EE100Su08 Lecture #9 (July 16 th 2008)


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1 EE100Su08 Lecture #9 (July 16 th 2008) Outline HW #1s and Midterm #1 returned today Midterm #1 notes HW #1 and Midterm #1 regrade deadline: Wednesday, July 23 rd 2008, 5:00 pm PST. Procedure: HW #1: Bart s office hours Midterm #1: Attach a note to the FRONT of your test with your complaint and drop it in HW box Questions? This week: Operational Amplifiers (OpAmps) OpAmp Model Negative Feedback for Stability Components around OpAmp define the Circuit Function Nonlinear circuits OpAmp from 2Port Blocks Slide 1
2 The Operational Amplifier The operational amplifier ( op amp ) is a basic building block used in analog circuits. Its behavior is modeled using a dependent source. When combined with resistors, capacitors, and inductors, it can perform various useful functions: amplification/scaling of an input signal sign changing (inversion) of an input signal addition of multiple input signals subtraction of one input signal from another integration (over time) of an input signal differentiation (with respect to time) of an input signal analog filtering nonlinear functions like exponential, log, sqrt, etc Isolate input from output; allow cascading Slide 2
3 Op Amp Terminals 3 signal terminals: 2 inputs and 1 output IC op amps have 2 additional terminals for DC power supplies Commonmode signal= (v 1 v 2 )/2 Differential signal = v 1 v 2 V positive power supply Inverting input v 2 Noninverting input v 1  v 0 output V negative power supply Slide 3
4 Op Amp Notation and Model Slide 4
5 Op Amp Notation and Model Slide 5
6 Op Amp Notation and Model Slide 6
7 Op Amp Notation and Model Slide 7
8 Op Amp Notation and Model Slide 8
9 Op Amp Notation and Model Slide 9
10 Op Amp Notation and Model Slide 10
11 Slide 11
12 Slide 12
13 Slide 13
14 Slide 14
15 Slide 15
16 SummingPoint Constraint Check if under negative feedback Small v i result in large v o Output v o is connected to the inverting input to reduce v i Resulting in v i =0 Summingpoint constraint v 1 = v 2 i 1 = i 2 =0 Virtual short circuit Not only voltage drop is 0 (which is short circuit), input current is 0 This is different from short circuit, hence called virtual short circuit. Slide 16
17 Ideal OpAmp Analysis Technique Assumption 1: The potential between the opamp input terminals, v () v (), equals zero. Assumption 2: The currents flowing into the opamp s two input terminals both equal zero. No Currents R 1 No Potential Difference R 2 VIN EXAMPLE V 0 Slide 17
18 Ideal OpAnalysis: NonInverting Amplifier Assumption 1: The potential between the opamp input terminals, v () v (), equals zero. Assumption 2: The currents flowing into the opamp s two input terminals both equal zero. R 1 VIN EXAMPLE KCL with currents in only two branches R 2 V 0 V IN appears here v R v in v in v R out = 1 2 R1 R2 out = v in R1 0 Noninverting Amplifier Slide 18
19 Ideal voltage amplifier v in  _ R 2 R 1 NonInverting Amplifier v 0 v1 = v2 = vin, i1 = i2 = 0 v 2 Use KCL At Node 2. 2 R L Closed loop gain ( v0 v2) ( v2 0) i = = R R 2 1 vo ( R1 R2) A = = v R in Input impedance 1 = A = v i v v v o in in = Slide 19
20 Ideal OpAmp Analysis: Inverting Amplifier R 1 R 2 I 2 V IN V R R L V OUT Voltage is V R Only two currents for KCL V V R V R OUT 1 IN = V R V R R R V R 2 OUT = 0 ( V V ) Inverting Amplifier with reference voltage 2 1 in R Slide 20
21 Negative feedback checked Use summingpoint constraint i v in  R 1 2 v 2 v 1 _ R 2 Inverting Amplifier v 0 R L v Closed loop gain = Av = v v1 = v2 = 0, i1 = i2 = 0 Use KCL At Node 2. ( vin v2) ( vout v2) i = = R1 R2 Rv 2 o vo = R1 vin Input impedance = = R1 i o in Ideal voltage source independent of load resistor Slide 21
22 Voltage Follower v in  v 2 v 0 _ RL R R i 2 1 = 0 ( v0 v2) ( v2 0) = = R R 2 1 vo ( R1 R2) R2 A = = = 1 = 1 v R R in 1 1 Slide 22
23 Slide 23
24 Slide 24
25 Slide 25
26 Slide 26
27 Slide 27
28 Slide 28
29 Summing Amplifier v 1 R 1  R 0  v 2  R 2 _ v 0 v 3 R 3 Slide 29
30 Difference Amplifier R 2 v R 1 _ v 0 v 2 R 3 R 4 Slide 30
31 Want v o Integrator = K vindt What is the difference between: v in  R C V 0  Slide 31
32 Differentiator Want R v in  C _ v 0 Slide 32
33 Nonlinear Opamp Circuits Start reading through online notes: Introduction to nonlinear circuit analysis. Outline: Differences between positive and negative feedback. Oscillator circuit. Slide 33
34 High Quality Dependent Source In an Amplifier V AMPLIFIER SYMBOL Differential Amplifier V V A 0 V 0 = A(V V ) AMPLIFIER MODEL Circuit Model in linear region R i V 1 AV 1 V 0 V 0 depends only on input (V V  ) See the utility of this: this Model when used correctly mimics the behavior of an amplifier but omits the complication of the many many transistors and other components. Slide 34
35 Model for Internal Operation A is differential gain or open loop gain Ideal op amp A Ri R = 0 o v 1 Circuit Model i 1 R o i o Common mode gain = 0 ( v v ) = = 2 v = A v A v 1 2 vcm, vd v1 v2 o cm cm d d Since v = A( v v ), A = 0 o 1 2 cm v 2 i 2 _ R i A(v 1 v 2 ) v o Slide 35
36 Model and Feedback Negative feedback connecting the output port to the negative input (port 2) Positive feedback connecting the output port to the positive input (port 1) Input impedance: R looking into the input terminals Output impedance: Impedance in series with the output terminals v 1 v 2 Circuit Model i 1 i 2 R o i o R i v o _ A(v 1 v 2 ) Slide 36
37 OpAmp and Use of Feedback A very highgain differential amplifier can function in an extremely linear fashion as an operational amplifier by using negative feedback. R 1 R 2 R 1 R 2 VIN Summing Point Negative feedback Stabilizes the output V 0 V IN R i  V 1 Circuit Model Hambley Example pp. 644 for Power Steering AV 1 V 0 We can show that that for A and R i, V 0 V IN R 1 R 1 R 2 Stable, finite, and independent of the properties of the OP AMP! Slide 37
38 Application: DigitaltoAnalog Conversion A DAC can be used to convert the digital representation of an audio signal into an analog voltage that is then used to drive speakers  so that you can hear it! Weightedadder D/A converter S4 10K 8V  S3 S2 S1 4Bit D/A 20K 40K 80K (Transistors are used as electronic switches) 5K V 0 S1 closed if LSB =1 S2 " if next bit = 1 S3 " if " " = 1 S4 " if MSB = 1 Slide 38 Binary number (volts) MSB LSB Analog output
39 Analog Output (V) Characteristic of 4Bit DAC 0100 Digital Input Slide
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