ECE3050 Assignment 7


 Kenneth Hoover
 1 years ago
 Views:
Transcription
1 ECE3050 Assignment 7. Sketch and label the Bode magnitude and phase plots for the transfer functions given. Use loglog scales for the magnitude plots and linearlog scales for the phase plots. On the magnitude plots, label the slopes of all asymptotes in dec/dec, label the break frequencies in rad/s, label the gain magnitude on all zeroslope asymptotes, and label the approximate gain magnitude for the actual plot at the break frequencies. You can check your plots with a convenient computer program, e.g. PSpice, Mathcad, MatLab, etc., to obtain computer generated plots. An example PSpice deck is given for one of the transfer functions. The output voltage is V(2), i.e. the voltage at node 2. It is obtained by the LAPLACE statement, which multiplies the voltage V() by the transfer function after the word LAPLACE. TheyaxisinthePSpice ProbegraphicsroutinemustbechangedtoalogscaletoseethecorrectslopesontheBode magnitude plot. The number of decades displayed on the yaxis should be changed to no more than 3 or 4 to get the best looking plot. T (s) =0 +s/00 T (s) =0 s/00 +s/00 0 T (s) = ( + s/00) ( + s/000) 0 T (s) = (s/00) 2 +2(s/00) + 2(s/00) T (s) = 00 (s/00) 2 +2(s/00) + T (s) =0 (s/00) 2 + 2(s/00) + 2(s/00) T (s) = 00 (s/00) 2 + 2(s/00) + T (s) =0 (s/00) (s/00) + 0.5(s/00) T (s) = 00 (s/00) (s/00) + T (s) =0 s/0 s/0 + (s/000) 2 T (s) =0 ( + s/00) ( + s/0000) (s/00) 2 T (s) =0 (s/00) 2 +2(s/00) + (s/00) 2 + T (s) =0 (s/00) 2 +2(s/00) + (s/00) 2 T (s) =0 (s/00) 2 + 2(s/00) + (s/00) 2 + T (s) =0 (s/00) 2 + 2(s/00) + (s/00) 2 T (s) =0 (s/00) (s/00) + (s/00) 2 + T (s) =0 (s/00) (s/00) + T (s) =0 (s/00)2 2(s/00) + (s/00) 2 + 2(s/00) + EXAMPLE TRANSFER FUNCTION BODE PLOT VS 0 AC E 2 0 LAPLACE {V()}={0*PWR(S/00,2)/(PWR(S/00,2)+SQRT(2)*S/00+)}.AC DEC 50 00K.PROBE.END 2. The figure shows an RLC circuit. Show that the voltage gain transfer function is of the form T (s) = (s/ω 0 ) 2 (s/ω 0 ) 2 + s/ (Qω 0 )+
2 where you must give the equations for ω 0 and Q. ForQ =0.5, show that the transfer function becomes T (s) = (s/ω 0) 2 (s/ω 0 +) 2 For Q<0.5, show that the transfer function becomes T (s) = s/ω s/ω + s/ω 2 s/ω 2 + where s µ ω,2 = ω 0 2 2Q ± 2Q Sketch the Bode magnitude and phase plots as a function of ω for the cases Q<0.5, Q =0.5, and Q>0.5. Label the slopes in dec/dec on the magnitude plot and label all break frequencies in the asymptotes. 3. Repeat problem 2 for the circuit given. Show that the transfer function is given by T (s) = s/ (Qω 0 ) (s/ω 0 ) 2 + s/ (Qω 0 )+ For Q =0.5, show that the transfer function becomes T (s) = s/ω 0 (s/ω 0 +) 2 For Q<0.5, show that the transfer function becomes r ω s/ω T (s) = ω 2 s/ω + s/ω 2 + where s µ ω,2 = ω 0 2 2Q ± 2Q Sketch the Bode magnitude and phase plots as a function of ω for the cases Q<0.5, Q =0.5, and Q>0.5. Label the slopes in dec/dec on the magnitude plot and label all break frequencies in the asymptotes. 2
3 4. Show that the voltage gain transfer function for the circuit is given by T (s) = R 2 k (R 3 + R 4 ) R + R 2 k (R 3 + R 4 ) +R 3 kr 4 Cs +(R kr 2 + R 4 ) kr 3 Cs Show that the input impedance is given by Z in =[R + R 2 k (R 3 + R 4 )] +[R 3k (R kr 2 + R 4 )] Cs +[R 3 k (R 2 + R 4 )] Cs 5. Show that the voltage gain transfer function for the circuit is given by T (s) = R 4 R k (R 2 + R 3 )+R 4 +(R + R 2 ) kr 3 Cs +(R kr 4 + R 2 ) kr 3 Cs Show that the input impedance is given by Z in =[R k (R 2 + R 3 )+R 4 ] +[R 3k (R kr 4 + R 2 )] Cs +[R 3 k (R + R 2 )] Cs 6. Solve for the transfer function for /V i for the circuit below. The short cut method we covered in class does not work with this circuit. However, the short cut method can be used to solve for V a /V i. Once this is obtained, superposition of V i and V a canbeusedtosolvefor. This eliminates writing node equations, but there is some algebra involved in combining terms to put the transfer function into the ratio of two polynomials. Sketch the Bode magnitude plot, label the break frequencies, and label the gain on the zeroslope asymptotes. Answer: = +[R 2R 3 / (R + R 2 + R 3 )] Cs V i +[(R + R 2 ) kr 3 ] Cs The element values are to be chosen so that the highfrequency asymptotic gain is 0.05 and the highfrequency asymptotic output resistance (with V i =0)is00 Ω. The frequency of the 3
4 zero in the transfer function is to be 00 Hz. If C = 220 µf, specify the element values in the circuit and calculate the pole frequency. Answers: R =2kΩ, R 2 =05.26 Ω, R 3 = Ω, f p =5Hz. 7. Solve for the transfer function for /V i for the circuit below. Sketch the Bode plot, label the break frequencies, and label the gain on the zeroslope asymptotes. Answer: V i = Z F R = R 2 R +R 3 Cs +(R 2 + R 3 ) Cs The circuit is to be designed as a laglead compensator for a motor control system. The specifications are lowfrequency asymptotic gain: 2, input resistance: 0 kω, pole frequency: Hz, zero frequency: 0 Hz. Specify the element values. Answers: R =0kΩ, R 2 =20kΩ, R 3 = Ω, andc =7.620 µf. 8. Solve for /V i for the circuits below. Sketch and label the Bode magnitude plots. Answers: (a) The transfer function is a lowpass shelving function with a dc gain of K dc = R 2 + R 3 R + R 2 + R 3 4
5 and a highfrequency gain of The transfer function is V i = K = R 2 + R 3 R + R 2 + R 3 R 2 + R 3 kr 4 R + R 2 + R 3 kr 4 +(R 2 kr 3 + R 4 ) Cs +[(R + R 2 ) kr 3 + R 4 ] Cs (b) The transfer function is a highpass shelving function. The zerofrequency gain is K dc =+ R + R 2 R 3 The highfrequency gain is K =+ R 2 R 3 The transfer function is given by µ V µ o Vf = = + R + R 2 +[(R2 + R 3 ) kr ] Cs V i R 3 +R Cs 9. It is desired to design a circuit that realizes the following impedance transfer function: Z = 000 ( + s/2πf 2)(+s/2πf 4 ) ( + s/2πf )(+s/2πf 3 ) where f =0Hz, f 2 = 00 Hz, f 3 =khz,andf 4 =0kHz. (a) Sketch the Bode magnitude plot for Z. Note that the impedance starts at 000 Ω, shelves at 00 Ω, then shelves again at 0 Ω. Label the break frequencies and label the magnitude of the impedance on each zeroslope asymptote. (b) A possible circuit realization is in the figure below. At low frequencies, the impedance starts at the value R + R + R 2. As frequency is increased, suppose that C becomes a short circuit well before C 2 becomes a short circuit. When C becomes a short, the impedance shelves at the value R + R 2. Therefore, C causes both a pole and a zero. As frequency is increased further, C 2 becomes a short and the impedance shelves at the value R. ThusC 2 also causes a pole and a zero. With this information show that the input impedance is approximately given by Z in (s) ' (R + R + R 2 ) +R k (R + R 2 ) C s +R C s +(R 2 kr) C 2 s +R 2 C 2 s where you consider C 2 to be an open in calculating the effect of C and you consider C to be a short in calculating the effect of C 2. 0Write the three equations for the resistors and solve for their values. Answers: R =0Ω, R = 900 Ω, andr 2 =90Ω. 5
6 (c) Solve for the two time constants for C assuming C 2 is an open circuit. What must be the value of C? Answer: The pole time constant is calculated with the inputs open circuited. The zero time constant is calculated with the inputs short circuited. The value of C is C =7.68 µf. (d) Solve for the two time constants for C 2 assuming C is a short circuit. What must be the value of C 2? Answer: The pole time constant is calculated with the inputs open circuited. The zero time constant is calculated with the inputs short circuited. The value of C 2 is C 2 =.77 µf. (e) Use SPICE to plot the magnitude of the impedance as a function of frequency. To do this, drive the circuit with an ac current source of A. The voltage across the terminals is the impedance. Use a log scale for the vertical axis to display the correct Bode plot. (.AC DEC 50 00K) 0. Use the inverting gain formula to solve for the voltagegain transfer function for the circuit below Sketch and label the Bode magnitude plot. Answer: V i = R 3 Z = R 3 R + R 2 +R 2 Cs +(R kr 2 ) Cs. Using a single 00 µf capacitor, design a single op amp circuit which has the voltagegain transfer function =0 +s/0 V i +s/00 Sketch and label the Bode magnitude plot. One possible answer is the circuit below. where µ V µ o Vf = = + R 3 +(R kr 3 + R 2 ) Cs V i R +R 2 Cs The element values are R =kω, R 2 = 00 Ω, R 3 =9kΩ, andc =5.92 µf. 6
7 2. For the circuit shown, show that = R 2 R V i V i2 +R 2 Cs 3. For the circuit shown, show that = +(R + R 2 ) Cs V i +R Cs 4. For the circuit shown, show that V i = R R 2 (s/ω 0 ) (s/ω 0 ) 2 +(/Q)(s/ω 0 )+ where ω 0 =/ LC and Q = ω 0 R C. Sketch and label the Bode magnitude and phase plots for Q =0.5, Q =,andq =2. 7
8 5. For the circuit shown, show that the impedance is real at the frequency s R 2 ω = L 2 + L C 6. For the circuit shown, show that = 2 V i RCs Show that the equivalent circuit for Z in is the resistor R = R in parallel with the negative inductor L = R 2 C. 7. For the potentiometer circuit shown, let the resistance below the wiper be xr p and the resistance above the wiper be ( x) R p.show that V i = x +x ( x) R p Cs 8
9 Show that the circuit has a worstcase minimum bandwidth when x = 0.5 and that the corresponding pole frequency is given by f pole = πr p C 8. For the circuit shown, show that V i = µ + R F R + R 2 +[R k (R 2 + R F )] Cs +(R kr 2 ) Cs 9
10 9. The figure shows a Schmidt trigger. It is given that V SAT =2Vand R F =0kΩ. Solvefor V REF and R for V A = 4V and V B =+2V.Answers:R =3.33 kω, V REF =.33 V. 20. The transfer function of a 4th order 0.5 db ripple Chebyshev lowpass filter is of the form T LP (s) =T (s) T 2 (s) where T (s) = T 2 (s) = (s/.033ω c ) 2 +(/2.9406) (s/.033ω c )+ (s/ ω c ) 2 +(/0.705) (s/ ω c )+ (a) Replace s/ω c with ω c /s to obtain the highpass transfer functions. (b) For ω c = 00π, designsallenkeyfilters for the two transfer functions. In each filter, use C = C 2 =0. µf. (c) The lowfrequency response of a closedbox loudspeaker can be modeled by a 2nd highpass transfer function. Suppose that T 2 (s) represents the transfer function of a particular closedbox loudspeaker. Use SPICE or a math program to obtain the Bode magnitude plot for T 2 (j2πf). Use the cursor or trace feature of the program to determine the lower 3dB cutoff frequency of the loudspeaker. (d) Let T (s) represent the transfer function of an active filter which precedes the power amplifier that drives the loudspeaker. Such a filter is called an equalizer. Use SPICE or a math program to obtain the Bode magnitude plot for T (j2πf). Use the trace feature of the program to determine the peak gain or peak lift of the filter and the frequency of the peak. (e) Use SPICE or a math program to obtain the Bode magnitude plot for T (j2πf) T 2 (j2πf). Use the trace feature of the program to determine the lower 3dB cutoff frequency of the loudspeaker plus equalizer. By what factor is it lower than that for the loudspeaker alone? (f) An audio amplifier is used to drive the loudspeaker. The loudspeaker can be assumed to have a resistive impedance of 8 Ω. The frequency response is to be measured using a sine wave source to drive the system. The amplitude of the sine wave source is set so that the power delivered to the loudspeaker at 500 Hz is 0 W. If the amplitude of the source is held constant as the frequency is decreased, determine the power delivered to the loudspeaker at the frequency where the equalizer exhibits its maximum peak lift. 0
11 2. If C and C 2 are specified for the secondorder unitygain SallenKey lowpass filter, it can be shown that R and R 2 are given by " r # R = ± 4Q R 2 2Qω 0 C 2 C 2 2 C where the plus sign can be used for either R or R 2 and the minus sign for the other, i.e. the values for R and R 2 are interchangeable. (a) Design the filter for ω 0 = 200π 0 and Q =.5. Use capacitor values having the ratio C /C 2 =2in the range from 000 pf and 0.22 µf. Specify C, C 2, R,andR 2. The capacitors should conform to standard 0% values. The resistors should conform to standard 5% values and should lie in the range from kω to 00 kω. You should attempt to come as close to the theoretical design as possible with the standard resistor and capacitor values. (The 5% values for one decade are 0,, 2, 3, 5, 6, 8, 20, 22, 24, 27, 30, 33, 36, 39, 43, 47, 5, 56, 62, 68, 75, 82, 9, and00. The0% values for onedecadeare0, 2, 5, 8, 22, 27, 33, 39, 47, 56, 68, 82, and00.) Answers: Pick C =2xµF and C 2 = xµf, wherex is any number that you can choose to obtain values for R and R 2 in the specified range. It follows that the calculated values for R and R 2 are 83.88/x Ω and 0.256/x kω. (b) For one choice of R and R 2, use SPICE to simulate the magnitude of the filter gain versus frequency over the range 0 Hz f 0 khz. Use an ac analysis with 50 points per decade and convert the yaxis to a log scale. Set the yaxis to display the gain from 0. to 0. (c) Repeat the previous part with the other choice for R and R 2. Note that the figure should be the same. 22. This problem illustrates how the table of 5% resistor values is determined. Let R and R 2 be two adjacent resistors in the 5% resistor table. If R is increased by 0%, itsnew value is.r. If this corresponds to the next resistor R 2 in the 5% table, it follows that R +5%R ' R 2 5%R 2.Inorderforthe5% table to repeat each decade, it is necessary for. n =0,wheren is an integer corresponding to the number of resistance values per decade. Solution for n yields n =24.6. In generating the 5% resistor table, this value is rounded off to n =24. It follows that R 2 = 24 0R for any two adjacent resistors in the the 5% table. Starting with R =0Ω, generate the 5% resistor table for 0 Ω R 00 Ω. When rounded off to 2 significant figures, verify that the values obtained correspond to those given in problem The frequency transformations for highpass, bandpass, and bandreject transfer functions are defined as follows: LowPass to HighPass p p µ LowPass to BandPass p B p + µ p LowPass to BandReject p B p + p where p = s/ω c is called the normalized frequency, ω c is the cutoff frequency, and the arrow is read is replaced by. The parameter B determines the 3 db bandwidth of the bandpass
12 and bandreject functions. For the following lowpass function T LP (s) =K +s/ (aω c ) where a is a constant such that a =for Butterworth filters and a 6= for Chebyshev filters, use the frequency transformations to show that (a) The highpass function is given by (b) The bandpass function is given by (c) The bandreject function is given by T HP (s) =K as/ω c +as/ω c as/bω c T BP (s) =K (s/ω c ) 2 + as/ (Bω c )+ (s/ω c ) 2 + T BR (s) =K (s/ω c ) 2 + s/ (abω c )+ 24. A thirdorder lowpass transfer function is given by T LP (s) =K (s/ω c ) 3 + a 2 (s/ω c ) 2 + a (s/ω c )+ The magnitude squared function for a thirdorder Butterworth lowpass function is given by T LP (jω) 2 = K 2 +(ω/ω c ) 6 (a) Set s = jω, solvefor T LP (jω) 2, equate it to the Butterworth function, and solve for a and a 2 to make the transfer function Butterworth. Answers: a = a 2 =2. (b) Factor the transfer function into the product of a firstorder function multiplied by a secondorder function. What is the relationship between the break frequencies on the Bode plots of the first and secondorder sections? What is the Q of the secondorder section? Answers: T LP (s) =K +s/ω c (s/ω c ) 2 + s/ω c + The break frequency is the same for both functions and is equal to ω c. The secondorder section has Q =. (c) Evaluate the transfer function for s = jω c and show that it is given by T LP (jω c )=K +j +j + = K For this problem, pertinent design data for Chebyshev filters is posted on the class web page at You can also find it in the ECE 3042 lab manual. 2
13 (a) A bandpass filter is to be designed that consists of the cascade of a highpass filter and a lowpass filter. Each filter is to be a 3rd order.25 db ripple Chebyshev filter. The highpass filter is to have a cutoff frequency of f c = 00 Hz. The lowpass filter is to have a cutoff frequency of f c2 =0kHz. Use capacitor values in the range of 000 pf to 0.22 µf and resistors in the range of kω to 00 kω. The capacitors should conform to standard 0% values. The resistors should conform to standard 5% values. You should attempt to come as close to the theoretical design as possible with the resistor and capacitor values specified. (The 5% values for one decade are 0,, 2, 3, 5, 6, 8, 20, 22, 24, 27, 30, 33, 36, 39, 43, 47, 5, 56, 62, 68, 75, 82, 9, and00. The0% values for one decade are 0, 2, 5, 8, 22, 27, 33, 39, 47, 56, 68, 82, and00.). Answers: The lowpass function is T LP (s) = = h =0.427 θ =30 a 2 =0.453 a = b =2.57 +s/0.453ω c The highpass transfer function is T HP (s) = 0.453s/ω c s/ω c2 (s/0.9774ω c ) 2 +(/2.57) (s/0.9774ω c )+ (0.9774s/ω c2 ) 2 (0.9774s/ω c2 ) 2 +(/2.57) (0.9774s/ω c2 )+ (b) Use SPICE to simulate the filter. Set the ac input voltage to V so that the output voltage will be equal to the gain. Display the gain versus frequency for frequencies between 0 Hz and 00 khz. Using a log scale, display the yaxis over the range from 0.00 to 0. Use the cursor feature of PROBE to flag the lower and upper cutoff frequencies, the lower and upper 3dB frequencies, the midband gain, and the amount of ripple at the low and high frequencies. Answer: Your plot should look like the following (which was made with Mathcad): 0 T f n f n 26. The circuit shows a Wein bridge oscillator. If R = R 2, C =0. µf, C 2 =0.22 µf, and R 4 =0kΩ, specify R, R 2,andR 3 for the circuit to have stable oscillations at f = 000 Hz. Answers: R = R 2 = 073 Ω and R 3 = 6875 Ω. 3
14 27. The figure shows a phaseshift oscillator with the feedback loop broken. By writing node equations, it can be shown that the loopgain transfer function is given by Vo 0 = R F (RCs) 3 R (RCs) 3 +6(RCs) 2 +5(RCs)+ (a) To solve for the frequency of oscillation, what do you set Vo/V 0 o equal to? Answer: 6 0. (b) Use the transfer function to solve for the frequency of oscillation. Answer: f 0 = / 2π 6RC. (c) Use the transfer function to solve for value of R F /R in order for Vo/V 0 o = 6 0 at f = f 0.Answer:R F /R = The figure shows a phase shift oscillator. If C =0. µf, specifyr and R F for the circuit to have stable oscillations at f = 250 Hz. Answers:R =3249kΩ and R F =94.2 kω. 29. The loopgain transfer function of a particular oscillator circuit is given by s Vo 0 = K (s/00) (s/00) + At what frequency does the circuit oscillate and what must be the value of K for stable oscillations? Answers: f =5.9Hz and K =
15 30. The figure shows a log converter. It is given that R =MΩ. (a)whenv I =0Vit is found that v O = V. Solve for the transistor saturation current I S. (b) What is v O if v I is increased to 20 V? To 40 V? (c) By how much does v O increase each time v I is doubled? Answers: (a) I S = A,(b)v O = 0.55 V and v O = V, (c) v O = 0.07 V. 3. The figure shows a precision rectifier. If R = R 2 = R 3 and the input resistance is to be 0 kω, specify the resistors in the circuit for the output voltage v O =5 v I.Forasinewave input, sketch the voltage waveforms at the two inputs to the inverting summer and show how they combine to produce the desired output. What effect does reversing the diodes have? Answers: R = R 2 = R 3 =20kΩ, R F =40kΩ, andr F 2 = 00 kω. Reversing the diodes causes the output voltage to be given by v O = 5 v I. 32. For the precision rectifier of problem 3: (a) Sketch v O and v O versus v I for R = R F = R 3 = 0 kω, R 2 =20kΩ, andr F 2 = 200 kω. (b) Sketch v O and v O versus t for v I =0.5sin(ωt) V. (c) For v I =0.5sin(ωt) Vand R 3 =20kΩ, sketchv O versus t. 33. Sketch the waveforms for v O and vo 0 for the circuit given. Identify which portions on the waveform where the diode is on and where the diode is off. Whatwouldbetheeffect of reversing the diode? How would you modify the circuit to prevent saturation in the first op amp? 5
16 34. The figure shows a feedback amplifier. (a) Identify the type of feedback. (b) Use signal tracing to verify that the feedback is negative. (c) Use signal tracing to identify whether the feedback increases or decreases the input resistance. (d) Use signal tracing to identify whether the feedback increases or decreases the output resistance. (e) If the gain before feedback is sufficiently large, show that v o ' R F + R F 2 v i R F The figure shows a feedback amplifier. (a) Identify the type of feedback. (b) Use signal tracing to verify that the feedback is negative. (c) Use signal tracing to identify whether the feedback increases or decreases the input resistance. (d) Use signal tracing to identify whether the feedback increases or decreases the output resistance. (e) If the gain before feedback is sufficiently large, show that v o ' R F i i. 36. The figure shows a feedback amplifier. (a) Identify the type of feedback. (b) Use signal tracing to verify that the feedback is negative. (c) Use signal tracing to identify whether the 6
17 feedback increases or decreases the input resistance. (d) Use signal tracing to identify whether the feedback increases or decreases the output resistance. (e) If the gain before feedback is sufficiently large and r 02 canbeassumedtobeinfinite, show that i o ' R C2 + R F + R F 2 v i αr C2 R F The figure shows a feedback amplifier. (a) Identify the type of feedback. (b) Use signal tracing to verify that the feedback is negative. (c) Use signal tracing to identify whether the feedback increases or decreases the input resistance. (d) Use signal tracing to identify whether the feedback increases or decreases the output resistance. To do this, you must draw r 02 as an external resistor from the collector to the emitter of Q 2. (e) If the gain before feedback is sufficiently large and r 02 canbeassumedtobeinfinite, show that i o ' α R F + R E2 i i R E2 7
The Approximating Impedance
Georgia Institute of Technology School of Electrical and Computer Engineering ECE 4435 Op Amp Design Laboratory Fall 005 DesignProject,Part A White Noise and Pink Noise Generator The following explains
More informationHomework Assignment 08
Homework Assignment 08 Question 1 (Short Takes) Two points each unless otherwise indicated. 1. Give one phrase/sentence that describes the primary advantage of an active load. Answer: Large effective resistance
More informationENGN3227 Analogue Electronics. Problem Sets V1.0. Dr. Salman Durrani
ENGN3227 Analogue Electronics Problem Sets V1.0 Dr. Salman Durrani November 2006 Copyright c 2006 by Salman Durrani. Problem Set List 1. Opamp Circuits 2. Differential Amplifiers 3. Comparator Circuits
More informationHomework Assignment 11
Homework Assignment Question State and then explain in 2 3 sentences, the advantage of switched capacitor filters compared to continuoustime active filters. (3 points) Continuous time filters use resistors
More informationElectronic Circuits EE359A
Electronic Circuits EE359A Bruce McNair B26 bmcnair@stevens.edu 212165549 Lecture 22 578 Second order LCR resonatorpoles V o I 1 1 = = Y 1 1 + sc + sl R s = C 2 s 1 s + + CR LC s = C 2 sω 2 s + + ω
More informationOPERATIONAL AMPLIFIER APPLICATIONS
OPERATIONAL AMPLIFIER APPLICATIONS 2.1 The Ideal Op Amp (Chapter 2.1) Amplifier Applications 2.2 The Inverting Configuration (Chapter 2.2) 2.3 The Noninverting Configuration (Chapter 2.3) 2.4 Difference
More information55:041 Electronic Circuits The University of Iowa Fall Final Exam
Final Exam Name: Score Max: 135 Question 1 (1 point unless otherwise noted) a. What is the maximum theoretical efficiency for a classb amplifier? Answer: 78% b. The abbreviation/term ESR is often encountered
More informationSophomore Physics Laboratory (PH005/105)
CALIFORNIA INSTITUTE OF TECHNOLOGY PHYSICS MATHEMATICS AND ASTRONOMY DIVISION Sophomore Physics Laboratory (PH5/15) Analog Electronics Active Filters Copyright c Virgínio de Oliveira Sannibale, 23 (Revision
More informationExercise s = 1. cos 60 ± j sin 60 = 0.5 ± j 3/2. = s 2 + s + 1. (s + 1)(s 2 + s + 1) T(jω) = (1 + ω2 )(1 ω 2 ) 2 + ω 2 (1 + ω 2 )
Exercise 7 Ex: 7. A 0 log T [db] T 0.99 0.9 0.8 0.7 0.5 0. 0 A 0 0. 3 6 0 Ex: 7. A max 0 log.05 0 log 0.95 0.9 db [ ] A min 0 log 40 db 0.0 Ex: 7.3 s + js j Ts k s + 3 + j s + 3 j s + 4 k s + s + 4 + 3
More informationSpeaker: Arthur Williams Chief Scientist Telebyte Inc. Thursday November 20 th 2008 INTRODUCTION TO ACTIVE AND PASSIVE ANALOG
INTRODUCTION TO ACTIVE AND PASSIVE ANALOG FILTER DESIGN INCLUDING SOME INTERESTING AND UNIQUE CONFIGURATIONS Speaker: Arthur Williams Chief Scientist Telebyte Inc. Thursday November 20 th 2008 TOPICS Introduction
More informationFinal Exam. 55:041 Electronic Circuits. The University of Iowa. Fall 2013.
Final Exam Name: Max: 130 Points Question 1 In the circuit shown, the opamp is ideal, except for an input bias current I b = 1 na. Further, R F = 10K, R 1 = 100 Ω and C = 1 μf. The switch is opened at
More informationOpAmp Circuits: Part 3
OpAmp Circuits: Part 3 M. B. Patil mbpatil@ee.iitb.ac.in www.ee.iitb.ac.in/~sequel Department of Electrical Engineering Indian Institute of Technology Bombay Introduction to filters Consider v(t) = v
More informationFeedback design for the Buck Converter
Feedback design for the Buck Converter Portland State University Department of Electrical and Computer Engineering Portland, Oregon, USA December 30, 2009 Abstract In this paper we explore two compensation
More informationHomework Assignment 09
Homework Assignment 09 Question 1 (Short Takes) Two points each unless otherwise indicated. 1. What is the 3dB bandwidth of the amplifier shown below if r π = 2.5K, r o = 100K, g m = 40 ms, and C L =
More informationFrequency Dependent Aspects of Opamps
Frequency Dependent Aspects of Opamps Frequency dependent feedback circuits The arguments that lead to expressions describing the circuit gain of inverting and noninverting amplifier circuits with resistive
More informationELECTRONIC SYSTEMS. Basic operational amplifier circuits. Electronic Systems  C3 13/05/ DDC Storey 1
Electronic Systems C3 3/05/2009 Politecnico di Torino ICT school Lesson C3 ELECTONIC SYSTEMS C OPEATIONAL AMPLIFIES C.3 Op Amp circuits» Application examples» Analysis of amplifier circuits» Single and
More informationECE2210 Final given: Fall 13
ECE22 Final given: Fall 3. (23 pts) a) Draw the asymptotic Bode plot (the straightline approximation) of the transfer function below. Accurately draw it on the graph provided. You must show the steps
More informationEE221 Circuits II. Chapter 14 Frequency Response
EE22 Circuits II Chapter 4 Frequency Response Frequency Response Chapter 4 4. Introduction 4.2 Transfer Function 4.3 Bode Plots 4.4 Series Resonance 4.5 Parallel Resonance 4.6 Passive Filters 4.7 Active
More informationEE221 Circuits II. Chapter 14 Frequency Response
EE22 Circuits II Chapter 4 Frequency Response Frequency Response Chapter 4 4. Introduction 4.2 Transfer Function 4.3 Bode Plots 4.4 Series Resonance 4.5 Parallel Resonance 4.6 Passive Filters 4.7 Active
More informationInput and Output Impedances with Feedback
EE 3 Lecture Basic Feedback Configurations Generalized Feedback Schemes Integrators Differentiators Firstorder active filters Secondorder active filters Review from Last Time Input and Output Impedances
More informationTime Varying Circuit Analysis
MAS.836 Sensor Systems for Interactive Environments th Distributed: Tuesday February 16, 2010 Due: Tuesday February 23, 2010 Problem Set # 2 Time Varying Circuit Analysis The purpose of this problem set
More informationStudio 9 Review Operational Amplifier Stability Compensation Miller Effect Phase Margin Unity Gain Frequency Slew Rate Limiting Reading: Text sec 5.
Studio 9 Review Operational Amplifier Stability Compensation Miller Effect Phase Margin Unity Gain Frequency Slew Rate Limiting Reading: Text sec 5.2 pp. 232242 Twostage opamp Analysis Strategy Recognize
More informationECE2210 Final given: Spring 08
ECE Final given: Spring 0. Note: feel free to show answers & work right on the schematic 1. (1 pts) The ammeter, A, reads 30 ma. a) The power dissipated by R is 0.7 W, what is the value of R. Assume that
More informationEE202 Exam III April 13, 2015
EE202 Exam III April 3, 205 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo7:308:30 Furgason 3:304:30 DeCarlo:302:30 202 2022 2023 INSTRUCTIONS There are 2 multiple choice
More informationChapter 8: Converter Transfer Functions
Chapter 8. Converter Transfer Functions 8.1. Review of Bode plots 8.1.1. Single pole response 8.1.2. Single zero response 8.1.3. Right halfplane zero 8.1.4. Frequency inversion 8.1.5. Combinations 8.1.6.
More informationECE 255, Frequency Response
ECE 255, Frequency Response 19 April 2018 1 Introduction In this lecture, we address the frequency response of amplifiers. This was touched upon briefly in our previous lecture in Section 7.5 of the textbook.
More informationToday. 1/25/11 Physics 262 Lecture 2 Filters. Active Components and Filters. Homework. Lab 2 this week
/5/ Physics 6 Lecture Filters Today Basics: Analog versus Digital; Passive versus Active Basic concepts and types of filters Passband, Stopband, Cutoff, Slope, Knee, Decibels, and Bode plots Active Components
More informationH(s) = 2(s+10)(s+100) (s+1)(s+1000)
Problem 1 Consider the following transfer function H(s) = 2(s10)(s100) (s1)(s1000) (a) Draw the asymptotic magnitude Bode plot for H(s). Solution: The transfer function is not in standard form to sketch
More informationElectronic Circuits EE359A
Electronic Circuits EE359A Bruce McNair B26 bmcnair@stevens.edu 212165549 Lecture 22 569 Second order section Ts () = s as + as+ a 2 2 1 ω + s+ ω Q 2 2 ω 1 p, p = ± 1 Q 4 Q 1 2 2 57 Second order section
More informationVer 3537 E1.1 Analysis of Circuits (2014) E1.1 Circuit Analysis. Problem Sheet 1 (Lectures 1 & 2)
Ver 3537 E. Analysis of Circuits () Key: [A]= easy... [E]=hard E. Circuit Analysis Problem Sheet (Lectures & ). [A] One of the following circuits is a series circuit and the other is a parallel circuit.
More informationECE343 Test 2: Mar 21, :008:00, Closed Book. Name : SOLUTION
ECE343 Test 2: Mar 21, 2012 6:008:00, Closed Book Name : SOLUTION 1. (25 pts) (a) Draw a circuit diagram for a differential amplifier designed under the following constraints: Use only BJTs. (You may
More informationCHAPTER.6 :TRANSISTOR FREQUENCY RESPONSE
CHAPTER.6 :TRANSISTOR FREQUENCY RESPONSE To understand Decibels, log scale, general frequency considerations of an amplifier. low frequency analysis  Bode plot low frequency response BJT amplifier Miller
More informationEE105 Fall 2014 Microelectronic Devices and Circuits
EE05 Fall 204 Microelectronic Devices and Circuits Prof. Ming C. Wu wu@eecs.berkeley.edu 5 Sutardja Dai Hall (SDH) Terminal Gain and I/O Resistances of BJT Amplifiers Emitter (CE) Collector (CC) Base (CB)
More informationStart with the transfer function for a secondorder highpass. s 2. ω o. Q P s + ω2 o. = G o V i
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
More information1. Design a 3rd order Butterworth lowpass filters having a dc gain of unity and a cutoff frequency, fc, of khz.
ECE 34 Experiment 6 Active Filter Design. Design a 3rd order Butterworth lowpass ilters having a dc gain o unity and a cuto requency, c, o.8 khz. c :=.8kHz K:= The transer unction is given on page 7 j
More informationE40M Review  Part 1
E40M Review Part 1 Topics in Part 1 (Today): KCL, KVL, Power Devices: V and I sources, R Nodal Analysis. Superposition Devices: Diodes, C, L Time Domain Diode, C, L Circuits Topics in Part 2 (Wed): MOSFETs,
More information6.302 Feedback Systems
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Electrical Engineering and Computer Science 6.302 Feedback Systems Fall Term 2005 Issued : November 18, 2005 Lab 2 Series Compensation in Practice Due
More informationDynamic circuits: Frequency domain analysis
Electronic Circuits 1 Dynamic circuits: Contents Free oscillation and natural frequency Transfer functions Frequency response Bode plots 1 System behaviour: overview 2 System behaviour : review solution
More informationSolved Problems. Electric Circuits & Components. 11 Write the KVL equation for the circuit shown.
Solved Problems Electric Circuits & Components 11 Write the KVL equation for the circuit shown. 12 Write the KCL equation for the principal node shown. 12A In the DC circuit given in Fig. 1, find (i)
More informationRefinements to Incremental Transistor Model
Refinements to Incremental Transistor Model This section presents modifications to the incremental models that account for nonideal transistor behavior Incremental output port resistance Incremental changes
More informationChapter 10 Feedback. PART C: Stability and Compensation
1 Chapter 10 Feedback PART C: Stability and Compensation Example: Noninverting Amplifier We are analyzing the two circuits (nmos diff pair or pmos diff pair) to realize this symbol: either of the circuits
More informationChapter 9: Controller design
Chapter 9. Controller Design 9.1. Introduction 9.2. Effect of negative feedback on the network transfer functions 9.2.1. Feedback reduces the transfer function from disturbances to the output 9.2.2. Feedback
More informationOperational Amplifiers
Operational Amplifiers A Linear IC circuit Operational Amplifier (opamp) An opamp is a highgain amplifier that has high input impedance and low output impedance. An ideal opamp has infinite gain and
More informationNotes for course EE1.1 Circuit Analysis TOPIC 10 2PORT CIRCUITS
Objectives: Introduction Notes for course EE1.1 Circuit Analysis 45 Reexamination of 1port subcircuits Admittance parameters for port circuits TOPIC 1 PORT CIRCUITS Gain and port impedance from port
More informationOperational amplifiers (Op amps)
Operational amplifiers (Op amps) Recall the basic twoport model for an amplifier. It has three components: input resistance, Ri, output resistance, Ro, and the voltage gain, A. v R o R i v d Av d v Also
More informationLaplace Transform Analysis of Signals and Systems
Laplace Transform Analysis of Signals and Systems Transfer Functions Transfer functions of CT systems can be found from analysis of Differential Equations Block Diagrams Circuit Diagrams 5/10/04 M. J.
More informationESE319 Introduction to Microelectronics Bode Plot Review High Frequency BJT Model
Bode Plot Review High Frequency BJT Model 1 Logarithmic Frequency Response Plots (Bode Plots) Generic form of frequency response rational polynomial, where we substitute jω for s: H s=k sm a m 1 s m 1
More information6.17 The Lossy VoiceCoil Inductance
6.7. THE LOSSY VOICECOIL INDUCTANCE Solution. The impedance function is given by (/3.3) (s/38.2) Z VC (s) =7+0.008s +70 (s/38.2) 2 +(/3.3) (s/38.2) + Example 0 Solve for the element values in the equivalent
More informationElectronics II. Midterm II
The University of Toledo su7ms_elct7.fm  Electronics II Midterm II Problems Points. 7. 7 3. 6 Total 0 Was the exam fair? yes no The University of Toledo su7ms_elct7.fm  Problem 7 points Equation ()
More informationMicroelectronic Circuit Design 4th Edition Errata  Updated 4/4/14
Chapter Text # Inside back cover: Triode region equation should not be squared! i D = K n v GS "V TN " v & DS % ( v DS $ 2 ' Page 49, first exercise, second answer: 1.35 x 10 6 cm/s Page 58, last exercise,
More informationEE105 Fall 2015 Microelectronic Devices and Circuits Frequency Response. Prof. Ming C. Wu 511 Sutardja Dai Hall (SDH)
EE05 Fall 205 Microelectronic Devices and Circuits Frequency Response Prof. Ming C. Wu wu@eecs.berkeley.edu 5 Sutardja Dai Hall (SDH) Amplifier Frequency Response: Lower and Upper Cutoff Frequency Midband
More informationEE 321 Analog Electronics, Fall 2013 Homework #3 solution
EE 32 Analog Electronics, Fall 203 Homework #3 solution 2.47. (a) Use superposition to show that the output of the circuit in Fig. P2.47 is given by + [ Rf v N + R f v N2 +... + R ] f v Nn R N R N2 R [
More informationFrequency Response. Re ve jφ e jωt ( ) where v is the amplitude and φ is the phase of the sinusoidal signal v(t). ve jφ
27 Frequency Response Before starting, review phasor analysis, Bode plots... Key concept: smallsignal models for amplifiers are linear and therefore, cosines and sines are solutions of the linear differential
More informationCE/CS Amplifier Response at High Frequencies
.. CE/CS Amplifier Response at High Frequencies INEL 4202  Manuel Toledo August 20, 2012 INEL 4202  Manuel Toledo CE/CS High Frequency Analysis 1/ 24 Outline.1 High Frequency Models.2 Simplified Method.3
More informationRLC Circuits and Resonant Circuits
P517/617 Lec4, P1 RLC Circuits and Resonant Circuits Consider the following RLC series circuit What's R? Simplest way to solve for is to use voltage divider equation in complex notation. X L X C in 0
More informationECE 2210 Final given: Spring 15 p1
ECE 2 Final given: Spring 15 Closed Book, Closed notes except preprinted yellow sheet, Calculators OK. Show all work to receive credit. Circle answers, show units, and round off reasonably 1. (15 pts)
More informationChapter 10: Sinusoids and Phasors
Chapter 10: Sinusoids and Phasors 1. Motivation 2. Sinusoid Features 3. Phasors 4. Phasor Relationships for Circuit Elements 5. Impedance and Admittance 6. Kirchhoff s Laws in the Frequency Domain 7. Impedance
More informationESE319 Introduction to Microelectronics. Output Stages
Output Stages Power amplifier classification Class A amplifier circuits Class A Power conversion efficiency Class B amplifier circuits Class B Power conversion efficiency Class AB amplifier circuits Class
More informationanalyse and design a range of sinewave oscillators understand the design of multivibrators.
INTODUTION In this lesson, we investigate some forms of waveform generation using op amps. Of course, we could use basic transistor circuits, but it makes sense to simplify the analysis by considering
More informationSwitchedCapacitor Circuits David Johns and Ken Martin University of Toronto
SwitchedCapacitor Circuits David Johns and Ken Martin University of Toronto (johns@eecg.toronto.edu) (martin@eecg.toronto.edu) University of Toronto 1 of 60 Basic Building Blocks Opamps Ideal opamps usually
More informationECE342 Test 3: Nov 30, :008:00, Closed Book. Name : Solution
ECE342 Test 3: Nov 30, 2010 6:008:00, Closed Book Name : Solution All solutions must provide units as appropriate. Unless otherwise stated, assume T = 300 K. 1. (25 pts) Consider the amplifier shown
More informationFilters and Tuned Amplifiers
Filters and Tuned Amplifiers Essential building block in many systems, particularly in communication and instrumentation systems Typically implemented in one of three technologies: passive LC filters,
More informationESE319 Introduction to Microelectronics. Feedback Basics
Feedback Basics Stability Feedback concept Feedback in emitter follower Onepole feedback and root locus Frequency dependent feedback and root locus Gain and phase margins Conditions for closed loop stability
More informationDesigning Information Devices and Systems II Fall 2018 Elad Alon and Miki Lustig Discussion 5A
EECS 6B Designing Information Devices and Systems II Fall 208 Elad Alon and Miki Lustig Discussion 5A Transfer Function When we write the transfer function of an arbitrary circuit, it always takes the
More informationSecondorder filters. EE 230 secondorder filters 1
Secondorder filters Second order filters: Have second order polynomials in the denominator of the transfer function, and can have zeroth, first, or secondorder polynomials in the numerator. Use two
More informationDESIGN MICROELECTRONICS ELCT 703 (W17) LECTURE 3: OPAMP CMOS CIRCUIT. Dr. Eman Azab Assistant Professor Office: C
MICROELECTRONICS ELCT 703 (W17) LECTURE 3: OPAMP CMOS CIRCUIT DESIGN Dr. Eman Azab Assistant Professor Office: C3.315 Email: eman.azab@guc.edu.eg 1 TWO STAGE CMOS OPAMP It consists of two stages: First
More informationLecture 4: RLC Circuits and Resonant Circuits
Lecture 4: RLC Circuits and Resonant Circuits RLC series circuit: What's V R? Simplest way to solve for V is to use voltage divider equation in complex notation: V X L X C V R = in R R + X C + X L L
More informationAs an example of the parameter sweeping capabilities of LTSPICE, consider the following elementary highpass filter circuit:
LTSpice Parameter Sweep Tutorial ECE 202 Signals and Systems I Andrew Herdrich Department of Electrical and Computer Engineering Portland State University January 7, 2007 Version 2 AC sweep analyses in
More informationEE202 Exam III April 6, 2017
EE202 Exam III April 6, 207 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo202 DeCarlo2022 7:30 MWF :30 TTH INSTRUCTIONS There are 3 multiple choice worth 5 points each and
More information( s) N( s) ( ) The transfer function will take the form. = s = 2. giving ωo = sqrt(1/lc) = 1E7 [rad/s] ω 01 := R 1. α 1 2 L 1.
Problem ) RLC Parallel Circuit R L C E4 E0 V a. What is the resonant frequency of the circuit? The transfer function will take the form N ( ) ( s) N( s) H s R s + α s + ω s + s + o L LC giving ωo sqrt(/lc)
More informationCHAPTER 14 SIGNAL GENERATORS AND WAVEFORM SHAPING CIRCUITS
CHAPTER 4 SIGNA GENERATORS AND WAEFORM SHAPING CIRCUITS Chapter Outline 4. Basic Principles of Sinusoidal Oscillators 4. Op Amp RC Oscillators 4.3 C and Crystal Oscillators 4.4 Bistable Multivibrators
More informationOperational amplifiers (Op amps)
Operational amplifiers (Op amps) v R o R i v i Av i v View it as an ideal amp. Take the properties to the extreme: R i, R o 0, A.?!?!?!?! v v i Av i v A Consequences: No voltage dividers at input or output.
More informationFEEDBACK AND STABILITY
FEEDBCK ND STBILITY THE NEGTIVEFEEDBCK LOOP x IN X OUT x S + x IN x OUT Σ Signal source _ β Open loop Closed loop x F Feedback network Output x S input signal x OUT x IN x F feedback signal x IN x S x
More informationIMPERIAL COLLEGE OF SCIENCE, TECHNOLOGY AND MEDICINE UNIVERSITY OF LONDON DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2010
Paper Number(s): E1.1 IMPERIAL COLLEGE OF SCIENCE, TECHNOLOGY AND MEDICINE UNIVERSITY OF LONDON DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2010 EEE/ISE PART I: MEng, BEng and ACGI
More informationE40M. Op Amps. M. Horowitz, J. Plummer, R. Howe 1
E40M Op Amps M. Horowitz, J. Plummer, R. Howe 1 Reading A&L: Chapter 15, pp. 863866. Reader, Chapter 8 Noninverting Amp http://www.electronicstutorials.ws/opamp/opamp_3.html Inverting Amp http://www.electronicstutorials.ws/opamp/opamp_2.html
More informationTexas A&M University Department of Electrical and Computer Engineering
Texas A&M University Department of Electrical and Computer Engineering ECEN 622: Active Network Synthesis Homework #2, Fall 206 Carlos Pech Catzim 72300256 Page of .i) Obtain the transfer function of circuit
More informationDesign Engineering MEng EXAMINATIONS 2016
IMPERIAL COLLEGE LONDON Design Engineering MEng EXAMINATIONS 2016 For Internal Students of the Imperial College of Science, Technology and Medicine This paper is also taken for the relevant examination
More informationBasics of Network Theory (PartI)
Basics of Network Theory (PartI). A square waveform as shown in figure is applied across mh ideal inductor. The current through the inductor is a. wave of peak amplitude. V 0 0.5 t (m sec) [Gate 987: Marks]
More informationElectronic Circuits Summary
Electronic Circuits Summary Andreas Biri, DITET 6.06.4 Constants (@300K) ε 0 = 8.854 0 F m m 0 = 9. 0 3 kg k =.38 0 3 J K = 8.67 0 5 ev/k kt q = 0.059 V, q kt = 38.6, kt = 5.9 mev V Small Signal Equivalent
More informationEE 40: Introduction to Microelectronic Circuits Spring 2008: Midterm 2
EE 4: Introduction to Microelectronic Circuits Spring 8: Midterm Venkat Anantharam 3/9/8 Total Time Allotted : min Total Points:. This is a closed book exam. However, you are allowed to bring two pages
More informationELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT
Chapter 31: ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT 1 A charged capacitor and an inductor are connected in series At time t = 0 the current is zero, but the capacitor is charged If T is the
More informationECE 304: Design Issues for Voltage Follower as Output Stage S&S Chapter 14, pp
ECE 34: Design Issues for oltage Follower as Output Stage S&S Chapter 14, pp. 131133 Introduction The voltage follower provides a good buffer between a differential amplifier and a load in two ways: 1.
More informationPHYS225 Lecture 9. Electronic Circuits
PHYS225 Lecture 9 Electronic Circuits Last lecture Field Effect Transistors Voltage controlled resistor Various FET circuits Switch Source follower Current source Similar to BJT Draws no input current
More informationESE319 Introduction to Microelectronics. Feedback Basics
Feedback Basics Feedback concept Feedback in emitter follower Stability Onepole feedback and root locus Frequency dependent feedback and root locus Gain and phase margins Conditions for closed loop stability
More informationECE 201 Fall 2009 Final Exam
ECE 01 Fall 009 Final Exam December 16, 009 Division 0101: Tan (11:30am) Division 001: Clark (7:30 am) Division 0301: Elliott (1:30 pm) Instructions 1. DO NOT START UNTIL TOLD TO DO SO.. Write your Name,
More informationSteady State Frequency Response Using Bode Plots
School of Engineering Department of Electrical and Computer Engineering 332:224 Principles of Electrical Engineering II Laboratory Experiment 3 Steady State Frequency Response Using Bode Plots 1 Introduction
More informationDeliyannis, Theodore L. et al "Two Integrator Loop OTAC Filters" ContinuousTime Active Filter Design Boca Raton: CRC Press LLC,1999
Deliyannis, Theodore L. et al "Two Integrator Loop OTAC Filters" ContinuousTime Active Filter Design Boca Raton: CRC Press LLC,1999 Chapter 9 Two Integrator Loop OTAC Filters 9.1 Introduction As discussed
More informationEE348L Lecture 1. EE348L Lecture 1. Complex Numbers, KCL, KVL, Impedance,Steady State Sinusoidal Analysis. Motivation
EE348L Lecture 1 Complex Numbers, KCL, KVL, Impedance,Steady State Sinusoidal Analysis 1 EE348L Lecture 1 Motivation Example CMOS 10Gb/s amplifier Differential in,differential out, 5 stage dccoupled,broadband
More informationAnalogue Filters Design and Simulation by Carsten Kristiansen Napier University. November 2004
Analogue Filters Design and Simulation by Carsten Kristiansen Napier University November 2004 Title page Author: Carsten Kristiansen. Napier No: 04007712. Assignment title: Analogue Filters Design and
More informationEE C245 / ME C218 INTRODUCTION TO MEMS DESIGN FALL 2011 C. Nguyen PROBLEM SET #7. Table 1: Gyroscope Modeling Parameters
Issued: Wednesday, Nov. 23, 2011. PROBLEM SET #7 Due (at 7 p.m.): Thursday, Dec. 8, 2011, in the EE C245 HW box in 240 Cory. 1. Gyroscopes are inertial sensors that measure rotation rate, which is an extremely
More informationFEEDBACK, STABILITY and OSCILLATORS
FEEDBACK, STABILITY and OSCILLATORS à FEEDBACK, STABILITY and OSCILLATORS  STABILITY OF FEEDBACK SYSTEMS  Example : ANALYSIS and DESIGN OF PHASESHIFTOSCILLATORS  Example 2: ANALYSIS and DESIGN OF
More informationLecture 7: Transistors and Amplifiers
Lecture 7: Transistors and Amplifiers Hybrid Transistor Model for small AC : The previous model for a transistor used one parameter (β, the current gain) to describe the transistor. doesn't explain many
More informationI. Frequency Response of Voltage Amplifiers
I. Frequency Response of Voltage Amplifiers A. CommonEmitter Amplifier: V i SUP i OUT R S V BIAS R L v OUT V Operating Point analysis: 0, R s 0, r o >, r oc >, R L > Find V BIAS such that I C
More information55:041 Electronic Circuits The University of Iowa Fall Exam 2
Exam 2 Name: Score /60 Question 1 One point unless indicated otherwise. 1. An engineer measures the (step response) rise time of an amplifier as t r = 0.35 μs. Estimate the 3 db bandwidth of the amplifier.
More informationFigure Circuit for Question 1. Figure Circuit for Question 2
Exercises 10.7 Exercises Multiple Choice 1. For the circuit of Figure 10.44 the time constant is A. 0.5 ms 71.43 µs 2, 000 s D. 0.2 ms 4 Ω 2 Ω 12 Ω 1 mh 12u 0 () t V Figure 10.44. Circuit for Question
More informationSingleTimeConstant (STC) Circuits This lecture is given as a background that will be needed to determine the frequency response of the amplifiers.
SingleTimeConstant (STC) Circuits This lecture is given as a background that will be needed to determine the frequency response of the amplifiers. Objectives To analyze and understand STC circuits with
More informationHandout 11: AC circuit. AC generator
Handout : AC circuit AC generator Figure compares the voltage across the directcurrent (DC) generator and that across the alternatingcurrent (AC) generator For DC generator, the voltage is constant For
More informationc Copyright 2009. W. Marshall Leach, Jr., Professor, Georgia Institute of Technology, School of Electrical and Computer Engineering. Feedback Amplifiers CollectionofSolvedProblems A collection of solved
More informationMod. Sim. Dyn. Sys. Amplifiers page 1
AMPLIFIERS A circuit containing only capacitors, amplifiers (transistors) and resistors may resonate. A circuit containing only capacitors and resistors may not. Why does amplification permit resonance
More informationDepartment of Mechanical and Aerospace Engineering. MAE334  Introduction to Instrumentation and Computers. Final Examination.
Name: Number: Department of Mechanical and Aerospace Engineering MAE334  Introduction to Instrumentation and Computers Final Examination December 12, 2003 Closed Book and Notes 1. Be sure to fill in your
More information