PART - I : PHYSICS ALLEN. According to problem particle is to land on disc. If we consider a time 't' then x component of displacement is Rwt
|
|
- Mildred Hubbard
- 5 years ago
- Views:
Transcription
1 IIT-JEE 0 EXAMINATIN TARGET : IIT-JEE 0 (eld on ) PAPER - ( ANSWERS & SLUTINS)
2 IIT-JEE 0 EXAMINATIN (ELD N : ) PART - I : PYSICS PAPER - SECTIN I : Single Correct Answer Type This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which NLY NE is correct.. Consider a disc rotating in the horizontal plane with a constant angular speed w about its centre. The disc has a shaded region on one side of the diameter and an unshaded region on the other side as shown in the figure. When the disc is in the orientation as shown, two pebbles P and Q are simultaneously projected at an angle towards R. The velocity of projection is in the y-z plane and is same for both pebbles with respect to the disc. Assume that (i) they land back on the disc before the disc has completed rotation, (ii) their range is less than half the disc radius, and (iii) w remains 8 constant throughout. Then (A) P lands in the shaded region and Q in the unshaded region. (B) P lands in the unshaded region and Q in the shaded region. (C) Both P and Q land in the unshaded region. (D) Both P and Q land in the shaded region. Ans. (C) y x R P Q w wt Rsinwt Rwt According to problem particle is to land on disc. If we consider a time 't' then x component of displacement is Rwt Rsinwt < Rwt Thus particle P lands in unshaded region. For Q, x-component is very small and y-component equal to P it will also land in unshaded region. Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: / 9
3 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER -. In the given circuit, a charge of +80 mc is given to the upper plate of the 4mF capacitor. Then in the steady state, the charge on the upper plate of the mf capacitor is +80mC 4mF mf mf (A) + mc (B) + 40mC (C) +48mC (D) + 80mC Ans. (C) KCL at x (x 0) + (x 0) 80 = 0 Þ 5x = 80 Þ x =6 v Þ charge on mf = (x 0) (mf) = 48 mc +80mC -80m C mf. Two moles of ideal helium gas are in a rubber balloon at 0 C. The balloon is fully expandable and can be assumed to required no energy in its expansion. The temperature of the gas in the balloon is slowly changed to 5 C. The amount of heat required in raising the temperature is nearly (take R = 8. J/mol.K) (A) 6 J (B) 04 J (C) 4 J (D) 08 J Ans. (D) (x) mf f æ f ö DQ = DU + DW = nrdt + PDV = ç + nrdt è ø æ ö = ç + ( 8. )( 5 ) = 08 J è ø 4. A loop carrying current I lies in the x-y plane as shown in the figure. The unit vector ˆk is coming out of the plane of the paper. The magnetic moment of the current loop is 0 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
4 Ans. (B) (A) ˆ a Ik (B) IIT-JEE 0 EXAMINATIN (ELD N : ) æp ö ç + a Ik ˆ è ø (C) PAPER - æp ö - ç + a Ik ˆ è ø (D) ( p + ) a Ik ˆ é Magnetic moment = ( )( ) æaö ù æp ö ina = I ê pç + a ú= ç + a Ik ˆ ë èø û è ø 5. Two identical discs of same radius R are rotating about their axes in opposite directions with the same constant angular speed w. The discs are in the same horizontal plane. At time t =0, the points P and Q are facing each other as shown in the figure. The relative speed between the two points P and Q is v r. In one time period (T) of rotation of the discs, v r as a function of time is best represented by (A) (C) Ans. (A) v r R 0 T v r 0 T t t P w (B) (D) w Q v r R 0 T v r 0 T t t vsinq q v q vcosq q vcosq q v vsinq V = Vsinq = Vsin ( wt) rcl Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: / 9
5 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - 6. A thin uniform cylindrical shell, closed at both ends, is partially filled with water. It is floating vertically in water in half-submerged state. If r C is the relative density of the material of the shell with respect to water, then the correct statement is that the shell is (A) more than half-filled if r C is less than 0.5 (B) more than half-filled if r C is more than.0 (C) half-filled if r C is more than 0.5 (D) less than half-filled if r c is less than 0.5 Ans. (A) V W For floating : mcg+ mwg= FB inside volume=v & container material volume = V C æv VCö V rcvg C + Vg w = ç + g è ø ÞVw V ö = + Cç -rc è ø æ ö if ç r C < è ø V V w > 7. A student is performing the experiment of Resonance Column. The diameter of the column tube is 4 cm. The frequency of the tuning fork is 5 z. The air temperature is 8 C in which the speed of sound is 6 m/s. The zero of the meter scale coincides with the top end of the Resonance column tube. When the first resonance occurs, the reading of the water level in the column is (A) 4.0 cm (B) 5. cm (C) 6.4 cm (D) 7.6 cm Ans. (B) l l v In resonance column experiment = l +e so, l = - e= -0.d 4 4 4f 6 00 cm = -( 0. )( 4 cm ) = = 5. cm An infinitely long hollow conducting cylinder with inner radius R/ and outer radius R carries a uniform current density along its length. The magnitude of the magnetic field, B r as a function of the radial distance r from the axis is best represented by (A) B (B) B R/ R r R/ R r (C) 4 / 9 B R/ R r B (D) R/ R Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: r
6 Ans. (D) B = 0 for r < R/ IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - B æm0jr m0 I ö = ç - è r ø for R r R = B B m I r 0 = r ³ R B B R/ R B r Section-II : Paragraph Type This section contains 6 multiple choice questions relating to three paragraphs with two questions on each paragraph. Each question has four choices (A), (B), (C) and (D) out of which NLY NE is correct. Paragraph for Questions 9 and 0 Most materials have the refractive index, n>. So, when a light ray from air enters a naturally occurring material, then by Snell's law, sinq n sinq = n, it is understood that the refracted ray bends towards the normal. But it never emerges on the same side of the normal as the incident ray. According to æcö electromagnetism, the refractive index of the medium is given by the relation, n = ç =± em r r è vø, where c is the speed of electromagnetic waves in vacuum, v its speed in the medium, e r and m r are the relative permittivity and permeability of the medium respectively. In normal materials, both e r and m r are positive, implying positive n for the medium. When both e r and m r are negative, one must choose the negative root of n. Such negative refractive index materials can now be artificially prepared and are called meta-materials. They exhibit significantly different optical behaviour, without violating any physical laws. Since n is negative, it results in a change in the direction of propagation of the refracted light. owever, similar to normal materials, the frequency of light remains unchanged upon refraction even in meta-materials. 9. For light incident from air on a meta-material, the appropriate ray diagram is Air q Air q (A) Meta-material q (B) Meta-material q Air q Air q (C) Meta-material q (D) Meta-material q Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 5 / 9
7 Ans. (C) Snell's law : IIT-JEE 0 EXAMINATIN (ELD N : ) sinq n sinq = n so, sinq = n sinq n sinq For Air & meta material sinq ( ) =, q - n is ( ve) 0. Choose the correct statement. (A) The speed of light in the meta-material is v = c n PAPER - Ans. (B) (B) The speed of light in the meta-material is v = c n (C) The speed of light in the meta-material is v = c. (D) The wavelength of the light in the meta-material (l m ) is given by l m = l air n, where l air is the wavelength of the light in air. C By definition of n : V = n Paragraph for Questions and The general motion of a rigid body can be considered to be a combination of (i) a motion of its centre of mass about an axis, and (ii) its motion about an instantaneous axis passing through the centre of mass. These axes need not be stationary. Consider, for example, a thin uniform disc welded (rigidly fixed) horizontally at its rim to a massless stick, as shown in the figure. When the disc-stick system is rotated about the origin on a horizontal frictionless plane with angular speed w, the motion at any instant can be taken as a combination of (i) a rotation of the centre of mass of the disc about the z- axis, and (ii) a rotation of the disc through an instantaneous vertical axis passing through its centre of mass (as is seen from the changed orientation of points P and Q). Both these motions have the same angular speed w in this case. Q P z w P Q y x Now consider two similar systems as shown in the figure : case (A) the disc with its face vertical and parallel to x-z plane; Case (B) the disc with its face making an angle of 45 with x-y plane and its horizontal diameter parallel to x-axis. In both the cases, the disc is welded at point P, and the systems are rotated with constant angular speed w about the z-axis. z w Q z w Q P y P y x case (a) x case (b) 6 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
8 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER -. Which of the following statements regarding the angular speed about the instantaneous axis (passing through the centre of mass) is correct? (A) It is w for both the cases. (B) It is w for case (a); and w for case (b). (C) It is w for case (a); and w for case (b). (D) It is w for both the cases. Ans. (D) Since body is rigid therefore w is same about each point.. Which of the following statements about the instantaneous axis (passing through the centre of mass) is correct? (A) It is vertical for both the cases (a) and (b). (B) It is vertical for case (a); and is at 45 to the x-z plane and lies in the plane of the disc for case (b). (C) It is horizontal for case (a); and is at 45 to the x-z plane and is normal to the plane of the disc for case (b). (D) It is vertical for case (a); and is at 45 to the x-z plane and is normal to the plane of the disc for case (b). Ans. (A) Since body is rigid therefore all of its part rotate about same axis. Paragraph for Questions and 4 The b-decay process, discovered around 900, is basically the decay of a neutron (n). In the laboratory, a proton (p) and an electron (e ) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a two-body decay process, it was predicted theoretically that the kinetic energy of the electron should be a constant. But experimentally, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process, i.e. n p + e + v r e, around 90, Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino ( v r e ) massless and possessing negligible energy, and the neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is ev. The kinetic energy carried by the proton is only the recoil energy.. If the anti-neutrino had a mass of ev/c (where c is the speed of light) instead of zero mass, what should be the range of the kinetic energy, K, of the electron? (A) 6 0 K ev (B) 6.0eV K ev (C) 6.0eV K < ev (D) 6 0 K < ev Ans. (D) Electron kinetic energy has continuous spectrum. Q-value of this reaction is very close to 0.8 MeV. 6 So 0 K < ev 4. What is the maximum energy of the anti-neutrino? (A) zero (B) much less than ev (C) Nearly ev (D) Much larger than ev Ans. (C) Sum of kinetic energy of electron and energy of neutrino remains nearly constant and proton carries away with negligible energy due to heavy mass. to be Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 7 / 9
9 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - Section III : Multiple Correct Answer (s) Type This section contains 6 multiple questions. Each question has four choices (A)_, (B), (C) and (D) out of which NE or MRE are correct. 5. A current carrying infinitely long wire is kept along the diameter of a circular wire loop, without touching it. The correct statement(s) is (are) (A) The emf induced in the loop is zero if the current is constant. (B) The emf induced in the loop is infinite if the current is constant. (C) The emf induced in the loop is zero if the current decreases at a steady rate. (D) The emf induced in the loop is finite if the current decreases at a steady rate. Ans. (A,C) Since flux of wire on the loop is zero therefore emf will not be induced. 6. In the given circuit, the AC source has w = 00 rad/s. Considering the inductor and capacitor to be ideal, the correct choice (s) is(are) 00mF W I 0V (A) The current through the circuit, I is 0. A. (B) The current through the circuit, i is 0. ÖA. (C) The voltage across 00W resistor = 0ÖV. (D) The voltage across 50W resistor = 0V. Ans. (A,C) 0 0 I = = = z A at 45 leading 00 5 I 0 0 = = = A at 45 lagging z 50 5 I = I + I = A» 0.A 0 VR = I R = 00 = 0 V 5 50W I X C=00mF I X =50R L R =00W 0V R =50W B I B 8 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
10 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - 7. Six point charges are kept at the vertices of a regular hexagon of side L and centre, as shown in q figure. Given that K = 4p Î, which of the following statement(s) is(are) correct? L 0 +q F L P E -q A +q S B +q (A) The electric field at is 6 K along D. (B) The potential at is zero. R C -q (C) The potential at all points on the line PR is same. (D) The potential at all points on the line ST is same. Ans. (A,B,C) T D -q Resultant is 6 K along D. For every point of PR there are two charges of opposite sign and equal magnitude at equal distance. 8. Two spherical planets P and Q have the same uniform density r, masses M P and M Q, and surface areas A and 4A, respectively. A spherical planet R also has uniform density r and its mass is (M P + M Q ). The escape velocities from the planets P, Q and R, are V P, V Q and V R, respectively. Then Ans. (B,D) (A) V Q > V R > V P (B) V R > V Q > V P (C) V R /V P = (D) V P /V Q = / 4 p Escape velocity = GM R µ µ R R [since density of each planet is same] Area Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 9 / 9
11 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - 9. The figure shows a system consisting of (i) a ring of outer radius R rolling clockwise without slipping on a horizontal surface with angular speed w and (ii) an inner disc of radius R rotating anti-clockwise with angular speed w/. The ring and disc are separated by frictionless ball bearing. The system is in the x-z plane. The point P on the inner disc is at a distance R from the origin, where P makes an angle of 0 with the horizontal. Then with respect to the horizontal surface, z w (A) the point has a linear velocity Rwiˆ w/ R R P 0 R (B) the point P has a linear velocity Rwi ˆ + Rwkˆ 4 4 (C) the point P has a linear velocity Rwi ˆ - Rwkˆ 4 4 æ ö (D) the point P has a linear velocity ç - Rwiˆ+ Rwkˆ è 4 ø 4 Ans. (AB) Velocity of the centre = v = rw, ˆ Rw sin 0 ˆ Rw v cos 0 ˆ P = Rwi - i + k v= Rwiˆ Rw/ 0 Rw ˆ ˆ Rwk vp = i Two solid cylinders P and Q of same mass and same radius start rolling down a fixed inclined plane from the same height at the same time. Cylinder P has most of its mass concentrated near its surface, while Q has most of its mass concentrated near the axis. Which statement(s) is(are) correct? (A) Both cylinders P and Q reach the ground at the same time. (B) Cylinder P has larger acceleration than cylinder Q. (C) Both cylinders reach the ground with same translational kinetic energy. (D) Cylinder Q reaches the ground with larger angular speed. Ans. (D) x P w Rw 0 / 9 q g sinq a = (where k is radius of curvature); k P > k Q k + R Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
12 IIT-JEE 0 EXAMINATIN (ELD N : ) PART - II : CEMISTRY PAPER - SECTIN I : Single Correct Answer Type This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which NLY NE is correct.. The compound that undergoes decarboxylation most readily under mild condition is : (A) C C C (B) C (C) C C (D) C C Ans. (B) It is example of b-keto acid which undergoes decarboxylation most readily.. The shape of Xe F molecule is Ans. (D) (A) Trigonal bipyramidal (C) tetrahedral F Xe F See-saw (B) Square planar (D) see-saw. For a dilute solution containing.5 g of a non-volatile non-electrolyte solute in 00 g of water, the Ans. (A) elevation in boiling point at atm pressure is C. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of g) of the solution is (take K b =0.76 K kg mol ) (A) 74 (B) 740 (C) 76 (D) 78 DT b = K b m...(i) 760 PS 8 = m [for a dilute solution]...(ii) By eq. (i) / (ii) = P 8 S P S = 74 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: / 9
13 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - 4. NiCl {P(C 5 ) (C 6 5 )} exhibits temperature dependent magnetic behavior (paramagnetic/diamagnetic). The coordination geometries of Ni + in the paramagnetic and diamagnetic states are respectively : (A) tetrahedral and tetrahedral (B) square planar and square planar (C) tetrahedral and square planar (D) square planar and tetrahedral Ans. (C) For tetrahedral compound For square planar compound + 8 Ni = d + 8 Ni = d d xy d yz d zx d x y d 8 d x y d z Two unpaired electron. ence paramagnetic d xy d z d xz d yz No unpaired electron ence dimagnetic 5. The major product of the given reaction sequence is : Ans. (B) C C C C CN (A) C C = C C C (C) C C C C C G 95% S eat 4 (B) C C= C CN C (D) C C= C C N C C C C C CN C C C C CN C C=C CN+ C 95% S4 (acts as dehydrating reagent) / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
14 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - 6. The reaction of white phosphorus with aqueous Na gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively (A) redox reaction ; and 5 (B) redox reaction ; + and +5 (C) disproportionation reaction ; and +5 (D) disproportionation reaction ; and + Ans. N PTIN IS CRRECT P 4 + Na (aq.) ¾ ¾ P - + xidation state of P in P = Na P + xidation state of P in Na P = + ence, (No option) is correct 7. Using the data provided, calculate the multiple bond energy (kj mol ) of a C º C bond in C. Ans. (D) That energy is (take the bond energy of a C bond as 50 kj mol.) C(s) + (g) ¾ C (g) D = 5 kj mol C(s) ¾ C(g) D = 40 kj mol (g) ¾ (g) D = 0 kj mol (A) 65 (B) 87 (C) 865 (D) 85 C(s) + (g) ¾ C º C (g) D = 5 kj/mole Þ 5 = D sub C(s) + B.E. B.E. C B.E. CºC 5 = B.E. CºC 5 = (B.E.) CºC B.E. CºC = 85 kj/mole 8. In the cyanide extraction process of silver from argentite ore, the oxidizing and reducing agents used are : Ans. (B) (A) and C respectively. (C) N and Zn dust respectively. (B) and Zn dust respectively. (D) N and C respectively. NaCN Ag S ¾¾¾¾¾ [Ag(CN) in presenceof air ] Ag S + 4NaCN Na [Ag(CN) ] + Na S Na S + + ¾ ¾ Na S 4 + S + Na ence, oxidising agent is. [Ag(CN )] + Zn ¾ ¾ Ag + [Zn (CN) 4 ] ence, reducing agent is 'Zn'. Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: / 9
15 IIT-JEE 0 EXAMINATIN (ELD N : ) SECTIN-II : Paragraph Type PAPER - This section contains 6 multiple choice questions relating to three paragraphs with two questions on each paragraph. Each question has four choices (A), (B), (C) and (D), out of which NLY NE is correct. Paragraph for Question 9 and 0 Bleaching powder and bleach solution are produced on a large scale and used in several house-hold products. The effectiveness of bleach solution is often measured by iodometry. 9. Bleaching powder contains a salt of an oxoacid as one of its components. The anhydride of that oxoacid is : Ans. (A) (A) Cl (B) Cl 7 (C) Cl (D) Cl 6 Bleaching powder is Ca(Cl)Cl. So, the associated oxo acid is Cl. ence, the anhydride of this acid is Cl. (Cl ¾ ¾ ¾ - Cl ) 0. 5 ml of household bleach solution was mixed with 0 ml of 0.50 M KI and 0 ml of 4 N acetic Ans. (C) acid. In the titration of the liberated iodine, 48 ml of 0.5 N Na S was used to reach the end point. The molarity of the household bleach solution is (A) 0.48 M (B) 0.96 M (C) 0.4 M (D) 0.04 M Eq. of CaCl = Eq. of Na S 5 M = [ + + CaCl + e ¾ Ca Cl ] (nf = ) M = 0.4 Paragraph for Question and In the following reaction sequence, the compound J is an intermediate. (C C) I C CNa J (i), Pd/C (ii) SCl (iii) anhyd. AlCl J (C 9 8 ) gives effervescence on treatment with NaC and a positive Baeyer s test.. The compound K is : K (A) (B) (C) (D) Ans. (C) 4 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
16 . The compound I is IIT-JEE 0 EXAMINATIN (ELD N : ) C PAPER - (A) (B) (C) (D) Ans. (A) C=C C I (C C) CCNa J (C) 9 8 J gives effervescence on treatment with NaC due to presence of C group and positive Baeyer's test due to presence of unsaturation. C=C C C C C (Pd) SCl C Cl AlCl K (Intramoleculer Fridel craft reaction) Paragraph for Question and 4 The electrochemical cell shown below is a concentration cell. M M + (saturated solution of a sparingly soluble salt, MX ) M + (0.00 mol dm ) M The emf of the cell depends on the difference in concentrations of M + ions at the two electrodes. The emf of the cell at 98 K is 0.059V.. The value of DG (kj mol ) for the given cell is (take If = C mol ) (A) 5.7 (B) 5.7 (C).4 (D).4. Ans. (D) Q DG = nfe DG = Joule =.4 kj/mole 4. The solubility product (K sp ; mol dm 9 ) of MX at 98 K based on the information available for the given concentration cell is (take.0 R 98/F = V) (A) 0 5 (B) (C) 0 (D) 0 Ans. (B) = [M ] log [M ] - = [M ++ ] = 0 5 = s K sp = 4s = 4 (0 5 ) = Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 5 / 9
17 IIT-JEE 0 EXAMINATIN (ELD N : ) SECTIN-III : Multiple Correct Answser(s) Type PAPER - This section contains 5 multiple choice question. Each question has four choices (A), (B), (C) and (D) out of which NE or MRE are correct. 5. The given graphs / data I, II, III and IV represent general trends observed for different physisorption and chemisorption processes under mild conditions of temperature and pressure. Which of the following choice(s) about I, II, III and IV is (are) correct? Amount of gas adsorbed Amount of gas adsorbed T P (I) (III) P constant 00K 50K (A) I is physisorption and II is chemisorption (C) IV is chemisorption and II is chemisorption Ans. (A,C) Amount of gas absorbed Potential energy (II) T (IV) P constant 0 Distance of molecule from the surface D uds=50kjmol (B) I is physisorption and III is chemisorption (D) IV is chemisorption and III is chemisorption 6. The reversible expansion of an ideal gas under adiabatic and isothermal conditions is shown in the figure. Which of the following statement(s) is (are) correct? (P,V,T) P adiabatic isothermal (P,V,T) (P,V,T) V (A) T = T (B) T > T (C) w isothermal > w adiabatic (D) DU isothermal > DU adiabatic 6 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
18 Ans. (A,D) IIT-JEE 0 EXAMINATIN (ELD N : ) (A) Since process is isothermal. (B) In adiabatic expansion temperature decreases. (C) Although W isothermal,exp > W adiabatic,exp Since expansion work is ve, so option is wrong. (D) Q DU isothermal = 0 & DU adiabatic < 0 Þ DU isothermal > DU adiabatic 7. For the given aqueous reactions, which of the statement(s) is (are) true? dilute S4 excess KI + K [Fe(CN) 6] brownish-yellow solution PAPER - ZnS 4 white precipitate + brownish-yellow filtrate NaS colourless solution (A) The first reaction is a redox reaction. (B) White precipitate is Zn [Fe(CN) 6 ]. (C) Addition of filtrate to starch solution gives blue colour. (D) White precipitate is soluble in Na solution. Ans. (A,C,D) I + [Fe(CN) 6 ] ¾ ¾ [Fe(CN) 6 ] 4 + I (Redox reaction) I + I ¾ ¾ I (Brownish yellow filtrate or solution). [Fe(CN) 6 ] 4 + Zn ¾ ¾ Zn [Fe(CN) 6] or K Zn [Fe(CN) 6] and I + S ¾ ¾ I + S 4 6 white ppt. (soluble in Na) I I + I ; starch + I ¾ ¾ deep blue solution. ence, answers are A,C, D 8. With reference to the scheme given, which of the given statement(s) about T,U,V and W is (are) correct? C T LiAl 4 (excess) Å Cr / (CC) V U W (A) T is soluble in hot aqueous Na (B) U is optically active (C) Molecular formula of W is C (D) V gives effervescence on treatment with aqueous NaC Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 7 / 9
19 Ans. (A,C,D) IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - C (T) hot aq. Na C Na + (Soluble in aq. Na) C LiAl 4 C Cr / + C (U) optically (inactive) (No Chiral centre) C C C (V) (due to presence of C group it gives effervescence with aq. NaC ) excess (C C) C C C C C C C Moleculor formula C Which of the given statement(s) about N,,P and Q with respect to M is (are) correct? Cl C Cl C Cl C M N Cl C C Cl P Cl Q (A) M and N are non-mirror image stereoisomers (B) M and are identical (C) M and P are enantiomers (D) M and Q are identical 8 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
20 Ans. (A,B,C) IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - (M) C Cl Cl C (N) () (P) (Q) Cl C C Cl C Cl C Cl Cl Cl Cl C C C Cl C MN M MP MQ Diastereomers (non mirror image stereo isomers) Identical Enantiomer Diastereomer 40. With respect to graphite and diamond, which of the statement(s) given below is (are) correct? Ans. (B,D) (A) Graphite is harder than diamond. (B) Graphite has higher electrical conductivity than diamond. (C) Graphite has higher thermal conductivity than diamond. (D) Graphite has higher C C bond order than diamond. Due to resonance the bond order is greater than in case of graphite. Diamond has higher thermal conductivity than graphite. Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 9 / 9
21 IIT-JEE 0 EXAMINATIN (ELD N : ) PART - III : MATEMATICS SECTIN I : Single Correct Answer Type PAPER - This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which NLY NE is correct. 4. Four fair dice D, D, D and D 4, each having six faces numbered,,, 4, 5 and 6 are rolled simultaneously. The probability that D 4 shows a number appearing on one of D, D and D is - (A) 9 6 Ans. (A) 6 C = (B) 08 6 (C) 5 6 (D) If P is a matrix such that P T = P + I, where P T is the transpose of P and I is the identity matrix, éxù é0ù then there exists a column matrix X= ê y ú ¹ ê 0 ú such that ê ú ê ú êëzúû êë0úû (A) é0ù PX= ê 0 ú ê ú êë0 úû Ans. (D) P T = P + I Þ P = P T + I Þ P = (P + I) + I Þ P = 4P + I Þ P = I Þ PX = X 4. Let a(a) and b(a) be the roots of the equation ( ) ( ) ( ) 6 (B) PX = X (C) PX = X (D) PX = X + a - x + + a - x+ + a - = 0 where a >. Then lim a (a) and + lim b (a) are + a 0 a 0 (A) Ans. (B) 5 - and (B) - and (C) ææ aö ö ææ aö ö æ a ö ç ç ç ç ç 6 èè ø ø èè ø ø è ø æx x ö aç + + = 0 Þ x + x + = 0 è 6ø Þ x =-,- Þ lim a (a) a 0 + and lim b ( a) + are a x x+ + - = and (D) - and 9 - and 0 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
22 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER The equation of a plane passing through the line of intersection of the planes x + y + z = and x y + z = and at a distance from the point (,, ) is (A) 5x y + z = 7 (B) x+ y = - (C) x + y + z = (D) x- y = - Ans. (A) Let required plane be (x + y + z ) + l(x y + z ) = 0 Q plane is at a distance Þ l( ) ( +l ) + ( -l ) + ( +l) from the point (,, ). ( ) = ( +l ) + (-l) + ( +l) Þ l = Þ l = l + l 4l + 6l Þ l=- æ 7 ö \ required plane is (x + y + z ) + ç - ( x- y+ z- ) = 0 è ø Þ 5x y + z = Let a, a, a,... be in harmonic progression with a = 5 and a 0 = 5. The least positive integer n for which a n < 0 is (A) (B) (C) 4 (D) 5 Ans. (D) a,a,a...be in.p Þ,,... be in A.P. a a a in A.P. T = = and T0 = = a 5 a0 5 \ T 0 = T + 9d 4 = + 9d Þ d = T n = T + (n )d < 0 Þ (n - - ).4 < Þ < n 4 Þ Þ 99 n 4 < Þ least positive integer n is 5. 4(n -) < Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: / 9
23 IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER If a r and b r r r r are vectors such that a + b = 9 and a (i ˆ+ j ˆ+ 4k) ˆ = (i ˆ+ j ˆ+ 4k) ˆ r b, then a possible r r value of (a + b).( - 7i ˆ+ j ˆ+ k) ˆ is (A) 0 (B) (C) 4 (D) 8 Ans. (C) r r (a + b) (i ˆ+ j ˆ+ 4k) ˆ = 0 Þ r r a + b =l (i ˆ+ j ˆ+ 4k) ˆ r r a + b = 9 Þ l = r r a + b = (i ˆ+ j ˆ+ 4k) ˆ r r (a + b).( 7i ˆ+ ˆj + k) ˆ = = The value of the integral (A) 0 Ans. (B) p/ p/ ò x cos x dx + p/ p/ = (B) p/ p / ò x cos x dx = ò I p/ 0 p+ x p ò / æ ö ç x + ln cos xdx p-x -p/è ø is p - (C) 4 æp+ xö ò l nç p-x cosxdx è ø x cos x dx æ p/ ö p/ = (x sin x) 0 - xsin xdx ç ò è 0 ø = æ p/ p æ öö p/ ç - (x cos x) 0 + cos x dx 4 ç ò è è øø p/ æp ö = ç - cos x dx 4 ò è ø æp ö p = ç - = -4 è 4 ø 0 0 II p p + 4 (D) 48. Let PQR be a triangle of area D with a =, b = 7 and 5 c =, where a, b and c are the lengths of the sides of the triangle opposite to the angles at P, Q and R respectively. Then sin P - sin P equals sinp+ sinp (A) 4D (B) 45 4D æ ö (C) ç è4d ø (D) æ 45 ö ç è4d ø / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
24 Ans. (C) IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - sinp-sinpcosp sinp+ sinpcosp = (- cos P) ( + cosp) = tan A = D s (s- a) = ( (s -b) (s -c) ) D s = 4 = ææ 7öæ 5öö 4-4- ç ç è ç øè ø ç è D ø = æ ö ç è4dø SECTIN II : Paragraph Type This section contains 6 multiple choice questions relating to three paragraphs with two questions on each paragraph. Each question has four choices (A), (B), (C) and (D), out of which NLY NE is correct. Paragraph for Question 49 and 50 Let a n denotes the number of all n-digit positive integers formed by the digits 0, or both such that no consecutive digits in them are 0. Let b n = the number of such n-digit integers ending with digit and c n = the number of such n-digit integers ending with digit The value of b 6 is (A) 7 (B) 8 (C) 9 (D) 50. Which of the following is correct? (A) a 7 = a 6 + a 5 (B) c 7 ¹ c 6 + c 5 (C) b 7 ¹ b 6 + c 6 (D) a 7 = c 7 + b 6 Solution for Q.49 & Q.50 For a n The first digit should be For b n ( n- Places) Last digit is. so b n is equal to number of ways of a n (i.e. remaining (n ) places) b n = a n For c n Last digit is 0 so second last digit must be So c n = a n b n + c n = a n So a n = a n + a n Similarly b n = b n + b n 49. Ans.(B) a =, a = So a =, a 4 = 5 a 5 = 8 Þ b 6 = a 5 = 8 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: / 9
25 50. Ans.(A) a n = a n + a n put n = 7 a 7 = a 6 + a 5 c n = c n + c n So put n = 7 c 7 = c 6 + c 5 IIT-JEE 0 EXAMINATIN (ELD N : ) (A) is correct (B) is incorrect PAPER - b n = b n + b n put n = 7 b 7 = b 6 + b 5 a 7 = a 6 + a 5 while (D) says a 7 = a 5 + a 5 (C) is incorrect (D) is incorrect Paragraph for Question 5 and 5 A tangent PT is drawn to the circle x + y = 4 at the point P(, ). A straight line L, perpendicular to PT is a tangent to the circle (x ) + y =. 5. A common tangent of the two circles is Ans. (D) (A) x = 4 (B) y = (C) x+ y= 4 (D) x+ y = 6-0 h = = 6 - equation of tangents from (6, 0) : y 0 = m(x 6) Þ y mx + 6m = 0 use p = r 6m + m = k= (0,0) (,0) (,0) (h,0) Þ 6m = 4 + 4m m = 4 m = /8 Þ m =± at m =- equation of tangent will be x+ y = A possible equation of L is (A) x- y = (B) x+ y = (C) x- y =- (D) x+ y = 5 4 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
26 Ans. (A) IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER - Equation of tangent at P will be x+ y = 4 Slope of line L will be Let equation of L be : x y= + c Þ x- y+ c= 0 Now this L is tangent to nd circle So + c =± Þ using c =- or c =- c =- x y= - Þ x- y =. ence (A) 5 Paragraph for Question 5 and 54 Let ƒ(x) = ( x) sin x + x for all x Î IR, and let 5. Consider the statements : P : There exists some x Î IR such that ƒ(x) + x = ( + x ) Q : There exists some x Î IR such that ƒ(x) + = x( + x) Then (A) both P and Q are true (C) P is false and Q is true Ans (C) ƒ(x) = ( x) sin x + x P : ƒ(x) + x = ( + x ) Þ ( x) sin x + x + x = + x Þ ( x) sin x x + x = 0 ( - ) ( x) cos x + = 0 which is not possible. \ P is false. Q : ƒ(x) + = x( + x) x + ( x) sin x + = x + x ( x) sin x x + = 0. Let h(x) = ( x) sin x x +, clearly h() = and h(x) = (x x + )sin x x + é æ ö ù = x êç - +.sin x x - + x x x ú ë è ø û \ h(x) as x. \ By intermediate value theorem h(x) = 0 has a root which is greater than. ence Q is true. x æ t ö g(x) = ç -l nt ƒ(t)dt for all x Î (, ). òè t+ ø (B) P is true and Q is false (D) both P and Q are false Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 5 / 9
27 IIT-JEE 0 EXAMINATIN (ELD N : ) 54. Which of the following is true? (A) g is increasing on (, ) (B) g is decreasing on (, ) (C) g is increasing on (,) and decreasing on (, ) (D) g is decreasing on (,) and increasing on (, ) Ans. (B) g( x) x ( - ) ( t+ ) æ t ö = ç -lnt ƒ(t)dt òè ø PAPER - æ(x -) ö g' ( x) = ç -lnx ƒ(x) è x+ ø ƒ(x) > 0 " xîr Suppose. (x -) h(x) = -lnx x+ æ 4 ö h(x) = - ç + lnx èx+ ø 4 h'(x) = (x + ) - x ( ) h'x ( x-) ( + ) =- x x h'(x) < 0 So h(x) is decreasing so h(x) < h(). " x > h(x) < 0 " x > So g'(x) = h(x) ƒ(x) g'(x) < 0 " x > g(x) is decreasing in (, ). SECTIN III : Multiple Correct Answer(s) Type This section contains 6 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which NE or MRE are correct. x ƒ(x) e t t dt ò for all x Î(0, ), then - t 55. If = ( - )( - ) 0 (A) ƒ has a local maximum at x = (B) ƒ is decreasing on (,) (C) there exists some c Î (0, ) such that ƒ"(c) = 0 (D) ƒ has a local minimum at x = 6 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
28 Ans. (A,B,C,D) ƒ(x) = x ò 0 t e (t -)(t -)dt IIT-JEE 0 EXAMINATIN (ELD N : ) + + PAPER - x Þ ƒ'(x) = e (x -)(x -) \ ƒ'() = ƒ'() = 0 Þ ƒ''(c) = 0 for same c Î (, ) (by Rolle's theorem) 56. For every integer n, let a n and b n be real numbers. Let function ƒ : IR IR be given by [ ] ( ) ì ïan + sin px, for xî n,n + ƒ(x) = í, for all integers n. ïîb n + cos px, for x Î n -,n If ƒ is continuous, then which of the following holds(s) for all n? (A) a n b n = 0 (B) a n b n = (C) a n b n+ = (D) a n b n = Ans. (B,D) For ƒ to be continuous : ƒ(n ) = ƒ(n + ). Þ Þ b n + cosnp = a n + sinnp b n + = a n Þ a n b n = (\ B is correct) Also ébn + cos px (n -, n) ê an + sin p x [n, n + ] ƒ(x) = ê ê bn+ + cos p x (n +, n + ) ê êëa n+ sin p x [n +, n + ] Again ƒ((n + ) ) = ƒ((n + ) + ) Þ a n = b n+ Þ a n b n+ = Þ a n b n = (\ D is correct) 57. If the straight lines x - y + = = z and x + y + = = z are coplanar, then the plane(s) containing k 5 k these two lines is(are) (A) y + z = (B) y + z = (C) y z = (D) y z = Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 7 / 9
29 Ans. (B,C) (,, 0); (,, 0) For coplanarity of lines IIT-JEE 0 EXAMINATIN (ELD N : ) PAPER k = 0 Þ (k 4) = 0 5 k Þ k = ± for k = r Normal vector n = ˆj-kˆ \ Required plane : y z = l Q Passes through (,, 0) Þ l = \ y z = for k = r n = ˆj+ kˆ \ Required plane : y + z = l Q Passes through (,, 0) Þ l = \ y + z = é 4 4ù ê 7 ú 58. If the adjoint of a matrix P is ê ú, then the possible value(s) of the determinant of P is (are)- êë úû (A) (B) (C) (D) Ans. (A,D) adjp = Þ P = 4 Þ P = ± æ pö æp pö 59. Let ƒ : (,) IR be such that ƒ(cos4 q ) = for qîç 0, Èç,. Then the value(s) of - sec q è 4ø è4 ø æ ö ƒç è ø is (are)- (A) - (B) + (C) - (D) + 8 / 9 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website:
30 Ans. (A,B) Q æ 0, p ö æ p, p ö qîç Èç è 4ø è4 ø æ pö æp ö Þ qîç 0, Èç, p è ø è ø IIT-JEE 0 EXAMINATIN (ELD N : ) + cosq Now ƒ(cos 4 q ) = = = + -sec q cos q cos q Let cos4q= Þ Þ Þ cos q- = cosq=± From (i) æö ƒç = ± èø Þ (A, B) are correct...(i) 60. Let X and Y be two events such that P( X Y ) =,P(Y X) = and P( X Y) following is(are) correct? (A) P( X Y) È = (B) X and Y are independent (C) X and Y are not independent (D) P( X Y) Ans. (A,B) P(X Ç Y) = P(X), P(Y/X) Þ P(X) = Also P(X Ç Y) = P(Y).P(X/Y) Þ P(Y) = Þ P(X Ç Y) = P(X).P(Y) Þ X,Y are independent P(X È Y) = P(X) + P(Y) P(X Ç Y) = + - = 6 P(X C Ç Y) = P(Y) P(X Ç Y) = - = 6 6 Þ (A, B) are correct Ç = C PAPER - Ç =. Which of the 6 Corporate ffice : CAREER INSTITUTE, SANKALP, CP-6, INDRA VIAR, KTA-4005 PNE : , Fax : , info@allen.ac.in Website: 9 / 9
Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) , PART II CHEMISTRY
R Prerna Tower, Road No, Contractors Area, Bistupur, Jamshedpur 831001, Tel (0657)189, www.prernaclasses.com IIT JEE 01 Chemistry Paper II PART II CEMISTRY SECTIN I : Single Correct Answer Type This Section
More informationIIT-JEE 2012 PAPER - 2 PART - II : CHEMISTRY. SECTION - I : Single Correct Answer Type
IIT-JEE 2012 PAPER - 2 PART - II : CHEMISTRY SECTION - I : Single Correct Answer Type This section contains 8 multiple choice questions, Each question has four choices, (A), (B), (C) and (D) out of which
More informationMODEL SOLUTIONS TO IIT JEE 2012
MDEL SLUTINS T IIT JEE Paper II Code PAT I 7 8 B D D A B C A D 9 B C B C D A 7 8 9 D A, C A, C A, B, C B, D A, B. A a a kˆ a kˆ M Ι A a Ιkˆ. ρ cg wρg ρg ρ cg w ρg Section I w ρc w ρ w ρ c If ρ c
More informationMODEL SOLUTIONS TO IIT JEE 2012
MDEL SLUTINS T IIT JEE Paper II Code PAT I 6 7 8 B A D C B C A D 9 C D B C D A 6 7 8 9 D A, C A, C A, B, C B, D A, B π. A a a kˆ a π kˆ π M Ι A a Ιkˆ Section I. Let V m volume of material of shell V w
More informationQ A. A B C A C D A,C,D A,B,C B,C B,C Q A. C C B SECTION-I. , not possible
PAPER CODE SCORE-I LEADER & ENTHUSIAST COURSE TARGET : JEE (Main + Advanced) 04 PART- : MATHEMATICS SECTION-I SECTION-II SECTION-IV. Ans. (A) 0 C T 0 7 SECTION-I For x > & >, [x] - [] - + is not possible
More informationIIT-JEE 2012 PAPER - 1 PART - I : PHYSICS. Section I : Single Correct Answer Type
IIT-JEE PAPER - PART - I : PHYSICS Section I : Single Correct Answer Type This section contains multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is
More informationIIT-JEE 2012 : PAPER-2
IIT-JEE : PAPER- Date : 8-4- Duration : Hours Ma. Marks : 98 Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose. INSTRUCTIONS : A. General. This booklet is
More informationPART - I : PHYSICS. SECTION I : Single Correct Answer Type ALLEN. n=1.5. n=1.2. R=14cm. (A) cm (B) 40.0 cm (C) 21.5 cm (D) 13.
IIT-JEE EXAMINATIN TARGET : IIT-JEE 3 (eld on 8-4-) AER - ( ANSWERS & SLUTINS) IIT-JEE EXAMINATIN (ELD N : 8-4-) ART - I : YSICS SECTIN I : Single Correct Answer Type This section contains multiple choice
More information2013_JEE-ADVANCED_MODEL PAPER PAPER-2. No.of Qs Sec I(Q.N : 1 5) Questions with Single Correct Choice Questions with Multiple Correct Choice
PYSICS: Section 01_JEE-ADVANCED_MODEL PAPER PAPER- Question Type +Ve Marks - Ve Marks Max Marks : 5 No.of Qs Sec I(Q.N : 1 5) Questions with Single Correct Choice -1 5 15 Sec II(Q.N : 6 11) Questions with
More informationCHEMISTRY. SECTION 1 (Maximum Marks : 28) at room temperature changes from gas to solid down the group (B) decrease in HOMO-LUMO gap down the group
JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [ ] This section contains SEVEN questions. CEMISTRY SECTIN (Maximum Marks : 8) Each question has FUR options (A), (B), (C) and (D). NE R MRE TAN NE of these four
More informationJEE(Advanced) 2015 TEST PAPER WITH ANSWER. (HELD ON SUNDAY 24 th MAY, 2015) PART - III : MATHEMATICS
PART - III : JEE(Advanced) 5 Final Eam/Paper-/Code- JEE(Advanced) 5 TEST PAPER WITH ANSWER (HELD ON SUNDAY 4 th MAY, 5) SECTION : (Maimum Marks : ) This section contains EIGHT questions. The answer to
More informationVidyamandir Classes SOLUTIONS JEE Entrance Examination - Advanced/Paper-1 Code -7
SOLUTIONS 7-JEE Entrance Examination - Advanced/Paper- Code -7 PART-I PHYSICS.(AD) Net external force acting on the system along the x-axis is zero. Along the x-axis Momentum is conserved mv MV From conservation
More informationIIT JEE PAPER The question paper consists of 3 parts (Chemistry, Mathematics and Physics). Each part has 4 sections.
IIT JEE - 2009 PAPER 2 A. Question paper format: 1. The question paper consists of 3 parts (Chemistry, Mathematics and Physics). Each part has 4 sections. 2. Section I contains 4 multiple choice questions.
More informationJEE(Advanced) 2017 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 21 st MAY, 2017)
JEE(Advanced) 17/Paper-/Code-9 JEE(Advanced) 17 TEST PAPE WITH SOLUTION (HELD ON SUNDAY 1 st MAY, 17) PAT-I : PHYSICS SECTION I : (Maximum Marks : 1) This section contains SEVEN questions. Each question
More informationPrerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) , PART II Physics
R Prerna Tower, Road No, Contractors rea, istupur, Jamshedpur 8311, Tel (657)189, www.prernaclasses.com IIT JEE 11 Physics Paper I PRT II Physics SECTION I (Total Marks : 1) (Single Correct nswer Type)
More informationPART A. 4cm 1 =1.4 1 =1.5. 5cm
PART A Straight Objective Type This section contains 30 multiple choice questions. Each question has 4 choices (1), (), (3) and (4) for its answer, out of which ONLY ONE is correct. 1. The apparent depth
More informationCHEMISTRY. concentration of salt at equivalence point = C = 0.1 M. K = M b
CHEMISTRY SECTION- I STRAIGHT OBJECTIVE TYPE This section contains 6 multiple choice questions. Each question has 4 choice (A), (B), (C) and (D), out of which ONLY-ONE is correct 47. 2.5 ml of 5 2 M weak
More informationJEE (Main) Chemistry Offline Solved Paper 2017
JEE (Main) Chemistry ffline Solved Paper 07. Which of the following compounds will form significant amount of meta product during mono-nitration reaction? C 3 N NCC 3 (d). DU is equal to isochoric work
More informationKELVIN Entrance Test (KET)
KELVIN Entrance Test (KET) Class : 12 th Passed (Engineering) Code : A Time : 80 minutes MM : 171 Registration Number :... Name of the Candidate :... Test Centre :... Instructions : Caution : Class, Paper,
More informationALL INDIA TEST SERIES
AITS-CRT-I-(Paper-)-PCM (Sol)-JEE(Advanced)/7 In JEE Advanced 06, FIITJEE Students bag 6 in Top 00 AIR, 75 in Top 00 AIR, 8 in Top 500 AIR. 54 Students from Long Term Classroom/ Integrated School Program
More informationTransweb Educational Services Pvt. Ltd Tel:
. The equivalent capacitance between and in the circuit given below is : 6F F 5F 5F 4F ns. () () 3.6F ().4F (3) 4.9F (4) 5.4F 6F 5F Simplified circuit 6F F D D E E D E F 5F E F E E 4F F 4F 5F F eq 5F 5
More informationNarayana IIT Academy INDIA Sec: Sr. IIT_IZ Jee-Advanced Date: Time: 02:00 PM to 05:00 PM 2013_P2 MODEL Max.Marks:180
INDIA Sec: Sr. IIT_IZ Jee-Advanced Date: 9--7 Time: 0:00 PM to 05:00 PM 0_P MODEL Max.Marks:80 KEY SHEET PHYSICS B ABC BCD 4 CD 5 BD D 7 ABD 8 ABC 9 C 0 B C C A 4 B 5 A C 7 A 8 B 9 D 0 B CHEMISTRY ABCD
More informationPhysics 227 Final Exam December 18, 2007 Prof. Coleman and Prof. Rabe. Useful Information. Your name sticker. with exam code
Your name sticker with exam code Physics 227 Final Exam December 18, 2007 Prof. Coleman and Prof. Rabe SIGNATURE: 1. The exam will last from 4:00 p.m. to 7:00 p.m. Use a #2 pencil to make entries on the
More informationEXTENDED_2019 IIT-2015 (P2) DATE: Time: 3 hours Maximum Marks: 240
FIITJEE RET 9 EXTENDED_19 IIT-15 (P) DATE: 8.1.18 Time: 3 hours Maximum Marks: 4 INSTRUCTINS: A. General 1. This booklet is your Question Paper containing 6 questions.. Blank papers, clipboards, log tables,
More informationET-105(A) : PHYSICS. Show that only an infinitesimal rotation can be regarded as a vector.
No. of Printed Pages : 7 ET-105(A) B.Tech. Civil (Construction Management) / B.Tech. Civil (Water Resources Engineering) / BTCLEVI / BTMEVI / BTELVI / BTECVI / BTCSVI Term-End Examination June, 2017 ET-105(A)
More informationJEE-ADVANCED MATHEMATICS. Paper-1. SECTION 1: (One or More Options Correct Type)
JEE-ADVANCED MATHEMATICS Paper- SECTION : (One or More Options Correct Type) This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONE OR
More informationCHEMISTRY PART - II : CHEMISTRY. SECTION 1 : (Only One Option Correct Type) (C) C 2
PART - II : CEMISTRY SECTIN 1 : (nly ne ption Correct Type) CEMISTRY This section contains 10 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which NLY NE option
More informationRao IIT Academy - JEE (ADVANCED) 2018 PAPER 2 PART - I PHYSICS
/ JEE ADVANCED EXAM 2018 / PAPER 2 / QP * This section contains SIX (06) questions. - JEE (ADVANCED) 2018 PAPER 2 PART - I PHYSICS SECTION 1 (Maximum marks: 24) * Each question has FOUR options for correct
More informationPHYSICAL SCIENCES MODEL QUESTION PAPER PART A PART B
PHYSICAL SCIENCES This Test Booklet will contain 65 ( Part `A + Part `B+5 Part C ) Multiple Choice Questions (MCQs). Candidates will be required to answer 5 in part A, in Part B and questions in Part C
More information12th IIT 24th Dec Test Paper-1 Solution
th IIT 4th Dec Test Paper- Solution Subject-PHYSICS Part : SECTIN-A (MULTIPLE CHICE NE R MRE THAN NE CRRECT ANSWER) Q Two capacitors of capacitance C and C are charged to a potential difference of V and
More information(a) zero. B 2 l 2. (c) (b)
1. Two identical co-axial circular loops carry equal currents circulating in the same direction: (a) The current in each coil decrease as the coils approach each other. (b) The current in each coil increase
More informationNarayana IIT Academy
IDIA Sec: Sr. IIT_IZ Jee-Advanced Date: 8-1-18 Time: : PM to 5: PM 11_P Model Max.Marks: 4 KEY SEET CEMISTRY 1 B C B 4 B 5 B 6 B 7 B 8 B 9 ABCD 1 ABCD 11 A 1 ABCD 1 1 14 15 16 4 17 6 18 19 A-PQRS B-PQRST
More informationJEE ADVANCED 2017 (PAPER-1) (QUESTION WITH ANSWER)
1 ( P C M ) JEE ADVANCED 017 (PAPER-1) (QUESTION WITH ANSWER) PART I (PHYSICS) SECTION 1 (MAXIMUM MARKS : 8) This section contains SEVEN questions. Each question has FOUR options (A), (B), (C) and (D).
More informationLimits and Continuity. 2 lim. x x x 3. lim x. lim. sinq. 5. Find the horizontal asymptote (s) of. Summer Packet AP Calculus BC Page 4
Limits and Continuity t+ 1. lim t - t + 4. lim x x x x + - 9-18 x-. lim x 0 4-x- x 4. sinq lim - q q 5. Find the horizontal asymptote (s) of 7x-18 f ( x) = x+ 8 Summer Packet AP Calculus BC Page 4 6. x
More informationQ1. A wave travelling along a string is described by
Coordinator: Saleem Rao Wednesday, May 24, 2017 Page: 1 Q1. A wave travelling along a string is described by y( x, t) = 0.00327 sin(72.1x 2.72t) In which all numerical constants are in SI units. Find the
More informationSOLUTIONS SECTION I: CHEMISTRY
P. CH CH CH CH H CH CH CH CH SLUTINS SECTIN I: CHEMISTRY S N NaH yellow I. CH CH CH CH C CH CH CH C Na CHI H H. H Ea 4..9 = loga.r769 Ea. = loga.r667 Ea = 4.7 4 cal mol - CH CH Cl H C CN H C CH 5. Cl h
More informationJEE MAIN 2018 Sample Question Paper
SET 1 Roll No. JEE MAIN 2018 Sample Question Paper CHEMISTRY (Theory) General Instructions (i) This test consists of 30 question. (ii) Each question is allotted 4 marks for correct response. (iii) Candidates
More informationGraduate Written Examination Spring 2014 Part I Thursday, January 16th, :00am to 1:00pm
Graduate Written Examination Spring 2014 Part I Thursday, January 16th, 2014 9:00am to 1:00pm University of Minnesota School of Physics and Astronomy Examination Instructions Part 1 of this exam consists
More informationKCET PHYSICS 2014 Version Code: C-2
KCET PHYSICS 04 Version Code: C-. A solenoid has length 0.4 cm, radius cm and 400 turns of wire. If a current of 5 A is passed through this solenoid, what is the magnetic field inside the solenoid? ().8
More informationMENTORS EDUSERV SCHOLASTIC APTITUDE TEST (ME-SAT) SAMPLE TEST PAPER
MENTORS EDUSERV SCHOLASTIC APTITUDE TEST (ME-SAT) SAMPLE TEST PAPER [For Students presently in Class 11 going to Class 1 in 019] (Stream: Engineering) Time : hours Maximum Marks: 19 DO NOT BREAK THE SEALS
More information12th IIT 14th May Test Paper-1 Solution
th IIT 4th May Test Paper- Solution Subject-PHYSICS Part : SECTIN-A (MULTIPLE CHICE NE R MRE THAN NE CRRECT ANSWER) Q Two capacitors of capacitance C and C are charged to a potential difference of V and
More informationQ1. Ans: (1.725) =5.0 = Q2.
Coordinator: Dr. A. Naqvi Wednesday, January 11, 2017 Page: 1 Q1. Two strings, string 1 with a linear mass density of 1.75 g/m and string 2 with a linear mass density of 3.34 g/m are tied together, as
More informationJEE(Advanced) 2017 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 21 st MAY, 2017)
JEE(Advanced) 2017 TEST PAPER WITH SLUTIN (HELD N SUNDAY 21 st MAY, 2017) This section contains SEVEN questions. PART-II : CHEMISTRY SECTIN I : (Maximum Marks : 21) Each question has FUR options (A), (B),
More informationNarayana IIT Academy
INDIA Sec: Jr. IIT_N10(CHAINA) JEE-MAIN Date: 7-08-18 Time: 08:00 AM to 11:00 AM CTM- Ma.Marks: 60 KEY SHEET MATHS 1 4 5 6 7 8 9 10 4 4 1 11 1 1 14 15 16 17 18 19 0 4 1 1 4 1 4 5 6 7 8 9 0 4 4 4 1 PHYSICS
More informationPAPER : IIT-JAM 2016 CHEMISTRY-CY
82 CEMISTRY-CY 1. Section-A contains 30 Multiple Choice Questions (MCQ). Each question has 4 choices (a), (b), (c) and (d), for its answer, out of which NLY NE is correct. From Q.1 to Q.10 carries 1 Marks
More informationCHEMISTRY 110 Final EXAM Dec 17, 2012 FORM A
CEMISTRY 110 Final EXAM Dec 17, 2012 FORM A 1. Given the following reaction which of the following statements is true? Fe(s) + CuCl 2 (aq)! Cu(s) + FeCl 2 (aq) A. Iron is oxidized and copper is reduced.
More informationI. Multiple choice: ( ) (2.5 points each, total: 75 points) 1. Which among the following represent a set of isotopes Atomic nuclei containing:
I. Multiple choice: ( ) (2.5 points each, total: 75 points) 1. Which among the following represent a set of isotopes Atomic nuclei containing: I. 20 protons and 20 neutrons. II. 21 protons and 19 neutrons.
More informationFIITJEE Solutions to AIEEE PHYSICS
FTJEE Solutions to AEEE - 7 -PHYSCS Physics Code-O 4. The displacement of an object attached to a spring and executing simple harmonic motion is given by x = cos πt metres. The time at which the maximum
More informationSpring Not-Break Review Assignment
Name AP Physics B Spring Not-Break Review Assignment Date Mrs. Kelly. A kilogram block is released from rest at the top of a curved incline in the shape of a quarter of a circle of radius R. The block
More informationANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VII (Paper - 1) Q. No. PHYSICS CHEMISTRY MATHEMATICS. 1. p); (D q, r) p) (D s) 2.
1 AIITS-HCT-VII (Paper-1)-PCM (Sol)-JEE(Advanced)/16 FIITJEE Students From All Programs have bagged in Top 100, 77 in Top 00 and 05 in Top 500 All India Ranks. FIITJEE Performance in JEE (Advanced), 015:
More information38. The total number of carboxylic acid groups in the product P is 38. [2] O C HO 3 O C C O C O C O. Total no. of carboxylic group = 2
(6) Vidyalankar : IIT JEE 0 Advanced : Question Paper & Solution 8. The total number of carboxylic acid groups in the product P is 8. [] C.... + H Heat C Total no. of carboxylic group = C C H 9. A tetrapeptide
More informationGeneral Physics 1. School of Science, University of Tehran Fall Exercises (set 07)
General Physics 1 School of Science, University of Tehran Fall 1396-97 Exercises (set 07) 1. In Fig., wheel A of radius r A 10cm is coupled by belt B to wheel C of radius r C 25 cm. The angular speed of
More informationPhysics 208, Spring 2016 Exam #3
Physics 208, Spring 206 Exam #3 A Name (Last, First): ID #: Section #: You have 75 minutes to complete the exam. Formulae are provided on an attached sheet. You may NOT use any other formula sheet. You
More informationPaper Reference. Thursday 14 June 2007 Morning Time: 1 hour 20 minutes
Centre No. Candidate No. Paper Reference(s) 6734/01 Edexcel GCE Physics Advanced Level Unit Test PHY 4 Thursday 14 June 007 Morning Time: 1 hour 0 minutes Materials required for examination Nil Paper Reference
More informationRao IIT Academy - JEE (ADVANCED) 2018 PAPER 1 PART - I PHYSICS
/ JEE ADVANCED EXAM 2018 / PAPER 1 / QP * This section contains SIX (06) questions. - JEE (ADVANCED) 2018 PAPER 1 PART - I PHYSICS SECTION 1 (Maximum marks: 24) * Each question has FOUR options for correct
More informationPhys102 Final-163 Zero Version Coordinator: Saleem Rao Tuesday, August 22, 2017 Page: 1. = m/s
Coordinator: Saleem Rao Tuesday, August 22, 2017 Page: 1 Q1. A 125 cm long string has a mass of 2.00 g and a tension of 7.00 N. Find the lowest resonant frequency of the string. A) 2.5 Hz B) 53.0 Hz C)
More informationJEE (ADVANCED) 2018 PAPER 1 PART-I PHYSICS
JEE (ADVANCED) 2018 PAPER 1 PART-I PHYSICS SECTION 1 (Maximum Marks: 24) This section contains SIX (06) questions. Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of these four
More informationFinal Exam: Physics Spring, 2017 May 8, 2017 Version 01
Final Exam: Physics2331 - Spring, 2017 May 8, 2017 Version 01 NAME (Please Print) Your exam should have 11 pages. This exam consists of 18 multiple-choice questions (2 points each, worth 36 points), and
More informationANSWERS, HINTS & SOLUTIONS
AIITS-PT-IV-PCM(SOL)-JEE(Main)/6 FIITJEE Students From All Programs have bagged in Top 00, 77 in Top 00 and 05 in Top 500 All India Ranks. FIITJEE Performance in JEE (Advanced), 05: 455 FIITJEE Students
More information2. A proton is traveling with velocity v, to the right, through a magnetic field pointing into the page as indicated in the figure below.
1. An electron has a mass of 9.11 x 10-31 kg and its charge is -1.6 x 10-19 C. The electron is released from rest in a vacuum between two flat, parallel metal plates that are 10 cm apart. The potential
More informationNARAYANA IIT ACADEMY
CPT-_XI (LJ) 7..7 NARAYANA IIT ACADEMY ANSWER KEY XI STUD (LJ) IITJEE MAINS MODEL Exam Date :7--7 physics Chemistry Mathematics. (C) 3. (B) 6. (C). (C) 3. (D) 6. (A) 3. (B) 33. (A) 63. (B) 4. (D) 34. (A)
More informationExam 3 Review Questions
Exam 3 Review Page 1 of Exam 3 Review Questions 8. Spring 9 Question 1 Which of the following expressions could be a valid representation of the E and B fields in an electromagnetic wave? (Remember that
More information12 th IIT 13 th May Test paper-1 Solution
1 th IIT 13 th May Test paper-1 Solution Subject-PHYSICS Part : 1 SECTION-A (NEXT TEN QUESTIONS: SINGLE CHOICE ONLY ONE CORRECT ANSWER) Q1 In a capillary tube placed inside the liquid of density ( ) in
More informationJee Advance 2014 PART II - CHEMISTRY
R Prerna Tower, Road No - 2, Contractors Area, Bistupur, Jamshedpur - 831001, Tel - (0657)2221892, www.prernaclasses.com Jee Advance 2014 Paper- II PART II - CHEMISTRY 24. For the identification of -napthol
More informationAP Physics C Mechanics Objectives
AP Physics C Mechanics Objectives I. KINEMATICS A. Motion in One Dimension 1. The relationships among position, velocity and acceleration a. Given a graph of position vs. time, identify or sketch a graph
More informationPART I : PHYSICS. SECTION 1 (Maximum Marks: 28)
This section contains SEVEN questions PART I : PHYSICS SECTION 1 (Maximum Marks: 28) Each question has FOUR options [A], [B], [C] and [D]. ONE OR MORE THAN ONE of these four options is(are) correct For
More informationPART - I (CHEMISTRY) ALLEN. oxidation State of Fe = III oxidation State of Fe = II, III OH H OH H OH RCH2OH
IIT-JEE 0 EXAMINATIN (ELD N : 0-04 - 0) PART - I (CEMISTRY) PAPER - SECTIN I : (Total Marks : 4) (Single Correct Answer Type) This section contains 8 multiple choice questions. Each question has four choices
More information( ) PART A CHEMISTRY. Li 6 1s 1s 2s. Li 7 1s 1s 2s 2s 4 3. Li + 2 is more stable than Li 2 because Li 2 has more numbers of antibonding electrons.
JEE (MAIN)-13-CMP - PART A CHEMISTRY 1. An unknown alcohol is treated with the Lucas reagent to determine whether the alcohol is primary, secondary or tertiary. Which alcohol reacts fastest and by what
More information2002 HKAL Physics MC Suggested Solution 1. Before the cord is cut, tension in the cord, T c = 2 mg, tension in the spring, T s = mg
00 HKAL Physics MC Suggested Solution 1. Before the cord is cut, tension in the cord, T c = mg, tension in the spring, T s = mg Just after the cord is cut, Net force acting on X = mg +T s = mg, so the
More informationNARAYANA IIT/PMT ACADEMY
CPT-_XI (LJ) 6.0.08 NARAYANA IIT ACADEMY ANSWER KEY XI STUD (LJ) IITJEE MAINS MODEL Exam Date :6-0-08 physics Chemistry Mathematics. (C). (C) 6. (A). (A). (B) 6. (C). (B). (A) 6. (B) 4. (A) 4. (D) 64.
More informationClass XII Chapter 1 Electric Charges And Fields Physics
Class XII Chapter 1 Electric Charges And Fields Physics Question 1.1: What is the force between two small charged spheres having charges of 2 10 7 C and 3 10 7 C placed 30 cm apart in air? Answer: Repulsive
More informationHomework (lecture 11): 3, 5, 9, 13, 21, 25, 29, 31, 40, 45, 49, 51, 57, 62
Homework (lecture ): 3, 5, 9, 3,, 5, 9, 3, 4, 45, 49, 5, 57, 6 3. An electron that has velocity: moves through the uniform magnetic field (a) Find the force on the electron. (b) Repeat your calculation
More informationJEE M EDICAL-UG BOARDS KVPY NTSE OLYM PIADS JEE - ADVANCED. Rao IIT Academy A Division of Rao Edusolutions Pvt. Ltd. OFFICAL PAPER PAPER - 1(CODE : 1)
JEE M EDICAL-UG BOARDS KVPY NTSE OLYM PIADS JEE - ADVANCED 2017 A Division of Rao Edusolutions Pvt. Ltd. OFFICAL PAPER PAPER - 1(CODE : 1) 1 1 Physics Multiple Correct Questions +4 2 1. A flat plate is
More informationJEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018)
JEE(Advanced 2018 TEST PAPER WITH SLUTIN (HELD N SUNDAY 20 th MAY, 2018 PART-2 : JEE(Advanced 2018/Paper-1 1. The compound(s which generate(s N 2 gas upon thermal decomposition below 300 C is (are (A NH
More informationAP Physics B Summer Assignment
BERGEN COUNTY TECHNICAL SCHOOL AP Physics B Summer Assignment 2011 Solve all problems on separate paper. This will be due the first week of school. If you need any help you can e-mail Mr. Zavorotniy at
More informationPHYSICS. 2. A force of 6 kgf and another force of 8 kg f can be applied to produce the effect of a single force equal to
PHYSICS 1. A body falls from rest, in the last second of its fall, it covers half of the total distance. Then the total time of its fall is (A) 2 + 2 sec (B) 2-2 sec (C) 2 2 (D) 4 sec 2. A force of 6 kgf
More informationA) m B) m C) m D) m E) m. 5. Which one of the following circuits has the largest resistance?
Use the following to answer question 1. Two point charges, A and B, lie along a line separated by a distance L. The point x is the midpoint of their separation. 1. Which combination of charges would yield
More information18 - ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS ( Answers at the end of all questions ) Page 1
( Answers at the end of all questions ) Page ) The self inductance of the motor of an electric fan is 0 H. In order to impart maximum power at 50 Hz, it should be connected to a capacitance of 8 µ F (
More informationPart I : (CHEMISTRY) SECTION I (Total Marks : 24) (Single Correct Answer Type) 10/04/2011
PAPER- IIT-JEE 011 EXAMINATION Part I : (CHEMISTRY) SECTION I (Total Marks : 4) CODE - 9 (Single Correct Answer Type) 10/04/011 This section contains 8 multiple choice questions. Each question has 4 choices
More informationGood Luck! Mlanie LaRoche-Boisvert - Electromagnetism Electromagnetism and Optics - Winter PH. Electromagnetism and Optics - Winter PH
1 Notes: 1. To submit a problem, just click the Submit button under it. The Submit All button is not necessary. 2. A problem accepted as correct by CAPA will be highlighted in green. Once you see this,
More information1 2 U CV. K dq I dt J nqv d J V IR P VI
o 5 o T C T F 3 9 T K T o C 73.5 L L T V VT Q mct nct Q F V ml F V dq A H k TH TC L pv nrt 3 Ktr nrt 3 CV R ideal monatomic gas 5 CV R ideal diatomic gas w/o vibration V W pdv V U Q W W Q e Q Q e Carnot
More information* Terms & Conditions apply. Name of the Student :... Reg. No. :... Duration : 1.30 hour Max. Marks : 114
Vision Infinity Scholarship Award IIT-JEE 0 Students of Vision Infinity who secure All India Rank in IIT JEE within top00,will be Awarded scholarship for four years during B.Tech in IIT Model Test Paper
More informationJEE Main. Sample Paper 4. For more about JEE Main. visit.
JEE Main Sample Paper 4 or more about JEE Main visit http://admission.aglasem.com/jee-main/ PHYSICS. Pick up the correct statements: (A) Area under a-t graph gives velocity (B) Area under a-t graph gives
More informationB r Solved Problems Magnetic Field of a Straight Wire
(4) Equate Iencwith d s to obtain I π r = NI NI = = ni = l π r 9. Solved Problems 9.. Magnetic Field of a Straight Wire Consider a straight wire of length L carrying a current I along the +x-direction,
More informationElectrostatics. 4πε 2) + Q / 2 4) 4 Q
Two spheres A and B of radius a and b respectively are at the same potential The ratio of the surface charge density of A to B is: ) a / b ) b / a a / b b / a Two free protons are separated by a distance
More informationPART B. Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27,
PART B Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27, Si = 28, P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5, Zn =
More information2. Determine the excess charge on the outer surface of the outer sphere (a distance c from the center of the system).
Use the following to answer question 1. Two point charges, A and B, lie along a line separated by a distance L. The point x is the midpoint of their separation. 1. Which combination of charges will yield
More informationNarayana IIT Academy
NDA Sec: Sr. T_Z Jee-Advanced Date: 9-01-18 Time: 0:00 PM to 05:00 PM 011_P Model Max.Marks: 40 KEY SHEET CHEMSTRY 1 C D A 4 B 5 B 6 C 7 A 8 A 9 ABC 10 ABCD 11 ABC 1 ABC 1 8 14 9 15 1 16 7 17 6 18 19 A-PQS,
More informationPhysics Standard level Paper 1
Physics Standard level Paper 1 Tuesday 8 November 2016 (morning) 45 minutes Instructions to candidates Do not open this examination paper until instructed to do so. Answer all the questions. For each question,
More informationDownloaded from
Question 1.1: What is the force between two small charged spheres having charges of 2 10 7 C and 3 10 7 C placed 30 cm apart in air? Repulsive force of magnitude 6 10 3 N Charge on the first sphere, q
More informationJEE (ADVANCED) 2018 PAPER 2 PART I-PHYSICS
JEE (ADVANCED) 2018 PAPER 2 PART I-PHYSICS SECTION 1 (Maximum Marks: 24) This section contains SIX (06) questions. Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of these four
More informationf n+2 f n = 2 = = 40 H z
Coordinator: Dr.I.M.Nasser Monday, May 18, 2015 Page: 1 Q1. Q2. One end of a stretched string vibrates with a period of 1.5 s. This results in a wave propagating at a speed of 8.0 m/s along the string.
More informationPART I : PHYSICS. SECTION 1 (Maximum Marks: 21) Each question has FOUR options [A], [B], [C] and [D]. ONLY ONE of these four options is correct
This section contains SEVEN questions PART I : PHYSICS SECTION 1 (Maximum Marks: 21) Each question has FOUR options [A], [B], [C] and [D]. ONLY ONE of these four options is correct For each question, darken
More informationg E. An object whose weight on 6 Earth is 5.0 N is dropped from rest above the Moon s surface. What is its momentum after falling for 3.0s?
PhysicsndMathsTutor.com 1 1. Take the acceleration due to gravity, g E, as 10 m s on the surface of the Earth. The acceleration due to gravity on the surface of the Moon is g E. n object whose weight on
More informationElectrodynamics Exam 3 and Final Exam Sample Exam Problems Dr. Colton, Fall 2016
Electrodynamics Exam 3 and Final Exam Sample Exam Problems Dr. Colton, Fall 016 Multiple choice conceptual questions 1. An infinitely long, straight wire carrying current passes through the center of a
More informationCHEMISTRY 51. An S N 2 reaction at an asymmetric carbon of a compound always gives
CHEMISTRY 51. An S N reaction at an asymmetric carbon of a compound always gives an enantiomer of the substrate a product with opposite optical rotation a mixture of diastereoisomers (d) a single stereoisomer
More information(D) (A) Q.3 To which of the following circles, the line y x + 3 = 0 is normal at the point ? 2 (A) 2
CIRCLE [STRAIGHT OBJECTIVE TYPE] Q. The line x y + = 0 is tangent to the circle at the point (, 5) and the centre of the circles lies on x y = 4. The radius of the circle is (A) 3 5 (B) 5 3 (C) 5 (D) 5
More informationPHYSICS. [Time 3 hours] [Maximum Marks: 720]
CBSE MAINS-07 PHYSICS [Time 3 hours] [Maximum Marks: 70] General Instructions:. The Answer Sheet is inside this Test Booklet. When you are directed to open the Test Booklet, take out the Answer Sheet and
More informationSome physical constants:
E= mc 2 ρhysics Ωlympiad Symbol No.: College: Grade: Some physical constants: g = 9.8 N/kg G = 6.67 10 11 N m 2 /kg 2 k = 1/4πԑ0 = 8.99 109 N m 2 /C 2 c = 3.00 108 m/s k B = 1.38 10 23 J/K N A = 6.02 1023
More informationExam II. Solutions. Part A. Multiple choice questions. Check the best answer. Each question carries a value of 4 points. The wires repel each other.
Exam II Solutions Part A. Multiple choice questions. Check the best answer. Each question carries a value of 4 points. 1.! Concerning electric and magnetic fields, which of the following is wrong?!! A
More information