Developmental Algebra Beginning and Intermediate - Preparing for College Mathematics

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Contents Excerpt of Chapter 1 For additional information on adopting this book

1 Developmental Algebra Beginning and Intermediate - Preparing for College Mathematics By Paul Pierce Included in this preview: Copyright Page Table of Contents Excerpt of Chapter 1 For additional information on adopting this book for your class, please contact us at x501 or via at info@cognella.com

2 Beginning and Intermediate ALGEBRA Preparing for College Mathematics By Paul Pierce Texas Tech University Lubbock, Texas

3 Copyright 2011 by Paul Pierce. All rights reserved. No part of this publication may be reprinted, reproduced, transmitted, or utilized in any form or by any electronic, mechanical, or other means, now known or hereafter invented, including photocopying, microfilming, and recording, or in any information retrieval system without the written permission of University Readers, Inc. First published in the United States of America in 2011 by Cognella, a division of University Readers, Inc. Trademark Notice: Product or corporate names may be trademarks or registered trademarks, and are used only for identification and explanation without intent to infringe Printed in the United States of America ISBN:

4 Table of Contents Solving Linear Equations: The Addition Principle of Equality Solving Linear Equations: The Multiplication Principle of Equality Solving Linear Equations: Combining Like Terms Solving Linear Equations: The Distributive Property Solving Linear Equations: Fractions and Decimals Solving Linear Equations: A General Strategy Solving Linear Inequalities Solving Absolute Value Equations and Inequalities Applications Involving One-Variable Linear Equations...33 Chapter 2: Two-Variable Linear Equations and Inequalities The Rectangular Coordinate System Intercepts and Graphing Lines Slopes and Graphing Lines Equations of Lines Parallel and Perpendicular Lines Graphing Two-Variable Linear Inequalities...74

5 Chapter 3: Systems of Two-Variable Linear Equations and Inequalities Solving Systems of Linear Equations: Graphing Method Solving Systems of Linear Equations: Substitution Method Solving Systems of Linear Equations: Elimination Method Graphing Systems of Linear Inequalities Applications Involving Systems of Linear Equations Chapter 4: Polynomials Basic Rules of Exponents Introduction to Polynomials Adding and Subtracting Polynomials Multiplying Polynomials Dividing Polynomials Operations on Polynomials with Multiple Variables Chapter 5: Factoring Polynomials Greatest Common Factors (GCF) Factoring by Grouping Factoring Trinomials of the Form x 2 + bx + c Factoring Trinomials of the Form ax 2 + bx + c, a > 1: The ac-method Factoring Differences of Squares, Differences of Cubes and Sums of Cubes Solving Quadratic Equations by Factoring Applications Involving Quadratic Equations

6 Chapter 6: Rational Expressions and Equations Simplifying Rational Expressions Multiplying Rational Expressions Dividing Rational Expressions Adding and Subtracting Rational Expressions With Common Denominators Least Common Denominators Adding and Subtracting Rational Expressions With Different Denominators Solving Rational Equations Chapter 7: Radical Expressions and Equations Multiplying and Simplifying Radical Expressions Dividing and Simplifying Radical Expressions Adding and Subtracting Radical Expressions Rationalizing Denominators Solving Radical Equations Chapter 8: Quadratic Equations Solving Quadratic Equations: Square Root Principle Solving Quadratic Equations: Completing the Square Solving Quadratic Equations: Quadratic Formula Graphing Quadratic Equations More Applications Involving Quadratic Equations...258

7 Appendix A: Review of Basic Math Skills Skill Objective 1: Multiplying Fractions Skill Objective 2: Simplifying Fractions Skill Objective 3: Multiplying, Dividing, and Simplifying Fractions Skill Objective 4: Adding and Subtracting Fractions With Common Denominators Skill Objective 5: Least Common Denominators Skill Objective 6: Adding and Subtracting Fractions With Different Denominators Skill Objective 7: Multiplying Signed Numbers Skill Objective 8: Dividing Signed Numbers Skill Objective 9: Adding Signed Numbers Skill Objective 10: Subtracting Signed Numbers Appendix B: Answers to Odd-Numbered Exercises Dedication To my beautiful wife, Laura. For over twenty years, she has held my hand while the lights have grown dim.

Chapter 1 One-Variable Linear Equations and Inequalities 1.1 Solving Linear Equations: The Addition Principle of Equality 1.2 Solving Linear Equations: The Multiplication Principle of Equality 1.

8 Chapter 1 One-Variable Linear Equations and Inequalities 1.1 Solving Linear Equations: The Addition Principle of Equality 1.2 Solving Linear Equations: The Multiplication Principle of Equality 1.3 Solving Linear Equations: Combining Like Terms 1.4 Solving Linear Equations: The Distributive Property 1.5 Solving Linear Equations: Fractions and Decimals 1.6 Solving Linear Equations: A General Strategy 1.7 Solving Linear Inequalities 1.8 Solving Absolute Value Equations and Inequalities 1.9 Applications Involving One-Variable Linear Equations Think of an equation as a scale. Keep it balanced!

9 2 1.1 Solving Linear Equations: The Addition Principle of Equality a. Determine whether a number is a solution of an equation. b. Solve one-variable linear equations using the addition principle of equality. What is an Equation? An equation is a statement that claims that one mathematical expression is the same as, or is equal to, another mathematical expression. The two expressions are separated by an equal sign, =. If there is no equal sign, then it is just an expression, not an equation. Not all statements are true, and likewise, not all equations are true. What is a Solution of an Equation? Any value which, when substituted in for the variable in an equation, causes the equation to be true is called a solution of the equation. To solve an equation means to find ALL of its solutions. All of the solutions of an equation form the solution set of the equation. Example 1 Determine whether the equation is true, false, or conditional. a = 11 True b. 5 1 = 3 False c. x + 2 = 15 Conditional, the value of x is not known. Example A Determine whether the equation is true, false, or conditional. a. 7 5 = 2 b = 9 c. x + 1 = 8 Example 2 Determine whether 7 is a solution of the equation x + 15 = 23. Solution: x + 15 = 23 Start with the equation ? 23 Substitute 7 for x False Since the left and right sides differ, 7 is not a solution. Example B Determine whether 8 is a solution of the equation x + 15 = 23.

10 3 What Does Equivalent Equation Mean? Equations with the same solution set are called equivalent equations. The Addition Principle of Equality For any real numbers a, b, and c, if a = b, then a + c = b + c, (1) and if a = b, then a c = b c. (2) This essentially means that the same value can be added to (or subtracted from) BOTH sides of an equation while preserving equality. The Addition Principle produces an equivalent equation. As a direct result of the Addition Principle, we can state the following rules: if a + c = b, then a = b c (3) and if a c = b, then a = b + c (4) Example 3 Solve x + 5 = 7. Solution: Using rule (3), subtract 5 from both sides to isolate x. x 5 7 x 7 5 x 12 Check: x ? 7 The solution is Example 4 Solve 8 = x 17 Solution: Using rule (4), add 17 to both sides to isolate x. 8 x x 25 x Check: 8 x 17 8? The solution is 25. Example C Solve x + 9 = 11. Example D Solve 15 = x 12

11 4 Example 5 Solve 7 + x = 18 Solution: Using rule (4), add 7 to both sides to isolate x. Example E Solve 3 + x = x 18 x 18 7 Check: 7 x 18 7 ( 11)? x 11 The solution is 11. Example 6 Solve x = 1 4 and graph the solution on a number line. Example F Solve x = 1 16 and graph the solution on a number line. Solution: Using rule (3), subtract 5 4 from both sides to isolate x. 5 1 x x x 1 4 The solution is 1.

12 5 Exercise Set 1.1 For exercises 1-26, solve the equation using the addition principle. 1) x 2 = 3 2) x 1 = 2 3) x + 7 = 9 4) x + 2 = 4 5) 9 = x + 6 6) 7 = x + 4 7) -10 = x 29 8) -19 = x 22 9) x = 0 10) x = 0 11) -7 + x = 18 12) -6 + x = 11 13) 17 = x 14) 10 = x 15) = x 16) = x 17) 18) x = x = 7 19) x = ) x = ) x 1 6 = ) x 1 4 = ) x = 24) x + 2 = 25) x = ) x 3 4 = 3 8

13 6 1.2 Solving Linear Equations: The Multiplication Principle of Equality a. Solve one-variable linear equations using the multiplication principle of equality. The Multiplication Principle of Equality For any real numbers a, b, and c with c 0, if a = b, then a c = b c, and if a = b, then a c = b c. This means that both sides of an equation can be multiplied (or divided) by any nonzero number while preserving equality. As with the Addition Principle of Equality, using the Multiplication Principle of Equality results in an equivalent equation. Example 1 Solve 7x = 77. Solution: Divide both sides of the equation by 7. 7x = 77 7x x = 11 Check: 7x = 77 7(11)? = 77 The solution is 11. Example 2 Solve 8x = 56 Solution: Divide both sides of the equation by 8. 8x = 56 8x x = 7 Check: 8x = 56-8(-7)? = 56 The solution is 7. Example A Solve 11x = 77. Example B Solve 7x = 56

14 7 Example 3 Solve x = 4 and graph the solution on a number line. Solution: A negative sign in front of x implies a multiplication by -1. x = 4 ( 1)x = 4 Divide both sides of the equation by 1. 1x x = 4 The solution is 4. Example C Solve x = 2 and graph the solution on a number line. Example 4 Solve x Example D Solve x Solution: Divide by 4 5, which is the same as multiplying by x 4 x Check : 4 x ( 25) x x x = 25 The solution is 25.

15 8 Exercise Set 1.2 For exercise 1-46, solve using the multiplication principle. 1) 3x = 12 2) 6x = 12 3) 40 = 8x 4) 48 = 8x 5) -x = 12 6) -x = -19 7) -2x = 8 21) 22) 23) 24) 1 4 x = x = 25 1 x = x = ) 33) 34) 8 16 x x x x 35) ) -9x = 36 9) -12 = 3x 10) 30 = -5x 11) -8x = ) -7x = ) 8x = ) 4x = ) -28 = 2x 16) -55 = 5x 17) -108 = -6x 18) -144 = -8x 19) -2x = ) -7x = ) 26) 27) 28) 29) 30) 31) 2 3 x = 8 4 x = x x 1 1 x x x 21 9 x 36) 16 2 x 37) 19 5 x 38) 22 8 x 39) 11 2 x 40) ) 7.3x = ) 8.4x = ) 9 = 4.5x 44) 13.8 = 4.6x 45) -9.5x = 38 46) -3.2x = 22.4

16 9 1.3 Solving Linear Equations: Combining Like Terms a. Solve equations in which like terms need to be combined. Combining Like Terms With one-variable linear equations, there are only two types of terms: terms with variables and terms without variables, which are called constants. To combine constants, simply add or subtract as indicated. To combine variable terms, add or subtract the numbers in front of the variables, which are called coefficients, to obtain a term with the same variable. DO NOT change the variable. Solving Equations: Combining Like Terms 1. If like terms appear on the same side of an equation, combine them, then 2. If like terms appear on opposite sides of the equation, use the addition principle to collect all like terms on the same side of the equation and combine like terms again, then 3. Solve the equation using the multiplication principle. Example 1 Solve 5x + 3x = Solution: Combine like terms on each side of the equation. 5x + 3x = x = 16 Now, solve by dividing both sides by 8. 8x = 16 x = 2 Example 2 Solve 3x + 7x = 19 9 Solution: Combine like terms on each side of the equation. 3x + 7x = x = 10 Now, solve by dividing both sides by x = 10 x = 1 Example A Solve 8x + 7x = Example B Solve 14x + 8x = 50 6

17 10 Example 3 Solve -7x + 6x = Example C Solve -9x + 8x = Solution: Combine like terms on both sides of the equation. -7x + 6x = x = -1 Now, solve by dividing by -1. -x = -1 x = 1 Example 4 Solve: 6x + 15 = 45 Example D Solve: 11x + 10 = 43 Solution: Isolate the x-term by subtracting 15 from both sides. 6x + 15 = 45 6x = x = 30 Now, solve for x by dividing by 6. 6x = 30 x = 5 Check: 6x + 15 = 45 6(5) + 15? ? = 45 The solution is 5.

18 11 Example 5 Solve 7x 11 = 5x + 13 Solution: Add 11 to both sides of the equation. 7x = 5x x = 5x + 24 Next, subtract 5x from both sides of the equation. 7x 5x = 24 2x = 24 Divide both sides of the equation by 2. x = 12 Example E Solve 9x 20 = 4x + 15 Example 6 Solve 6x 8x + 16 = 7x Example F Solve 5x 9x + 11 = 3x Solution: Combine like terms on each side of the equation. 6x 8x + 16 = 7x x + 16 = 7x 9 Subtract 16 from both sides of the equation. 2x = 7x 25 Subtract 17x from both sides of the equation. 9x = 25 Divide both sides by x 9 9

19 12 Exercise Set 1.3 For exercises 1-80, solve the equation. 1) 9x + 3x = ) 7x 16x = ) 3x + 8 = 35 61) 5x + 2 = 4x + 6 2) 11x + 2x = ) -3x 2x = ) 8x + 7 = 87 62) 6x + 4 = 2x ) 3x + 11x = 98 23) -5x 3x = ) 8x + 2 = 42 63) 4x + 6 = 3x + 9 4) 4x + 9x = ) -5x + 2x = ) 3x + 10 = 22 64) 8x + 6 = 2x ) 8x + 9x = 85 6) 6x + 3x = 45 7) 7x + 6x = 39 8) 11x + 8x = 228 9) 6x + 5x = 33 10) 6x + 4x = ) -2x 4x = 24 12) -3x 6x = ) -2x 7x = 36 14) -7x 7x = ) -2x 3x = ) -6x 4x = 30 17) -6x 3x = 63 18) -6x 3x = 45 19) -8x 4x = ) -3x 8x = ) 9x 16x = ) 4x 10x = ) 5x 7x = ) 5x 12x = ) 2x 5x = ) 9x x = ) 7x x = ) 7x x = ) 9x x = ) 5x x = ) 3x x = ) 9x x = ) 6x + x = ) 7x + x = ) 8x + 3 = 43 46) 8x + 9 = 33 47) 10x + 8 = 28 48) 2x + 6 = 24 49) 3x + 7 = 28 50) 3x + 2 = 23 51) 10x 4 = 26 52) 4x 4 = 24 53) 4x 9 = 7 54) 4x 2 = 10 55) 4x 7 = 33 56) 2x 8 = 6 57) 5x 4 = 36 58) 10x 8 = 82 59) 3x 2 = 25 65) 8x + 4 = 3x ) 7x + 3 = 5x ) 9x + 7 = 2x ) 6x + 8 = 4x ) 4x + 9 = 2x ) 8x + 4 = 3x ) 2x 4 = 46 8x 72) 9x 3 = 117 6x 73) 7x 5 = 85 8x 74) 2x 4 = 52 6x 75) 6x 6 = 85 7x 76) 3x 6 = 15 4x 77) 4x 7 = 110 9x 78) 8x 1 = 76 3x 79) 10x 3 = 105 8x 80) 4x 1 = 53 5x 20) -3x 5x = 32 40) 3x + x = ) 8x 3 = 13

20 Solving Linear Equations: The Distributive Property a. Solve equations containing parentheses using the distributive property. The Distributive Property When a number appears in front of a pair of parentheses, such as 5(x + 2), this represents a multiplication. To remove the parentheses, we use this distributive property: For example, a(b + c) = ab + ac 5(x + 2) = 5 x = 5x (x + 2) = (-5) x + (-5) 2 = -5x 10 Example 1 Solve 5(x + 2) = 25 Example A Solve: 11(x + 5) = 77 Solution: Use the distributive property to remove the parentheses. 5(x + 2) = 25 5x + 10 = 25 Subtract 10 from both sides of the equation. 5x = x = 15 Divide both sides of the equation by 5. x = 3

21 14 Example 2 Solve 7(x 4) = 3(x + 4) Solution: Use the distributive property to remove the parentheses. 7(x 4) = 3(x + 4) 7x 28 = 3x + 12 Add 28 to both sides of the equation. Subtract 3x from both sides. Divide by 4. Example 3 Solve 6x 4(x + 3) = 5(x 2) 1 7x = 3x x = 40 x = 10 Solution: Remove parentheses using the distributive property. Note that the first parentheses are multiplied by 4, not just 4. 6x 4(x + 3) = 5(x 2) 1 6x 4x 12 = 5x 10 1 Combine like terms on each side of the equation. 2x 12 = 5x 11 Add 12 to both sides of the equation. 2x = 5x + 1 Subtract 5x from both sides of the equation. Divide by 3. 3x = 1 1 x 3 Example B Solve 2(x 6) = 9(x + 2) Example C Solve 5x 7(x + 5) = 4(x 6) 3

Chapter R - Review of Basic Algebraic Concepts (26 topics, no due date)

Chapter R - Review of Basic Algebraic Concepts (26 topics, no due date) Course Name: Math 00023 Course Code: N/A ALEKS Course: Intermediate Algebra Instructor: Master Templates Course Dates: Begin: 08/15/2014 End: 08/15/2015 Course Content: 245 topics Textbook: Miller/O'Neill/Hyde: