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17 N

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29 r = 0.88

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43 P x λ P x λ

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45 d m = d 1/ m, d m i 1...m ( d i ) 2 = c c i m

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53 d

54 β = 1 β = 1.5 β = 2 β = 3 d b = d a d b = 1.0 d b = 2.0 d b = 3.0 β = 1 β = 2 β = 3 d a d a χ 2 β d b

55 m m

56

57

58 µ A d A,B d A µ N µ B d B µ N A B µ N µ A d A A B A B d A,B A B d, = 2d, d d d d,

59 2 2 d d = 2z [P (C)], z [ ] z P(C) ϕ A (c) ϕ B (c) = 1, c ϕ A B

60 χ 2 χ 2 χ 2 χ 2 k k χ 2 χ 2 χ 2 χ 2 (d ) 2 d

61 µ C δ S µ C µ C + δ S c c + µ C δ S c c + µ C χ 2 HR c d ( HR = 1 F c; 1, (d ) 2), χ 2 FA FA = 1 F (c; 1), χ 2 c

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66 β = SE = p < 0.001

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69 β = SE = p = β = SE = p = d d

70 d d 1 m (d m) 2 = d m = d 1/ m + 1 d m = d 1/ m + c

71 d d d d a d m, = a d 1,, m d m, = a d m,.

72 d d d d d χ 2 = i C N i j R (p ij π ij ) 2 π ij, i j R C N i p ij π ij

73 d χ = G 2 + k (N), G 2 G 2 = 2 i C N i j R p ij (p ij /π ij ) k N i i N χ 2 G 2 d χ 2

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78 Px (C) P D (C) P D (C) P x(c) d χ 2 d d

79 d d d d d d d

80

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82 β = SE = p < β = SE = p = β = SE = p = 0.450

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84

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86 m

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90 d χ d χ d χ d χ

91 d χ

92 χ 2 d d β β χ d d β β χ

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100 β = SE = p < β = SE = p < β = SE = p = 0.076

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102 A B p A p B p R p R = p A p B, t f(t) g(t) F (f) F (g) (f g) F 1 [F (f) F (g)], F 1 f g t

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104 G 2 G 2 = 2 i N ij p ijk p ijk, π ijk j i j k N ij p ijk π ijk BIC = G 2 + k (N) k N G 2 G 2 k

105 G 2 G 2 G 2 G

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113 z s T T N (ν, η) a t ν η a T s T

114 d ν η σ

115 A B a T T er s T ν

116 G 2 0.1

117 ν α T α α α u m P(u m ) = ( ) i α m i<m ( m 1 i ) p i (1 p) m i 1, p p 1 2 m d m = d 1 m ν m

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119 ν η a T s T α T α ν α ν m = ν 1 m.

120 s t η t T

121 G 2 T ν t T T a t T a t T α t T T T T T

122 T T

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125 β = SE = p < β = SE = p < 0.001

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127 G 2 G 2 G 2 G β = SE = p < G 2

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129 G 2

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135 ν d a t T t ν d T t α t ν d a t T t α t ν ν t ν T

136 G 2 ν d a t T t ν d a t T t α t ν d a t T t α t ν d T t ν d a t T t a α ν d a t T t ν d T t α t ν α

137 ν d a t T t α t ν d a t T t ν d T t α t ν d a t T t α t

138 ν d a t T t

139 ν d T t α t α

140 ν d a t T t α t

141 ν α α

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149 T T ν d T t α t ν d a t T t ν d a t T t α t

150 G 2 T ν t T T T α t a t T G 2 T a t T T α t ν t T ν t a t T G 2 ν t T α t ν t a t T ν t T α t Tα t ν t a t T α t Tα t ν t a t T α t

151 G 2 T ν t T T α t a t T T G 2 a t T a t T α t ν t a t T a t T α t Tα t ν t a t α t

152 T ν sν a T st α Tα να T

153 T ν sν a T st α Tα να T

154 G 2 ν d T t α t ν d T t α t ν d T t α t ν d α ν T α t Tα t ν d T t α t ν d α G 2 ν T ν T ν d T t α t Tα ν t d α ν d T t α t Tα ν t d α ν d T t G 2 ν d a t T t ν d a t T t ν d a t T t α t ν d a t T t α t ν d a t T t α t ν d α

155 G 2 ν a t T α t Tα t ν a t T α t ν a t T α t Tα ν t t α ν a t T α t t ν a t T α t Tα ν t t α G 2 ν d T t ν d T t α t ν d T t α t ν T ν d T t

156 ν d T t α t ν sν a T st α Tα να ν d T t α t

157 ν d a t T t ν sν a T st α Tα να ν d a t T t

158 ν d a t T t α t ν sν a T st α Tα να ν d a t T t α t

159

160

161

162

163 π/4

164 3π/4

165 3π/4 π/4 π/4 3π/4 β = SE = p = β = SE = p < β = SE = p < 0.001

166

167

168 (d i,m) 2 = (1 f (b (θ i a))) (d 1 )2, m i m d 1 f ( ) a b d (d ) 2 d i,m = (1 f (b (θ i a))) d 1. m

169 , d (d ) 2 (d ) 2

170 θ P θ P θ P θ P (d ) 2 λ M λ M λ M / λ M = λ M f (θ) f : ( π, π) [0, 1] d = f (θ) λ M θ (0, f (θ))

171 θ 0 θ 0 π/2

172 (1 f ( )) f

173 m (d m) 2 =

174 G G 2 = 2 i A N i,j j B k R p i,j,k p i,j,k π i,j,k, i A j B k R N i,j p i,j,k π i,j,k < i, j, k >

175

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179 β = SE = p = β = SE = p = β = SE = p = 0.170

180 β = SE = p = β = SE = p = β = SE = p < β = SE = p < 0.001

181 d i,m = f (b (θi a)) d 1 ατ, m i m α τ

182 d i,m = f (b (θ i a)) d 1 ατ. m

183 m (d m) 2 = const

184 G

185 d

186

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190 G G G

191 G G

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195 G G G

196 G G

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200 β = SE = p < β = SE = p < β = SE = p < 0.001

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203 d (d i,m )2 m i (d i,m) 2 = (1 ϕ (bθ i)) (d 1 )2, m θ i i ϕ b d 1 ν ν i,m = (1 ϕ (bθi )) ν 1 m.

204 T l l T

205 η η G 2

206 T η α ν T l T s η s α s ν α ν α ν

207 G 2 η s T s ν α η s T s ν α T s ν α T s ν α η s T l ν α η s T s ν α

208 η s T s ν α η s T s ν α

209 η s T s ν α

210 T s ν α

211 T s ν α η s T s ν α

212 β = SE = p = 0.014

213 ν i,m = (1 ϕ (bθi )) ν 1 γτ m i m γ ϕ τ ν α

214

215 ν α ν α ν α ν α ν α ν l α ν t α ν α G 2 η s T s ν α η s T s ν α η s T s ν α η s T s ν t α η s T l ν α

216 ν s T s ν α γ

217 ν s T s ν α

218

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220 d 1 / m d 1 m η

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223 η s T s ν α ν s T s ν α

224 G 2 T s ν α T s ν α T s ν α η s T s ν α η s T s ν α G 2 T l ν α T l ν α T s ν α T s ν α η s T l ν α G 2 η s T s ν α T s ν α T s ν α T s ν α η s T s ν α

225 G 2 η s T s ν α η s T s ν α η s T s ν α η s T l ν α η s T l ν α G 2 η s T s ν α η s T l ν α η s T s ν α η s T s ν α η s T l ν α

226 η s T s ν α ν b η a T st α Tα να

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230 G 2 η s T s ν α η s T s ν α η s T s ν α η s T s ν α η s T s ν α G 2 η s T s ν α η s T l ν α η s T s ν l α η s T s ν α η s T l ν α G 2 η s T s ν α η s T s ν t α η s T s ν α η s T s ν α η s T s ν α

231 G 2 η s T s ν α η s T l ν α η s T l ν α η s T s ν α η s T l ν α G 2 η s T s ν α η s T s ν α η s T s ν α T s ν α T s ν α

232 η s T s ν α ν b γ η a T st α Tα να

233 N

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273 Minerva Access is the Institutional Repository of The University of Melbourne Author/s: Lilburn, Simon David Title: Information limits within visual short-term memory Date: 2016 Persistent Link: File Description: Information limits within visual short-term memory Terms and Conditions: Terms and Conditions: Copyright in works deposited in Minerva Access is retained by the copyright owner. The work may not be altered without permission from the copyright owner. Readers may only download, print and save electronic copies of whole works for their own personal non-commercial use. Any use that exceeds these limits requires permission from the copyright owner. Attribution is essential when quoting or paraphrasing from these works.

Chapter 10: BIM for Facilitation of Land Administration Systems in Australia

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