Lesson-5 PROPERTIES AND SOLUTIONS OF TRIANGLES

Size: px
Start display at page:

Download "Lesson-5 PROPERTIES AND SOLUTIONS OF TRIANGLES"

Transcription

1 Leon-5 PROPERTIES ND SOLUTIONS OF TRINGLES Reltion etween the ide nd trigonometri rtio of the ngle of tringle In ny tringle, the ide, oppoite to the ngle, i denoted y ; the ide nd, oppoite to the ngle nd repetively, re denoted y nd. Formule involving ide nd ngle of tringle. Sine Rule : In ny tringle, R in in in where R i the rdiu of the irumirle of the tringle. R i known irumrdiu of the tringle.. oine Rule : In ny tringle, o o o or o + 0 or o + 0 or o + 0. Hlf -ngle Formule in in in where i the emiperimeter of tringle i.e. o, o, o tn, tn, tn

2 . Projetion Rule : In ny tringle, o + o o + o o + o 5. Npier nlogy : In ny tringle, tn ot tn ot tn ot 6. re of tringle : The re of tringle i given y in in in R r Hero formul where r rdiu of inirle of tringle inrdiu of tringle irumirle, Inirle nd Ex-irle of Tringle The irle whih pe through the ngulr point vertie of tringle i lled it irumirle. It rdiu i denoted y R R in in in O lo, R

3 Inirle : The irle whih n e inried within the tringle o to touh eh of the ide i lled it inried irle or inirle. It rdiu i denoted y r. r i lled inrdiu of tringle. r tn tn tn F E lo, r R in in in r D Eried irle : The irle whih touhe the ide nd the two ide nd produed of tringle i lled it eried irle, oppoite the ngle. It rdiu i denoted y r. Similrly r denote the rdiu of the irle whih touhe the ide nd the two ide nd produed. lo r denote the rdiu of the irle touhing ide nd the two ide nd produed. r tn R in o o r tn R o in o r r tn R o o in l r + r + r r + R r r + r r + r r S r r r rs r R Equlity hold for only n equilterl tringle. in in in 8. Equlity hold for only n equilterl tringle. Ptolemy Theorem If D i yli qudrilterl, then.d.d +.D

4 SOLVED EXMPLES Ex.: Prove tht o in. Sol.: in in in, [uing ine Rule] in o in o o o in o, [ + + ] o in + in o. Ex.: In ny tringle prove tht, ot + ot + ot 0. Sol.: in R in in ot + ot + ot R o o o R.. [ + + R ]. 0

5 Ex.: In tringle, prove tht, ot + ot + ot. Sol.: L.H.S. ot + ot + ot R.H.S. Ex.: In ny tringle, prove tht, + o + + o + + o + +. Sol.: L.H.S. + o + + o + + o o + o + o + o + o + o, o + o + o + o + o + o + + R.H.S. [y uing projetion Rule] Ex.5: If p, p, p re the ltitude of the tringle, prove tht, R p p p o o o. Sol.: In the tringle, let N p M p Q p Q M N Then, re of tringle p p p or p, p, p o o o o o o p p p, o in o in o in R R R [uing ine rule]

6 R in in in R in o in o R in o o [uing + + ] R in in in R in in in R. R R. R [uing ine rule] R R R R [y uing R ] Ex.6: In ny, if, nd 60º, olve the tringle. Sol.: Two ide nd inluded ngle i given tn ot ot 0º tn 60º tn 5º tn 60º tn 5º 5º tn 60º 5º tn 5º or 0º...i We know, º + 0º...ii Solving i nd ii, we get 75º & 5º To find ide, we ue ine Rule in in 60º

7 or 6 Thu 5º, 75º nd 6. Ex.7: If 0º, 00, 00, olve the tringle. Sol.: in in in ; 5 or ; 5 5 ; in in in in Ex.8: Let O e point inide tringle uh tht O O O. Show tht ot ot + ot + ot. Sol.: O nd O pplying the ine Rule in tringle O, we hve in O in - O in in pplying the ine Rule in tringle O, we hve O in in...i - O - O in in...ii From i nd ii, we hve in in in in Uing Sine Rule we hve R in in in in in in R in in in in in in in in in ot ot ot + ot ot ot or ot ot + ot + ot.

8 Ex.9: If the ide of tringle re in.p nd if it gretet ngle exeed the let ngle y, how tht the ide re in the rtio x : : + x where x Sol.: Let the ide e d,, + d : d > 0 Let e the let ngle nd e the gretet ngle. Let ; then + nd 80º o 7 o. d in d in in[ ] d or in d in in From firt nd eond term we get in in...i d in d in d in or d in y ompenendo nd dividendo, we hve + d d d in in in in in o o in or d tn tn tn d tn...ii From third nd fourth term of i we get in in in o o o o Note: 0 < < o > 0 ; i ute tn o o...iii

9 From ii nd iii we get d in o d in o o o o 7 o x Required Rtio d : : + d d/ : : + d/ x : : + x. Ex.0: In tringle, the medin D nd the perpendiulr E from the vertex to the ide divide ngle into three equl prt. Show tht o in. Sol.: D DE E D D DE E D In D o [Sine tringle DE nd tringle E re ongruent] 8...i In tringle, we hve o o o...ii D E

10 Sutrting ii from i we get o o o 8 o o 8 o in. Ex.: Sol.: If, nd re the ditne of the vertie of tringle from neret point of ontt of the inirle with ide of, prove tht r Given. F E F D D E F E Perimeter of tringle I D + + v re of tringle r r Ex.: In ny tringle, if o etween 0 nd, prove tht tn tn tn tn tn tn. where,, lie Sol.: o tn tn

11 y omponendo nd dividendo tn tn Similrly, tn nd tn tn tn tn tn tn tn...i Now tn tn tn From i nd ii...ii tn tn tn tn tn tn. Ex.: The ietor of ngle of tringle meet t D. If D l then, prove tht i l o ii l Sol.: i re of tringle re of tringle D + re of tringle D in l in l in o l + l o ii D D D

12 or D D In tringle D, D o D D l D l... l o + + l D Sutituting vlue of o from i we get D l l + + l D Eqution give l l or or l. Ex.: yli qudrilterl D of re nd i ute nd the digonl D i inried in unit irle. If one of it ide find the length of the other ide. Sol.: Given, D In tringle D, O O OD O R O eing entre of the irle D in R in Given irle i irumirle of D Hene Uing oine Rule in tringle D D i yli qudrilterl o D D. D D D or D D 0

13 or D D + 0 D Uing oine Rule in tringle D, we hve o D D. D D. D or + D + D 0...i re of yli qudrilterl re of tringle D + re of tringle D +.D.. in.. D in or.d...ii Solving i nd ii, we get D Hene length of ide of yli qudrilterl re D, D.

14 OJETIVE SSIGNMENT hooe the orret option in the following :. If,, 5, then the vlue of in i. If 5 o o o 5, then the tringle i d none of thee right ngled ioele otue ngled d equilterl. If,, 60º then i the root of the eqution d o + o + o d 5. In tringle, if, then tn i equl to d 6. If the ide of tringle re : 7 : 8 then R : r : 7 7 : : 7 d 7 : 7. In, R r o o o re of tringle d re of tringle 8. If p, p, p re repetively the perpendiulr from the vertie of tringle to the oppoite ide, then p p p 8 R 8R 8 R d none of thee 9. If, nd, then the numer of tringle tht n e ontruted i Infinite Two One d Nil 0. If one ide of tringle i twie the other ide nd the ngle oppoite to thee ide differ y 60º, then the tringle i Equilterl Ioele Right ngled d none of thee. If in tringle, o o o then the vlue of the ngle i 90º 60º 0º d none of thee

15 . In tringle, the length of the two lrger ide re 0 nd 9 repetively. If the ngle re in.p, then the length of the third ide n e d 5 6. In right-ngled tringle the hypotenue i four time long the ditne of the hypotenue from the oppoite vertex. It ute ngle re 0º, 60º 5º, 75º 5º, 5º d none of thee. irle i inried in n equilterl tringle of ide 6. The re of ny qure inried in the irle i d none of thee 5. If in tringle,, then ot.tn / / d none of thee 6. If in tringle, the exrdii r, r, r re uh tht r r r then : : i 5 : : : 5 : : 5 d none of thee 7. If tringle i right ngled t then the dimeter of the inried irle of the tringle i d none of thee 8. In tringle, tn nd tn /. If 65 then the irumrdiu of the tringle i 65 / 7 65/ 65 d none of thee 9. If the medin D of tringle mke n ngle with, then in i equl to in in in d none of thee 0. If the ietor of ngle of tringle mke n ngle with, then in i equl to o in in. The expreion i equl to d none of thee o in o o o d none of thee. In tringle, point D nd E re tken on ide uh tht D DE E. If DE ED, then tn tn tn tn + 6 tn 6 tn tn d 9 ot tn 0

16 . If the ngle, nd of tringle re in.p. nd the ide,, oppoite thee ngle re in G.P., then, nd re in G.P..P. H.P. d none of thee. The length of the ide of the tringle tify, , then tringle i Right ngled Ioele Equilterl d none of thee 5. If the ngle,, of re in.p., then d none of thee 6. The rtio of the ditne of the orthoentre of n ute-ngled from the ide, nd i o : o : o e : e : e in : in : in d none of thee 7. In, I i the inentre. The rtio I : I : I i equl to o e : o e : oe in : in : in e : e :e d none of thee 8. If,, re the ltitude of nd ; denote it perimeter then + + i equl to. d none of thee 9. In D, the ide re in the rtio : 5 : 6. The rtio of the iumrdiu nd the inrdiu i 8 : 7 : 7 : d 6 : 7 0. In n equilterl tringle, irumrdiu : inrdiu : exrdiu i equl to : : : : : : d : : MORE THN ONE ORRET NSWERS. If in, 6, nd o then 5 in r 9 d none of thee 5. The numer of poile tringle in whih m, m nd 60 i 0 d none of thee

17 . In, nd : :. If tn, 0, then d 60. In tringle the oine of two ngle re inverely proportionl to the ide oppoite the ngle. The tringle i ioele equilterl right ngled d none of thee 5. In D, the line igement D, E nd F re three ltitude. If R i the irumrdiu of the D, ide of the DDEF will e R in o in d o 6. In, tn nd tn re the root of the eqution x + x, where, nd re the ide of the tringle. Then tn ot 0 in + in d none of thee 7. The ditne of the irumentre of the ute-ngled from the ide, nd re in the rtio in : in : in o : o : o ot : ot : ot d none of thee 8. In ny, in i equl to in in o o 0 d none of the 9. In, o. Then,, re in P d + 0. In, tn < 0. Then tn. tn < tn. tn > tn +tn + tn < 0 d tn + tn + tn > 0

18 omprehenion-i MISELLNEOUS SSIGNMENT In tringle, the um of two ide i x nd their produt i y uh tht x + zx z y where z i the third ide of the tringle.. Gretet ngle of the tringle i d 5. Squre of the length of the third ide of the tringle i x + y x y x + y d x y. re of the tringle i y x x y /y 8 /x d x z. Inrdiu of the tringle i x z y y x z x y d z y omprehenion-ii If in tringle with re, r r r ; D i the mid-point of, D. DL i perpendiulr to, re of the tringle LD i. 5. in i equl to d 5 6. DL i equl to d D 7. i equl to d 8 Mth the following 8. In tringle. o + o p R + r. o + o + o q r. ot + ot + ot r R in in in D. R in / in / in /

19 9.. If,, e the length of medin of tringle p then + + i equl to. Let the point P liein the interior of n equilterl q tringle of ide length nd it ditne from the ide, nd re repetively x, y nd z then x + y + z i equl to. In tringle,,, re in P nd,, re in q / GP, then i equl to D. In tringle,, the let vlue of i INTEGER TYPE QUESTIONS 0. In the vlue of R i. In the vlue of. In the vlue of r r r r i r r r r r r i. In the vlue of. In the vlue of 5. In the vlue of r r r r R Rin i o i i 6. In if S repreent the re then in / o / S i 7. In r r R i 8. In if,, 5, then r r r 9. In ny if, 60, then I I i i

20 PREVIOUS YER QUESTIONS IIT-JEE/JEE-DVNE QUESTIONS.,, re the ide of uh tht no two ide re equl nd x x if x i rel then rnge for R i 7, d 7,. In,,, re the length of it ide nd,, re the ngle of tringle. The orret reltion i given y in o o in + in o d o in. mn from the top of 00 metre high tower ee r moving towrd the tower t n ngle of depreion of 0. fter ome time, the ngle of depreion eome 60. The ditne in metre trvelled y the r during thi time i d 00. pole tnd inide tringulr prk. If the ngle of elevtion of the top of the pole from eh orner of the prk i me, then in the foot of the pole i t the entroid irum entre inentre d other entre 5. The minimum vlue of the expreion in + in + in, where,, re rel poitive ngle tifying + + i poitive zero negtive d 6. If the vertie P, Q, R of tringle PQR re rtionl point, whih of the following point of the tringle PQR i re lwy rtionl point? entroid inentre irumentre d orthoentre in D 7. In tringle,, nd D divide internlly in the rtio :, then in D 6 d 8. Whih of the following piee of dt doe not uniquely determine n ute ngle tringle

21 R eing the rdiu of the irumirle?, in, in,,, in, R d, in, R 9. In tringle, D i the ltitude from. Given >, nd D then, d none of thee 0. In tringle, in d. Let 0 5 e regulr hexgon inried in irle of unit rdiu. The produt of the length of the line egment 0, 0 nd 0 i d. In tringle, if, 0, then the tringle i right ngled ioele otue ngled d none of thee. In tringle, the length of the two lrger ide re 0 nd 9 repetively. If the ngle re in.p., then the length of the third ide n e d In tringle if then ngle i equl to d 5 5. The ide of tringle re in the rtio : :, then the ngle of the tringle re in the rtio : : 5 : : : : d : : 6. In n equilterl tringle, oin of rdii unit eh re kept o tht they touh eh other nd lo the ide of the tringle. re of the tringle i d If i ioele tringle nd one of ngle i 0º nd the rdiu of it inirle i of length then

22 the re of i d 7 8. Internl ietor of of tringle meet ide t D. line drwn through D perpendiulr to D interet the ide t E nd the ide t F. If,, repreent ide of E i HM of nd D o EF in d the tringle EF i ioele then 9. In tringle with fixed e, the vertex move uh tht o o in. If, nd denote the length of the ide of the tringle oppoite to the ngle, nd, repetively, then + + lou of point i n ellipe d lou of point i pir of tright line 0. tright line through the vertex P of tringle PQR interet the ide QR t the point S nd the irumirle of the tringle PQR t the point T. If S i not the entre of the irumirle, then PS ST QS SR PS ST QS SR PS ST QR d PS ST QR. In tringle with fixed e, the vertex move uh tht If, o o in. nd denote the length of the ide of the tringle oppoite to the ngle, nd, repetively, then + + lou of point i n ellipe d lou of point i pir of tright line. If the ngle, nd of tringle re in n rithmeti progreion nd if, nd denote the length of the ide oppoite to, nd repetively, then the vlue of the expreion in in i. Let PQR e tringle of re with 7, nd d 5, where, nd re the length of the

23 in P in P ide of the tringle oppoite to the ngle t P, Q nd R repetively. Then in P in P 5 d 5 equl. In tringle the um of two ide i x nd the produt of the me two ide i y. If x y, where i the third ide of the tringle, then the rtio of the in-rdiu to the irum-rdiu of the tringle i y y y y x x x x x d x DE QUESTIONS. In : : : 5 :. Then + + i equl to d. If the perimeter of tringle i 6 time the.m. of the ine of it ngle nd the ide i, then ngle i d 0. In tringle,, +, 60. Then the ide 6 d none of thee. The ngle of elevtion of top of tower from point on the ground i 0 nd it i 60 when it i viewed from point loted 0 m wy from the initil point towrd the tower. The height of the tower i d 0 IEEE/JEE-MINS QUESTIONS. The ide of tringle re in, o nd in o for ome 0 < <. Then the gretet ngle of the tringle i. If in, the ltitude from the vertie,, on oppoite ide re in H.P., then in, in, in re in rithmeti Geometri Progreion H.P. G.P. d.p.. In tringle, let. If r i the inrdiu nd R i the irumrdiu of the tringle, then r + R equl d +

24 . The um of the rdii of inried nd irumried irle for n n ided regulr polygon of ide, i ot n ot n ot n d ot n 5. The upper / th portion of vertile pole utend n ngle tn /5 t point in the horizontl plne through it foot nd t ditne 0 m from the foot. 80 m 0 m 0 m d 60 m 6. In tringle, medin D nd E re drwn. If D, D /6 nd E /, then the re of the i d 7. If in o + o, then the ide, nd tify + re in. P. re in G. P. d re in H. P. 8. peron tnding on the nk of river oerve tht the ngle of elevtion of the top of tree on the oppoite nk of the river i 60 nd when he retire 0 meter wy from the tree the ngle of elevtion eome 0. The redth of the river i 0 m 60 m 0 m d 0 m 9. i vertil pole with t the ground level nd t the top. mn find tht the ngel of elevtion of the point from ertin point on the ground i 60. He move wy from the pole long the line to point D uh tht D 7 m. From D the ngle of elevtion of the point i 5. Then the height of the pole i m m m d 7 m 0. For regulr polygon, let r nd R e the rdii of the inried nd the irumried irle. fle ttement mong the following i There i regulr polygon with There i regulr polygon with r R There i regulr polygon with r R r R d There i regulr polygon with r R. Let T n e the numer of ll poile tringle formed y joining vertie of n n-ided regulr polygon. If T n + T n 0, then the vlue of n i d 5. ird i itting on the top of vertil pole 0 m high nd it elevtion from point O on the ground i

25 5. It flie off horizontlly tright wy from the point O. fter one eond, the elevtion of the ird from O i redued to 0. Then the peed in m/ of the ird i d 0

26 SI LEVEL SSIGNMENT. If,, 5, find r nd R.. In n equilterl tringle, find the reltion etween the in-rdiu nd the irum-rdiu.. Solve the tringle, if, 6,.. If 5, 7 nd in, olve the tringle, if poile. 5. If 0º, 8 nd 6, find. 6. The ngle of tringle re in the rtio : : 7, find the rtio of it ide. 7. In, prove tht : o o o o o o o o o. 8. Prove tht + {ot / + ot / } ot /. 9. Prove tht in + in + in With uul nottion, if in tringle, then prove tht o 7 o o In tringle, prove tht tn tn tn.. irle of rdiu,, 5 touhe externlly. Find the ditne from point of ontt to interetion point of tngent.. If i the re of tringle with ide length,, then how tht.. In ny tringle, prove tht ot ot ot ot ot ot. 5. Let e tringle with inentre I nd rdiu of inirle r. Let D, E, F e the feet of the perpendiulr from I to the ide, nd repetively. If r, r, r re the rdii of irle inried in the qudrilterl FIE, DIF nd DIE repetively, Prove tht r r r r r r r r r r rr. r r r r r r

27 DVNED LEVEL SSIGNMENT. If in tringle in, prove tht it i either right ngled or n ioele tringle. in. If i lene nd o + o in / then prove tht,, re in.p.. Two ide of the tringle re of length 6 nd nd the ngle oppoite to mller ide i 0º. How mny uh tringle re poile? Find the length of their third ide nd re.. If in tringle, nd D i medin then prove tht : D In tringle, if +, prove tht : ot ot. 6. D i the mid point of in tringle. If D i perpendiulr to, prove tht o o. 7. If p, p, p e the ltitude of tringle from the vertie,, repetively nd e the re of the tringle, prove tht p p p o 8. The ide of tringle re three oneutive nturl numer nd it lrget ngle i twie the mllet one. Determine the ide of the tringle. 9. In tringle, prove tht o o tn tn e. o o o o 0. Prove tht the rdiu of the irle ping through the entre of the inried irle of the tringle nd through the end point of the e i e.. Perpendiulr re drwn from the vertie,, of n ute ngled tringle on the oppoite ide, nd produed to meet the irumirle of the tringle. If thee produed prt e,, repetively, how tht tn + tn + tn.

28 . If in tringle 8R + +, prove tht the tringle i right ngled.. In tringle of e, the rtio of the other two ide i r <. Show tht the ltitude of the tringle i le thn or equl to r r.. Let e tringle hving O nd I it irumentre nd inentre repetively if R nd r e the irum rdiu nd the inrdiu repetively, then prove tht IO R Rr. Further how tht the tringle IO i right ngled tringle if nd only if i the.m. of nd. 5. If nd re the ltitude of the from the vertie, nd repetively then how tht ot + ot + ot

29 NSWERS Ojetive ignment.. d.. d d d d 0..,..,., 5.,d 6.,, 7., 8.,, 9., 0., Miellneou ignment ; -r; -p; D-q 9. -r; -q; -p; D Previou Yer Quetion IIT-JEE/JEE-DVNE ,, d d ,d.,d 5. d ,,,d 9., 0. d.,. d.. DE QUESTIONS.... d

30 MINS QUESTIONS.. d. d. d d d. d. d i Level ignment. r, R r R 5.,,. No tringle n e formed ::. 5 dvned Level ignment. Side re, 8., 5 nd 6.

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions )

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions ) - TRIGONOMETRY Pge P ( ) In tringle PQR, R =. If tn b c = 0, 0, then Q nd tn re the roots of the eqution = b c c = b b = c b = c [ AIEEE 00 ] ( ) In tringle ABC, let C =. If r is the inrdius nd R is the

More information

LESSON 11: TRIANGLE FORMULAE

LESSON 11: TRIANGLE FORMULAE . THE SEMIPERIMETER OF TRINGLE LESSON : TRINGLE FORMULE In wht follows, will hve sides, nd, nd these will e opposite ngles, nd respetively. y the tringle inequlity, nd..() So ll of, & re positive rel numers.

More information

m m m m m m m m P m P m ( ) m m P( ) ( ). The o-ordinte of the point P( ) dividing the line segment joining the two points ( ) nd ( ) eternll in the r

m m m m m m m m P m P m ( ) m m P( ) ( ). The o-ordinte of the point P( ) dividing the line segment joining the two points ( ) nd ( ) eternll in the r CO-ORDINTE GEOMETR II I Qudrnt Qudrnt (-.+) (++) X X - - - 0 - III IV Qudrnt - Qudrnt (--) - (+-) Region CRTESIN CO-ORDINTE SSTEM : Retngulr Co-ordinte Sstem : Let X' OX nd 'O e two mutull perpendiulr

More information

Mathematics 10 Page 1 of 5 Properties of Triangle s and Quadrilaterals. Isosceles Triangle. - 2 sides and 2 corresponding.

Mathematics 10 Page 1 of 5 Properties of Triangle s and Quadrilaterals. Isosceles Triangle. - 2 sides and 2 corresponding. Mthemtis 10 Pge 1 of 5 Properties of s Pthgoren Theorem 2 2 2 used to find the length of sides of right tringle Tpe of s nd Some s Theorems ngles s Slene Isoseles Equilterl ute - ll ngles re less thn 90

More information

PYTHAGORAS THEOREM,TRIGONOMETRY,BEARINGS AND THREE DIMENSIONAL PROBLEMS

PYTHAGORAS THEOREM,TRIGONOMETRY,BEARINGS AND THREE DIMENSIONAL PROBLEMS PYTHGORS THEOREM,TRIGONOMETRY,ERINGS ND THREE DIMENSIONL PROLEMS 1.1 PYTHGORS THEOREM: 1. The Pythgors Theorem sttes tht the squre of the hypotenuse is equl to the sum of the squres of the other two sides

More information

PROPERTIES OF TRIANGLES

PROPERTIES OF TRIANGLES PROPERTIES OF TRINGLES. RELTION RETWEEN SIDES ND NGLES OF TRINGLE:. tringle onsists of three sides nd three ngles lled elements of the tringle. In ny tringle,,, denotes the ngles of the tringle t the verties.

More information

The Intouch Triangle and the OI-line

The Intouch Triangle and the OI-line Forum Geometriorum Volume 4 004 15 134. FORUM GEOM ISSN 1534-1178 The Intouh Tringle nd the OI-line Eri Dnneel Abtrt. We prove ome intereting reult relting the intouh tringle nd the OI line of tringle.

More information

SOLUTION OF TRIANGLES

SOLUTION OF TRIANGLES SOLUTION OF TIANGLES DPP by VK Sir B.TEH., IIT DELHI VK lsses, -9-40, Indr Vihr, Kot. Mob. No. 989060 . If cos A + cosb + cos = then the sides of the AB re in A.P. G.P H.P. none. If in tringle sin A :

More information

Geometry of the Circle - Chords and Angles. Geometry of the Circle. Chord and Angles. Curriculum Ready ACMMG: 272.

Geometry of the Circle - Chords and Angles. Geometry of the Circle. Chord and Angles. Curriculum Ready ACMMG: 272. Geometry of the irle - hords nd ngles Geometry of the irle hord nd ngles urriulum Redy MMG: 272 www.mthletis.om hords nd ngles HRS N NGLES The irle is si shpe nd so it n e found lmost nywhere. This setion

More information

A Study on the Properties of Rational Triangles

A Study on the Properties of Rational Triangles Interntionl Journl of Mthemtis Reserh. ISSN 0976-5840 Volume 6, Numer (04), pp. 8-9 Interntionl Reserh Pulition House http://www.irphouse.om Study on the Properties of Rtionl Tringles M. Q. lm, M.R. Hssn

More information

VECTOR ALGEBRA. Syllabus :

VECTOR ALGEBRA. Syllabus : MV VECTOR ALGEBRA Syllus : Vetors nd Slrs, ddition of vetors, omponent of vetor, omponents of vetor in two dimensions nd three dimensionl spe, slr nd vetor produts, slr nd vetor triple produt. Einstein

More information

Comparing the Pre-image and Image of a Dilation

Comparing the Pre-image and Image of a Dilation hpter Summry Key Terms Postultes nd Theorems similr tringles (.1) inluded ngle (.2) inluded side (.2) geometri men (.) indiret mesurement (.6) ngle-ngle Similrity Theorem (.2) Side-Side-Side Similrity

More information

GM1 Consolidation Worksheet

GM1 Consolidation Worksheet Cmridge Essentils Mthemtis Core 8 GM1 Consolidtion Worksheet GM1 Consolidtion Worksheet 1 Clulte the size of eh ngle mrked y letter. Give resons for your nswers. or exmple, ngles on stright line dd up

More information

Activities. 4.1 Pythagoras' Theorem 4.2 Spirals 4.3 Clinometers 4.4 Radar 4.5 Posting Parcels 4.6 Interlocking Pipes 4.7 Sine Rule Notes and Solutions

Activities. 4.1 Pythagoras' Theorem 4.2 Spirals 4.3 Clinometers 4.4 Radar 4.5 Posting Parcels 4.6 Interlocking Pipes 4.7 Sine Rule Notes and Solutions MEP: Demonstrtion Projet UNIT 4: Trigonometry UNIT 4 Trigonometry tivities tivities 4. Pythgors' Theorem 4.2 Spirls 4.3 linometers 4.4 Rdr 4.5 Posting Prels 4.6 Interloking Pipes 4.7 Sine Rule Notes nd

More information

Non Right Angled Triangles

Non Right Angled Triangles Non Right ngled Tringles Non Right ngled Tringles urriulum Redy www.mthletis.om Non Right ngled Tringles NON RIGHT NGLED TRINGLES sin i, os i nd tn i re lso useful in non-right ngled tringles. This unit

More information

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then. pril 8, 2017 Mth 9 Geometry Solving vetor prolems Prolem Prove tht if vetors nd stisfy, then Solution 1 onsider the vetor ddition prllelogrm shown in the Figure Sine its digonls hve equl length,, the prllelogrm

More information

Section 1.3 Triangles

Section 1.3 Triangles Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior

More information

MATHEMATICS AND STATISTICS 1.6

MATHEMATICS AND STATISTICS 1.6 MTHMTIS N STTISTIS 1.6 pply geometri resoning in solving prolems ternlly ssessed 4 redits S 91031 inding unknown ngles When finding the size of unknown ngles in figure, t lest two steps of resoning will

More information

No. Diagram Given Condition Conclusion Abbreviation a and b are adjacent angles on a straight a b 180. a, b and c are angles at a point

No. Diagram Given Condition Conclusion Abbreviation a and b are adjacent angles on a straight a b 180. a, b and c are angles at a point Pge 46 REVITION USE IN EUTIVE GEOMETR. Properties of Plne Geometry No. igrm Given ondition onlusion revition nd re djent 1 ngles on stright 180 dj. s on st. line line 2, nd re ngles t point 360 s t pt.

More information

THREE DIMENSIONAL GEOMETRY

THREE DIMENSIONAL GEOMETRY MD THREE DIMENSIONAL GEOMETRY CA CB C Coordintes of point in spe There re infinite numer of points in spe We wnt to identif eh nd ever point of spe with the help of three mutull perpendiulr oordintes es

More information

Chapter 6. Section 6.1. Chapter 6 Opener. Big Ideas Math Blue Worked-Out Solutions. 6.1 Activity (pp ) Try It Yourself (p.

Chapter 6. Section 6.1. Chapter 6 Opener. Big Ideas Math Blue Worked-Out Solutions. 6.1 Activity (pp ) Try It Yourself (p. Chpter 6 Opener Try It Yourelf (p. 9). Becue 0 i equl to,.0 i equl to.. 0 So,.0.. i le thn. Becue 8 So,.

More information

CHENG Chun Chor Litwin The Hong Kong Institute of Education

CHENG Chun Chor Litwin The Hong Kong Institute of Education PE-hing Mi terntionl onferene IV: novtion of Mthemtis Tehing nd Lerning through Lesson Study- onnetion etween ssessment nd Sujet Mtter HENG hun hor Litwin The Hong Kong stitute of Edution Report on using

More information

3 Angle Geometry. 3.1 Measuring Angles. 1. Using a protractor, measure the marked angles.

3 Angle Geometry. 3.1 Measuring Angles. 1. Using a protractor, measure the marked angles. 3 ngle Geometry MEP Prtie ook S3 3.1 Mesuring ngles 1. Using protrtor, mesure the mrked ngles. () () (d) (e) (f) 2. Drw ngles with the following sizes. () 22 () 75 120 (d) 90 (e) 153 (f) 45 (g) 180 (h)

More information

DEEPAWALI ASSIGNMENT

DEEPAWALI ASSIGNMENT DEEPWLI SSIGNMENT CLSS & DOPPE FO TGET IIT JEE Get Solution & Video Tutorils online www.mthsbysuhg.com Downlod FEE Study Pckges, Test Series from w ww.tekoclsses.com Bhopl : Phone : (0755) 00 000 Wishing

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Nme Dte hpter 9 Mintining Mthemtil Profiieny Simplify the epression. 1. 500. 189 3. 5 4. 4 3 5. 11 5 6. 8 Solve the proportion. 9 3 14 7. = 8. = 9. 1 7 5 4 = 4 10. 0 6 = 11. 7 4 10 = 1. 5 9 15 3 = 5 +

More information

Similar Right Triangles

Similar Right Triangles Geometry V1.noteook Ferury 09, 2012 Similr Right Tringles Cn I identify similr tringles in right tringle with the ltitude? Cn I identify the proportions in right tringles? Cn I use the geometri mens theorems

More information

m A 1 1 A ! and AC 6

m A 1 1 A ! and AC 6 REVIEW SET A Using sle of m represents units, sketh vetor to represent: NON-CALCULATOR n eroplne tking off t n ngle of 8 ± to runw with speed of 6 ms displement of m in north-esterl diretion. Simplif:

More information

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the

More information

( ) { } [ ] { } [ ) { } ( ] { }

( ) { } [ ] { } [ ) { } ( ] { } Mth 65 Prelulus Review Properties of Inequlities 1. > nd > >. > + > +. > nd > 0 > 4. > nd < 0 < Asolute Vlue, if 0, if < 0 Properties of Asolute Vlue > 0 1. < < > or

More information

MATHEMATICS STUDY MATERIAL PROPERTIES AND SOLUTIONS OF TRIANGLES & HEIGHTS AND DISTANCES AIEEE NARAYANA INSTITUTE OF CORRESPONDENCE COURSES

MATHEMATICS STUDY MATERIAL PROPERTIES AND SOLUTIONS OF TRIANGLES & HEIGHTS AND DISTANCES AIEEE NARAYANA INSTITUTE OF CORRESPONDENCE COURSES MTHEMTIS STUDY MTERIL PROPERTIES ND SOLUTIONS OF TRINGLES & HEIGHTS ND DISTNES IEEE NRYN FNS HOUSE, 6 KLU SRI MRKET SRVPRIY VIHR, NEW DELHI-006 PH.: (0) 00//50 FX : (0) 880 Wesite : w w w. n r y n i. m

More information

QUADRATIC EQUATION EXERCISE - 01 CHECK YOUR GRASP

QUADRATIC EQUATION EXERCISE - 01 CHECK YOUR GRASP QUADRATIC EQUATION EXERCISE - 0 CHECK YOUR GRASP. Sine sum of oeffiients 0. Hint : It's one root is nd other root is 8 nd 5 5. tn other root 9. q 4p 0 q p q p, q 4 p,,, 4 Hene 7 vlues of (p, q) 7 equtions

More information

The Ellipse. is larger than the other.

The Ellipse. is larger than the other. The Ellipse Appolonius of Perg (5 B.C.) disovered tht interseting right irulr one ll the w through with plne slnted ut is not perpendiulr to the is, the intersetion provides resulting urve (oni setion)

More information

SOLUTION OF TRIANGLE GENERAL NOTATION : 1. In a triangle ABC angles at vertices are usually denoted by A, B, C

SOLUTION OF TRIANGLE GENERAL NOTATION : 1. In a triangle ABC angles at vertices are usually denoted by A, B, C GENERL NOTTION : SOLUTION OF TRINGLE In tringle BC ngles t vertices re usully denoted by, B, C PGE # sides opposite to these vertices re denoted by, b, c respectively Circumrdius is denoted by R 3 Inrdius

More information

Trigonometry and Constructive Geometry

Trigonometry and Constructive Geometry Trigonometry nd Construtive Geometry Trining prolems for M2 2018 term 1 Ted Szylowie tedszy@gmil.om 1 Leling geometril figures 1. Prtie writing Greek letters. αβγδɛθλµπψ 2. Lel the sides, ngles nd verties

More information

GEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS:

GEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS: GEOMETRICL PROPERTIES OF NGLES ND CIRCLES, NGLES PROPERTIES OF TRINGLES, QUDRILTERLS ND POLYGONS: 1.1 TYPES OF NGLES: CUTE NGLE RIGHT NGLE OTUSE NGLE STRIGHT NGLE REFLEX NGLE 40 0 4 0 90 0 156 0 180 0

More information

Answers: ( HKMO Heat Events) Created by: Mr. Francis Hung Last updated: 15 December 2017

Answers: ( HKMO Heat Events) Created by: Mr. Francis Hung Last updated: 15 December 2017 Answers: (0- HKMO Het Events) reted y: Mr. Frncis Hung Lst updted: 5 Decemer 07 - Individul - Group Individul Events 6 80 0 4 5 5 0 6 4 7 8 5 9 9 0 9 609 4 808 5 0 6 6 7 6 8 0 9 67 0 0 I Simplify 94 0.

More information

Pythagoras Theorem. The area of the square on the hypotenuse is equal to the sum of the squares on the other two sides

Pythagoras Theorem. The area of the square on the hypotenuse is equal to the sum of the squares on the other two sides Pythgors theorem nd trigonometry Pythgors Theorem The hypotenuse of right-ngled tringle is the longest side The hypotenuse is lwys opposite the right-ngle 2 = 2 + 2 or 2 = 2-2 or 2 = 2-2 The re of the

More information

Trigonometry Revision Sheet Q5 of Paper 2

Trigonometry Revision Sheet Q5 of Paper 2 Trigonometry Revision Sheet Q of Pper The Bsis - The Trigonometry setion is ll out tringles. We will normlly e given some of the sides or ngles of tringle nd we use formule nd rules to find the others.

More information

Log1 Contest Round 3 Theta Individual. 4 points each 1 What is the sum of the first 5 Fibonacci numbers if the first two are 1, 1?

Log1 Contest Round 3 Theta Individual. 4 points each 1 What is the sum of the first 5 Fibonacci numbers if the first two are 1, 1? 008 009 Log1 Contest Round Thet Individul Nme: points ech 1 Wht is the sum of the first Fiboncci numbers if the first two re 1, 1? If two crds re drwn from stndrd crd deck, wht is the probbility of drwing

More information

Ellipses. The second type of conic is called an ellipse.

Ellipses. The second type of conic is called an ellipse. Ellipses The seond type of oni is lled n ellipse. Definition of Ellipse An ellipse is the set of ll points (, y) in plne, the sum of whose distnes from two distint fied points (foi) is onstnt. (, y) d

More information

QUADRATIC EQUATION. Contents

QUADRATIC EQUATION. Contents QUADRATIC EQUATION Contents Topi Pge No. Theory 0-04 Exerise - 05-09 Exerise - 09-3 Exerise - 3 4-5 Exerise - 4 6 Answer Key 7-8 Syllus Qudrti equtions with rel oeffiients, reltions etween roots nd oeffiients,

More information

R(3, 8) P( 3, 0) Q( 2, 2) S(5, 3) Q(2, 32) P(0, 8) Higher Mathematics Objective Test Practice Book. 1 The diagram shows a sketch of part of

R(3, 8) P( 3, 0) Q( 2, 2) S(5, 3) Q(2, 32) P(0, 8) Higher Mathematics Objective Test Practice Book. 1 The diagram shows a sketch of part of Higher Mthemtics Ojective Test Prctice ook The digrm shows sketch of prt of the grph of f ( ). The digrm shows sketch of the cuic f ( ). R(, 8) f ( ) f ( ) P(, ) Q(, ) S(, ) Wht re the domin nd rnge of

More information

+ R 2 where R 1. MULTIPLE CHOICE QUESTIONS (MCQ's) (Each question carries one mark)

+ R 2 where R 1. MULTIPLE CHOICE QUESTIONS (MCQ's) (Each question carries one mark) 2. C h p t e r t G l n c e is the set of ll points in plne which re t constnt distnce from fixed point clled centre nd constnt distnce is known s rdius of circle. A tngent t ny point of circle is perpendiculr

More information

Lesson-5 ELLIPSE 2 1 = 0

Lesson-5 ELLIPSE 2 1 = 0 Lesson-5 ELLIPSE. An ellipse is the locus of point which moves in plne such tht its distnce from fied point (known s the focus) is e (< ), times its distnce from fied stright line (known s the directri).

More information

/ 3, then (A) 3(a 2 m 2 + b 2 ) = 4c 2 (B) 3(a 2 + b 2 m 2 ) = 4c 2 (C) a 2 m 2 + b 2 = 4c 2 (D) a 2 + b 2 m 2 = 4c 2

/ 3, then (A) 3(a 2 m 2 + b 2 ) = 4c 2 (B) 3(a 2 + b 2 m 2 ) = 4c 2 (C) a 2 m 2 + b 2 = 4c 2 (D) a 2 + b 2 m 2 = 4c 2 SET I. If the locus of the point of intersection of perpendiculr tngents to the ellipse x circle with centre t (0, 0), then the rdius of the circle would e + / ( ) is. There re exctl two points on the

More information

ICSE Board Class IX Mathematics Paper 4 Solution

ICSE Board Class IX Mathematics Paper 4 Solution ICSE Bord Clss IX Mthemtics Pper Solution SECTION A (0 Mrks) Q.. () Consider x y 6 5 5 x y 6 5 5 0 6 0 6 x y 6 50 8 5 6 7 6 x y 6 7 6 x y 6 x 7,y (b) Dimensions of the brick: Length (l) = 0 cm, bredth

More information

UNIT 31 Angles and Symmetry: Data Sheets

UNIT 31 Angles and Symmetry: Data Sheets UNIT 31 Angles nd Symmetry Dt Sheets Dt Sheets 31.1 Line nd Rottionl Symmetry 31.2 Angle Properties 31.3 Angles in Tringles 31.4 Angles nd Prllel Lines: Results 31.5 Angles nd Prllel Lines: Exmple 31.6

More information

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES PAIR OF LINEAR EQUATIONS IN TWO VARIABLES. Two liner equtions in the sme two vriles re lled pir of liner equtions in two vriles. The most generl form of pir of liner equtions is x + y + 0 x + y + 0 where,,,,,,

More information

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point GCSE C Emple 7 Work out 9 Give your nswer in its simplest form Numers n inies Reiprote mens invert or turn upsie own The reiprol of is 9 9 Mke sure you only invert the frtion you re iviing y 7 You multiply

More information

5. Every rational number have either terminating or repeating (recurring) decimal representation.

5. Every rational number have either terminating or repeating (recurring) decimal representation. CHAPTER NUMBER SYSTEMS Points to Rememer :. Numer used for ounting,,,,... re known s Nturl numers.. All nturl numers together with zero i.e. 0,,,,,... re known s whole numers.. All nturl numers, zero nd

More information

Alg. Sheet (1) Department : Math Form : 3 rd prep. Sheet

Alg. Sheet (1) Department : Math Form : 3 rd prep. Sheet Ciro Governorte Nozh Directorte of Eduction Nozh Lnguge Schools Ismili Rod Deprtment : Mth Form : rd prep. Sheet Alg. Sheet () [] Find the vlues of nd in ech of the following if : ) (, ) ( -5, 9 ) ) (,

More information

JEE Advnced Mths Assignment Onl One Correct Answer Tpe. The locus of the orthocenter of the tringle formed the lines (+P) P + P(+P) = 0, (+q) q+q(+q) = 0 nd = 0, where p q, is () hperol prol n ellipse

More information

Form 5 HKCEE 1990 Mathematics II (a 2n ) 3 = A. f(1) B. f(n) A. a 6n B. a 8n C. D. E. 2 D. 1 E. n. 1 in. If 2 = 10 p, 3 = 10 q, express log 6

Form 5 HKCEE 1990 Mathematics II (a 2n ) 3 = A. f(1) B. f(n) A. a 6n B. a 8n C. D. E. 2 D. 1 E. n. 1 in. If 2 = 10 p, 3 = 10 q, express log 6 Form HK 9 Mthemtics II.. ( n ) =. 6n. 8n. n 6n 8n... +. 6.. f(). f(n). n n If = 0 p, = 0 q, epress log 6 in terms of p nd q.. p q. pq. p q pq p + q Let > b > 0. If nd b re respectivel the st nd nd terms

More information

Triangles The following examples explore aspects of triangles:

Triangles The following examples explore aspects of triangles: Tringles The following exmples explore spects of tringles: xmple 1: ltitude of right ngled tringle + xmple : tringle ltitude of the symmetricl ltitude of n isosceles x x - 4 +x xmple 3: ltitude of the

More information

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS JEE(MAIN) 05 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 0 th APRIL, 05) PART B MATHEMATICS CODE-D. Let, b nd c be three non-zero vectors such tht no two of them re colliner nd, b c b c. If is the ngle

More information

Chapter 1: Fundamentals

Chapter 1: Fundamentals Chpter 1: Fundmentls 1.1 Rel Numbers Types of Rel Numbers: Nturl Numbers: {1, 2, 3,...}; These re the counting numbers. Integers: {... 3, 2, 1, 0, 1, 2, 3,...}; These re ll the nturl numbers, their negtives,

More information

2.1 ANGLES AND THEIR MEASURE. y I

2.1 ANGLES AND THEIR MEASURE. y I .1 ANGLES AND THEIR MEASURE Given two interseting lines or line segments, the mount of rottion out the point of intersetion (the vertex) required to ring one into orrespondene with the other is lled the

More information

Pythagoras theorem and surds

Pythagoras theorem and surds HPTER Mesurement nd Geometry Pythgors theorem nd surds In IE-EM Mthemtis Yer 8, you lernt out the remrkle reltionship etween the lengths of the sides of right-ngled tringle. This result is known s Pythgors

More information

PARABOLA EXERCISE 3(B)

PARABOLA EXERCISE 3(B) PARABOLA EXERCISE (B). Find eqution of the tngent nd norml to the prbol y = 6x t the positive end of the ltus rectum. Eqution of prbol y = 6x 4 = 6 = / Positive end of the Ltus rectum is(, ) =, Eqution

More information

Proportions: A ratio is the quotient of two numbers. For example, 2 3

Proportions: A ratio is the quotient of two numbers. For example, 2 3 Proportions: rtio is the quotient of two numers. For exmple, 2 3 is rtio of 2 n 3. n equlity of two rtios is proportion. For exmple, 3 7 = 15 is proportion. 45 If two sets of numers (none of whih is 0)

More information

Math Lesson 4-5 The Law of Cosines

Math Lesson 4-5 The Law of Cosines Mth-1060 Lesson 4-5 The Lw of osines Solve using Lw of Sines. 1 17 11 5 15 13 SS SSS Every pir of loops will hve unknowns. Every pir of loops will hve unknowns. We need nother eqution. h Drop nd ltitude

More information

Alg 3 Ch 7.2, 8 1. C 2) If A = 30, and C = 45, a = 1 find b and c A

Alg 3 Ch 7.2, 8 1. C 2) If A = 30, and C = 45, a = 1 find b and c A lg 3 h 7.2, 8 1 7.2 Right Tringle Trig ) Use of clcultor sin 10 = sin x =.4741 c ) rete right tringles π 1) If = nd = 25, find 6 c 2) If = 30, nd = 45, = 1 find nd c 3) If in right, with right ngle t,

More information

Mathematics. Area under Curve.

Mathematics. Area under Curve. Mthemtics Are under Curve www.testprepkrt.com Tle of Content 1. Introduction.. Procedure of Curve Sketching. 3. Sketching of Some common Curves. 4. Are of Bounded Regions. 5. Sign convention for finding

More information

Trigonometry. cosθ. sinθ tanθ. Mathletics Instant Workbooks. Copyright

Trigonometry. cosθ. sinθ tanθ. Mathletics Instant Workbooks. Copyright Student Book - Series K- sinθ tnθ osθ Mtletis Instnt Workooks Copyrigt Student Book - Series K Contents Topis Topi - Nming te sides of rigt-ngled tringle Topi 2 - Te trigonometri rtios Topi 3 - Using lultor

More information

Similarity and Congruence

Similarity and Congruence Similrity nd ongruence urriculum Redy MMG: 201, 220, 221, 243, 244 www.mthletics.com SIMILRITY N ONGRUN If two shpes re congruent, it mens thy re equl in every wy ll their corresponding sides nd ngles

More information

GEOMETRY OF THE CIRCLE TANGENTS & SECANTS

GEOMETRY OF THE CIRCLE TANGENTS & SECANTS Geometry Of The ircle Tngents & Secnts GEOMETRY OF THE IRLE TNGENTS & SENTS www.mthletics.com.u Tngents TNGENTS nd N Secnts SENTS Tngents nd secnts re lines tht strt outside circle. Tngent touches the

More information

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES Mthemtics SKE: STRN J STRN J: TRNSFORMTIONS, VETORS nd MTRIES J3 Vectors Text ontents Section J3.1 Vectors nd Sclrs * J3. Vectors nd Geometry Mthemtics SKE: STRN J J3 Vectors J3.1 Vectors nd Sclrs Vectors

More information

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths Intermedite Mth Cirles Wednesdy 17 Otoer 01 Geometry II: Side Lengths Lst week we disussed vrious ngle properties. As we progressed through the evening, we proved mny results. This week, we will look t

More information

EXERCISE - 01 CHECK YOUR GRASP

EXERCISE - 01 CHECK YOUR GRASP SLUTIN F TRINGLE EXERISE - 0 HEK YUR GRSP 4 4R sin 4R sin 4R sin sin sin sin 4R (sin sin sin ) sin sin 6R os sin R sin sin sin R 8R 4R 5 p p p 6 p p p (s ) ( + + s) os tn os 8 + + s s pplying hlf ngle

More information

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL: PYTHAGORAS THEOREM 1 WHAT S IN CHAPTER 1? 1 01 Squres, squre roots nd surds 1 02 Pythgors theorem 1 03 Finding the hypotenuse 1 04 Finding shorter side 1 05 Mixed prolems 1 06 Testing for right-ngled tringles

More information

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES THE 08 09 KENNESW STTE UNIVERSITY HIGH SHOOL MTHEMTIS OMPETITION PRT I MULTIPLE HOIE For ech of the following questions, crefully blcken the pproprite box on the nswer sheet with # pencil. o not fold,

More information

1.3 SCALARS AND VECTORS

1.3 SCALARS AND VECTORS Bridge Course Phy I PUC 24 1.3 SCLRS ND VECTORS Introdution: Physis is the study of nturl phenomen. The study of ny nturl phenomenon involves mesurements. For exmple, the distne etween the plnet erth nd

More information

Something found at a salad bar

Something found at a salad bar Nme PP Something found t sld r 4.7 Notes RIGHT TRINGLE hs extly one right ngle. To solve right tringle, you n use things like SOH-H-TO nd the Pythgoren Theorem. n OLIQUE TRINGLE hs no right ngles. To solve

More information

USA Mathematical Talent Search Round 1 Solutions Year 21 Academic Year

USA Mathematical Talent Search Round 1 Solutions Year 21 Academic Year 1/1/21. Fill in the circles in the picture t right with the digits 1-8, one digit in ech circle with no digit repeted, so tht no two circles tht re connected by line segment contin consecutive digits.

More information

Perimeter and Area. Mathletics Instant Workbooks. Copyright

Perimeter and Area. Mathletics Instant Workbooks. Copyright Perimeter nd Are Student Book - Series J- L B Mthletis Instnt Workooks Copyright Student Book - Series J Contents Topis Topi - Plne shpes Topi 2 - Perimeter of regulr shpes Topi 3 - Perimeter of irregulr

More information

Level I MAML Olympiad 2001 Page 1 of 6 (A) 90 (B) 92 (C) 94 (D) 96 (E) 98 (A) 48 (B) 54 (C) 60 (D) 66 (E) 72 (A) 9 (B) 13 (C) 17 (D) 25 (E) 38

Level I MAML Olympiad 2001 Page 1 of 6 (A) 90 (B) 92 (C) 94 (D) 96 (E) 98 (A) 48 (B) 54 (C) 60 (D) 66 (E) 72 (A) 9 (B) 13 (C) 17 (D) 25 (E) 38 Level I MAML Olympid 00 Pge of 6. Si students in smll clss took n em on the scheduled dte. The verge of their grdes ws 75. The seventh student in the clss ws ill tht dy nd took the em lte. When her score

More information

Vector Integration. Line integral: Let F ( x y,

Vector Integration. Line integral: Let F ( x y, Vetor Integrtion Thi hpter tret integrtion in vetor field. It i the mthemti tht engineer nd phiit ue to deribe fluid flow, deign underwter trnmiion ble, eplin the flow of het in tr, nd put tellite in orbit.

More information

4. Statements Reasons

4. Statements Reasons Chpter 9 Answers Prentie-Hll In. Alterntive Ativity 9-. Chek students work.. Opposite sides re prllel. 3. Opposite sides re ongruent. 4. Opposite ngles re ongruent. 5. Digonls iset eh other. 6. Students

More information

MEP Practice Book ES3. 1. Calculate the size of the angles marked with a letter in each diagram. None to scale

MEP Practice Book ES3. 1. Calculate the size of the angles marked with a letter in each diagram. None to scale ME rctice ook ES3 3 ngle Geometr 3.3 ngle Geometr 1. lculte the size of the ngles mrked with letter in ech digrm. None to scle () 70 () 20 54 65 25 c 36 (d) (e) (f) 56 62 d e 60 40 70 70 f 30 g (g) (h)

More information

Andrei D. Polyanin, Alexander V. Manzhirov. Andrei D. Polyanin, Alexander V. Manzhirov Published online on: 27 Nov 2006

Andrei D. Polyanin, Alexander V. Manzhirov. Andrei D. Polyanin, Alexander V. Manzhirov Published online on: 27 Nov 2006 This rtile ws downloded y: 0.3.98.93 On: 08 Nov 08 ess detils: susription numer Pulisher: Press Inform Ltd egistered in Englnd nd Wles egistered Numer: 07954 egistered offie: 5 Howik Ple, London SWP WG,

More information

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Vector Integration

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Vector Integration www.boopr.om VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Vetor Integrtion Thi hpter tret integrtion in vetor field. It i the mthemti tht engineer nd phiit ue to deribe fluid flow, deign underwter trnmiion

More information

Polynomials and Division Theory

Polynomials and Division Theory Higher Checklist (Unit ) Higher Checklist (Unit ) Polynomils nd Division Theory Skill Achieved? Know tht polynomil (expression) is of the form: n x + n x n + n x n + + n x + x + 0 where the i R re the

More information

MATH4455 Module 10 Evens, Odds and Ends

MATH4455 Module 10 Evens, Odds and Ends MATH4455 Module 10 Even, Odd nd End Min Mth Conept: Prity, Ple Vlue Nottion, Enumertion, Story Prolem Auxiliry Ide: Tournment, Undireted grph I. The Mind-Reding Clultor Prolem. How doe the mind-reding

More information

Introduction to Olympiad Inequalities

Introduction to Olympiad Inequalities Introdution to Olympid Inequlities Edutionl Studies Progrm HSSP Msshusetts Institute of Tehnology Snj Simonovikj Spring 207 Contents Wrm up nd Am-Gm inequlity 2. Elementry inequlities......................

More information

Trigonometric Functions

Trigonometric Functions Trget Publictions Pvt. Ltd. Chpter 0: Trigonometric Functions 0 Trigonometric Functions. ( ) cos cos cos cos (cos + cos ) Given, cos cos + 0 cos (cos + cos ) + ( ) 0 cos cos cos + 0 + cos + (cos cos +

More information

Basic Angle Rules 5. A Short Hand Geometric Reasons. B Two Reasons. 1 Write in full the meaning of these short hand geometric reasons.

Basic Angle Rules 5. A Short Hand Geometric Reasons. B Two Reasons. 1 Write in full the meaning of these short hand geometric reasons. si ngle Rules 5 6 Short Hnd Geometri Resons 1 Write in full the mening of these short hnd geometri resons. Short Hnd Reson Full Mening ) se s isos Δ re =. ) orr s // lines re =. ) sum s t pt = 360. d)

More information

Proving the Pythagorean Theorem

Proving the Pythagorean Theorem Proving the Pythgoren Theorem W. Bline Dowler June 30, 2010 Astrt Most people re fmilir with the formul 2 + 2 = 2. However, in most ses, this ws presented in lssroom s n solute with no ttempt t proof or

More information

2. There are an infinite number of possible triangles, all similar, with three given angles whose sum is 180.

2. There are an infinite number of possible triangles, all similar, with three given angles whose sum is 180. SECTION 8-1 11 CHAPTER 8 Setion 8 1. There re n infinite numer of possile tringles, ll similr, with three given ngles whose sum is 180. 4. If two ngles α nd β of tringle re known, the third ngle n e found

More information

2) Three noncollinear points in Plane M. [A] A, D, E [B] A, B, E [C] A, B, D [D] A, E, H [E] A, H, M [F] H, A, B

2) Three noncollinear points in Plane M. [A] A, D, E [B] A, B, E [C] A, B, D [D] A, E, H [E] A, H, M [F] H, A, B Review Use the points nd lines in the digrm to identify the following. 1) Three colliner points in Plne M. [],, H [],, [],, [],, [],, M [] H,, M 2) Three noncolliner points in Plne M. [],, [],, [],, [],,

More information

12.4 Similarity in Right Triangles

12.4 Similarity in Right Triangles Nme lss Dte 12.4 Similrit in Right Tringles Essentil Question: How does the ltitude to the hpotenuse of right tringle help ou use similr right tringles to solve prolems? Eplore Identifing Similrit in Right

More information

CSCI565 - Compiler Design

CSCI565 - Compiler Design CSCI565 - Compiler Deign Spring 6 Due Dte: Fe. 5, 6 t : PM in Cl Prolem [ point]: Regulr Expreion nd Finite Automt Develop regulr expreion (RE) tht detet the longet tring over the lphet {-} with the following

More information

In right-angled triangles the square on the side subtending the right angle is equal to the squares on the sides containing the right angle.

In right-angled triangles the square on the side subtending the right angle is equal to the squares on the sides containing the right angle. Mth 3329-Uniform Geometries Leture 06 1. Review of trigonometry While we re looking t Eulid s Elements, I d like to look t some si trigonometry. Figure 1. The Pythgoren theorem sttes tht if = 90, then

More information

Calculus Cheat Sheet. Integrals Definitions. where F( x ) is an anti-derivative of f ( x ). Fundamental Theorem of Calculus. dx = f x dx g x dx

Calculus Cheat Sheet. Integrals Definitions. where F( x ) is an anti-derivative of f ( x ). Fundamental Theorem of Calculus. dx = f x dx g x dx Clulus Chet Sheet Integrls Definitions Definite Integrl: Suppose f ( ) is ontinuous Anti-Derivtive : An nti-derivtive of f ( ) on [, ]. Divide [, ] into n suintervls of is funtion, F( ), suh tht F = f.

More information

( ) 1. 1) Let f( x ) = 10 5x. Find and simplify f( 2) and then state the domain of f(x).

( ) 1. 1) Let f( x ) = 10 5x. Find and simplify f( 2) and then state the domain of f(x). Mth 15 Fettermn/DeSmet Gustfson/Finl Em Review 1) Let f( ) = 10 5. Find nd simplif f( ) nd then stte the domin of f(). ) Let f( ) = +. Find nd simplif f(1) nd then stte the domin of f(). ) Let f( ) = 8.

More information

MATHEMATICS PART A. 1. ABC is a triangle, right angled at A. The resultant of the forces acting along AB, AC

MATHEMATICS PART A. 1. ABC is a triangle, right angled at A. The resultant of the forces acting along AB, AC FIITJEE Solutions to AIEEE MATHEMATICS PART A. ABC is tringle, right ngled t A. The resultnt of the forces cting long AB, AC with mgnitudes AB nd respectively is the force long AD, where D is the AC foot

More information

ONLINE PAGE PROOFS. Trigonometry Kick off with CAS 12.2 Trigonometry 12.3 Pythagorean triads

ONLINE PAGE PROOFS. Trigonometry Kick off with CAS 12.2 Trigonometry 12.3 Pythagorean triads 12 12.1 Kik off with S 12.2 Trigonometry 12.3 Pythgoren trids Trigonometry 12.4 Three-dimensionl Pythgors theorem 12.5 Trigonometri rtios 12.6 The sine rule 12.7 miguous se of the sine rule 12.8 The osine

More information

Plotting Ordered Pairs Using Integers

Plotting Ordered Pairs Using Integers SAMPLE Plotting Ordered Pirs Using Integers Ple two elsti nds on geoord to form oordinte xes shown on the right to help you solve these prolems.. Wht letter of the lphet does eh set of pirs nme?. (, )

More information

03. Early Greeks & Aristotle

03. Early Greeks & Aristotle 03. Erly Greeks & Aristotle I. Erly Greeks Topis I. Erly Greeks II. The Method of Exhustion III. Aristotle. Anximnder (. 60 B.C.) to peiron - the unlimited, unounded - fundmentl sustne of relity - underlying

More information

CET MATHEMATICS 2013

CET MATHEMATICS 2013 CET MATHEMATICS VERSION CODE: C. If sin is the cute ngle between the curves + nd + 8 t (, ), then () () () Ans: () Slope of first curve m ; slope of second curve m - therefore ngle is o A sin o (). The

More information

Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : ,

Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : , MT TRIGONOMETRIC FUNCTIONS AND TRIGONOMETRIC EQUATIONS C Trigonometric Functions : Bsic Trigonometric Identities : + cos = ; ; cos R sec tn = ; sec R (n ),n cosec cot = ; cosec R {n, n I} Circulr Definition

More information