GCSE Mathematics. Paper 2 Higher Tier. Mark scheme November Version: 1.0 Final

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1 GCSE Mathematics Paper Higher Tier Mark scheme 8300 November 017 Version: 1.0 Final

2 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Mark schemes are prepared by the Lead Assessment Writer and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation events which all associates participate in and is the scheme which was used by them in this examination. The standardisation process ensures that the mark scheme covers the students responses to questions and that every associate understands and applies it in the same crect way. As preparation f standardisation each associate analyses a number of students scripts. Alternative answers not already covered by the mark scheme are discussed and legislated f. If, after the standardisation process, associates encounter unusual answers which have not been raised they are required to refer these to the Lead Assessment Writer. It must be stressed that a mark scheme is a wking document, in many cases further developed and expanded on the basis of students reactions to a particular paper. Assumptions about future mark schemes on the basis of one year s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular examination paper. Further copies of this mark scheme are available from aqa.g.uk Copyright 017 AQA and its licenss. All rights reserved. AQA retains the copyright on all its publications. However, registered schools/colleges f AQA are permitted to copy material from this booklet f their own internal use, with the following imptant exception: AQA cannot give permission to schools/colleges to photocopy any material that is acknowledged to a third party even f internal use within the centre.

3 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Glossary f Mark Schemes GCSE examinations are marked in such a way as to award positive achievement wherever possible. Thus, f GCSE Mathematics papers, marks are awarded under various categies. If a student uses a method which is not explicitly covered by the mark scheme the same principles of marking should be applied. Credit should be given to any valid methods. Examiners should seek advice from their seni examiner if in any doubt. M A B ft SC M dep B dep Method marks are awarded f a crect method which could lead to a crect answer. Accuracy marks are awarded when following on from a crect method. It is not necessary to always see the method. This can be implied. Marks awarded independent of method. Follow through marks. Marks awarded f crect wking following a mistake in an earlier step. Special case. Marks awarded f a common misinterpretation which has some mathematical wth. A method mark dependent on a previous method mark being awarded. A mark that can only be awarded if a previous independent mark has been awarded. Or equivalent. Accept answers that are equivalent. eg accept 0.5 as well as 1 [a, b] Accept values between a and b inclusive. [a, b) Accept values a value < b 3.14 Accept answers which begin 3.14 eg 3.14, 3.14, Use of brackets It is not necessary to see the bracketed wk to award the marks. 3

4 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Examiners should consistently apply the following principles Diagrams Diagrams that have wking on them should be treated like nmal responses. If a diagram has been written on but the crect response is within the answer space, the wk within the answer space should be marked. Wking on diagrams that contradicts wk within the answer space is not to be considered as choice but as wking, and is not, therefe, penalised. Responses which appear to come from increct methods Whenever there is doubt as to whether a student has used an increct method to obtain an answer, as a general principle, the benefit of doubt must be given to the student. In cases where there is no doubt that the answer has come from increct wking then the student should be penalised. Questions which ask students to show wking Instructions on marking will be given but usually marks are not awarded to students who show no wking. Questions which do not ask students to show wking As a general principle, a crect response is awarded full marks. Misread miscopy Students often copy values from a question increctly. If the examiner thinks that the student has made a genuine misread, then only the accuracy marks (A B marks), up to a maximum of marks are penalised. The method marks can still be awarded. Further wk Once the crect answer has been seen, further wking may be igned unless it gs on to contradict the crect answer. Choice When a choice of answers and/ methods is given, mark each attempt. If both methods are valid then M marks can be awarded but any increct answer method would result in marks being lost. Wk not replaced Erased crossed out wk that is still legible should be marked. Wk replaced Erased crossed out wk that has been replaced is not awarded marks. Premature approximation Rounding off too early can lead to inaccuracy in the final answer. This should be penalised by 1 mark unless instructed otherwise. Continental notation Accept a comma used instead of a decimal point (f example, in measurements currency), provided that it is clear to the examiner that the student intended it to be a decimal point. 4

5 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER B1 50% B1 3 1, B1 kg/m 3 B1 4 5

6 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 1x 8 May be seen in a grid their 1x x = 5 + their 8 10x = 3 their = x their 1x 3 = 10x ft Collecting two terms in x and two constant terms crectly eg 10x 3 = 0 ft M0 M0 with exactly one err Alternative method 5 x 5 4 3x their x = their x = their 5 4 = their x 3x Collecting two terms in x and two constant terms crectly eg 5 x 3 4 = = 5 x ft ft M0 M0 with exactly one err is on the next page 6

7 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 1x = x 5 10x = 3 x = 0.3 1x 8 = x 5 10x = 5 5 x = 10 M0 ft M0 ft 5 1x 8 = x 5 14x = 3 x = x 8 = x 5 14x = 13 x = 13 (two errs) 14 1x 8 = 8x 0 Any ft answer must be exact rounded truncated to at least dp The last two marks can be implied without the collection of terms seen eg 1x 6 = x 5 and answer 0.1 Collecting terms befe the bracket has been expanded M0 ft M0 A0ft M0A0 M0ft Zero 7

8 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Crect product using a point on the curve crect division using a point on the curve B1 eg 1 (= 4) 3 8 (= 4) (= 4) 6 4 (= 4) 10.4 (= 4) 4 = = (= 4) B0 6(a) (= 4) B0 3 4 = 4 B0 F multiplication, 4 ds not have to be shown Igne any units seen Igne any lines on the graph 8 3 = 4 and = 4 (choice) B0 area 6 and length 4 and volume 4 B0 8

9 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 Reading from 5 on the graph to give [4.7, 4.9] 1 6 h = [4.7, 4.9] [4.7, 4.9] ( 1 6) dep [1.56, 1.64] Alternative method 6(b) h 1 6 h h = ( 1 6) 1 6 h 5 = 4 15h = ( 6 5 ) 4 15 dep 1.6 9

10 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Enlargement B1 Scale fact ( ) 1 3 B1 Centre (5, 1) B1 7 Enlarge ( ) 1 3 (5, 1) B1B1B1 Reduction makes bigger unenlargement increase negative enlargement 1st B0 Any other transfmation mentioned implied such as reflection, rotation translation loses the mark f enlargement eg enlarged and moved up 4 enlarged and Do not accept 3 f scale fact 1st B0 nd B0 [0, 5] 0 + [5, 10] 48 + [10, 15] 30 + [15, 0] 1170 their dep Must add 4 products with 5 < x 10 on answer line MA0 Do not allow f wking in the table if a different method is used in wking lines 10

11 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 tan x = 3 7 tan sin x = sin x = 3(sin 90) (sin 90) 7 eg cos x = Any letter cos x = cos x = tan [66.7, 66.81] [3, 3.3] tan = 3 7 tan 3 7 tan 1 = 3 7 (unless recovered) M0 Answer [3, 3.3] (possibly coming from scale drawing) If using sine rule must rearrange to sin x = f If using cosine rule must rearrange to cos x = f Allow [0.4, 0.43] f 3 7 Allow.33 f 3 7 Allow [7.6, 7.6] f

12 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER n Answer line blank with 35 as next term in sequence Answer line has attempt at term to term rule nth term but 35 seen A0 35 seen on dotted line in sequence but a different answer given eg 50 A0 11 x x 1 B1 1

13 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER ( ) ( ) ( ) and 585.( ) and Comparable values and crect conclusion ft population area Accept a pair of consistent divisions eg and Crect comparable values from consistent divisions eg and Accept 700 with division seen f UK Accept 600 with division seen f Germany eg 673 and 585 and greater f UK and and greater f UK ft A0 and comparable values Igne further wk Comparable values means both must be in the same fm eg fractions with common denominats = = 5857 Germany is higher A0 ft Igne subtraction of results 673 and 585 and UK has me people per square mile ft 673 and 585 and Germany has me space f their population ft 673 and 585 and UK s population is less spread out ft 673 and 585 and UK is me than Germany ft 673 and 585 and UK is 78 me than Germany (igne further wk) ft continues on the next page 13

14 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER and 585 and the difference is 88 A0ft 673 and 585 and UK population is bigger A0ft 1 cont 673 and 586 and UK A0ft 673 and 585 and Germany has me space A0ft 673 > 585 (unless links to countries in wking) A0ft and and UK is greater (fractions not comparable) A0A0ft 14

15 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER , 1 3 B and 4 3 their (a) 8.4(375) seen, answer 8 3 of 11.5 (unless crectly evaluated) M , answer 6.38 (further wk) A , answer (further wk) A0 15

16 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 14(b) Ticks second box and [7.45, ] Ticks second box and crectly evaluates their Alternative method Ticks second box and valid comparison Bft B ft crect box ticked f comparing with their answer to (a) B1ft [7.45, ] with no increct decision Crectly evaluates their with no increct decision eg 1 8 and and (...)% 67% and 75% 9 8 and clear diagrams showing 3 and 3 4 B1 Ticks second box and incomplete comparison eg 1 8 and 4 3 two thirds is less than three quarters = and = Valid comparison (that would sce B) with no increct decision is on the next page 16

17 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 In Alt 1 only follow through their answer to (a) f the comparison, the wking f 3 their 11.5 must be crect (a) answer 6.5 (b) Ticks first box and 7.5 seen Bft Accept f 3 Using 0.6 f 3 B0 17

18 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method n f any positive integer n > 1 11 Alternative method Evaluates n f any positive integer n > 1 and dep dep 1.5 eg 101.5% Implied by 6090 Implied by 6181.( ) If showing trials f 10 and/ 11 years, must have = 6963.( ) and/ = 7067.( ) 7068 If showing totals from year on year f 10 and/ 11 years, must have (Y10) [6963.1, ] and/ (Y11) [ , ] 1.5 eg 101.5% Implied by 6090 If showing trials f n = 10 and/ 11 must have = [1.160, 1.161] and/ = [1.177, 1.178] is on the next page 18

19 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER Values f wking year on year Y = 6090 Y = Y = [674.07, ] Y4 [674.07, ] = [ , ] Y5 [ , ] = [ , ] Y6 [ , ] = [ , ] Y7 [ , ] = [ , ] Y8 [ , ] = [ , ] Y9 [ , ] = [ , ] Y10 [ , ] = [6963.1, ] Y11 [6963.1, ] = [ , ] Answer 11 with no wking M = 11.1 Answer 11 Zero 19

20 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 3y(3y ) 3y( 3y ) B B1 3(3y 3 y) y(9y 6) 3(y 3y 3 ) y(6 9y ) 3y(3y ) 3y( 3y ) followed by increct further wk eg 3y(3y ) = 3y (3y ) B1 16(a) 3y(3y ) = 3y( 3 y + ) ( 3 y ) B 3y(3y ) = 9y 3 6y (checking) 3y (3y ) B B 3 (3y 3 y) B1 y3(3y ) B1 (3x 1)(x 7) (1 3x)(7 x) B B1 (3x + a)(x + b) where ab = 7 a + 3b = (a 3x)(b x) where ab = 7 a + 3b = (3x + 1)(x + 7) B1 16(b) (3x 1)(x 7) B1 (3x 4)(x 6) B1 (7 3x)(1 x) B1 (10 3x)(4 x) B1 (3x 1) (x 7) B Igne any solutions seen eg (3x 1)(x 7) in wking with 3 1 and 7 on answer line B 0

21 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 sin 7 = 1 h 1 sin 7 cos (90 7) = 1 h 1 cos (90 7) h sin = 1 sin 90 Any letter 16 their 11.4 dep [18.4, ] 183 Alternative method h + (1 cos 7) = 1 h + (1 sin (90 7)) = 1 Any letter 17 1 (1 cos7) 1 (1 sin (90 7)) their 11.4 dep [18.4, ] 183 Alternative method sin eg sin 108 their 91.3 dep [18.4, ] sin 7 M0A0 sin = 1 h sin = 1 h (unless recovered) M0 1

22 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 A Bˈ B1 18(a) (A U B)ˈ B1 18(b) Alternative method 1 5w w 5w trials a value of w f 5w Any letter eg dep 5 18 A0 if 18 also given Alternative method 19 l 5 l l l trials a value of l f 5 Any letter eg dep 18 A0 if 18 also given Answer 18 M 18 in wking with 90 on answer line MA0 Trials f 5w l 5 without answer 18 M0A0

23 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 h = kv 5 = k : 10 1 (k =) (k =) h = v h = 0.05v 0 Crect value f k crect equation in h and v 0 their dep 1 4 implies ft ft their k and A0 Alternative method kh = v k 5 = : 5 (k =) 0 0h = v Crect value f k crect equation crect equation in h and v 4 their 0 dep 4 0 implies 8.8 ft ft their k and A0 Mark scheme continues on the next page is on the next page 3

24 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method : h 4 = 5 10 Crect equation in h 5 their 4 10 dep implies 8.8 ft ft their 4 10 and A0 Alternative method = h : Crect equation in h 5 their 10 4 dep implies 8.8 ft ft their 4 10 and A0 h α v with no further valid wking Zero h = kv h = kv 3 h = k v etc not recovered Zero Up to first two marks can be awarded f crect wking even if not subsequently used Allow use of other letters 4

25 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 1(a) Draws y = 3x and (x =) [ 0.1, 0.1] and (x =) [1.4, 1.6] B B1 Draws y = 3x states y = 3x ± 1 square tolerance f drawing graph Graph must be seen f x values from 0 to 1.5 Igne any y values seen Solutions from a non-graphical method B0 Igne other lines drawn on grid 5

26 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Full evaluation of method and answer B eg1 Cannot divide by x as it could be zero eg Should have factised and then he would have also found that x = 0 eg3 Should have used the fmula and then he would have also found that x = 0 eg4 Should have used a graphical method then he would have also found that x = 0 eg5 Should have completed the square then he would have also found that x = 0 1(b) B1 Partial evaluation eg1 x = 0 has been omitted eg Should have factised eg3 Should have used the fmula eg4 Should have drawn a graph eg5 Only found one solution eg6 Cannot divide by zero F B there needs to be an evaluation of the method and an indication that x = 0 has been omitted from the answer x(x + 5) = 0 x = 0 and x =.5 Should be two solutions What about x = 0 The answer is wrong B B1 B1 B0 Igne non-contradicty further wk 6

27 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 1 ( ) π π 31.5π [196.5, 1964] [981, 98] π π [45, 45.45] Area of circle semicircle radius 5 area of circle radius (6 ) May be seen in two steps eg their π dep on M 360 π 1 1 their 150 dep Area of sect 60π [188.4, 188.5] their [188.4, 188.5] their [981, 98] [0.19, 0.19] ( 100) dep dep on M3 their [981, 98] must be the [19, 19.] area of semicircle radius 5 [19, 19.] and No [0.19, 0.19] and 0. and No Mark scheme continues on the next page 7

28 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 ( ) π π 31.5π [196.5, 1964] [981, 98] π π [45, 45.45] Area of circle semicircle radius 5 area of circle radius (6 ) May be seen in two steps eg their π π 1 1 their 150 dep dep on M Area of sect 60π [188.4, 188.5] their [188.4, 188.5] 5 [94, 94.6] dep dep on M3 [94, 94.6] and [981, 98] and No eg 300π and 31.5π and No Mark scheme continues on the next page is on the next page 8

29 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 3 1 ( ) π π 31.5π [196.5, 1964] [981, 98] π π [45, 45.45] 0. their [981, 98] 6.5π [196., 196.4] dep Area of circle semicircle radius 5 area of circle radius 1 dep on 1st their [981, 98] must be the area of semicircle radius (6 ) May be seen in two steps eg their π π 1 1 their 150 dep dep on 1st and 3rd Area of sect 60π [188.4, 188.5] [188.4, 188.5] and [196., 196.4] and No eg 60π and 6.5π and No Alt 3 0% of [981, 98] ds not sce nd unless evaluated crectly 9

30 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method May be implied by crect labelling on vertical axis Draws block f 65 x < 80 with height 8 small squares Alternative method Mark intention 1 (30 6) their Draws block f 65 x < 80 with height 8 small squares dep Mark intention 3(a) Alternative method 3 1 (30 150) their Draws block f 65 x < 80 with height 8 small squares Alternative method 4 dep Mark intention 1.5 (30 6) their dep Draws block f 65 x < 80 with height 8 small squares Mark intention Draws block f 65 x < 80 with height 8 small squares 3 marks 30

31 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 3(b) (30 6) (30 6) 180 (30 6) (30 6) 50 (30 6) (30 6) May be seen on histogram

32 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method (7 8) (7 8) 9 07 dep May be seen on graph M 0.5 (7 + 19) 9 07 and Yes Alternative method May be seen on graph 00 their dep 9 6. and Yes 18. and 19 and Yes 4 Alternative method May be seen on graph 00 their and Yes dep 19 Alternative method May be seen on graph Attempt at total distance f Beth f 6.. total time < 7 Crect total distance f Beth f 6.. total time < 7 and Yes dep eg (time 6.5s) (6.5 8) 9 eg (time 6.5s) 0.5 and Yes 3

33 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER B1 Allow f B1 Allow f 6.45 Allow f.65 their 6.35 their Must use their lower bounds f lengths their 6.35 must be [6.3, 6.4) their.55 must be [.5,.6) 5 their their dep Must use their upper bound f fce their bound must be (345, 350] 1.46 Must come from ( ) ( ) ( ) = 1.46 B0B1A ds not sce any marks if no wking is seen 33

34 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 Shows that CB ( BC) is equal and parallel to DE ( ED) ( CB =) (b a) b a ( BC =) b a + b + a ( CB =) a 3b ( BC =) 3b a CB is equal and parallel to DE method Must see crect method f CB BC Must see a crect vect f first and have a statement eg CB is equal and parallel to ED Alternative method Shows that BE ( EB) is equal and parallel to CD ( DC) 6 ( BE =) a + b ( CD =) (b a) (a 3b) ( EB =) a b ( DC =) (a 3b) + (b a) method ( BE =) a + b and ( CD =) a + b Must see crect method f CD DC eg ( BE =) a + b and ( DC =) a b ( EB =) a b and ( DC =) a b BE is equal and parallel to CD Must see two crect vects f first and have a statement eg BE is equal and parallel to DC Mark scheme continues on the next page 34

35 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 3 Shows that two pairs of opposite sides are parallel ( CB =) (b a) b a ( BC =) b a + b + a ( BE =) a + b ( CD =) (b a) (a 3b) ( EB =) a b ( DC =) (a 3b) + (b a) method 6 ( CB =) a 3b ( BC =) 3b a ( BE =) a + b and ( CD =) a + b Must see crect method f CB BC CD DC eg ( BE =) a + b and ( DC =) a b ( EB =) a b and ( DC =) a b ( CB =) a 3b and ( BE =) a + b and ( CD =) a + b and CB is parallel to DE and BE is parallel to CD Must see three crect vects and have two statements eg ( BC =) 3b a and ( BE =) a + b and ( DC =) a b and BC is parallel to DE and BE is parallel to DC Mark scheme continues on the next page is on the next page 35

36 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 4 Shows that two pairs of opposite sides are equal 6 ( CB =) (b a) b a ( BC =) b a + b + a ( BE =) a + b ( CD =) (b a) (a 3b) ( EB =) a b ( DC =) (a 3b) + (b a) ( CB =) a 3b ( BC =) 3b a ( BE =) a + b and ( CD =) a + b ( EB =) a b and ( DC =) a b ( CB =) a 3b and ( BE =) a + b and ( CD =) a + b and CB is equal to DE and BE is equal to CD Must see crect method f CB BC CD DC eg ( BE =) a + b and ( DC =) a b Must see three crect vects and have two statements eg ( BC =) 3b a and ( BE =) a + b and ( DC =) a b and BC is equal to DE and BE is equal to DC Choose the method that gives most marks Igne increct vects if not contradicty F parallel allow in the same direction in the opposite direction F equal to allow = the same as Condone increct notation if unambiguous eg CB = (b a) b a 36

37 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 Alternative method 1 x(x + ) x + x x 4 8x 4(x + ) 4x + 8 x(x + ) x + x and x 4 8x dep eg x( x ) x 4 4( x ) and 4(x + ) 4x x(x + ) x 4 = 4(x + ) dep equation with fractions eliminated dep on M x 10x 8 (= 0) 3-term quadratic equation with terms collected 10 ( 10) Crect f their 3-term quadratic Allow crect factisation of their 3-term quadratic 5 ± ± 33 [10.744, ] and [ 0.745, 0.744] and 0.74 with x 10x 8 (= 0) seen Must both be to decimal places Mark scheme continues on the next page 37

38 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 x x Alternative method (from = 1 + ) 4 x x(x + ) x + x (x + ) + x 3x + 1x + 8 x( x ) 4 x x 4 and dep x x x 3x x 7 x(x + ) = 4(x + + x) dep equation with fractions eliminated dep on M x(x + ) = 4(3x + ) x 10x 8 (= 0) 3-term quadratic equation with terms collected 10 ( 10) Crect f their 3-term quadratic Allow crect factisation of their 3-term quadratic 5 ± ± 33 [10.744, ] and [ 0.745, 0.744] and 0.74 with x 10x 8 (= 0) seen Must both be to decimal places Mark scheme continues on the next page is on the next page 38

39 MARK SCHEME GCSE MATHEMATICS 8300/H NOVEMBER 017 x x Alternative method 3 (from 1 = ) 4 x x 4 4 (x 4)(x + ) x 4x + x 8 x x 8 and dep x 4 8x (x 4)(x + ) = x 4 equation with fractions eliminated dep dep on M x 4x + x 8 = 8x x 10x 8 (= 0) 3-term quadratic equation with terms collected 7 10 ( 10) Crect f their 3-term quadratic Allow crect factisation of their 3-term quadratic 5 ± ± 33 [10.744, ] and [ 0.745, 0.744] and 0.74 with x 10x 8 (= 0) seen Must both be to decimal places and 0.74 from T & I with no wking 6 marks from T & I with no wking Zero In quadratic fmula, do not allow 10 f ( 10) unless recovered 39

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