Balance the following equation: Fe + O 2 Fe 2 O 3. Please complete your warm-up on a scratch piece of paper and turn it into the basket.
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1 Balance the following equation: Fe + O 2 Fe 2 O 3 Please complete your warm-up on a scratch piece of paper and turn it into the basket. 1
2 Balancing Equations Law of Conservation of Mass Law of Definite Proportions The RAP Table Balancing Equations 2
3 Law of Conservation of Mass The Law of Conservation of Mass: States that matter is neither lost nor gained in chemical reactions, but simply changes form. Mass of Reactants = Mass of Products
4 Dalton s Law of Definite Proportions Atoms are indestructible and unchangeable Compounds are formed when one atom chemically combines with other atoms When elements react to form compounds, they react in defined, whole-number ratios.
5 If a chemical equation does not obey the law of conservation of mass the equation is said to be what? NOT BALANCED So Let s look at the steps we need to take to BALANCE chemical equations Let s work with the following equation: Fe + O 2 Fe 2 O 3 5
6 Step 1. Create a RAP table A table that shows us what atoms are present in this reaction, how many there are and are they reactants or products? For example: #Reactants atom #Products 1 Fe 2 2 O 3 Fe + O 2 Fe 2 O 3 6
7 Rule 2. Go to the first atom that s not balanced and balance it! Since Fe atoms are not balanced what do we need to do to balance it? Right! Multiply it by 2 (Only multiply) 2x 1 Fe 2 2 O 3 7
8 In step 2, we balanced the number of Fe atoms by multiplying the reactant side by 2. This now becomes the new coefficient in the chemical equation. 2x 1 Fe 2 2 O 3 Modify the equation to reflect the change 2Fe + O 2 Fe 2 O 3 Are all atoms balanced? 8
9 3. Move to the next unbalanced atom. What is it? 2 Fe 2 2 O 3 How can we balance the Oxygen? Multiply Reactants by 3 and Products by 2 2 Fe 2 3x2 O 3x2 Adjust the equation to reflect your changes 2Fe + 3O 2 2Fe 2 O 3 But notice that by changing Oxygen we also Changed Iron. We need to go back and fix this. 9
10 4. Write out the updated RAP table. How can we Balance the Iron? 2x 2 Fe 4 6 O 6 Sure! Multiply the # of Reactant Fe atoms by 2! Re-write the equation reflecting The new changes you ve made. 4Fe + 3O 2 2Fe 2 O 3 Do we have a balanced Chemical Equation now? Yes we do! 10
11 Polyatomics When an equation has Polyatomics in it, such as in this Balanced chemical equation 2AgNO 3 + MgCl 2 2AgCl + Mg(NO 3 ) 2 And the polyatomic appears on BOTH the reactant and product Side of the equation Count the polyatomic as an ATOM So the above reactant atoms would be: If the same polyatomic does not Appear on both sides break the Polyatomic down into atoms! 2 Ag 2 2 NO Mg 1 2 Cl 2 11
12 Polyatomic Ions 12
13 Steps to Balancing Equations There are four basic steps to balancing a chemical equation. 1. Write the correct formula for the reactants and the products. **And most importantly, once you write them correctly DO NOT CHANGE THE FORMULAS! 2. Find the number of atoms for each element on the left side. Compare those against the number of the atoms of the same element on the right side. 3. Determine where to place coefficients in front of formulas so that the left side has the same number of atoms as the right side for EACH element in order to balance the equation. 4. Check your answer to see if: The numbers of atoms on both sides of the equation are now balanced. The coefficients are in the lowest possible whole number ratios. (reduced)
14 Some Suggestions to Help Some helpful hints for balancing equations: Take one element at a time, working left to right except for H and O. Metals, then nonmetals are a good way, too. Save H for next to last, and O until last. IF everything balances except for O, and there is no way to balance O with a whole number, double all the coefficients and try again. (Because O is diatomic as an element)
15 Let s Do Some Examples! 15
16 Is this equation balanced? NaOH + CaBr 2 Ca(OH) 2 + NaBr What atoms do we have in This equation? 1) Count atoms & Start the RAP table 1 NA 1 1 OH 2 1 Ca 1 2 Br 1 2) Do the #Reactant atoms = the # of Product atoms? 3) So pick the 1st unbalanced atom & begin balancing 16
17 We ll start with balancing Hydroxide NaOH + CaBr 2 Ca(OH) 2 +NaBr How can we make both Hydroxides equal? Sure we ll multiply #R OH by 2 Next step rewrite the modified eqn. 2NaOH + CaBr 2 Ca(OH) 2 + NaBr 2x 1 Na 1 1 OH 2 1 Ca 1 2 Br 1 Hydroxide is now balanced so let s move to the next Unbalanced atom, which is? 17
18 What can we do to balance the Bromine? Sure! Multiply the #P Bromine by 2 Now adjust the table to reflect The changes and then rewrite the Eqn. 2 Na 1 2 OH 2 1 Ca 1 2 Br 1 x2 2NaOH + CaBr 2 Ca(OH) 2 + 2NaBr 18
19 Let s update the RAP table with the new # s Based on our updated equation. 2NaOH + CaBr 2 Ca(OH) 2 + 2NaBr Are we now balanced? Sure! 2 Na 2 2 OH 2 1 Ca 1 2 Br 2 19
20 Ok Try Balancing this equation: C 2 H 6 + O 2 CO 2 + H 2 O Step 1. Total up the atoms Step 2. Balance the #P Carbon 2 C 1 6 H 2 2 O 3 2 C 2 6 H 2 2 O 5 & Re-write the equation C 2 H 6 + O 2 2CO 2 + H 2 O Are we done? 20
21 Step 3. Carbons are balanced now but Hydrogen isn t. So, balance Hydrogen atoms next Multiply #P Hydrogen by 3 Step 4. Re-write the eqn. & Retotal the number of atoms 2 C 2 6 H 2 2 O 5 x3 2 C 2 6 H 6 2 O 7 C 2 H 6 + O 2 2CO 2 + 3H 2 O Carbon and Hydrogen are now balanced but oxygen isn t. 21
22 Step 5. To balance Oxygen multiply O by 3½ Step 6. Re-write the eqn. & Retotal the number of atoms 2 C 2 6 H 6 3 ½ x2 O 7 C 2 H 6 + 3½ O 2 2CO 2 + 3H 2 O It looks like we re balanced. But, are we? No! We can t have 3 ½ Oxygen molecules! Only whole Numbers are allowed. So what do we need to do to fix this? 22
23 Step 7. Let s clean this up by Multiply everything by 2 C 2 H 6 + 3½ O 2 2CO 2 + 3H 2 O x 2 2C 2 H O 2 4CO 2 + 6H 2 O Step 8. Retotal #R and the #P atoms 4 C 4 12 H O 14 Are we balanced? YES! 23
24 Try this problem NH 4 OH + FeCl 3 Fe(OH) 3 + NH 4 Cl Start here. Recognize we Have polyatomics but they Appear on both sides of the Equation. 1 NH OH 3 1 Fe 1 3 Cl 1 OK Now finish it up 24
25 3NH 4 OH + FeCl 3 Fe(OH) 3 + 3NH 4 Cl 25
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