NATIONAL SENIOR CERTIFICATE GRADE 11

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1 NATIONAL SENIOR CERTIFICATE GRADE 11 PHYSICAL SCIENCES: PHYSICS (P1) NOVEMBER MEMORANDUM MARKS: 150 This memorandum consists of 12 pages.

2 Physical Science P1/Memo 2 LimpopoDoE/November QUESTION 1 / VRAAG C 1.2 A 1.3 A 1.4. C 1.5 C 1.6 B 1.7 D 1.8 B 1.9 B 1.10 B [20]

3 Physical Science P1/Memo 3 LimpopoDoE/November QUESTION 2/ VRAAG a single force with the same effects as two or more other forces. n enkelle krag wat dieselfde uitwerking het as twee of meer kragte tesame 2.2 Option 1 Take west as positive/wes as + R = F 1 + F 2 + F 3 (+10) = (+45) + (-60) + F 3 = +25N F 3 Option 2 Take east as positive/ Oos as + R = F 1 + F 2 + F 3 (-10) = (-45) + (+60) + F 3 = - 25N F Marking criteria 1 mark for vectors drawn with arrows. 1 mark for correct directions of the vectors 1 mark for labelling the vectors OR/OF An alternative vector diagram 2.4 With the resultant being 10N and westwards, Die resultant is 10N weswaarts: The object move westwards /die voorwerp beweeg weswaarts The object move with acceleration / die voorwerp versnel

4 Physical Science P1/Memo 4 LimpopoDoE/November [11] QUESTION Static friction is the force that opposes the tendency of motion of a stationary object relative to a surface. / Statiese wrywingskrag is die wrywingskrag van een kontakoppervlakte op n ander wanneer daar geen relatiewe beweging tussen die voorwerpe is nie. 3.2 N f s N f s OR W W // W Marking Criteria One mark : correct force with correct direction and its label (for each force) and (one mark for components of weight). No mark if an indicated force is not labeled. 3.3 w// = w sin Ɵ or w// = m g sin Ɵ w// = (25 )(9.8)sin 22 o w// = 91.78N 3.4 tan = μ tan = 0.5 = o 3.5 f s(max) = μw or f s(max) = μmgcos f s(max) = (0.5 ) (25 ) (9.8) Cos o f s(max) = N [16] QUESTION 4/VRAAG When a net force is applied to an object of mass m, it accelerates in the direction of the force. The acceleration is directly proportional to the magnitude of the force and is inversely proportional to the mass of the object. / Indien n netto krag uitgeoefen word op n liggaam met massa

5 Physical Science P1/Memo 5 LimpopoDoE/November m, sal die voorwerp versnel in die rigting van die krag. Die versnelling is direk eweredig aan die grootte van die krag en omgekeerd eweredig aan die massa van die voorwerp. 2 kg block/blok 4 kg block/blok 4.2 T T w w 4.3 Consider the mass m 1, the 2 kg-block/beskou massa m 1, die 2 kg blok: F net = ma T w = m 1 a T (9.8) = a T 19.6 = 2a. (1) Consider the mass m 2, the 4 kg-block/ Beskou massa m 2, die 4 kg blok: w -T = m 1 a (9.8) - T = a 39,2 - T = 4a.. (5) Adding (1) and :/ Tel (1) en bymekaar: = 6a 6a = 19.6 a = 3, From/Van (1): T 19.6 = 2a T 19.6 = 2(3.27 ) T = T = N [14] QUESTION 5/ VRAAG Every object in the universe exerts a gravitational attraction force on all other objects. The attractive force is directly proportional to the product of their masses and is inversely proportional to the square of the distance between their centres. Tussen enige twee voorwerpe in die heelal bestaan daar n gravitasieaantrekkingskrag. Hierdie aantrekkingskrag is direk eweredig aan die produk van die massas van die voorwerpe en omgekeerd eweredig aan die kwadraat van die afstand tussen die massamiddelpunte van die twee voorwerpe. 5.2

6 Physical Science P1/Memo 6 LimpopoDoE/November F = 3.2 x 10-5 N 5.3 The force is the same/ die krag is dieselfde OR/OF A exerts to B the same force as B exerts to A / A oefen op B dieselfde grootte krag uit as wat B op A uitoefen. 5.4 Force = 6.4 x 10-5 N [10] QUESTION 6 /VRAAG Refraction is the change of the path of light ray when it moves from one optical medium to another optical medium. / Breking is die verandering in die pad van n ligstraal indien dit van een optiese medium na n ander optiese medium beweeg. 6.2 i = 59 o (1) 6.3 r = 35 o (1) 6.4 n 1 Sin 1 = n 2 Sin 2 (1) Sin59 o = n 2 Sin35 o 6.5

7 Physical Science P1/Memo 7 LimpopoDoE/November Normaal Uitvalstraal Marking Criteria 1 mark of the for emergent ray 1 mark each for labelling emergent ray and normal 1 mark for both angle of incidence and refraction 6.6 Smaller. / kleiner QUESTION 7/ VRAAG The ability of waves to spread out in wave fronts as they pass through a small opening or around a sharp edge. / Die vermoë van n golf om uit te sprei in golffronte wanneer dit om n skerp kant of deur n klein opening beweeg [14] 7.2 Diffraction grating / skerm met spleet (1) 7.3 A wide central blue band will be formed on the screen/ n wye sentrale band word op die skerm gevorm There will be darker band next to it (on its sides) / daar vorm donker bande weerskante The darker bands will be followed by smaller bright(blue) bands, and so on/ die donker bande word gevolg deur helder (blou) bande en die patroon herhaal 7.5 Red has longer wave-length than blue/ Rooi lig het n langer golflengte as blou lig It undergoes more diffraction than blue/ Dit ondergaan meer diffraksie as blou lig It gives a wider central band / Dit gee n wyer sentrale band [16]

8 Physical Science P1/Memo 8 LimpopoDoE/November QUESTION The magnitude of the electrostatic force exerted by two point charges (Q 1 and Q 2 ) on each other is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. / Die elektrostatiese krag tussen twee puntladings (Q 1 and Q 2 ) is direk eweredig aan die produk van die ladings en omgekeerd eweredig aan die kwadraat van die afstand tussen die ladings 8.2 P Q Marking Criteria / Nasien kriteria 1 mark for lines not touching each other and correct form./ lyne raak nie en vorm korrek(1) 1 mark for correct arrows / pyle korrek (1) 8.3

9 Physical Science P1/Memo 9 LimpopoDoE/November 1.8 x N attraction / aantrekkend. 8.4 F P on R = = = 4,8 x 10-6 N left/links F Q on R = = = 2,4 x 10-6 N left/links F R = F P on R + F Q on R = 7,2 x 10-6 Left/links (5) (7) 8.5 Q = Q = -1.5 x 10-9 C [12] QUESTION 9/ VRAAG Faraday s Law / Faraday se wet (1) 9.2 An EMF is induced in a conductor when the magnetic fields that surround it changes. The magnitude of the induced EMF across the conductor is directly proportional to the rate of change in the magnetic flux linkage with the conductor. / wanneer n geleier en magneetveld relatief tot mekaar beweeg, word n EMK oor die ente van die geleier geïnduseer. Die geïnduseerde EMK in die geleier is direk eweredig aan die tempo waarteen die magnetiese vloed in die geleier verander. 9.3 Galvanometer (1) speed (of movement of a bar magnet)/ spoed waarteen die magnet beweeg Induced electric current (or induced EMF)/ geïnduseerde elektriese stroom (of potensiaalverskil) 9.5 Does the amount of the induced electric current (or induced EMF) change as the speed of bar magnet moving relative to the solenoid changes? / Wat is die verwantskap tussen die spoed waarteen die magneet beweeg en die geïnduseerde stroom (of EMK) 9.6 When the speed of bar magnet relative to the solenoid increases, the amount of induced electric current (or induced EMF) increases./ indien die spoed van die magneet relatief tot die soleniëd verhoog, verhoog die

10 Physical Science P1/Memo 10 LimpopoDoE/November geïnduseerde stroom (of EMK) 9.7 Strength of magnet / sterkte van die magneet and / en Number of turns of the solenoid / aantal windings op die solenoïed 9.8 Induced current against speed of magnet /Geïnduseerde stroom teenspoed van magneet In d u c e d c ur Speed of magnet ( Marking Criteria 1 mark for the heading / 1 punt vir opskrif 1 mark for correct graph shape/ 1 punt vir korrekte vorm 1 mark for correct label on both x-axis and y-axis / 1 punt vir korrekte benoeming van asse 9.9 Marking Criteria 1 Mark = indicating magnetic field lines in concentric cycles/ veldlyne in konsentriese sirkels 1 Mark = indicating arrows in correct Direction / rigting van pyle korrek [17]

Physical Science P1/Memo 11 LimpopoDoE/November QUESTION 10 10.1 The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature.

3 It has high resistance which can completely stop the flow of current / Dit het n hoë weerstand en laat geen stroom deur nie (1) 10.

11 Physical Science P1/Memo 11 LimpopoDoE/November QUESTION The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature. / Die potensiaalverskil oor n geleier is direk eweredig aan die stroom deur die geleier mits die temperatuur constant bly 10.2 V =(6 2) = 4 V 10.3 It has high resistance which can completely stop the flow of current / Dit het n hoë weerstand en laat geen stroom deur nie (1) 10.4 Resistance in top branch R = R 1 + R 2 = = 20 Ω Current in A 2 = (0,5 0,2 ) = 0,3 A (6) P = VI P = (2 x 0.5) P = 1W 10.7 Voltmeterreading will deacrease. The resistance in the circuit increases and the current decrease. Because R 1 stay the same, the voltmeterreading will deacrease according to V=IR. / Die voltmeterlesing sal afneem. Omdat die weerstand in die stroombaan toeneem sal die stroomsterkte afneem omdat R 1 konstant bly sal die voltmeterlesing afneem volgens V = IR.. [20] TOTAL / TOTAAL: 150

MEMORANDUM PHYSICAL SCIENCE/FISIESE WETENSKAPPE SEPTEMBER 2018 CW PLC COMMON PAPER 1 QUESTION A (2) 1.2 A (2) 1.3 C (2) 1.4 D (2) 1.

1 MEMORANDUM PHYSICAL SCIENCE/FISIESE WETENSKAPPE SEPTEMBER 2018 CW PLC COMMON PAPER 1 QUESTION 1 1.1 A 1.2 A 1.3 C 1.4 D 1.5 D 1.6 A 1.7 B 1.8 B 1.9 D 1.10 D [20] 2 QUESTION 2 21. 2.1.1 When a resultant/net