction force from the wall acting on a 60. kg rider. Which of these is the centripetal force? 1. A 45.0-N force is applied to pull a luggage carrier an angle θ = 50 for a distance of 75.0 m at a constant speed. Find the work done by the applied force. W = F s cos θ W A = (45.0 N)(75 m) cos 50 o = 170 J 3. A 100-kg demolition ball swings at the end of a 15-m cable on the arc of a vertical circle. At the lowest point of the swing, the ball is moving at a speed of 7.6 m/s. Determine the tension in the cable.. a) How much work is done dragging the 5.00 kg box to the top of the hill shown if the hill exerts an average friction force of 5.0 N? b) Compare your answer to the amount of work done lifting the box straight up to the top of the hill. Work, Power and Efficiency Work: product of force and displacement in the direction of the force W = (F cos θ) s N m or Joules (J) c) Calculate the power expended if the box is dragged to the top in 15 seconds. W = F s cos θ θ is angle between F and s Type: Scalar but can be positive or negative d) Calculate the efficiency of dragging the box rather than lifting the box. Power: 1) the rate at which work is done P = W/ t = E / t = Q/t Alternate P = W / t = (F cos θ d) / t = F v cos θ J / s = Watts (W) ) the rate at which energy is transferred Efficiency: 1) ratio of useful work done by a system to the total work done by the system ) ratio of useful energy output of a system to the total energy input to the system Type: Scalar e = useful out/ total in Work = area under curve W = b h W = f s Determining Work Done Graphically Work = area under curve W = ½ b h W = ½ F s W = (avg force) (displacement) 3) ratio of useful power output of a system to total power input to the system 9 1. Work done by a constant force. Work done by a constantly varying force ex. stretching a spring 10

6 Energy Linear Momentum and Impulse Linear Momentum: the product of an object s mass and velocity p = mv kg m/s Types of Energy Formulas: A kg car is traveling east at a speed of 5.0 m/s. Compare its inertia, momentum, and kinetic energy. inertia (inertial mass) m = 1500 kg scalar momentum p = (1500) (5) = 3.75 x 10 4 kg m/s, east vector kinetic energy E k = ½ (1500)(5) = J = 4.69 x 10 5 J scalar 1. Kinetic energy (energy of motion). Gravitational Potential energy (energy of position) 1. E K = ½ mv. E P = mgh Alternate formula for kinetic energy: 3. Elastic potential energy 4. Internal energy (thermal energy) 5. Chemical Potential energy (stored in chemical bonds) Electrical energy Light energy 3. E elas = ½ kx 4. Q = mc t Q = ml 5. E e = Pt = VIt = I Rt = V /R t How does the momentum of an object change? A net external force acts for a finite amount of time Impulse: Conservation of Energy Principle (the change in momentum of a system) the product of the average force and the time interval over which the force acts In an isolated system, the total amount of energy remains constant. 1. A motorcyclist is trying to leap across a canyon by driving horizontally off the cliff at a speed of 38.0 m/s. Ignoring air resistance, find the speed with which the cycle strikes the ground on the other side. Ns or kg m/s Type: vector Usually... Force is not instantaneous and is not constant Derivation of Impulse Formula. What is the speed of the box at the bottom of the incline if an average frictional force of 15 N acts on it as it slides? 0 meters 160 N p F = t p= F t ( mv) = F t m v= F t (if mass is constant) J = p= F t= m v Graphically, the impulse is J = F avg t = area 30 0 If force is linear: J = ½ F max t 11 1

7 Bouncing and Impulse Collisions A 0.50 kg basketball hits the floor at a speed of 4.0 m/s and rebounds at 3.0 m/s. Calculate the impulse applied to it by the floor. Calculation: p= m v p= 0.50 kg( ( 3.0)) p= 7.0 kgm / s In general: v v p= m v v v p= m v p= m v + v ( f i) ( f i) Force vs. time graph for bounce Velocity vs. time graph for bounce Force Velocity Time Elastic collision: a collision in which the total kinetic energy is conserved 1. A freight train is being assembled in a switching yard, and the figure below shows two boxcars. Car 1 has a mass of m 1 = kg and moves at a velocity of v 01 = m/s. Car, with a mass of m = kg and a velocity of v 0 = +1.3 m/s, overtakes car 1 and couples to it. Neglecting friction, find the common velocity v f of the cars after they become coupled. Inelastic collision: a collision in which the total kinetic energy is not conserved Where does some of the mechanical energy go in an inelastic collision? energy of deformation, internal energy, sound energy Time The Principle of Conservation of Linear Momentum: The total momentum of an isolated system remains constant. p before = p after. Is this collision elastic or inelastic? Justify your answer. 1. Bouncy Types of Interactions. Sticky 3. A ballistic pendulum is sometimes used in laboratories to measure the speed of a projectile, such as a bullet. A ballistic pendulum consists of a block of wood (mass m =.50 kg) suspended by a wire of negligible mass. A bullet (mass m 1 = kg) is fired with a speed v 01. Just after the bullet collides with it, the block (with the bullet in it) has a speed v f and then swings to a maximum height of m above the initial position (see part b of the drawing). Find the speed v 01 of the bullet, assuming that air resistance is negligible. 3. Explosion 13 14