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1 peden (jp5559) Time onstants peden (0100) 1 This print-out should have 21 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. Test is Thursday! HW Due Thursday morning at 8:00 AM! 001 (part 1 of 2) 10.0 points B1: V = 0 B2: V = V B3: V = V e 1/() lose the switch for a very long time, the current through and the potential across the capacitor are given respectively by 2.6 MΩ 16 V 3.6 µf 1. A1, B3 2. A1, B2 3. A3, B2 4. A2, B2 A 2.6 MΩ resistor and a 3.6 µf capacitor are connected in series with a 16 V power supply. After the switch is closed, what is the time constant for the circuit? Answer in units of s. 002 (part 2 of 2) 10.0 points What is the charge on the capacitor at 12 s after the switch is closed? Answer in units of points onsider the circuit shown. The emf of the battery is V, the resistance, and the capacitance. E i 5. A3, B3 6. A1, B1 7. A2, B1 8. A2, B3 9. A3, B1 004 (part 1 of 4) 10.0 points In the circuit shown, the capacitor is initially uncharged. At t 1 = 0, the switch is moved to position a. 2 V 0 b a onsider the following statements. A1: I = 0 A2: I = V A3: I = V e 1/() Find V 1, the voltage drop across, as a function of time t 1. (1+2) t1/(1 2 ) 1. V 1 = V 0 e t1/(2 2. V 1 = V 0 1 e

2 peden (jp5559) Time onstants peden (0100) 2 t1/(1 3. V 1 = V 0 1 e 1 t2/(1 5. V 1 = V 0 1 e + 2 t1/(2 ) 4. V 1 = V 0 e t1/(1 ) 5. V 1 = V 0 e t1/(1+2) 6. V 1 = V 0 1 e ]] (1+2) t1/( V 1 = V 0 1 e t1/(1+2) ] 8. V 1 = V 0 e 005 (part 2 of 4) 10.0 points Find V, the voltage across, as a function of time t 1. t1/(1 ) 1. V = V 0 e (1+2) t1/(1 2 ) 2. V = V 0 e t1/(1+2) ] 3. V = V 0 e t1/(2 ) 4. V = V 0 e 5. V = V 0 1 e t1/(1+2)]] (1+2) t1/( V = V 0 1 e t1/(1 7. V = V 0 1 e t1/(2 8. V = V 0 1 e 006 (part 3 of 4) 10.0 points Much later (t 1 ), at some time t 2 = 0 (the clock is restarted at t 2 = 0), the switch is moved from position a to position b. Find the voltage drop, V 1, across, as a function of time t 2. t2/(2 ) 1. V 1 = V 0 e t2/(2 2. V 1 = V 0 1 e + 2 t2/(1 ) 3. V 1 = V 0 e V 1 = V e (1+2)t2/(12 { 1 t2/(1+2) 6. V 1 = V 0 1 e ]} + 2 (1+2)t2/(1 2 ) 7. V 1 = V 0 e + 2 t2/(1+2) ] 8. V 1 = V 0 e (part 4 of 4) 10.0 points Find V as a function of time t 2. { t2/(1+2) 1. V = V 0 1 e ]} t2/(2 2. V = V 0 1 e t2/(1 3. V = V 0 1 e t2/(1 ) 4. V = V 0 e 5. V = V 0 e t2/(1+2)] (1+2)t2/(1 2 ) 6. V = V 0 e (1+2)t2/( V = V 0 1 e t2/(2 ) 8. V = V 0 e 008 (part 1 of 4) 10.0 points A 32 µf capacitor is charged to 61 V and is then connected across a 636 Ω resistor. What is the initial charge on the capacitor? Answer in units of µ. 009 (part 2 of 4) 10.0 points What is the initial current just after the capacitor is connected to the resistor? 010 (part 3 of 4) 10.0 points What is the time constant of this circuit? Answer in units of ms. 011 (part 4 of 4) 10.0 points How much charge is on the capacitor after ms? Answer in units of µ.

3 peden (jp5559) Time onstants peden (0100) (part 1 of 2) 10.0 points Unlike most real bulbs, the resistance of the bulb in the questions below does not change as the current through it changes. A capacitor, a bulb, and a switch are in the circuit as shown below. The switch is initially open as shown in the above diagram, and the capacitor is charged. Which of the following correctly describes what happens to the bulb when the switch is closed? 1. None of these is correct. 2. The bulb is bright and remains bright. 3. At first the bulb is bright and it gets dimmer and dimmer until it goes off. 4. The bulb is dim and remains dim. 5. At first the bulb is dim and it gets brighter and brighter until the brightness levels off. 013 (part 2 of 2) 10.0 points Which correctly describes what happens after the switch has remained closed for a long time? 1. The bulb is permanently off. 2. None of these is correct. 3. The potential difference across the capacitor is steady. 4. The bulb is on and is bright. 5. The current in the circuit is steady. 014 (part 1 of 3) 10.0 points 2.5 Ω 6.6 Ω I V 8.2 Ω I Ω I V 5.8 V Find the current I 1 in the 0.8 Ω resistor at the bottom of the circuit between the two power supplies. 015 (part 2 of 3) 10.0 points Determine I (part 3 of 3) 10.0 points Determine I (part 1 of 3) 10.0 points onsider two cylindrical conductors made of the same ohmic material. onductor 1 has a radius r 1 and length l 1 while conductor 2 has a radius r 2 and length l 2. Denote: The currents of the two conductors as I 1 and I 2, the potential differences between the two ends of the conductors as V 1 and V 2, and the electric fields within the conductors as and E 2. r 1 E1 I 1 V 1 l 1 r 2 E2 I 2 V 2 If ρ 2 = ρ 1, r 2 r 1, l 2 l 1 and V 2 = l 2

4 peden (jp5559) Time onstants peden (0100) 4 V 1, find the ratio 2 of the resistances (part 2 of 3) 10.0 points When the two conductors are attached to a battery of voltage V, determine the ratio E 2 of the electric fields. 1. E E E 2 4. E 2 5. E E 2 7. E E 2 9. E E (part 3 of 3) 10.0 points Now consider a different case where the currents in the two conductors are the same (i.e., I 1 = I 2 ). Determine the ratio E 2 of the electric fields. 1. E E 2 3. E 2 4. E 2 5. E E 2 7. E 2 8. E E E points You have a 5.95 W, 232 Ω resistor. What is the maximum current that should be allowed in it? points onsider the capacitor circuit

5 peden (jp5559) Time onstants peden (0100) 5 31 µf 36 µf 52 µf 15 µf 77 V What is the effective capacitance of the circuit? Answer in units of µf.

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