Class 6 Second quarter at school
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1 ID : in6secondquarteratschool [] Class 6 Second quarter at school For more such worksheets visit wwwedugaincom Answer the questions () Find the value of the following : 7 () If the following figure represents 0, what is the result of the given problem? () Bala had hokey practice for 7 days in the month of July Find the fraction of the days Bala practiced in the month of July (4) What number do we get by adding ten thousandths and hundredths together to thousands, and multiplying the result with tenths? () A caterpillar can crawl 6 meters in 7 hours How much distance can it crawl in days? (6) What is the smallest number that should be added to 4 to give an even number? (7) Shade the images to show the following fraction addition + 4 and makes (8) What number do you get by adding Hundredths and 8 Hundredths together to 6 Hundreds?
2 ID : in6secondquarteratschool [] (9) How many 4 's are there in 7? (0) Find the value of z 8 z () Sita's father gave her Rs 4 to spend She spent Rs 04 to buy some toys and Rs 8 to buy some books How much money is she left with in the end? () Solve the following and reduce to the simplest form: A) ( ) + 4 B) ( ) + C) ( ) + D) ( ) + () Add the following fractions and reduce the sum to the simplest form: A) B) C) + 6 D) E) + 4 F) Choose correct answer(s) from the given choices (4) Which figure shows fraction? a c b d Fill in the blanks () Subtract the following fractions and reduce them to the simplest form: A) 8 8 B) C)
3 ID : in6secondquarteratschool [] D) E) 6 F) 6 07 Edugain (wwwedugaincom) All Rights Reserved Many more such worksheets can be generated at wwwedugaincom
4 Answers ID : in6secondquarteratschool [4] () 4 The given expression 7 can be simplified as: Thus, the value of 7 is 4
5 () 04 ID : in6secondquarteratschool [] If we look at the figure, we notice that, there are a total of 00 boxes of 00 represents 0 Therefore, of 00 represents The difference of the boxes in the given figures Hence, 4 of 00 represents Thus, the result of is 04
6 ID : in6secondquarteratschool [6] () 7 We know, Number of days in the month of July Number of days Bala had hokey practice 7 We know, the fraction of days Bala practised in the month of July Number of days he practised 7 Number of days in the month of July Hence, the fraction of the days Bala practiced in the month of July is 7
7 (4) ID : in6secondquarteratschool [7] We know, ten thousandths 0000, hundredths 00, thousands 000, and tenths 0 Let us add the first three numbers Now, let us multiply the above sum by tenths Hence, is the correct answer
8 () 88 ID : in6secondquarteratschool [8] Let us first find the number of hours in days One day has 4 hours Therefore, number of hours in days 4 48 hours The caterpillar can crawl 6 meters in 7 hours Therefore, the distance it can crawl in hour will be: 6 6 meters 7 To find the distance it can crawl in 48 hours, we will multiply 6 with 48, which comes out to be 88 Step Hence, the caterpillar can crawl 88 meters in days (6) 08 (7) + 4 +
9 (8) ID : in6secondquarteratschool [9] Let us first convert the number names into numerals: Hundredths Hundredths Hundreds Let us first add the decimal numbers as below: Lakhs Thousands Ones Tenths Hundredths Thousandths Ten thousandths TL L TTH TH H T O (/0) (/00) (/000) (/0000) Total Legend: TL Ten Lakhs, L Lakhs, TTH Ten Thousands, TH Thousands, H Hundreds, T Tens, O Ones Let us now add the decimal numbers to the whole number: Lakhs Thousands Ones Tenths Hundredths Thousandths Ten thousandths TL L TTH TH H T O (/0) (/00) (/000) (/0000) Total Therefore, by adding Hundredths and 8 Hundredths together to 6 Hundreds, we get 60009
10 (9) 68 ID : in6secondquarteratschool [0] In the given problem, we have a fraction 4 and a whole number 7 Here, we need to find how many 4 's are there in 7 For that, we need to divide 7 into equal parts of size 4 or, in other words, simply divide 7 by 4 : Hence, the number of 4 's in 7 is 68
11 (0) 000 ID : in6secondquarteratschool [] The equation that we have been given is: 8 z z (Transpose the term 9 from the LHS to the RHS) 8 z (Transpose the terms 0 and from the LHS to the RHS) 8 z (Write 04 as ) (Replace the denominator by their LCM and adjust the numerator z 000 accordingly) (Simplify the numerator) z (Simplify the numerator) z 000 By cross multiplying, we get: z z z 000 Therefore, the value of z is 000
12 () Rs 7 ID : in6secondquarteratschool [] The amount of money Sita's father gave her Rs 4 The amount of money Sita spent on buying toys Rs 04 The amount of money Sita spent on buying books Rs 8 Let us add the amount of money she spent on buying toys and books to find her total expense: Toys Rs 04 Books Rs 8 Total expense Rs 686 Step In order to find the amount left with her, we need to subtract the amount Sita spent from the amount her father gave her Step 6 Before subtracting the two numbers, let us make sure they are written as Like Decimals We know that the decimals with the same number of decimal places are called Like Decimals Thus, let us write Rs 4 as Rs 400 and subtract Rs 686 from it Step 7 Let us subtract the amount Sita spent (Rs 686) from the amount her father gave (Rs 4), digit by digit The numbers must be placed according to their place values The greater number of the two numbers must be placed on top and the smaller one below it Thousands Hundreds Tens Ones Tenth Hundredth Step 8 Hence, Sita is left with Rs 7
13 ID : in6secondquarteratschool [] () A) 4 ( ) + 4 can be written as: ( 8 6 ) + 9 [ Converting mixed fractions into improper fractions ] ( 8 6 ) + 9 [ Dividing by a fraction is same as multiplying with its reciprocal] Thus, the simplest form of ( ) + 4 is 4
14 ID : in6secondquarteratschool [4] B) 6 ( ) + can be written as: ( ) + 6 [ Converting mixed fractions into improper fractions ] ( reciprocal] + 6 ) + 6 [ Dividing by a fraction is same as multiplying with its Thus, the simplest form of ( ) + is 6
15 ID : in6secondquarteratschool [] C) 6 ( ) + can be written as: ( 6 ) + [ Converting mixed fractions into improper fractions ] ( 6 reciprocal] 6 + ) + [ Dividing by a fraction is same as multiplying with its Thus, the simplest form of ( ) + is 6
16 ID : in6secondquarteratschool [6] D) 6 ( ) + can be written as: ( 4 0 ) + 4 [ Converting mixed fractions into improper fractions ] ( 4 0 reciprocal] ) + 4 [ Dividing by a fraction is same as multiplying with its Thus, the simplest form of ( ) + is 6
17 ID : in6secondquarteratschool [7] () A) 7 46 We need to add the following Unlike fractions: 4 Let us first convert them to Like fractions Let us find the LCM of the denominators 4 and 9 The LCM of 4 and 9 is 46 and 9 What should we multiply to the denominator 4 to get the LCM 46? It is So, the first fraction can be written as: Similarly, the second fraction can be written as: Step On adding the Like fractions, we may still not get the simplest form Step 6 The HCF of 7 and 46 is This means that the sum 7 46 is already in the simplest form Step 7 Hence, the sum of the given fractions is 7 46
18 ID : in6secondquarteratschool [8] B) 96 6 We need to add the following Unlike fractions: 9 0 and 6 Let us first convert them to Like fractions Let us find the LCM of the denominators 0 and 6 The LCM of 0 and 6 is 0 What should we multiply to the denominator 0 to get the LCM 0? It is 0 0 So, the first fraction can be written as: Similarly, the second fraction can be written as: Step On adding the Like fractions, we may still not get the simplest form Step 6 The HCF of 9 and 0 is This means that the sum 9 0 is already in the simplest form Step 7 Hence, the sum of the given fractions is 96 6
19 ID : in6secondquarteratschool [9] C) 6 We need to add the following Unlike fractions: Let us first convert them to Like fractions Let us find the LCM of the denominators and 6 The LCM of and 6 is 6 and 6 What should we multiply to the denominator to get the LCM 6? It is 6 So, the first fraction can be written as: Similarly, the second fraction can be written as: Step On adding the Like fractions, we may still not get the simplest form Step 6 The HCF of and 6 is This means that the sum 6 is already in the simplest form Step 7 Hence, the sum of the given fractions is 6
20 ID : in6secondquarteratschool [0] D) We need to add the following Unlike fractions: 9 and 7 7 Let us first convert them to Like fractions Let us find the LCM of the denominators and 7 The LCM of and 7 is 74 What should we multiply to the denominator to get the LCM 74? It is 74 7 So, the first fraction can be written as: Similarly, the second fraction can be written as: Step On adding the Like fractions, we may still not get the simplest form Step 6 The HCF of 477 and 74 is This means that the sum is already in the simplest form Step 7 Hence, the sum of the given fractions is
21 ID : in6secondquarteratschool [] E) 9 8 We need to add the following Unlike fractions: and 4 Let us first convert them to Like fractions Let us find the LCM of the denominators and 4 The LCM of and 4 is 8 What should we multiply to the denominator to get the LCM 8? It is 8 4 So, the first fraction can be written as: Similarly, the second fraction can be written as: Step On adding the Like fractions, we may still not get the simplest form Step 6 The HCF of 9 and 8 is This means that the sum 9 8 is already in the simplest form Step 7 Hence, the sum of the given fractions is 9 8
22 ID : in6secondquarteratschool [] F) 7 0 We need to add the following Unlike fractions: 4 9 Let us first convert them to Like fractions Let us find the LCM of the denominators 9 and The LCM of 9 and is 0 and What should we multiply to the denominator 9 to get the LCM 0? It is 0 9 So, the first fraction can be written as: Similarly, the second fraction can be written as: Step On adding the Like fractions, we may still not get the simplest form Step 6 The HCF of 7 and 0 is This means that the sum 7 0 is already in the simplest form Step 7 Hence, the sum of the given fractions is 7 0
23 (4) b ID : in6secondquarteratschool [] Look at the all of the figures carefully and notice that in figure The number of in selected box and the total number of 9 Now the fraction of the number of in the selected box to the total number of in given figure 9 Therefore the figure shows fraction
24 ID : in6secondquarteratschool [4] () A) 8 8 The given fractions are like fractions, since their denominators are same To add two like fractions we can directly subtract the numerators, and the denominator will remain the same This means the new fraction will be: In order to convert the fraction in the simplest/lowest form, let us divide both the numerator and denominator by their HCF Step The HCF of 0 and is Step 6 0 Hence, the simplest/lowest form of 0 is
25 ID : in6secondquarteratschool [] B) The given fractions are unlike fractions, since their denominators are different To add two unlike fractions we should take LCM of their denominators The LCM of the denominators 8 and comes out to be 8 itself, which is the denominator for the new fraction This means the new fraction will be: (8 4) Step In order to convert the fraction 4 8 in the simplest/lowest form, let us divide both the numerator and denominator by their HCF Step 6 The HCF of 4 and 8 is 4 Step 7 4 Hence, the simplest/lowest form of 4 8 is 4 8 4
26 ID : in6secondquarteratschool [6] C) The given fractions are unlike fractions, since their denominators are different To add two unlike fractions we should take LCM of their denominators The LCM of the denominators 8 and comes out to be 8 itself, which is the denominator for the new fraction This means the new fraction will be: (6 9) Step In order to convert the fraction in the simplest/lowest form, let us divide both the 8 numerator and denominator by their HCF Step 6 The HCF of and 8 is 6 Step 7 Hence, the simplest/lowest form of 8 is 6 8 6
27 ID : in6secondquarteratschool [7] D) The given fractions are unlike fractions, since their denominators are different To add two unlike fractions we should take LCM of their denominators The LCM of the denominators 0 and 0 comes out to be 0 itself, which is the denominator for the new fraction This means the new fraction will be: 9 9 ( ) Step In order to convert the fraction in the simplest/lowest form, let us divide both the 0 numerator and denominator by their HCF Step 6 The HCF of and 0 is Step 7 Hence, the simplest/lowest form of 0 is 0 4
28 ID : in6secondquarteratschool [8] E) 6 7 The given fractions are like fractions, since their denominators are same To add two like fractions we can directly subtract the numerators, and the denominator will remain the same This means the new fraction will be: 6 6 In order to convert the fraction in the simplest/lowest form, let us divide both the numerator and denominator by their HCF Step The HCF of and is Step 6 Hence, the simplest/lowest form of is 7
29 ID : in6secondquarteratschool [9] F) 6 8 The given fractions are like fractions, since their denominators are same To add two like fractions we can directly subtract the numerators, and the denominator will remain the same This means the new fraction will be: In order to convert the fraction in the simplest/lowest form, let us divide both the numerator and denominator by their HCF Step The HCF of 6 and is Step 6 6 Hence, the simplest/lowest form of 6 is 8
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