MA 1125 Lecture 15 - The Standard Normal Distribution. Friday, October 6, Objectives: Introduce the standard normal distribution and table.

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1 MA 1125 Lecture 15 - The Standard Normal Distribution Friday, October 6, Objectives: Introduce the standard normal distribution and table. 1. The Standard Normal Distribution We ve been looking at probability distributions for a couple of lectures. For the most part, we ve focused on binomial distributions, which are important for a number of reasons. One of them, we ll start discussing today. Let s start by looking at the histogram for the binomial distribution corresponding to tossing a coin three times. 4/8 3/8 2/8 1/ Figure 1. A histogram for the tossing-a-coin-three-times binomial distribution. The histogram for three tosses has an important overall shape. It s symmetric, and it s highest in the middle. If we look at the binomial distribution for six tosses, we get a histogram that looks like the one in Figure 2. Figure 2. A histogram for six tosses of a coin. 1

2 2 We see the same basic shape, highest in the middle, but with more rectangles. What would happen, if we looked at the histogram for a thousand tosses? Or a million tosses? We wouldn t want to actually do that, but we could imagine that there would be so many rectangles, we wouldn t really be able to see them. They would make a very smooth curve. Something like the curve shown in Figure 3. Figure 3. The normal curve. The curve shown in Figure 3 is a rough depiction of the curve (1) y = e x2 /2 2π. You don t have to remember this equation, but remember the shape of the curve. The curve is called the normal curve. It s also known as the bell curve for its shape, or the Gauss curve for the mathematician Carl Friedrich Gauss. What s important about the normal curve is that there is a natural tendency for distributions to gravitate towards it. For example, if you let the number of trials in a binomial distribution go to infinity, the shapes of the histograms will approach the shape of the normal curve. Similar things happen with many distributions. As a result, distributions you run into in statistics tend to look very much like the normal curve. 2. The Standard Normal Distribution Since there is a natural tendency for histograms to look like the normal curve, there must be a special probability distribution that other distributions gravitate towards. There is. It s called the Standard Normal Distribution. It is defined to be distributed according to the normal curve. This is how it works. The normal curve goes out to infinity to the right and left. It is low enough, however, so that the total area under the curve is exactly one. Remember that in a probability distribution,

3 MA 1125 Lecture 15 - The Standard Normal Distribution 3 all the probabilities must add up to one. It is natural, therefore, to equate area under the normal curve with probability. That s what we do. Now, the standard normal distribution is an example of a continuous distribution. As a result, the variable, we ll use z, can take on an infinite number of values. It doesn t make sense, therefore, to talk about the probability of z being anything other than zero. We ll talk instead about the probability of z falling in some range. For example, (2) P(1.00 z 1.73). In general, we define the probability P(a z b) to be equal to the area under the normal curve and between the values z = a and z = b. This area is shaded in Figure 4. It s actually pretty hard to find these areas, but luckily, we ll have a table to help us. 0 a b z Figure 4. The normal curve. Finally, I want to tell you that z = 0 is always in the middle. The highest point of the curve lies above z = 0. Furthermore, the normal curve is perfectly symmetric about z = 0. Since the total area is 1, then the area to the right of z = 0 must be 1 2. As a result, (3) P(0 z < ) = Note that I used < with the s. That s because it doesn t make sense to talk about z =. In all other cases, I ll use most of the time, although it doesn t really matter. The probability for any specific value of z is zero. 3. Computing specific probabilities in the standard normal distribution Like I said, we ll find the areas and probabilities using a table. We ll spend the rest of today talking about how we ll do that.

4 4 0 z Figure 5. The table gives areas like the one shaded here. At the end of this lecture, and as a separate document linked to my web page is a table that contains probabilities for areas like the one shown in Figure 5. As I said before, z = 0 is in the middle of the standard normal distribution. The table gives probabilities between z = 0 and positive values for z Figure 6. The area corresponding to P(0 z 1.12). For example, consider P(0 z 1.12) (see Figure 6). This we can read directly from the table. Think of the z value of 1.12 as (4) 1.12 = Find 1.1 in the left column, and then look across to the 0.02-column. You should find This means that (5) P(0 z 1.12) = Similarly, P(0 z 0.56) = (6) P(0 z 2.24) = P(0 z 3.00) =

5 MA 1125 Lecture 15 - The Standard Normal Distribution 5 Note: I ve left the repeated values in the table blank. There is so little area in the tails, that the fourth decimal place doesn t change very much. In fact, the area beyond z = 3.89 rounds down to Computing probabilities not in the table Suppose we would like to compute (7) P(1.12 z < ) =? First, and you should always do this, we ll draw a sketch. Since z = 1.12 is positive and we want the area to the right of this number, the picture looks something like Figure Figure 7. The area corresponding to P(1.12 z < ). The table tells us that the area between z = 0 and z = 1.12 is We also know that all the area to the right of z = 0 is It follows, and this should make sense to you from the picture, that (8) P(1.12 z < ) = P(0 z < ) P(0 z 1.12) = = It s important that you see this formula in the picture. Play with this in your mind until it makes sense. Let s find P(3.00 z < ). The picture looks similar to Figure 7, but 3.00 is further out than 1.12, and so we should expect a smaller probability. (9) P(3.00 z < ) = = For the standard normal, at least, we see that getting a z-score greater than 3.00 is about 0.13%. Much less than 1%, which itself isn t very much. We re way way up in the 100th percentile here.

6 6 5. Quiz 15 Don t round. 1. Find P(0 z 1.10). 2. Find P(0 z 3.00). 3. Find P(0 z 0.87). 4. Find P(0 z 1.56). 5. Find P(1.55 z). 6. Homework 15 Find the following probabilities in the Standard Normal Distribution. Keep your answers accurate to four decimal places. 1. P(0 z 2.19). 2. P(0 z 1.53). 3. P(0 z 0.11). 4. P(0 z 1.10). 5. P(0 z 0.99). 6. P(1.55 z). 7. P(0.51 z). 8. P(3.01 z). 9. P( < z < ). 10. P( < z 0). Answers on next page.

7 MA 1125 Lecture 15 - The Standard Normal Distribution 7 HW Answers: 1) ) ) ) ) ) = ) = ) = (Remember that when the values start repeating, I ve left the repeated spots blank.) 9) This is the area under the entire graph. 10) This is half of the total area.

8 8 The Standard Normal Distribution z z

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