ECE 201 Fall 2009 Final Exam


 Rosa Philomena Jones
 2 years ago
 Views:
Transcription
1 ECE 01 Fall 009 Final Exam December 16, 009 Division 0101: Tan (11:30am) Division 001: Clark (7:30 am) Division 0301: Elliott (1:30 pm) Instructions 1. DO NOT START UNTIL TOLD TO DO SO.. Write your Name, division, professor, and student ID# (PUID) on your scantron sheet. 3. This is a CLOSED BOOKS and CLOSED NOTES exam. 4. There is only one correct answer to each question. 5. Calculators are allowed (but not necessary). Please clear any formulas, text, or other information from your calculator memory prior to the exam. 6. If extra paper is needed, use back of test pages. 7. Formulas are given on the final page of this exam. 8. Cheating will not be tolerated. Cheating in this exam will result in an F in the course. 9. If you cannot solve a question, be sure to look at the other ones and come back to it if time permits. 10. As described in the course syllabus, we must certify that every student who receives a passing grade in this course has satisfied each of the course outcomes. On this exam, you have the opportunity to satisfy all outcomes. (See the course syllabus for a complete description of each outcome.) On the chart below, we list the criteria we use for determining whether you have satisfied these course outcomes. You only need to satisfy the outcomes once during the course, so any outcomes that you satisfied previously will remain satisfied, independent of your performance on this exam. Course Outcome Exam Questions i 13, 5 ii 16 1 iii 4, 9, 18, 7 iv v vi 19 vii 36 viii 7 1 ix Minimum correct answers required to satisfy the course outcome 1
2 1. Determine the voltage V z. (1) 15V () 10V (3) 7.5V (4) 5V (5) 0 (6) 5V (7) 7.5V (8) 10V (9) 15V. For the circuit shown below, the current I is: (1) 0A () A (3) 5A (4) 6A (5) 6A (6) 10A (7) 10A
3 3. The voltage V x in the circuit shown below is: (1) 33V () 1V (3) 9V (4) 3V (5) 3V (6) 9V (7) 1V (8) 33V 4. The circuit shown below has two independent sources V 1 and I. The output voltage V out has been measured for two combinations of input sources: V 1 I V out V 5 A 1 V 4 V.5 A 1 V What would the value of V out be for V 1 = 1 V and I = 1 A? (1) 1 V () V (3) 3 V (4) 4 V (5) 5 V (6) 6 V (7) 0 V 3
4 5. The capacitor is uncharged at t = 0 (i.e. V c (0 + ) = 0). Determine V c at t = sec. (1) 10 V () 8.65 V (3) 5 V (4) 1.35 V (5) 0 (6) 1.35 V (7) 5 V (8) 8.65 V (9) 10 V 6. The switch in the RL circuit shown below has been open for a long time and closes at t=0 s. Find the inductor current i L (t) for t > 0. (1) ( e 10t ) A () ( + e 10t ) A (3) ( 4 4e 10t ) A (4) ( 4 4e 10t ) (5) ( 4 e 10t ) A (6) ( 4 e 10t ) + A (7) none of the above + A 4
5 7. Determine the rate of change in the inductor current at t = 0 + +, il '0 ( ) circuit below. di ( t) L = in the dt + t= 0 (1) 0 A/s () A/s (3) 3 A/s (4) 5 A/s (5) 5 A/s (6) 3 A/s (7)  A/s (8) 1 A/s 8. Given an input voltage of 4V, what is the output voltage V out of this circuit containing an ideal operational amplifier? (1) 0 () 5 V (3) 10 V (4) 0 V (5) 40 V (6) 0 V (7) 10 V (8) 5 V 5
6 9. Assume an ideal operational amplifier and that the capacitor is uncharged at t = 0. Find the correct expression for the output voltage V o (t) in volts for t > 0 where t is in seconds. (1) t () t + 3 (3) t + 1/4 (4) 4t + (5) 4t + 3 (6) t + 4 (7) t + 1/4 10. In the Op Amp circuit below, the Thévenin equivalent resistance R th at the inverting input is: (1) 3 kω () kω (3) 1 kω (4) 0.5 kω (5) 0 kω (6) 0.5 kω (7) 1 kω (8) kω (9) 3 kω 6
7 11. The current phasor I in the circuit below is: (1) j100 A () j10 A (3) j1 A (4) 0 A (5) j1 A (6) j10 A (7) j100 A 1. At ω = π rad/s, the phasor current through the element shown below is I = ( 45 )Arms. Determine the voltage v(t) across the element. (1) 0 () sin ( π t) V (3) cos( π t) V (4) sin ( π t 45 ) V (5) cos( π t 45 ) V (6) ( π+ ) (7) cos( π+ t 45 ) V sin t 45 V 7
8 13. The phasor current I for the node sketched below has a magnitude of: (1) 0 A () 1 A (3) 3 A (4) A (5) 5 A (6) 7 A (7) 1 A 14. The mesh current phasor I 1 in the circuit below is: (1) 1 0 A () 0 A (3) j1 A (4) j A (5) (1+j) A (6) (1+j) A (7) (+j) A (8) (+j) A 8
9 15. At ω = rad/s, the impedance Z TH (jω) = ( + jω) shown in the circuit below can be realized with: (1) a single 1Ω resistor () a single Ω resistor (3) a single 1Η inductor (4) a single H inductor (5) a 1Ω resistor in series with a 1Η inductor (6) a 1Ω resistor in series with a Η inductor (7) a Ω resistor in series with a 1Η inductor (8) a Ω resistor in series with a Η inductor 9
10 16. The circuit below contains a floating voltage source. The voltage phasors at nodes A and B are V A and V B, respectively. The correct nodal equation involving the super node (containing both nodes A and B) is: (1) V A = 5 0 V () V B =10 0 V (3) (1+j)V A + jv B = 5 0 V (4) (1+j)V A + (1+j)V B = 15 0 V (5) (+j)v A + jv B = 5 0 V (6) (+j)v A + (+j)v B = 15 0 V (7) (1+j)V A + jv B = 5 0 V (8) (1+j)V A + (1+j)V B = 15 0 V 17. In the circuit shown below, let i s (t) =.5 cos(ωt) A, with the frequency ω variable. As ω is varied, we measure the amplitude of the voltage across the capacitor as shown in the plot to the right. Determine C. (1) 1 µf () µf (3) 5 µf (4) 10 µf (5) 0 µf (6) 50 µf (7) 100 µf (8) 00 µf 10
11 18. Find the Thévenin equivalent of the following network. The value of the source V th and impedance Z th are: (1) V th = 5V, Z th = 5Ω () V th = j5v, Z th = (5+j10)Ω (3) V th = 5V, Z th = 5Ω (4) V th = (5j5)V, Z th = (5j10)Ω (5) V th = j5v, Z th = 5jΩ (6) V th = 5V, Z th = (5+j5)Ω (7) V th = 5V, Z th = (5j10)Ω (8) V th = 5V, Z th = 5jΩ 19. In the circuit below, the average power dissipated by the 1Ω resistor is 4W. If the magnitude of the source voltage phasor is increased to 3V, determine the average power dissipated by the 1Ω resistor. [Hint: Use linearity. You do not need to solve for X c!] (1) W () 4W (3) 5W (4) 6W (5) 9W (6) 1W (7) 15W 11
12 0. In the circuit shown below, the voltage across the resistor is v(t) = 4 + cos (πt) V. Find the effective (rms) value of the voltage. (1) V () V (3) 3V (4) 4V (5) 6V (6) V (7) 3V (8) 3 V 1. The current in the circuit shown below is i(t) = cos(ωt)+5cos(ωt) A. The average power absorbed by the inductor is: (1) 0 W () 0.5 W (3) 1W (4) 5W (5) 5 W (6) ( 1+ 5 ) W (7) cannot be determined 1
13 . The input current to the load Z load is i( t) = 5cos( 30 ) absorbed by the load? t A. What is the average power (1) 0 W () 5 W (3) 10 W (4) 0 W (5) 40 W (6) 80 W (7) 160 W (8) 30 W 3. A load (as shown) draws a complex power S = (40 + j30) VA. Determine the power factor of this load. (1) 1.0 leading () 0.8 leading (3) 0.6 leading (4) 0.4 leading (5) 1.0 lagging (6) 0.8 lagging (7) 0.6 lagging (8) 0.4 lagging 13
14 4. A load (as shown) draws a complex power S = (40 + j30) VA. Find the apparent power delivered to this load. (1) 50 VA () 30j VAR (3) 30 VAR (4) (4030j) VA (5) 40 VA (6) ( j) 1 VAR 5. A load (as shown) draws a complex power S = (40 + j30) VA. Determine the value of C which, when placed in parallel with the original load, will minimize the current I. Use ω = 100 rad/s. (1) 30 µf () 100 µf (3) 300 µf (4) 1000 µf (5) 3000 µf (6) 10,000 µf (7) 30,000 µf 14
15 6. In the circuit shown below, Vs is a 60 Hz, 10 V rms generator. The load consumes 30 kw of power at a power factor of cos45 lagging. A capacitor is placed in parallel with the load to improve the power factor to cos30 lagging. It is known that without the capacitor, Q old Load = 30 kvar, and with the capacitor, Qnew Load, C = 17.3 kvar. What is the value of C? (1) 35 mf () 14.7 mf (3).3 mf (4) 0 mf (5).3 mf (6) 14.7 mf (7) 35 mf 7. Find the load impedance Z L that will absorb the maximum power from the source. (1) 5 (1j) Ω () 5 (1j) Ω (3) 5 (1+j) Ω (4) 5 (1+j) Ω (5) 50 (1j) Ω (6) 50 (1j) Ω (7) 50 (1+j) Ω (8) 50 (1+j) Ω 15
16 Useful formulas + + ( o ) x(t) = x( ) + x(t o ) x( ) e t t / τ τ = L/R τ = RC ( ) t x(t) = x( ) + Acosω dt + Bsinω dt e σ t x(t) = x( ) + ( A + Bt) e σ ( st 1 st) x(t) = x( ) + Ae + Be R / L σ= 1 RC (series) (parallel) s 1, = σ ± σ ω o b ± b 4c s 1,s = for s + bs + c = 0 4c b ω d = = ω σ o ω o = 1 LC 1 cos(x) cos(y) = cos(x + y) + cos(x y) [ ] 1 cos(x) sin(y) = sin(x + y) sin(x y) [ ] 1 sin(x) sin(y) = cos(x y) cos(x + y) sin(x) = cos( x 90 ) [ ] 16
ECE Spring 2017 Final Exam
ECE 20100 Spring 2017 Final Exam May 2, 2017 Section (circle below) Qi (12:30) 0001 Tan (10:30) 0004 Hosseini (7:30) 0005 Cui (1:30) 0006 Jung (11:30) 0007 Lin (9:30) 0008 PeleatoInarrea (2:30) 0009 Name
More informationECE Spring 2015 Final Exam
ECE 20100 Spring 2015 Final Exam May 7, 2015 Section (circle below) Jung (1:30) 0001 Qi (12:30) 0002 Peleato (9:30) 0004 Allen (10:30) 0005 Zhu (4:30) 0006 Name PUID Instructions 1. DO NOT START UNTIL
More informationECE 202 Fall 2013 Final Exam
ECE 202 Fall 2013 Final Exam December 12, 2013 Circle your division: Division 0101: Furgason (8:30 am) Division 0201: Bermel (9:30 am) Name (Last, First) Purdue ID # There are 18 multiple choice problems
More informationECE Circuit Theory. Final Examination. December 5, 2008
ECE 212 H1F Pg 1 of 12 ECE 212  Circuit Theory Final Examination December 5, 2008 1. Policy: closed book, calculators allowed. Show all work. 2. Work in the provided space. 3. The exam has 3 problems
More informationEE313 Fall 2013 Exam #1 (100 pts) Thursday, September 26, 2013 Name. 1) [6 pts] Convert the following timedomain circuit to the RMS Phasor Domain.
Name If you have any questions ask them. Remember to include all units on your answers (V, A, etc). Clearly indicate your answers. All angles must be in the range 0 to +180 or 0 to 180 degrees. 1) [6 pts]
More informationEE221  Practice for the Midterm Exam
EE1  Practice for the Midterm Exam 1. Consider this circuit and corresponding plot of the inductor current: Determine the values of L, R 1 and R : L = H, R 1 = Ω and R = Ω. Hint: Use the plot to determine
More informationEE 3120 Electric Energy Systems Study Guide for Prerequisite Test Wednesday, Jan 18, pm, Room TBA
EE 3120 Electric Energy Systems Study Guide for Prerequisite Test Wednesday, Jan 18, 2006 67 pm, Room TBA First retrieve your EE2110 final and other course papers and notes! The test will be closed book
More informationFigure Circuit for Question 1. Figure Circuit for Question 2
Exercises 10.7 Exercises Multiple Choice 1. For the circuit of Figure 10.44 the time constant is A. 0.5 ms 71.43 µs 2, 000 s D. 0.2 ms 4 Ω 2 Ω 12 Ω 1 mh 12u 0 () t V Figure 10.44. Circuit for Question
More informationBasics of Network Theory (PartI)
Basics of Network Theory (PartI). A square waveform as shown in figure is applied across mh ideal inductor. The current through the inductor is a. wave of peak amplitude. V 0 0.5 t (m sec) [Gate 987: Marks]
More informationMAE140 Linear Circuits Fall 2016 Final, December 6th Instructions
MAE40 Linear Circuits Fall 206 Final, December 6th Instructions. This exam is open book. You may use whatever written materials you choose, including your class notes and textbook. You may use a handheld
More informationHomework 2 SJTU233. Part A. Part B. Problem 2. Part A. Problem 1. Find the impedance Zab in the circuit seen in the figure. Suppose that R = 5 Ω.
Homework 2 SJTU233 Problem 1 Find the impedance Zab in the circuit seen in the figure. Suppose that R = 5 Ω. Express Zab in polar form. Enter your answer using polar notation. Express argument in degrees.
More information= 32.0\cis{38.7} = j Ω. Zab = Homework 2 SJTU233. Part A. Part B. Problem 2. Part A. Problem 1
Homework 2 SJTU233 Problem 1 Find the impedance Zab in the circuit seen in the figure. Suppose that R = 5 Ω. Express Zab in polar form. Enter your answer using polar notation. Express argument in degrees.
More informationEECE 2150 Circuits and Signals, Biomedical Applications Final Exam Section 3
EECE 2150 Circuits and Signals, Biomedical Applications Final Exam Section 3 Instructions: Closed book, closed notes; Computers and cell phones are not allowed You may use the equation sheet provided but
More informationEE201 Review Exam I. 1. The voltage Vx in the circuit below is: (1) 3V (2) 2V (3) 2V (4) 1V (5) 1V (6) None of above
EE201, Review Probs Test 1 page1 Spring 98 EE201 Review Exam I Multiple Choice (5 points each, no partial credit.) 1. The voltage Vx in the circuit below is: (1) 3V (2) 2V (3) 2V (4) 1V (5) 1V (6)
More informationEECE 2150 Circuits and Signals Final Exam Fall 2016 Dec 16
EECE 2150 Circuits and Signals Final Exam Fall 2016 Dec 16 Instructions: Write your name and section number on all pages Closed book, closed notes; Computers and cell phones are not allowed You can use
More informationEECE 2510 Circuits and Signals, Biomedical Applications Final Exam Section 3. Name:
EECE 2510 Circuits and Signals, Biomedical Applications Final Exam Section 3 Instructions: Closed book, closed notes; Computers and cell phones are not allowed Scientific calculators are allowed Complete
More informationECE202 FINAL April 30, 2018 CIRCLE YOUR DIVISION
ECE 202 Final, Spring 8 ECE202 FINAL April 30, 208 Name: (Please print clearly.) Student Email: CIRCLE YOUR DIVISION DeCarlo 7:308:30 DeCarlo:302:45 2025 202 INSTRUCTIONS There are 34 multiple choice
More informationSchedule. ECEN 301 Discussion #20 Exam 2 Review 1. Lab Due date. Title Chapters HW Due date. Date Day Class No. 10 Nov Mon 20 Exam Review.
Schedule Date Day lass No. 0 Nov Mon 0 Exam Review Nov Tue Title hapters HW Due date Nov Wed Boolean Algebra 3. 3.3 ab Due date AB 7 Exam EXAM 3 Nov Thu 4 Nov Fri Recitation 5 Nov Sat 6 Nov Sun 7 Nov Mon
More informationSinusoidal Response of RLC Circuits
Sinusoidal Response of RLC Circuits Series RL circuit Series RC circuit Series RLC circuit Parallel RL circuit Parallel RC circuit RL Series Circuit RL Series Circuit RL Series Circuit Instantaneous
More informationLecture 11  AC Power
 AC Power 11/17/2015 Reading: Chapter 11 1 Outline Instantaneous power Complex power Average (real) power Reactive power Apparent power Maximum power transfer Power factor correction 2 Power in AC Circuits
More information4/27 Friday. I have all the old homework if you need to collect them.
4/27 Friday Last HW: do not need to turn it. Solution will be posted on the web. I have all the old homework if you need to collect them. Final exam: 79pm, Monday, 4/30 at Lambert Fieldhouse F101 Calculator
More informationSinusoidal SteadyState Analysis
Chapter 4 Sinusoidal SteadyState Analysis In this unit, we consider circuits in which the sources are sinusoidal in nature. The review section of this unit covers most of section 9.1 9.9 of the text.
More informationProf. Shayla Sawyer CP08 solution
What does the time constant represent in an exponential function? How do you define a sinusoid? What is impedance? How is a capacitor affected by an input signal that changes over time? How is an inductor
More informationChapter 10 AC Analysis Using Phasors
Chapter 10 AC Analysis Using Phasors 10.1 Introduction We would like to use our linear circuit theorems (Nodal analysis, Mesh analysis, Thevenin and Norton equivalent circuits, Superposition, etc.) to
More informationChapter 1W Basic Electromagnetic Concepts
Chapter 1W Basic Electromagnetic Concepts 1W Basic Electromagnetic Concepts 1W.1 Examples and Problems on Electric Circuits 1W.2 Examples on Magnetic Concepts This chapter includes additional examples
More informationELEC 2501 AB. Come to the PASS workshop with your mock exam complete. During the workshop you can work with other students to review your work.
It is most beneficial to you to write this mock midterm UNDER EXAM CONDITIONS. This means: Complete the midterm in 3 hour(s). Work on your own. Keep your notes and textbook closed. Attempt every question.
More informationSinusoidal Steady State Power Calculations
10 Sinusoidal Steady State Power Calculations Assessment Problems AP 10.1 [a] V = 100/ 45 V, Therefore I = 20/15 A P = 1 (100)(20)cos[ 45 (15)] = 500W, 2 A B Q = 1000sin 60 = 866.03 VAR, B A [b] V = 100/
More informationPossible
Department of Electrical Engineering and Computer Science ENGR 21. Introduction to Circuits and Instruments (4) ENGR 21 SPRING 24 FINAL EXAMINATION given 5/4/3 Possible 1. 1 2. 1 3. 1 4. 1 5. 1 6. 1 7.
More informationEE202 Exam III April 13, 2015
EE202 Exam III April 3, 205 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo7:308:30 Furgason 3:304:30 DeCarlo:302:30 202 2022 2023 INSTRUCTIONS There are 2 multiple choice
More informationConsider a simple RC circuit. We might like to know how much power is being supplied by the source. We probably need to find the current.
AC power Consider a simple RC circuit We might like to know how much power is being supplied by the source We probably need to find the current R 10! R 10! is VS Vmcosωt Vm 10 V f 60 Hz V m 10 V C 150
More information12. Introduction and Chapter Objectives
Real Analog  Circuits 1 Chapter 1: SteadyState Sinusoidal Power 1. Introduction and Chapter Objectives In this chapter we will address the issue of power transmission via sinusoidal or AC) signals. This
More informationSolved Problems. Electric Circuits & Components. 11 Write the KVL equation for the circuit shown.
Solved Problems Electric Circuits & Components 11 Write the KVL equation for the circuit shown. 12 Write the KCL equation for the principal node shown. 12A In the DC circuit given in Fig. 1, find (i)
More informationSinusoidal Steady State Analysis (AC Analysis) Part II
Sinusoidal Steady State Analysis (AC Analysis) Part II Amin Electronics and Electrical Communications Engineering Department (EECE) Cairo University elc.n102.eng@gmail.com http://scholar.cu.edu.eg/refky/
More informationPower Factor Improvement
Salman bin AbdulazizUniversity College of Engineering Electrical Engineering Department EE 2050Electrical Circuit Laboratory Power Factor Improvement Experiment # 4 Objectives: 1. To introduce the concept
More informationREACTANCE. By: Enzo Paterno Date: 03/2013
REACTANCE REACTANCE By: Enzo Paterno Date: 03/2013 5/2007 Enzo Paterno 1 RESISTANCE  R i R (t R A resistor for all practical purposes is unaffected by the frequency of the applied sinusoidal voltage or
More informationI. Impedance of an RL circuit.
I. Impedance of an RL circuit. [For inductor in an AC Circuit, see Chapter 31, pg. 1024] Consider the RL circuit shown in Figure: 1. A current i(t) = I cos(ωt) is driven across the circuit using an AC
More informationAC Circuits Homework Set
Problem 1. In an oscillating LC circuit in which C=4.0 μf, the maximum potential difference across the capacitor during the oscillations is 1.50 V and the maximum current through the inductor is 50.0 ma.
More informationECE 2210 Final given: Spring 15 p1
ECE 2 Final given: Spring 15 Closed Book, Closed notes except preprinted yellow sheet, Calculators OK. Show all work to receive credit. Circle answers, show units, and round off reasonably 1. (15 pts)
More informationElectric Circuits I FINAL EXAMINATION
EECS:300, Electric Circuits I s6fs_elci7.fm  Electric Circuits I FINAL EXAMINATION Problems Points.. 3. 0 Total 34 Was the exam fair? yes no 5//6 EECS:300, Electric Circuits I s6fs_elci7.fm  Problem
More information11. AC Circuit Power Analysis
. AC Circuit Power Analysis Often an integral part of circuit analysis is the determination of either power delivered or power absorbed (or both). In this chapter First, we begin by considering instantaneous
More informationThree Phase Circuits
Amin Electronics and Electrical Communications Engineering Department (EECE) Cairo University elc.n102.eng@gmail.com http://scholar.cu.edu.eg/refky/ OUTLINE Previously on ELCN102 Three Phase Circuits Balanced
More informationDesign Engineering MEng EXAMINATIONS 2016
IMPERIAL COLLEGE LONDON Design Engineering MEng EXAMINATIONS 2016 For Internal Students of the Imperial College of Science, Technology and Medicine This paper is also taken for the relevant examination
More informationElectric Circuits Fall 2015 Solution #5
RULES: Please try to work on your own. Discussion is permissible, but identical submissions are unacceptable! Please show all intermeate steps: a correct solution without an explanation will get zero cret.
More informationEE202 Exam III April 6, 2017
EE202 Exam III April 6, 207 Name: (Please print clearly.) Student ID: CIRCLE YOUR DIVISION DeCarlo202 DeCarlo2022 7:30 MWF :30 TTH INSTRUCTIONS There are 3 multiple choice worth 5 points each and
More informationProblem Set 5 Solutions
University of California, Berkeley Spring 01 EE /0 Prof. A. Niknejad Problem Set 5 Solutions Please note that these are merely suggested solutions. Many of these problems can be approached in different
More informationEE101 IMPERIAL COLLEGE LONDON DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2013 ANALYSIS OF CIRCUITS. Tuesday, 28 May 10:00 am
EE101 IMPERIAL COLLEGE LONDON DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2013 ExamHeader: EEE/EIE PART I: MEng, Beng and ACGI ANALYSIS OF CIRCUITS Tuesday, 28 May 10:00 am Time allowed:
More informationChapter 33. Alternating Current Circuits
Chapter 33 Alternating Current Circuits 1 Capacitor Resistor + Q = C V = I R R I + + Inductance d I Vab = L dt AC power source The AC power source provides an alternative voltage, Notation  Lower case
More informationChapter 10: Sinusoidal SteadyState Analysis
Chapter 10: Sinusoidal SteadyState Analysis 1 Objectives : sinusoidal functions Impedance use phasors to determine the forced response of a circuit subjected to sinusoidal excitation Apply techniques
More informationElectrical Circuits Lab Series RC Circuit Phasor Diagram
Electrical Circuits Lab. 0903219 Series RC Circuit Phasor Diagram  Simple steps to draw phasor diagram of a series RC circuit without memorizing: * Start with the quantity (voltage or current) that is
More informationSingle Phase Parallel AC Circuits
Single Phase Parallel AC Circuits 1 Single Phase Parallel A.C. Circuits (Much of this material has come from Electrical & Electronic Principles & Technology by John Bird) n parallel a.c. circuits similar
More informationDEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING RUTGERS UNIVERSITY
DEPARTMENT OF EECTRICA AND COMPUTER ENGINEERING RUTGERS UNIVERSITY 330:222 Principles of Electrical Engineering II Spring 2002 Exam 1 February 19, 2002 SOUTION NAME OF STUDENT: Student ID Number (last
More informationEE202 Exam III April 13, 2006
EE202 Exam III April 13, 2006 Name: (Please print clearly) Student ID: CIRCLE YOUR DIVISION DeCarlo 2:30 MWF Furgason 3:30 MWF INSTRUCTIONS There are 10 multiple choice worth 5 points each and there is
More informationUNIVERSITY OF CALIFORNIA, BERKELEY College of Engineering Department of Electrical Engineering and Computer Sciences
UNIVERSITY OF CALIFORNIA, BERKELEY College of Engineering Department of Electrical Engineering and Computer Sciences EECS 40 Spring 2000 Introduction to Microelectronic Devices Prof. King MIDTERM EXAMINATION
More informationSinusoids and Phasors
CHAPTER 9 Sinusoids and Phasors We now begins the analysis of circuits in which the voltage or current sources are timevarying. In this chapter, we are particularly interested in sinusoidally timevarying
More informationTest II Michael R. Gustafson II
'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ EGR 224 Spring 2016 Test II Michael R. Gustafson II Name (please print) In keeping with the Community Standard, I have neither provided nor received any
More informationMidterm Exam 2. Prof. Miloš Popović
Midterm Exam 2 Prof. Miloš Popović 100 min timed, closed book test. Write your name at top of every page (or initials on later pages) Aids: single page (single side) of notes, handheld calculator Work
More informationELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT
Chapter 31: ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT 1 A charged capacitor and an inductor are connected in series At time t = 0 the current is zero, but the capacitor is charged If T is the
More informationPhysics 4B Chapter 31: Electromagnetic Oscillations and Alternating Current
Physics 4B Chapter 31: Electromagnetic Oscillations and Alternating Current People of mediocre ability sometimes achieve outstanding success because they don't know when to quit. Most men succeed because
More informationSourceFree RC Circuit
First Order Circuits SourceFree RC Circuit Initial charge on capacitor q = Cv(0) so that voltage at time 0 is v(0). What is v(t)? Prof Carruthers (ECE @ BU) EK307 Notes Summer 2018 150 / 264 First Order
More information04Electric Power. ECEGR 452 Renewable Energy Systems
04Electric Power ECEGR 452 Renewable Energy Systems Overview Review of Electric Circuits Phasor Representation Electrical Power Power Factor Dr. Louie 2 Introduction Majority of the electrical energy
More informationECE 212H1F Circuit Analysis October 30, :1019: Reza Iravani 02 Reza Iravani 03 Piero Triverio. (Nonprogrammable Calculators Allowed)
Please Print Clearly Last Name: First Name: Student Number: Your Tutorial Section (CIRCLE ONE): 01 Thu. 911 RS211 02 Thu. 911 GB119 03 Tue. 1012 SF2202 04 Tue. 1012 SF3201 05 Tue. 1315 GB304 06 Tue.
More informationEECE 2150 Circuits and Signals Final Exam Fall 2016 Dec 9
EECE 2150 Circuits and Signals Final Exam Fall 2016 Dec 9 Name: Instructions: Write your name and section number on all pages Closed book, closed notes; Computers and cell phones are not allowed You can
More informationEE221 Circuits II. Chapter 14 Frequency Response
EE22 Circuits II Chapter 4 Frequency Response Frequency Response Chapter 4 4. Introduction 4.2 Transfer Function 4.3 Bode Plots 4.4 Series Resonance 4.5 Parallel Resonance 4.6 Passive Filters 4.7 Active
More informationChapter 10: Sinusoids and Phasors
Chapter 10: Sinusoids and Phasors 1. Motivation 2. Sinusoid Features 3. Phasors 4. Phasor Relationships for Circuit Elements 5. Impedance and Admittance 6. Kirchhoff s Laws in the Frequency Domain 7. Impedance
More informationENGR4300 Spring 2009 Test 2. Name: SOLUTION. Section: 1(MR 8:00) 2(TF 2:00) 3(MR 6:00) (circle one) Question I (20 points): Question II (20 points):
ENGR43 Test 2 Spring 29 ENGR43 Spring 29 Test 2 Name: SOLUTION Section: 1(MR 8:) 2(TF 2:) 3(MR 6:) (circle one) Question I (2 points): Question II (2 points): Question III (17 points): Question IV (2 points):
More informationMAE140  Linear Circuits  Winter 09 Midterm, February 5
Instructions MAE40  Linear ircuits  Winter 09 Midterm, February 5 (i) This exam is open book. You may use whatever written materials you choose, including your class notes and textbook. You may use a
More informationProf. Anyes Taffard. Physics 120/220. Voltage Divider Capacitor RC circuits
Prof. Anyes Taffard Physics 120/220 Voltage Divider Capacitor RC circuits Voltage Divider The figure is called a voltage divider. It s one of the most useful and important circuit elements we will encounter.
More information'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ. EGR 224 Spring Test II. Michael R. Gustafson II
'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ EGR 224 Spring 2017 Test II Michael R. Gustafson II Name (please print) In keeping with the Community Standard, I have neither provided nor received any
More informationSinusoidal Steady State Analysis
Sinusoidal Steady State Analysis 9 Assessment Problems AP 9. [a] V = 70/ 40 V [b] 0 sin(000t +20 ) = 0 cos(000t 70 ).. I = 0/ 70 A [c] I =5/36.87 + 0/ 53.3 =4+j3+6 j8 =0 j5 =.8/ 26.57 A [d] sin(20,000πt
More informationEE221 Circuits II. Chapter 14 Frequency Response
EE22 Circuits II Chapter 4 Frequency Response Frequency Response Chapter 4 4. Introduction 4.2 Transfer Function 4.3 Bode Plots 4.4 Series Resonance 4.5 Parallel Resonance 4.6 Passive Filters 4.7 Active
More informationMidterm Exam (closed book/notes) Tuesday, February 23, 2010
University of California, Berkeley Spring 2010 EE 42/100 Prof. A. Niknejad Midterm Exam (closed book/notes) Tuesday, February 23, 2010 Guidelines: Closed book. You may use a calculator. Do not unstaple
More informationFall 2011 ME 2305 Network Analysis. Sinusoidal Steady State Analysis of RLC Circuits
Fall 2011 ME 2305 Network Analysis Chapter 4 Sinusoidal Steady State Analysis of RLC Circuits Engr. Humera Rafique Assistant Professor humera.rafique@szabist.edu.pk Faculty of Engineering (Mechatronics)
More informationHandout 11: AC circuit. AC generator
Handout : AC circuit AC generator Figure compares the voltage across the directcurrent (DC) generator and that across the alternatingcurrent (AC) generator For DC generator, the voltage is constant For
More informationmywbut.com Lesson 16 Solution of Current in AC Parallel and Seriesparallel
esson 6 Solution of urrent in Parallel and Seriesparallel ircuits n the last lesson, the following points were described:. How to compute the total impedance/admittance in series/parallel circuits?. How
More informationEE 40: Introduction to Microelectronic Circuits Spring 2008: Midterm 2
EE 4: Introduction to Microelectronic Circuits Spring 8: Midterm Venkat Anantharam 3/9/8 Total Time Allotted : min Total Points:. This is a closed book exam. However, you are allowed to bring two pages
More informationBasic RL and RC Circuits RL TRANSIENTS: STORAGE CYCLE. Engineering Collage Electrical Engineering Dep. Dr. Ibrahim Aljubouri
st Class Basic RL and RC Circuits The RL circuit with D.C (steady state) The inductor is short time at Calculate the inductor current for circuits shown below. I L E R A I L E R R 3 R R 3 I L I L R 3 R
More informationTo find the step response of an RC circuit
To find the step response of an RC circuit v( t) v( ) [ v( t) v( )] e tt The time constant = RC The final capacitor voltage v() The initial capacitor voltage v(t ) To find the step response of an RL circuit
More informationENGG Fundamentals of Electrical Circuits and Machines Final Examination
Name: Lecture Section: ID#: ENGG 225  Fundamentals of Electrical Circuits and Machines Final Examination Monday, April 18, 2011 Time: 3:306:30 PM Red and Auxiliary Gymnasium L01, L02  Norm Bartley L03
More informationTwoPort Networks Admittance Parameters CHAPTER16 THE LEARNING GOALS FOR THIS CHAPTER ARE THAT STUDENTS SHOULD BE ABLE TO:
CHAPTER16 TwoPort Networks THE LEARNING GOALS FOR THIS CHAPTER ARE THAT STUDENTS SHOULD BE ABLE TO: Calculate the admittance, impedance, hybrid, and transmission parameter for twoport networks. Convert
More informationName: (Please print clearly) Student ID: CIRCLE YOUR DIVISION INSTRUCTIONS
EE 202 Exam III April 13 2011 Name: (Please print clearly) Student ID: CIRCLE YOUR DIVISION Morning 7:30 MWF Furgason INSTRUCTIONS Afternoon 3:30 MWF DeCarlo There are 10 multiple choice worth 5 points
More informationElectric Circuits I Final Examination
EECS:300 Electric Circuits I ffs_elci.fm  Electric Circuits I Final Examination Problems Points. 4. 3. Total 38 Was the exam fair? yes no //3 EECS:300 Electric Circuits I ffs_elci.fm  Problem 4 points
More information'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ. EGR 224 Spring Test II. Michael R. Gustafson II
'XNH8QLYHUVLW\ (GPXQG73UDWWU6FKRRORI(QJLQHHULQJ EGR 224 Spring 2018 Test II Michael R. Gustafson II Name (please print) In keeping with the Community Standard, I have neither provided nor received any
More informationDesigning Information Devices and Systems II Spring 2016 Anant Sahai and Michel Maharbiz Midterm 2
EECS 16B Designing Information Devices and Systems II Spring 2016 Anant Sahai and Michel Maharbiz Midterm 2 Exam location: 145 Dwinelle (SIDs ending in 1 and 5) PRINT your student ID: PRINT AND SIGN your
More informationMassachusetts Institute of Technology Department of Electrical Engineering and Computer Science Electronic Circuits Fall 2000.
Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.002 Electronic Circuits Fall 2000 Final Exam Please write your name in the space provided below, and circle
More informationVer 3537 E1.1 Analysis of Circuits (2014) E1.1 Circuit Analysis. Problem Sheet 1 (Lectures 1 & 2)
Ver 3537 E. Analysis of Circuits () Key: [A]= easy... [E]=hard E. Circuit Analysis Problem Sheet (Lectures & ). [A] One of the following circuits is a series circuit and the other is a parallel circuit.
More informationSINUSOIDAL STEADY STATE CIRCUIT ANALYSIS
SINUSOIDAL STEADY STATE CIRCUIT ANALYSIS 1. Introduction A sinusoidal current has the following form: where I m is the amplitude value; ω=2 πf is the angular frequency; φ is the phase shift. i (t )=I m.sin
More informationPhysics 227 Final Exam December 18, 2007 Prof. Coleman and Prof. Rabe. Useful Information. Your name sticker. with exam code
Your name sticker with exam code Physics 227 Final Exam December 18, 2007 Prof. Coleman and Prof. Rabe SIGNATURE: 1. The exam will last from 4:00 p.m. to 7:00 p.m. Use a #2 pencil to make entries on the
More informationLO 1: Three Phase Circuits
Course: EEL 2043 Principles of Electric Machines Class Instructor: Dr. Haris M. Khalid Email: hkhalid@hct.ac.ae Webpage: www.harismkhalid.com LO 1: Three Phase Circuits Three Phase AC System Three phase
More informationPrerequisites: Successful completion of PHYS 2222 General Physics (Calculus) with a grade of C or better.
Prepared by: P. Blake Reviewed by: M. Mayfield Date prepared: March 13, 2017 C&GE approved: April 17, 2017 Board approved: May 10, 2017 Semester effective: Spring 2018 Engineering (ENGR) 2000 Circuit Analysis
More informationAlternating Currents. The power is transmitted from a power house on high voltage ac because (a) Electric current travels faster at higher volts (b) It is more economical due to less power wastage (c)
More informationModule 4. Singlephase AC Circuits
Module 4 Singlephase AC Circuits Lesson 14 Solution of Current in RLC Series Circuits In the last lesson, two points were described: 1. How to represent a sinusoidal (ac) quantity, i.e. voltage/current
More informationQUESTION BANK SUBJECT: NETWORK ANALYSIS (10ES34)
QUESTION BANK SUBJECT: NETWORK ANALYSIS (10ES34) NOTE: FOR NUMERICAL PROBLEMS FOR ALL UNITS EXCEPT UNIT 5 REFER THE EBOOK ENGINEERING CIRCUIT ANALYSIS, 7 th EDITION HAYT AND KIMMERLY. PAGE NUMBERS OF
More information1 Phasors and Alternating Currents
Physics 4 Chapter : Alternating Current 0/5 Phasors and Alternating Currents alternating current: current that varies sinusoidally with time ac source: any device that supplies a sinusoidally varying potential
More informationGeorgia Institute of Technology School of Electrical and Computer Engineering. Midterm1 Exam (Solution)
Georgia Institute of Technology School of Electrical and Computer Engineering Midterm1 Exam (Solution) ECE6414 Spring 2012 Friday, Feb. 17, 2012 Duration: 50min First name Solutions Last name Solutions
More informationChapter 9 Objectives
Chapter 9 Engr8 Circuit Analysis Dr Curtis Nelson Chapter 9 Objectives Understand the concept of a phasor; Be able to transform a circuit with a sinusoidal source into the frequency domain using phasor
More informationELEC 202 Electric Circuit Analysis II Lecture 10(a) Complex Arithmetic and Rectangular/Polar Forms
Dr. Gregory J. Mazzaro Spring 2016 ELEC 202 Electric Circuit Analysis II Lecture 10(a) Complex Arithmetic and Rectangular/Polar Forms THE CITADEL, THE MILITARY COLLEGE OF SOUTH CAROLINA 171 Moultrie Street,
More informationEE202 Exam III April 15, 2010
EE0 Exam III April 5, 00 Name: SOLUTION (No period) (Please print clearly) Student ID: CIRCLE YOUR DIVISION Morning 8:30 MWF Afternoon 3:30 MWF INSTRUCTIONS There are 9 multiple choice worth 5 points
More informationEXPERIMENT 07 TO STUDY DC RC CIRCUIT AND TRANSIENT PHENOMENA
EXPERIMENT 07 TO STUDY DC RC CIRCUIT AND TRANSIENT PHENOMENA DISCUSSION The capacitor is a element which stores electric energy by charging the charge on it. Bear in mind that the charge on a capacitor
More informationToolbox: Electrical Systems Dynamics
Toolbox: Electrical Systems Dynamics Dr. John C. Wright MIT  PSFC 05 OCT 2010 Introduction Outline Outline AC and DC power transmission Basic electric circuits Electricity and the grid Image removed due
More informationElectric Circuits I Final Examination
The University of Toledo s8fs_elci7.fm  EECS:300 Electric Circuits I Electric Circuits I Final Examination Problems Points.. 3. Total 34 Was the exam fair? yes no The University of Toledo s8fs_elci7.fm
More information