AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri. Chapter 4 Stoichiometry and MB with Reactions

Size: px
Start display at page:

Download "AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri. Chapter 4 Stoichiometry and MB with Reactions"

Transcription

1 AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri Chapter 4 Stoichiometry and MB with Reactions

2 Stoichiometry Stoichiometry provides a quantitative means of relating the amount of products produced by chemical reactions to the amount of reactants. The stoichiometric equation of a chemical reaction is a statement of a relative numbers of molecules or moles of reactants and products that participate in the reaction. The stoichiometric coefficients of a balanced equation tell us the mole ratios among substances that reacted and produced by the reaction. The stoichiometric ratio is the ratio of stoichiometric coefficients in the balanced reaction equation.

3 Sulfur Trioxide (SO 3 ) Production During combustion of sulfur bearing fuels, such as coal, sulfur oxides are produced. While most of the sulfur forms sulfur dioxide (SO 2 ), a small amount is further oxidized to sulfur trioxide (SO 3 ) due to the oxidation of SO 2. The stoichiometric equation for this reaction is written as: 2SO 2 + O 2 2SO 3 Let i = stoichiometric coefficient of substance i in the reaction, then SO2 = (-) 2 O2 = (-) 1 SO3 = (+) 2 The stoichiometric ratios from this reaction can be; 2 moles of SO 3 produced 2 mole ofso 2 reacted or 2 moles of SO 3 produced 1 mole ofo 2 reacted or 2 moles of SO 3 reacted 1 mole ofo 2 reacted

4 Example 1: Combustion of heptane (C 7 H 16 ) In the combustion of heptane, carbon dioxide is produced. Assume you want to produce 500 kg of dry ice per hour, and that 50% of the CO 2 can be convert into dry ice. How many kilograms of heptane must be burned per hour? Other gases C 7 H 16 O 2 Combustion Chamber CO 2

5 Example 2: Application of Stoichiometry when more than one reaction occurs By heating limestone we can recover oxides known as Lime. A limestone composition is analyzed as Component % wt CaCO MgCO Inert 1.70 (1) How many pounds of CaO can be made from 1 ton of limestone? (2) How many pounds of CO 2 can be recovered per pound of limestone? (3) How many pounds of limestone are needed to produce 1 ton of lime?

6 Limiting and Excess Reactants In industrial reactors, it is very rare to find exact stoichiometric amounts of materials used. Some reactants are costly that we need to use it up. However, there will always be excess materials come out of the reactor together with the products. The limiting reactant is the specie in a chemical reaction that would theoretically run out first if the reaction proceeds to completion according to the chemical reaction. The reactant is limiting since it presents in less than its stoichiometric proportion relative to every other reactants. The other species of reactants are, then, called excess reactants. % excess reactant = 100[ amount of excess reactant fed stoichiometric amount stoichiometric amount ]

7 Example 3: Hydrogenation of Acetylene The hydrogenation of acetylene will form ethane as shown below: C 2 H 2 + 2H 2 C 2 H 6 Suppose that 20 kmol/h of acetylene and 50kmol/h of hydrogen are fed to a reactor. Therefore, the ratio of H 2 to C 2 H 2 in the reactor is 50:20, or 2.5:1. However, the stoichiometric ratio of H 2 to C 2 H 2 is 2:1. Hydrogen is fed in a greater than stoichiometric proportion to acetylene. Therefore, acetylene is the limiting reactant. With 20 kmol/h of C 2 H 2 fed, we will need 40 kmol/h of H 2 to do the reaction. %excess of H 2 = (50 40) kmol/h 40 kmol/h x 100 = 25%

8 Extent of Reaction ( ) Extent of reaction denotes how much reaction occurs, mostly reflecting by the consumption of limiting reactants. The unit of extent of reaction is presented as mole reacting. When, Or, = n i n io i n i and n io are moles of specie i present in the system after reaction and when reaction starts, respectively. i = stoichiometric coefficient of specie I n i = n io + i

9 Example 4: Calculation of the Extent of Reaction Determine the extent of reaction for the following chemical reaction N 2 + 3H 2 2NH 3 Given the following analysis of feed and product: Specie Amount in Feed (g) Amount in Product (g) N na. H 2 50 na. NH

10 Maximum Extent of Reaction ( Max ) The maximum extent of reaction is the of each reactant, based on the complete reaction. The amount of products produced would be controlled by the amount of limiting reactant. Max = 0 n io i The amount of n i will always be zero for the complete reaction. The reactant with the smallest Max is the limiting reactant.

11 Example 5: Determination of limiting reactant using Max Consider the combustion of heptane; C 7 H O 2 7CO 2 + 8H 2 O If 1 gmol of heptane and 12 gmol of oxygen are mixed, which specie will be considered a limiting reactant? Using maximum extent of reaction to answer this problem.

12 Example 6: Calculation of the Ammonia Production If we feed 10 g of N 2 and 10 g of H 2 into a reactor; (A) What is the maximum amount of NH3 that can be produced? (B) Which specie is a limiting reactant? (C) What is the %excess of an excess reactant? Knowing that MW. of N 2 =28 MW. of H 2 = 2 MW. of NH 3 = 17 N 2 + 3H 2 2NH 3

13 Conversion Conversion is the fraction of the feed that is converted into products; amount of feed that reacted %conversion = 100 x [ amount of feed introduced ] Or, Conversion = extent of reaction that occurs extent of reaction for complete reaction = Max = n i n io 0 n io

14 Yield 1. Yield based on feed: Yield 1 = amount of desired product obtained amount of the limiting reactant fed 2. Yield based on reactant consumed: Yield 2 = amount of desired product obtained amount of the limiting reactant consumed 1. Yield based on theoretical consumption of the limiting reactant: Yield 3 = amount of desired product obtained amount of that product that would be obtained theoretically

15 Selectivity Selectivity is the ratio of desired product produced to the amount of other products co-produced. In most chemical processes, reactants are bought together with the object of producing a desired production, Unfortunately, reactants can usually combine in more than one way, and the product once formed may react to yield something less desirable. The result of these side reactions is an economic loss. Take an example on ethylene production by dehydrogenation of ethane; C 2 H 6 H 2 + C 2 H 4 Once hydrogen is produced, it can react with ethane and form methane; C 2 H 6 + H 2 2CH 4 Ethylene can also react with ethane to form propylene and methane; C 2 H 6 + C 2 H 4 C 3 H 6 + CH 4

16 Example 7: Production of Ethanol from Sugar Yeasts are living organisms that consume sugars and produce a variety of products. For example, yeasts are used to convert malt to beer, and convert corn to ethanol. The growth of S. cerevisiae on glucose under anaerobic conditions proceeds by the following reaction to produce biomass, glycerol, and ethanol. C 6 H 12 O NH CH 1.74 N 0.2 O C 3 H 8 O CO C 2 H 5 OH H 2 O Calculate the theoretical yield of biomass (in g. biomass per g. glucose) and yield of ethanol (in g. ethanol per g. glucose).

17 Example 8: Selectivity in the Production of Nanotubes A carbon nanotube may consist of a single wall tube or a number of concentric tubes. A single wall tube may be produced as unaligned structures or bundles of ropes packed together in an orderly manner. The structure of the carbon nanotubes influences its properties, such as conductance. In nanotechnology, numerous methods exist to produce nanotubes. For example, large amount of single wall carbon nanotubes can be produced by the catalytic decomposition of ethane over Co and Fe catalysts supported on silica. C 2 H 6 2C + 3H 2 C 2 H 6 C 2 H 4 + H 2 (a) (b) If you collect 3 gmol of H 2 and 0.5 gmol of C 2 H 4 in the products, what is the selectivity of C relative to C 2 H 4?

18 Carbon Nanotubes Structures Conceptual diagram of single-walled carbon nanotube (SWCNT) (A) and multi-walled carbon nanotube (MWCNT) (B) delivery systems showing typical dimensions of length, width, and separation distance between graphene layers in MWCNTs. THE JOURNAL OF NUCLEAR MEDICINE Vol. 48 No. 7 July 2007

19 Example 9: Determination of limiting reactant when there are more than two reactants involved Acrylonitrile (C 3 H 3 N) is produced in the reaction of propylene (C 3 H 6 ), ammonia (NH 3 ), and oxygen (O 2 ): C 3 H 6 + NH O 2 C 3 H 3 N + 3H 2 O The feed contains 10%mol propylene, 12%mol ammonia and 78%mol air. A fractional conversion of 30% of the limiting reactant is achieved. Taking 100 gmol of feed as a basis, determine (A) Which reactant is limiting? (B) %excess of the excess reactants (C) Molar amount of all products

20 Review of Mass Balance Equation Let m 0 = initial mass of the system m t = mass of the system at time t m i = mass of inlet stream(s) m e = mass of exit stream(s) m gen = mass of generated material(s) m con = mass of consumed material(s) m t m 0 = m i m e + m gen m con

21 Species Mole Balance When reaction occurs, equation of mass balance can be modified for each specie, replacing mass by mole. Let n A,0 = initial mass of specie A in the system n A,t = mass of specie A in the system at time t n A,i = mass of specie A in inlet stream(s) n e = mass of specie A in exit stream(s) n gen = mass of specie A generated n con = mass of specie A consumed n A,t n A, 0 = n A, i n A,e + n A,gen n A,con

22 The use of For an open and steady-state process n A,t na, 0 = 0 From the definition of extent of the reaction ( ), = n A,out n A,in A For reacting species (reactants); n A,con = n A,out n A,in = A For producing species (products); n A,gen = n A,out n A,in = A

23 Example of ammonia production (open, steady state process): N 2 + 3H 2 2NH 3 6 gmol NH 3 18 gmol H 2 15 gmol N 2 Reactor 9 gmol H 2 12 gmol N 2 Species mole balance can be written as follow; For H 2 ; n H2,con = n H2,out n H2,in = 9 18 = 9 gmol reacted For N 2 ; n N2,con = n N2,out n N2,in = = 3 gmol reacted For NH 3 ; n NH3,gen = n NH3,out n NH3,in = 6 0 = 6 gmol produced

24 Example 10: Reaction in which the fraction conversion is specified The chlorination of methane occurs by the following reaction: CH 4 + Cl 2 CH 3 Cl + HCl Determine the product composition if the conversion of the limiting reactant is 67%, and the feed composition in mole percent is 40% methane, 50% chlorine gas, and 10% nitrogen gas.

25 Processes involving multiple reactions For open, steady-state processes with multiple reactions, R n A,e n A,i = ij j Where ij = j = R = j=1 Stoichiometric coefficient of specie i in the reaction j in the minimal reaction set extent of reaction for the j th reaction, in which component i is present in the minimal set number of independent chemical reactions

26 The Minimal Set The minimal set is the set of independent chemical reactions among all the multiple chemical reactions occur in the process of interest. Consider the carbon dioxide (CO 2 ) generation; C + O 2 CO 2 (1) C + ½ O 2 CO (2) CO + ½ O 2 CO 2 (3) The independent reactions are (1) and (2), since reaction (3) is the operation of (1) and (2).

27 Example 11: Material balances involving two ongoing reactions Formaldehyde is produced by catalytic oxidation of methanol by the following reaction, CH 3 OH + ½ O 2 CH 2 O + H 2 O (A) Unfortunately, under the conditions used, a significant portion of formaldehyde can react with oxygen to produce carbon monoxide. CH 2 O + ½ O 2 CO + H 2 O (B) Methanol and twice the stoichiometric amount of air needed for complete oxidation of methanol are fed to the reactor. This results 90% conversion of methanol, and 75% yield of formaldehyde (based on reaction A). Determine the composition of product leaving the reactor.

28 Analysis of Bioreactor (unsteady-state process) In the anaerobic fermentation of grain, the yeast Saccharomyces cerevisiae digests glucose from plants to form ethanol (C 2 H 5 OH) and propenoic acid (C 2 H 3 CO 2 H) by the following reactions: Reaction 1: C 6 H 12 O 6 C 2 H 5 OH + 2CO 2 Reaction 2: C 6 H 12 O 6 C 2 H 3 CO 2 H + 2H 2 O In a process, a tank is initially charged with 4,000 kg of a 12% glucose solution (in water). After fermentation, 120 kg of CO 2 have been produced and 90 kg of unreacted glucose remain the the broth. What are the weight percent of ethanol and propenoic acic in the broth at the end of the process?

29 Combustion Process Combustion is a reaction of substance with oxygen, with the association of energy released and generation of product gases such as H 2 O, CO 2, CO and SO 2. Most combustion uses air as a source of oxygen. We usually approximate the composition of air as it contains 79%mol N 2 and 21%mol O 2, with MW =29 O entering - O required O required 2 2 %Excess Air = x 100 2

30 Example 12: Excess Air Calculation Fuels other than gasoline are being used for motor vehicles because the create lower levels of pollutants than gasoline does. Compressed propane (C 3 H 8 ) is one such proposed fuel. Suppose that 20 kg of C 3 H 8 is burned with 400 kg of air to produce 44 kg of CO 2 and 12 kg of CO. What is the percent excess air? C 3 H 8 + 5O 2 3 CO 2 + 4H 2 O

31 Element Balance Element balance is useful when the exact stoichiometric equations are not known. For element balance, there will be no generation nor consumption terms in the material balance equations. All elements are conserved through out the reactions. Example 13: Octane cracking process produces the cracked products with the following composition. C 3 H %mol C 4 H %mol C 5 H %mol Determine the molar ratio of hydrogen to octane reacted for this process.

32 Example 14: Combustion of Fuel Component of coal (Fuel) %wt C H 4.45 O 3.36 N 1.08 S 0.70 Ash 7.36 Total Component of Stack gas (Product) %mol CO2 + SO O2 4.0 N Total A local utility burns coal and report the gas product as tabulated. Moisture in the fuel was 3.9%wt and the air contains lb water/lb dry air. The refuse showed 14% unburned coal, with remainder being ash. You are asked to check the consistency of the report, and find the percent excess of air used.

Chapter 9 The Chemical Reaction Equation and Stoichiometry 9.1 Stoichiometry

Chapter 9 The Chemical Reaction Equation and Stoichiometry 9.1 Stoichiometry Chapter 9 The Chemical Reaction Equation and Stoichiometry 9.1 Stoichiometry The stoichiometric coefficients in the chemical reaction equation Is (1 for C 7 H 16, 11 for O 2 and so on). Another way to

More information

THE CHEMICAL REACTION EQUATION AND STOICHIOMETRY

THE CHEMICAL REACTION EQUATION AND STOICHIOMETRY 9.1 Stoichiometry Stoichiometry provides a quantitative means of relating the amount of products produced by chemical reaction(s) to the amount of reactants. You should take the following steps in solving

More information

FDE 211-MATERIAL AND ENERGY BALANCES: MATERIAL BALANCES ON REACTIVE SYSTEMS. Dr. Ilgın PakerYıkıcı Fall 2015

FDE 211-MATERIAL AND ENERGY BALANCES: MATERIAL BALANCES ON REACTIVE SYSTEMS. Dr. Ilgın PakerYıkıcı Fall 2015 FDE 211-MATERIAL AND ENERGY BALANCES: MATERIAL BALANCES ON REACTIVE SYSTEMS 1 Dr. Ilgın PakerYıkıcı Fall 2015 Learning Objectives Write a balanced chemical reaction and use stoichiometry to determine the

More information

Chapter 4. Fundamentals of Material Balance

Chapter 4. Fundamentals of Material Balance Chapter 4 Fundamentals of Material Balance Introduction to Chapter 4 1) In chapter 4 we will present methods for organizing known information about process variables, setting up martial balance equations,

More information

AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri. Fundamentals for Chemical Engineering Calculations

AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri. Fundamentals for Chemical Engineering Calculations AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri Fundamentals for Chemical Engineering Calculations AE 205 Materials and Energy Balances Asst. Prof. Dr. Tippabust Eksangsri Dimensions,

More information

Usual Atomic Charges of Main Group Elements

Usual Atomic Charges of Main Group Elements Usual Atomic Charges of Main Group Elements +1 +2 +3 +4 +5 +6 +7-5 -4-3 -2-1 Examples SO 3 sulfur trioxide CO 2 carbon dioxide Al 2 O 3 aluminum trioxide IF 7 iodine heptafluoride Fig. 2-6, p.63 Chemical

More information

Chemical Equation and Stoichiometry

Chemical Equation and Stoichiometry 31 Introduction to Chemical Engineering Calculations Lecture 4. 4 What can we learn from a chemical equation? C7H16 + 11 O2 7 CO2 + 8 H2O 1. What information can we get from this equation? 2.

More information

Chemical Equations 10/30/13. Types of Chemical Reactions. Types of Chemical Reactions. Types of Chemical Reactions. Types of Chemical Reactions

Chemical Equations 10/30/13. Types of Chemical Reactions. Types of Chemical Reactions. Types of Chemical Reactions. Types of Chemical Reactions Chemical Equations A chemical equation just like a mathematical equation is a way to express, in symbolic form, the reactions occurring in a chemical system. n Balancing chemical equations n Reaction stoichiometry

More information

Balancing chemical reaction equations (stoichiometry)

Balancing chemical reaction equations (stoichiometry) Balancing chemical reaction equations (stoichiometry) This worksheet and all related files are licensed under the Creative Commons Attribution License, version 1.0. To view a copy of this license, visit

More information

Quantity Relationships in Chemical Reactions

Quantity Relationships in Chemical Reactions Chapter 10 Relationships in Chemical Reactions Section 10.1 Conversion Factors from a Chemical Equation Goal 1 The coefficients in a chemical equation give us the conversion factors to get from the number

More information

2. Review on Material Balances

2. Review on Material Balances 2. Review on Material Balances Objectives After completing this chapter, students should be able to recall the principle of the conservation of mass recall the principle of the stoichiometry of chemical

More information

Chapter 3: Chemical Reactions and the Earth s Composition

Chapter 3: Chemical Reactions and the Earth s Composition Chapter 3: Chemical Reactions and the Earth s Composition Problems: 3.1-3.3, 3.5, 3.11-3.86, 3.95-3.115, 3.119-3.120, 3.122, 3.125-3.128, 3.132, 3.134, 3.136-3.138-3.141 3.2 The Mole Stoichiometry (STOY-key-OM-e-tree):

More information

Slide 1 / 90. Stoichiometry HW. Grade:«grade» Subject: Date:«date»

Slide 1 / 90. Stoichiometry HW. Grade:«grade» Subject: Date:«date» Slide 1 / 90 Stoichiometry HW Grade:«grade» Subject: Date:«date» Slide 2 / 90 1 The calculation of quantities in chemical equations is called. A B C D E accuracy and precision dimensional analysis percent

More information

Name: Class: Date: ID: A. (g), what is the ratio of moles of oxygen used to moles of CO 2 produced? a. 1:1 b. 2:1 c. 1:2 d. 2:2

Name: Class: Date: ID: A. (g), what is the ratio of moles of oxygen used to moles of CO 2 produced? a. 1:1 b. 2:1 c. 1:2 d. 2:2 Name: Class: _ Date: _ Chpt 12 review Multiple Choice Identify the choice that best completes the statement or answers the question. 1. What is conserved in the reaction shown below? H 2 + Cl 2 2HCl a.

More information

The Mole. Relative Atomic Mass Ar

The Mole. Relative Atomic Mass Ar STOICHIOMETRY The Mole Relative Atomic Mass Ar Relative Molecular Mass Mr Defined as mass of one atom of the element when compared with 1/12 of an atom of carbon-12 Some Ar values are not whole numbers

More information

Stoichiometry of Gases

Stoichiometry of Gases CHAPTER 13 Stoichiometry of Gases Now that you have worked with relationships among moles, mass, and volumes of gases, you can easily put these to work in stoichiometry calculations. Many reactions have

More information

Name Date Class. Match each term in Column B with the correct description in Column A. Write the letter of the correct term on the line.

Name Date Class. Match each term in Column B with the correct description in Column A. Write the letter of the correct term on the line. 12 STOICHIOMETRY Chapter Test B A. Matching Match each term in Column B with the correct description in Column A. Write the letter of the correct term on the line. 1. 2. 3. 4. 5. Column A the substance

More information

Chapter 4: Chemical and Solution Stoichiometry

Chapter 4: Chemical and Solution Stoichiometry Chapter 4: Chemical and Solution Stoichiometry (Sections 4.1-4.4) 1 Reaction Stoichiometry The coefficients in a balanced chemical equation specify the relative amounts in moles of each of the substances

More information

Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University

Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University Chapter 15 CHEMICAL REACTIONS Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University 2 Objectives Give an overview of fuels and combustion. Apply the conservation of mass to reacting

More information

Name Date Class STUDY GUIDE FOR CONTENT MASTERY

Name Date Class STUDY GUIDE FOR CONTENT MASTERY Stoichiometry Section 12.1 What is stoichiometry? In your textbook, read about stoichiometry and the balanced equation. For each statement below, write true or false. 1. The study of the quantitative relationships

More information

Question 1.1: Calculate the molecular mass of the following: (i) H 2 O (ii) CO 2 (iii) CH 4 (i) H 2 O: The molecular mass of water, H 2 O = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen) = [2(1.0084)

More information

AP Chemistry: Chapter 3 Notes Outline

AP Chemistry: Chapter 3 Notes Outline AP Chemistry: Chapter 3 Notes Outline Objectives: Balance chemical equations Use dimensional analysis to solve stoichiometric problems Use dimensional analysis to do limiting reactant problems Use dimensional

More information

Chapter 9. Chemical Quantities

Chapter 9. Chemical Quantities Chapter 9 Chemical Quantities Section 9.1 Information Given by Chemical Equations A balanced chemical equation gives relative numbers (or moles) of reactant and product molecules that participate in a

More information

Chapter 5. Stoichiometry

Chapter 5. Stoichiometry Chapter 5 Stoichiometry Chapter 5 Table of Contents (5-1) Counting by weighing (5-2) Atomic masses (5-3) Learning to solve problems (5-4) The mole (5-5) Molar mass (5-6) Percent composition of compounds

More information

Example Exercise 10.1 Interpreting Chemical Equation Calculations

Example Exercise 10.1 Interpreting Chemical Equation Calculations Example Exercise 10.1 Interpreting Chemical Equation Calculations Given the chemical equation for the combustion of methane, CH 4, balance the equation and interpret the coefficients in terms of (a) moles

More information

Chapter 3. Mass Relationships in Chemical Reactions

Chapter 3. Mass Relationships in Chemical Reactions Chapter 3 Mass Relationships in Chemical Reactions In this chapter, Chemical structure and formulas in studying the mass relationships of atoms and molecules. To explain the composition of compounds and

More information

Chapter 3: Stoichiometry

Chapter 3: Stoichiometry Chapter 3: Stoichiometry Key Skills: Balance chemical equations Predict the products of simple combination, decomposition, and combustion reactions. Calculate formula weights Convert grams to moles and

More information

Outcomes: Interpret a balanced chemical equation in terms of moles, mass and volume of gases. Solve stoichiometric problems involving: moles, mass,

Outcomes: Interpret a balanced chemical equation in terms of moles, mass and volume of gases. Solve stoichiometric problems involving: moles, mass, Stoichiometry Outcomes: Interpret a balanced chemical equation in terms of moles, mass and volume of gases. Solve stoichiometric problems involving: moles, mass, volume, and heat of reaction. Stoichiometry

More information

UNIT 1 Chemical Reactions Part II Workbook. Name:

UNIT 1 Chemical Reactions Part II Workbook. Name: UNIT 1 Chemical Reactions Part II Workbook Name: 1 Molar Volume 1. How many moles of a gas will occupy 2.50 L at STP? 2. Calculate the volume that 0.881 mol of gas at STP will occupy. 3. Determine the

More information

Class XI Chapter 1 Some Basic Concepts of Chemistry Chemistry

Class XI Chapter 1 Some Basic Concepts of Chemistry Chemistry Question 1.1: Calculate the molecular mass of the following: (i) H 2 O (ii) CO 2 (iii) CH 4 (i) H 2 O: The molecular mass of water, H 2 O = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen) = [2(1.0084)

More information

Problem Solving. Percentage Yield

Problem Solving. Percentage Yield Skills Worksheet Problem Solving Percentage Yield Although we can write perfectly balanced equations to represent perfect reactions, the reactions themselves are often not perfect. A reaction does not

More information

Stoichiometry Dr. M. E. Bridge

Stoichiometry Dr. M. E. Bridge Preliminary Chemistry Course Stoichiometry Dr. M. E. Bridge What is stoichiometry? The meaning of the word: The word stoichiometry comes from two Greek words: stoichon(meaning element ) and metron(meaning

More information

2.9 The Mole and Chemical Equations:

2.9 The Mole and Chemical Equations: 2.9 The Mole and Chemical Equations: Stoichiometry Whether you are making omelettes in a kitchen or soap in a factory, you need to know the quantities of ingredients required to produce a certain quantity

More information

CHEM Chapter3. Mass Relations in Chemical Reactions (Homework)

CHEM Chapter3. Mass Relations in Chemical Reactions (Homework) Multiple Choice Identify the choice that best completes the statement or answers the question. 1. There are two different common crystalline forms of carbon diamond and graphite. A less common form called

More information

Fundamentals of Combustion

Fundamentals of Combustion Fundamentals of Combustion Lec 3: Chemical Thermodynamics Dr. Zayed Al-Hamamre Content Process Heat Transfer 1-3 Process Heat Transfer 1-4 Process Heat Transfer 1-5 Theoretical and Excess Air Combustion

More information

Sample Problem Set. Teacher Notes and Answers. Skills Worksheet PERCENTAGE YIELD. Name: Class: Date:

Sample Problem Set. Teacher Notes and Answers. Skills Worksheet PERCENTAGE YIELD. Name: Class: Date: Skills Worksheet Sample Problem Set Teacher Notes and Answers PERCENTAGE YIELD 1. a. 64.3% yield b. 58.0% yield c. 69.5% yield d. CH 3 CH OH is limiting; 79% yield. a. 69.5% yield b. 79.0% yield c. 48%

More information

Stoichiometry. Introduction. Rx between Hydrogen and Oxygen can be described as: Balanced equation: Or Avogadros Number: (number of Molecules)

Stoichiometry. Introduction. Rx between Hydrogen and Oxygen can be described as: Balanced equation: Or Avogadros Number: (number of Molecules) Stoichiometry Introduction Rx between Hydrogen and Oxygen can be described as: Balanced equation: Or Or Avogadros Number: (number of Molecules) Or Moles (amount of a substance containing avogadros number

More information

Chapter 8: Quantities in Chemical Reactions

Chapter 8: Quantities in Chemical Reactions C h e m i s t r y 1 2 C h 8 : Q u a n t i t i e s i n C h e m i c a l R e a c t i o n s P a g e 1 Chapter 8: Quantities in Chemical Reactions Read Chapter 8 and Check MasteringChemistry due dates. Stoichiometry:

More information

Chapter 1 IB Chemistry Warm Ups Stoichiometry. Mrs. Hilliard

Chapter 1 IB Chemistry Warm Ups Stoichiometry. Mrs. Hilliard Chapter 1 IB Chemistry Warm Ups Stoichiometry Mrs. Hilliard Vocabulary 1. Atomic theory 2. Kelvin 3. Mole 4. Relative abundance 5. Molar Mass 6. Empirical formula 7. Molecular formula 8. Stoichiometry

More information

CHEMICAL ARITHMATICS MODULE - 1. Objectives. Chemical Arithmatics. Atoms, Molecules and Chemical Arithmatics. Notes

CHEMICAL ARITHMATICS MODULE - 1. Objectives. Chemical Arithmatics. Atoms, Molecules and Chemical Arithmatics. Notes 2 MODULE - 1 CHEMICAL ARITHMATICS W e know that atoms of different elements combine in simple whole-number ratios to form molecules. For example, hydrogen and oxygen atoms combine in the mass ratio of

More information

Slide 1 / 90. Slide 2 / 90. Slide 3 / 90 A B. percent yield stoichiometry A B. atoms and mass

Slide 1 / 90. Slide 2 / 90. Slide 3 / 90 A B. percent yield stoichiometry A B. atoms and mass Stoichiometry HW Slide 1 / 90 Grade:«grade» Subject: ate:«date» 1 The calculation of quantities in chemical equations is called. Slide 2 / 90 accuracy and precision dimensional analysis percent composition

More information

Chemistry (www.tiwariacademy.com)

Chemistry (www.tiwariacademy.com) () Question 1.1: Calculate the molecular mass of the following: (i) H2O (ii) CO2 (iii) CH4 Answer 1.1: (i) H2O: The molecular mass of water, H2O = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen)

More information

Name Date Class THE ARITHMETIC OF EQUATIONS

Name Date Class THE ARITHMETIC OF EQUATIONS 12.1 THE ARITHMETIC OF EQUATIONS Section Review Objectives Calculate the amount of reactants required or product formed in a nonchemical process Interpret balanced chemical equations in terms of interacting

More information

11 Stoichiometry. Section 11.1 What is stoichiometry?

11 Stoichiometry. Section 11.1 What is stoichiometry? 11 Stoichiometry Section 11.1 What is stoichiometry? In your textbook, read about stoichiometry and the balanced equation. For each statement below, write true or false. 1.. 3. 4. 5. The study of the quantitative

More information

Chapter 3 Chemical Reactions and Reaction Stoichiometry

Chapter 3 Chemical Reactions and Reaction Stoichiometry Chapter 3 Chemical Reactions and Reaction Stoichiometry 2015 Pearson Education, Inc. Chemical Reactions and Reaction Stoichiometry 3.1 Chemical Equations 3.2 Simple Patterns of Chemical Reactivity 3.3

More information

Chemical Equations. Law of Conservation of Mass. Anatomy of a Chemical Equation CH4(g) + 2O2(g) Chapter 3

Chemical Equations. Law of Conservation of Mass. Anatomy of a Chemical Equation CH4(g) + 2O2(g) Chapter 3 Chemical Equations Chemical equations are concise representations of chemical reactions. Chapter 3 : Calculations with Chemical Formulas and Equations Law of Conservation of Mass Anatomy of a Chemical

More information

Chemistry. Chapter 17

Chemistry. Chapter 17 Chemistry Chapter 17 Chemical Equations C+O 2 CO 2 C (s) +O 2 (g) CO 2 (g) Reactants on left, products on right Each are balanced because same number of atoms of reactants as products Balancing Chemical

More information

I hope you aren't going to tear open the package and count the nails. We agree that. mass of nails = 1340 g g = g

I hope you aren't going to tear open the package and count the nails. We agree that. mass of nails = 1340 g g = g The Mole Concept Counting by weighing The size of molecule is so small that it is physically difficult if not impossible to directly count out molecules. this problem is solved using a common trick. Atoms

More information

Chapter 3. Stoichiometry

Chapter 3. Stoichiometry Chapter 3 Stoichiometry Chapter 3 Chemical Stoichiometry Stoichiometry The study of quantities of materials consumed and produced in chemical reactions. Since atoms are so small, we must use the average

More information

Chem. I Notes Ch. 11 STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics.

Chem. I Notes Ch. 11 STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. Chem. I Notes Ch. 11 STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. 11.1 notes 1 MOLE = 6.02 x 10 23 representative particles representative particles

More information

Ch 9 Stoichiometry Practice Test

Ch 9 Stoichiometry Practice Test Ch 9 Stoichiometry Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A balanced chemical equation allows one to determine the a. mole ratio

More information

Stoichiometry. The quantitative study of reactants and products in a chemical reaction. Burlingame High School Chemistry

Stoichiometry. The quantitative study of reactants and products in a chemical reaction. Burlingame High School Chemistry Stoichiometry The quantitative study of reactants and products in a chemical reaction 1 Stoichiometry Whether the units given for reactants or products are moles, grams, liters (for gases), or some other

More information

Gestão de Sistemas Energéticos 2017/2018

Gestão de Sistemas Energéticos 2017/2018 Gestão de Sistemas Energéticos 2017/2018 Exergy Analysis Prof. Tânia Sousa taniasousa@tecnico.ulisboa.pt Conceptualizing Chemical Exergy C a H b O c enters the control volume at T 0, p 0. O 2 and CO 2,

More information

Basic Concepts of Chemistry and Chemical Calculations. The ratio of the average mass factor to one twelfth of the mass of an atom of carbon-12

Basic Concepts of Chemistry and Chemical Calculations. The ratio of the average mass factor to one twelfth of the mass of an atom of carbon-12 Basic Concepts of Chemistry and Chemical Calculations Relative Atomic mass: The relative atomic mass is defined as the ratio of the average atomic mass factor to the unified atomic mass unit. (Or) The

More information

General Chemistry. Chapter 3. Mass Relationships in Chemical Reactions CHEM 101 (3+1+0) Dr. Mohamed El-Newehy 10/12/2017

General Chemistry. Chapter 3. Mass Relationships in Chemical Reactions CHEM 101 (3+1+0) Dr. Mohamed El-Newehy 10/12/2017 General Chemistry CHEM 101 (3+1+0) Dr. Mohamed El-Newehy http://fac.ksu.edu.sa/melnewehy Chapter 3 Mass Relationships in Chemical Reactions 1 In this chapter, Chemical structure and formulas in studying

More information

Ch. 10 Notes STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics.

Ch. 10 Notes STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. Ch. 10 Notes STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. 1 MOLE = 6.02 x 10 23 representative particles representative particles = ATOMS, IONS,

More information

Chapter 9. Table of Contents. Stoichiometry. Section 1 Introduction to Stoichiometry. Section 2 Ideal Stoichiometric Calculations

Chapter 9. Table of Contents. Stoichiometry. Section 1 Introduction to Stoichiometry. Section 2 Ideal Stoichiometric Calculations Stoichiometry Table of Contents Section 1 Introduction to Stoichiometry Section 2 Ideal Stoichiometric Calculations Section 3 Limiting Reactants and Percentage Yield Section 1 Introduction to Stoichiometry

More information

Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations. Lecture Presentation

Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations. Lecture Presentation Lecture Presentation Chapter 3 : Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community College Cottleville, MO Law of Conservation of Mass We may lay it down as an

More information

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Chapter 3 : Calculations with Chemical Formulas and Equations AP Chemistry 2014-15 North Nova Education Centre Mr. Gauthier Law of Conservation of Mass We may lay it down as an incontestable axiom that,

More information

Stoichiometric Calculations

Stoichiometric Calculations Slide 1 / 109 Slide 2 / 109 Stoichiometric Calculations Slide 3 / 109 Table of Contents Click on the topic to go to that section Stoichiometry Calculations with Moles Stoichiometry Calculations with Particles

More information

Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations

Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations Lecture Outline 3.1 Chemical Equations The quantitative nature of chemical formulas and reactions is called stoichiometry. Lavoisier

More information

Fundamentals of Material Balances

Fundamentals of Material Balances Chapter 4 Fundamentals of Material Balances Material Balance-Part 1 Process Classifications 3 type of chemical processes: - Concept of boundary of the process 1. Batch process Feed is charge to the process

More information

Name Date Class STOICHIOMETRY. SECTION 12.1 THE ARITHMETIC OF EQUATIONS (pages )

Name Date Class STOICHIOMETRY. SECTION 12.1 THE ARITHMETIC OF EQUATIONS (pages ) Name Date Class 1 STOICHIOMETRY SECTION 1.1 THE ARITHMETIC OF EQUATIONS (pages 353 358) This section explains how to calculate the amount of reactants required or product formed in a nonchemical process.

More information

C 6 H H 2 C 6 H 12. n C6H12 n hydrogen n benzene. n C6H6 n H2 100 C 6 H 6 n 2 n C6H H 2. n 1

C 6 H H 2 C 6 H 12. n C6H12 n hydrogen n benzene. n C6H6 n H2 100 C 6 H 6 n 2 n C6H H 2. n 1 1. Cyclohexane (C 6 H 12 ) can be made by the reaction of benzene (C 6 H 6 ) and hydrogen gas. The products from the reactor are sent to a separator where the cyclohexane and some of the unreacted hydrogen

More information

Mole: base unit for an amount of substance A mole contains Avogadro s number (N A ) of particles (atoms, molecules, ions, formula units )

Mole: base unit for an amount of substance A mole contains Avogadro s number (N A ) of particles (atoms, molecules, ions, formula units ) Mole: base unit for an amount of substance A mole contains Avogadro s number (N A ) of particles (atoms, molecules, ions, formula units ) N A 6.0 10 mol -1 1 mol substance contains N A Molar mass (g/mol)

More information

STOICHIOMETRY & LIMITING REACTANTS UNDERSTANDING MASS RELATIONSHIPS IN CHEMICAL REACTIONS

STOICHIOMETRY & LIMITING REACTANTS UNDERSTANDING MASS RELATIONSHIPS IN CHEMICAL REACTIONS STOICHIOMETRY & LIMITING REACTANTS UNDERSTANDING MASS RELATIONSHIPS IN CHEMICAL REACTIONS If the number of atoms is conserved in a chemical reaction, the mass must also be conserved as expected from the

More information

Stoichiometric Calculations

Stoichiometric Calculations Slide 1 / 109 Slide 2 / 109 Stoichiometric Calculations Slide 3 / 109 Slide 4 / 109 Table of Contents Stoichiometry Calculations with Moles Click on the topic to go to that section Stoichiometry Calculations

More information

Balancing Chemical Reactions. CHAPTER 3: Quantitative Relationships in Chemical Reactions. Zn + HCl ZnCl 2 + H 2. reactant atoms product atoms

Balancing Chemical Reactions. CHAPTER 3: Quantitative Relationships in Chemical Reactions. Zn + HCl ZnCl 2 + H 2. reactant atoms product atoms CHAPTER 3: Quantitative Relationships in Chemical Reactions Stoichiometry: Greek for measure elements Stoichiometry involves calculations based on chemical formulas and chemical equations (reactions) quantitative.

More information

Stoichiometry. Chapter 3

Stoichiometry. Chapter 3 Stoichiometry Chapter 3 Chemical Stoichiometry Stoichiometry: The study of quantities of materials consumed and produced in chemical reactions. In macroworld, we can count objects by weighing assuming

More information

Stoichiometry. Consider the reaction in which the reactants are nitrogen gas and hydrogen gas. They produce the product ammonia gas.

Stoichiometry. Consider the reaction in which the reactants are nitrogen gas and hydrogen gas. They produce the product ammonia gas. 1 1. Interpreting Chemical Equations Stoichiometry Calculations using balanced equations are called stoichiometric calculations. The starting point for any problem involving quantities of chemicals in

More information

Chapter 15. In the preceding chapters we limited our consideration to CHEMICAL REACTIONS. Objectives

Chapter 15. In the preceding chapters we limited our consideration to CHEMICAL REACTIONS. Objectives Chapter 15 CHEMICAL REACTIONS In the preceding chapters we limited our consideration to nonreacting systems systems whose chemical composition remains unchanged during a process. This was the case even

More information

Mass Relationships in Chemical Reactions

Mass Relationships in Chemical Reactions Mass Relationships in Chemical Reactions Chapter 3 Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Micro World atoms & molecules Macro World grams Atomic mass

More information

AP Chapter 3 Study Questions

AP Chapter 3 Study Questions Class: Date: AP Chapter 3 Study Questions True/False Indicate whether the statement is true or false. 1. The mass of a single atom of an element (in amu) is numerically EQUAL to the mass in grams of 1

More information

Stoichiometry. Please take out your notebooks

Stoichiometry. Please take out your notebooks Stoichiometry Please take out your notebooks Stoichiometry stochio = Greek for element metry = measurement Stoichiometry is about measuring the amounts of elements and compounds involved in a reaction.

More information

Chapter 4. Chemical Quantities and Aqueous Reactions

Chapter 4. Chemical Quantities and Aqueous Reactions Chapter 4 Chemical Quantities and Aqueous Reactions Stoichiometry The study of the numerical relationship between chemical quantities in a chemical reaction Making Pizza The number of pizzas you can make

More information

HOMEWORK 11-1 (pp )

HOMEWORK 11-1 (pp ) CHAPTER 11 HOMEWORK 11-1 (pp. 333 335) VOCABULARY Define. 1. Gay-Lussac s law of combining volumes of gases 2. Avogadro s law Answer each question. 3. Write and explain the equation that expresses the

More information

STOICHIOMETRY. Measurements in Chemical Reactions

STOICHIOMETRY. Measurements in Chemical Reactions STOICHIOMETRY Measurements in Chemical Reactions STOICHIOMETRY Stoichiometry is the analysis of the quantities of substances in a chemical reaction. Stoichiometric calculations depend on the MOLE-MOLE

More information

Unit 6: Stoichiometry. How do manufacturers know how to make enough of their desired product?

Unit 6: Stoichiometry. How do manufacturers know how to make enough of their desired product? Unit 6: Stoichiometry How do manufacturers know how to make enough of their desired product? Chocolate Chip Cookies Using the following recipe, complete the questions. Cookie Recipe 1.5 c sugar 1 c. butter

More information

**continued on next page**

**continued on next page** Chapter 9 Stoichiometry Section 9.1 Introduction to Stoichiometry Standard.e.: Students know how to calculate the masses of reactant and products in a chemical reaction from the mass of one of the reactants

More information

Copyrighted by Gabriel Tang B.Ed., B.Sc.

Copyrighted by Gabriel Tang B.Ed., B.Sc. Unit 5: Chemical Equations and Reactions & Stoichiometry Chemistry Chapter 9: Stoichiometry 9.1: Calculating Quantities in Reactions Avogadro s Number: - a group of (6.0 10 ) molecules = 1 mole Stoichiometry:

More information

CHAPTER 8. Stoichiometry

CHAPTER 8. Stoichiometry CHAPTER 8 Stoichiometry So far in your chemistry course, you have learned that chemists count quantities of elements and compounds in terms of moles and that they relate moles of a substance to mass by

More information

CHAPTER 12. Chemists use balanced to calculate how much reactant is needed or product is formed in a reaction. + 3H 2NH. Hon Chem 12.

CHAPTER 12. Chemists use balanced to calculate how much reactant is needed or product is formed in a reaction. + 3H 2NH. Hon Chem 12. CHAPTER 12 Stoichiometry is the calculation of quantities using different substances in chemical equations. Based on the Law of Conservation of Mass. Mg(s) + How many moles of H Chemists use balanced to

More information

9/14/ Chemistry Second Edition Julia Burdge. Stoichiometry: Ratios of Combination. Molecular and Formula Masses

9/14/ Chemistry Second Edition Julia Burdge. Stoichiometry: Ratios of Combination. Molecular and Formula Masses 9/14/1 Chemistry Second Edition Julia Burdge Stoichiometry: Ratios of Combination Copyright (c) The McGraw-Hill Companies, Inc. Permission required for reproduction or display. 1 Stoichiometry: Ratios

More information

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Chemistry, The Central Science, 11th edition Theodore L. Brown, H. Eugene LeMay, Jr., and Bruce E. Bursten Chapter 3 : Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community

More information

AP Chemistry Chapter 3. Stoichiometry

AP Chemistry Chapter 3. Stoichiometry AP Chemistry Chapter 3 Stoichiometry Stoichiometry Is the study of the quantities of substances consumed and produced in chemical reactions Derived from the Greek words stoicheion meaning element and metron

More information

Mass Relationships in Chemical Reactions

Mass Relationships in Chemical Reactions Mass Relationships in Chemical Reactions Chapter 3 Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Micro World atoms & molecules Macro World grams Atomic mass

More information

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Chemistry, The Central Science, 10th edition Theodore L. Brown, H. Eugene LeMay, Jr., and Bruce E. Bursten Chapter 3 : Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community

More information

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations

Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Chemistry, The Central Science, 10th edition Theodore L. Brown, H. Eugene LeMay, Jr., and Bruce E. Bursten Chapter 3 : Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community

More information

Unit 7: Stoichiometry Homework Packet (85 points)

Unit 7: Stoichiometry Homework Packet (85 points) Name: Period: By the end of the Unit 7, you should be able to: Chapter 12 1. Use stoichiometry to determine the amount of substance in a reaction 2. Determine the limiting reactant of a reaction 3. Determine

More information

General Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction

General Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction General Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction Given an amount of a substance involved in a chemical reaction, we can figure out the amount

More information

Unit 14 Calculations for Chemical Equations

Unit 14 Calculations for Chemical Equations Unit 14 Calculations for Chemical Equations INTRODUCTION The most often encountered problem in chemistry is one that involves a balanced chemical reaction. Almost all areas of chemistry deal with reactions

More information

IGCSE Double Award Extended Coordinated Science

IGCSE Double Award Extended Coordinated Science IGCSE Double Award Extended Coordinated Science Chemistry 4.1 - The Mole Concept The Atomic Mass Unit You need to know the atomic mass unit and the relative atomic mass. In Unit C3.3, 1 atomic mass unit

More information

Chemical Reactions. Chapter 17

Chemical Reactions. Chapter 17 Chemical Reactions Chapter 17 Chemical Equations C+O 2 CO 2 C (s) +O 2 (g) CO 2 (g) Reactants on left, products on right Each are balanced because same number of atoms of reactants as products Some equations

More information

Stoichiometry World of Chemistry: Chapter 9

Stoichiometry World of Chemistry: Chapter 9 Stoichiometry World of Chemistry: Chapter 9 Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose flour 1 teaspoon

More information

Chapter 2: Mass Relations in Formulas, Chemical Reactions, and Stoichiometry

Chapter 2: Mass Relations in Formulas, Chemical Reactions, and Stoichiometry Previous Chapter Table of Contents Next Chapter Chapter 2: Mass Relations in Formulas, Chemical Reactions, and Stoichiometry Section 2.1: The Atomic Mass The atomic mass is the mass of 1 atom. Atoms are

More information

Stoichiometry Dry Lab

Stoichiometry Dry Lab Stoichiometry Dry Lab Name: Mole-Mass Conversions The molar mass of a substance is the conversion factor that allows us to convert between the mass of a substance (in grams) and the number of moles of

More information

Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations

Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Matter Matter is anything that has mass and takes up space 2 Composition of Matter Atom number of protons = atomic number (Z)

More information

5. The mass of oxygen required to completely convert 4.0 grams of hydrogen to water is 1) 8.0 grams; 2) 2.0 grams; 3) 32 grams; 4) 16 grams.

5. The mass of oxygen required to completely convert 4.0 grams of hydrogen to water is 1) 8.0 grams; 2) 2.0 grams; 3) 32 grams; 4) 16 grams. CHEMISTRY TEST NAME: MASS AND VOLUME DATE: EQUATION RELATIONSHIPS Directions: For each of the following questions, choose the number that best answers the question and place it on your answer sheet. Directions:

More information

Chapter 3 The Mole and Stoichiometry

Chapter 3 The Mole and Stoichiometry Chapter 3 The Mole and Stoichiometry Chemistry, 7 th Edition International Student Version Brady/Jespersen/Hyslop Brady/Jespersen/Hyslop Chemistry7E, Copyright 015 John Wiley & Sons, Inc. All Rights Reserved

More information

UNIT 3 Chemical Quantities Chapter 5 Counting Atoms and Molecules The Mole

UNIT 3 Chemical Quantities Chapter 5 Counting Atoms and Molecules The Mole UNIT 3 Chemical Quantities Chapter 5 Counting Atoms and Molecules The Mole How does the mass of a substance relate to the number of atoms in the substance? Recall: Atomic mass units. Atomic mass units

More information