Thermal engineering with QuickField
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1 Thermal engineering with QuickField Vladimir Podnos Director of marketing and support, Tera Analysis Ltd. Thermal problems in QuickField Sergey Ionin Support engineer, Tera Analysis Ltd. Basics of the thermal problem setup
2 Thermal problems in QuickField Vladimir Podnos, Director of Marketing and Support, Tera Analysis Ltd.
3 QuickField Magnetic Problems Electric Problems Thermal and mechanical problems Magnetic analysis suite Magnetostatics AC Magnetics Transient Magnetics Electric analysis suite Electrostatics and DC Conduction AC Conduction Transient Electric field Thermostructural analysis suite Steady-State Heat transfer Transient Heat transfer Stress analysis
4 Thermal analysis Magnetic Problems Electric Problems Thermal and mechanical problems Magnetic analysis suite Magnetostatics AC Magnetics Transient Magnetics Electric analysis suite Electrostatics and DC Conduction AC Conduction Transient Electric field Thermostructural analysis suite Steady-State Heat transfer Transient Heat transfer Stress analysis
5 Stages of solution Geometry Physical parameters Result
6 Thermal parameters Blocks: Thermal conductivity (may be temperaturedependent or anisotropic); Volume power of the heat source; for time-domain Specific heat (may be temperature-dependent); Volume density. Edges: Vertices: Coupling: Temperature, flux, convection, radiation; Equal temperature, even and odd periodic temperature. Temperature; Heat sources. Heat Sources distribution may be imported from Electromagnetic problems
7 Thermal parameters Blocks: Thermal conductivity (may be temperaturedependent or anisotropic); Volume power of the heat source; for time-domain Specific heat (may be temperature-dependent); Volume density. Edges: Vertices: Coupling: Temperature, flux, convection, radiation; Equal temperature, even and odd periodic temperature. Temperature; Heat sources. Heat Sources distribution may be imported from Electromagnetic problems
8 Basics of the thermal problem setup Sergey Ionin Support engineer, Tera Analysis Ltd.
9 Basics of the thermal problem setup 1. Heat transfer through the wall. Heat Losses. 2. Natural Convection. Calculation of the convection coefficient. 3. Radiation. Heat Transfer in case of Radiation. 4. Complex problem with automation.
10 1. Heat transfer through the wall. Water t=95 0 C Heat Losses. Wall λ = 42 W/(K m) t=15 0 C α = 2850 W/(K m 2 ) α = 10 W/(K m2 ) Air Find: 1. Temperature of the wall surface 2. Heat flux t, 0 С Flux, W/m 2 Theory* 94,52 795,2 QuickField 94,53 795,3 *Engineering Thermodynamics, Third Edition, R.K.Rajput, example 15.6
11 Basics of the thermal problem setup 1. Heat transfer through the wall. Heat Losses. 2. Natural Convection. Calculation of the convection coefficient. 3. Radiation. Heat Transfer in case of Radiation. 4. Complex problem with automation.
12 inside t = C α =? Convection Brick wall Insulation Plaster Find: 1. Convection coefficients 2. Temperature of the wall 3. In what layer the condensation may occur (dew point 10 0 C) outside t = C α =?
13 Convection Surface shape and orientation Specific dimensions, L Viscosity, μ Thermal conductivity, λ Density, ρ Thermal coefficient of volumetric expansion, β Heat capacity, C p Temperature, T; Temperature difference ΔT Similarity theory formulas for the natural convection from the vertical plate Grasshof number Prandtl number Rayleigh number Gr L 3 C Pr 2 g T p Ra Gr Pr 2 Convection coefficient Nu L Nusselt number Nu 1/ Ra /16 8/ 27 [1 (0.492 / Pr) ]
14 Pr Ra Gr Pr Ra Gr Convection inside Nu outside Nu W/(K m 2 ) W/(K m 2 )
15 Convection inside t = C α = 3.59 W/(K m 2 ) λ = 0,7 W/(K m) λ = 0,04 W/(K m) λ = 0,21 W/(K m) outside t = C α = 3,80 W/(K m 2 )
16 Basics of the thermal problem setup 1. Heat transfer through the wall. Heat Losses. 2. Natural Convection. Calculation of the convection coefficient. 3. Radiation. Heat Transfer in case of Radiation. 4. Complex problem with automation.
17 Radiation Find: 1. Temperature of the filament Q = P / V P bulb power V filament volume Straightening of the tungsten filament Radiating surface Zero-flux surface (radiated energy =absorbed energy)
18 Basics of the thermal problem setup 1. Heat transfer through the wall. Heat Losses. 2. Natural Convection. Calculation of the convection coefficient. 3. Radiation. Heat Transfer in case of Radiation. 4. Complex problem with automation.
19 Steam Pipe Air α = 30 W/(K m 2 ) Find: Insulation λ = 0,8 W/(K m) 1. Insulation thickness to limit heat losses by 2.1 kw r, mm Theory* 105 QuickField 104,65 *Engineering Thermodynamics, Third Edition, R.K.Rajput, example Steam, α = 100 W/(K m 2 ) Steel Pipe, λ = 42 W/(K m)
20 Steam Pipe Similarity theory formulas for the natural convection from the cylindrical surface Grasshof number Prandtl number Rayleigh number Nusselt number Gr Nu Convection coefficient L 3 C Pr 2 g T p Ra Gr Pr Nu L Ra / Pr 1/ 6 9/16 8/ 27 2
21 More examples QuickField.com > Applications > Industrial > Thermal models Applications > Sample problems> Examples gallery
22 Thank you
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