A Model Answer for. Problem Set #7
|
|
- Jonah Lester
- 5 years ago
- Views:
Transcription
1 A Model Answer for Problem Set #7 Pipe Flow and Applications Problem.1 A pipeline 70 m long connects two reservoirs having a difference in water level of 6.0 m. The pipe rises to a height of 3.0 m above the water level in the upper reservoir at a distance of 40 m from the entrance before falling to the lower reservoir. If the pipe is 1. m diameter and the friction coefficient f = 0.015, find the discharge and the pressure at highest point in the pipeline 1
2 Problem.1 - sol Apply B.E bet. 1 & (Neglect minor losses) = h f1- h f1- = 6 = ( 8fL/g π D 5 ) Q = (8*0.015*70 / g π (1.) 5 ) Q Q = 4.09 m 3 /sec v =Q/A = 3.6 m/sec Apply B.E bet. 1 & 3 (Neglect minor losses) = 9 + v / g + P 3 / γ + h f1-3 h f1-3 = (8fL/g π D 5 ) Q = (8*0.015*40 / g π (1.) 5 ) Q P 3 / γ = -3 - (3.6) / g - (8*0.015*40 / g π (1.) 5 ) (4.09) = Problem. Water discharges from a reservoir into the atmosphere through a pipeline 39 m long. The pipeline, which has a sharp entrance, is 50 mm diameter (f = 0.0) for the first 15 m then suddenly enlarges to 75 mm diameter (f = 0.05) for the rest of its length. If the discharge is maintained at.8x10-3 m 3 /sec, calculate the water head in the reservoir taking into account all losses.
3 Problem. - sol v 1 = Q/A 1 = 1.46 m/sec & v = Q/A = m/sec Apply B.E bet. 1 & H = v / g + h l1- H = v / g v 1 / g + (8f 1 L 1 /g π D 15 ) Q + ( v 1 -v ) /g + (8f L /g π D 5 ) Q H = 0.89 m Problem.3 Oil of kinematic viscosity 0.1 stoke flows through a smooth pipe of 30 cm diameter. If the virtual slope is 1/800, obtain the discharge 3
4 Problem.3 - sol h f = (8fL/g π D 5 ) Q The virtual slope = slope of total energy line = h f /L =(8f/g π D 5 ) Q = 1/800 f Q = * (1) assume f 0 = sub. In (1) ---- Q0 = m 3 /sec v 0 = Q 0 / A = m/sec R n0 = v0 D / ν = Moody chart --- Smooth pipe -- f 1 = f 1 = sub. In (1) ---- Q1 = m 3 /sec v 1 = Q 1 / A = 0.57 m/sec R n1 = v 1 D / ν = Moody chart --- Smooth pipe - -- f = 0.06 f = sub. In (1) ---- Q = m 3 /se Problem.4 Water from a large reservoir discharges into the atmosphere through a 100 mm diameter pipe 450 m long ending with a nozzle of diameter.45 cm. If the pipe, which discharges at a level 1 m below that of the water in the reservoir, has a sharpedged entrance and roughness of 0.1 mm, calculate the discharge knowing that the coefficient of the nozzle is 0.98 and the viscosity of water is 0.01 poise. 4
5 Problem4 - sol Apply B.E bet. 1 & = v / g + h l1- H = v / g vp / g + (8fL p /g π D p5 ) Q v / g v = Q / A & v p = Q / A p H = Q / ga Q / ga p + (8fLp/g π D p5 ) Q Q / ga Q fq = (1) ЄS / D = 0.1/10 = assume f 0 = sub. In (1) ---- Q 0 = m 3 /sec R n0 = ρ v 0 D / µ = ρ Q 0 D / Aµ = Moody chart --- ЄS / D = f 1 = sub. In (1) ---- Q 1 = m 3 /sec R n1 = ρ Q 1 D / µ = Moody chart --- ЄS / D = f = sub. In (1) ---- Q = m 3 /sec Problem5 Two reservoirs are connected by a pipeline, which is 150 mm diameter for the first 6 m and 55 mm diameter for the remaining 15 m. The difference in water levels is 6 m. If the entrance and exit are sharp-edged and the change in diameter is sudden, determine the losses and calculate the discharge. Sketch the hydraulic gradient and the total energy lines. (f = 0.04). 5
6 Problem5 - sol Apply B.E bet. 1 & = h l1-6 = 0.5 v 1 / g + (8f 1 L 1 /g π D 15 ) Q + ( v 1 - v ) /g + (8f L /g π D 5 ) Q + v / g v 1 = Q/A 1 & v = Q/A 6 = 0.5 Q / g A 1 + (8f 1 L 1 /g π D 15 ) Q + (Q/A 1 -Q/A ) /g + (8f L /g π D 5 ) Q + Q / g A Q = m 3 /sec Problem.6 A tank delivers water through a pipeline to a lower tank with a rectangular sharpedged weir of 5 cm width and (0.00) crest level; refer to figure (1). If the weir coefficient of discharge is 0.6, determine the steady discharge and the water head (h) above the weir crest taking into account all losses. 6
7 Problem.6 - sol Apply B.E bet. 1 & (the crest level is the datum ) = h h l1-.5 = h + [ 0.5 v / g + (8fL/g π D 5 ) Q + v / g ].5 = h + [ 1.5 Q / ga + (8fL/g π D 5 ) Q ].5 = h Q (1) Q = /3 C d B g h 1.5 Q = /3 * 0.6 * 0.5 g h 1.5 Q = h () From 1 &.5 = h h 3 h = 0.8 m & Q = 0.1 m 3 /sec H =.5 h = 1.7 m Problem.7 A, B, C and D are four points on a pipeline. Sections AB, BC and CD are straight with lengths 00 m, 300 m and 00 m, respectively. Elevations above datum of points A, B, C and D are 78 m, 764 m, 60 m and 614 m respectively. If the pressure at point A is 1. kg/cm and at point D is 19.3 kg/cm, find the pressure at a point 700 m above datum. (Neglect minor losses ) 7
8 Problem.7 - sol T.E A = Z A + v / g + P A / γ = * 10 4 / v / g = v / g T.E D = Z D + v / g + P D / γ = * 10 4 / v / g = v / g T.E D > T.E A The flow direction from D to A hl = T.E D -T.E A = 13 m hl / m= 13 / 700 m E C /300 = 80/ E C = m Apply B.E bet. D & E v / g * 10 4 /1000 = v / g + PE / γ + h ld-e Where h ld-e = hl/m * DE = 13/700 * ( ) = 6.81 m PE / γ = m PE = t/m Problem.8 A compound pipeline 8 km long is made up of a pipe 10 cm diameter for length of 1 km, 0 cm for km, 5 cm for 1.5 km and 30 cm for 3.5 km. It is required to replace the compound pipe by an equivalent pipe for the same total length and discharge. Find the diameter of the new pipe assuming all pipes have the same friction coefficient. 8
9 Problem.8 - sol Neglect the minor losses h f (pipe1) = h f (pipe ) (8fL 1 /g π D 15 ) Q + (8fL /g π D 5 ) Q + (8fL 3 /g π D 35 ) Q + (8fL 4 /g π D 45 ) Q = (8fL/g π D 5 ) Q 1000/(0.10) /(0.0) /(0.5) /(0.30) 5 = 8000/D 5 D = cm Problem.9 Two reservoirs are connected by a 600 m long, 30 cm diameter pipe ( f = 0.03). The flow produced by the difference in the water levels is 170 lit/sec. If a new pipe 00 m long, 30 cm diameter (f = 0.0) is laid parallel to an equal length of the old pipe, determine the new discharge. If it is required to double the original discharge, calculate the required length of the new pipe 9
10 Problem.9 - sol Apply B.E bet. 1 & H = h f = (8fL/g π D 5 ) Q H = m h f = 8f L/gπ D5 Q = k Q k 1 = 8f L 1 /gπ D 15 = k = 8f L /gπ D 5 = k 3 = 8f L 3 /gπ D 35 = Q 1 = Q + Q (1) Apply B.E bet. 1 & = k 1 Q 1 + k Q = k 1 Q 1 + k Q () Problem.9 - sol Apply B.E bet. 1 & = k 1 Q 1 + k 3 Q = k 1 Q 1 + k 3 Q (3) from & 3 k Q = k 3 Q 3 Q = Q (4) Sub. from 4 in 1 Q 1 = Q (5) Q 3 = m 3 /sec Q = m 3 /sec 10
11 Problem.9 - sol Sub. from 5 in 3 Q 1 = m 3 /sec k 1 = 8f (600 L)/gπ D 5 1 = L k = 8f L/gπ D 5 = 1.0 L k 3 = 8f L/gπ D 5 3 = 0.68 L 0.34 = Q + Q (1) Apply B.E bet. 1 & = k 1 Q 1 + k Q = k 1 Q 1 + k Q () Apply B.E bet. 1 & = k 1 Q 1 + k 3 Q = k 1 Q 1 + k 3 Q (3) from & 3 k Q = k 3 Q 3 Q = Q (4) Sub. from 4 in = Q 3 Q 3 = m 3 /sec Q = m 3 /sec Sub. in = ( L) * (0.3) L * (0.158) L = m Problem.10 A water main is 100 mm diameter and 4.8 km long. Supplies, that are arranged along the water main, uniformly draw a discharge q of 7.5 lit/hr per meter of its length. Calculate the difference in head between the pipe entrance and the last point of supply. Take f =
12 Problem.10 - sol Q= (Q in Q out ) / L If Q out = 0 Q in = q L = 7.5 / (1000 * 60 * 60 ) * 4.8 * 1000 = 0.01 m 3 /sec h f = 1/3 [8f L/gπ D 5 Q ] h f = 1/3 [8*0.0*4.8*1000 /gπ (0.10) 5 (0.01) ] = 6.44 m Problem.11 Water flows between two reservoirs with water level difference of 1.5 m through a pipe 4 km long, 50 cm diameter. It is required to feed a third reservoir, which is 15 m lower than the highest reservoir. The new pipe is 1.5 km long and is connected to the main pipe at a point 1.0 km from its entrance. Find the diameter of this new pipe such that water discharges equally into both reservoirs. Take f = 0.03 for all pipes and plot the Hydraulic Gradient line. 1
13 Problem.11 - sol Apply B.E bet. 1 & = h f1 + h f =.5 + (8fL 1 /g π D 15 ) Q +(8fL /g π D 5 ) (Q/) Q = m 3 /sec Apply B.E bet. 1 & = h f1 + h f3 = (8f 1 L 1 /g π D 15 ) Q +((8f L /g π D 5 ) Q D 3 = m Problem.1 A pump delivers water through two pipes laid parallel and connected to each other at the pump outlet. One pipe is 100-mm diameter and 45 m long and the other pipe is 150 mm diameter and 60 m long. They both discharge to the atmosphere at 6 m and 8 m, respectively, above pump outlet. Determine the total head at the pump outlet if the flow rate through it is m 3 /sec. Take the datum at the pump outlet and assume f =
14 Problem.1 - sol = Q + Q3. Q = Q (1) Apply B.E bet. 1 & H P = v /g + 8f L /gπd 5 Q H P = 6 + Q /ga + 8f L /gπ D 5 Q H P = Q () Apply B.E bet. 1 & 3 H P = v3/g + 8f L 3 /gπ D 35 Q 3 H P = 8 + Q3/gA3 + 8f L 3 /gπ D 35 Q 3 H P = Q (3) From & Q = Q (4) sub. From 1 in ( Q 3 ) = Q 3 Q 3 = > (rejected) OR. Q 3 = m 3 /sec. Q = m3/sec Sub in 3 The total head at the pump outlet = 9.0 m 14
Hydraulics. B.E. (Civil), Year/Part: II/II. Tutorial solutions: Pipe flow. Tutorial 1
Hydraulics B.E. (Civil), Year/Part: II/II Tutorial solutions: Pipe flow Tutorial 1 -by Dr. K.N. Dulal Laminar flow 1. A pipe 200mm in diameter and 20km long conveys oil of density 900 kg/m 3 and viscosity
More informationPipe Flow. Lecture 17
Pipe Flow Lecture 7 Pipe Flow and the Energy Equation For pipe flow, the Bernoulli equation alone is not sufficient. Friction loss along the pipe, and momentum loss through diameter changes and corners
More informationV/ t = 0 p/ t = 0 ρ/ t = 0. V/ s = 0 p/ s = 0 ρ/ s = 0
UNIT III FLOW THROUGH PIPES 1. List the types of fluid flow. Steady and unsteady flow Uniform and non-uniform flow Laminar and Turbulent flow Compressible and incompressible flow Rotational and ir-rotational
More informationUNIT I FLUID PROPERTIES AND STATICS
SIDDHARTH GROUP OF INSTITUTIONS :: PUTTUR Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) Subject with Code : Fluid Mechanics (16CE106) Year & Sem: II-B.Tech & I-Sem Course & Branch:
More informationFLUID MECHANICS D203 SAE SOLUTIONS TUTORIAL 2 APPLICATIONS OF BERNOULLI SELF ASSESSMENT EXERCISE 1
FLUID MECHANICS D203 SAE SOLUTIONS TUTORIAL 2 APPLICATIONS OF BERNOULLI SELF ASSESSMENT EXERCISE 1 1. A pipe 100 mm bore diameter carries oil of density 900 kg/m3 at a rate of 4 kg/s. The pipe reduces
More informationChapter (3) Water Flow in Pipes
Chapter (3) Water Flow in Pipes Water Flow in Pipes Bernoulli Equation Recall fluid mechanics course, the Bernoulli equation is: P 1 ρg + v 1 g + z 1 = P ρg + v g + z h P + h T + h L Here, we want to study
More informationChapter (3) Water Flow in Pipes
Chapter (3) Water Flow in Pipes Water Flow in Pipes Bernoulli Equation Recall fluid mechanics course, the Bernoulli equation is: P 1 ρg + v 1 g + z 1 = P ρg + v g + z h P + h T + h L Here, we want to study
More informationLECTURE 6- ENERGY LOSSES IN HYDRAULIC SYSTEMS SELF EVALUATION QUESTIONS AND ANSWERS
LECTURE 6- ENERGY LOSSES IN HYDRAULIC SYSTEMS SELF EVALUATION QUESTIONS AND ANSWERS 1. What is the head loss ( in units of bars) across a 30mm wide open gate valve when oil ( SG=0.9) flow through at a
More informationChapter (6) Energy Equation and Its Applications
Chapter (6) Energy Equation and Its Applications Bernoulli Equation Bernoulli equation is one of the most useful equations in fluid mechanics and hydraulics. And it s a statement of the principle of conservation
More informationHydraulic (Piezometric) Grade Lines (HGL) and
Hydraulic (Piezometric) Grade Lines (HGL) and Energy Grade Lines (EGL) When the energy equation is written between two points it is expresses as in the form of: Each term has a name and all terms have
More informationWhen water (fluid) flows in a pipe, for example from point A to point B, pressure drop will occur due to the energy losses (major and minor losses).
PRESSURE DROP AND OSSES IN PIPE When water (luid) lows in a pipe, or example rom point A to point B, pressure drop will occur due to the energy losses (major and minor losses). A B Bernoulli equation:
More informationINSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad AERONAUTICAL ENGINEERING QUESTION BANK : AERONAUTICAL ENGINEERING.
Course Name Course Code Class Branch INSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad - 00 0 AERONAUTICAL ENGINEERING : Mechanics of Fluids : A00 : II-I- B. Tech Year : 0 0 Course Coordinator
More informationCVE 372 HYDROMECHANICS EXERCISE PROBLEMS
VE 37 HYDROMEHNIS EXERISE PROLEMS 1. pump that has the characteristic curve shown in the accompanying graph is to be installed in the system shown. What will be the discharge of water in the system? Take
More informationR09. d water surface. Prove that the depth of pressure is equal to p +.
Code No:A109210105 R09 SET-1 B.Tech II Year - I Semester Examinations, December 2011 FLUID MECHANICS (CIVIL ENGINEERING) Time: 3 hours Max. Marks: 75 Answer any five questions All questions carry equal
More informationPROPERTIES OF FLUIDS
Unit - I Chapter - PROPERTIES OF FLUIDS Solutions of Examples for Practice Example.9 : Given data : u = y y, = 8 Poise = 0.8 Pa-s To find : Shear stress. Step - : Calculate the shear stress at various
More informationFE Fluids Review March 23, 2012 Steve Burian (Civil & Environmental Engineering)
Topic: Fluid Properties 1. If 6 m 3 of oil weighs 47 kn, calculate its specific weight, density, and specific gravity. 2. 10.0 L of an incompressible liquid exert a force of 20 N at the earth s surface.
More informationHydraulics and hydrology
Hydraulics and hydrology - project exercises - Class 4 and 5 Pipe flow Discharge (Q) (called also as the volume flow rate) is the volume of fluid that passes through an area per unit time. The discharge
More informationNPTEL Quiz Hydraulics
Introduction NPTEL Quiz Hydraulics 1. An ideal fluid is a. One which obeys Newton s law of viscosity b. Frictionless and incompressible c. Very viscous d. Frictionless and compressible 2. The unit of kinematic
More informationMechanical Engineering Programme of Study
Mechanical Engineering Programme of Study Fluid Mechanics Instructor: Marios M. Fyrillas Email: eng.fm@fit.ac.cy SOLVED EXAMPLES ON VISCOUS FLOW 1. Consider steady, laminar flow between two fixed parallel
More informationFE Exam Fluids Review October 23, Important Concepts
FE Exam Fluids Review October 3, 013 mportant Concepts Density, specific volume, specific weight, specific gravity (Water 1000 kg/m^3, Air 1. kg/m^3) Meaning & Symbols? Stress, Pressure, Viscosity; Meaning
More informationChapter 7 FLOW THROUGH PIPES
Chapter 7 FLOW THROUGH PIPES 7-1 Friction Losses of Head in Pipes 7-2 Secondary Losses of Head in Pipes 7-3 Flow through Pipe Systems 48 7-1 Friction Losses of Head in Pipes: There are many types of losses
More informationCIVE HYDRAULIC ENGINEERING PART II Pierre Julien Colorado State University
1 CIVE 401 - HYDRAULIC ENGINEERING PART II Pierre Julien Colorado State University Problems with and are considered moderate and those with are the longest and most difficult. In 2018 solve the problems
More informationA Model Answer for. Problem Set #4 FLUID DYNAMICS
A Model Answer for Problem Set #4 FLUID DYNAMICS Problem. Some elocity measurements in a threedimensional incomressible flow field indicate that u = 6xy and = -4y z. There is some conflicting data for
More information2 Internal Fluid Flow
Internal Fluid Flow.1 Definitions Fluid Dynamics The study of fluids in motion. Static Pressure The pressure at a given point exerted by the static head of the fluid present directly above that point.
More informationCE 6303 MECHANICS OF FLUIDS L T P C QUESTION BANK 3 0 0 3 UNIT I FLUID PROPERTIES AND FLUID STATICS PART - A 1. Define fluid and fluid mechanics. 2. Define real and ideal fluids. 3. Define mass density
More informationLesson 6 Review of fundamentals: Fluid flow
Lesson 6 Review of fundamentals: Fluid flow The specific objective of this lesson is to conduct a brief review of the fundamentals of fluid flow and present: A general equation for conservation of mass
More informationReynolds, an engineering professor in early 1880 demonstrated two different types of flow through an experiment:
7 STEADY FLOW IN PIPES 7.1 Reynolds Number Reynolds, an engineering professor in early 1880 demonstrated two different types of flow through an experiment: Laminar flow Turbulent flow Reynolds apparatus
More informationChapter 6. Losses due to Fluid Friction
Chapter 6 Losses due to Fluid Friction 1 Objectives ä To measure the pressure drop in the straight section of smooth, rough, and packed pipes as a function of flow rate. ä To correlate this in terms of
More informationChapter 4 DYNAMICS OF FLUID FLOW
Faculty Of Engineering at Shobra nd Year Civil - 016 Chapter 4 DYNAMICS OF FLUID FLOW 4-1 Types of Energy 4- Euler s Equation 4-3 Bernoulli s Equation 4-4 Total Energy Line (TEL) and Hydraulic Grade Line
More informationHomework 6. Solution 1. r ( V jet sin( θ) + ω r) ( ρ Q r) Vjet
Problem 1 Water enters the rotating sprinkler along the axis of rotation and leaves through three nozzles. How large is the resisting torque required to hold the rotor stationary for the angle that produces
More informationExperiment- To determine the coefficient of impact for vanes. Experiment To determine the coefficient of discharge of an orifice meter.
SUBJECT: FLUID MECHANICS VIVA QUESTIONS (M.E 4 th SEM) Experiment- To determine the coefficient of impact for vanes. Q1. Explain impulse momentum principal. Ans1. Momentum equation is based on Newton s
More informationChapter 3 Water Flow in Pipes
The Islamic University o Gaza Faculty o Engineering Civil Engineering Department Hydraulics - ECI 33 Chapter 3 Water Flow in Pipes 3. Description o A Pipe Flow Water pipes in our homes and the distribution
More informationChapter 6. Losses due to Fluid Friction
Chapter 6 Losses due to Fluid Friction 1 Objectives To measure the pressure drop in the straight section of smooth, rough, and packed pipes as a function of flow rate. To correlate this in terms of the
More information2.The lines that are tangent to the velocity vectors throughout the flow field are called steady flow lines. True or False A. True B.
CHAPTER 03 1. Write Newton's second law of motion. YOUR ANSWER: F = ma 2.The lines that are tangent to the velocity vectors throughout the flow field are called steady flow lines. True or False 3.Streamwise
More informationEXPERIMENT No.1 FLOW MEASUREMENT BY ORIFICEMETER
EXPERIMENT No.1 FLOW MEASUREMENT BY ORIFICEMETER 1.1 AIM: To determine the co-efficient of discharge of the orifice meter 1.2 EQUIPMENTS REQUIRED: Orifice meter test rig, Stopwatch 1.3 PREPARATION 1.3.1
More informationPressure Head: Pressure head is the height of a column of water that would exert a unit pressure equal to the pressure of the water.
Design Manual Chapter - Stormwater D - Storm Sewer Design D- Storm Sewer Sizing A. Introduction The purpose of this section is to outline the basic hydraulic principles in order to determine the storm
More informationVALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur
VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur 603 203 DEPARTMENT OF CIVIL ENGINEERING QUESTION BANK III SEMESTER CE 8302 FLUID MECHANICS Regulation 2017 Academic Year 2018 19 Prepared by Mrs.
More informationReview of pipe flow: Friction & Minor Losses
ENVE 204 Lecture -1 Review of pipe flow: Friction & Minor Losses Assist. Prof. Neslihan SEMERCİ Marmara University Department of Environmental Engineering Important Definitions Pressure Pipe Flow: Refers
More informationFLOW FRICTION CHARACTERISTICS OF CONCRETE PRESSURE PIPE
11 ACPPA TECHNICAL SERIES FLOW FRICTION CHARACTERISTICS OF CONCRETE PRESSURE PIPE This paper presents formulas to assist in hydraulic design of concrete pressure pipe. There are many formulas to calculate
More informationFluid Mechanics II 3 credit hour. Fluid flow through pipes-minor losses
COURSE NUMBER: ME 323 Fluid Mechanics II 3 credit hour Fluid flow through pipes-minor losses Course teacher Dr. M. Mahbubur Razzaque Professor Department of Mechanical Engineering BUET 1 Losses in Noncircular
More information1-Reynold s Experiment
Lect.No.8 2 nd Semester Flow Dynamics in Closed Conduit (Pipe Flow) 1 of 21 The flow in closed conduit ( flow in pipe ) is differ from this occur in open channel where the flow in pipe is at a pressure
More informationM E 320 Professor John M. Cimbala Lecture 24
M E 30 Professor John M. Cimbala Lecture 4 Today, we will: Discuss pump performance curves Discuss how to match a pump and a piping system, and do some example problems. Pump Performance a. Pump performance
More informationUNIVERSITY OF BOLTON WESTERN INTERNATIONAL COLLEGE FZE. BEng (HONS) IN CIVIL ENGINEERING SEMESTER ONE EXAMINATION 2016/2017 GROUND AND WATER STUDIES 1
OCD59 UNIVERSITY OF BOLTON WESTERN INTERNATIONAL COLLEGE FZE BEng (HONS) IN CIVIL ENGINEERING SEMESTER ONE EXAMINATION 2016/2017 GROUND AND WATER STUDIES 1 MODULE NO: CIE4009 Date: Saturday 14 January
More informationCIVE HYDRAULIC ENGINEERING PART I Pierre Julien Colorado State University
CIVE 401 - HYDRAULIC ENGINEERING PART I Pierre Julien Colorado State University Problems with and are considered moderate and those with are the longest and most difficult. In 2018 solve the problems with
More informationNew Website: M P E il Add. Mr. Peterson s Address:
Brad Peterson, P.E. New Website: http://njut009fall.weebly.com M P E il Add Mr. Peterson s Email Address: bradpeterson@engineer.com If 6 m 3 of oil weighs 47 kn calculate its If 6 m 3 of oil weighs 47
More informationS.E. (Mech.) (First Sem.) EXAMINATION, (Common to Mech/Sandwich) FLUID MECHANICS (2008 PATTERN) Time : Three Hours Maximum Marks : 100
Total No. of Questions 12] [Total No. of Printed Pages 8 Seat No. [4262]-113 S.E. (Mech.) (First Sem.) EXAMINATION, 2012 (Common to Mech/Sandwich) FLUID MECHANICS (2008 PATTERN) Time : Three Hours Maximum
More informationPiping Systems and Flow Analysis (Chapter 3)
Piping Systems and Flow Analysis (Chapter 3) 2 Learning Outcomes (Chapter 3) Losses in Piping Systems Major losses Minor losses Pipe Networks Pipes in series Pipes in parallel Manifolds and Distribution
More informationEngineers Edge, LLC PDH & Professional Training
510 N. Crosslane Rd. Monroe, Georgia 30656 (770) 266-6915 fax (678) 643-1758 Engineers Edge, LLC PDH & Professional Training Copyright, All Rights Reserved Engineers Edge, LLC Pipe Flow-Friction Factor
More informationME 305 Fluid Mechanics I. Part 8 Viscous Flow in Pipes and Ducts. Flow in Pipes and Ducts. Flow in Pipes and Ducts (cont d)
ME 305 Fluid Mechanics I Flow in Pipes and Ducts Flow in closed conduits (circular pipes and non-circular ducts) are very common. Part 8 Viscous Flow in Pipes and Ducts These presentations are prepared
More informationRate of Flow Quantity of fluid passing through any section (area) per unit time
Kinematics of Fluid Flow Kinematics is the science which deals with study of motion of liquids without considering the forces causing the motion. Rate of Flow Quantity of fluid passing through any section
More informationME 305 Fluid Mechanics I. Chapter 8 Viscous Flow in Pipes and Ducts
ME 305 Fluid Mechanics I Chapter 8 Viscous Flow in Pipes and Ducts These presentations are prepared by Dr. Cüneyt Sert Department of Mechanical Engineering Middle East Technical University Ankara, Turkey
More informationChapter 7 The Energy Equation
Chapter 7 The Energy Equation 7.1 Energy, Work, and Power When matter has energy, the matter can be used to do work. A fluid can have several forms of energy. For example a fluid jet has kinetic energy,
More informationIf a stream of uniform velocity flows into a blunt body, the stream lines take a pattern similar to this: Streamlines around a blunt body
Venturimeter & Orificemeter ELEMENTARY HYDRAULICS National Certificate in Technology (Civil Engineering) Chapter 5 Applications of the Bernoulli Equation The Bernoulli equation can be applied to a great
More information15. GRIT CHAMBER 15.1 Horizontal Velocity in Flow Though Grit Chamber
15. GRIT CHAMBER Grit chamber is the second unit operation used in primary treatment of wastewater and it is intended to remove suspended inorganic particles such as sandy and gritty matter from the wastewater.
More informationUNIVERSITY OF BOLTON WESTERN INTERNATIONAL COLLEGE FZE BENG (HONS) CIVIL ENGINEERING SEMESTER TWO EXAMINATION 2016/2017 GROUND AND WATER STUDIES 2
OCD27 UNIVERSITY OF BOLTON WESTERN INTERNATIONAL COLLEGE FZE BENG (HONS) CIVIL ENGINEERING SEMESTER TWO EXAMINATION 2016/2017 GROUND AND WATER STUDIES 2 MODULE NO: CIE5005 Date: Saturday 27 May 2017 Time:
More informationFACULTY OF CHEMICAL & ENERGY ENGINEERING FLUID MECHANICS LABORATORY TITLE OF EXPERIMENT: MINOR LOSSES IN PIPE (E4)
FACULTY OF CHEMICAL & ENERGY ENGINEERING FLUID MECHANICS LABORATORY TITLE OF EXPERIMENT: MINOR LOSSES IN PIPE (E4) 1 1.0 Objectives The objective of this experiment is to calculate loss coefficient (K
More informationLesson 37 Transmission Of Air In Air Conditioning Ducts
Lesson 37 Transmission Of Air In Air Conditioning Ducts Version 1 ME, IIT Kharagpur 1 The specific objectives of this chapter are to: 1. Describe an Air Handling Unit (AHU) and its functions (Section 37.1).
More informationChapter 8: Flow in Pipes
Objectives 1. Have a deeper understanding of laminar and turbulent flow in pipes and the analysis of fully developed flow 2. Calculate the major and minor losses associated with pipe flow in piping networks
More informationFLUID MECHANICS. Dynamics of Viscous Fluid Flow in Closed Pipe: Darcy-Weisbach equation for flow in pipes. Major and minor losses in pipe lines.
FLUID MECHANICS Dynamics of iscous Fluid Flow in Closed Pipe: Darcy-Weisbach equation for flow in pipes. Major and minor losses in pipe lines. Dr. Mohsin Siddique Assistant Professor Steady Flow Through
More informationReservoir Oscillations with Through Flow
American Journal of Environmental Sciences 3 (): 37-42, 27 ISSN 553-345X 27 Science Publications Reservoir Oscillations with Through Flow A. A. Khan 28 Lowry Hall, epartment of Civil Engineering, Clemson
More informationChapter 1 INTRODUCTION
Chapter 1 INTRODUCTION 1-1 The Fluid. 1-2 Dimensions. 1-3 Units. 1-4 Fluid Properties. 1 1-1 The Fluid: It is the substance that deforms continuously when subjected to a shear stress. Matter Solid Fluid
More information1.060 Engineering Mechanics II Spring Problem Set 8
1.060 Engineering Mechanics II Spring 2006 Due on Monday, May 1st Problem Set 8 Important note: Please start a new sheet of paper for each problem in the problem set. Write the names of the group members
More informationSTEADY FLOW THROUGH PIPES DARCY WEISBACH EQUATION FOR FLOW IN PIPES. HAZEN WILLIAM S FORMULA, LOSSES IN PIPELINES, HYDRAULIC GRADE LINES AND ENERGY
STEADY FLOW THROUGH PIPES DARCY WEISBACH EQUATION FOR FLOW IN PIPES. HAZEN WILLIAM S FORMULA, LOSSES IN PIPELINES, HYDRAULIC GRADE LINES AND ENERGY LINES 1 SIGNIFICANCE OF CONDUITS In considering the convenience
More informationUniform Channel Flow Basic Concepts. Definition of Uniform Flow
Uniform Channel Flow Basic Concepts Hydromechanics VVR090 Uniform occurs when: Definition of Uniform Flow 1. The depth, flow area, and velocity at every cross section is constant 2. The energy grade line,
More informationLOSSES DUE TO PIPE FITTINGS
LOSSES DUE TO PIPE FITTINGS Aim: To determine the losses across the fittings in a pipe network Theory: The resistance to flow in a pipe network causes loss in the pressure head along the flow. The overall
More information5 ENERGY EQUATION OF FLUID MOTION
5 ENERGY EQUATION OF FLUID MOTION 5.1 Introduction In order to develop the equations that describe a flow, it is assumed that fluids are subject to certain fundamental laws of physics. The pertinent laws
More informationWater Circuit Lab. The pressure drop along a straight pipe segment can be calculated using the following set of equations:
Water Circuit Lab When a fluid flows in a conduit, there is friction between the flowing fluid and the pipe walls. The result of this friction is a net loss of energy in the flowing fluid. The fluid pressure
More informationApplied Fluid Mechanics
Applied Fluid Mechanics 1. The Nature of Fluid and the Study of Fluid Mechanics 2. Viscosity of Fluid 3. Pressure Measurement 4. Forces Due to Static Fluid 5. Buoyancy and Stability 6. Flow of Fluid and
More informationAtmospheric pressure. 9 ft. 6 ft
Name CEE 4 Final Exam, Aut 00; Answer all questions; 145 points total. Some information that might be helpful is provided below. A Moody diagram is printed on the last page. For water at 0 o C (68 o F):
More informationHydraulics of pipelines
Hydraulics of pipelines K 4 HYAE Hydraulics of pipelines Application of Bernoulli equation BE continuity equation CE g g p h g g p h loss head (losses): friction losses t (in distance L) local losses m
More informationHydraulics Part: Open Channel Flow
Hydraulics Part: Open Channel Flow Tutorial solutions -by Dr. K.N. Dulal Uniform flow 1. Show that discharge through a channel with steady flow is given by where A 1 and A 2 are the sectional areas of
More informationHydraulic Design Of Polyethylene Pipes
Hydraulic Design Of Polyethylene Pipes Waters & Farr polyethylene pipes offer a hydraulically smooth bore that provides excellent flow characteristics. Other advantages of Waters & Farr polyethylene pipes,
More informationFluid Mechanics c) Orificemeter a) Viscous force, Turbulence force, Compressible force a) Turbulence force c) Integration d) The flow is rotational
Fluid Mechanics 1. Which is the cheapest device for measuring flow / discharge rate. a) Venturimeter b) Pitot tube c) Orificemeter d) None of the mentioned 2. Which forces are neglected to obtain Euler
More informationFinal 1. (25) 2. (10) 3. (10) 4. (10) 5. (10) 6. (10) TOTAL = HW = % MIDTERM = % FINAL = % COURSE GRADE =
MAE101B: Advanced Fluid Mechanics Winter Quarter 2017 http://web.eng.ucsd.edu/~sgls/mae101b_2017/ Name: Final This is a three hour open-book exam. Please put your name on the top sheet of the exam. Answer
More informationEFFECT OF BAFFLE BLOCKS ON THE PERFORMANCE OF RADIAL HYDRAULIC JUMP
Fourth International Water Technology Conference IWTC 99, Alexandria, Egypt 255 EFFECT OF BAFFLE BLOCKS ON THE PERFORMANCE OF RADIAL HYDRAULIC JUMP O. S. Rageh Irrigation & Hydraulics Dept., Faculty of
More informationMass of fluid leaving per unit time
5 ENERGY EQUATION OF FLUID MOTION 5.1 Eulerian Approach & Control Volume In order to develop the equations that describe a flow, it is assumed that fluids are subject to certain fundamental laws of physics.
More informationExam #2: Fluid Kinematics and Conservation Laws April 13, 2016, 7:00 p.m. 8:40 p.m. in CE 118
CVEN 311-501 (Socolofsky) Fluid Dynamics Exam #2: Fluid Kinematics and Conservation Laws April 13, 2016, 7:00 p.m. 8:40 p.m. in CE 118 Name: : UIN: : Instructions: Fill in your name and UIN in the space
More informationUNIT -5. Dimensional Analysis. Model Analysis. Fundamental Dimensions Dimensional Homogeneity Method of analysis
UNIT -5 Dimensional Analysis Fundamental Dimensions Dimensional Homogeneity Method of analysis Rayleigh Method Buckingham pi theorem Method Model Analysis Dimensionless parameters Similitude and model
More informationCIE4491 Lecture. Hydraulic design
CIE4491 Lecture. Hydraulic design Marie-claire ten Veldhuis 19-9-013 Delft University of Technology Challenge the future Hydraulic design of urban stormwater systems Focus on sewer pipes Pressurized and
More informationCHAPTER THREE FLUID MECHANICS
CHAPTER THREE FLUID MECHANICS 3.1. Measurement of Pressure Drop for Flow through Different Geometries 3.. Determination of Operating Characteristics of a Centrifugal Pump 3.3. Energy Losses in Pipes under
More informationLecture 4. Lab this week: Cartridge valves Flow divider Properties of Hydraulic Fluids. Lab 8 Sequencing circuit Lab 9 Flow divider
91 Lecture 4 Lab this week: Lab 8 Sequencing circuit Lab 9 Flow divider Cartridge valves Flow divider Properties of Hydraulic Fluids Viscosity friction and leakage Bulk modulus Inertance Cartridge Valves
More informationLecture 3 The energy equation
Lecture 3 The energy equation Dr Tim Gough: t.gough@bradford.ac.uk General information Lab groups now assigned Timetable up to week 6 published Is there anyone not yet on the list? Week 3 Week 4 Week 5
More informationBasic Hydraulics. Rabi H. Mohtar ABE 325
Basic Hydraulics Rabi H. Mohtar ABE 35 The river continues on its way to the sea, broken the wheel of the mill or not. Khalil Gibran The forces on moving body of fluid mass are:. Inertial due to mass (ρ
More informationHydraulic resistance at sudden pipe expansion-the influence of cavitation
Hydraulic resistance at sudden pipe expansion-the influence of cavitation I Department of Hydraulic Structures and Water Resources Management, Technical University Graz 2 Department of Hydraulic Machinery,
More informationStage Discharge Tabulation for Only Orifice Flow
Stage Discharge Tabulation for Only Orifice Flow DEPTH STAGE DISCHARGE (meters) (feet) (meters) (feet) (m 3 /s) (ft 3 /s) 0 0.20 0.40 0.60 0.80 1.00 1.20 1.40 1.60 1.80 2.00 0.7 1.3 2.0 2.6 3.3 3.9 4.6
More informationModule 15 : Grit Chamber. Lecture 19 : Grit Chamber
1 P age Module 15 : Grit Chamber Lecture 19 : Grit Chamber 2 P age Grit chamber is the second unit operation used in primary treatment of wastewater and it is intended to remove suspended inorganic particles
More informationSourabh V. Apte. 308 Rogers Hall
Sourabh V. Apte 308 Rogers Hall sva@engr.orst.edu 1 Topics Quick overview of Fluid properties, units Hydrostatic forces Conservation laws (mass, momentum, energy) Flow through pipes (friction loss, Moody
More informationESSEX COUNTY COLLEGE Engineering Technologies and Computer Sciences Division MET 215 Fluid Mechanics Course Outline
ESSEX COUNTY COLLEGE Engineering Technologies and Computer Sciences Division MET 215 Fluid Mechanics Course Outline Course Number & Name: MET 215 Fluid Mechanics Credit Hours: 3.0 Contact Hours: 4.5 Lecture:
More informationPIPING SYSTEMS. Pipe and Tubing Standards Sizes for pipes and tubes are standardized. Pipes are specified by a nominal diameter and a schedule number.
PIPING SYSTEMS In this chapter we will review some of the basic concepts associated with piping systems. Topics that will be considered in this chapter are - Pipe and tubing standards - Effective and hydraulic
More informationFLUID MECHANICS. Chapter 3 Elementary Fluid Dynamics - The Bernoulli Equation
FLUID MECHANICS Chapter 3 Elementary Fluid Dynamics - The Bernoulli Equation CHAP 3. ELEMENTARY FLUID DYNAMICS - THE BERNOULLI EQUATION CONTENTS 3. Newton s Second Law 3. F = ma along a Streamline 3.3
More informationChapter Four Hydraulic Machines
Contents 1- Introduction. - Pumps. Chapter Four Hydraulic Machines (لفرع الميكانيك العام فقط ( Turbines. -3 4- Cavitation in hydraulic machines. 5- Examples. 6- Problems; sheet No. 4 (Pumps) 7- Problems;
More informationREE 307 Fluid Mechanics II. Lecture 1. Sep 27, Dr./ Ahmed Mohamed Nagib Elmekawy. Zewail City for Science and Technology
REE 307 Fluid Mechanics II Lecture 1 Sep 27, 2017 Dr./ Ahmed Mohamed Nagib Elmekawy Zewail City for Science and Technology Course Materials drahmednagib.com 2 COURSE OUTLINE Fundamental of Flow in pipes
More informationUNIVERSITY OF BOLTON WESTERN INTERNATIONAL COLLEGE, RAS AL KHAIMAH BENG (HONS) CIVIL ENGINEERING SEMESTER TWO EXAMINATION 2014/2015
OCD54 UNIVERSITY OF BOLTON WESTERN INTERNATIONAL COLLEGE, RAS AL KHAIMAH BENG (HONS) CIVIL ENGINEERING SEMESTER TWO EXAMINATION 2014/2015 GROUND AND WATER STUDIES 2 MODULE NO: CIE5005 Date: Thursday 10
More informationEXPERIMENT NO: F5. Losses in Piping Systems
SJSU ME115 - THERMAL ENGINEERING LAB EXPERIMENT NO: F5 Losses in Piping Systems Objective One of the most common problems in fluid mechanics is the estimation of pressure loss. It is the objective of this
More informationFLOW MEASUREMENT IN PIPES EXPERIMENT
University of Leicester Engineering Department FLOW MEASUREMENT IN PIPES EXPERIMENT Page 1 FORMAL LABORATORY REPORT Name of the experiment: FLOW MEASUREMENT IN PIPES Author: Apollin nana chaazou Partner
More informationClosed duct flows are full of fluid, have no free surface within, and are driven by a pressure gradient along the duct axis.
OPEN CHANNEL FLOW Open channel flow is a flow of liquid, basically water in a conduit with a free surface. The open channel flows are driven by gravity alone, and the pressure gradient at the atmospheric
More informationEXPERIMENT II - FRICTION LOSS ALONG PIPE AND LOSSES AT PIPE FITTINGS
MM 30 FLUID MECHANICS II Prof. Dr. Nuri YÜCEL Yrd. Doç. Dr. Nureddin DİNLER Arş. Gör. Dr. Salih KARAASLAN Arş. Gör. Fatih AKTAŞ EXPERIMENT II - FRICTION LOSS ALONG PIPE AND LOSSES AT PIPE FITTINGS A. Objective:
More informationPIPE FLOW. The Energy Equation. The first law of thermodynamics for a system is, in words = +
The Energy Equation PIPE FLOW The first law of thermodynamics for a system is, in words Time rate of increase of the total storage energy of the t Net time rate of energy addition by heat transfer into
More informationSignature: (Note that unsigned exams will be given a score of zero.)
Neatly print your name: Signature: (Note that unsigned exams will be given a score of zero.) Circle your lecture section (-1 point if not circled, or circled incorrectly): Prof. Dabiri Prof. Wassgren Prof.
More information1.060 Engineering Mechanics II Spring Problem Set 4
1.060 Engineering Mechanics II Spring 2006 Due on Monday, March 20th Problem Set 4 Important note: Please start a new sheet of paper for each problem in the problem set. Write the names of the group members
More information