Motion. ( (3 dim) ( (1 dim) dt. Equations of Motion (Constant Acceleration) Newton s Law and Weight. Magnitude of the Frictional Force


 Kathleen York
 3 years ago
 Views:
Transcription
1 Insucos: ield/mche PHYSICS DEPARTMENT PHY 48 Em Sepeme 6, 4 Nme pin, ls fis: Signue: On m hono, I he neihe gien no eceied unuhoied id on his eminion. YOUR TEST NUMBER IS THE 5DIGIT NUMBER AT THE TOP O EACH PAGE. Code ou es nume on ou nswe shee use lines 76 8 on he nswe shee fo he 5digi nume. Code ou nme on ou nswe shee. DARKEN CIRCLES COMPLETELY. Code ou UID nume on ou nswe shee. Pin ou nme on his shee nd sign i lso. 3 Do ll scch wok nwhee on his em h ou like. Cicle ou nswes on he es fom. A he end of he es, his em pinou is o e uned in. No cedi will e gien wihou oh nswe shee nd pinou. 4 Blcken he cicle of ou inended nswe compleel, using # pencil o lue o lck ink. Do no mke n s mks o some nswes m e couned s incoec. 5 The nswes e ounded off. Choose he closes o ec. Thee is no penl fo guessing. If ou eliee h no lised nswe is coec, lee he fom lnk. 6 Hnd in he nswe shee sepel. Use g = 9.8 m/s
2 PHY48 ll 4 PHY48 Em omul Shee Vecos k j i k j i Mgniudes: Scl Poduc: Mgniude: cos = ngle eween nd Veco Poduc: k j i Mgniude: sin = smlles ngle eween nd Moion Displcemen: dimension 3 dimensions Aege Veloci: e dim e 3 dim Aege Speed: s e = ol disnce/ Insnneous Veloci: d d dim d d 3 dim Relie Veloci: BC AB AC 3 dim Aege Acceleion: e dim e 3 dim Insnneous Acceleion: d d d d dim d d d d 3 dim Equions of Moion Consn Acceleion Newon s Lw nd Weigh m ne m = mss Weigh ne he sufce of he Eh = W = mg use g = 9.8 m/s Mgniude of he icionl oce s = sic coefficien of ficion, k = kineic coefficien of ficion Sic: N s s f m Kineic: N k k f N is he mgniude of he noml foce Unifom Cicul Moion Rdius R, Tngenil Speed = R, Angul Veloci Cenipel Acceleion & oce: R R mr R m Peiod: R T Pojecile Moion hoionl sufce ne Eh, = iniil speed, = iniil ngle wih hoionl Rnge: g R sin M Heigh: g H sin Time of fligh: g f sin Qudic omul If: c Then: c 4 Pge of
3 . A in eling long he is is iniill he poin i =. The in hen els km o he Es i.e., igh s shown in he figue. I hen eeses diecion nd els disnce d o he Wes i.e., lef o he finl poin f. If he in s ege speed fo his ip ws 5 km/h, nd is ege eloci fo he ip ws km/h, wh ws he disnce d in km? W Iniil Posiion = i is E. A in eling long he is is iniill he poin i =. The in hen els km o he Es i.e., igh s shown in he figue. I hen eeses diecion nd els disnce d o he Wes i.e., lef o he finl poin f. If he in s ege speed fo his ip ws km/h, nd is ege eloci fo he ip ws km/h, wh ws he disnce d in km? W Iniil Posiion = i is E 3. A in eling long he is is iniill he poin i =. The in hen els km o he Es i.e., igh s shown in he figue. I hen eeses diecion nd els disnce d o he Wes i.e., lef o he finl poin f. If he in s ege speed fo his ip ws 3 km/h, nd is ege eloci fo he ip ws km/h, wh ws he disnce d in km? W Iniil Posiion = i is E 4. An ojec is elesed fom es = ne he sufce of n unknown plne no Eh nd flls mees duing he ime inel fom = s o = s. Ignoing mospheic esisnce, how f does i fll in m duing he ime inel fom = s o = 3 s?.5 m 3. m m m 5.9 m 5. An ojec is elesed fom es = ne he sufce of n unknown plne no Eh nd flls mees duing he ime inel fom = s o = s. Ignoing mospheic esisnce, how f does i fll in m duing he ime inel fom = s o = 4 s? 3. m.5 m m m 5.9 m 6. An ojec is elesed fom es = ne he sufce of n unknown plne no Eh nd flls mees duing he ime inel fom = s o = s. Ignoing mospheic esisnce, how f does i fll in m duing he ime inel fom = s o = 5 s? 5.5 m.5 m 3 3. m m 5.9 m 7. A moois dies long sigh od consn speed of 8 m/s. A = she psses pked mooccle police office, nd he office kes off fe he wih cceleion, =, whee is consn nd is he ime i.e., he cceleion ies linel wih ime. If he office minins his e of cceleion, wh is he speed of he police office when he eches he moois in m/s?
4 8. A moois dies long sigh od consn speed of 85 m/s. A = she psses pked mooccle police office, nd he office kes off fe he wih cceleion, =, whee is consn nd is he ime i.e., he cceleion ies linel wih ime. If he office minins his e of cceleion, wh is he speed of he police office when he eches he moois in m/s? A moois dies long sigh od consn speed of 9 m/s. A = she psses pked mooccle police office, nd he office kes off fe he wih cceleion, =, whee is consn nd is he ime i.e., he cceleion ies linel wih ime. If he office minins his e of cceleion, wh is he speed of he police office when he eches he moois in m/s? Ne he sufce of he Eh suspension idge is heigh H oe he leel se of goge. A sone is hown o dopped fom he idge. Ignoe i esisnce. If ou dop he sone fom es, i kes 3 seconds fo i o fll o he se of he goge. If ou how he sme sone sigh down wih speed of m/s, how long in s efoe i his he gound? Ne he sufce of he Eh suspension idge is heigh H oe he leel se of goge. A sone is hown o dopped fom he idge. Ignoe i esisnce. If ou dop he sone fom es, i kes 3 seconds fo i o fll o he se of he goge. If ou how he sme sone sigh down wih speed of 5 m/s, how long in s efoe i his he gound? Ne he sufce of he Eh suspension idge is heigh H oe he leel se of goge. A sone is hown o dopped fom he idge. Ignoe i esisnce. If ou dop he sone fom es, i kes 3 seconds fo i o fll o he se of he goge. If ou how he sme sone sigh down wih speed of m/s, how long in s efoe i his he gound? If he componen of he eco A shown in he figue is nd he ngle i mkes wih he is = 5, wh is he componen? is A is 4. If he componen of he eco A shown in he figue is nd he ngle i mkes wih he is = 6, wh is he componen? is A is
5 5. If he componen of he eco A shown in he figue is nd he ngle i mkes wih he is = 7, wh is he componen? is A is 6. If A+ B = C, A B = C, nd C = î ĵ, hen wh is he lue of he scl poduc A B? If A+ B = C, A B = C, nd C = î 4ĵ, hen wh is he lue of he scl poduc A B? If A+ B = C, A B = C, nd C = î 6ĵ, hen wh is he lue of he scl poduc A B? Two ecos he he sme mgniude. If he mgniude of hei eco poduc is wice he mgniude of hei scl poduc, wh is he ngle eween hem? Two ecos he he sme mgniude. If he mgniude of hei eco poduc is hee imes he mgniude of hei scl poduc, wh is he ngle eween hem? Two ecos he he sme mgniude. If he mgniude of hei eco poduc is onehlf he mgniude of hei scl poduc, wh is he ngle eween hem? A pojecile is lunched fom he posiion = = n ngle of wih he hoionl is. I eches miumu heigh H nd els mimum hoionl disnce R efoe lnding ck =. If H = R, wh is he ngle? A pojecile is lunched fom he posiion = = n ngle of wih he hoionl is. I eches miumu heigh H nd els mimum hoionl disnce R efoe lnding ck =. If H = R, wh is he ngle? A pojecile is lunched fom he posiion = = n ngle of wih he hoionl is. I eches miumu heigh H nd els mimum hoionl disnce R efoe lnding ck =. If H = R/, wh is he ngle?
6 5. A eng is hown hoionll fom dom oom window. The heigh of he window is h = mees oe he gound s shown in he figue. If he eng s eloci jus efoe impc wih he gound is = 3 elow he hoionl, wh hoionl disnce d in m fom he dom diecl elow he window fom which i ws hown does he enghi he gound? Ignoe i esisnce. Dom h d gound A eng is hown hoionll fom dom oom window. The heigh of he window is h = mees oe he gound s shown in he figue. If he eng s eloci jus efoe impc wih he gound is = 35 elow he hoionl, wh hoionl disnce d in m fom he dom diecl elow he window fom which i ws hown does he enghi he gound? Ignoe i esisnce. Dom h d gound A eng is hown hoionll fom dom oom window. The heigh of he window is h = mees oe he gound s shown in he figue. If he eng s eloci jus efoe impc wih he gound is = 4 elow he hoionl, wh hoionl disnce d in m fom he dom diecl elow he window fom which i ws hown does he enghi he gound? Ignoe i esisnce. Dom h d gound Jck wns o ow diecl coss ie fom he es shoe o poin on he wes shoe, s shown in he figue. The widh of he ie is 5 m nd he cuen flows fom noh o souh.5 m/s. The ip kes Jck 4 minues. A wh speed in m/s wih espec o he sill we is Jck le o ow? We Cuen Jck N W E Shoe Shoe S 9. Jck wns o ow diecl coss ie fom he es shoe o poin on he wes shoe, s shown in he figue. The widh of he ie is 5 m nd he cuen flows fom noh o souh. m/s. The ip kes Jck 4 minues. A wh speed in m/s wih espec o he sill we is Jck le o ow? We Cuen Jck N W E Shoe Shoe S
7 3. Jck wns o ow diecl coss ie fom he es shoe o poin on he wes shoe, s shown in he figue. The widh of he ie is 5 m nd he cuen flows fom noh o souh.5 m/s. The ip kes Jck 4 minues. A wh speed in m/s wih espec o he sill we is Jck le o ow? We Cuen Jck N W E Shoe Shoe S 3. A smll o els fo min 3 km noh nd hen els fo 4 min 4 km es. Wh is he mgniude of he o s ege eloci in km/h fo he onehou ip? A smll o els fo min 6 km noh nd hen els fo 4 min 8 km es. Wh is he mgniude of he o s ege eloci in km/h fo he onehou ip? A smll o els fo min 9 km noh nd hen els fo 4 min km es. Wh is he mgniude of he o s ege eloci in km/h fo he onehou ip? A i is dshing hough he foes. Is posiion s funcion of ime is gien = 3 5î+3 3 ĵ, whee posiion is mesued in mees nd ime in seconds. ind he mgniude of he i s eloci in m/s = s A i is dshing hough he foes. Is posiion s funcion of ime is gien = 3 5î+3 3 ĵ, whee posiion is mesued in mees nd ime in seconds. ind he mgniude of he i s eloci in m/s = s A i is dshing hough he foes. Is posiion s funcion of ime is gien = 3 5î+3 3 ĵ, whee posiion is mesued in mees nd ime in seconds. ind he mgniude of he i s eloci in m/s =.5 s Ne he sufce of he Eh, child pulls sled up snow hill consn speed. Wh is he mss of he sled in kg if he child is pulling wih foce of 9.6 N nd he slope s ngle is 3? Neglec ficion Ne he sufce of he Eh, child pulls sled up snow hill consn speed. Wh is he mss of he sled in kg if he child is pulling wih foce of 9.4 N nd he slope s ngle is 3? Neglec ficion
8 39. Ne he sufce of he Eh, child pulls sled up snow hill consn speed. Wh is he mss of he sled in kg if he child is pulling wih foce of 39. N nd he slope s ngle is 3? Neglec ficion Ne he sufce of he Eh, suden is using simple pulle o lif ce of mss M = 3 kg fom es o heigh H pulling on he ope wih consn foce s shown in he figue. If he eking sengh of he ope is 4 N, wh is he minimum ime in s equied fo he suden o hul he ce o heigh H = m? Assume h he pulle is mssless nd ficionless H ope M ce gound 4. Ne he sufce of he Eh, suden is using simple pulle o lif ce of mss M = 35 kg fom es o heigh H pulling on he ope wih consn foce s shown in he figue. If he eking sengh of he ope is 4 N, wh is he minimum ime in s equied fo he suden o hul he ce o heigh H = m? Assume h he pulle is mssless nd ficionless H ope M ce gound 4. Ne he sufce of he Eh, suden is using simple pulle o lif ce of mss M = 4 kg fom es o heigh H pulling on he ope wih consn foce s shown in he figue. If he eking sengh of he ope is 4 N, wh is he minimum ime in s equied fo he suden o hul he ce o heigh H = m? Assume h he pulle is mssless nd ficionless H ope M ce gound 43. Ne he sufce of he Eh, wo locks A nd B e es on le s shown in he figue. If M A = kg nd he mgniude of he noml foce eeed he le on lock B is 9.4 N, wh is he mss of lock B in kg? A B Ne he sufce of he Eh, wo locks A nd B e es on le s shown in he figue. If M A = kg nd he mgniude of he noml foce eeed he le on lock B is 39. N, wh is he mss of lock B in kg? A B
9 45. Ne he sufce of he Eh, wo locks A nd B e es on le s shown in he figue. If M A = kg nd he mgniude of he noml foce eeed he le on lock B is 49. N, wh is he mss of lock B in kg? A B Conside mss M = kg suspended e ligh sing fom he ceiling of ilwcne he sufceof he Eh. The c hs consn cceleion s shownin he figue, cusing he mss o hng n ngle wih he eicl. If he cceleion of he ilw c is = 5 m/s, wh is he ension in he sing in N? Conside mss M = 3 kg suspended e ligh sing fom he ceiling of ilwcne he sufceof he Eh. The c hs consn cceleion s shownin he figue, cusing he mss o hng n ngle wih he eicl. If he cceleion of he ilw c is = 5 m/s, wh is he ension in he sing in N? Conside mss M = 4 kg suspended e ligh sing fom he ceiling of ilwcne he sufceof he Eh. The c hs consn cceleion s shownin he figue, cusing he mss o hng n ngle wih he eicl. If he cceleion of he ilw c is = 5 m/s, wh is he ension in he sing in N? Ne he sufce of he Eh, lock A, wih mss m A, is iniill es on hoionl floo. Block B, wih mss m B, is iniill es on he hoionl op sufce of A. The sum of he wo msses is m A + m B = kg. Block A is pulled wih hoionl foce s shown in he figue. If he coefficien of sic ficion eween he wo locks is µ s =.8, nd if lock B egins o m B m A slide off lock A when is gee hn 98 N, wh is he kineic coefficien of ficion, µ k, eween lock A nd he floo? Ne he sufce of he Eh, lock A, wih mss m A, is iniill es on hoionl floo. Block B, wih mss m B, is iniill es on he hoionl op sufce of A. The sum of he wo msses is m A + m B = kg. Block A is pulled wih hoionl foce s shown in he figue. If he coefficien of sic ficion eween he wo locks is µ s =.7, nd if lock B egins o m B m A slide off lock A when is gee hn 98 N, wh is he kineic coefficien of ficion, µ k, eween lock A nd he floo? Ne he sufce of he Eh, lock A, wih mss m A, is iniill es on hoionl floo. Block B, wih mss m B, is iniill es on he hoionl op sufce of A. The sum of he wo msses is m A + m B = kg. Block A is pulled wih hoionl foce s shown in he figue. If he coefficien of sic ficion eween he wo locks is µ s =.6, nd if lock B egins o m B m A slide off lock A when is gee hn 98 N, wh is he kineic coefficien of ficion, µ k, eween lock A nd he floo?
10 5. Ne he sufce of he Eh lock of mss M = kg is pushed long he floo consn speed V n eenl foce e = N pplied downwd ngle = 5 elie o he hoionl s shown in he figue. Wh is he coefficien of kineic ficion µ k eween he lock nd he floo? e M V Ne he sufce of he Eh lock of mss M = kg is pushed long he floo consn speed V n eenl foce e = N pplied downwd ngle = 3 elie o he hoionl s shown in he figue. Wh is he coefficien of kineic ficion µ k eween he lock nd he floo? e M V Ne he sufce of he Eh lock of mss M = kg is pushed long he floo consn speed V n eenl foce e = N pplied downwd ngle = 4 elie o he hoionl s shown in he figue. Wh is he coefficien of kineic ficion µ k eween he lock nd he floo? e M V A mn wih weigh of N dies c speed = 4 m/s oe cicul hill nd hen ino cicul lle wih he sme dius, u wih speed, sshown in he figue. A he op ofhe hill, he noml foce on he mn fom he c se is eo. If he mgniude of he noml foce on he mn fom he se when he c psses hough he oom of he lle is 5 N, wh is he speed in m/s? Rdius Rdius A mn wih weigh of N dies c speed = 4 m/s oe cicul hill nd hen ino cicul lle wih he sme dius, u wih speed, sshown in he figue. A he op ofhe hill, he noml foce on he mn fom he c se is eo. If he mgniude of he noml foce on he mn fom he se when he c psses hough he oom of he lle is, N, wh is he speed in m/s? Rdius Rdius A mn wih weigh of N dies c speed = 4 m/s oe cicul hill nd hen ino cicul lle wih he sme dius, u wih speed, sshown in he figue. A he op ofhe hill, he noml foce on he mn fom he c se is eo. If he mgniude of he noml foce on he mn fom he se when he c psses hough he oom of he lle is,7 N, wh is he speed in m/s? Rdius Rdius A cnil ide ne he sufce of he Eh consiss of he ides snding gins he inside wll of clindicl oom wih dius R = 5. m. The oom spins ou he eicl clinde is wih consn speed. Once i is up o speed, he floo of he oom flls w. If he clindicl oom complees 6 eoluions pe minue, wh minimum coefficien of sic ficion eween he ides nd he wll will keep hem fom dopping wih he floo? ω
11 OLLOWING GROUPS O QUESTIONS WILL BE SELECTED AS ONE GROUP ROM EACH TYPE TYPE Q# S Q# S Q# S 3 TYPE Q# S 4 Q# S 5 Q# S 6 TYPE 3 Q# S 7 Q# S 8 Q# S 9 TYPE 4 Q# S Q# S Q# S TYPE 5 Q# S 3 Q# S 4 Q# S 5 TYPE 6 Q# S 6 Q# S 7 Q# S 8 TYPE 7 Q# S 9 Q# S Q# S TYPE 8 Q# S Q# S 3 Q# S 4 TYPE 9 Q# S 5 Q# S 6 Q# S 7 TYPE Q# S 8 Q# S 9 Q# S 3 TYPE Q# S 3 Q# S 3 Q# S A cnil ide ne he sufce of he Eh consiss of he ides snding gins he inside wll of clindicl oom wih dius R = 5. m. The oom spins ou he eicl clinde is wih consn speed. Once i is up o speed, he floo of he oom flls w. If he clindicl oom complees 8 eoluions pe minue, wh minimum coefficien of sic ficion eween he ides nd he wll will keep hem fom dopping wih he floo? ω A cnil ide ne he sufce of he Eh consiss of he ides snding gins he inside wll of clindicl oom wih dius R = 5. m. The oom spins ou he eicl clinde is wih consn speed. Once i is up o speed, he floo of he oom flls w. If he clindicl oom complees eoluions pe minue, wh minimum coefficien of sic ficion eween he ides nd he wll will keep hem fom dopping wih he floo? ω
12 TYPE Q# S 34 Q# S 35 Q# S 36 TYPE 3 Q# S 37 Q# S 38 Q# S 39 TYPE 4 Q# S 4 Q# S 4 Q# S 4 TYPE 5 Q# S 43 Q# S 44 Q# S 45 TYPE 6 Q# S 46 Q# S 47 Q# S 48 TYPE 7 Q# S 49 Q# S 5 Q# S 5 TYPE 8 Q# S 5 Q# S 53 Q# S 54 TYPE 9 Q# S 55 Q# S 56 Q# S 57 TYPE Q# S 58 Q# S 59 Q# S 6
Axis. Axis. Axis. Solid cylinder (or disk) about. Hoop about. Annular cylinder (or ring) about central axis. central axis.
Insucos: Fiel/che/Deweile PYSICS DEPATENT PY 48 Em ch 5, 5 Nme pin, ls fis: Signue: On m hono, I he neihe gien no eceie unuhoie i on his eminion. YOU TEST NUBE IS TE 5DIGIT NUBE AT TE TOP OF EAC PAGE.
More informationCh.4 Motion in 2D. Ch.4 Motion in 2D
Moion in plne, such s in he sceen, is clled 2dimensionl (2D) moion. 1. Posiion, displcemen nd eloci ecos If he picle s posiion is ( 1, 1 ) 1, nd ( 2, 2 ) 2, he posiions ecos e 1 = 1 1 2 = 2 2 Aege eloci
More informationPhysics 201, Lecture 5
Phsics 1 Lecue 5 Tod s Topics n Moion in D (Chp 4.14.3): n D Kinemicl Quniies (sec. 4.1) n D Kinemics wih Consn Acceleion (sec. 4.) n D Pojecile (Sec 4.3) n Epeced fom Peiew: n Displcemen eloci cceleion
More informationScience Advertisement Intergovernmental Panel on Climate Change: The Physical Science Basis 2/3/2007 Physics 253
Science Adeisemen Inegoenmenl Pnel on Clime Chnge: The Phsicl Science Bsis hp://www.ipcc.ch/spmfeb7.pdf /3/7 Phsics 53 hp://www.fonews.com/pojecs/pdf/spmfeb7.pdf /3/7 Phsics 53 3 Sus: Uni, Chpe 3 Vecos
More informationPHY2048 Exam 1 Formula Sheet Vectors. Motion. v ave (3 dim) ( (1 dim) dt. ( (3 dim) Equations of Motion (Constant Acceleration)
Insrucors: Field/Mche PHYSICS DEPATMENT PHY 48 Em Ferur, 5 Nme prin, ls firs: Signure: On m honor, I he neiher gien nor receied unuhoried id on his eminion. YOU TEST NUMBE IS THE 5DIGIT NUMBE AT THE TOP
More information1. Kinematics of Particles
1. Kinemics o Picles 1.1 Inoducion o Dnmics Dnmics  Kinemics: he sud o he geome o moion; ele displcemen, eloci, cceleion, nd ime, wihou eeence o he cuse o he moion.  Kineics: he sud o he elion eising
More informationAxis Thin spherical shell about any diameter
Insucos: Fiel/che/Deweile PYSICS DEPATET PY 48 Finl Em Apil 5, 5 me pin, ls fis: Signue: On m hono, I he neihe gien no eceie unuhoie i on his eminion. YOU TEST UBE IS TE 5DIGIT UBE AT TE TOP OF EAC PAGE.
More informationMotion on a Curve and Curvature
Moion on Cue nd Cuue his uni is bsed on Secions 9. & 9.3, Chpe 9. All ssigned edings nd execises e fom he exbook Objecies: Mke cein h you cn define, nd use in conex, he ems, conceps nd fomuls lised below:
More information() t. () t r () t or v. ( t) () () ( ) = ( ) or ( ) () () () t or dv () () Section 10.4 Motion in Space: Velocity and Acceleration
Secion 1.4 Moion in Spce: Velociy nd Acceleion We e going o dive lile deepe ino somehing we ve ledy inoduced, nmely () nd (). Discuss wih you neighbo he elionships beween posiion, velociy nd cceleion you
More informationME 141. Engineering Mechanics
ME 141 Engineeing Mechnics Lecue 13: Kinemics of igid bodies hmd Shhedi Shkil Lecue, ep. of Mechnicl Engg, UET Emil: sshkil@me.bue.c.bd, shkil6791@gmil.com Websie: eche.bue.c.bd/sshkil Couesy: Veco Mechnics
More information2D Motion WS. A horizontally launched projectile s initial vertical velocity is zero. Solve the following problems with this information.
Nme D Moion WS The equions of moion h rele o projeciles were discussed in he Projecile Moion Anlsis Acii. ou found h projecile moes wih consn eloci in he horizonl direcion nd consn ccelerion in he ericl
More informationLECTURE 5. is defined by the position vectors r, 1. and. The displacement vector (from P 1 to P 2 ) is defined through r and 1.
LECTURE 5 ] DESCRIPTION OF PARTICLE MOTION IN SPACE The displcemen, veloci nd cceleion in D moion evel hei veco nue (diecion) houh he cuion h one mus p o hei sin. Thei full veco menin ppes when he picle
More informationA 1.3 m 2.5 m 2.8 m. x = m m = 8400 m. y = 4900 m 3200 m = 1700 m
PHYS : Soluions o Chper 3 Home Work. SSM REASONING The displcemen is ecor drwn from he iniil posiion o he finl posiion. The mgniude of he displcemen is he shores disnce beween he posiions. Noe h i is onl
More informationAns: In the rectangular loop with the assigned direction for i2: di L dt , (1) where (2) a) At t = 0, i1(t) = I1U(t) is applied and (1) becomes
omewok # P73 ecngul loop of widh w nd heigh h is siued ne ve long wie cing cuen i s in Fig 7 ssume i o e ecngul pulse s shown in Fig 7 Find he induced cuen i in he ecngul loop whose selfinducnce is
More informationCircuits 24/08/2010. Question. Question. Practice Questions QV CV. Review Formula s RC R R R V IR ... Charging P IV I R ... E Pt.
4/08/00 eview Fomul s icuis cice s BL B A B I I I I E...... s n n hging Q Q 0 e... n... Q Q n 0 e Q I I0e Dischging Q U Q A wie mde of bss nd nohe wie mde of silve hve he sme lengh, bu he dimee of he bss
More information2d Motion: Constant Acceleration
d Moion: Consan Acceleaion Kinemaic Equaions o Moion (eco Fom Acceleaion eco (consan eloci eco (uncion o Posiion eco (uncion o The eloci eco and posiion eco ae a uncion o he ime. eloci eco a ime. Posiion
More informationPhysic 231 Lecture 4. Mi it ftd l t. Main points of today s lecture: Example: addition of velocities Trajectories of objects in 2 = =
Mi i fd l Phsic 3 Lecure 4 Min poins of od s lecure: Emple: ddiion of elociies Trjecories of objecs in dimensions: dimensions: g 9.8m/s downwrds ( ) g o g g Emple: A foobll pler runs he pern gien in he
More information(b) 10 yr. (b) 13 m. 1.6 m s, m s m s (c) 13.1 s. 32. (a) 20.0 s (b) No, the minimum distance to stop = 1.00 km. 1.
Answers o Een Numbered Problems Chper. () 7 m s, 6 m s (b) 8 5 yr 4.. m ih 6. () 5. m s (b).5 m s (c).5 m s (d) 3.33 m s (e) 8. ().3 min (b) 64 mi..3 h. ().3 s (b) 3 m 4..8 mi wes of he flgpole 6. (b)
More informationPhysics 101 Lecture 4 Motion in 2D and 3D
Phsics 11 Lecure 4 Moion in D nd 3D Dr. Ali ÖVGÜN EMU Phsics Deprmen www.ogun.com Vecor nd is componens The componens re he legs of he righ ringle whose hpoenuse is A A A A A n ( θ ) A Acos( θ) A A A nd
More informationPHYS PRACTICE EXAM 2
PHYS 1800 PRACTICE EXAM Pa I Muliple Choice Quesions [ ps each] Diecions: Cicle he one alenaive ha bes complees he saemen o answes he quesion. Unless ohewise saed, assume ideal condiions (no ai esisance,
More informationPHYSICS 1210 Exam 1 University of Wyoming 14 February points
PHYSICS 1210 Em 1 Uniersiy of Wyoming 14 Februry 2013 150 poins This es is opennoe nd closedbook. Clculors re permied bu compuers re no. No collborion, consulion, or communicion wih oher people (oher
More informationWORK POWER AND ENERGY Consevaive foce a) A foce is said o be consevaive if he wok done by i is independen of pah followed by he body b) Wok done by a consevaive foce fo a closed pah is zeo c) Wok done
More informationPhysics 2A HW #3 Solutions
Chper 3 Focus on Conceps: 3, 4, 6, 9 Problems: 9, 9, 3, 41, 66, 7, 75, 77 Phsics A HW #3 Soluions Focus On Conceps 33 (c) The ccelerion due o grvi is he sme for boh blls, despie he fc h he hve differen
More information1. Consider a PSA initially at rest in the beginning of the lefthand end of a long ISS corridor. Assume xo = 0 on the left end of the ISS corridor.
In Eercise 1, use sndrd recngulr Cresin coordine sysem. Le ime be represened long he horizonl is. Assume ll ccelerions nd decelerions re consn. 1. Consider PSA iniilly res in he beginning of he lefhnd
More informationMotion in a Straight Line
Moion in Srigh Line. Preei reched he mero sion nd found h he esclor ws no working. She wlked up he sionry esclor in ime. On oher dys, if she remins sionry on he moing esclor, hen he esclor kes her up in
More informationToday  Lecture 13. Today s lecture continue with rotations, torque, Note that chapters 11, 12, 13 all involve rotations
Today  Lecue 13 Today s lecue coninue wih oaions, oque, Noe ha chapes 11, 1, 13 all inole oaions slide 1 eiew Roaions Chapes 11 & 1 Viewed fom aboe (+z) Roaional, o angula elociy, gies angenial elociy
More informationChapter 4 Circular and Curvilinear Motions
Chp 4 Cicul n Cuilin Moions H w consi picls moing no long sigh lin h cuilin moion. W fis su h cicul moion, spcil cs of cuilin moion. Anoh mpl w h l sui li is h pojcil..1 Cicul Moion Unifom Cicul Moion
More informationFaraday s Law. To be able to find. motional emf transformer and motional emf. Motional emf
Objecie F s w Tnsfome Moionl To be ble o fin nsfome. moionl nsfome n moionl. 331 1 331 Mwell s quion: ic Fiel D: Guss lw :KV : Guss lw H: Ampee s w Poin Fom Inegl Fom D D Q sufce loop H sufce H I enclose
More information3 Motion with constant acceleration: Linear and projectile motion
3 Moion wih consn ccelerion: Liner nd projecile moion cons, In he precedin Lecure we he considered moion wih consn ccelerion lon he is: Noe h,, cn be posiie nd neie h leds o rie of behiors. Clerl similr
More informationTechnical Vibration  text 2  forced vibration, rotational vibration
Technicl Viion  e  foced viion, oionl viion 4. oced viion, viion unde he consn eenl foce The viion unde he eenl foce. eenl The quesion is if he eenl foce e is consn o vying. If vying, wh is he foce funcion.
More informationRelative and Circular Motion
Relaie and Cicula Moion a) Relaie moion b) Cenipeal acceleaion Mechanics Lecue 3 Slide 1 Mechanics Lecue 3 Slide 2 Time on Video Pelecue Looks like mosly eeyone hee has iewed enie pelecue GOOD! Thank you
More informationVersion 001 test1 swinney (57010) 1. is constant at m/s.
Version 001 es1 swinne (57010) 1 This prinou should hve 20 quesions. Muliplechoice quesions m coninue on he nex column or pge find ll choices before nswering. CubeUniVec1x76 001 10.0 poins Acubeis1.4fee
More informationPHYSICS 102. Intro PHYSICSELECTROMAGNETISM
PHYS 0 Suen Nme: Suen Numbe: FAUTY OF SIENE Viul Miem EXAMINATION PHYSIS 0 Ino PHYSISEETROMAGNETISM Emines: D. Yoichi Miyh INSTRUTIONS: Aemp ll 4 quesions. All quesions hve equl weighs 0 poins ech. Answes
More informationSection 35 SHM and Circular Motion
Section 35 SHM nd Cicul Motion Phsics 204A Clss Notes Wht do objects do? nd Wh do the do it? Objects sometimes oscillte in simple hmonic motion. In the lst section we looed t mss ibting t the end of sping.
More information( ) ( ) Physics 111. Lecture 13 (Walker: Ch ) Connected Objects Circular Motion Centripetal Acceleration Centripetal Force Sept.
Physics Lectue 3 (Wlke: Ch. 6.45) Connected Objects Cicul Motion Centipetl Acceletion Centipetl Foce Sept. 30, 009 Exmple: Connected Blocks Block of mss m slides on fictionless tbletop. It is connected
More informationAverage & instantaneous velocity and acceleration Motion with constant acceleration
Physics 7: Lecure Reminders Discussion nd Lb secions sr meeing ne week Fill ou Pink dd/drop form if you need o swich o differen secion h is FULL. Do i TODAY. Homework Ch. : 5, 7,, 3,, nd 6 Ch.: 6,, 3 Submission
More informationPhys 110. Answers to even numbered problems on Midterm Map
Phys Answers o een numbered problems on Miderm Mp. REASONING The word per indices rio, so.35 mm per dy mens.35 mm/d, which is o be epressed s re in f/cenury. These unis differ from he gien unis in boh
More informationGo over vector and vector algebra Displacement and position in 2D Average and instantaneous velocity in 2D Average and instantaneous acceleration
Mh Csquee Go oe eco nd eco lgeb Dsplcemen nd poson n D Aege nd nsnneous eloc n D Aege nd nsnneous cceleon n D Poecle moon Unfom ccle moon Rele eloc* The componens e he legs of he gh ngle whose hpoenuse
More informationOne of the common descriptions of curvilinear motion uses path variables, which are measurements made along the tangent t and normal n to the path of
Oe of he commo descipios of cuilie moio uses ph ibles, which e mesuemes mde log he ge d oml o he ph of he picles. d e wo ohogol xes cosideed sepely fo eey is of moio. These coodies poide ul descipio fo
More informationÖRNEK 1: THE LINEAR IMPULSEMOMENTUM RELATION Calculate the linear momentum of a particle of mass m=10 kg which has a. kg m s
MÜHENDİSLİK MEKANİĞİ. HAFTA İMPULS MMENTUMÇARPIŞMA Linea oenu of a paicle: The sybol L denoes he linea oenu and is defined as he ass ies he elociy of a paicle. L ÖRNEK : THE LINEAR IMPULSEMMENTUM RELATIN
More informationU>, and is negative. Electric Potential Energy
Electic Potentil Enegy Think of gvittionl potentil enegy. When the lock is moved veticlly up ginst gvity, the gvittionl foce does negtive wok (you do positive wok), nd the potentil enegy (U) inceses. When
More informationAxis. Axis. Axis. Solid cylinder (or disk) about. Hoop about. Annular cylinder (or ring) about central axis. central axis.
Insucos: Fel/ce PYSICS DEPATET PY 48 Em Ocoe 3, 4 me pn, ls fs: Sgnue: On m ono, I e nee gen no ecee unuoe on s emnon. YOU TEST UBE IS TE 5DIGIT UBE AT TE TOP OF EAC PAGE. Coe ou es nume on ou nswe see
More informationENGR 1990 Engineering Mathematics The Integral of a Function as a Function
ENGR 1990 Engineering Mhemics The Inegrl of Funcion s Funcion Previously, we lerned how o esime he inegrl of funcion f( ) over some inervl y dding he res of finie se of rpezoids h represen he re under
More informationD zone schemes
Ch. 5. Enegy Bnds in Cysls 5.. D zone schemes Fee elecons E k m h Fee elecons in cysl sinα P + cosα cosk α cos α cos k cos( k + π n α k + πn mv ob P 0 h cos α cos k n α k + π m h k E Enegy is peiodic
More informationChapter 10. Simple Harmonic Motion and Elasticity. Goals for Chapter 10
Chper 0 Siple Hronic Moion nd Elsiciy Gols or Chper 0 o ollow periodic oion o sudy o siple hronic oion. o sole equions o siple hronic oion. o use he pendulu s prooypicl syse undergoing siple hronic oion.
More informationPhysics 111. Uniform circular motion. Ch 6. v = constant. v constant. Wednesday, 89 pm in NSC 128/119 Sunday, 6:308 pm in CCLIR 468
ics Announcements dy, embe 28, 2004 Ch 6: Cicul Motion  centipetl cceletion Fiction Tension  the mssless sting Help this week: Wednesdy, 89 pm in NSC 128/119 Sundy, 6:308 pm in CCLIR 468 Announcements
More informationChapter 2 PROBLEM SOLUTIONS
Chper PROBLEM SOLUTIONS. We ssume h you re pproximely m ll nd h he nere impulse rels uniform speed. The elpsed ime is hen Δ x m Δ = m s s. s.3 Disnces reled beween pirs of ciies re ( ) Δx = Δ = 8. km h.5
More informationFM Applications of Integration 1.Centroid of Area
FM Applicions of Inegrion.Cenroid of Are The cenroid of ody is is geomeric cenre. For n ojec mde of uniform meril, he cenroid coincides wih he poin which he ody cn e suppored in perfecly lnced se ie, is
More informationπ,π is the angle FROM a! TO b
Mth 151: 1.2 The Dot Poduct We hve scled vectos (o, multiplied vectos y el nume clled scl) nd dded vectos (in ectngul component fom). Cn we multiply vectos togethe? The nswe is YES! In fct, thee e two
More informationf(x) dx with An integral having either an infinite limit of integration or an unbounded integrand is called improper. Here are two examples dx x x 2
Impope Inegls To his poin we hve only consideed inegls f() wih he is of inegion nd b finie nd he inegnd f() bounded (nd in fc coninuous ecep possibly fo finiely mny jump disconinuiies) An inegl hving eihe
More informationEquations from The Four Principal Kinetic States of Material Bodies. Copyright 2005 Joseph A. Rybczyk
Equions fom he Fou Pinipl Kinei Ses of Meil Bodies Copyigh 005 Joseph A. Rybzyk Following is omplee lis of ll of he equions used in o deied in he Fou Pinipl Kinei Ses of Meil Bodies. Eh equion is idenified
More informationt s (half of the total time in the air) d?
.. In Cl or Homework Eercie. An Olmpic long jumper i cpble of jumping 8.0 m. Auming hi horizonl peed i 9.0 m/ he lee he ground, how long w he in he ir nd how high did he go? horizonl? 8.0m 9.0 m / 8.0
More informationChapter 2. Kinematics in One Dimension. Kinematics deals with the concepts that are needed to describe motion.
Chpe Kinemic in One Dimenin Kinemic del wih he cncep h e needed decibe min. Dynmic del wih he effec h fce he n min. Tgehe, kinemic nd dynmic fm he bnch f phyic knwn Mechnic.. Diplcemen. Diplcemen.0 m 5.0
More informationMagnetostatics Bar Magnet. Magnetostatics Oersted s Experiment
Mgneosics Br Mgne As fr bck s 4500 yers go, he Chinese discovered h cerin ypes of iron ore could rc ech oher nd cerin mels. Iron filings "mp" of br mgne s field Crefully suspended slivers of his mel were
More informationAnswers to test yourself questions
Answes to test youself questions opic Descibing fields Gm Gm Gm Gm he net field t is: g ( d / ) ( 4d / ) d d Gm Gm Gm Gm Gm Gm b he net potentil t is: V d / 4d / d 4d d d V e 4 7 9 49 J kg 7 7 Gm d b E
More informationwhen t = 2 s. Sketch the path for the first 2 seconds of motion and show the velocity and acceleration vectors for t = 2 s.(2/63)
. The coordine of pricle in curiliner oion i gien b where i in eer nd i in econd. The coponen of ccelerion in eer per econd ured i gien b =. If he pricle h coponen = nd when = find he gniude of he eloci
More informationMotion. Part 2: Constant Acceleration. Acceleration. October Lab Physics. Ms. Levine 1. Acceleration. Acceleration. Units for Acceleration.
Moion Accelerion Pr : Consn Accelerion Accelerion Accelerion Accelerion is he re of chnge of velociy. = v  vo = Δv Δ ccelerion = = v  vo chnge of velociy elpsed ime Accelerion is vecor, lhough in onedimensionl
More informationAQA Maths M2. Topic Questions from Papers. Circular Motion. Answers
AQA Mths M Topic Questions fom Ppes Cicul Motion Answes PhysicsAndMthsTuto.com PhysicsAndMthsTuto.com Totl 6 () T cos30 = 9.8 Resolving veticlly with two tems Coect eqution 9.8 T = cos30 T =.6 N AG 3 Coect
More informationChapter 2. Motion along a straight line. 9/9/2015 Physics 218
Chper Moion long srigh line 9/9/05 Physics 8 Gols for Chper How o describe srigh line moion in erms of displcemen nd erge elociy. The mening of insnneous elociy nd speed. Aerge elociy/insnneous elociy
More informationSuggested Practice Problems (set #2) for the Physics Placement Test
Deparmen of Physics College of Ars and Sciences American Universiy of Sharjah (AUS) Fall 014 Suggesed Pracice Problems (se #) for he Physics Placemen Tes This documen conains 5 suggesed problems ha are
More informationMark Scheme (Results) January 2008
Mk Scheme (Results) Jnuy 00 GCE GCE Mthemtics (6679/0) Edecel Limited. Registeed in Englnd nd Wles No. 4496750 Registeed Office: One90 High Holbon, London WCV 7BH Jnuy 00 6679 Mechnics M Mk Scheme Question
More informationPhysics Worksheet Lesson 4: Linear Motion Section: Name:
Physics Workshee Lesson 4: Liner Moion Secion: Nme: 1. Relie Moion:. All moion is. b. is n rbirry coorine sysem wih reference o which he posiion or moion of somehing is escribe or physicl lws re formule.
More informationv T Pressure Extra Molecular Stresses Constitutive equations for Stress v t Observation: the stress tensor is symmetric
Momenum Blnce (coninued Momenum Blnce (coninued Now, wh o do wih Π? Pessue is p of i. bck o ou quesion, Now, wh o do wih? Π Pessue is p of i. Thee e ohe, nonisoopic sesses Pessue E Molecul Sesses definiion:
More informationPhysics 15 Second Hour Exam
hc 5 Second Hou e nwe e Mulle hoce / ole / ole /6 ole /  ol / I ee eone ole lee how ll wo n ode o ecee l ced. I ou oluon e llegle no ced wll e gen.. onde he collon o wo 7.
More informationEnergy Dissipation Gravitational Potential Energy Power
Lectue 4 Chpte 8 Physics I 0.8.03 negy Dissiption Gvittionl Potentil negy Powe Couse wesite: http://fculty.uml.edu/andiy_dnylov/teching/physicsi Lectue Cptue: http://echo360.uml.edu/dnylov03/physicsfll.html
More informationPHY2053 Summer C 2013 Exam 1 Solutions
PHY053 Sue C 03 E Soluon. The foce G on o G G The onl cobnon h e '/ = doubln.. The peed of lh le 8fulon c 86,8 le 60 n 60n h 4h d 4d fonh.80 fulon/ fonh 3. The dnce eled fo he ene p,, 36 (75n h 45 The
More information1 Using Integration to Find Arc Lengths and Surface Areas
Novembe 9, 8 MAT86 Week Justin Ko Using Integtion to Find Ac Lengths nd Sufce Aes. Ac Length Fomul: If f () is continuous on [, b], then the c length of the cuve = f() on the intevl [, b] is given b s
More informationComputer Propagation Analysis Tools
Compue Popagaion Analysis Tools. Compue Popagaion Analysis Tools Inoducion By now you ae pobably geing he idea ha pedicing eceived signal sengh is a eally impoan as in he design of a wieless communicaion
More information1. The sphere P travels in a straight line with speed
1. The sphee P tels in stight line with speed = 10 m/s. Fo the instnt depicted, detemine the coesponding lues of,,,,, s mesued eltie to the fixed Oxy coodinte system. (/134) + 38.66 1.34 51.34 10sin 3.639
More informationReinforcement learning
CS 75 Mchine Lening Lecue b einfocemen lening Milos Huskech milos@cs.pi.edu 539 Senno Sque einfocemen lening We wn o len conol policy: : X A We see emples of bu oupus e no given Insed of we ge feedbck
More informationCHAPTER 11 PARAMETRIC EQUATIONS AND POLAR COORDINATES
CHAPTER PARAMETRIC EQUATIONS AND POLAR COORDINATES. PARAMETRIZATIONS OF PLANE CURVES., 9, _ _ Ê.,, Ê or, Ÿ. 5, 7, _ _.,, Ÿ Ÿ Ê Ê 5 Ê ( 5) Ê ˆ Ê 6 Ê ( 5) 7 Ê Ê, Ÿ Ÿ $ 5. cos, sin, Ÿ Ÿ 6. cos ( ), sin (
More informationPhysics Mechanics. Rule #2: LABEL/LIST YOUR KNOWN VALUES AND THOSE DESIRED (Include units!!)
Phic Mechnic Rule #1: DRAW A PICTURE (Picoil Repeenion, Moion Dim, eebod Dim) Dw picue o wh he queion i decibin. Ue moion dim nd eebod dim o i ou in eein wh i oin on in he queion. Moion Dim: + eebod
More informationMinimum Squared Error
Minimum Squred Error LDF: Minimum SquredError Procedures Ide: conver o esier nd eer undersood prolem Percepron y i > for ll smples y i solve sysem of liner inequliies MSE procedure y i = i for ll smples
More informationReleased Assessment Questions, 2017 QUESTIONS
Relese Assessmen Quesions, 17 QUESTIONS Gre 9 Assessmen of Mhemis Aemi Re he insruions elow. Along wih his ookle, mke sure ou hve he Answer Bookle n he Formul Shee. You m use n spe in his ook for rough
More informationCircular Motion. Radians. One revolution is equivalent to which is also equivalent to 2π radians. Therefore we can.
1 Cicula Moion Radians One evoluion is equivalen o 360 0 which is also equivalen o 2π adians. Theefoe we can say ha 360 = 2π adians, 180 = π adians, 90 = π 2 adians. Hence 1 adian = 360 2π Convesions Rule
More informationFirst, we will find the components of the force of gravity: Perpendicular Forces (using away from the ramp as positive) ma F
1.. In Clss or Homework Eercise 1. An 18.0 kg bo is relesed on 33.0 o incline nd ccelertes t 0.300 m/s. Wht is the coeicient o riction? m 18.0kg 33.0? 0 0.300 m / s irst, we will ind the components o the
More informationMinimum Squared Error
Minimum Squred Error LDF: Minimum SquredError Procedures Ide: conver o esier nd eer undersood prolem Percepron y i > 0 for ll smples y i solve sysem of liner inequliies MSE procedure y i i for ll smples
More informationLecture 5. Chapter 3. Electromagnetic Theory, Photons, and Light
Lecue 5 Chape 3 lecomagneic Theo, Phoons, and Ligh Gauss s Gauss s Faada s Ampèe Mawell s + Loen foce: S C ds ds S C F dl dl q Mawell equaions d d qv A q A J ds ds In mae fields ae defined hough ineacion
More information0 for t < 0 1 for t > 0
8.0 Sep nd del funcions Auhor: Jeremy Orloff The uni Sep Funcion We define he uni sep funcion by u() = 0 for < 0 for > 0 I is clled he uni sep funcion becuse i kes uni sep = 0. I is someimes clled he Heviside
More informationPage 1 o 13 1. The brighes sar in he nigh sky is α Canis Majoris, also known as Sirius. I lies 8.8 lighyears away. Express his disance in meers. ( lighyear is he disance coered by ligh in one year. Ligh
More informationCalculus 241, section 12.2 Limits/Continuity & 12.3 Derivatives/Integrals notes by Tim Pilachowski r r r =, with a domain of real ( )
Clculu 4, econ Lm/Connuy & Devve/Inel noe y Tm Plchow, wh domn o el Wh we hve o : vecovlued uncon, ( ) ( ) ( ) j ( ) nume nd ne o veco The uncon, nd A w done wh eul uncon ( x) nd connuy e he componen
More informationCHAPTER 2 KINEMATICS IN ONE DIMENSION ANSWERS TO FOCUS ON CONCEPTS QUESTIONS
Physics h Ediion Cunell Johnson Young Sdler Soluions Mnul Soluions Mnul, Answer keys, Insrucor's Resource Mnul for ll chpers re included. Compleed downlod links: hps://esbnkre.com/downlod/physicshediionsoluionsmnulcunelljohnsonyoungsdler/
More informationInvert and multiply. Fractions express a ratio of two quantities. For example, the fraction
Appendi E: Mnipuling Fions Te ules fo mnipuling fions involve lgei epessions e el e sme s e ules fo mnipuling fions involve numes Te fundmenl ules fo omining nd mnipuling fions e lised elow Te uses of
More information10 m, so the distance from the Sun to the Moon during a solar eclipse is. The mass of the Sun, Earth, and Moon are = =
Chpte 1 nivesl Gvittion 11 *P1. () The unth distnce is 1.4 nd the thmoon 8 distnce is.84, so the distnce fom the un to the Moon duing sol eclipse is 11 8 11 1.4.84 = 1.4 The mss of the un, th, nd Moon
More informationAn object moving with speed v around a point at distance r, has an angular velocity. m/s m
Roion The mosphere roes wih he erh n moions wihin he mosphere clerly follow cure phs (cyclones, nicyclones, hurricnes, ornoes ec.) We nee o epress roion quniiely. For soli objec or ny mss h oes no isor
More informationPhysics 232 Exam I Feb. 13, 2006
Phsics I Fe. 6 oc. ec # Ne..5 g ss is ched o hoizol spig d is eecuig siple hoic oio. The oio hs peiod o.59 secods. iiil ie i is oud o e 8.66 c o he igh o he equiliiu posiio d oig o he le wih eloci o sec.
More informationProperties of Logarithms. Solving Exponential and Logarithmic Equations. Properties of Logarithms. Properties of Logarithms. ( x)
Properies of Logrihms Solving Eponenil nd Logrihmic Equions Properies of Logrihms Produc Rule ( ) log mn = log m + log n ( ) log = log + log Properies of Logrihms Quoien Rule log m = logm logn n log7 =
More informationCollision Detection and Bouncing
Collision Deecion nd Bouncing Collisions re Hndled in Two Prs. Deecing he collision Mike Biley mj@cs.oregonse.edu. Hndling he physics of he collision collisionouncing.ppx If You re Lucky, You Cn Deec
More informationPhysics 201 Lecture 18
Phsics 0 ectue 8 ectue 8 Goals: Define and anale toque ntoduce the coss poduct Relate otational dnamics to toque Discuss wok and wok eneg theoem with espect to otational motion Specif olling motion (cente
More informationChapter 28 Sources of Magnetic Field
Chpte 8 Souces of Mgnetic Field  Mgnetic Field of Moving Chge  Mgnetic Field of Cuent Element  Mgnetic Field of Stight CuentCying Conducto  Foce Between Pllel Conductos  Mgnetic Field of Cicul Cuent
More information+ r Position Velocity
1. The phee P tel in tight line with contnt peed of =100 m/. Fo the intnt hown, detemine the coeponding lue of,,,,, eltie to the fixed Ox coodinte tem. meued + + Poition Velocit e 80 e 45 o 113. 137 d
More informationChapter 4 TwoDimensional Motion
D Kinemtic Quntities Position nd Velocit Acceletion Applictions Pojectile Motion Motion in Cicle Unifom Cicul Motion Chpte 4 TwoDimensionl Motion D Motion Pemble In this chpte, we ll tnsplnt the conceptul
More informationPhysics 101 Fall 2006: Exam #1 PROBLEM #1
Physics 101 Fall 2006: Exam #1 PROBLEM #1 1. Problem 1. (+20 ps) (a) (+10 ps) i. +5 ps graph for x of he rain vs. ime. The graph needs o be parabolic and concave upward. ii. +3 ps graph for x of he person
More informationElectric Potential. and Equipotentials
Electic Potentil nd Euipotentils U Electicl Potentil Review: W wok done y foce in going fom to long pth. l d E dl F W dl F θ Δ l d E W U U U Δ Δ l d E W U U U U potentil enegy electic potentil Potentil
More informationClassification of Equations Characteristics
Clssiiion o Eqions Cheisis Consie n elemen o li moing in wo imensionl spe enoe s poin P elow. The ph o P is inie he line. The posiion ile is s so h n inemenl isne long is s. Le he goening eqions e epesene
More informationAlgebra Based Physics. Gravitational Force. PSI Honors universal gravitation presentation Update Fall 2016.notebookNovember 10, 2016
Newton's Lw of Univesl Gvittion Gvittionl Foce lick on the topic to go to tht section Gvittionl Field lgeb sed Physics Newton's Lw of Univesl Gvittion Sufce Gvity Gvittionl Field in Spce Keple's Thid Lw
More informationKinematics in two dimensions
Lecure 5 Phsics I 9.18.13 Kinemaics in wo dimensions Course websie: hp://facul.uml.edu/andri_danlo/teaching/phsicsi Lecure Capure: hp://echo36.uml.edu/danlo13/phsics1fall.hml 95.141, Fall 13, Lecure 5
More informationRotations.
oons j.lbb@phscs.o.c.uk To s summ Fmes of efeence Invnce une nsfomons oon of wve funcon: funcons Eule s ngles Emple: e e   Angul momenum s oon geneo Genec nslons n Noehe s heoem Fmes of efeence Conse
More informationLecture 3. Electrostatics
Lecue lecsics In his lecue yu will len: Thee wys slve pblems in elecsics: ) Applicin f he Supepsiin Pinciple (SP) b) Applicin f Guss Lw in Inegl Fm (GLIF) c) Applicin f Guss Lw in Diffeenil Fm (GLDF) C
More information2002 November 14 Exam III Physics 191
November 4 Exam III Physics 9 Physical onsans: Earh s freefall acceleraion = g = 9.8 m/s ircle he leer of he single bes answer. quesion is worh poin Each 3. Four differen objecs wih masses: m = kg, m
More information