Using the shake culture technique, it was possible to separate a Methanosarcina
|
|
- Winifred Booker
- 5 years ago
- Views:
Transcription
1 STUDIES ON THE METHANE FERMENTATION IX. THE ORIGIN OF METHANE IN THE ACETATE AND METHANOL FERMENTATIONS BY METHANOSARCINA1 THRESSA C. STADTMAN2 AND H. A. BARKER Diviaion of Plant Biochemistry, University of California, Berkeley, California Received for publication October 9, 1950 It is well established that the methane formed in the fermentation of a variety of substrates, including ethanol, isopropanol, propionate, butyrate, valerate, carbon monoxide, and hydrogen, is derived from carbon dioxide (Stadtman and Barker, 1949; Kluyver and Schnellen, 1947). There is equally conclusive evidence to show that, in the methane fermentation of acetate, most of the methane is derived not from carbon dioxide but from the methyl group of the substrate (Buswell and Sollo, 1948; Stadtman and Barker, 1949). This has been demonstrated both with crude enrichment cultures and with partially purified cultures of a Methanococcus species. The significance of these results in relation to the carbon dioxide reduction theory of the origin of methane has already been discussed. Tracer experiments on the origin of methane, carried out with another acetatefermenting bacterium, a species of Methanosarcina, are reported in the present paper. Since either methanol or acetate can be metabolized as a sole carbon source by this bacterium, it was possible to examine the role of carbon dioxide in fermentations of both substrates. These experiments provide additional examples of fermentations wherein methane arises chiefly from the organic substrate and carbon dioxide reduction appears to be of little importance. MATERIALS AND METHODS Actively fermenting acetate enrichment cultures of methane-producing bac- belonging to the genus Methanosarcina were obtained from black mud. teria Using the shake culture technique, it was possible to separate a Methanosarcina from the other bacteria present with the exception of a long, threadlike, motile, rod-shaped bacterium that frequently contained terminal spherical spores. Successive transfers of isolated colonies did not completely eliminate the contaminant, for a few cells could occasionally be found in colonies of the Methanosarcina. Further purification was not attempted because of the very slow rate of development of the methane organism. The Methanosarcina is a large coccus forming typical packets of cells. In liquid cultures these packets make up large zoogloeal masses. The organism can ferment both methyl alcohol and acetate. Growth is more rapid on the former sub- I This investigation was supported in part by a research grant from the Division of Research Grants and Fellowships of the National Institutes of Health, United States Public Health Service. 2 Present address: National Heart Institute, Bethesda, Maryland. 81
2 82 THRESSA C. STADTMAN AND H. A. BARKER [VOL. 61 strate. In these respects the organism is like one isolated by Schnellen (1947) and designated Methanosarcina barkeri. Unfortunately Schnellen's culture has been lost, and hence the complete identity of the two organisms could not be established. The bacteria were grown anaerobically in a mineral medium (Stadtman and Barker, 1951) containing 5 mm of sodium acetate or 10 mm of methanol and 2 mm of sodium bicarbonate in a total volume of 100 ml. When active fermentation had started, the C14-labeled substrate was added. Oxygen was removed from the gas over the medium, and the evolved gases were collected as previously described (Stadtman and Barker, 1949). Samples of the medium were withdrawn for analysis immediately after the radioactive substrate was added and after fermentation was complete. Methyl alcohol was determined by the microdiffusion method of Widmark (1922). Methyl alcohol is oxidized completely to carbon dioxide by excess N/10 INCUBAnON TABLE 1 Specific activnties of carbon dioxide and methane formed in the fermentation of C14H3COOH by a Methanoearcinal IN WEEKS SPECIJIC ACTIITES, CTS./MI/mM Substrate addedt COts CH4 0 24, , (dissolved gas) 1 One hundred per cent of the added C14 was recovered in the products. 2 Initially 4.20 mm of labeled acetate were present; 3.05 mm were decomposed during the experiment. 3 Initially 2.55 mm of unlabeled carbon dioxide were present in the medium. dichromate in concentrated H2S04 at 55 C in 30 minutes. For specific activity measurements, methyl alcohol was converted to barium carbonate. Other methods have been described elsewhere (Stadtman and Barker, 1949). Fermentation of C14H3COOH. The fermentation of methyl-labeled acetate by the Methanosarcina culture gave essentially the same results as were obtained in a similar experiment with a Methanococcus culture (Stadtman and Barker, 1949). The molar specific activities of the methane and the added acetate were the same (table 1). Therefore it may be concluded that all the methane was derived from the methyl group of the acetate. The average specific activity of the evolved carbon dioxide (after correction for isotopic dilution by bicarbonate added to the medium) indicates that 5.9 per cent of it was derived from the acetate methyl group. The long duration of the experiment was due to the fact that the Methanosarcina grows very slowly on acetate. No gas was evolved during the first 4 to 6 weeks of incubation. Fermentation of methanol and C1402. The specific activityof the methane evolved during the fermentation of methanol in the presence of labeled carbon dioxide
3 1951] STUDIES ON THE METHANE FERMENTATION 83 was much less than that of the carbon dioxide (table 2). The ratio of the specific activity of the methane produced during the first 32 days of the fermentation to that of the carbon dioxide was approximately During the next 58 days this ratio increased to These results are essentially the same as those obtained in the acetate fermentation (Buswell and Sollo, 1948; Stadtman and Barker, 1949). Since the methane was not derived from carbon dioxide, it must have been formed almost entirely (98 to 99 per cent) from methanol. This is the second example of a methane fermentation wherein the methane is derived from the substrate rather than from carbon dioxide. When the fermentation was stopped, the residual methyl alchohol (7.56 mm) was found to contain a small amount of C14 (270 cts. per min per mm). The incorporation of labeled carbon into methyl alcohol may have resulted from a limited reversibility of the reactions involved in the oxidation of the alcohol. TABLE 2 Specific activities of carbon dioxide and methane formed in the methyl alcohol1-c402 fermentation2 INCUBATION TIME IN DAYS CO, SPECIFIC ACTIVITIES, CTS./M3N/mM 0 29, , , ,100 (dissolved) 1 Initially 9.50 mm of methyl alcohol were present in the medium; 1.94 mm were decomposed during the fermentation. 2 Of the added C14, 112 per cent was recovered in the products. BSpecific activity of 1.93 mm of carbon dioxide present in the medium initially. The decrease in specific activity of the carbon dioxide (table 2) was due to the fornation of inactive carbon dioxide from methyl alcohol according to the over-all reaction. 4CH30H -- 3CH4 + CO2 + 2H20 (1) At the end of the fermentation, 0.72 mm of volatile acid were recovered from the medium. A Duclaux distillation indicated that the acid was chiefly acetic acid. The absence of formic acid was shown by the observation that no carbon dioxide was evolved when the material was oxidized with HgO (Friedemann, 1938). The specific activity of the "acetate" (25,500 cts. per min per mm) indicates that approximately 50 per cent of it was derived from the labeled carbon dioxide. This acid may have been synthesized either by the methane organism or by the contaminant. DISCUSSION The data on the fermentation of methyl-labeled acetate by the Methanosarcina culture show that the methane is derived from the methyl group and that the CH,
4 84 THRESSA C. STADTMAN AND H. A. BARKER [vol. 61- carbon dioxide comes from the carboxyl group of the substrate. This is in agreement with earlier experiments done with crude enrichment cultures and with a purified culture of a Methanococcus species. Although further observations on other species of methane-producing bacteria would be desirable, the available information justifies the conclusion that the methane fermentation of acetate differs fundamentally from that of most other substrates in that carbon dioxide reduction is a minor reaction. Carbon dioxide utilization is also of little importance in the fermentation of methyl alcohol by Methanosarcina. From the data it is apparent that at least 98 per cent of the methane is derived from the alcohol, whereas not more than 2 per cent comes from carbon dioxide. This result may appear to be inconsistent with earlier experiments (Barker et al., 1940) in which C"l was used to study carbon dioxide utilization. However, it may be noted that, because of the short half life of C" and the inexperience of the investigators in 1940 with tracer methods, the data obtained at that time were of only qualitative significance. The conclusion that carbon dioxide can be converted to methane in the methyl alcohol fermentation was correct. But we now know that only a small fraction of the methane is derived from this source. The fermentation of methyl alcohol to methane and carbon dioxide (reaction 1) could be interpreted as a dismutation wherein the oxidation of 1 mole of methyl alcohol to carbon dioxide (reaction 2) is coupled with the reduction of 3 moles of alcohol to methane (reaction 3). CHsOH + H20 - C002+ 6H (2) 3CH3OH + 6H -* 3CH4 + 3H20 (3) The net result would be the same as reaction 1. Although this formulation is consistent with the data obtained in the tracer experiments, it does not account for all the known facts. Reaction 2 implies that methyl alcohol is reduced directly to methane and, therefore, should be used as an oxidant in other methane fermentations. Actually, methyl alcohol cannot be used by Methanobacterium omelianskii as a hydrogen acceptor in place of carbon dioxide (Barker, 1941), and also it is metabolized much more slowly than carbon dioxide by the unidentified methane bacterium studied by Stephenson and Stickland (1933). Therefore we must conclude that methyl alcohol is not reduced directly to methane. A more satisfactory interpretation is that methyl alcohol is transformed, probably by oxidation, to a hypothetical intermediate (compound Y in scheme I, below) common to the paths of methane formation from both methyl alcohol and carbon dioxide. The existence of a common intermediate is assumed because Schnellen (1947) has shown that M. barkeri can ferment methyl alcohol and also reduce carbon dioxide to methane with gaseous hydrogen. Although we do not know that our Methanosarcina is able to reduce carbon dioxide with hydrogen or that Schnellen's bacterium forms methane from methyl alcohol by a mechanism not involving carbon dioxide reduction, the great similarity of the two organisms makes it probable that they both carry out the same reactions.
5 1951] STUDIES ON THE METHANE FERMENTATION 85 Scheme I summarizes the conclusions about the mechanism of methane formation from carbon dioxide, methyl alcohol, and acetic acid that can be drawn from the information now available. The scheme is based on the assumption that there is only one general mechanism of methane formation, Acetate CH3 group -) X - CH4 t1~ Scheme I CH3OH > y C002 and on the following facts: (1) Acetate, methyl alcohol, and carbon dioxide are utilized by a single organism, M. barkeri (Schnellen, 1947). (2) The methyl group of acetate is converted to methane but only slightly to carbon dioxide (Stadtman and Barker, 1949). (3) Methyl alcohol is converted readily to both methane and carbon dioxide. (4) Carbon dioxide is reduced to methane by bacteria that cannot use either acetate or methanol (Barker, 1941; Stadtman and Barker, 1949). Compound X, the hypothetical intermediate derived from the methyl group of acetate, is distinguished from compound Y, derived from methyl alcohol, by the fact that it is readily converted to methane but not to carbon dioxide, whereas compound Y is converted to both products. The conversion of Y to X must be almost irreversible. At present we have no information concerning the identities of the postulated intermediates. However, it is probable that they are multicarbon compounds in view of the fact that none of the other C1 compounds so far tested (CO, HCOOH, HCHO) can be reduced directly to methane (Barker, 1941; Kluyver and Schneilen, 1947; Stephenson and Stickland, 1933). Scheme I does not exclude the conversion of carbon dioxide to methane during the fermentation of acetate and methyl alcohol. However, we have seen that, with these substrates, carbon dioxide utilization is actually very small. This can be attributed to an inhibition of carbon dioxide reduction by the accumulation of intermediates X and Y, which are presumably formed more readily from acetate and methyl alcohol than from carbon dioxide. This is analogous to the wellknown inhibition of nitrogen fixation by ammonia. Recently du Vigneaud and Verly (1950) reported that C'4-labeled methyl alcohol is incorporated in vivo into the methyl groups of choline in the rat. It seems possible that the pathways of conversion of methyl alcohol to labile methyl groups in the animal and to methane in bacteria may be similar. SUMMARY By the tracer technique, a Methanosarcina species was shown to form methane from the methyl group of acetate and from methyl alcohol rather than from carbon dioxide in the fermentation of these substrates. The significance of these results is discussed in relation to the mechanism of methane formation. REFERENCES BARKER, H. A Studies on the methane fernentation. V. Biochemical properties of Methanobacterium omelianskii. J. Biol. Chem., 137,
6 86 THRESSA C. STADTMAN AND H. A. BARKER [vol. 61 BARKER, H. A., RUBEN, S., AND KAMEN, M. D The reduction of radioactive carbon dioxide by methane-producing bacteria. Proc. Nat. Acad. Sci. U.S., 2B, BUSWELL, A. M., AND SOLLO, F. W The mechanism of methane fermentation. J. Am. Chem. Soc., 70, DU VIGNEAUD, V., AND VERLY, W. G Incorporation in vivo of C14 from labeled methanol into the methyl groups of choline. J. Am. Chem. Soc., 72, FRIEDEMANN, T. E The identification and quantitative determination of volatile alcohols and acids. J. Biol. Chem., 123, KLUYVER, A. J., AND SCHNELLEN, C. G. T. P On the fermentation of carbon monoxide by pure cultures of methane bacteria. Arch. Biochem., 14, SCHNELLEN, C. G. T. P Onderzoekingen over de Methaangisting. Dissertation, Delft. STADTMAN, T. C., AND BARKER, H. A Studies on the methane fermentation. VII. Tracer experiments on the mechanism of methane formation. Arch. Biochem., 21, STADTMAN, T. C., AND BARKER, H. A Studies on the methane fermentation. VIII. Tracer experiments on fatty acid oxidation by methane bacteria. J. Bact., 61, STEPHENSON, M., AND STICKLAND, L. H Hydrogenase. III. The bacterial formation of methane by the reduction of one-carbon compounds by molecular hydrogen. Biochem. J., 27, WIDMARK, E. M. P Eine Mikromethode zur Bestimmung von Athylalkohol im Blut. Biochem. Z., 131, Downloaded from on January 25, 2019 by guest
METHANE FORMATION; FERMENTATION OF ETHANOL IN THE ABSENCE OF CARBON DIOXIDE BY METHANOBACILLUS OMELIANSKII'
METHANE FORMATION; FERMENTATION OF ETHANOL IN THE ABSENCE OF CARBON DIOXIDE BY METHANOBACILLUS OMELIANSKII' A. T. JOHNS2 AND H. A. BARKER Department of Biochemistry, University of California, Berkeley,
More informationHYDROGEN. technique. uptake/co2 uptake, which according to equation (1) should equal 4, has
184 BA CTERIOLOG Y: H. A. BARKER PROC. N. A. S. STUDIES ON THE METHANE FERMENTATION. VI. THE IN- FLUENCE OF CARBON DIOXIDE CONCENTRATION ON THE RATE OF CARBON DIOXIDE REDUCTION BY MOLECULAR HYDROGEN By
More informationXII. THE PATHWAY OF HYDROGEN IN 1Hi ACETATE FERMENTATION1
STUDIES ON THE METHANE FERMENTATION XII. THE PATHWAY OF HYDROGEN IN 1Hi ACETATE FERMENTATION1 MARTIN J. PINE" AND H. A. BARKER Department of Plant Biochemistry, University of California, Berkeley, California
More informationTentative Identification of Methanogenic Bacteria by Fluorescence Microscopy
APPLIED AND ENVIRONMENTAL MICROBIOLOGY, Mar. 1977, p. 713-717 Copyright (C 1977 American Society for Microbiology Vol. 33, No. 3 Printed in U.S.A. Tentative Identification of Methanogenic Bacteria by Fluorescence
More informationMC 17 C SECTION - I (40 marks) Compulsory : Attempt all questions from this section.
Question 1. (a) SECTION - I (40 marks) Compulsory : Attempt all questions from this section. Choose from the following list of substances, as to what matches the description from to given below : [Bronze,
More informationChemistry 20 Lesson 17 Solubility
Chemistry 20 Lesson 17 Solubility The ability of one compound to dissolve in another compound is called solubility. The term solubility can be used in two senses, qualitatively and quantitatively. Qualitatively,
More informationSample Problem Set. Teacher Notes and Answers. Skills Worksheet PERCENTAGE YIELD. Name: Class: Date:
Skills Worksheet Sample Problem Set Teacher Notes and Answers PERCENTAGE YIELD 1. a. 64.3% yield b. 58.0% yield c. 69.5% yield d. CH 3 CH OH is limiting; 79% yield. a. 69.5% yield b. 79.0% yield c. 48%
More informationProblem Solving. Percentage Yield
Skills Worksheet Problem Solving Percentage Yield Although we can write perfectly balanced equations to represent perfect reactions, the reactions themselves are often not perfect. A reaction does not
More informationThe Atom, The Mole & Stoichiometry. Chapter 2 I. The Atomic Theory A. proposed the modern atomic model to explain the laws of chemical combination.
Unit 2: The Atom, The Mole & Stoichiometry Chapter 2 I. The Atomic Theory A. proposed the modern atomic model to explain the laws of chemical combination. Postulates of the atomic theory: 1. All matter
More informationChem. I Notes Ch. 11 STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics.
Chem. I Notes Ch. 11 STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. 11.1 notes 1 MOLE = 6.02 x 10 23 representative particles representative particles
More informationICSE-Science 2(Chemistry) 2009
ICSE-Science 2(Chemistry) 2009 Answers to this Paper must be written on the paper provided separately. You will not be allowed to write during the first 15 minutes. This time is to be spent in reading
More informationAP Chemistry Review Packet # form B. How many grams of water are present in 1.00 mol of copper(ii) sulfate pentahydrate?
AP Chemistry Review Packet #4 Warmup: Reaction Prediction 2010 form B (a) Solid copper(ii) sulfate pentahydrate is gently heated. How many grams of water are present in 1.00 mol of copper(ii) sulfate pentahydrate?
More informationMetabolic diversity is based on the Electron donors, acceptors, and carbon sources available - thermodynamics
To date you have covered microbial community sampling using molecular techniques to identify who is present in the environment. You have also looked at various genetic mechanisms to understand how organisms
More informationChapter 3 Stoichiometry
Chapter 3 Sep 22 1:45 PM Average atomic mass: The weighted average of all isotopes of a specific element. Takes into consideration abundance of each isotope. (% x M 1 ) + (% x M 2 ) +... Sep 22 1:45 PM
More informationCampbell's Biology, 9e (Reece et al.) Chapter 2 The Chemical Context of Life
Campbell's Biology, 9e (Reece et al.) Chapter 2 The Chemical Context of Life This chapter presents basic chemical principles for understanding the chemical context of living organisms, from atomic structure
More informationCHEMISTRY HIGHER LEVEL
*P15* Pre-Leaving Certificate Examination, 2012 Triailscrúdú na hardteistiméireachta, 2012 CHEMISTRY HIGHER LEVEL TIME: 3 HOURS 400 MARKS Answer eight questions in all These must include at least two questions
More informationOrganic Chemistry. Alkanes are hydrocarbons in which the carbon atoms are joined by single covalent bonds.
Organic Chemistry Organic compounds: The branch of chemistry which deals with the study of carbon compounds is called organic chemistry. Catenation: The carbon atom has a property to undergo self linking
More informationInternational General Certificate of Secondary Education UNIVERSITYOF CAMBRIDGELOCALEXAMINATIONSYNDICATE CHEMISTRY 0620/3
Centre Number Candidate Number Candidate Name International General Certificate of Secondary Education UNIVERSITYOF CAMBRIDGELOCALEXAMINATIONSYNDICATE CHEMISTRY 0620/3 PAPER 3 Thursday 27 MAY 1999 Afternoon
More information1. The reaction between solid barium hydroxide and solid ammonium chloride can be represented by the equation below.
1. The reaction between solid barium hydroxide and solid ammonium chloride can be represented by the equation below. Ba(OH) 2 (s) + 2NH 4 Cl(s) BaCl 2 (s) + 2NH 3 (g) + 2H 2 O(l) ΔH ο = +51.1 kj mol 1
More informationTHE UNITED REPUBLIC OF TANZANIA NATIONAL EXAMINATIONS COUNCIL CERTIFICATE OF SECONDARY EDUCATION EXAMINATION
THE UNITED REPUBLIC OF TANZANIA NATIONAL EXAMINATIONS COUNCIL CERTIFICATE OF SECONDARY EDUCATION EXAMINATION 032/1 CHEMISTRY 1 (For Both School and Private Candidates) Time: 3 Hours Thursday, 07 th November
More information10 States of Matter. Aubrey High School AP Chemistry. Period Date / / 10.2 Problems - Liquids and Gases
Aubrey High School AP Chemistry 10 States of Matter 1. Use the following table to answer these questions. Vapor Pressures of Various Liquids Temp. ( C) Ethyl alcohol Benzene Methyl salicylate Water Carbon
More informationCHEM111 UNIT 1 MOLES, FORMULAE AND EQUATIONS QUESTIONS
Lesson 1 1. (a) Deduce the number of protons, neutrons and electrons in the following species: (i) 37 Cl - (ii) 1 H + (iii) 45 Sc 3+ (b) Write symbols for the following species: (i) 8 protons, 8 neutrons,
More information2. What mass of an aqueous 22.9% sodium chloride solution contains 99.5 g of water?
CHEM 1412 MIDTERM EXAM (100 pts total) ANSWER KEY Student s Name PART A (20 multiple choice questions, 3 pts each): 1. The solubility of a gas in a liquid can always be increased by: a) decreasing the
More informationDuring photosynthesis, plants convert carbon dioxide and water into glucose (C 6 H 12 O 6 ) according to the reaction:
Example 4.1 Stoichiometry During photosynthesis, plants convert carbon dioxide and water into glucose (C 6 H 12 O 6 ) according to the reaction: Suppose that a particular plant consumes 37.8 g of CO 2
More informationStoichiometry. Percent composition Part / whole x 100 = %
Stoichiometry Conversion factors 1 mole = 6.02 x 10 23 atoms (element) 1 mole = 6.02 x 10 23 molecules (covalent compounds) 1 mole = 6.02 x 10 23 formula units (ionic compounds) 1 mole (any gas @ STP)
More informationHonors Cup Synthetic Proposal
onors Cup Synthetic Proposal Section: 270-V Group Members: Azhar Carim, Ian Cross, Albert Tang Title: Synthesis of indigo from -(2-bromoethyl)-2-nitrobenzamide Introduction: Indigo has been used as a dye
More informationTHE UNITED REPUBLIC OF TANZANIA NATIONAL EXAMINATIONS COUNCIL CERTIFICATE OF SECONDARY EDUCATION EXAMINATION
THE UNITED REPUBLIC OF TANZANIA NATIONAL EXAMINATIONS COUNCIL CERTIFICATE OF SECONDARY EDUCATION EXAMINATION 032/1 CHEMISTRY 1 (For Both School and Private Candidates) Time: 3 Hours Thursday, 06 th November
More information5. The mass of oxygen required to completely convert 4.0 grams of hydrogen to water is 1) 8.0 grams; 2) 2.0 grams; 3) 32 grams; 4) 16 grams.
CHEMISTRY TEST NAME: MASS AND VOLUME DATE: EQUATION RELATIONSHIPS Directions: For each of the following questions, choose the number that best answers the question and place it on your answer sheet. Directions:
More informationCh 4-5 Practice Problems - KEY
Ch 4-5 Practice Problems - KEY The following problems are intended to provide you with additional practice in preparing for the exam. Questions come from the textbook, previous quizzes, previous exams,
More informationCh. 10 Notes STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics.
Ch. 10 Notes STOICHIOMETRY NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. 1 MOLE = 6.02 x 10 23 representative particles representative particles = ATOMS, IONS,
More informationBalancing chemical reaction equations (stoichiometry)
Balancing chemical reaction equations (stoichiometry) This worksheet and all related files are licensed under the Creative Commons Attribution License, version 1.0. To view a copy of this license, visit
More informationChapter 10 Organic Reactions
Chapter 0 Organic Reactions Name: Class: Date: Time: 85 minutes Marks: 85 marks Comments: Page of 32 This question is about organic compounds. (a) Ethanol burns in air. Use the correct answer from the
More informationCH3CO*COOH - CH3CHO + CO2 (1)
VOL. 27, 1941 CHEMISTRY: CARSON, RUBEN, KAMENAND FOSTER 475 RADIOACTIVE CARBON AS AN INDICATOR OF CARBON DIOXIDE UTILIZATION. VI. ON THE POSSIBILITY OF CAR- BON DIOXIDE REDUCTION VIA THE CARBOXYLASE SYSTEM
More informationChapter 5. Stoichiometry
Chapter 5 Stoichiometry Chapter 5 Table of Contents (5-1) Counting by weighing (5-2) Atomic masses (5-3) Learning to solve problems (5-4) The mole (5-5) Molar mass (5-6) Percent composition of compounds
More informationCHEMISTRY HIGHER LEVEL
*P15* PRE-LEAVING CERTIFICATE EXAMINATION, 2007 CHEMISTRY HIGHER LEVEL TIME: 3 HOURS 400 MARKS Answer eight questions in all These must include at least two questions from Section A All questions carry
More informationExperiment Initial [A] Initial [B] Initial Rate
Chem 120 Practice Final Winter 2014 1 of 14 1. The following are initial rate data for: A + 2 B C + 2 D Experiment Initial [A] Initial [B] Initial Rate 1 0.10 0.10 0.300 2 0.20 0.10 0.600 3 0.10 0.20 1.200
More informationLesson 22: Theoretical Yield Actual Yield Percent Yield
Lesson 22: Theoretical Yield Actual Yield Percent Yield Do Now (5pts) 3.20.8 Copy down info from CJ board. Answer questions in Box of Lesson 22 note packet. You have a test in one week it ll be multiple
More informationWhat is happening in a system at equilibrium? How do scientists predict shifts in the equilibrium of a system?
Equilibrium in Chemical Reactions. (15% of Chemistry 30) What is happening in a system at equilibrium? How do scientists predict shifts in the equilibrium of a system? Key Concepts chemical equilibrium
More informationClass XI Chapter 1 Some Basic Concepts of Chemistry Chemistry
Question 1.1: Calculate the molecular mass of the following: (i) H 2 O (ii) CO 2 (iii) CH 4 (i) H 2 O: The molecular mass of water, H 2 O = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen) = [2(1.0084)
More informationAP Chemistry Summer Assignment
AP Chemistry Summer Assignment Due Date: Thursday, September 1 st, 2011 Directions: Show all of your work for full credit. Include units and labels. Record answers to the correct number of significant
More informationBasic Concepts of Chemistry and Chemical Calculations. The ratio of the average mass factor to one twelfth of the mass of an atom of carbon-12
Basic Concepts of Chemistry and Chemical Calculations Relative Atomic mass: The relative atomic mass is defined as the ratio of the average atomic mass factor to the unified atomic mass unit. (Or) The
More informationChemistry. ANSWERS and MARKING SCHEME. Final Examination Preliminary Course General Instructions. Total Marks 64
ANSWERS and MARKING SCHEME Chemistry Final Examination Preliminary Course 2003 General Instructions Reading time 5 minutes Working time 120 minutes Write using black or blue pen Draw diagrams using pencil
More informationAP Biology Review Chapters 6-8 Review Questions Chapter 6: Metabolism: Energy and Enzymes Chapter 7: Photosynthesis Chapter 8: Cellular Respiration
AP Biology Review Chapters 6-8 Review Questions Chapter 6: Metabolism: Energy and Enzymes 1. Understand and know the first and second laws of thermodynamics. What is entropy? What happens when entropy
More informationCHEM111 UNIT 1 MOLES, FORMULAE AND EQUATIONS QUESTIONS
Lesson 1 1. (a) Deduce the number of protons, neutrons and electrons in the following species: (i) 37 Cl - (ii) 1 H + (iii) 45 Sc 3+ (b) Write symbols for the following species: (i) 8 protons, 8 neutrons,
More informationNational 4/5 Chemistry
National 4/5 hemistry omework Unit 2 Nature s hemistry Please do not write on these booklets questions should be answered in homework jotters. Part 1 Introduction to Unit 2 1. You are given three unlabelled
More informationICSE Board. Class X Chemistry. Board Paper Time: 1½ hrs Total Marks: 80
ICSE Board Class X Chemistry Board Paper 2013 Time: 1½ hrs Total Marks: 80 General Instructions: 1. Answers to this paper must be written on the paper provided separately. 2. You will NOT be allowed to
More informationAn important fuel is methane, natural gas. The equation for its combustion is as follows. CO 2 + 2H 2 O
1 (a Exothermic reactions produce heat energy. An important fuel is methane, natural gas. The equation for its combustion is as follows. CH 4 + 2O 2 CO 2 + 2H 2 O (i) In chemical reactions bonds are broken
More informationName Date. Chapter 2 - Chemistry Guide Microbiology (MCB 2010C) Part 1
Name Date Chapter 2 - Chemistry Guide Microbiology (MCB 2010C) Part 1 The study of biology in the 21 st century is actually the study of biochemistry. In order to be successful in this course, it is important
More informationThe Titration of Acetic Acid in Vinegar
Experiment 22 Revision 1.0 The Titration of Acetic Acid in Vinegar To learn about Volumetric Analysis and Titration. To learn about Aceticc Acid and Vinegar. To learn about Weak Acids. To learn about Equilibria
More informationUnit 3(a) Introduction to Organic Chemistry
Surname Other Names Leave blank Centre Number Candidate Number Candidate Signature General Certificate of Education January 2002 Advanced Subsidiary Examination CHEMISTRY Unit 3(a) Introduction to Organic
More informationChemistry (www.tiwariacademy.com)
() Question 1.1: Calculate the molecular mass of the following: (i) H2O (ii) CO2 (iii) CH4 Answer 1.1: (i) H2O: The molecular mass of water, H2O = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen)
More informationLimiting Reagent Synthesis of Aspirin Thomas M. Moffett Jr., SUNY Plattsburgh, 2007.
Limiting Reagent Synthesis of Aspirin Thomas M. Moffett Jr., SUNY Plattsburgh, 007. Aspirin (acetylsalicylic acid) is the most common medicinal drug in use today. Aspirin is an analgesic (pain reliever),
More informationQ1. (a) State what is meant by the term activation energy of a reaction. (1)
Q1. (a) State what is meant by the term activation energy of a reaction. (c) State in general terms how a catalyst increases the rate of a chemical reaction. The curve below shows the Maxwell Boltzmann
More informationChapter 2 The Chemical Context of Life
Chapter 2 The Chemical Context of Life Information in this chapter establishes a foundation for later discussion and elaboration of molecular-level events and processes in biological systems. Ensuring
More informationCHM 101 GENERAL CHEMISTRY FALL QUARTER 2008
CHM 101 GENERAL CHEMISTRY FALL QUARTER 2008 Section 2 Lecture Notes 10/15/2008 (last revised: 10/15/08, 4:30 PM) 3.3 The Mole: The mole (abbreviated mol) is a unit of measure that greatly facilitates our
More informationChemistry. Student Number. Mark / 64. Final Examination Preliminary Course General Instructions. Total Marks 64
Student Number Mark / 64 Chemistry Final Examination Preliminary Course 2003 General Instructions Reading time 5 minutes Working time 120 minutes Write using black or blue pen Draw diagrams using pencil
More informationCollision Theory Reversible Chemical Reactions
Collision Theory Reversible Chemical Reactions BIOB111 CHEMISTRY & BIOCHEMISTRY Session 4 Key concepts: session 4 From this session you are expected to develop an understanding of the following concepts:
More informationMathematical Models for Sulphate Reduction Processes
Industrial Electrical Engineering and Automation CODEN:LUTEDX/(TEIE-7262)/1-7/(2016) Mathematical Models for Sulphate Reduction Processes Kimberly Solon Division of Industrial Electrical Engineering and
More informationAcid-Base Titration Acetic Acid Content of Vinegar
Acid-Base Titration Acetic Acid Content of Vinegar Prelab Assignment Read the entire lab. Write an objective and any hazards associated with this lab in your laboratory notebook. On a separate sheet of
More informationQuestion 1.1: Calculate the molecular mass of the following: (i) H 2 O (ii) CO 2 (iii) CH 4 (i) H 2 O: The molecular mass of water, H 2 O = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen) = [2(1.0084)
More informationPENTAERYTHRITOL DERIVATIVES. L. W. TREVOY AND M. E. MYERS Research Department, Canadian Chemical Company, Limited, Edmonton, Alberta
PENTAERYTHRITOL DERIVATIVES I. MECHANISM OF FORMATION OF DIPENTAERYTHRITOL1 L. W. TREVOY AND M. E. MYERS Research Department, Canadian Chemical Company, Limited, Edmonton, Alberta Received October 30,
More information3. Atoms and Molecules. Mark (1) Mark (1) Mark (1) Mark (1) Mark (1) Mark (1) Marks (2)
3. Atoms and Molecules Q 1 144 grams of pure water is decomposed by passing electricity. 16 grams of hydrogen and 128 grams of oxygen are obtained. Which chemical law is illustrated by this statement?
More informationIdentification of ions and gases
For more awesome GSE and level resources, visit us at www.savemyexams.co.uk/ Identification Of ions nd Gases Question Paper Level Subject Exam oard Topic Sub-Topic ooklet O Level hemistry ambridge International
More informationCHEMICAL EQUILIBRIA. Section A Q1 The dissociation of dinitrogen tetraoxide into nitrogen dioxide is represented by the equation below.
Section A Q1 The dissociation of dinitrogen tetraoxide into nitrogen dioxide is represented by the equation below. If the temperature of an equilibrium mixture of the gases is increased at constant pressure,
More informationis considered acid 1, identify the other three terms as acid 2, base 1, and base 2 to indicate the conjugate acid-base pairs.
18.1 Introduction to Acids and Bases 1. Name the following compounds as acids: a. H2SO4 d. HClO4 b. H2SO3 e. HCN c. H2S 2. Which (if any) of the acids mentioned in item 1 are binary acids? 3. Write formulas
More informationChemistry Assessment Unit AS 2
Centre Number 71 Candidate Number ADVANCED SUBSIDIARY (AS) General Certificate of Education January 2011 Chemistry Assessment Unit AS 2 assessing Module 2: Organic, Physical and Inorganic Chemistry [AC121]
More informationCampbell Biology Canadian 1st Edition Reece TEST BANK
Campbell Biology Canadian 1st Edition Reece TEST BANK Full download at: https://testbankreal.com/download/campbell-biology-canadian-1stedition-reece-test-bank/ Campbell Biology, Cdn. Ed. (Reece et al.)
More informationSTUDIES IN THE PHYSIOLOGY OF LICHENS
STUDIES IN THE PHYSIOLOGY OF LICHENS V. TRANSLOCATION FROM THE ALGAL LAYER TO THE MEDULLA IN PELTIGERA POLYDACTYLA BY D. C. SMITH AND E. A. DREW Department of Agriculture, University of Oxford {Received
More informationIntermolecular Forces and Physical Properties
Intermolecular Forces and Physical Properties Attractive Forces Particles are attracted to each other by electrostatic forces. The strength of the attractive forces depends on the kind(s) of particles.
More informationLesson 01: Atomic Masses and Avogadro s Hypothesis. 01 Counting Atoms and Molecules
Chemistry 11, Mole Concept, Unit 04 1 Lesson 01: Atomic Masses and Avogadro s Hypothesis 01 Counting Atoms and Molecules The chemical changes we observe always involve a certain number of atoms that rearrange
More informationHigher Chemistry Principles to Production October Revision
igher Chemistry Principles to Production October Revision You should use your class notes, Evans2Chemweb and Scholar to help. Show your working for each question. Sections covered so far; Principles to
More informationICSE Chemistry Board Paper 2016
2015 Time: 2 hours; Max. Marks: 80 General Instructions: Answers to this Paper must be written on the paper provided separately. You will not be allowed 10 write during the first 15 minutes. This time
More informationCHEM J-9 June The equilibrium constant expressions for reactions (1) and (2) are given by:
CHEM1101 014-J-9 June 014 Use the following equilibria: CH 4 (g) C H 6 (g) + H (g) K 1 = 9.5 10 13 CH 4 (g) + H O(g) CH 3 OH(g) + H (g) K =.8 10 1 to calculate the equilibrium constant, K 3, for the following
More informationChapter 6. Types of Chemical Reactions and Solution Stoichiometry
Chapter 6 Types of Chemical Reactions and Solution Stoichiometry Chapter 6 Table of Contents (6.1) (6.2) (6.3) (6.4) (6.5) (6.6) (6.7) (6.8) Water, the common solvent The nature of aqueous solutions: Strong
More informationChemistry Midterm Review. Topics:
Chemistry Midterm Review Unit 1: laboratory equipment and safety rules accuracy vs precision scientific method: observation, hypothesis. experimental design: independent vs dependent variables, control
More information(Unit -9) Chemical Equilibrium
UNIT 9 Chemical Equilibrium INTRODUCTION: We owe our existence to equilibrium phenomenon taking place in atmosphere. We inhale oxygen and exhale carbon dioxide, while plants consume carbon dioxide and
More informationPhotosynthesis and Cellular Respiration Survey
Photosynthesis and Cellular Respiration Survey Multiple Choice - Choose the best and most complete answer. 1. Which type of energy transformation occurs in photosynthesis? A. heat to electrical B. light
More information2. An aldehyde can be obtained by the dehydrogenation of an alcohol. The catalyst used in the reaction is
Class: 12 Subject: Chemistry Topic: Organic Chemistry of O compounds No. of Questions: 20 Duration: 60 Min Maximum Marks: 60 1. Rectified spirit is converted to absolute alcohol taking advantage of the
More informationTECHNICAL SCIENCE DAS12703 ROZAINITA BT. ROSLEY PUSAT PENGAJIAN DIPLOMA UNVERSITI TUN HUSSEIN ONN MALAYSIA
TECHNICAL SCIENCE DAS12703 ROZAINITA BT. ROSLEY PUSAT PENGAJIAN DIPLOMA UNVERSITI TUN HUSSEIN ONN MALAYSIA ii TABLE OF CONTENTS TABLE OF CONTENTS... i LIST OF FIGURES... iii Chapter 1... 4 SOLUTIONS...
More informationSincerely, Ramesh Venukadasula. Summer Contact : Chem Sheets to Memorize. Solubility Exceptions
AP Chemistry 2014-2015 Summer Review Dutchtown High School Dear AP Chemistry Students, We are looking forward to the school year and the work we re going to do together. This packet is meant to refresh
More informationTOPIC 4: THE MOLE CONCEPTS
TOPIC 4: THE MOLE CONCEPTS INTRODUCTION The mass is gram (g) of 1 mole of substances is called its.. 1 mole of substances has.. particles of a substances The mass of 1 mole of substances is always equal
More informationHelp! I m Melting, wait...i m dissolving! Notes (Ch. 4)
Aqueous Solutions I. Most reactions happen. II. Aqueous means. III. A solution is a. IV. Dissolving occurs when water and/or. V. Electrolytes:. A. In solution, ionic compounds dissolve into. B. molecular
More informationدورةالعام 2015 العادية الثالثاء 16 حسيراى 2015
وزارة التربية والتعلين العالي الوديرية العاهة للتربية دائرة االهتحانات اهتحانات الشهادة الثانىية العاهة فرع العلىم العاهة هسابقة في هادة الكيوياء الودة: ساعتاى االسن: الرقن: دورةالعام 5 العادية الثالثاء
More informationChem II - Wed, 9/14/16
Chem II - Wed, 9/14/16 Do Now Drop off any study guides you want color coded Pull out stoich HW Homework See board Agenda Stoich Ch 4 Labish thing Chapter 4 Chemical Reactions & Solution Stoich Water Possesses
More informationIn the early version of the periodic table (by Newlands and then Mendeleev), how were the elements arranged?
Page 1 In the early version of the periodic table (by Newlands and then Mendeleev), how were the elements arranged? What can we say about the elements in the same group of the periodic table? Why is the
More informationStoichiometry Part 1
Stoichiometry Part 1 Formulae of simple compounds Formulae of simple compounds can be deduced from their ions/valencies but there are some that you should know off by heart. You will learn these and more
More information3.2.1 Energetics. Enthalpy Change. 263 minutes. 259 marks. Page 1 of 41
..1 Energetics Enthalpy Change 6 minutes 59 marks Page 1 of 41 Q1. (a) Define the term standard molar enthalpy of formation, ΔH f. (b) State Hess s law. (c) Propanone, CO, burns in oxygen as shown by the
More informationINTRO TO THE MOLE -PART 1
INTRO TO THE MOLE -PART 1 Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. 1. The law of definite proportions states that Specific substances
More informationInternational Advanced Level Chemistry Advanced Subsidiary Unit 2: Application of Core Principles of Chemistry
Write your name here Surname Other names Pearson Edexcel International Advanced Level Centre Number Candidate Number Chemistry Advanced Subsidiary Unit 2: Application of Core Principles of Chemistry Friday
More informationIGCSE (9-1) Edexcel - Chemistry
IGCSE (9-1) Edexcel - Chemistry Principles of Chemistry Chemical Formulae, Equations and Calculations NOTES 1.25: Write word equations and balanced chemical equations (including state symbols): For reactions
More informationWhich particle diagram represents molecules of only one compound in the gaseous phase?
Name: 1) Which species represents a chemical compound? 9114-1 - Page 1 NaHCO3 NH4 + Na N2 2) 3) 4) Which substance represents a compound? Co(s) O2(g) CO(g) C(s) Which terms are used to identify pure substances?
More informationUnit Two Worksheet WS DC U2
Unit Two Worksheet WS DC U2 Name Period Short Answer [Writing]. Write skeleton equations representing the following reactions and then balance them. Then identify the reaction type. Include all needed
More informationAP Chapter 3 Study Questions
Class: Date: AP Chapter 3 Study Questions True/False Indicate whether the statement is true or false. 1. The mass of a single atom of an element (in amu) is numerically EQUAL to the mass in grams of 1
More informationName:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks =
Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks = 1. Which salt is colorless? (A) KMn 4 (B) BaS 4 (C) Na 2 Cr 4 (D) CoCl 2 2. Which 0.10 M aqueous solution exhibits the lowest
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) When the following equation is balanced, the coefficients are. 1) NH3 (g) + O2 (g) NO2
More informationACP Chemistry (821) - Mid-Year Review
ACP Chemistry (821) - Mid-Year Review *Be sure you understand the concepts involved in each question. Do not simply memorize facts!* 1. What is chemistry? Chapter 1: Chemistry 2. What is the difference
More informationQuestions Q1. Given the following data: select the expression which gives the enthalpy change, in kj mol 1, for the reaction: ( 820 ½) = 140
Questions Q1. Given the following data: select the expression which gives the enthalpy change, in kj mol 1, for the reaction: A ( 820 ½) + 270 = 140 B (+820 ½) 270 = +140 C 820 + (270 2) = 280 D +820 (270
More informationICSE Board Class X Chemistry Board Paper Time: 1½ hrs Total Marks: 80
ICSE Board Class X Chemistry Board Paper 2011 Time: 1½ hrs Total Marks: 80 General Instructions: 1. Answers to this paper must be written on the paper provided separately. 2. You will NOT be allowed to
More informationEFFECT OF ph AND AMMONIUM IONS ON THE PERMEABILITY
EFFECT OF ph AND AMMONIUM IONS ON THE PERMEABILITY OF BACILLUS PASTEURII W. R. WILEY AND J. L. STOKES Department of Bacteriology and Public Health, Washington State University, Pullman, Washington ABSTRACT
More informationAlcohols, Phenols and Ethers
SUBJECTIVE PROBLEMS: Alcohols, Phenols and Ethers Q1. An organic liquid (A), containing C, H and O with boiling point: 78 o C, and possessing a rather pleasant odour, on heating with concentrated sulphuric
More information