Polynomials. Polynomials. Curriculum Ready ACMNA:
|
|
- Hugh Webster
- 5 years ago
- Views:
Transcription
1 Polynomils Polynomils Curriulum Redy ACMNA: 66
2
3 Polynomils POLYNOMIALS A polynomil is mthemtil expression with one vrile whose powers re neither negtive nor frtions. The power in eh expression is non-negtive integer. Answer these questions, efore working through the hpter. I used to think: Wht is the degree nd leding oeffiient of polynomil? If n expression is divided y ftor, then wht is the reminder? How do the ftors of polynomil relte to its solution in n eqution? Answer these questions, fter working through the hpter. But now I think: Wht is the degree nd leding oeffiient of polynomil? If n expression is divided y ftor, then wht is the reminder? How do the ftors of polynomil relte to its solution in n eqution? Wht do I know now tht I didn t know efore? 100% Polynomils Mthletis 100% 3P Lerning K 1 1 SERIES TOPIC
4 Polynomils Bsis Wht is Polynomil? It is lredy known tht inomil ontins two terms (eg. x + ) nd trinomil ontins three terms (eg. x + x + ). Now, polynomil n hve ny numer of terms, ut there re few rules. Here is generl polynomil: The highest power is lled the degree of the polynomil The powers must e non-negtive intergers. no frtions, no negtive numers A polynomil n only hve one vrile (x) Px () x n n n-1 n- = + n -1x + n -x x + x+ 1 0 The oeffiient of the highest power (n ) is lled the leding oeffiene 1 to n re the oeffiients of the polynomil. The oeffiients n y ny rel numer This is onstnt term If the leding oeffiient (n) is 1, then the polynomil is lled moni. The P(x) mens the polynomil is lled P nd is in terms of the vrile x. Here re some exmples. Answer the following questions out P(x) nd Q(x) elow: d 4 6 Px () = x - 5x + 3x - x+ 7 Qx () x nd = - x + 4x -8x - 3x + 6x- Wht is the degree of eh polynomil? The degree (highest power) of P(x) is 4. The degree (highest power) of Q(x) is 6. Wht is the leding oeffiient of eh polynomil? The leding oeffiient of P(x) is. The leding oeffiient of Q(x) is 1. Whih polynomil is moni? Q(x) is moni euse it hs leding oeffiient of 1. Wht is the onstnt term of eh polynomil? The onstnt term of P(x) is 7. The onstnt term of Q(x) is -. In the nottion of polynomils, the vrile is written inside rkets. Just like P(x). If nything else is written inside the rket, sustitute this vlue into eh vrile. Here is n exmple. Find the following vlues if P^xh= x - 4x + 3x + 5 P( ) P( - 1) P^h = ^h - 4^h + 3^h+ 5 = = 11 P^- 1h= ( -1) -4(- 1) + 3^- 1h+ 5 = =-4 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
5 Polynomils Questions Bsis 1. Explin why the following re not polynomils. 4x - + x+ 1 3x 3 - x - 1 x 3-7x -5 d x + y+ 3 e 3 x + x + 6 f 1 4x x x 100% Polynomils Mthletis 100% 3P Lerning K 3 1 SERIES TOPIC
6 Polynomils Questions Bsis 5 4. Anwser the following questions out P^xh =- 3x + 8x - x + 4x+ 6 nd R^th = t - t + t - 5. Wht is the onstnt term in eh polynomil? Wht is the leding oeffiient in eh polynomil? Are either of the polynomils moni? d Wht is the degree of eh polynomil? e Find P( - 1). f Find P( ). g Find R (1). h Find R (3). 4 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
7 Polynomils Bsis Adding nd Sutrting Polynomils? When dding nd sutrting polynomils, simply ollet like terms. Let P^xh= x 5 + x 4-3x 3 + 7x -6x- 1 nd Q^xh=- x 6 + x 5 + 7x 4 + 5x x - 8x + 4 Find P^xh+ Qx ^ h Px ^ h+ Qx ^ h= ^x + x - 3x + 7x -6x- 1h+ ^- x + x + 7x + 5x + 10x - 8x + 4h = x + x - 3x + 7x -6x-1- x + x + 7x + 5x + 10x - 8x =- x + ^x + x h+ ^x + 7x h+- ^ 3x + 5x h+ ^7x + 10x h+ ^-6x- 8xh+- ^ 1+ 4h =- x + 3x + 9x + x + 17x - 14x + 3 Find P^xh- Qx ^ h Px ^ h- Qx ^ h= ^x + x - 3x + 7x -6x-1h-^- x + x + 7x + 5x + 10x - 8x + 4h = x + x - 3x + 7x -6x- 1+ x -x -7x -5x - 10x + 8x = x + ^x - x h+ ^x - 7x h+ ^-3x - 5x h+ ^7x - 10x h+- ^ 6x+ 8xh+ ^-1-4h = x -x -5x -8x - 3x + x- 5 Multiplying Polynomils Use the distriutive lw to multiply polynomils. Let P^xh=- 3x+ 4 nd Q^xh= x - 3x + 1. Find P^xh# Qx ^ h. Px ^ h# Qx ^ h= ^- 3x+ 4h^x - 3x + 1h =-3x^x - 3x+ 1h+ 4 ^ x - 3x + 1h = ^- 6x + 9x - 3xh+ ^8x - 1x + 4h =- 6x + ^9x + 8x h +- ^ 3x- 1xh + 4 Find Q^xh# Px ^ h. =- 6x + 17x - 15x + 4 Qx ^ h# Px ^ h= ^x - 3x+ 1h^- 3x + 4h = x ^- 3x+ 4h-3x^- 3x+ 4h+ 1^- 3x + 4h = ^- 6x + 8x h+ ^9x - 1xh+ ^- 3x + 4h =- 6x + ^8x + 9x h +- ^ 1x- 3xh + 4 =- 6x + 17x - 15x + 4 So Px ()# Qx () = Qx ()# Px (). This is lwys true! Sometimes Px ()# Qx () is written s Px (): Qx () 100% Polynomils Mthletis 100% 3P Lerning K 5 1 SERIES TOPIC
8 Polynomils Questions Bsis Simplify ^x + 4x - x + 5x+ 9h+ ^x - 3x + h. 4. Let T^xh= x 5 + 3x 4 - x 3 + 3x - x+ 3 nd Q^xh = 3x 5 - x 4 + 6x 3 + 7x - 4x+ 5. Find T^xh+ Qx ^ h. Let Sx ^ h= Tx ^ h+ Qx ^ h. Find S^-1h. Find T^- 1h+ Q^-1h. Wht do you notie? 6 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
9 Polynomils Questions Bsis 5. Use Tx ( ) nd Q^xh in the previous question to nswer these questions: Let D^xh= Tx ^ h-qx ^ h. Find D^h. Does D^h= T^h -Q( )? Wht is the degree, leding oeffiient nd onstnt term of D^xh? 100% Polynomils Mthletis 100% 3P Lerning K 7 1 SERIES TOPIC
10 Polynomils Questions Bsis 6. Let P^xh= x + 1 nd Q^xh = 3x -x - 5. Find P^xh: Qx ^ h. Find P^h: Q^h. Wht is the degree, leding oeffiient nd onstnt term of P^xh: Qx ^ h? 8 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
11 Polynomils Questions Bsis 3 7. Let M^yh= 3y- nd N^yh = 4y - y + 3. Find M^-3h nd N^-3h. Find M^-3 h# N( -3). Let Ay ^ h= My ^ h# Ny (). Find Ay (). d Find A( - 3). Is this the sme s M( -3)# N( - 3)? e Wht is the degree, leding oeffiient nd onstnt term of Ay ^ h? 100% Polynomils Mthletis 100% 3P Lerning K 9 1 SERIES TOPIC
12 Polynomils Knowing More Dividing Polynomils Polynomil division is sed on long division. Using long division to find 13' 5: Quotient g Divisor It is esy to see tht 13 = 5^4h + 3. This is lwys true: Dividend = Divisor # Quotient + Reminder. Dividend Reminder Here is n exmple using polynomils: Rewrite the dividend in terms of the divisor, quotient nd reminder. Quotient Divisor x - x + 1 r 6 x+ 4 x + x - 7x+ 10 g Reminder Dividend so x + x - 7x+ 10 = ( x+ 4)( x - x+ 1) + 6 The question is: How is this quotient found? It is found with long division using the sme proess s the numers ove: Find this quotient using long division: Step 1: Divide x 3 (first term of dividend) y x (first term of the divisor). This gives the first term of the quotient. ( x + x - 7x+ 10) ' ( x+ 4) Step : Multiply x y x + 4 (divisor) nd sutrt it from the dividend Step 3: ring the - 7x (the next term) down Dividend Quotient Divisor Step 4: Divide x - (first term of new dividend) y x (first term of the divisor) nd write this in the quotient. Step 5: Multiply x + 4 (divisor) y - x (the new quotient term) nd sutrt from -x - 7x (the new dividend) Step 6: ring the + 10 (the next term) down Step 7: Divide x (first term of new dividend) y x (first term of divisor) nd write this in the quotient Step 8: Multiply 1 y x + 4 (divisor) nd sutrt from x + 10 (new dividend) Step 9: Stop when the differene is onstnt (6 in this exmple) x - x+ 1 x+ 4 x + x - 7x+ 10 g x + 4x -x -7x -x -8x x + 10 x Reminder ` x + x - 7x+ 10 = ( x+ 4)( x - x+ 1) + 6 Dividend = Divisor # Quotient + Reminder 10 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
13 Polynomils Knowing More After eh step the expression under the dividend eomes the new dividend. The divisor never hnges. Here is nother exmple: Find ^x 3 + 3x-3x-h' ( x- 3) 3 Step 1: Divide x y x. This gives the first term of the quotient. Step : Multiply x y x- 3 (divisor) nd sutrt it from the dividend Step 3: ring the - 3x (the next term) down Step 4: Divide 6x (first term of new dividend) y x (from divisor) nd write in the quotient. Step 5: Multiply x + 3 y 3x (new quotient) nd sutrt from 6x - 3x (new dividend) Step 6: ring the - (the next term) down x + 3x + 3 x- x + 3x -3x- g x - 3x 6x - 3x 6x - 9x 6x - 6x So x + 3x -3x- = (x- 3)( x + 3x+ 3) + 7 Step 7: Divide 6x (first term of new dividend) y x (first term of divisor) nd write this in the quotientt Step 8: Multiply 3 y x - 3 (divisor) nd sutrt from 6x - (new dividend) Step 9: Stop when the differene is onstnt (7 in this exmple) Now this eomes prtiulrly interesting when the reminder is zero. If the reminder is zero, then the divisor is tully ftor of the dividend. This is euse if the reminder is zero then there is tully no reminder, whih mens the divisor would hve to e ftor. Is ^x + 3h or ^x - 3h ftor of x + x -10x - 6? Divide x + x -10x - 6 y x + 3 nd then y x - 3 nd see whih quotient hs reminder of zero: x -x - 1 x+ 3 x + x -10x-6 g x + 3x -x -10x -x - 9x -x -6 -x -3-3 x + 4x + x- 3 x + x -10x-6 g x + 3x 4x - 10x 4x - 1x x - 6 x So x + x -10x- 6 = ( x+ 3)( x -x-1) -3 So x + x -10x- 6 = ( x- 3)( x + 4x+ ) There is reminder of -3 There is no reminder ` x + 3 is not ftor ` x - 3 is ftor 100% Polynomils Mthletis 100% 3P Lerning K 11 1 SERIES TOPIC
14 Polynomils Questions Knowing More 1. Use the following to nswer the questions elow: 3x + x + 5 r 11 x-1 3x - x + 4x+ 6 g Wht is the divisor? Wht is the reminder? Wht is the dividend? d Wht is the quotient?. Find these quotients (rewrite s Dividend = Divisor # Quotient + Reminder). ( x - 3x + 4x-5) ' ( x- ) (x + 5x + x- 1) ' ( x+ 4) 1 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
15 Polynomils Questions Knowing More 3. Find the following quotient: 4 x - x + 5x - 6x+ 8 x - 1 Rememer = ' 4 Complete the following: x - x + 5x - 6x+ 8 = ( x - 1)( ) + 100% Polynomils Mthletis 100% 3P Lerning K 13 1 SERIES TOPIC
16 Polynomils Questions Knowing More 4. How do you know if divisor is ftor? 5. Show tht x + 7 is ftor of x + 17x + 0x Show tht x - 4 is ftor of 6x - 8x + 4x K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
17 Polynomils Using Our Knowledge The Reminder Theorem Here is some stndrd mthemtil nottion: Let Px ^ h= dividend Qx () + Let Qx ^ h= quotient x- g Px () Let x- = divisor, where is ny onstnt Let = reminder. The reminder will lwys e onstnt if the divisor is liner. Now So this mens nd for P^h Dividend = Divisor # Quotient + Reminder Px ^ h = ^x- hqx ^ h + P ^ h = ^- hq ^ h + = 0. Q ^ h + = So P^h is the reminder of Px ^ h ' ( x- ). This mens the reminder n e found without doing long division. Here re some exmples Find the reminder of the following quotient ^x + x - 3x+ 8h' ( x-) Let Px ^ h= x + x - 3x + 8 Thedivisor is x-. ` =. P^h= + ^ h - 3 ^ h + 8 = 18 ` ^x + x - 3x+ 8h ' ( x-) hs reminder of 18. Find the reminder of the following quotient ^x + x - 3x+ 8h' ( x+ ) Let Px ^ h= x 3 + x - 3x + 8 The divisor is x+, or x-^- h. ` =-. = 14 ` ^x + x - 3x+ 8h ' ( x+ ) hs reminder of 14. P^- h= (- ) + ( -) -3^- h % Polynomils Mthletis 100% 3P Lerning K 15 1 SERIES TOPIC
18 Polynomils Questions Using Our Knowledge 1. Find the reminder of ^x + 3x -6x-8h ' d^xh if: dx ^ h= x -3. dx ^ h= x + 1. dx ^ h= x +. d dx ^ h= x -. e dx ^ h= x -7. f dx ^ h= x + 4. g Whih divisors ove re ftors? (leve reminder of 0) 16 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
19 Polynomils Using Our Knowledge The Ftor Theorem Rememer it is ftors we re interested in, nd ftors use reminder to e zero. The reminder theorem sys tht the vlue of P^h is the reminder of Px ^ h ' ( x- ). So if P ^ h = 0 then the reminder of Px ()'( x- ) is 0. This mens ^x- h would e ftor. The Ftor theorem sttes: ^x- h is ftor of P^xh if nd only if P ^ h = 0. Here is n exmple: Find ftor of x + 3x -6x -8 Let Px () = x + 3x -6x -8 =-10 ` P() 1! 0 ` P() 1 = () -61 ()-8 ` ` P( - 1) = (- 1) + 3( -1) -6(-1)-8 = 0 P( - 1) = 0 ` x - 1 is not ftor ` x-- ^ 1h= x+ 1is ftor Use tril nd error to find the vlue for so tht P ^ h = 0. Try = 1, then =- 1, then =, then =- nd so on. Find ftor for x + 4x -11x-30 nd perform long division to ftorise it into three rkets with no reminder Let Px ^ h= x + 4x -11x -30 P^1 h =-36. So x - 1 is not ftor of P^xh P^- 1h =-16. So x-- ^ 1h = x+ 1 is not ftor of P^xh P^ h =-8. So x - is not ftor P^- h = 0. So x-- ^ h = x+ is ftor x + x - 15 x+ g x + 4x -11x-30 x 3 + x x - 11x x + 4x -15x x ` ` Px () = ( x+ )( x + x -15) Px () = ( x+ )( x- 3)( x + 5) This n e ftorised like n ordinry qudrti trinomil 100% Polynomils Mthletis 100% 3P Lerning K 17 1 SERIES TOPIC
20 Polynomils Questions Using Our Knowledge. Answer the following questions out P^xh = x -x - 9x Find the vlue of: P() 1 P( -1) Is ^x - 1h or ^x + 1h ftor of P^xh? Use long division with the ftor ove to ftorise P^xh into three rkets. 18 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
21 Polynomils Questions Using Our Knowledge 3. Find liner ftor for these polynomils: 3x + 8x - 33x + 10 x + 19x + 3x - 1 x -3x -65x % Polynomils Mthletis 100% 3P Lerning K 19 1 SERIES TOPIC
22 Polynomils Questions Using Our Knowledge 4. Ftorise the following into three rkets with no reminder. 3x - 19x + 16x + 0 4x -5x - 47x K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
23 Polynomils Thinking More Ftorising Polynomils Dividing polynomils, the ftor theorem nd the reminder theorem re used to ftorise polynomils into rkets. This n e done for polynomil with ny degree (highest power). Here is n exmple with degree 4 polynomil. Ftorise this polynomil into liner ftor rkets: P^xh= x 4 + 3x 3-15x - 19x+ 30 P^1 h = 0 nd so ^x - 1h is ftor of P^xh. x + 4x -11x x- 1g x + 3x -15x - 19x x - x 4x - 15x 4x - 4x -11x -19x - 11x + 11x - 30x x + 30 There is no reminder, s we expeted 0 So ording to P^x h = Divisor # Quotient + Reminder Px () = ( x- 1)( x + 4x -11x- 30) Needs to e ftorised gin Let Ax ^ h= x + 4x -11x -30 A^- h = 0 nd so ^x + h is ftor of Ax ^ h x + x - 15 x+ g x + 4x -11x-30 x 3 + x x - 11x x + 4x -15x x -30 There is no reminder, s we expeted 0 So Ax ^ h = ^x+ h^x + x -15h This mens P^xh = ^x- 1h^x+ h^x + x- 15h Ftorise s qudrti Px ^ h = ^x- 1h^x+ h^x- 3h^x+ 5h Whih hs een ftorised into 4 rkets of liner ftors. 100% Polynomils Mthletis 100% 3P Lerning K 1 1 SERIES TOPIC
24 Polynomils Thinking More Polynomil Equtions The whole point of ftorising polynomils is to solve polynomil equtions. Here is n exmple. Solve the following eqution 4 x + 3x -15x - 19x+ 30 = 0 From the previous exmple the polynomil n e ftorised to eome: ^x- 1h^x+ h^x- 3h^x+ 5h= 0 ` x - 1 = 0 x + = 0 x - 3 = 0 x + 5 = 0 or or or x = 1 x =- x = 3 x =-5 When ftorising using long division, e reful not to leve out power. Look t this exmple: Solve this eqution Let Px ^ h= x - 1x+ 0 3 P^1 h = 0 so x-1 is ftor of P^xh. x 3-1x+ 0 = 0 Notie, there is no x term inp^xh. No power n e left out of long division, so rewrite Px ^ h = x + 0x - 1x+ 0. x 3-1x+ 0 = 0 ` ( x- 1) ^x + x - 0h= 0 x + x - 0 x- 1g x + 0x - 1x+ 0 x - x x x - 1x - x - 0x + 0-0x There is no reminder, s we expeted Ftorise s qudrti ` ( x-1) ^x- 4h^x + 5h= 0 ` x = 1 or x = 4 or x =-5 When solving polynomil equtions, follow these three steps. Step 1. Mke sure the right hnd side is 0 Step. Rewrite the polynomil to inlude missing powers Step 3. Ftorise. K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
25 Polynomils Questions Thinking More 1. Let P^xh= x -5x - 18x + 7. Find numer so tht P ^ h = 0. Bsed on, find liner ftor of P^xh. Ftorise P^xh. d Solve the eqution x -5x - 18x + 7 = % Polynomils Mthletis 100% 3P Lerning K 3 1 SERIES TOPIC
26 Polynomils Questions Thinking More 4. Let P^xh = x + x -13x - 14x+ 4. Given tht P^- h = 0, ftorise P^xh into four liner ftors. 4 Solve the eqution x + x -13x - 14x+ 4 = 0. 4 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
27 Polynomils Questions Thinking More 3. Solve x -x - 15x + 36 = 0 y ftorising. 100% Polynomils Mthletis 100% 3P Lerning K 5 1 SERIES TOPIC
28 Polynomils Questions Thinking More 4. Solve x + 3x - 4 = 0 y ftorising. (Be reful of the missing power) 6 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
29 Polynomils Questions Thinking More 5. Solve x + 8x -10x- 40 = x + 4x + 8 y ftorising. Hint: move everything to one side nd equl to 0 first. 100% Polynomils Mthletis 100% 3P Lerning K 7 1 SERIES TOPIC
30 Polynomils Answers Bsis: 1. The first term hs negtive power -, 5. so the expression is not polynomil. d The first term hs frtionl power 3, so the expression is not polynomil. The power in the first term 3 x is not neessrily n integer, so the expression in not polynomil. The polynomil must hve only one vrile. This expression hs x nd y. 6. Bsis: D^h=-30 Yes, D^h= T^h-Q^h The degree of D(x) is 5 Leding oeffiient is -1 Constnt term is - 3x -x -x -x e f The expression hs frtionl index so it is not polynomil. The first term of the expression hs negtive power so it is not polynomil. 7. The Degree is 4 The leding oeffiient is 3 The onstnt term is 5. M( - 3) =-11. Px ^ h: 6 R^th: -5 N^- 3h=-10 Px ^ h: -3 R^th: 1 11 d Px ^ h : No, the leding oeffiient is not 1 R^th : Yes, the leding oeffiient is 1 Px ^ h :5, the vlue of the highest power R^th :4, the vlue of the highest power d 4 1y -8y - 3y + 11y-6 A^- 3h= 11 A(-3) is the sme s M^-3h# N^-3h e g P( - 1) =- 5 f P( ) =-6 R() 1 =- 3 h R( 3) = 67 e The degree is 4 The leding oeffiient is 1 The onstnt term is x + 5x -x - 3x + 5x + 11 Knowing More: x + x + 4x + 10x - 6x + 8 S^- 1h= 16 T^- 1h+ Q^- 1h= 16 Notie T^- 1h+ Q^- 1h= S^-1h 1. d x - 1 is the divisor 11 is the reminder 3x - x + 4x + 6 is the dividend 3x + x+ 5 is the quotient 8 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
31 Polynomils Answers Knowing More: Using Our Knowledge:. ^x - 3x + 4x-5h ' ^x-h 3. x - = ^x-h # ^x - x + h -1 x + 3 ^x + 5x + x- 1h ' ^x+ 4h x + 4 = ^x+ 4h^x - 3x + 13h Px ^ h = ^x- h^3x+ h^x -5h 3. 4 x - x + 5x - 6x+ 8 Px ^ h = ^x+ 3h^4x-1h^ x -4h = ^x-1h^x - x + 4x- h + 6 Thinking More: 4. A divisor is ftor if the reminder is zero. 1. P( 3) = 0 5. x + 7 is ftor of x + 17x + 0x - 7 euse when x + 17x + 0x - 7 is divided y x + 7, the reminder is zero. d x - 3 is liner ftor. Px () = ^x-3h^x- 6h^x + 4h x = 3, x = 6 nd x =-4 6. x - 4 is ftor of 6x - 8x + 4x - 4 euse when 6x - 8x + 4x - 4 is divided y x - 4, the reminder is zero.. Px () = ^x+ h^x- 1h^x+ 4h^x- 3h x = 1 or x = 3 or x =- or x =-4 1. Using Our Knowledge: x = 3 or x = 3 or x =-4 8 d 0 4. x = 1 or x =- or x =- e 440 g ^x + 1h, ^x + 4h nd ^x - h re ftors. f 0 5. x =- or x =- 8 or x = 3. P() 1 = 0 P( - 1) = 56 x - 1 is ftor of P^xh sine P() 1 = 0 ^x-1h^x- 6h^x + 5h 100% Polynomils Mthletis 100% 3P Lerning K 9 1 SERIES TOPIC
32 Polynomils Notes 30 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
33 Polynomils Notes 100% Polynomils Mthletis 100% 3P Lerning K 31 1 SERIES TOPIC
34 Polynomils Notes 3 K 1 100% Polynomils SERIES TOPIC Mthletis 100% 3P Lerning
35
36 Polynomils
K 7. Quadratic Equations. 1. Rewrite these polynomials in the form ax 2 + bx + c = 0. Identify the values of a, b and c:
Qudrti Equtions The Null Ftor Lw Let's sy there re two numers nd. If # = then = or = (or oth re ) This mens tht if the produt of two epressions is zero, then t lest one of the epressions must e equl to
More informationFactorising FACTORISING.
Ftorising FACTORISING www.mthletis.om.u Ftorising FACTORISING Ftorising is the opposite of expning. It is the proess of putting expressions into rkets rther thn expning them out. In this setion you will
More informationSurds and Indices. Surds and Indices. Curriculum Ready ACMNA: 233,
Surs n Inies Surs n Inies Curriulum Rey ACMNA:, 6 www.mthletis.om Surs SURDS & & Inies INDICES Inies n surs re very losely relte. A numer uner (squre root sign) is lle sur if the squre root n t e simplifie.
More informationProject 6: Minigoals Towards Simplifying and Rewriting Expressions
MAT 51 Wldis Projet 6: Minigols Towrds Simplifying nd Rewriting Expressions The distriutive property nd like terms You hve proly lerned in previous lsses out dding like terms ut one prolem with the wy
More informationLogarithms LOGARITHMS.
Logrithms LOGARITHMS www.mthletis.om.u Logrithms LOGARITHMS Logrithms re nother method to lulte nd work with eponents. Answer these questions, efore working through this unit. I used to think: In the
More informationChapter 8 Roots and Radicals
Chpter 8 Roots nd Rdils 7 ROOTS AND RADICALS 8 Figure 8. Grphene is n inredily strong nd flexile mteril mde from ron. It n lso ondut eletriity. Notie the hexgonl grid pttern. (redit: AlexnderAIUS / Wikimedi
More information1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the
More informationNon Right Angled Triangles
Non Right ngled Tringles Non Right ngled Tringles urriulum Redy www.mthletis.om Non Right ngled Tringles NON RIGHT NGLED TRINGLES sin i, os i nd tn i re lso useful in non-right ngled tringles. This unit
More informationAlgebra Basics. Algebra Basics. Curriculum Ready ACMNA: 133, 175, 176, 177, 179.
Curriulum Redy ACMNA: 33 75 76 77 79 www.mthletis.om Fill in the spes with nything you lredy know out Alger Creer Opportunities: Arhitets eletriins plumers et. use it to do importnt lultions. Give this
More informationSIMPLE NONLINEAR GRAPHS
S i m p l e N o n l i n e r G r p h s SIMPLE NONLINEAR GRAPHS www.mthletis.om.u Simple SIMPLE Nonliner NONLINEAR Grphs GRAPHS Liner equtions hve the form = m+ where the power of (n ) is lws. The re lle
More informationTutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4.
Mth 5 Tutoril Week 1 - Jnury 1 1 Nme Setion Tutoril Worksheet 1. Find ll solutions to the liner system by following the given steps x + y + z = x + y + z = 4. y + z = Step 1. Write down the rgumented mtrix
More information20 MATHEMATICS POLYNOMIALS
0 MATHEMATICS POLYNOMIALS.1 Introduction In Clss IX, you hve studied polynomils in one vrible nd their degrees. Recll tht if p(x) is polynomil in x, the highest power of x in p(x) is clled the degree of
More informationNumbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point
GCSE C Emple 7 Work out 9 Give your nswer in its simplest form Numers n inies Reiprote mens invert or turn upsie own The reiprol of is 9 9 Mke sure you only invert the frtion you re iviing y 7 You multiply
More informationChapter Gauss Quadrature Rule of Integration
Chpter 7. Guss Qudrture Rule o Integrtion Ater reding this hpter, you should e le to:. derive the Guss qudrture method or integrtion nd e le to use it to solve prolems, nd. use Guss qudrture method to
More informationBases for Vector Spaces
Bses for Vector Spces 2-26-25 A set is independent if, roughly speking, there is no redundncy in the set: You cn t uild ny vector in the set s liner comintion of the others A set spns if you cn uild everything
More informationTrigonometry Revision Sheet Q5 of Paper 2
Trigonometry Revision Sheet Q of Pper The Bsis - The Trigonometry setion is ll out tringles. We will normlly e given some of the sides or ngles of tringle nd we use formule nd rules to find the others.
More information( ) { } [ ] { } [ ) { } ( ] { }
Mth 65 Prelulus Review Properties of Inequlities 1. > nd > >. > + > +. > nd > 0 > 4. > nd < 0 < Asolute Vlue, if 0, if < 0 Properties of Asolute Vlue > 0 1. < < > or
More informationSection 1.3 Triangles
Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior
More informationHow do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?
XII. LINEAR ALGEBRA: SOLVING SYSTEMS OF EQUATIONS Tody we re going to tlk out solving systems of liner equtions. These re prolems tht give couple of equtions with couple of unknowns, like: 6= x + x 7=
More informationQuadratic Forms. Quadratic Forms
Qudrtic Forms Recll the Simon & Blume excerpt from n erlier lecture which sid tht the min tsk of clculus is to pproximte nonliner functions with liner functions. It s ctully more ccurte to sy tht we pproximte
More information5. Every rational number have either terminating or repeating (recurring) decimal representation.
CHAPTER NUMBER SYSTEMS Points to Rememer :. Numer used for ounting,,,,... re known s Nturl numers.. All nturl numers together with zero i.e. 0,,,,,... re known s whole numers.. All nturl numers, zero nd
More informationAP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals
AP Clulus BC Chpter 8: Integrtion Tehniques, L Hopitl s Rule nd Improper Integrls 8. Bsi Integrtion Rules In this setion we will review vrious integrtion strtegies. Strtegies: I. Seprte the integrnd into
More informationThe area under the graph of f and above the x-axis between a and b is denoted by. f(x) dx. π O
1 Section 5. The Definite Integrl Suppose tht function f is continuous nd positive over n intervl [, ]. y = f(x) x The re under the grph of f nd ove the x-xis etween nd is denoted y f(x) dx nd clled the
More information10. AREAS BETWEEN CURVES
. AREAS BETWEEN CURVES.. Ares etween curves So res ove the x-xis re positive nd res elow re negtive, right? Wrong! We lied! Well, when you first lern out integrtion it s convenient fiction tht s true in
More informationIntroduction to Algebra - Part 2
Alger Module A Introduction to Alger - Prt Copright This puliction The Northern Alert Institute of Technolog 00. All Rights Reserved. LAST REVISED Oct., 008 Introduction to Alger - Prt Sttement of Prerequisite
More information1 ELEMENTARY ALGEBRA and GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE
ELEMENTARY ALGEBRA nd GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE Directions: Study the exmples, work the prolems, then check your nswers t the end of ech topic. If you don t get the nswer given, check
More informationSymmetrical Components 1
Symmetril Components. Introdution These notes should e red together with Setion. of your text. When performing stedy-stte nlysis of high voltge trnsmission systems, we mke use of the per-phse equivlent
More informationSimplifying Algebra. Simplifying Algebra. Curriculum Ready.
Simplifying Alger Curriculum Redy www.mthletics.com This ooklet is ll out turning complex prolems into something simple. You will e le to do something like this! ( 9- # + 4 ' ) ' ( 9- + 7-) ' ' Give this
More information2.4 Linear Inequalities and Interval Notation
.4 Liner Inequlities nd Intervl Nottion We wnt to solve equtions tht hve n inequlity symol insted of n equl sign. There re four inequlity symols tht we will look t: Less thn , Less thn or
More informationMath Lesson 4-5 The Law of Cosines
Mth-1060 Lesson 4-5 The Lw of osines Solve using Lw of Sines. 1 17 11 5 15 13 SS SSS Every pir of loops will hve unknowns. Every pir of loops will hve unknowns. We need nother eqution. h Drop nd ltitude
More informationPolynomials and Division Theory
Higher Checklist (Unit ) Higher Checklist (Unit ) Polynomils nd Division Theory Skill Achieved? Know tht polynomil (expression) is of the form: n x + n x n + n x n + + n x + x + 0 where the i R re the
More informationExponentials - Grade 10 [CAPS] *
OpenStx-CNX module: m859 Exponentils - Grde 0 [CAPS] * Free High School Science Texts Project Bsed on Exponentils by Rory Adms Free High School Science Texts Project Mrk Horner Hether Willims This work
More informationQUADRATIC EQUATION. Contents
QUADRATIC EQUATION Contents Topi Pge No. Theory 0-04 Exerise - 05-09 Exerise - 09-3 Exerise - 3 4-5 Exerise - 4 6 Answer Key 7-8 Syllus Qudrti equtions with rel oeffiients, reltions etween roots nd oeffiients,
More informationMA123, Chapter 10: Formulas for integrals: integrals, antiderivatives, and the Fundamental Theorem of Calculus (pp.
MA123, Chpter 1: Formuls for integrls: integrls, ntiderivtives, nd the Fundmentl Theorem of Clculus (pp. 27-233, Gootmn) Chpter Gols: Assignments: Understnd the sttement of the Fundmentl Theorem of Clculus.
More informationLecture 1 - Introduction and Basic Facts about PDEs
* 18.15 - Introdution to PDEs, Fll 004 Prof. Gigliol Stffilni Leture 1 - Introdution nd Bsi Fts bout PDEs The Content of the Course Definition of Prtil Differentil Eqution (PDE) Liner PDEs VVVVVVVVVVVVVVVVVVVV
More information18.06 Problem Set 4 Due Wednesday, Oct. 11, 2006 at 4:00 p.m. in 2-106
8. Problem Set Due Wenesy, Ot., t : p.m. in - Problem Mony / Consier the eight vetors 5, 5, 5,..., () List ll of the one-element, linerly epenent sets forme from these. (b) Wht re the two-element, linerly
More informationAlgebraic fractions. This unit will help you to work with algebraic fractions and solve equations. rs r s 2. x x.
Get strted 25 Algeri frtions This unit will help you to work with lgeri frtions nd solve equtions. AO1 Flueny hek 1 Ftorise 2 2 5 2 25 2 6 5 d 2 2 6 2 Simplify 2 6 3 rs r s 2 d 8 2 y 3 6 y 2 3 Write s
More informationINTEGRATION. 1 Integrals of Complex Valued functions of a REAL variable
INTEGRATION NOTE: These notes re supposed to supplement Chpter 4 of the online textbook. 1 Integrls of Complex Vlued funtions of REAL vrible If I is n intervl in R (for exmple I = [, b] or I = (, b)) nd
More informationImproper Integrals, and Differential Equations
Improper Integrls, nd Differentil Equtions October 22, 204 5.3 Improper Integrls Previously, we discussed how integrls correspond to res. More specificlly, we sid tht for function f(x), the region creted
More informationLinear Algebra Introduction
Introdution Wht is Liner Alger out? Liner Alger is rnh of mthemtis whih emerged yers k nd ws one of the pioneer rnhes of mthemtis Though, initilly it strted with solving of the simple liner eqution x +
More informationEquations and Inequalities
Equtions nd Inequlities Equtions nd Inequlities Curriculum Redy ACMNA: 4, 5, 6, 7, 40 www.mthletics.com Equtions EQUATIONS & Inequlities & INEQUALITIES Sometimes just writing vribles or pronumerls in
More informationFor a, b, c, d positive if a b and. ac bd. Reciprocal relations for a and b positive. If a > b then a ab > b. then
Slrs-7.2-ADV-.7 Improper Definite Integrls 27.. D.dox Pge of Improper Definite Integrls Before we strt the min topi we present relevnt lger nd it review. See Appendix J for more lger review. Inequlities:
More informationChapter 1: Logarithmic functions and indices
Chpter : Logrithmic functions nd indices. You cn simplify epressions y using rules of indices m n m n m n m n ( m ) n mn m m m m n m m n Emple Simplify these epressions: 5 r r c 4 4 d 6 5 e ( ) f ( ) 4
More informationPYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:
PYTHAGORAS THEOREM 1 WHAT S IN CHAPTER 1? 1 01 Squres, squre roots nd surds 1 02 Pythgors theorem 1 03 Finding the hypotenuse 1 04 Finding shorter side 1 05 Mixed prolems 1 06 Testing for right-ngled tringles
More informationQUADRATIC EQUATION EXERCISE - 01 CHECK YOUR GRASP
QUADRATIC EQUATION EXERCISE - 0 CHECK YOUR GRASP. Sine sum of oeffiients 0. Hint : It's one root is nd other root is 8 nd 5 5. tn other root 9. q 4p 0 q p q p, q 4 p,,, 4 Hene 7 vlues of (p, q) 7 equtions
More informationGeometry of the Circle - Chords and Angles. Geometry of the Circle. Chord and Angles. Curriculum Ready ACMMG: 272.
Geometry of the irle - hords nd ngles Geometry of the irle hord nd ngles urriulum Redy MMG: 272 www.mthletis.om hords nd ngles HRS N NGLES The irle is si shpe nd so it n e found lmost nywhere. This setion
More informationThe graphs of Rational Functions
Lecture 4 5A: The its of Rtionl Functions s x nd s x + The grphs of Rtionl Functions The grphs of rtionl functions hve severl differences compred to power functions. One of the differences is the behvior
More informationTOPIC: LINEAR ALGEBRA MATRICES
Interntionl Blurete LECTUE NOTES for FUTHE MATHEMATICS Dr TOPIC: LINEA ALGEBA MATICES. DEFINITION OF A MATIX MATIX OPEATIONS.. THE DETEMINANT deta THE INVESE A -... SYSTEMS OF LINEA EQUATIONS. 8. THE AUGMENTED
More informationMathematics Number: Logarithms
plce of mind F A C U L T Y O F E D U C A T I O N Deprtment of Curriculum nd Pedgogy Mthemtics Numer: Logrithms Science nd Mthemtics Eduction Reserch Group Supported y UBC Teching nd Lerning Enhncement
More informationMatrices SCHOOL OF ENGINEERING & BUILT ENVIRONMENT. Mathematics (c) 1. Definition of a Matrix
tries Definition of tri mtri is regulr rry of numers enlosed inside rkets SCHOOL OF ENGINEERING & UIL ENVIRONEN Emple he following re ll mtries: ), ) 9, themtis ), d) tries Definition of tri Size of tri
More informationSystem Validation (IN4387) November 2, 2012, 14:00-17:00
System Vlidtion (IN4387) Novemer 2, 2012, 14:00-17:00 Importnt Notes. The exmintion omprises 5 question in 4 pges. Give omplete explntion nd do not onfine yourself to giving the finl nswer. Good luk! Exerise
More information1B40 Practical Skills
B40 Prcticl Skills Comining uncertinties from severl quntities error propgtion We usully encounter situtions where the result of n experiment is given in terms of two (or more) quntities. We then need
More informationChapters Five Notes SN AA U1C5
Chpters Five Notes SN AA U1C5 Nme Period Section 5-: Fctoring Qudrtic Epressions When you took lger, you lerned tht the first thing involved in fctoring is to mke sure to fctor out ny numers or vriles
More informationProportions: A ratio is the quotient of two numbers. For example, 2 3
Proportions: rtio is the quotient of two numers. For exmple, 2 3 is rtio of 2 n 3. n equlity of two rtios is proportion. For exmple, 3 7 = 15 is proportion. 45 If two sets of numers (none of whih is 0)
More informationSection 7.1 Integration by Substitution
Section 7. Integrtion by Substitution Evlute ech of the following integrls. Keep in mind tht using substitution my not work on some problems. For one of the definite integrls, it is not possible to find
More informationBridging the gap: GCSE AS Level
Bridging the gp: GCSE AS Level CONTENTS Chpter Removing rckets pge Chpter Liner equtions Chpter Simultneous equtions 8 Chpter Fctors 0 Chpter Chnge the suject of the formul Chpter 6 Solving qudrtic equtions
More informationGauss Quadrature Rule of Integration
Guss Qudrture Rule o Integrtion Computer Engineering Mjors Authors: Autr Kw, Chrlie Brker http://numerilmethods.eng.us.edu Trnsorming Numeril Methods Edution or STEM Undergrdutes /0/00 http://numerilmethods.eng.us.edu
More informationL1 2.1 Long Division of Polynomials and The Remainder Theorem Lesson MHF4U Jensen
L1 2.1 Long Division of Polynomials and The Remainder Theorem Lesson MHF4U Jensen In this section you will apply the method of long division to divide a polynomial by a binomial. You will also learn to
More informationNow we must transform the original model so we can use the new parameters. = S max. Recruits
MODEL FOR VARIABLE RECRUITMENT (ontinue) Alterntive Prmeteriztions of the pwner-reruit Moels We n write ny moel in numerous ifferent ut equivlent forms. Uner ertin irumstnes it is onvenient to work with
More informationI1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3
2 The Prllel Circuit Electric Circuits: Figure 2- elow show ttery nd multiple resistors rrnged in prllel. Ech resistor receives portion of the current from the ttery sed on its resistnce. The split is
More informationA Study on the Properties of Rational Triangles
Interntionl Journl of Mthemtis Reserh. ISSN 0976-5840 Volume 6, Numer (04), pp. 8-9 Interntionl Reserh Pulition House http://www.irphouse.om Study on the Properties of Rtionl Tringles M. Q. lm, M.R. Hssn
More informationAP CALCULUS Test #6: Unit #6 Basic Integration and Applications
AP CALCULUS Test #6: Unit #6 Bsi Integrtion nd Applitions A GRAPHING CALCULATOR IS REQUIRED FOR SOME PROBLEMS OR PARTS OF PROBLEMS IN THIS PART OF THE EXAMINATION. () The ext numeril vlue of the orret
More informationInterpreting Integrals and the Fundamental Theorem
Interpreting Integrls nd the Fundmentl Theorem Tody, we go further in interpreting the mening of the definite integrl. Using Units to Aid Interprettion We lredy know tht if f(t) is the rte of chnge of
More informationProbability. b a b. a b 32.
Proility If n event n hppen in '' wys nd fil in '' wys, nd eh of these wys is eqully likely, then proility or the hne, or its hppening is, nd tht of its filing is eg, If in lottery there re prizes nd lnks,
More informationPart I: Study the theorem statement.
Nme 1 Nme 2 Nme 3 A STUDY OF PYTHAGORAS THEOREM Instrutions: Together in groups of 2 or 3, fill out the following worksheet. You my lift nswers from the reding, or nswer on your own. Turn in one pket for
More informationIntroduction to Olympiad Inequalities
Introdution to Olympid Inequlities Edutionl Studies Progrm HSSP Msshusetts Institute of Tehnology Snj Simonovikj Spring 207 Contents Wrm up nd Am-Gm inequlity 2. Elementry inequlities......................
More informationPythagoras Theorem. Pythagoras Theorem. Curriculum Ready ACMMG: 222, 245.
Pythgors Theorem Pythgors Theorem Curriulum Redy ACMMG:, 45 www.mthletis.om Fill in these spes with ny other interesting fts you n find out Pythgors. In the world of Mthemtis, Pythgors is legend. He lived
More informationUniversity of Sioux Falls. MAT204/205 Calculus I/II
University of Sioux Flls MAT204/205 Clulus I/II Conepts ddressed: Clulus Textook: Thoms Clulus, 11 th ed., Weir, Hss, Giordno 1. Use stndrd differentition nd integrtion tehniques. Differentition tehniques
More informationIf deg(num) deg(denom), then we should use long-division of polynomials to rewrite: p(x) = s(x) + r(x) q(x), q(x)
Mth 50 The method of prtil frction decomposition (PFD is used to integrte some rtionl functions of the form p(x, where p/q is in lowest terms nd deg(num < deg(denom. q(x If deg(num deg(denom, then we should
More informationIntegration. antidifferentiation
9 Integrtion 9A Antidifferentition 9B Integrtion of e, sin ( ) nd os ( ) 9C Integrtion reognition 9D Approimting res enlosed funtions 9E The fundmentl theorem of integrl lulus 9F Signed res 9G Further
More informationReview of Gaussian Quadrature method
Review of Gussin Qudrture method Nsser M. Asi Spring 006 compiled on Sundy Decemer 1, 017 t 09:1 PM 1 The prolem To find numericl vlue for the integrl of rel vlued function of rel vrile over specific rnge
More informationa) Read over steps (1)- (4) below and sketch the path of the cycle on a P V plot on the graph below. Label all appropriate points.
Prole 3: Crnot Cyle of n Idel Gs In this prole, the strting pressure P nd volue of n idel gs in stte, re given he rtio R = / > of the volues of the sttes nd is given Finlly onstnt γ = 5/3 is given You
More informationNON-DETERMINISTIC FSA
Tw o types of non-determinism: NON-DETERMINISTIC FS () Multiple strt-sttes; strt-sttes S Q. The lnguge L(M) ={x:x tkes M from some strt-stte to some finl-stte nd ll of x is proessed}. The string x = is
More informationInfinite Geometric Series
Infinite Geometric Series Finite Geometric Series ( finite SUM) Let 0 < r < 1, nd let n be positive integer. Consider the finite sum It turns out there is simple lgebric expression tht is equivlent to
More informationL1 2.1 Long Division of Polynomials and The Remainder Theorem Lesson MHF4U Jensen
L1 2.1 Long Division of Polynomials and The Remainder Theorem Lesson MHF4U Jensen In this section you will apply the method of long division to divide a polynomial by a binomial. You will also learn to
More information5: The Definite Integral
5: The Definite Integrl 5.: Estimting with Finite Sums Consider moving oject its velocity (meters per second) t ny time (seconds) is given y v t = t+. Cn we use this informtion to determine the distnce
More informationGauss Quadrature Rule of Integration
Guss Qudrture Rule o Integrtion Mjor: All Engineering Mjors Authors: Autr Kw, Chrlie Brker http://numerilmethods.eng.us.edu Trnsorming Numeril Methods Edution or STEM Undergrdutes /0/00 http://numerilmethods.eng.us.edu
More informationHow do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?
XII. LINEAR ALGEBRA: SOLVING SYSTEMS OF EQUATIONS Tody we re going to tlk bout solving systems of liner equtions. These re problems tht give couple of equtions with couple of unknowns, like: 6 2 3 7 4
More informationLesson 1: Quadratic Equations
Lesson 1: Qudrtic Equtions Qudrtic Eqution: The qudrtic eqution in form is. In this section, we will review 4 methods of qudrtic equtions, nd when it is most to use ech method. 1. 3.. 4. Method 1: Fctoring
More informationType 2: Improper Integrals with Infinite Discontinuities
mth imroer integrls: tye 6 Tye : Imroer Integrls with Infinite Disontinuities A seond wy tht funtion n fil to be integrble in the ordinry sense is tht it my hve n infinite disontinuity (vertil symtote)
More informationLinear Inequalities. Work Sheet 1
Work Sheet 1 Liner Inequlities Rent--Hep, cr rentl compny,chrges $ 15 per week plus $ 0.0 per mile to rent one of their crs. Suppose you re limited y how much money you cn spend for the week : You cn spend
More informationBEGINNING ALGEBRA (ALGEBRA I)
/0 BEGINNING ALGEBRA (ALGEBRA I) SAMPLE TEST PLACEMENT EXAMINATION Downlod the omplete Study Pket: http://www.glendle.edu/studypkets Students who hve tken yer of high shool lger or its equivlent with grdes
More informationSeptember 13 Homework Solutions
College of Engineering nd Computer Science Mechnicl Engineering Deprtment Mechnicl Engineering 5A Seminr in Engineering Anlysis Fll Ticket: 5966 Instructor: Lrry Cretto Septemer Homework Solutions. Are
More informationAlgebra 2 Semester 1 Practice Final
Alger 2 Semester Prtie Finl Multiple Choie Ientify the hoie tht est ompletes the sttement or nswers the question. To whih set of numers oes the numer elong?. 2 5 integers rtionl numers irrtionl numers
More informationwhere the box contains a finite number of gates from the given collection. Examples of gates that are commonly used are the following: a b
CS 294-2 9/11/04 Quntum Ciruit Model, Solovy-Kitev Theorem, BQP Fll 2004 Leture 4 1 Quntum Ciruit Model 1.1 Clssil Ciruits - Universl Gte Sets A lssil iruit implements multi-output oolen funtion f : {0,1}
More informationEdexcel GCE Core Mathematics (C2) Required Knowledge Information Sheet. Daniel Hammocks
Edexcel GCE Core Mthemtics (C) Required Knowledge Informtion Sheet C Formule Given in Mthemticl Formule nd Sttisticl Tles Booklet Cosine Rule o = + c c cosine (A) Binomil Series o ( + ) n = n + n 1 n 1
More informationSUMMER ASSIGNMENT FOR Pre-AP FUNCTIONS/TRIGONOMETRY Due Tuesday After Labor Day!
SUMMER ASSIGNMENT FOR Pre-AP FUNCTIONS/TRIGONOMETRY Due Tuesdy After Lor Dy! This summer ssignment is designed to prepre you for Functions/Trigonometry. Nothing on the summer ssignment is new. Everything
More informationUNCORRECTED. Australian curriculum NUMBER AND ALGEBRA
0A 0B 0C 0D 0E 0F 0G 0H Chpter Wht ou will lern Qudrti equtions (Etending) Solving + = 0 nd = d (Etending) Solving + + = 0 (Etending) Applitions of qudrti equtions (Etending) The prol Skething = with diltions
More informationThe Fundamental Theorem of Algebra
The Fundmentl Theorem of Alger Jeremy J. Fries In prtil fulfillment of the requirements for the Mster of Arts in Teching with Speciliztion in the Teching of Middle Level Mthemtics in the Deprtment of Mthemtics.
More informationGM1 Consolidation Worksheet
Cmridge Essentils Mthemtis Core 8 GM1 Consolidtion Worksheet GM1 Consolidtion Worksheet 1 Clulte the size of eh ngle mrked y letter. Give resons for your nswers. or exmple, ngles on stright line dd up
More informationAT100 - Introductory Algebra. Section 2.7: Inequalities. x a. x a. x < a
Section 2.7: Inequlities In this section, we will Determine if given vlue is solution to n inequlity Solve given inequlity or compound inequlity; give the solution in intervl nottion nd the solution 2.7
More informationImproper Integrals. The First Fundamental Theorem of Calculus, as we ve discussed in class, goes as follows:
Improper Integrls The First Fundmentl Theorem of Clculus, s we ve discussed in clss, goes s follows: If f is continuous on the intervl [, ] nd F is function for which F t = ft, then ftdt = F F. An integrl
More informationThis enables us to also express rational numbers other than natural numbers, for example:
Overview Study Mteril Business Mthemtis 05-06 Alger The Rel Numers The si numers re,,3,4, these numers re nturl numers nd lso lled positive integers. The positive integers, together with the negtive integers
More informationCS 373, Spring Solutions to Mock midterm 1 (Based on first midterm in CS 273, Fall 2008.)
CS 373, Spring 29. Solutions to Mock midterm (sed on first midterm in CS 273, Fll 28.) Prolem : Short nswer (8 points) The nswers to these prolems should e short nd not complicted. () If n NF M ccepts
More informationCalculus AB. For a function f(x), the derivative would be f '(
lculus AB Derivtive Formuls Derivtive Nottion: For function f(), the derivtive would e f '( ) Leiniz's Nottion: For the derivtive of y in terms of, we write d For the second derivtive using Leiniz's Nottion:
More informationARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac
REVIEW OF ALGEBRA Here we review the bsic rules nd procedures of lgebr tht you need to know in order to be successful in clculus. ARITHMETIC OPERATIONS The rel numbers hve the following properties: b b
More informationMultiplying integers EXERCISE 2B INDIVIDUAL PATHWAYS. -6 ì 4 = -6 ì 0 = 4 ì 0 = -6 ì 3 = -5 ì -3 = 4 ì 3 = 4 ì 2 = 4 ì 1 = -5 ì -2 = -6 ì 2 = -6 ì 1 =
EXERCISE B INDIVIDUAL PATHWAYS Activity -B- Integer multipliction doc-69 Activity -B- More integer multipliction doc-698 Activity -B- Advnced integer multipliction doc-699 Multiplying integers FLUENCY
More informationCAAM 453 NUMERICAL ANALYSIS I Examination There are four questions, plus a bonus. Do not look at them until you begin the exam.
Exmintion 1 Posted 23 October 2002. Due no lter thn 5pm on Mondy, 28 October 2002. Instructions: 1. Time limit: 3 uninterrupted hours. 2. There re four questions, plus bonus. Do not look t them until you
More informationModule 6: LINEAR TRANSFORMATIONS
Module 6: LINEAR TRANSFORMATIONS. Trnsformtions nd mtrices Trnsformtions re generliztions of functions. A vector x in some set S n is mpped into m nother vector y T( x). A trnsformtion is liner if, for
More informationUnit 4. Combinational Circuits
Unit 4. Comintionl Ciruits Digitl Eletroni Ciruits (Ciruitos Eletrónios Digitles) E.T.S.I. Informáti Universidd de Sevill 5/10/2012 Jorge Jun 2010, 2011, 2012 You re free to opy, distriute
More information