EE 3CL4: Introduction to Control Systems Lab 4: Lead Compensation


 Candice Jenkins
 4 years ago
 Views:
Transcription
1 EE 3CL4: Introduction to Control Systems Lab 4: Lead Compensation Tim Davidson Ext Objective To use the root locus technique to design a lead compensator for a marginallystable servomotor. Assessment The assessment for this laboratory will consist of 1. a prelab design exercise, which must be completed before the lab, 2. a system identification experiment, 3. the design of a lead compensator for the system identified in item 2, 4. an experiment to evaluate the performance of the compensated closed loop designed in item 3. Your answer to the prelab exercise will be evaluated at the beginning of the lab. Your performance of the system identification experiment, the compensator design and the performance evaluation experiment will be evaluated during the lab. The marks for each component are clearly indicated. 1 Prelab design exercise (5 marks) Consider the closed loop in Figure 1 in the case in which H(s) = 1 and G(s) = 4.7 s(s+3.2). Design a lead compensator of the form G c (s) = Kc(s+z) (s+p) so that for a unit step input r(t) = u(t) the percentage overshoot of the output y(t) is 22% and its 2% settling time is 0.8 seconds. Please provide the details of the calculations that you performed in each step of the design process. (In addition to the material in lectures and the text book, the material in Section 3 may be of assistance.) Figure 1: A compensated closed loop. We will focus on the case in which H(s) = 1. (Figure 10.1 of Dorf and Bishop, Modern Control Systems, 11th edition, Prentice Hall, 2008.) 1
2 2 Exp. 1: Closed Loop System Identification (2 marks) Recall that we will model the motor in the experiments using the transfer function G(s) = A s(sτ m + 1). (1) In order to perform the design component of this lab, we will need to obtain the A and τ m for the motor that you will use in this laboratory. Note that the values that you obtain may be different from those that you obtained in Lab. 1, even if you are using the same motor. Repeat experiments 1 and 2 from Lab. 1 to obtain the parameters A and τ m for the motor that you will use in this laboratory. Remember that this involves constructing a circuit of the form in Fig. 2 using components in the form of Figs 3 and 4. For these systems you can choose R 1 = R 2 = 10 kω. Please follow the instructions from Lab. 1 carefully. To obtain your mark for this experiment you must show your TA the scope trace for input frequency ω p and must provide the corresponding values of A and τ m. 3 Design of a Lead Compensator for the Servomotor In Lab. 2, we designed a proportional controller that had a large gain and achieved no more than 25% overshoot. However, we were unable to adjust the settling time of the closed loop by manipulating the value of the amplifier gain. In this lab, we will design a lead compensator that will enable us to achieve 25% overshoot and a settling time that is three times shorter than that achieved in Lab. 2. We will also examine the velocity error constant obtained in this design. 3.1 Design of compensator (7 marks) In this section we will determine the pole positions required to achieve the desired goals. Begin a sketch of the root locus by rewriting the motor transfer function as G(s) = plotting the poles of the model in (1). A/τm s(s+1/τ m) Recall from Lab. 2 that the time constant for an underdamped closed loop with proportional control is 2τ m. On your graph, mark with squares the positions of the closed loop poles that would result in an overshoot of 25% and a settling time that is 1/3 of that achieved in the previous lab. s+z As a first step in the design of the compensator, G c (s) = K c s+p, place the zero of the compensator on the real axis with the same real part as that of the desired closedloop poles. The pole of the compensator will be on the real axis to the left of this zero. Use the angle criterion to determine where the pole should be placed in order for the root locus to pass through the squares. Use the magnitude criterion to determine the gain K c A/τ m required to place the poles in this position. Complete the sketch of the root locus. You will need to compute the angles and the centroid of the asymptotes, but you may simply estimate the breakaway points. and 2
3 Figure 2: Closed loop circuit from Labs 1 and 2. Figure 3: Summing amplifier. Figure 4: Unitgain inverting amplifier (inverter). Figure 5: An implementation of a lead compensator. 3
4 If we write the compensator in the form G c (s) = K aτs+1 c τs+1 what values should we choose for τ, a and K c? Compute the velocity error constant for the closed loop that you have designed. Recall that the velocity error constant of a stable closed loop satisfies K v = lim s 0 s 1+G c(s)g(s) s. 2 To obtain your marks for this section, you must show a TA your worked solution, including the computed position for the pole, your sketch of the root locus, and the values you computed for τ, a and K c 3.2 Design of compensator circuit (3 marks) The goal of this section is to design a circuit that will implement the compensator that was designed in the previous section. For the circuit in Fig. 5, assume that the opamp is ideal and the bias resistor is absent. Show that the transfer function can be written as G c (s) = K c aτs + 1 τs + 1 where K c = R 3 /R 2, τ = C 1 R 1, and a = (R 1 + R 2 )/R 1. Note that a > 1 so that the zero is closer to the origin than the pole. Hence, this circuit can be used to construct a lead compensator. Now choose values for R 1, R 2, R 3 and C 1 so that we achieve the desired value of K c, and the zero and pole positions designed above. Note that there are three requirements, and four degrees of freedom. This provides the flexibility required to ensure that we can use standard values for at least some of the components. In particular, Capacitors should be selected between 0.1µF and 30µF, preferably from standard values. For the opamps that we are using, resistors should be chosen between 10kΩ and 1MΩ. If R 2 is chosen to be larger than 500kΩ, we must add the bias resistor in Fig. 5. As a guide, you should consider choosing R 2 to be a value that satisfies 10 4 (a 1) R (a 1), preferably a standard value. That should enable you to choose values for the capacitor and R 1 that can be constructed from the available equipment and enable linear operation of the opamp. To obtain your marks for this section, you must show a TA your worked solution, including the values for the resistors and the capacitor. 4 Exp. 2: Implementation of the Lead Compensator 4.1 Construct the closed loop (1 mark) Construct a closed loop that implements the designed system using a combination of the summing amplifier in Fig. 3, the inverter in Fig. 4, the lead compensator in Fig. 5, and the SEU. (Recall that the output of the summing amplifier is proportional to the negative of the sum.) Make sure that the Laplace Transform of the output of the compensator is G c (s) ( R(s) Θ(s) ), where R(s) is the Laplace Transform of the input and Θ(s) is the Laplace Transform of the angle output. In order to ensure that the sign of this output is correct, the architecture of your closed loop may need to be different from that in Fig. 2. Before enabling this circuit, obtain your mark for this section by showing your block diagram to a TA, and showing the TA your implementation. (2) 4
5 4.2 Evaluation of the design To obtain your marks for each section, you must show a TA the appropriate trace on the oscilloscope and your associated calculations, and you should provide appropriate discussion Evaluate the percentage overshoot of your design (4 marks) Apply a square wave to the command input, and measure the percentage overshoot that you obtained. Make sure that the amplitude is large enough so that the nonlinear effects of the motor are mitigated, but small enough so that the opamp voltage does not saturate. Some guidance on the latter point can be obtained by considering the steadystate response of the compensator circuit to a step input, and the percentage overshoot Evaluate the settling time of your design (4 marks) Apply a square wave to the command input, and assess the settling time. Compare this value to 8τ m, which was the settling time of an underdamped closedloop with proportional control Evaluate the velocity error constant of your design (2 marks) Apply a triangular wave to the command input. Make sure that the frequency of the wave is low enough for the loop to settle into the steady state before the wave reverses. Let β be the magnitude of the slope of the triangular wave. Estimate the velocity error constant by dividing the steadystate value of r(t) θ(t) by β. The steadystate error can be measured by measuring the input r(t) using channel 1 of the oscilloscope and measuring the output θ(t) using channel 2. Be sure to select a value of β that facilitates this measurement. Compare the achieved velocity error constant to the value that can be calculated from the gains and the positions of the openloop poles and zeros in your design in Section
EE 380 EXAM II 3 November 2011 Last Name (Print): First Name (Print): ID number (Last 4 digits): Section: DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO
EE 380 EXAM II 3 November 2011 Last Name (Print): First Name (Print): ID number (Last 4 digits): Section: DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO Problem Weight Score 1 25 2 25 3 25 4 25 Total
More informationRoot Locus Design Example #4
Root Locus Design Example #4 A. Introduction The plant model represents a linearization of the heading dynamics of a 25, ton tanker ship under empty load conditions. The reference input signal R(s) is
More information(b) A unity feedback system is characterized by the transfer function. Design a suitable compensator to meet the following specifications:
1. (a) The open loop transfer function of a unity feedback control system is given by G(S) = K/S(1+0.1S)(1+S) (i) Determine the value of K so that the resonance peak M r of the system is equal to 1.4.
More information6.302 Feedback Systems
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Electrical Engineering and Computer Science 6.302 Feedback Systems Fall Term 2005 Issued : November 18, 2005 Lab 2 Series Compensation in Practice Due
More informationCompensator Design to Improve Transient Performance Using Root Locus
1 Compensator Design to Improve Transient Performance Using Root Locus Prof. Guy Beale Electrical and Computer Engineering Department George Mason University Fairfax, Virginia Correspondence concerning
More informationUNIVERSITY OF BOLTON SCHOOL OF ENGINEERING BENG (HONS) IN BIOMEDICAL ENGINEERING SEMESTER 1 EXAMINATION 2017/2018 ADVANCED BIOMECHATRONIC SYSTEMS
ENG0016 UNIVERSITY OF BOLTON SCHOOL OF ENGINEERING BENG (HONS) IN BIOMEDICAL ENGINEERING SEMESTER 1 EXAMINATION 2017/2018 ADVANCED BIOMECHATRONIC SYSTEMS MODULE NO: BME6003 Date: Friday 19 January 2018
More informationControl Systems. University Questions
University Questions UNIT1 1. Distinguish between open loop and closed loop control system. Describe two examples for each. (10 Marks), Jan 2009, June 12, Dec 11,July 08, July 2009, Dec 2010 2. Write
More informationMethods for analysis and control of. Lecture 4: The root locus design method
Methods for analysis and control of Lecture 4: The root locus design method O. Sename 1 1 Gipsalab, CNRSINPG, FRANCE Olivier.Sename@gipsalab.inpg.fr www.lag.ensieg.inpg.fr/sename Lead Lag 17th March
More informationDr Ian R. Manchester Dr Ian R. Manchester AMME 3500 : Review
Week Date Content Notes 1 6 Mar Introduction 2 13 Mar Frequency Domain Modelling 3 20 Mar Transient Performance and the splane 4 27 Mar Block Diagrams Assign 1 Due 5 3 Apr Feedback System Characteristics
More informationECE Circuit Theory. Final Examination. December 5, 2008
ECE 212 H1F Pg 1 of 12 ECE 212  Circuit Theory Final Examination December 5, 2008 1. Policy: closed book, calculators allowed. Show all work. 2. Work in the provided space. 3. The exam has 3 problems
More informationEEE 184 Project: Option 1
EEE 184 Project: Option 1 Date: November 16th 2012 Due: December 3rd 2012 Work Alone, show your work, and comment your results. Comments, clarity, and organization are important. Same wrong result or same
More informationRobust Performance Example #1
Robust Performance Example # The transfer function for a nominal system (plant) is given, along with the transfer function for one extreme system. These two transfer functions define a family of plants
More informationMethods for analysis and control of dynamical systems Lecture 4: The root locus design method
Methods for analysis and control of Lecture 4: The root locus design method O. Sename 1 1 Gipsalab, CNRSINPG, FRANCE Olivier.Sename@gipsalab.inpg.fr www.gipsalab.fr/ o.sename 5th February 2015 Outline
More informationAppendix A: Exercise Problems on Classical Feedback Control Theory (Chaps. 1 and 2)
Appendix A: Exercise Problems on Classical Feedback Control Theory (Chaps. 1 and 2) For all calculations in this book, you can use the MathCad software or any other mathematical software that you are familiar
More informationSolved Problems. Electric Circuits & Components. 11 Write the KVL equation for the circuit shown.
Solved Problems Electric Circuits & Components 11 Write the KVL equation for the circuit shown. 12 Write the KCL equation for the principal node shown. 12A In the DC circuit given in Fig. 1, find (i)
More informationEE3CL4: Introduction to Linear Control Systems
1 / 17 EE3CL4: Introduction to Linear Control Systems Section 7: McMaster University Winter 2018 2 / 17 Outline 1 4 / 17 Cascade compensation Throughout this lecture we consider the case of H(s) = 1. We
More informationAlireza Mousavi Brunel University
Alireza Mousavi Brunel University 1 » Control Process» Control Systems Design & Analysis 2 OpenLoop Control: Is normally a simple switch on and switch off process, for example a light in a room is switched
More informationSteady State Frequency Response Using Bode Plots
School of Engineering Department of Electrical and Computer Engineering 332:224 Principles of Electrical Engineering II Laboratory Experiment 3 Steady State Frequency Response Using Bode Plots 1 Introduction
More informationProblem Weight Score Total 100
EE 350 EXAM IV 15 December 2010 Last Name (Print): First Name (Print): ID number (Last 4 digits): Section: DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO Problem Weight Score 1 25 2 25 3 25 4 25 Total
More informationIf you need more room, use the backs of the pages and indicate that you have done so.
EE 343 Exam II Ahmad F. Taha Spring 206 Your Name: Your Signature: Exam duration: hour and 30 minutes. This exam is closed book, closed notes, closed laptops, closed phones, closed tablets, closed pretty
More informationOutline. Classical Control. Lecture 2
Outline Outline Outline Review of Material from Lecture 2 New Stuff  Outline Review of Lecture System Performance Effect of Poles Review of Material from Lecture System Performance Effect of Poles 2 New
More informationECE 212H1F Circuit Analysis October 30, :1019: Reza Iravani 02 Reza Iravani 03 Piero Triverio. (Nonprogrammable Calculators Allowed)
Please Print Clearly Last Name: First Name: Student Number: Your Tutorial Section (CIRCLE ONE): 01 Thu. 911 RS211 02 Thu. 911 GB119 03 Tue. 1012 SF2202 04 Tue. 1012 SF3201 05 Tue. 1315 GB304 06 Tue.
More informationPID Control. Objectives
PID Control Objectives The objective of this lab is to study basic design issues for proportionalintegralderivative control laws. Emphasis is placed on transient responses and steadystate errors. The
More informationKINGS COLLEGE OF ENGINEERING DEPARTMENT OF ELECTRONICS AND COMMUNICATION ENGINEERING
KINGS COLLEGE OF ENGINEERING DEPARTMENT OF ELECTRONICS AND COMMUNICATION ENGINEERING QUESTION BANK SUB.NAME : CONTROL SYSTEMS BRANCH : ECE YEAR : II SEMESTER: IV 1. What is control system? 2. Define open
More informationTest II Michael R. Gustafson II
'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ EGR 224 Spring 2016 Test II Michael R. Gustafson II Name (please print) In keeping with the Community Standard, I have neither provided nor received any
More informationVALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur
VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur 603 203. DEPARTMENT OF ELECTRONICS & COMMUNICATION ENGINEERING SUBJECT QUESTION BANK : EC6405 CONTROL SYSTEM ENGINEERING SEM / YEAR: IV / II year
More informationController Design using Root Locus
Chapter 4 Controller Design using Root Locus 4. PD Control Root locus is a useful tool to design different types of controllers. Below, we will illustrate the design of proportional derivative controllers
More information2.004 Dynamics and Control II Spring 2008
MIT OpenCourseWare http://ocw.mit.edu 2.004 Dynamics and Control II Spring 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. Massachusetts Institute
More informationHomework Assignment 08
Homework Assignment 08 Question 1 (Short Takes) Two points each unless otherwise indicated. 1. Give one phrase/sentence that describes the primary advantage of an active load. Answer: Large effective resistance
More informationVideo 5.1 Vijay Kumar and Ani Hsieh
Video 5.1 Vijay Kumar and Ani Hsieh Robo3x1.1 1 The Purpose of Control Input/Stimulus/ Disturbance System or Plant Output/ Response Understand the Black Box Evaluate the Performance Change the Behavior
More informationLecture 7:Time Response PoleZero Maps Influence of Poles and Zeros Higher Order Systems and Pole Dominance Criterion
Cleveland State University MCE441: Intr. Linear Control Lecture 7:Time Influence of Poles and Zeros Higher Order and Pole Criterion Prof. Richter 1 / 26 FirstOrder Specs: Step : Pole Real inputs contain
More informationTransient Response of a SecondOrder System
Transient Response of a SecondOrder System ECEN 830 Spring 01 1. Introduction In connection with this experiment, you are selecting the gains in your feedback loop to obtain a wellbehaved closedloop
More informationTest 2 SOLUTIONS. ENGI 5821: Control Systems I. March 15, 2010
Test 2 SOLUTIONS ENGI 5821: Control Systems I March 15, 2010 Total marks: 20 Name: Student #: Answer each question in the space provided or on the back of a page with an indication of where to find the
More informationFeedback design for the Buck Converter
Feedback design for the Buck Converter Portland State University Department of Electrical and Computer Engineering Portland, Oregon, USA December 30, 2009 Abstract In this paper we explore two compensation
More informationECE137B Final Exam. There are 5 problems on this exam and you have 3 hours There are pages 119 in the exam: please make sure all are there.
ECE37B Final Exam There are 5 problems on this exam and you have 3 hours There are pages 9 in the exam: please make sure all are there. Do not open this exam until told to do so Show all work: Credit
More informationINSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad ELECTRICAL AND ELECTRONICS ENGINEERING TUTORIAL QUESTION BANK
Course Name Course Code Class Branch INSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad 500 043 ELECTRICAL AND ELECTRONICS ENGINEERING TUTORIAL QUESTION BAN : CONTROL SYSTEMS : A50 : III B. Tech
More informationCYBER EXPLORATION LABORATORY EXPERIMENTS
CYBER EXPLORATION LABORATORY EXPERIMENTS 1 2 Cyber Exploration oratory Experiments Chapter 2 Experiment 1 Objectives To learn to use MATLAB to: (1) generate polynomial, (2) manipulate polynomials, (3)
More informationHomework 7  Solutions
Homework 7  Solutions Note: This homework is worth a total of 48 points. 1. Compensators (9 points) For a unity feedback system given below, with G(s) = K s(s + 5)(s + 11) do the following: (c) Find the
More informationVALLIAMMAI ENGINEERING COLLEGE
VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur 603 203 DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING QUESTION BANK V SEMESTER IC650 CONTROL SYSTEMS Regulation 203 Academic Year 207 8 Prepared
More informationAutomatic Control (MSc in Mechanical Engineering) Lecturer: Andrea Zanchettin Date: Student ID number... Signature...
Automatic Control (MSc in Mechanical Engineering) Lecturer: Andrea Zanchettin Date: 29..23 Given and family names......................solutions...................... Student ID number..........................
More informationEE C128 / ME C134 Final Exam Fall 2014
EE C128 / ME C134 Final Exam Fall 2014 December 19, 2014 Your PRINTED FULL NAME Your STUDENT ID NUMBER Number of additional sheets 1. No computers, no tablets, no connected device (phone etc.) 2. Pocket
More informationModule 3F2: Systems and Control EXAMPLES PAPER 2 ROOTLOCUS. Solutions
Cambridge University Engineering Dept. Third Year Module 3F: Systems and Control EXAMPLES PAPER ROOTLOCUS Solutions. (a) For the system L(s) = (s + a)(s + b) (a, b both real) show that the rootlocus
More informationEE C128 / ME C134 Fall 2014 HW 6.2 Solutions. HW 6.2 Solutions
EE C28 / ME C34 Fall 24 HW 6.2 Solutions. PI Controller For the system G = K (s+)(s+3)(s+8) HW 6.2 Solutions in negative feedback operating at a damping ratio of., we are going to design a PI controller
More informationECE317 : Feedback and Control
ECE317 : Feedback and Control Lecture : Steadystate error Dr. Richard Tymerski Dept. of Electrical and Computer Engineering Portland State University 1 Course roadmap Modeling Analysis Design Laplace
More informationCONTROL SYSTEMS ENGINEERING Sixth Edition International Student Version
CONTROL SYSTEMS ENGINEERING Sixth Edition International Student Version Norman S. Nise California State Polytechnic University, Pomona John Wiley fir Sons, Inc. Contents PREFACE, vii 1. INTRODUCTION, 1
More informationOutline. Classical Control. Lecture 5
Outline Outline Outline 1 What is 2 Outline What is Why use? Sketching a 1 What is Why use? Sketching a 2 Gain Controller Lead Compensation Lag Compensation What is Properties of a General System Why use?
More informationCourse Summary. The course cannot be summarized in one lecture.
Course Summary Unit 1: Introduction Unit 2: Modeling in the Frequency Domain Unit 3: Time Response Unit 4: Block Diagram Reduction Unit 5: Stability Unit 6: SteadyState Error Unit 7: Root Locus Techniques
More informationControl System Design
ELEC ENG 4CL4: Control System Design Notes for Lecture #4 Monday, January 13, 2003 Dr. Ian C. Bruce Room: CRL229 Phone ext.: 26984 Email: ibruce@mail.ece.mcmaster.ca Impulse and Step Responses of ContinuousTime
More informationFigure Circuit for Question 1. Figure Circuit for Question 2
Exercises 10.7 Exercises Multiple Choice 1. For the circuit of Figure 10.44 the time constant is A. 0.5 ms 71.43 µs 2, 000 s D. 0.2 ms 4 Ω 2 Ω 12 Ω 1 mh 12u 0 () t V Figure 10.44. Circuit for Question
More informationDepartment of Electrical Engineering and Computer Sciences University of California, Berkeley. Final Exam Solutions
Electrical Engineering 42/00 Summer 202 Instructor: Tony Dear Department of Electrical Engineering and omputer Sciences University of alifornia, Berkeley Final Exam Solutions. Diodes Have apacitance?!?!
More informationCourse roadmap. Step response for 2ndorder system. Step response for 2ndorder system
ME45: Control Systems Lecture Time response of ndorder systems Prof. Clar Radcliffe and Prof. Jongeun Choi Department of Mechanical Engineering Michigan State University Modeling Laplace transform Transfer
More informationControls Problems for Qualifying Exam  Spring 2014
Controls Problems for Qualifying Exam  Spring 2014 Problem 1 Consider the system block diagram given in Figure 1. Find the overall transfer function T(s) = C(s)/R(s). Note that this transfer function
More informationMAS107 Control Theory Exam Solutions 2008
MAS07 CONTROL THEORY. HOVLAND: EXAM SOLUTION 2008 MAS07 Control Theory Exam Solutions 2008 Geir Hovland, Mechatronics Group, Grimstad, Norway June 30, 2008 C. Repeat question B, but plot the phase curve
More informationME 375 EXAM #1 Friday, March 13, 2015 SOLUTION
ME 375 EXAM #1 Friday, March 13, 2015 SOLUTION PROBLEM 1 A system is made up of a homogeneous disk (of mass m and outer radius R), particle A (of mass m) and particle B (of mass m). The disk is pinned
More informationLaboratory 11 Control Systems Laboratory ECE3557. State Feedback Controller for Position Control of a Flexible Joint
Laboratory 11 State Feedback Controller for Position Control of a Flexible Joint 11.1 Objective The objective of this laboratory is to design a full state feedback controller for endpoint position control
More informationCONTROL * ~ SYSTEMS ENGINEERING
CONTROL * ~ SYSTEMS ENGINEERING H Fourth Edition NormanS. Nise California State Polytechnic University, Pomona JOHN WILEY& SONS, INC. Contents 1. Introduction 1 1.1 Introduction, 2 1.2 A History of Control
More informationR10 JNTUWORLD B 1 M 1 K 2 M 2. f(t) Figure 1
Code No: R06 R0 SET  II B. Tech II Semester Regular Examinations April/May 03 CONTROL SYSTEMS (Com. to EEE, ECE, EIE, ECC, AE) Time: 3 hours Max. Marks: 75 Answer any FIVE Questions All Questions carry
More informationEE214 Early Final Examination: Fall STANFORD UNIVERSITY Department of Electrical Engineering. SAMPLE FINAL EXAMINATION Fall Quarter, 2002
STANFORD UNIVERSITY Department of Electrical Engineering SAMPLE FINAL EXAMINATION Fall Quarter, 2002 EE214 8 December 2002 CLOSED BOOK; Two std. 8.5 x 11 sheets of notes permitted CAUTION: Useful information
More informationAn Introduction to Control Systems
An Introduction to Control Systems Signals and Systems: 3C1 Control Systems Handout 1 Dr. David Corrigan Electronic and Electrical Engineering corrigad@tcd.ie November 21, 2012 Recall the concept of a
More informationChapter 5 HW Solution
Chapter 5 HW Solution Review Questions. 1, 6. As usual, I think these are just a matter of text lookup. 1. Name the four components of a block diagram for a linear, timeinvariant system. Let s see, I
More informationINSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad
INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad  500 043 Electrical and Electronics Engineering TUTORIAL QUESTION BAN Course Name : CONTROL SYSTEMS Course Code : A502 Class : III
More informationDelhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:
Serial : 0. LS_D_ECIN_Control Systems_30078 Delhi Noida Bhopal Hyderabad Jaipur Lucnow Indore Pune Bhubaneswar Kolata Patna Web: Email: info@madeeasy.in Ph: 04546 CLASS TEST 089 ELECTRONICS ENGINEERING
More informationME 375 Final Examination Thursday, May 7, 2015 SOLUTION
ME 375 Final Examination Thursday, May 7, 2015 SOLUTION POBLEM 1 (25%) negligible mass wheels negligible mass wheels v motor no slip ω r r F D O no slip e in Motor% Cart%with%motor%a,ached% The coupled
More information12.7 Steady State Error
Lecture Notes on Control Systems/D. Ghose/01 106 1.7 Steady State Error For first order systems we have noticed an overall improvement in performance in terms of rise time and settling time. But there
More informationEECE 2510 Circuits and Signals, Biomedical Applications Final Exam Section 3. Name:
EECE 2510 Circuits and Signals, Biomedical Applications Final Exam Section 3 Instructions: Closed book, closed notes; Computers and cell phones are not allowed Scientific calculators are allowed Complete
More informationMAE143 B  Linear Control  Spring 2018 Midterm, May 3rd
MAE143 B  Linear Control  Spring 2018 Midterm, May 3rd Instructions: 1. This exam is open book. You can consult any printed or written material of your liking. 2. You have 70 minutes. 3. Most questions
More informationLecture 5: Frequency domain analysis: Nyquist, Bode Diagrams, second order systems, system types
Lecture 5: Frequency domain analysis: Nyquist, Bode Diagrams, second order systems, system types Venkata Sonti Department of Mechanical Engineering Indian Institute of Science Bangalore, India, 562 This
More informationPHYSICS 171 UNIVERSITY PHYSICS LAB II. Experiment 6. Transient Response of An RC Circuit
PHYSICS 171 UNIVERSITY PHYSICS LAB II Experiment 6 Transient Response of An RC Circuit Equipment: Supplies: Function Generator, Dual Trace Oscilloscope.002 Microfarad, 0.1 Microfarad capacitors; 1 Kilohm,
More informationu (t t ) + e ζωn (t tw )
LINEAR CIRCUITS LABORATORY OSCILLATIONS AND DAMPING EFFECT PART I TRANSIENT RESPONSE TO A SQUARE PULSE Transfer Function F(S) = ω n 2 S 2 + 2ζω n S + ω n 2 F(S) = S 2 + 3 RC ( RC) 2 S + 1 RC ( ) 2 where
More informationTime Response Analysis (Part II)
Time Response Analysis (Part II). A critically damped, continuoustime, second order system, when sampled, will have (in Z domain) (a) A simple pole (b) Double pole on real axis (c) Double pole on imaginary
More informationEE202 Exam III April 6, 2017
EE202 Exam III April 6, 207 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo202 DeCarlo2022 7:30 MWF :30 TTH INSTRUCTIONS There are 3 multiple choice worth 5 points each and
More informationDepartment of Electrical and Computer Engineering. EE461: Digital Control  Lab Manual
Department of Electrical and Computer Engineering EE461: Digital Control  Lab Manual Winter 2011 EE 461 Experiment #1 Digital Control of DC Servomotor 1 Objectives The objective of this lab is to introduce
More informationProblem Value Score Total 100/105
RULES This is a closed book, closed notes test. You are, however, allowed one piece of paper (front side only) for notes and definitions, but no sample problems. The top half is the same as from the first
More information'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ. EGR 224 Spring Test II. Michael R. Gustafson II
'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ EGR 224 Spring 2017 Test II Michael R. Gustafson II Name (please print) In keeping with the Community Standard, I have neither provided nor received any
More informationControl System. Contents
Contents Chapter Topic Page Chapter Chapter Chapter3 Chapter4 Introduction Transfer Function, Block Diagrams and Signal Flow Graphs Mathematical Modeling Control System 35 Time Response Analysis of
More informationELECTRONIC SYSTEMS. Basic operational amplifier circuits. Electronic Systems  C3 13/05/ DDC Storey 1
Electronic Systems C3 3/05/2009 Politecnico di Torino ICT school Lesson C3 ELECTONIC SYSTEMS C OPEATIONAL AMPLIFIES C.3 Op Amp circuits» Application examples» Analysis of amplifier circuits» Single and
More informationDEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING RUTGERS UNIVERSITY
DEPARTMENT OF EECTRICA AND COMPUTER ENGINEERING RUTGERS UNIVERSITY 330:222 Principles of Electrical Engineering II Spring 2002 Exam 1 February 19, 2002 SOUTION NAME OF STUDENT: Student ID Number (last
More informationModule 07 Control Systems Design & Analysis via RootLocus Method
Module 07 Control Systems Design & Analysis via RootLocus Method Ahmad F. Taha EE 3413: Analysis and Desgin of Control Systems Email: ahmad.taha@utsa.edu Webpage: http://engineering.utsa.edu/ taha March
More informationPURPOSE: See suggested breadboard configuration on following page!
ECE4902 Lab 1 C2011 PURPOSE: Determining Capacitance with Risetime Measurement Reverse Biased Diode Junction Capacitance MOSFET Gate Capacitance Simulation: SPICE Parameter Extraction, Transient Analysis
More informationTime Varying Circuit Analysis
MAS.836 Sensor Systems for Interactive Environments th Distributed: Tuesday February 16, 2010 Due: Tuesday February 23, 2010 Problem Set # 2 Time Varying Circuit Analysis The purpose of this problem set
More informationH(s) = 2(s+10)(s+100) (s+1)(s+1000)
Problem 1 Consider the following transfer function H(s) = 2(s10)(s100) (s1)(s1000) (a) Draw the asymptotic magnitude Bode plot for H(s). Solution: The transfer function is not in standard form to sketch
More informationQuanser NIELVIS Trainer (QNET) Series: QNET Experiment #02: DC Motor Position Control. DC Motor Control Trainer (DCMCT) Student Manual
Quanser NIELVIS Trainer (QNET) Series: QNET Experiment #02: DC Motor Position Control DC Motor Control Trainer (DCMCT) Student Manual Table of Contents 1 Laboratory Objectives1 2 References1 3 DCMCT Plant
More informationDEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING
KINGS COLLEGE OF ENGINEERING DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING QUESTION BANK SUBJECT CODE & NAME: CONTROL SYSTEMS YEAR / SEM: II / IV UNIT I SYSTEMS AND THEIR REPRESENTATION PARTA [2
More informationControl of Electromechanical Systems
Control of Electromechanical Systems November 3, 27 Exercise Consider the feedback control scheme of the motor speed ω in Fig., where the torque actuation includes a time constant τ A =. s and a disturbance
More informationRoot Locus. Signals and Systems: 3C1 Control Systems Handout 3 Dr. David Corrigan Electronic and Electrical Engineering
Root Locus Signals and Systems: 3C1 Control Systems Handout 3 Dr. David Corrigan Electronic and Electrical Engineering corrigad@tcd.ie Recall, the example of the PI controller car cruise control system.
More informationMASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Mechanical Engineering Dynamics and Control II Fall K(s +1)(s +2) G(s) =.
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Mechanical Engineering. Dynamics and Control II Fall 7 Problem Set #7 Solution Posted: Friday, Nov., 7. Nise problem 5 from chapter 8, page 76. Answer:
More informationDESIGN MICROELECTRONICS ELCT 703 (W17) LECTURE 3: OPAMP CMOS CIRCUIT. Dr. Eman Azab Assistant Professor Office: C
MICROELECTRONICS ELCT 703 (W17) LECTURE 3: OPAMP CMOS CIRCUIT DESIGN Dr. Eman Azab Assistant Professor Office: C3.315 Email: eman.azab@guc.edu.eg 1 TWO STAGE CMOS OPAMP It consists of two stages: First
More information3 Lab 3: DC Motor Transfer Function Estimation by Explicit Measurement
3 Lab 3: DC Motor Transfer Function Estimation by Explicit Measurement 3.1 Introduction There are two common methods for determining a plant s transfer function. They are: 1. Measure all the physical parameters
More informationR a) Compare open loop and closed loop control systems. b) Clearly bring out, from basics, Forcecurrent and ForceVoltage analogies.
SET  1 II B. Tech II Semester Supplementary Examinations Dec 01 1. a) Compare open loop and closed loop control systems. b) Clearly bring out, from basics, Forcecurrent and ForceVoltage analogies..
More information'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ. EGR 224 Spring Test II. Michael R. Gustafson II
'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ EGR 224 Spring 2018 Test II Michael R. Gustafson II Name (please print) In keeping with the Community Standard, I have neither provided nor received any
More informationTeaching State Variable Feedback to Technology Students Using MATLAB and SIMULINK
Teaching State Variable Feedback to Technology Students Using MATLAB and SIMULINK Kathleen A.K. Ossman, Ph.D. University of Cincinnati Session 448 I. Introduction This paper describes a course and laboratory
More informationECE343 Test 2: Mar 21, :008:00, Closed Book. Name : SOLUTION
ECE343 Test 2: Mar 21, 2012 6:008:00, Closed Book Name : SOLUTION 1. (25 pts) (a) Draw a circuit diagram for a differential amplifier designed under the following constraints: Use only BJTs. (You may
More informationLab 4 RC Circuits. Name. Partner s Name. I. Introduction/Theory
Lab 4 RC Circuits Name Partner s Name I. Introduction/Theory Consider a circuit such as that in Figure 1, in which a potential difference is applied to the series combination of a resistor and a capacitor.
More informationECEN 607 (ESS) OpAmps Stability and Frequency Compensation Techniques. Analog & MixedSignal Center Texas A&M University
ECEN 67 (ESS) OpAmps Stability and Frequency Compensation Techniques Analog & MixedSignal Center Texas A&M University Stability of Linear Systems Harold S. Black, 97 Negative feedback concept Negative
More informationEE 321 Analog Electronics, Fall 2013 Homework #3 solution
EE 32 Analog Electronics, Fall 203 Homework #3 solution 2.47. (a) Use superposition to show that the output of the circuit in Fig. P2.47 is given by + [ Rf v N + R f v N2 +... + R ] f v Nn R N R N2 R [
More informationLab Experiment 2: Performance of First order and second order systems
Lab Experiment 2: Performance of First order and second order systems Objective: The objective of this exercise will be to study the performance characteristics of first and second order systems using
More informationState Feedback Controller for Position Control of a Flexible Link
Laboratory 12 Control Systems Laboratory ECE3557 Laboratory 12 State Feedback Controller for Position Control of a Flexible Link 12.1 Objective The objective of this laboratory is to design a full state
More informationPHYSICS 122 Lab EXPERIMENT NO. 6 AC CIRCUITS
PHYSICS 122 Lab EXPERIMENT NO. 6 AC CIRCUITS The first purpose of this laboratory is to observe voltages as a function of time in an RC circuit and compare it to its expected time behavior. In the second
More informationHomework Assignment 11
Homework Assignment Question State and then explain in 2 3 sentences, the advantage of switched capacitor filters compared to continuoustime active filters. (3 points) Continuous time filters use resistors
More information06 Feedback Control System Characteristics The role of error signals to characterize feedback control system performance.
Chapter 06 Feedback 06 Feedback Control System Characteristics The role of error signals to characterize feedback control system performance. Lesson of the Course Fondamenti di Controlli Automatici of
More information