UNIT-I STRESS, STRAIN. 1. A Member A B C D is subjected to loading as shown in fig determine the total elongation. Take E= 2 x10 5 N/mm 2
|
|
|
- Cory Marsh
- 5 years ago
- Views:
Transcription
1 UNIT-I STRESS, STRAIN 1. A Member A B C D is subjected to loading as shown in fig determine the total elongation. Take E= 2 x10 5 N/mm 2 Young s modulus E= 2 x10 5 N/mm 2 Area1=900mm 2 Area2=400mm 2 Area3=625mm 2 Length1=1500mm Length2=1000mm Length3=750mm To find Total elongation Consider tensile force +ve [increasing length] Compressive force ve [decreasing length] Step1 Consider part AB: To calculate the total load acts on suction AB (P 1 ) Left side load = right side load Step2 Consider part BC: To calculate the total load acts on suction BC (P 2 ) 1
2 Step3 Consider part CD: To calculate the total load acts on suction CD (P 3 ) Step 4 To calculate the change in length = A reinforced concrete column 300 x 300 mm has 4 reinforcing steel bars of 25mm diameter in each corner. Find the safe axial load on the column when concrete subjected to a stress of 5N/mm 2 what is the corresponding stress in steel take E s /E s =18 Area of the column =300x300 Area of the steel bar= Stress on concrete =5N/mm 2 E s /E s =18 To find Load (P) Stress in steel Step: 1 To calculate total load on steel = 2
3 Step: 2 To calculate total load on concrete = Step: 3 To calculate total load on the beam = + Step: 4 Total Stress in steel = 3. A rod of made brass, copper and aluminum, as shown in fig is held between two rigid supports at A and D calculate the stresses developed in each material when the temperature of the system is raised by 40 o C. Take E s =2.1x10 5 N/mm 2. E c =1.1x10 5 N/mm 2. E a =0.7x10 5 N/mm 2 = 12x10-6 / 0 C; = 17x10-6 / 0 C.; = 21x10-6 / 0 C; 3
4 Area of the steel A s =100 mm 2 Length of the steel L s =75mm Area of the copper A c =200 mm 2 Length of the copper L c =150mm Area of the Aluminium A a =400 mm 2 Length of the Aluminium L a =200mm Rise in temperature T=40 0 C Young s modulus of steel E s =2.1x10 5 N/mm 2 Young s modulus of copper E c =1.1x10 5 N/mm 2 Young s modulus of aluminium E a =0.7x10 5 N/mm 2 Co- Efficient of linear expansions of steel = 12x10-6 / 0 C Co- Efficient of linear expansions of copper = 17x10-6 / 0 C. Co- Efficient of linear expansions of Aluminium = 21x10-6 / 0 C To Find 1. Stress in steel 2. Stress in copper 3. Stress in aluminium Step: 1 To calculate elongation of steel = Step: 2 To calculate elongation of copper = Step: 3 To calculate elongation of aluminum = 4
5 Step: 4 To calculate total elongation = + + Step: 5 Total force exerted in the bar P= = = Step: 6 To calculate total elongation = + + 5
6 4. Find the Young s modulus and poisons ratio of a metallic bar of length 300mm breadth 40mm depth 40mm when the bar is subjected to an axial load of 40KN decrease in length is 0.75 and increase in breadth in 0.03mm also find the modulus of rigidity of bar. Length L=300mm Breadth b =40mm Depth t = 40mm Axial load P= 40kN Decrease in length δ L =0.75mm Increase in breadth δ b =0.03mm To find Young s modulus E Poisson s ratio 1/m Modulus of rigidity G Step: 1 To calculate the passion ratio Passion ratio 1/m= = Lateral strain (e t ) = Lateral strain (e t ) = 6
7 Step: 2 To calculate the young s modulus Tensile stress σ= load /area E= tensile stress /tensile (or) longitudinal strain Step: 3 To calculate the modulus of rigidity Young s modulus (E) = UNIT II SHEAR AND BENDING OF BEAMS 5. A cantilever 1.5m long is loaded with uniformly distributed load of 2KN/m run over the length of 1.25 m from the free end. It also carries a point load of 3kNat a distance of 0.25m from the free end. Draw the shear force and bending moment diagram for the cantilever beam. 7
8 To draw: SFD and BMD. Step: 1 SF calculation draw: SFD and BMD. Step: 2 BM calculations 8
9 6. A simply supported beam is loaded as shown in fig Q. 12 (b). Draw the shear force and bending moment diagrams. (AU-APR-2005) Refer figure Q. 12 To draw: SFD and BMD. Draw: SFD and BMD. Step: 1 SF calculation 9
10 Step: 2 BM calculations 7. A beam 8 meters long rest on two supports one at the right end and the other two meters from the left end. The beam carries uniformly distributed load of 15kN/m over its entire length and point load of 80kN at a point 1.5m from the right end. Draw the SFD and BMD and find magnitude and location of maximum bending moment. Locate also the point of contra flexure 10
11 To draw: SFD and BMD. Step: 1 SF calculation draw: SFD and BMD. Step: 2 BM calculations 11
12 8. A timber beam of rectangular section is to support a load of 20 kn uniformly distributed over a span of 3.6 m, when the beam is simply supported. If the depth is twice the width of the section and the stress in timber is not to exceed 3.5 N/mm 2, find the dimensions of the cross section? UDL load=20kn/m Length (L) =3.6m Depth=twice the width Stress= 3.5 N/mm 2 To find Dimensions of the cross section Step: 1 To calculate the bending moment M= for SSB Step: 2 To calculate section modulus of the beam (Z) Bending equation = = = = y=d/2 for rectangular crass section 12
13 Step: 3 To calculate the dimensions of the beam Section modulus of the beam (Z) = for rectangular crass section 9. A I section beam 350mm x 200mm has a web thickness of 12.5mm and a flange thickness of 25mm. it carries a shearing force of 20 tonnes at a section. To calculate shear stress a crosses the section Breath b=350mm Depth d=200mm Flange thickness =25mm Web thickness =12.5mm Shear force (F) =20tonnes To find Shear stress of the beam 13
14 Step: 1 To calculate the center of gravity section from top face. = Step: 2 To cal calculate the total moment of inertia of the beam (I) = + + Step: 3 To calculate shear stress in upper flange with web (q) = 14
15 Step: 4 To calculate shear stress in web with upper flange (q) = Step:5 To calculate maximum shear stress of the beam (q max ) =
16 UNIT III TORSION 10. A shaft is subjected to a torque of 1.6kNm. Find the necessary diameter of the shaft, if the allowable shear stress is 60Mpa, the allowable twist is 1 o for every 20 diameters length of the shaft, take C=80Gpa. Torque (T)=1.6 knm Allowable shear stress ( )=60Mpa Angle of twist =1 o Length l= 20d To find Diameter of the shaft (d) Step:1 To calculate the diameter considering shear stress Torque (T) = 16
17 Step:2 To calculate the diameter considering angle of twist Torsion equation = = for solid shaft 11. Calculate the power that can be transmitted at a300rpm by a hollow steel shaft of 75mm external diameter and 50mm internal diameter when the permissible shear stress for the steel is 70N/mm 2 and the maximum torque is 1.3 times of the mean torque. Compare the strength of this hollow shaft with that of an solid shaft. The same material, weight and length of both the shafts are same. Speed N=300rpm External dia D=75mm Internal dia d=50mm Shear stress ( ) = 70N/mm 2 Torque T max =1.3T mean To find Power Strength of hollow shaft Strength of solid shaft Step: 1 To calculate maximum torque (T max ) (T h ) =(T max )= 17
18 Step :2 To calculate mean torque (T mean ) T max =1.3T mean Step: 3 To calculate power Power (P) = Step :4 Strength compression Area of the hollow shaft = area of the solid shaft = 4 4 To calculate solid shaft diameter Step : 5 Torque transmitted to the solid shaft (T s ) Torque (T) = 18
19 Step :6 = 12. Hollow steel shaft of 75mm outside diameter is transmitting a power of 300kW at 2000rpm. Find the thickness of the shaft if the maximum shear stress should not exceed 40N/mm 2 Speed N=2000rpm External dia D=75mm Power (P)= 300KW Shear stress ( ) = 40N/mm2 To find Thickness of the shaft Step :1 To calculate maximum torque (T) Power (P) = Step :2 (T)= 19
20 Step :3 To calculate thickness t= 13. A closed coil helical spring of circular crass section wire 18mm diameter is loaded by a force of 500N. the mean coil diameter of the spring is 125mm. the modulus of rigidity is 80 kn/mm 2 determine the maximum shear in the material of the spring. What number of coils must the spring have for its deflection to be 6mm and calculate the stiffness of the spring Wire diameter d=18mm Mean diameter D= 125mm Load P= 500N Modulus of rigidity C= 80 kn/mm 2 Deflection δ=6mm To find Shear stress (τ) Number of coils (n) Stiffness of the spring (K) Step: 1 To calculate the Shear stress (τ) Shear stress (τ) = 20
21 Step: 2 To calculate number of coils = 8 Step: 3 To calculate the stiffness of the spring = = 64 Step: 4 To calculate strain energy (U) = l=πdn 21
22 14. An open coiled helical spring made of 5mm diameter wire 16 coils 100mm inner diameter with the helix angle of 16 o calculate the deflection, maximum direct and shear stresses induced due to an axial load of 300N. take G= 90Gpa and E=200Gpa Wire diameter d=5mm Inner diameter Di= 125mm Load P= 300N Modulus of rigidity C= 90 Gpa Young s modulus E=200Gpa Number of coils (n) =16 Helix angle = 16 To find Maximum direct& Shear stress (τ) Deflection δ Stiffness of the spring (K) Step: 1 Deflection = + Step: 2 Calculate bending stress 22
23 = 32 Step: 3 Calculate shear stress = 16 Step: 4 Calculate maximum shear stress = 16 Step: 4 Calculate maximum principal stress (direct stress) =
24 UNIT IV DEFLECTION 15. A cantilever AB, 2m long is carrying a load of 20kN at free end and 30kN at a distance of 1 m from the free end. Find the slop and deflection at the free end. Take E= 200Gpa and I= 150 x 10 6 mm 4 E= 200Gpa I= 150 x 10 6 mm 4 To find Slop and deflection of the beam at the free end Double integration method Step: 1 To calculate Slope at the free end due W 1 = 2 24
25 Step: 2 To calculate Slope at the free end due W 2 = 2 Step: 3 To calculate total slope at the free end = = + Step: 4 To calculate the deflection at the free end To calculate deflection at the free end due W 1 = 3 Step :5 To calculate deflection at the free end due W 2 = 3 25
26 Step: 6 To calculate total deflection at the free end = = + Macaulay s method Moment area method 26
27 Conjugate beam method 16. A beam is simply supported as its ends over a span of 10m and carries two concentrated loads of 100kN and 60 kn at a distance of 2m and 5m respectively from the left support. Calculate (i) slope at left support (ii) slope and deflection at under the100 kn load. Assume EI=36x10 4 kn-m 2 EI=36x10 4 kn-m 2 To find (i) slope at left support (ii) slope and deflection at under the100 kn load 27
28 Step-1 Macaulay s method Step-2 Slope at the left support Step-3 Deflection at 100kN load 28
29 Step-4 Slope at 100 kn load 17. An I section joist 400mmx 200mmx 20mm and 6m long is used as strut with both ends fixed. What is Euler s crippling load for the column? Take E=200Gpa. Depth (d) = 400mm Breath (b) =200mm Thickness (t) = 20mm Length l= 6m Young s modulus (E) = 2x 10 5 N/mm 2 To find Critical load Step-1 To calculate the moment of inertia about x-x axis = 29
30 Step-2 To calculate the moment of inertia about y-y axis = Step-3 To calculate the crippling load (P) ( ) = Find Euler s crippling load for a hollow cylindrical cast iron column of 20mm external diameter, 25mm thick and 6m long hinged at both ends. Compare the load with 30
31 crushing load calculated from Rankin s formula f c = 550N/mm 2 Rankin s constant =1/1600, E=1.2x 10 5 N/mm 2 Major dia D = 200mm Minor dia d=( ) Thickness (t) = 25mm Length l= 6m σ c = 550N/mm 2 Rankin s constant = Young s modulus (E) = 1.2x 10 5 N/mm 2 To find Critical load Step-1 To calculate the moment of inertia for circular section = 1 64 Step-2 Radius of gyration K= area (A) = 31
32 Step-3 To calculate the crippling load (P) ( ) = Critical load by using Rankin s formula Step-4 P= UNIT-5 COMPLEX STRESSES AND PLANE TRUSSES 19. A steel cylinder shell 3m long which is closed at its ends, had an internal diameter of 1.5m and a wall thickness of 20mm calculate the circumferential and longitudinal stress induced and also change in dimensions of the shell if it is subjected to an internal pressure of 1.0 N/mm 2 assume the modulus of elasticity and passion ratio for steel as 200 kn/mm 2 and 0.3 respectively Length of the shell L= 3m Diameter of the shell = 1.5m Pressure (P) = 1.0 N/mm 2 Thickness of shell t= 20mm Modulus of elasticity (E)=200 kn/mm 2 Passion ratio (1/m) = 0.3 To find 32
33 Circumferential stress Longitudinal stress Change in dimensions Step-1 To calculate circumferential stress = 2 Step-2 To calculate longitudinal stress = 4 Step-3 To calculate maximum shear stress = 2 Step-4 To calculate circumferential strain = 33
34 Change in dia = Step-5 To calculate longitudinal strain = Change in length = Step-6 To calculate volumetric strain = + Change in length = 34
35 20. A spherical shell of 2m diameter is made up of 10mm thick plates. Calculate the change in diameter and volume of the cylinder, when it s subjected to an internal pressure of 1.6 Mpa. Take E= 200Gpa and 1/m= 0.3 Diameter of the shell = 2m Pressure (P) = 1.6 N/mm 2 Thickness of shell t= 10mm Modulus of elasticity (E) =200 Gpa Passion ratio (1/m) = 0.3 To find Change in dimensions Step-1 Change in dia = Step-2 Change in dia =
36 21. The state of stress at a certain point in a strained material is shown in fig calculate the principal stress inclination of the principal plane normal, shear and resultant stress on the plane MN Direct stress σ 1 =200N/mm 2 Direct stress σ 2 = 150N/mm 2 (compressive) Shear stress q= 100 N/mm 2 To find 1. Principal planes and principal stresses 2. Maximum shear stress and plane Step-1 To calculate principal plane 2 2 = Step-2 Major Principal Stress = Step-3 MinorPrincipal Stress =
37 Step-4 Maximum shear Stress = + 4 A steel cylinder shell 3m long which is closed at its ends, had an internal diameter of and wall thickness 20mm calculate the circumferential and longitudinal stress induced and also chane in dimensions of the shell if it is subjected to an internal pressure 1.0 N/mm 2 assume the modulus of elasticity and passion ratio for steel as 200kN/mm 2 and 0.3 respectively. 37
18.Define the term modulus of resilience. May/June Define Principal Stress. 20. Define Hydrostatic Pressure.
CE6306 STREGNTH OF MATERIALS Question Bank Unit-I STRESS, STRAIN, DEFORMATION OF SOLIDS PART-A 1. Define Poison s Ratio May/June 2009 2. What is thermal stress? May/June 2009 3. Estimate the load carried
SRI CHANDRASEKHARENDRA SARASWATHI VISWA MAHAVIDHYALAYA
SRI CHANDRASEKHARENDRA SARASWATHI VISWA MAHAVIDHYALAYA (Declared as Deemed-to-be University under Section 3 of the UGC Act, 1956, Vide notification No.F.9.9/92-U-3 dated 26 th May 1993 of the Govt. of
QUESTION BANK SEMESTER: III SUBJECT NAME: MECHANICS OF SOLIDS
QUESTION BANK SEMESTER: III SUBJECT NAME: MECHANICS OF SOLIDS UNIT 1- STRESS AND STRAIN PART A (2 Marks) 1. Define longitudinal strain and lateral strain. 2. State Hooke s law. 3. Define modular ratio,
QUESTION BANK DEPARTMENT: CIVIL SEMESTER: III SUBJECT CODE: CE2201 SUBJECT NAME: MECHANICS OF SOLIDS UNIT 1- STRESS AND STRAIN PART A
DEPARTMENT: CIVIL SUBJECT CODE: CE2201 QUESTION BANK SEMESTER: III SUBJECT NAME: MECHANICS OF SOLIDS UNIT 1- STRESS AND STRAIN PART A (2 Marks) 1. Define longitudinal strain and lateral strain. 2. State
PERIYAR CENTENARY POLYTECHNIC COLLEGE PERIYAR NAGAR - VALLAM THANJAVUR. DEPARTMENT OF MECHANICAL ENGINEERING QUESTION BANK
PERIYAR CENTENARY POLYTECHNIC COLLEGE PERIYAR NAGAR - VALLAM - 613 403 - THANJAVUR. DEPARTMENT OF MECHANICAL ENGINEERING QUESTION BANK Sub : Strength of Materials Year / Sem: II / III Sub Code : MEB 310
KINGS COLLEGE OF ENGINEERING DEPARTMENT OF MECHANICAL ENGINEERING QUESTION BANK. Subject code/name: ME2254/STRENGTH OF MATERIALS Year/Sem:II / IV
KINGS COLLEGE OF ENGINEERING DEPARTMENT OF MECHANICAL ENGINEERING QUESTION BANK Subject code/name: ME2254/STRENGTH OF MATERIALS Year/Sem:II / IV UNIT I STRESS, STRAIN DEFORMATION OF SOLIDS PART A (2 MARKS)
R13. II B. Tech I Semester Regular Examinations, Jan MECHANICS OF SOLIDS (Com. to ME, AME, AE, MTE) PART-A
SET - 1 II B. Tech I Semester Regular Examinations, Jan - 2015 MECHANICS OF SOLIDS (Com. to ME, AME, AE, MTE) Time: 3 hours Max. Marks: 70 Note: 1. Question Paper consists of two parts (Part-A and Part-B)
Downloaded from Downloaded from / 1
PURWANCHAL UNIVERSITY III SEMESTER FINAL EXAMINATION-2002 LEVEL : B. E. (Civil) SUBJECT: BEG256CI, Strength of Material Full Marks: 80 TIME: 03:00 hrs Pass marks: 32 Candidates are required to give their
Only for Reference Page 1 of 18
Only for Reference www.civilpddc2013.weebly.com Page 1 of 18 Seat No.: Enrolment No. GUJARAT TECHNOLOGICAL UNIVERSITY PDDC - SEMESTER II EXAMINATION WINTER 2013 Subject Code: X20603 Date: 26-12-2013 Subject
3 Hours/100 Marks Seat No.
*17304* 17304 14115 3 Hours/100 Marks Seat No. Instructions : (1) All questions are compulsory. (2) Illustrate your answers with neat sketches wherever necessary. (3) Figures to the right indicate full
UNIT 1 STRESS STRAIN AND DEFORMATION OF SOLIDS, STATES OF STRESS 1. Define stress. When an external force acts on a body, it undergoes deformation.
UNIT 1 STRESS STRAIN AND DEFORMATION OF SOLIDS, STATES OF STRESS 1. Define stress. When an external force acts on a body, it undergoes deformation. At the same time the body resists deformation. The magnitude
CIVIL DEPARTMENT MECHANICS OF STRUCTURES- ASSIGNMENT NO 1. Brach: CE YEAR:
MECHANICS OF STRUCTURES- ASSIGNMENT NO 1 SEMESTER: V 1) Find the least moment of Inertia about the centroidal axes X-X and Y-Y of an unequal angle section 125 mm 75 mm 10 mm as shown in figure 2) Determine
PES Institute of Technology
PES Institute of Technology Bangalore south campus, Bangalore-5460100 Department of Mechanical Engineering Faculty name : Madhu M Date: 29/06/2012 SEM : 3 rd A SEC Subject : MECHANICS OF MATERIALS Subject
ISHIK UNIVERSITY DEPARTMENT OF MECHATRONICS ENGINEERING
ISHIK UNIVERSITY DEPARTMENT OF MECHATRONICS ENGINEERING QUESTION BANK FOR THE MECHANICS OF MATERIALS-I 1. A rod 150 cm long and of diameter 2.0 cm is subjected to an axial pull of 20 kn. If the modulus
INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad
INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad -00 04 CIVIL ENGINEERING QUESTION BANK Course Name : STRENGTH OF MATERIALS II Course Code : A404 Class : II B. Tech II Semester Section
Name :. Roll No. :... Invigilator s Signature :.. CS/B.TECH (CE-NEW)/SEM-3/CE-301/ SOLID MECHANICS
Name :. Roll No. :..... Invigilator s Signature :.. 2011 SOLID MECHANICS Time Allotted : 3 Hours Full Marks : 70 The figures in the margin indicate full marks. Candidates are required to give their answers
Sample Question Paper
Scheme I Sample Question Paper Program Name : Mechanical Engineering Program Group Program Code : AE/ME/PG/PT/FG Semester : Third Course Title : Strength of Materials Marks : 70 Time: 3 Hrs. Instructions:
2. Determine the deflection at C of the beam given in fig below. Use principal of virtual work. W L/2 B A L C
CE-1259, Strength of Materials UNIT I STRESS, STRAIN DEFORMATION OF SOLIDS Part -A 1. Define strain energy density. 2. State Maxwell s reciprocal theorem. 3. Define proof resilience. 4. State Castigliano
CE6306 STRENGTH OF MATERIALS TWO MARK QUESTIONS WITH ANSWERS ACADEMIC YEAR
CE6306 STRENGTH OF MATERIALS TWO MARK QUESTIONS WITH ANSWERS ACADEMIC YEAR 2014-2015 UNIT - 1 STRESS, STRAIN AND DEFORMATION OF SOLIDS PART- A 1. Define tensile stress and tensile strain. The stress induced
STRESS STRAIN AND DEFORMATION OF SOLIDS, STATES OF STRESS
1 UNIT I STRESS STRAIN AND DEFORMATION OF SOLIDS, STATES OF STRESS 1. Define: Stress When an external force acts on a body, it undergoes deformation. At the same time the body resists deformation. The
2012 MECHANICS OF SOLIDS
R10 SET - 1 II B.Tech II Semester, Regular Examinations, April 2012 MECHANICS OF SOLIDS (Com. to ME, AME, MM) Time: 3 hours Max. Marks: 75 Answer any FIVE Questions All Questions carry Equal Marks ~~~~~~~~~~~~~~~~~~~~~~
Sub. Code:
Important Instructions to examiners: ) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. ) The model answer and the answer written by candidate may
BE Semester- I ( ) Question Bank (MECHANICS OF SOLIDS)
BE Semester- I ( ) Question Bank (MECHANICS OF SOLIDS) All questions carry equal marks(10 marks) Q.1 (a) Write the SI units of following quantities and also mention whether it is scalar or vector: (i)
STRENGTH OF MATERIALS-I. Unit-1. Simple stresses and strains
STRENGTH OF MATERIALS-I Unit-1 Simple stresses and strains 1. What is the Principle of surveying 2. Define Magnetic, True & Arbitrary Meridians. 3. Mention different types of chains 4. Differentiate between
PDDC 1 st Semester Civil Engineering Department Assignments of Mechanics of Solids [ ] Introduction, Fundamentals of Statics
![PDDC 1 st Semester Civil Engineering Department Assignments of Mechanics of Solids [ ] Introduction, Fundamentals of Statics](/thumbs/92/109382806.jpg "PDDC 1 st Semester Civil Engineering Department Assignments of Mechanics of Solids [ ] Introduction, Fundamentals of Statics")
Page1 PDDC 1 st Semester Civil Engineering Department Assignments of Mechanics of Solids [2910601] Introduction, Fundamentals of Statics 1. Differentiate between Scalar and Vector quantity. Write S.I.
For more Stuffs Visit Owner: N.Rajeev. R07
Code.No: 43034 R07 SET-1 JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD II.B.TECH - I SEMESTER REGULAR EXAMINATIONS NOVEMBER, 2009 FOUNDATION OF SOLID MECHANICS (AERONAUTICAL ENGINEERING) Time: 3hours
: APPLIED MECHANICS & STRENGTH OF MATERIALS COURSE CODE : 4021 COURSE CATEGORY : A PERIODS/ WEEK : 5 PERIODS/ SEMESTER : 75 CREDIT : 5 TIME SCHEDULE
COURSE TITLE : APPLIED MECHANICS & STRENGTH OF MATERIALS COURSE CODE : 4021 COURSE CATEGORY : A PERIODS/ WEEK : 5 PERIODS/ SEMESTER : 75 CREDIT : 5 TIME SCHEDULE MODULE TOPIC PERIODS 1 Simple stresses
COURSE TITLE : THEORY OF STRUCTURES -I COURSE CODE : 3013 COURSE CATEGORY : B PERIODS/WEEK : 6 PERIODS/SEMESTER: 90 CREDITS : 6
COURSE TITLE : THEORY OF STRUCTURES -I COURSE CODE : 0 COURSE CATEGORY : B PERIODS/WEEK : 6 PERIODS/SEMESTER: 90 CREDITS : 6 TIME SCHEDULE Module Topics Period Moment of forces Support reactions Centre
N = Shear stress / Shear strain
UNIT - I 1. What is meant by factor of safety? [A/M-15] It is the ratio between ultimate stress to the working stress. Factor of safety = Ultimate stress Permissible stress 2. Define Resilience. [A/M-15]
COURSE TITLE : APPLIED MECHANICS & STRENGTH OF MATERIALS COURSE CODE : 4017 COURSE CATEGORY : A PERIODS/WEEK : 6 PERIODS/ SEMESTER : 108 CREDITS : 5
COURSE TITLE : APPLIED MECHANICS & STRENGTH OF MATERIALS COURSE CODE : 4017 COURSE CATEGORY : A PERIODS/WEEK : 6 PERIODS/ SEMESTER : 108 CREDITS : 5 TIME SCHEDULE MODULE TOPICS PERIODS 1 Simple stresses
SN QUESTION YEAR MARK 1. State and prove the relationship between shearing stress and rate of change of bending moment at a section in a loaded beam.
ALPHA COLLEGE OF ENGINEERING AND TECHNOLOGY DEPARTMENT OF MECHANICAL ENGINEERING MECHANICS OF SOLIDS (21000) ASSIGNMENT 1 SIMPLE STRESSES AND STRAINS SN QUESTION YEAR MARK 1 State and prove the relationship
mportant nstructions to examiners: ) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. ) The model answer and the answer written by candidate may
SSC-JE MAINS ONLINE TEST SERIES / CIVIL ENGINEERING SOM + TOS
SSC-JE MAINS ONLINE TEST SERIES / CIVIL ENGINEERING SOM + TOS Time Allowed:2 Hours Maximum Marks: 300 Attention: 1. Paper consists of Part A (Civil & Structural) Part B (Electrical) and Part C (Mechanical)
Government of Karnataka Department of Technical Education Board of Technical Examinations, Bangalore
CIE- 25 Marks Government of Karnataka Department of Technical Education Board of Technical Examinations, Bangalore Course Title: STRENGTH OF MATERIALS Course Code: Scheme (L:T:P) : 4:0:0 Total Contact
Mechanics of Structure
S.Y. Diploma : Sem. III [CE/CS/CR/CV] Mechanics of Structure Time: Hrs.] Prelim Question Paper Solution [Marks : 70 Q.1(a) Attempt any SIX of the following. [1] Q.1(a) Define moment of Inertia. State MI
STRESS, STRAIN AND DEFORMATION OF SOLIDS
VELAMMAL COLLEGE OF ENGINEERING AND TECHNOLOGY, MADURAI 625009 DEPARTMENT OF CIVIL ENGINEERING CE8301 STRENGTH OF MATERIALS I -------------------------------------------------------------------------------------------------------------------------------
UNIT III DEFLECTION OF BEAMS 1. What are the methods for finding out the slope and deflection at a section? The important methods used for finding out the slope and deflection at a section in a loaded
Mechanics of Materials II. Chapter III. A review of the fundamental formulation of stress, strain, and deflection
Mechanics of Materials II Chapter III A review of the fundamental formulation of stress, strain, and deflection Outline Introduction Assumtions and limitations Axial loading Torsion of circular shafts
VALLIAMMAI ENGINEERING COLLEGE
VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur 603 203 DEPARTMENT OF CIVIL ENGINEERING QUESTION BANK IV SEMESTER CE6402 STRENGTH OF MATERIALS Regulation 2013 Academic Year 2017 18 Prepared by
675(1*7+ 2) 0$7(5,$/6
675(1*7+ 2) 0$7(5,$/6 (MECHANICS OF SOLIDS) (As per Leading Universities Latest syllabus including Anna University R2013 syllabus) Dr. S.Ramachandran, Professor and Research Head Faculty of Mechanical
DEPARTMENT OF CIVIL ENGINEERING
KINGS COLLEGE OF ENGINEERING DEPARTMENT OF CIVIL ENGINEERING SUBJECT: CE 2252 STRENGTH OF MATERIALS UNIT: I ENERGY METHODS 1. Define: Strain Energy When an elastic body is under the action of external
MAAE 2202 A. Come to the PASS workshop with your mock exam complete. During the workshop you can work with other students to review your work.
It is most beneficial to you to write this mock final exam UNDER EXAM CONDITIONS. This means: Complete the exam in 3 hours. Work on your own. Keep your textbook closed. Attempt every question. After the
Stress Analysis Lecture 3 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy
Stress Analysis Lecture 3 ME 276 Spring 2017-2018 Dr./ Ahmed Mohamed Nagib Elmekawy Axial Stress 2 Beam under the action of two tensile forces 3 Beam under the action of two tensile forces 4 Shear Stress
71- Laxmi Nagar (South), Niwaru Road, Jhotwara, Jaipur ,India. Phone: Mob. : /
www.aarekh.com 71- Laxmi Nagar (South), Niwaru Road, Jhotwara, Jaipur 302 012,India. Phone: 0141-2348647 Mob. : +91-9799435640 / 9166936207 1. Limiting values of poisson s ratio are (a) -1 and 0.5 (b)
2014 MECHANICS OF MATERIALS
R10 SET - 1 II. Tech I Semester Regular Examinations, March 2014 MEHNIS OF MTERILS (ivil Engineering) Time: 3 hours Max. Marks: 75 nswer any FIVE Questions ll Questions carry Equal Marks ~~~~~~~~~~~~~~~~~~~~~~~~~
Strength Of Materials/Mechanics of Solids
Table of Contents Stress, Strain, and Energy 1. Stress and Strain 2. Change in length 3. Determinate Structure - Both ends free 4. Indeterminate Structure - Both ends fixed 5. Composite Material of equal
MAHALAKSHMI ENGINEERING COLLEGE
MAHALAKSHMI ENGINEERING COLLEGE TIRUCHIRAALLI - 6113. QUESTION WITH ANSWERS DEARTMENT : CIVIL SEMESTER: V SUB.CODE/ NAME: CE 5 / Strength of Materials UNIT 3 COULMNS ART - A ( marks) 1. Define columns
D : SOLID MECHANICS. Q. 1 Q. 9 carry one mark each. Q.1 Find the force (in kn) in the member BH of the truss shown.
D : SOLID MECHANICS Q. 1 Q. 9 carry one mark each. Q.1 Find the force (in kn) in the member BH of the truss shown. Q.2 Consider the forces of magnitude F acting on the sides of the regular hexagon having
DEPARTMENT OF MECHANICAL ENGINEERING CE6306-STRENGTH OF MATERIALS
DEPARTMENT OF MECHANICAL ENGINEERING CE6306-STRENGTH OF MATERIALS CE6306 STRENGTH OF MATERIALS UNIT I STRESS, STRAIN AND DEFORMATION OF SOLIDS Rigid bodies and deformable solids Tension, Compression and
Structural Analysis I Chapter 4 - Torsion TORSION
ORSION orsional stress results from the action of torsional or twisting moments acting about the longitudinal axis of a shaft. he effect of the application of a torsional moment, combined with appropriate
MECHANICS OF SOLIDS. (For B.E. Mechanical Engineering Students) As per New Revised Syllabus of APJ Abdul Kalam Technological University
MECHANICS OF SOLIDS (For B.E. Mechanical Engineering Students) As per New Revised Syllabus of APJ Abdul Kalam Technological University Dr. S.Ramachandran, M.E., Ph.D., Mr. V.J. George, M.E., Mr. S. Kumaran,
MARKS DISTRIBUTION AS PER CHAPTER (QUESTION ASKED IN GTU EXAM) Name Of Chapter. Applications of. Friction. Centroid & Moment.
Introduction Fundamentals of statics Applications of fundamentals of statics Friction Centroid & Moment of inertia Simple Stresses & Strain Stresses in Beam Torsion Principle Stresses DEPARTMENT OF CIVIL
Strength of Materials (15CV 32)
Strength of Materials (15CV 32) Module 1 : Simple Stresses and Strains Dr. H. Ananthan, Professor, VVIET,MYSURU 8/21/2017 Introduction, Definition and concept and of stress and strain. Hooke s law, Stress-Strain
The University of Melbourne Engineering Mechanics
The University of Melbourne 436-291 Engineering Mechanics Tutorial Four Poisson s Ratio and Axial Loading Part A (Introductory) 1. (Problem 9-22 from Hibbeler - Statics and Mechanics of Materials) A short
Direct and Shear Stress
Direct and Shear Stress 1 Direct & Shear Stress When a body is pulled by a tensile force or crushed by a compressive force, the loading is said to be direct. Direct stresses are also found to arise when
PURE BENDING. If a simply supported beam carries two point loads of 10 kn as shown in the following figure, pure bending occurs at segment BC.
BENDING STRESS The effect of a bending moment applied to a cross-section of a beam is to induce a state of stress across that section. These stresses are known as bending stresses and they act normally
NORMAL STRESS. The simplest form of stress is normal stress/direct stress, which is the stress perpendicular to the surface on which it acts.
NORMAL STRESS The simplest form of stress is normal stress/direct stress, which is the stress perpendicular to the surface on which it acts. σ = force/area = P/A where σ = the normal stress P = the centric
2. Polar moment of inertia As stated above, the polar second moment of area, J is defined as. Sample copy
GATE PATHSHALA - 91. Polar moment of inertia As stated above, the polar second moment of area, is defined as z π r dr 0 R r π R π D For a solid shaft π (6) QP 0 π d Solid shaft π d Hollow shaft, " ( do
ME Final Exam. PROBLEM NO. 4 Part A (2 points max.) M (x) y. z (neutral axis) beam cross-sec+on. 20 kip ft. 0.2 ft. 10 ft. 0.1 ft.
ME 323 - Final Exam Name December 15, 2015 Instructor (circle) PROEM NO. 4 Part A (2 points max.) Krousgrill 11:30AM-12:20PM Ghosh 2:30-3:20PM Gonzalez 12:30-1:20PM Zhao 4:30-5:20PM M (x) y 20 kip ft 0.2
Members Subjected to Torsional Loads
Members Subjected to Torsional Loads Torsion of circular shafts Definition of Torsion: Consider a shaft rigidly clamped at one end and twisted at the other end by a torque T = F.d applied in a plane perpendicular
(48) CHAPTER 3: TORSION
(48) CHAPTER 3: TORSION Introduction: In this chapter structural members and machine parts that are in torsion will be considered. More specifically, you will analyze the stresses and strains in members
Mechanics of Solids. Mechanics Of Solids. Suraj kr. Ray Department of Civil Engineering
Mechanics Of Solids Suraj kr. Ray (surajjj2445@gmail.com) Department of Civil Engineering 1 Mechanics of Solids is a branch of applied mechanics that deals with the behaviour of solid bodies subjected
The problem of transmitting a torque or rotary motion from one plane to another is frequently encountered in machine design.
CHAPER ORSION ORSION orsion refers to the twisting of a structural member when it is loaded by moments/torques that produce rotation about the longitudinal axis of the member he problem of transmitting
Reg. No. : Question Paper Code : B.Arch. DEGREE EXAMINATION, APRIL/MAY Second Semester AR 6201 MECHANICS OF STRUCTURES I
WK 4 Reg. No. : Question Paper Code : 71387 B.Arch. DEGREE EXAMINATION, APRIL/MAY 2017. Second Semester AR 6201 MECHANICS OF STRUCTURES I (Regulations 2013) Time : Three hours Maximum : 100 marks Answer
EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 3 Torsion
EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 3 Torsion Introduction Stress and strain in components subjected to torque T Circular Cross-section shape Material Shaft design Non-circular
FIXED BEAMS IN BENDING
FIXED BEAMS IN BENDING INTRODUCTION Fixed or built-in beams are commonly used in building construction because they possess high rigidity in comparison to simply supported beams. When a simply supported
D : SOLID MECHANICS. Q. 1 Q. 9 carry one mark each.
GTE 2016 Q. 1 Q. 9 carry one mark each. D : SOLID MECHNICS Q.1 single degree of freedom vibrating system has mass of 5 kg, stiffness of 500 N/m and damping coefficient of 100 N-s/m. To make the system
2. (a) Explain different types of wing structures. (b) Explain the advantages and disadvantages of different materials used for aircraft
Code No: 07A62102 R07 Set No. 2 III B.Tech II Semester Regular/Supplementary Examinations,May 2010 Aerospace Vehicle Structures -II Aeronautical Engineering Time: 3 hours Max Marks: 80 Answer any FIVE
Unit I Stress and Strain
Unit I Stress and Strain Stress and strain at a point Tension, Compression, Shear Stress Hooke s Law Relationship among elastic constants Stress Strain Diagram for Mild Steel, TOR steel, Concrete Ultimate
Stress Analysis Lecture 4 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy
Stress Analysis Lecture 4 ME 76 Spring 017-018 Dr./ Ahmed Mohamed Nagib Elmekawy Shear and Moment Diagrams Beam Sign Convention The positive directions are as follows: The internal shear force causes a
Advanced Structural Analysis EGF Section Properties and Bending
Advanced Structural Analysis EGF316 3. Section Properties and Bending 3.1 Loads in beams When we analyse beams, we need to consider various types of loads acting on them, for example, axial forces, shear
Engineering Science OUTCOME 1 - TUTORIAL 4 COLUMNS
Unit 2: Unit code: QCF Level: Credit value: 15 Engineering Science L/601/10 OUTCOME 1 - TUTORIAL COLUMNS 1. Be able to determine the behavioural characteristics of elements of static engineering systems
Unit III Theory of columns. Dr.P.Venkateswara Rao, Associate Professor, Dept. of Civil Engg., SVCE, Sriperumbudir
Unit III Theory of columns 1 Unit III Theory of Columns References: Punmia B.C.,"Theory of Structures" (SMTS) Vol II, Laxmi Publishing Pvt Ltd, New Delhi 2004. Rattan.S.S., "Strength of Materials", Tata
IDE 110 Mechanics of Materials Spring 2006 Final Examination FOR GRADING ONLY
Spring 2006 Final Examination STUDENT S NAME (please print) STUDENT S SIGNATURE STUDENT NUMBER IDE 110 CLASS SECTION INSTRUCTOR S NAME Do not turn this page until instructed to start. Write your name on
UNIT-I Introduction & Plane Stress and Plane Strain Analysis
SIDDHARTH INSTITUTE OF ENGINEERING & TECHNOLOGY:: PUTTUR (AUTONOMOUS) Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) Subject with Code : Advanced Solid Mechanics (18CE1002) Year
Sabah Shawkat Cabinet of Structural Engineering Walls carrying vertical loads should be designed as columns. Basically walls are designed in
Sabah Shawkat Cabinet of Structural Engineering 17 3.6 Shear walls Walls carrying vertical loads should be designed as columns. Basically walls are designed in the same manner as columns, but there are
The example of shafts; a) Rotating Machinery; Propeller shaft, Drive shaft b) Structural Systems; Landing gear strut, Flap drive mechanism
TORSION OBJECTIVES: This chapter starts with torsion theory in the circular cross section followed by the behaviour of torsion member. The calculation of the stress stress and the angle of twist will be
Mechanical Engineering Ph.D. Preliminary Qualifying Examination Solid Mechanics February 25, 2002
student personal identification (ID) number on each sheet. Do not write your name on any sheet. #1. A homogeneous, isotropic, linear elastic bar has rectangular cross sectional area A, modulus of elasticity
UNIVERSITY OF SASKATCHEWAN ME MECHANICS OF MATERIALS I FINAL EXAM DECEMBER 13, 2008 Professor A. Dolovich
UNIVERSITY OF SASKATCHEWAN ME 313.3 MECHANICS OF MATERIALS I FINAL EXAM DECEMBER 13, 2008 Professor A. Dolovich A CLOSED BOOK EXAMINATION TIME: 3 HOURS For Marker s Use Only LAST NAME (printed): FIRST
CIVL222 STRENGTH OF MATERIALS. Chapter 6. Torsion
CIVL222 STRENGTH OF MATERIALS Chapter 6 Torsion Definition Torque is a moment that tends to twist a member about its longitudinal axis. Slender members subjected to a twisting load are said to be in torsion.
2 marks Questions and Answers
1. Define the term strain energy. A: Strain Energy of the elastic body is defined as the internal work done by the external load in deforming or straining the body. 2. Define the terms: Resilience and
Semester: BE 3 rd Subject :Mechanics of Solids ( ) Year: Faculty: Mr. Rohan S. Kariya. Tutorial 1
Semester: BE 3 rd Subject :Mechanics of Solids (2130003) Year: 2018-19 Faculty: Mr. Rohan S. Kariya Class: MA Tutorial 1 1 Define force and explain different type of force system with figures. 2 Explain
CIV100 Mechanics. Module 5: Internal Forces and Design. by: Jinyue Zhang. By the end of this Module you should be able to:
CIV100 Mechanics Module 5: Internal Forces and Design by: Jinyue Zhang Module Objective By the end of this Module you should be able to: Find internal forces of any structural members Understand how Shear
Tuesday, February 11, Chapter 3. Load and Stress Analysis. Dr. Mohammad Suliman Abuhaiba, PE
1 Chapter 3 Load and Stress Analysis 2 Chapter Outline Equilibrium & Free-Body Diagrams Shear Force and Bending Moments in Beams Singularity Functions Stress Cartesian Stress Components Mohr s Circle for
Purpose of this Guide: To thoroughly prepare students for the exact types of problems that will be on Exam 3.
ES230 STRENGTH OF MTERILS Exam 3 Study Guide Exam 3: Wednesday, March 8 th in-class Updated 3/3/17 Purpose of this Guide: To thoroughly prepare students for the exact types of problems that will be on
NAME: Given Formulae: Law of Cosines: Law of Sines:
NME: Given Formulae: Law of Cosines: EXM 3 PST PROBLEMS (LESSONS 21 TO 28) 100 points Thursday, November 16, 2017, 7pm to 9:30, Room 200 You are allowed to use a calculator and drawing equipment, only.
Strength of Material. Shear Strain. Dr. Attaullah Shah
Strength of Material Shear Strain Dr. Attaullah Shah Shear Strain TRIAXIAL DEFORMATION Poisson's Ratio Relationship Between E, G, and ν BIAXIAL DEFORMATION Bulk Modulus of Elasticity or Modulus of Volume
2. Rigid bar ABC supports a weight of W = 50 kn. Bar ABC is pinned at A and supported at B by rod (1). What is the axial force in rod (1)?
IDE 110 S08 Test 1 Name: 1. Determine the internal axial forces in segments (1), (2) and (3). (a) N 1 = kn (b) N 2 = kn (c) N 3 = kn 2. Rigid bar ABC supports a weight of W = 50 kn. Bar ABC is pinned at
Entrance exam Master Course
- 1 - Guidelines for completion of test: On each page, fill in your name and your application code Each question has four answers while only one answer is correct. o Marked correct answer means 4 points
CHENDU COLLEGE OF ENGINEERING &TECHNOLOGY DEPARTMENT OF CIVIL ENGINEERING SUB CODE & SUB NAME : CE2351-STRUCTURAL ANALYSIS-II UNIT-1 FLEXIBILITY
CHENDU COLLEGE OF ENGINEERING &TECHNOLOGY DEPARTMENT OF CIVIL ENGINEERING SUB CODE & SUB NAME : CE2351-STRUCTURAL ANALYSIS-II UNIT-1 FLEXIBILITY METHOD FOR INDETERMINATE FRAMES PART-A(2MARKS) 1. What is
CO~RSEOUTL..INE. revisedjune 1981 by G. Frech. of..a.pqij~t(..~ttsa.fidteconol.q.gy. Sault ",Ste'...:M~ri,e.: SAUl. ir.ft\,nl~t';~l' G ". E b:.
-/ 1/ /.. SAUl. ir.ft\,nl~t';~l' G ". E b:.~~~~~, of..a.pqij~t(..~ttsa.fidteconol.q.gy. Sault ",Ste'...:M~ri,e.: ',' -.\'~. ~ ;:T.., CO~RSEOUTL..INE ARCHITECTURAL ENGINEERING II ARC 200-4 revisedjune 1981
UNIT I SIMPLE STRESSES AND STRAINS
Subject with Code : SM-1(15A01303) Year & Sem: II-B.Tech & I-Sem SIDDHARTH GROUP OF INSTITUTIONS :: PUTTUR Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) UNIT I SIMPLE STRESSES
Chapter 4-b Axially Loaded Members
CIVL 222 STRENGTH OF MATERIALS Chapter 4-b Axially Loaded Members AXIAL LOADED MEMBERS Today s Objectives: Students will be able to: a) Determine the elastic deformation of axially loaded member b) Apply
Strength of Materials Prof S. K. Bhattacharya Department of Civil Engineering Indian Institute of Technology, Kharagpur Lecture - 18 Torsion - I
Strength of Materials Prof S. K. Bhattacharya Department of Civil Engineering Indian Institute of Technology, Kharagpur Lecture - 18 Torsion - I Welcome to the first lesson of Module 4 which is on Torsion
National Exams May 2015
National Exams May 2015 04-BS-6: Mechanics of Materials 3 hours duration Notes: If doubt exists as to the interpretation of any question, the candidate is urged to submit with the answer paper a clear
UNIT-V MOMENT DISTRIBUTION METHOD
UNIT-V MOMENT DISTRIBUTION METHOD Distribution and carryover of moments Stiffness and carry over factors Analysis of continuous beams Plane rigid frames with and without sway Neylor s simplification. Hardy
Aluminum shell. Brass core. 40 in
PROBLEM #1 (22 points) A solid brass core is connected to a hollow rod made of aluminum. Both are attached at each end to a rigid plate as shown in Fig. 1. The moduli of aluminum and brass are EA=11,000
EDEXCEL NATIONAL CERTIFICATE/DIPLOMA SCIENCE FOR TECHNICIANS OUTCOME 1 - STATIC AND DYNAMIC FORCES TUTORIAL 3 STRESS AND STRAIN
EDEXCEL NATIONAL CERTIFICATE/DIPLOMA SCIENCE FOR TECHNICIANS OUTCOME 1 - STATIC AND DYNAMIC FORCES TUTORIAL 3 STRESS AND STRAIN 1 Static and dynamic forces Forces: definitions of: matter, mass, weight,
Cork Institute of Technology. Autumn 2007 Mechanics of Materials (Time: 3 Hours)
Cork Institute of Technology Bachelor of Engineering (Honours) in Mechanical Engineering- Stage 2 (NFQ Level 8) Autumn 2007 Mechanics of Materials (Time: 3 Hours) Instructions Answer Five Questions Question
Design of Beams (Unit - 8)
Design of Beams (Unit - 8) Contents Introduction Beam types Lateral stability of beams Factors affecting lateral stability Behaviour of simple and built - up beams in bending (Without vertical stiffeners)