1 8 =1 8 8 =1 6 =3. Unit cell Atoms at corner Atoms at faces Atoms at centre. Total no. of atoms per unit cell. bcc. fcc

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1 Q. No. Amorphous substances show () Short and long range order (2) Short range order (3) Long range order (4) Have no sharp M.P. Option and 3 are correct Option 2 2 and 3 are correct Option 3 3 and 4 are correct Option 4 2 and 4 are correct Explanation Amorphous solids ordered but short range they don't have m.p. Q. No. 2 Amorphous solids are Option Solid substance in real sense Option 2 Liquid in real sense Option 3 Super cooled liquid Option 4 Substance with definite melting point Explanation Super cooled liquids/ pseudo solids Q. No. 3 Crystalline solid are Option Glass Option 2 Rubber Option 3 Plastic Option 4 Sugar Explanation Crystalline solids are sugar Q. No. 4 A crystalline solid Option Changes abruptly from solid to liquid when heated Option 2 Has no definite melting point Option 3 Undergoes deformation of its geometry easily Option 4 Has an irregular 3-dimensional arrangements Explanation Crystalline solids changes abruptly from solid to liquid when heated. Q. No. 5 Which of the following is a molecular crystal Option SiC Option 2 NaCl Option 3 Graphite Option 4 Ice Explanation Molecular solid is a solid composed of molecules held together by the vander waals forces. e.g. ice.

2 Q. No. 6 Solid CO 2 is an example of Option Molecular crystal Option 2 Ionic crystal Option 3 Covalent crystal Option 4 Metallic crystal Explanation Molecular crystal Q. No. 7 In graphite, carbon atoms are joined together due to Option Ionic bonding Option 2 Vander Waal s forces Option 3 Metallic bonding Option 4 Covalent bonding Explanation Covalent bonding Q. No. 8 Mostly crystals show good cleavage because their atoms, ions or molecules are Option Weakly bonded together Option 2 Strongly bonded together Option 3 Spherically symmetrical Option 4 Arranged in planes Explanation Arranged in planes. Q. No. 9 The number of spheres contained (i) in one body centred cubic unit cell and (ii) in one face centred cubic unit cell, is Option In (i) 2 and in (ii) 4 Option 2 In (i) 3 and in (ii) 2 Option 3 In (i) 4 and in (ii) 2 Option 4 In (i) 2 and in (ii) 3 Explanation Unit cell Atoms at corner Atoms at faces Atoms at centre Total no. of atoms per unit cell bcc 8 = fcc 8 = 6 = Q. No. 0 The number of atoms or molecules contained in one body centered cubic unit cell is Option Option 2 2 Option 3 4 Option 4 6 Explanation 2

3 Q. No. If the number of atoms per unit in a crystal is 2, the structure of crystal is Option Octahedral Option 2 Body centred cubic Option 3 Face centred cubic Option 4 Simple cubic Explanation Unit cell Atoms at corner Atoms at faces Atoms at centre Total no. of atoms per unit cell Sc 8 = bcc 8 = fcc 8 = 8 6 = Q. No. 2 In fcc lattice, the neighbouring number of atoms for any lattice point is Option 6 Option 2 8 Option 3 2 Option 4 4 Explanation + r Coordination no. - of cation Str. Eg. r fcc NaCl, Kcl, Rbf, RbI, Agf, Agcl, AgBr, NH 4 Cl Q. No. 3 In a face centred cubic arrangement of A and B atoms when A atoms are at the corner of the unit cell and B atoms of the face centres. One of the A atom missing from one corner in unit cell. The simplest formula of compound is Option A 7 B 3 Option 2 AB 3 Option 3 A 7 B 24 Option 4 A 7/8 B 3 Explanation For f.c.c arrangement (A) (B) Atoms at corner (one A is missing) Atoms at force 7 7 = : 24 Simplest formula will be. A 7 B 24 6 =3 2

4 Q. No. 4 An alloy of Cu, Ag and Au is found to have copper constituting the ccp lattice. If silver atoms occupy the edge centre and gold is present at body centre, the alloy has a formula Option Cu 4 Ag 2 Au Option 2 Cu 4 Ag 2 Au Option 3 Cu 4 Ag 3 Au Option 4 CuAgAu Explanation Cu 4 Ag 3 Au Q. No. 5 Option Option 2 Option 3 Option 4 Sodium metal crystallizes as a body centred cubic lattice with the cell edge 4.29A o. what is the radius of sodium atom cm cm cm cm Explanation For bcc Atomic radius r = 3 = = cm, A =0 m 4 Q. No. 6 In a cubic structure of compound which is made from X and Y, where X atoms are at the corners of the cube and Y at the face centres of the cube. The molecular formula of the compound is Option X 2 Y Option 2 X 3 Y Option 3 XY 2 Option 4 XY 3 Explanation f.c.c arrangement Atoms at corner (x) Atoms at faces (y) 8 = 8 Molecular formula is xy 3 6 =3 2 Q. No. 7 A compound is formed by elements A and B. this crystallizes in the cubic structure when atoms A are the corners of the cube and atoms B are at the centre of the body. The simplest formula of the compounds is Option AB Option 2 AB 2 Option 3 A 2 b Option 4 AB 2 Explanation bcc arrangement

5 Atom at corner (A) Atom at faces Atoms at centre (B) Total 8 = Simplest formula is Q. No. 8 Potassiumhasabccstructurewithnearestneighbourdistance4.52A o Its atomic weight is 39. Its density will be Option 454 kg m -3 Option 2 804kg m -3 Option kg m -3 Option kgm -3 Explanation In bcc. Nearest neighbour distance 3 o o a= 4.52A a= = A = cm 3a Inbcc 3a=4r r= r= 2 =2.26A 3 o 4 Z.M 2 39 density= = =0.9 g/cm N a ( ) A Q. No. 9 The number of atoms in 00 g of an FCC crystal with density d = 0g cm -3 and cell edge as 200 pm is equal to Option Option Option Option Explanation Density = 0 g/cm 3-0 Cell edge =200pm=200 0 cm Z.M 4 M d= = N A (2 0 ) 0= 4 M M 40M = = M= =2g g= atoms g= 00=0.5 0 atoms 2 3

6 Q. No. 20 An element (atomic mass = 00 g/mol) having bcc structure has unit cell edge 400 pm. Then density of the element is Option g/cm 3 Option g/cm 3 Option g/cm 3 Option g/cm 3 Explanation Z.M density = = (400 0 ) 3 23 NA a = = =5.2g/cm Q. No. 2 A crystal plane makes intercepts 2a, 2b and 3c on the crystallographic axes where a, b, c represent the intercepts of the unit plane. The miller indices of the plane will be Option 223 Option Option Option Explanation 332 mins be Willer indices of the plane Q. No. 22 The unit cell of aluminum is a cube with an edge length of 405 pm. The density of aluminium is 2.70 g cm -3. What is the structure of unit cell of aluminium? Option Body-centred cubic cell Option 2 Face-centred cubic cell Option 3 End-centred cubic cell Option 4 Simple cubic cell Explanation Z.M density= 2.7= ( ) 3 23 N a A = = =2 2=4 fcc 00 Q. No. 23 How many lithium atoms are present in a unit cell with edge length 3.5A o and density 0.53 gcm -3?(Atomic mass of Li = 6.94) Option 2 Option 2 Option 3 4 Option 4 6 Explanation Let the no. of atoms in a unit cell be2.

7 Z.M Thendensity= N. 3 A a Z = (3.5 0 ) Z 0.53= = 2= = Q. No. 24 An element with atomic mass 00 has a bcc structure and edge length 400 pm. The density of element is Option 0.37 gcm -3 Option g cm -3 Option g cm -3 Option g cm -3 Explanation Z.M density= N. 3 A a 2 00 d = ( ) d = = =5.8g/cm Q. No. 25 A metal crystallises into a lattice containing a sequence of layer as AB AB AB..what percentage of voids are left in the lattice? Option 72 % Option 2 48 % Option 3 26 % Option 4 32 % Explanation Co-ordination no. = 2 Type of packing = hexagonal Spaceused=74 % Space left = =26 % Q. No. 26 The two dimensional coordination number of a molecule in square close packed layer is Option 4 Option 2 2 Option 3 3 Option 4 6

8 Explanation CN = 4 For two dimensional 5lr. Space occupied =52.4 % of available space. Q. No. 27 Which of the following statements is not true about the voids? Option Octahedral void is formed at the centre of six spheres which lie at the apices of a regular octahedron. Option 2 There is one octahedral sites for each sphere. Option 3 There are two tetrahedral site for each sphere. Option 4 Octahedral voids are formed when the triangular voids in second layer exactly overlap with similar voids in the first layer. Explanation Whenever a sphere of second layer is place a bone the void of first layer, a tetrahedral void is formed these voids are called tetrahedral voids 0 k a tetrahedral is formed when the centres of these four spheres are joined (T voids) The void a are double triangular voids, the triangular void in second layer are above the triangular voids in the first layer and the triangular spaces of these voids do not overlap. One of the m other downward. Such voids are surrounded by six spheres and are called octahedral void. So statement a is not true. Q. No. 28 In ABCABC packing if the number of atoms in the unit cell is n then number of tetrahedral voids in the cell is equal to Option n Option 2 n/2 Option 3 n/4 Option 4 2n Explanation No.of effective tetrahedral voids = 2 no. of effective atoms.

9 large cube is original fcc and smaller cube is an imaginary cube inside the large cube. There are 8 smaller cube in a bigger cube and each having one void. In fcc there are four atoms so the no. of effective tetrahedral void in a unit cell is double the no. of effective atoms in that unit cell. Q. No. 29 In ccp arrangement the pattern of successive layers can be designated as Option AB AB AB Option 2 ABC ABC ABC Option 3 AB ABC AB Option 4 ABA ABA ABA Explanation ABC ABC ABC Cubic close packing (ccp) = fcc

10 Q. No. 30 In which compound 4:4 coordination is found Option ZnS Option 2 CuCl Option 3 Agl Option 4 All of these Explanation Types of ionic solid Q. No. 3 The unit cell of a NaCl lattice Option Is body centred cube Option 2 Has 3Na + ions Option 3 Has 4NaCl units Option 4 Is electrically charged Explanation Cl occupy corners and face centres and Na + occupy octahedral voids in fcc crystal. Effective formula = Na 4 Cl 4 Co-ordination No. of Na + = 6 Co-ordination No. of Cl = 6 r - r - a Distance between nearest neighbours = Na + Cl = 2 Q. No. 32 In CsCl structure, the coordination number of Cs + is Option Equal to that of Cl -, that is 6 Option 2 Equal to that of Cl -, that is 8 Option 3 Not equal to that of Cl -, that is 6 Option 4 Not equal to that of Cl -, that is 8 Explanation Equal to that of Cl - that is 8 Q. No. 33 Which of the following statements is not true about NaCl structure Option Cl - ions are in fcc arrangement Option 2 Na + ions has coordination number 4 Option 3 Cl - ions has coordination number 6 Option 4 Each unit cell contains 4NaCl molecules Explanation Statement that Na + ions has co-ordination number 4. Is not true.

11 Q. No. 34 A solid A + B - has the B - ions arranged as below. If the A + ions occupy half of the octahedral sites in the structure. The formula of solid is Option AB Option 2 AB 2 Option 3 A 2 B Option 4 A 3 B 4 Explanation AB 2 Q. No. 35 For the structure of solid given below if the lattice points represent A + ions and B - ions occupy all the tetrahedral voids then coordination number of A is Option 2 Option 2 4 Option 3 6 Option 4 8 Explanation 8 Q. No. 36 In A + B - ionic compound, radii of A + and B - ions are 80 pm and 87 respectively. The crystal structure of this compound will be Option NaCl type Option 2 CsCl type Option 3 ZnS type Option 4 Similar to diamond Explanation r+ Limiting radian Ratios x = r CN Shape ex. -

12 x < Linear Bef < x < Planar triangular Alcl < x < Tetrahedron Zns 0.44 < x< octahedron NaCl 0.732< x< Body center cubic cscl Here in given statement. r + /r - = = cscl type Q. No. 37 rc If the value of ionic radius ratio is 0.52 in an ionic compound, the geometrical ra arrangement of ions in crystal is Option Tetrahedral Option 2 Planar Option 3 Octahedral Option 4 pyramidal Explanation Octahedral Q. No. 38 The maximum radius of sphere that can be fitted in the tetrahedral hole of cubical closed packing of sphere of radius r is. Option 0.732r Option r Option r Option r Explanation 0.44r Q. No. 39 r + Na in NaCl lattice the radius ratio is = r - Cl Option Option Option Option Explanation Pauling s rule explains (first rules) rna + = rcl Q. No. 40 For an ionic crystal of the general formula AX and coordination number 6, the value of radio will be Option Greater than 0.73 Option 2 In between 0.73 and 0.4 Option 3 In between 0.4 and 0.22 Option 4 Less than 0.22 Explanation In between 73 and 4

13 Q. No. 4 A unit cell of sodium chloride has four formula units. The edge length of unit cell is nm. What is the density of sodium chloride? Option 3.89g cm -3 Option 2 2.6g cm -3 Option 3 3g cm -3 Option 4.82 g cm -3 Explanation M 2 density= a 3 N a = 564 nm z = 4 23 N A = M =58 = 2.6 g cm -3 A Q. No. 42 Which defect causes decrease in the density of crystal Option Frenkel Option 2 Schottky Option 3 Interstitial Option 4 F-centre Explanation (equal No. of C +, C - are missing) = Schottky defect causes in density of crystal. Q. No. 43 In a solid lattice the cation has left a lattice site and is located at an interstitial position, the lattice defect is Option Interstitial defect Option 2 Valency defect Option 3 Frenkel defect Option 4 Schottky defect Explanation Frenkel defect

14 Q. No. 44 The correct statements regarding F-centre is Option Electron are held in the voids of crystals Option 2 F-centre produces colour to the crystals Option 3 Conductivity of the crystal increases due to F-centre Option 4 All of these Explanation For benzenter meaning colour The anion may be missing from its lattice site leaving e - s behind so that charge remains balanced conductivity e s Q. No. 45 Schottky defect in crystals is observed when Option Density of crystal is increased Option 2 Unequal number of cations and anions are missing from the lattice Option 3 An ion leaves its normal site and occupies an interstitial site Option 4 Equal number of cations and anions are missing from the lattice Explanation Equal no. of cations and anions are missing from the lattice. Q. No. 46 If a electron is present in place of anion in a crystal lattice, then it is called Option Frenkel defect Option 2 Schottky defect Option 3 Interstitial defect Option 4 F-centre Explanation F-centre Q. No. 47 Schottky defect in crytals is observed when Option An ion leaves its normal site and occupies an interstitials site Option 2 Few cations are missing from the crystal Option 3 Equal number of cations and anions are missing from the crystal Option 4 Few anions are missing from the crystal. Explanation Equal no. of cation and anion are missing Q. No. 48 What is the effect of frenkel defect on the density of ionic solids? Option The density of the crystal increases. Option 2 The density of the crystal decreases. Option 3 The density of the crystal remains unchanged. Option 4 There is no relationship between density of a crystal and defect present in it. Explanation Density remains unchanged (2+ dislocation of ion) Q. No. 49 Alkali halides do not show frenkel defect because Option Cations and anions have almost equal size Option 2 There is a large difference in size of cations and anions. Option 3 Cations and anions have low coordination number Option 4 Anions cannot be accommodated in voids. Explanation Cation and anion have almost equal size. -

15 Q. No. 50 Zinc oxide loses oxygen on heating according to the reaction, ZnO Zn + O +2e 2 It becomes yellow on heating because Option Zn 2+ ions and electrons move to interstitial sites and F-centres are created Option 2 Oxygen and electrons move out of the crystal and ions become yellow Option 3 Zn 2+ again combine with oxygen to give yellow oxide Option 4 Zn 2+ are replaced by oxygen Explanation Zn 2+ ions and electrons move to interstitial sites and F-centres are created heat Q. No. 5 In a schottyky defect, Option An ion moves to interstitial position between the lattice points Option 2 Electrons are trapped in a lattice site Option 3 Some lattice sites are vacant Option 4 Some extra cations are present in interstitial spaces. Explanation Some lattice site are vacant. Q. No. 52 Which substance shows antiferromagatism? Option ZrO 2 Option 2 CdO Option 3 CrO 2 Option 4 Mn 2 O 3 Explanation Antiferromagatism arisen when net dipole alignment is zero due to equal and opposite alignment eg. Mn 2 O 3 CrO ferromagnetism 2 Q. No. 53 The electricity produced on applying stress on the crystals is called Option Pyroelectricity Option 2 Piezoelectricity Option 3 Ferroelectricity Option 4 Anti-ferroelectricity Explanation Pizz electricity when Megnatic property description allingment meg. Eg. Dipole Pizz electricity When polar crystal is subjected to mechanical site is - electricity is produced pizz electric crystal with permanent dipoles are said BaTi O 3 to have ferro electricity than with zero are said to have antiferroelectricity Pbzro 3 Pyrolelectricity Small electric current is produced due to heating of some of polar-crystalpyroelectricity

16 Q. No. 54 Crystals where dipoles may align themselves in an ordered manner so that there is a net dipole moment, exhibit Option Pyro-electricity Option 2 Piezo-electricity Option 3 Ferro-electricity Option 4 Antiferro-electricity Explanation Pizz electricity when Megnatic property description allingment meg. Eg. Dipole Pizz electricity When polar crystal is subjected to mechanical site is - electricity is produced pizz electric crystal with permanent dipoles are said BaTi O 3 to have ferro electricity than with zero are said to have antiferroelectricity Pbzro 3 Pyrolelectricity Small electric current is produced due to heating of some of polar-crystalpyroelectricity Q. No. 55 On heating some polar crystals, weak electric current is produced. It is termed as: Option Piezoelectricity Option 2 Pyroelectricity Option 3 Photoelectric current Option 4 superconductivity Explanation Pizz electricity when Megnatic property description allingment meg. Dipole Eg. Pizz electricity When polar crystal is subjected to mechanical site is - electricity is produced pizz electric crystal with permanent dipoles are said BaTi O 3 to have ferro electricity than with zero are said to have antiferroelectricity Pbzro 3 Pyrolelectricity Small electric current is produced due to heating of some of polar-crystalpyroelectricity

17 Q. No. 56 Which one among the following is an example of ferroelectric substance? Option Quartz Option 2 Lead chromate Option 3 Barium titanate Option 4 Rochelle salt. Explanation Pizz electricity when Megnatic property description allingment meg. Eg. Dipole Pizz electricity When polar crystal is subjected to mechanical site is - electricity is produced pizz electric crystal with permanent dipoles are said BaTi O 3 to have ferro electricity than with zero are said to have antiferroelectricity Pbzro 3 Pyrolelectricity Small electric current is produced due to heating of some of polar-crystalpyroelectricity Q. No. 57 The substance which possesses zero resistance at OK is called Option Conductor Option 2 Superconductor Option 3 Insulator Option 4 Semiconductor. Explanation 3-23 a = a=407 0 a = 407 pm Q. No. 58 Which substance acts as superconductor at 4 K? Option Hg Option 2 Cu Option 3 Na Option 4 Mg Explanation 2 r= = pm -0 2 For r= a 4 a = edge length

18 Q. No. 59 A solid with high electrical and thermal conductivity from the following is Option Si Option 2 Li Option 3 NaCl Option 4 Ice Explanation No. of O void = No. of effective atoms No. of T void = 2 No. of effective atom For hccp no. of effective atoms = 6 So, the diff between T void - O = = 6 Q. No. 60 Pure silicon and germanium behave as Option Conductors Option 2 Semiconductors Option 3 Insulators Option 4 Piezoelectric crystals. Explanation Let effective no. of atoms be x tetrahedral voids = 2x 2 4x 2/3 of tetrahedral void =2 = 3 3 Byx FormulawillbeA A 3x B yx 3 Total no. of A and B will be = 7

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